The length of time to build the fence is 8 hours
How to determine the length of time to build the fenceFrom the question, we have the following parameters that can be used in our computation:
Length of the fence = 1 1/3 miles
Rate of building = 1/6 miles per hour
The length of time to build the fence is then calculated as
Length of time = Length of the fence/Rate of building
Substitute the known values in the above equation, so, we have the following representation
Length of time = (1 1/3 miles)/(1/6 miles per hour)
Evaluate the quotient
This gives
Length of time = 8 hours
Hence, the time taken is 8 hours
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hey any help? (please make sure this is correct i'd appreciate it)
Answer:
Below
Step-by-step explanation:
Line AB is of the form y = mx + b where m is the slope = 2
Line BC is perpendicular to this and will have slope - 1/m = - 1/2 and includes the point C (0,6)
The point slope form of line BC will then be
( y-6) = - 1/2 ( x - 0) which can be re-arranged to
y = - 1/2x + 6 < ==== equation for line BC
Mary is going for a walk. She takes 3 hours to walk 9.6 miles. What is her speed?
Answer:
3.2 mph
Step-by-step explanation:
If it takes her 3 hours to walk 9.6 miles, we need to divide 9.6 by 3.
To do so, we can remove the decimal point in 9.6, to give us 96.
Then, we can divide 96 by 3 to get 32.
Add the decimal back to 32.
Doing so would give us 3.2, and our answer.
We can check this answer by multiplying 3.2 by 3, which gives us 9.6, telling us our answer is correct.
Please help me with this question
Answer:
Step-by-step explanation:
i have no idea
If the HCF is 5 and the product of the two numbers is 70, find the value of LCM.
If the HCF is 5 and the product of the two numbers is 70, then the value of LCM is 14.
Do two numbers make a product when they are the LCM of two numbers?The smallest number that can be divided by both numbers is known as the least common multiple, or LCM, of two numbers. The product of the two numbers is the LCM if their greatest common divisor is 1, in which case their product is 1.
Using the fundamental theorem of mathematics, how do you find the HCF and LCM?First, multiply both numbers by their prime factors to express them. Then, multiply the common factor with the highest power by the remaining factors to obtain the LCM. Take the common factors with the lowest power and multiply them to determine HCF.
To find the LCM of two numbers, you can use the formula: LCM = (a * b) / HCF.
In this case, we know that the HCF is 5, and the product of the two numbers is 70. Therefore, we can substitute these values into the formula:
LCM = (70) / 5 = 14.
So the LCM of the two numbers is 14.
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find the mean in the picture
Will mark brainliest (I also need to find the x and y intercepts)
Solve for x in the triangle. Round your answer to the nearest tenth.
In the right triangle in the figure the value of x is solved to be 4.5
How to find the value of xUsing SOH CAH TOA for the right triangle
Sin = opposite / hypotenuse - SOH
Cos = adjacent / hypotenuse - CAH
Tan = opposite / adjacent - TOA
The figures show that
hypotenuse = 6
adjacent = x
given angle = 41 degrees
The value of x will be calculated using cos, CAH let the angle be y
cos y = adjacent / hypotenuse
cos 41 = x / 6
x = 6 * cos 41
x = 4.528
x = 4.5
Hence the value of x is 4.5
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The diagonals of a quadrilateral ABCD intersects each other at the point O such that AO/BO=CO/DO.Prove that ABCD is a trapezium.
Answer:
Step-by-step explanation:
To prove that a quadrilateral ABCD is a trapezium when the diagonals intersect at a point O such that AO/BO=CO/DO, we can use the fact that opposite sides of a trapezium are parallel.
