A math teacher was frustrated at the number of students leaving their graphing calculator behind in her classroom at the end of class without a way to locate the student. A random sample of 50 students is selected, and of the students questioned, 32 had their names written on their graphing calculators.

Required:
What would be a 99% confidence interval for the proportion of all students at this school who have their names written on their graphing calculators?

Answer:

g(11) = 101

Step-by-step explanation:

g(r) = -20 + 11r

So in g(11), we just need to replace 'r' with '11'

g(11) = -20 + 11 (11)

--> g(11) = -20 + 121 = 101

--> g(11) = 101

Please comment down below if 8(11) wasn't a typo. I thought it was, so I replaced 8 with g. If that was intentional, I'll edit my answer as soon as possible.

Answer:

D

Step-by-step explanation:

I assume that for C and D, you meant e^x.

Since the function is defined at 0, eliminate A and B (since ln 0 is undefined)

Between C and D, we know that when x=0, e^x = 1. Since the y intercept of the graph is -3, this means the equation is y = e^x - 4.

Paul's rent budget is $750, given that his food budget of $225, is 30 percent of his rent budget.

Fractions are representation of quantities as a part of a certain quantity.

Written as a/b, read as a by b, and functions as a divided by b, represents a fraction showing a parts of b equal parts.

a is called the numerator, and b is called the denominator.

Percentages are modified fractions where the whole quantity is represented by 100.

To convert a fraction into percentages we multiply it by 100, while to convert percentages to fraction divided by 100.

In the question, we are given that Paul's budget for food is 30% of the budget he has for rent.

We are asked if his budget for food is $225, what is his budget for rent.

We assume Paul's budget for rent to be $x.

We know that Paul's food's budget is 30 percent of his rent.

Hence, Paul's food budget = 30% of x.

or, Paul's budget for food = 30/100 * x {To convert percentages to fraction divided by 100}

But, we know that Paul's food budget is $225. Thus, we can show that:

225 = 30/100 * x,

or, x = (225*100)/30 = 750.

Thus, Paul's rent budget is $750, given that his food budget of $225, is 30 percent of his rent budget.

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Using conditional probability, there is a 0.6667 = 66.67% probability that a new product will be unpopular if a focus group study indicates that it will be unpopular.

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

For this problem, the events are given as follows:

The parameters are given as follows:

Hence the conditional probability is:

[tex]P(B|A) = \frac{0.33}{0.495} = 0.6667[/tex]

0.6667 = 66.67% probability that a new product will be unpopular if a focus group study indicates that it will be unpopular.

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[tex]order \: does \: not \:matter \\ sample \: space = 15 \: letters \\ no \: repetition\\ P(A) = 15C5 = 3003 \: ways[/tex]

Answer:

1050 masks per person.

Step-by-step explanation:

1) Create an equation to find the total number of masks

2) Solve equation and divide total by 2 to get the number of masks that can be given to both Mark and Paula so that they have equal number.

1) Since Paula has 70% of the total masks, it can be represented as 0.7 * t where t is the variable representing the total number of masks. Mark on the other hand has the remaining number of masks out of 100% which is 30%. We can express that as 0.3. We multiply that by t because he has 30% of the masks. The final equation we have is 0.3t + 840 = 0.7t. 840 because Paula has 840 more masks than Mark.

2) Solve by subtracting 0.3t from both sides leaving you with 0.4t = 840. We divide both sides by 0.4 to get 2100. That is the total number of masks. If we divide that number by 2, we get 1050.

answer:

x = - 9/2

y = -10

Step-by-step explanation:

make both equations look like y =

2x-3y=21 -> -3y= -2x+21 -> y = (-2x+21)/-3 -> y = 2/3x - 7

-6x + 2y = 7 -> 2y = 6x + 7 -> y = 3x + 7/2

now make the equations equal to each other (since they both equal y)

get x

2/3x - 7 = 3x + 7/2

-7 -7/2 = 3x - 2/3x

-14/2 -7/2 = 9/3x - 2/3x

-21/2 = 7/3x

(3/7) -21/2 = x

x = (3/7) -21/2

x = - 63/14

x = - 9/2

put it back in an equation to get y

y = 3x + 7/2

y = 3(-9/2) + 7/2

y = -27/2 + 7/2

y = -20/2

y = - 10

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Answer:

f(x)⁻¹ = (x - 11)²

Step-by-step explanation:

To find the inverse of the function, you need to (1) swap the places of the "x" and "y" variables and then (2) solve for "y". Remember, f(x) is another way of writing "y".

y = √x + 11                                        <----- Original equation

x = √y + 11                                        <----- Swap variables

x - 11 = √y                                         <----- Subtract 11 from both sides

(x - 11)² = (√y)²                                  <----- Square both sides

(x - 11)² = y                                        <----- Simplify

Another way of writing the output of an inverse function is with f(x)⁻¹.