First, let's draw a diagram to represent the given information:
[asy]
pair A, B, C, D, O;
A = (0,0);
B = (2,0);
C = (3,2);
D = (1,2);
O = intersection point(A-C, B--D);
draw(A--B--C--D--cycle);
draw(A-C);
draw(B--D);
label("A", A, W);
label("B", B, E);
label("C", C, E);
label("D", D, W);
label("O", O, N);
label("$\theta_1$", (B+O)/2, NE);
label("$\theta_2$", (O+D)/2, NE);
label("$\theta_3$", (O+C)/2, NW);
label("$\theta_4$", (A+O)/2, NW);
[/asy]
Since the diagonals intersect at point O, the angles formed by the diagonals at O are supplementary (that is, they add up to 180 degrees). In other words, we have:
θ1 + θ2 = 180 degrees
θ3 + θ4 = 180 degrees
Since AO/BO=CO/DO, the triangles AOB and COD are similar. This means that the ratios of their sides are equal. We can write this as:
AO/BO = CO/DO
We can also write this as:
AO/DO = CO/BO
Then, since the angles formed by the diagonals at O are supplementary, we have:
θ1 + θ2 = 180 degrees
θ1 + θ4 = 180 degrees
Subtracting these two equations gives us:
θ2 - θ4 = 0
Since the angles are equal, they are also opposite angles of the quadrilateral ABCD. Therefore, the opposite sides of AB and CD are parallel, which means that ABCD is a trapezium.
Write an addition equation with three equal fractional parts.
15
4
=
+
+
Step-by-step explanation:
please refer to the sketch
- Complete the function table for f(x) = 3x + 2.
groce
x
-2
-1
0
1
opies of graph pap
The value of the function f(x) at x = - 2, - 1, 0, 1 are - 4, - 1, 2, 5.
What is a function?A function can be defined as the outputs for a given set of inputs.
The inputs of a function are known as the independent variable and the outputs of a function are known as the dependent variable.
Given, A function f(x) = 3x + 2.
Now,
At x = - 2, f(x) = 3(-2) + 2 ⇒ f(x) = - 4.
At x = - 1, f(x) = 3(-1) + 2 ⇒ f(x) = - 1.
At x = 0, f(x) = 3(0) + 2 ⇒ f(x) = 2.
At x = 1, f(x) = 3(1) + 2 ⇒ f(x) = 5.
This can also be written in the form of ordered pairs
(- 2, - 4), (- 1, - 1), (0, 2), (1, 5).
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Katerina needs 200 balloons fillied with helium for a party. She knows that each balloon will need 0.7ft^3 of helium. the helium canisters hold 0.20m^3. 1m^3 = 35ft^3. How many Canisters will Katerina need to buy?
=======================================================
Explanation:
1 balloon = 0.7 ft^3 of helium
200 balloons = 200*0.7 = 140 ft^3 of helium
Katerina needs 140 cubic feet of helium to fill all 200 balloons.
---------------
1m^3 = 35ft^3 which is approximate
0.2 m^3 = 0.2*35 = 7 ft^3
Each canister holds approximately 7 cubic feet of helium.
----------------
To summarize so far.
Katerina needs 140 cubic feet of helium.Each canister holds approximately 7 cubic feet of helium.Let x be the number of canisters. Because of fact 2 mentioned above, 7x represents the total amount of helium from all of the x number of canisters.
Set this equal to the amount she needs (140) and solve for x.
7x = 140
x = 140/7
x = 20
Katerina needs 20 canisters.
Select the correct answer. What is this equation rewritten in exponential form? log7 343 = 3 A. 37 = 343 B. 73 = 343 C. 343x = 7 D. 343x = 3
The solution to the equation log₇343 = 3 is 7³ = 343
What is an equation?An equation is used to show the relationship between numbers and variables.
The logarithm can be defined as the exponent that raises a base to get a particular number. The law of logarithm states:
logₓm = n is the same as xⁿ = m
Given the equation:
log₇343 = 3
Applying the law of logarithm gives:
7³ = 343
The solution to the equation is 7³ = 343
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5. Jackson purchased a pack of game cards that was on sale for 22% off. The sales tax in his county is 6%. Let y represent the original price of the cards. Write an expression that can be used to determine the final cost of the cards.
The decimal value is exact without any rounding.