Answer:

31

Step-by-step explanation:

Substitute -10 for x in b(x)=|x+41|, obtaining f(-10) = |-10 + 41|.  This result simplifies to f(-10) = |31| = 31

Notice that

[tex]7^{2014} - 7^{2012} = 7^{2012} \bigg(7^2 - 1\bigg) = 7^{2012} \times 48 = 2^4 \times 3 \times 7^{2012}[/tex]

[tex]12=2^2\times3[/tex], so

[tex]\dfrac{7^{2014}-7^{2012}}{12} = 2^2 \times 7^{2012}[/tex]

Then taking the positive square root gives

[tex]\sqrt{\dfrac{7^{2014}-7^{2012}}{12}} = \sqrt{2^2 \times 7^{2012}} = 2\times7^{1006}[/tex]

so [tex]\boxed{a=2}[/tex] and [tex]\boxed{b=1006}[/tex].

Answer:24

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: 10x + 30 = 90[/tex]

[ according to given figure ]

[tex]\qquad \sf  \dashrightarrow \: 10x = 90 - 30[/tex]

[tex]\qquad \sf  \dashrightarrow \: 10x = 60[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 60 \div 10[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 6 \degree[/tex]

Correct choice is D

Answer: [tex]\sqrt{407}[/tex]

Step-by-step explanation:

In this triangle, we know that [tex]IJ=46, IK=24, JK=36[/tex].

So, using the Law of Cosines in triangle IJK,

[tex]36^2 = 46^2 + 24^2 - 2(46)(24) \cos (\angle JIK)\\\\-1396=-2(46)(24) \cos(\angle JIK)\\\\\cos (\angle JIK)=\frac{349}{552}[/tex]

Using the Law of Cosines in the triangle LIK,

[tex](KL)^2 = 23^2 + 24^2 - 2(23)(24) \cos (\angle JIK)\\\\(KL)^2 = 23^2 + 24^2 - 2(23)(24)\left(\frac{349}{552} \right)\\\\(KL)^2 = 407\\\\KL=\sqrt{407}[/tex]

Volume of a cylinder: PI x radius^2 x height

= 3.14 x 5^2 x 10 = 785 m^3

Volume of a cone: pi x radius^2 x height/3

= 3.14 x 5^2 x 4/3 = 104.67 m^3

Total volume  = 785 + 104.67 = 889.67 M63

Answer: C. 889.67 M^3

Answer:

[tex]\textsf{C)}\quad \sf 889.67\: m^3[/tex]

Step-by-step explanation:

The given composite solid is made up of a cylinder and a cone.

To find the volume of the composite solid, find the volume of the cylinder and the volume of the cone, then add them together.

Volume of a cylinder:

[tex]\sf V=\pi r^2 h[/tex]

(where r is the radius and h is the height)

Given:

Substitute the given values into the formula and solve for V:

[tex]\begin{aligned}\implies \sf Volume\:of\:the\:cylinder & = \sf \pi (5)^2(10)\\ & = \sf 250 \pi \:\:m^3 \end{aligned}[/tex]

Volume of a cone:

[tex]\sf V=\dfrac{1}{3} \pi r^2 h[/tex]

(where r is the radius and h is the height)

Given:

Substitute the given values into the formula and solve for V:

[tex]\begin{aligned}\implies \sf Volume\:of\:the\:cone & = \sf \dfrac{1}{3} \pi (5)^2(4)\\ & = \sf \dfrac{100}{3}\pi \:\:m^3 \end{aligned}[/tex]

Therefore, the volume of the composite solid is:

[tex]\begin{aligned}\implies \sf Volume\:of\:composite\:solid & = \sf Cylinder\:volume+Cone\:volume\\ & = \sf 250\pi + \dfrac{100}{3}\pi \\ & = \sf \dfrac{850}{3} \pi \\ & = \sf \dfrac{850}{3} \times 3.14 \\ & = \sf 889.67\:m^3\:(2\:d.p.)\end{aligned}[/tex]

The solution to the given system of linear equations is x = 1, y = 2. That is (1, 2)

From the question, we are to solve the given system of equations

The given system of equations is

4x + y = 6     -----------(1)

2x - 3y = -4   -----------(2)

From the equation (1)

4x + y = 6

y = 6 - 4x      ----------(3)

Substitute the value of y into equation (2)

2x - 3y = -4

2x -3(6 - 4x) = -4

2x -18 +12x = -4

2x + 12x = -4 + 18

14x = 14

x = 14/14

x = 1

Substitute the value of x into equation (3)

y = 6 - 4x

y = 6 - 4(1)

y = 6 - 4

y = 2

Hence, the solution to the given system of linear equations is x = 1, y = 2. That is (1, 2)

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Answer:

[tex]x^4-20x^3 +175x^2 -750x+1250[/tex]

Step-by-step explanation:

By the conjugate root theorem, 5+5i is also a root.