==========================================================
Explanation:
If Jackson saves 22%, then he pays the remaining 100% - 22% = 78%, which leads to the decimal value 0.78
An increase of 6% leads to 100%+6% = 106% and that converts to 1.06
Multiply those decimal values: 0.78*1.06 = 0.8268; this trick is useful to chain together multiple discounts and/or tax increases.
Therefore, the final cost expression is 0.8268y where the variable y is the original price before the discount and taxes.
---------
Extra info:
The expression 0.8268y tells us that Jackson is paying 82.68% of the original price. Note how 100% - 82.68% = 17.32%
This means Jackson is getting a real discount of 17.32% after the taxes have been considered.
All of the quadrilaterals in the shape below are squares. Find the area of the shaded
region.
Answer: I don't remember how to solve, but, I figured out the lengths of each side in the shaded region:
11, 11, 7, 7, 4, 4
Step-by-step explanation:
Hope this helps!! :D
The weight of the square is 10 grams. How much heavier is the circle than the square?
By adding the weight of the triangle, the weight of the circle heavier than that of the square.
How to determine how much heavier the circle is than the squareThe linear equation that results from examining the weights will contain the following parameters.
Let t stand for the triangle.
Let c stand for the circle.
Let's use the shape square.
left side of the equation = 6s + 3t
right side of the equation = 3s + 3c
equating both sides
6s + 3t = 3s + 3c
6s - 3s + 3t = 3s + 3c
3s + 3t = 3c
3(s + t) = 3c
dividing all through by 3
s + t = c
10 + t = c
Because of the resulting equation, we can conclude that the the circle is weightier than the square by the weight of the triangle
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15. The center of the circle in the figure is at O. Determine the measure of ZABC.
According to the Central Angle Theorem, the central angle occupied by two points on a circle will always be twice the inscribed angle occupied by those same two points, therefore ∠ABC = 1/2 × 56 = 28°.
What is Central Angle Theorem?Since subtended and inscribed angles are mentioned in the definition, we must first understand them in order to understand the central angle theorem. An object at a specific outer position forms an angle known as a subtended angle.
If you disagree with that definition, think about this: On Earth, you are standing and gazing up at the sun. A triangle with three sides is created. The sun's height, the sun ray that travels from the bottom of the sun to your eyes, and these three directions are the three sides of the sun.
The Central Angle Theorem states that the central angle occupied by two points on a circle is always twice the inscribed angle occupied by those same two points.
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If m∠ABJ = 28, ∠ABC ≅ ∠DBJ, find m∠JBC.
Answer:
Step-by-step explanation:
If m∠ABJ = 28 and ∠ABC ≅ ∠DBJ, then we can set up the following equation:
m∠ABC = m∠DBJ
Since angles ∠ABC and ∠DBJ are congruent, they have the same measure, so the equation above is true.
Since we are trying to find m∠JBC, we can use the fact that the measure of an angle is equal to the sum of the measures of the other two angles in the triangle to set up another equation:
m∠JBC = m∠ABC + m∠ABJ
Substituting the value for m∠ABC from the first equation into the second equation, we get:
m∠JBC = m∠DBJ + m∠ABJ
Substituting the given value of m∠ABJ into this equation, we get:
m∠JBC = m∠DBJ + 28
Since m∠ABJ = m∠DBJ, we can substitute m∠ABJ in for m∠DBJ:
m∠JBC = m∠ABJ + 28
Substituting the given value of m∠ABJ into this equation, we get:
m∠JBC = 28 + 28
Solving this equation, we find that m∠JBC = 56.
Therefore, the measure of angle ∠JBC is 56 degrees.
Find the midpoint of the line segment with endpoints:
(9, -5/2) to (-5, -3/2)
Answer must be as a point, using integers or reduced fractions for coordinates.
Answer:
Step-by-step explanation:
Midpoint formula is x3 = (x1+x2)/2, y3=(y1+y2)/2
so x3=(9-5)/2=2, y3=(-5/2-3/2)/2=-2.
the coordinates is (2, -2).
Find the circumference of a circle with a diameter of 50 centimeters
Answer:
157.08 is the circumference. Hope it helps you
Step-by-step explanation:
A certain type of fertilizer contains 8% nitrogen. If 2 kilograms of nitrogen are needed to fertilize a lawn, how many kilograms of fertilizer are needed?
25 kilograms of fertilizer would be needed to fertilize the lawn.
what is the percentage?In essence, percentages are fractions with 100 as the denominator. We place the percent symbol (%) next to the number to indicate that the number is a percentage.
given, A certain type of fertilizer contains 8 percent of nitrogen. If 2 kilograms of nitrogen are needed to fertilize a lawn.
Since fertilizer contain 8% nitrogen in it
thus for 80 grams of nitrogen = 1 kg of fertilizer
for 1 gram of nitrogen = 1/80 kg fertilizer
for 2000 gram of nitrogen = (1/80)* 2000 kg fertilizer
for 2 kilograms of nitrogen = 25 kg fertilizer
therefore, To fertilize the yard, 25 kg of fertilizer would be required.
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Customary American Units of Capacity
1 cup = 8 ounces
1 pint = 2 cups or 16 ounces
1 quart = 2 pints, 4 cups, or 32 ounces
1 gallon = 4 quarts, 8 pints, 16 cups, or 128 ounces
5 quarts 4 pints =____ pints
Answer:
14
Step-by-step explanation:
5 quarts = 10 pints
10 pints + 4 pints = 14 pints
Find the area of a regular 12-sided polygon inscribed in a circle of radius
8 cm.
area of n sided polygon inscribed in a circle is
A = (1/2)nr²sin(360/n) (r = radius of circle)
A = (1/2)12*8²*sin30
= 1/2*12*64*1/2
A = 192 square unit
Find the missing term 2,..,20,29
Answer:
11
Step-by-step explanation:
29-20= 91
2+9=11
11+9=
PLEASE HELP ME 2 QUESTIONS ARE LISTED DOWN BELOW
A) The linear equation is:
y = (3/4)*x + 3
B) The sets with only positive elements are:
{x| x ∈ N}{y| 0 < y < 1}{y| 3 ≤ y ≤22}How to write the linear equation?A general linear equation can be written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
Here, we do know that the y-intercept of the linear equation is (0, 3), then we know that b = 3.
Then the line is something like:
y = a*x + 3
We also know that the line passes through (-4, 0), then we can replace these values in the equation above to get:
0 = a*-4 + 3
4a = 3
a = 3/4
Then the linear equation is:
y = (3/4)*x + 3
In which sets all the numbers are positive?The sets where all the numbers are positive are:
{x| x ∈ N}
Where N is the set of the natural numbers, these are all the integers equal to or larger than 1, so all are positives.
{y| 0 < y < 1}
There we can see that y must be larger than zero, so all the elements are positive.
{y| 3 ≤ y ≤22}
Here the elements are between 3 and 22, so all of these are positve.
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<
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a translation.
←++
-7-6-5-4-3/2
A translation by
up/down
7-
6+
6543
У
5-
3-
24
2345
-3-
Determine the translation.
Use non-negative numbers.
-5+
-6-
D'
A
34 9/7
B
2
units to the right/left ✓
and
units
Answer:
1 unit to the left, 3 units down
Step-by-step explanation:
Take any point: I will take D. In order to get to D', you need to travel 1 unit along the x-axis towards the left, then 3 until along the y-axis downwards. The same applies for any other point.
a tee junction occurs when a connection meets an existing pipe of header at what angle? A 180 degree, B 30 degree, C. 90 degree, D.45 degree
Tee welding joints are formed when two members intersect at a 90-degree angle that makes the edges come together in the center of a plate or component
value of y please help me
An item on sale costs 80% of the original price. The original price was 33%
The sale price of the item is given by the equation A = $ 26.40
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the sale price of the item be represented as A
Now , the equation will be
The original price of the item = $ 33
An item on sale costs 80% of the original price
So , the sale price of the item A = 80 % x original price of the item
Substituting the values in the equation , we get
The sale price of the item A = ( 80 / 100 ) x 33
The sale price of the item A = 0.80 x 33
The sale price of the item A = $ 26.40
Therefore , the value of A is $ 26.40
Hence , the sale price is $ 26.40
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hello i need help with question 5 please
5a) The total cost of buying the car, including the harmonized sales tax (HST) of 13%, is $36,160.
5b) Under the lease, the customer saves $14,760.
5c) The lessee after returning the car has the following lease options:
Lease buyoutLease extensionNew lease contractBuying out the vehicle and then reselling it.6a) The after-tax cost of the car that Jordan wants to buy is $32,199.35.
6b) The part of the Honda Civic that needs to be financed after the down payment is $26,199.35.
6c) The monthly payment will be $567.26.
6d) After four years, the total amount Jordan had paid for the vehicle is $33,228.48.
Car Financing Options:A lease is a financing option for the use of capital assets by which the lessee utilizes an asset for a stated period while making periodic payments to the lessor.
A car purchase can also be financed through loans, like home mortgages.
Value of the car = $32,000
Harmonized Sales Tax (HST) = 13%
Cost of the car with HST = $36,160 ($32,000 x 1.13)
Lease Arrangement:Down payment = $1,000
Financing part = $35,160 ($36,160 - $1,000)
Installment payments = 48
Periodic payments = $425
Total lease cost = $21,400 ($1,000 + 48 x $425)
Savings from leasing = $14,760 ($36,160 - $21,400)
Jordan's Car:The value of the Honda Civic = $28,495
Harmonized Sales Tax (HST) = 13%
After-tax cost = $32,199.35 ($28,495 x 1.13)
Annual interest rate = 1.9% compounded monthly
Down payment = $6,000
Financing part = $26,199.35 ($32,199.35 -$6,000)
Financing period = 4 years
N (# of periods) = 48 months (4 years x 12)
I/Y (Interest per year) = 1.9%
PV (Present Value) = $26,199.35
FV (Future Value) = $0
P/Y (# of periods per year) = 12
C/Y (# of times interest compound per year) = 12
Results:
Monthly Payments (PMT) = $567.26
Sum of all periodic payments = $27,228.48
Total Interest $1,029.13
Total amount paid by Jordan after 4 years = $33,228.48 ($27,228.48 + $6,000)
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1) A publisher wants to determine the thickness of a book they will print soon. The book has a front cover and a back cover, each of which have a thickness of
1/4 in. The publisher can choose on what type of paper to print the book.
Bond paper has a thickness of 1/4 in. per 100 pages.
Write an equation that gives the width `y` of the book, if it has `x`-hundred pages printed on bond paper.
Ledger paper has a thickness of 2/5 in. per `100` pages. Write an equation that gives the width `y` of the book, if it has `x`-hundred pages printed on ledger paper.
2) If the publisher selects front and back covers with a thickness of 1/3 in. each, how would this change the equations you wrote on the previous slides?
1a) An equation that gives the width `y` of the book, if it has `x`-hundred pages printed on bond paper is; y = ¹/₂ + ¹/₄x
1b) Ledger paper has a thickness of 2/5 in. per `100` pages, the equation is; y = ¹/₂ + ²/₅x
2) The equation will be; y = ²/₃ +¹/₄x
How to solve Algebraic Word Problems?1) We are told that the front cover and the back cover have a thickness of 1/4 inches and they also have a thickness of 1/4 inch. Thus;
The addition of both gives to the book thickness of;
1/4 + 1/4 = 1/2 inch, despite how many pages the book has.
We are told that for every hundred pages, a thickness of 1/4 inch is added to the book, then the equation is:
y = ¹/₂ + ¹/₄x
where;
y is the width of the book in inches.
x is every hundred pages printed on bond paper.
1b) If ledger paper has a thickness of 2/5 in. per 100 pages, then the equation is now;
y = ¹/₂ + ²/₅x
2) If both front and back covers now, have a thickness of 1/3 inches instead of 1/4 inches each, then the equation will be;
y = 2(1/3) +¹/₄x
y = ²/₃ +¹/₄x
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