[tex]f(x)=a(x-5)^2 (x-5-5i)(x-5+5i) \\ \\

= a(x^2 - 10x+25)((x-5)^2 - (5i)^2) \\ \\

= a(x^2 - 10x+25)(x^2 - 10x+25+25) \\ \\

= a(x^2-10x+25)(x^2-10x+50) \\ \\

= a(x^4- 10x^3 + 50x^2 - 10x^3 + 100x^2 - 500x + 25x^2 - 250x+1250) \\ \\

= a(x^4-20x^3 +175x^2 -750x+1250) \\ \\ [/tex]

The graph that represents the inequality is:

Number line with an open circle on 1, shading to the right and an open circle on 5, shading to the left.

The inequality is:

|2x - 6| < 4

Which means that the distance of 2x - 6 to the origin is less than 4, hence:

-4 < 2x - 6 < 4.

The solution is:

2x - 6 > -4

2x > 2

x > 1

2x - 6 < 4

2x < 10

x < 5

The solution has open circles at x = 1 and x = 5, as they are not part of the solution, and the shading is in the middle, as the solution is 1 < x < 5, hence the correct option is:

Number line with an open circle on 1, shading to the right and an open circle on 5, shading to the left.

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Answer:

IV 5

Step-by-step explanation:

you have to solve for x:

x-3<2

x-3+3<2+3

x=5

could you put the brainlyest Icon for me? I have 1500 points, but no brainlyest, so I can't move up the ranks.

The correct product of (6x - 2)(6 x + 2) is 36x^2 - 4

The expression is given as:

(6x - 2)(6 x + 2).

The above expression is a difference of two squares.

And this is represented as

(a - b)(a + b)= a^2 - b^2

So, we have

(6x - 2)(6 x + 2) = (6x)^2 - 2^2

Evaluate

(6x - 2)(6 x + 2) = 36x^2 - 4

Hence, the correct product of (6x - 2)(6 x + 2) is 36x^2 - 4

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Complete question

What is the product?

(6x - 2)(6 x + 2).

The width and height of the rectangle inscribed in the right triangle have a measure of 3.529 units.

In this problem we must use critical values and algebraic methods to determine to determine the dimensions of the rectangle such that the area is a maximum. The equation of the quadrilateral is formed by definition of the area of a rectangle:

A = w · h    (1)

Where:

And the area of the entire triangle is:

0.5 · (5) · (12) = w · h + 0.5 · w · (12 - h) + 0.5 · (5 - w) · h

30 = w · h + 6 · w - 0.5 · w · h + 2.5 · h - 0.5 · w · h

30 = 6 · w + 2.5 · h

2.5 · h = 30 - 6 · w

h = 12 - 2.4 · w    (2)

The quadrilateral of maximum area is always a square, then we must  solve for w = h:

w = 12 - 2.4 · w

3.4 · w = 12

w = 3.529

Then, the width and height of the rectangle inscribed in the right triangle have a measure of 3.529 units.

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Answer: About 830 dollars

Step-by-step explanation: find 15% off on 897 then find 7.5 percent of 897, then add them together.

Answer:

here ya go :)

the black line is y=-2x-3

the lavender line is y=-x+6

The area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

Since the curves are

We find their point of intersection.

So, r² = r²

2sin(2θ) = 1²

2sin(2θ) = 1

sin(2θ) = 1/2

2θ = sin⁻¹(1/2)

2θ = π/6

θ = π/12

So, we integrate the area from θ = 0 to θ = π/12

Now the area A of the region between two curves between θ = α to θ = β is

[tex]A = \int\limits^{\beta }_\alpha ({r^{2} - r^{'2} }) \, d\theta[/tex]

So, the area betwwen the curves r² = 2sin(2θ),  r = 1 between θ = 0 to θ = π/12 is

[tex]A = \int\limits^{\frac{\pi}{12} }_0 ({r^{2} - r^{'2} }) \, d\theta \\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1^{2} }) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1}) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 {2sin2\theta}\, d\theta - \int\limits^{\frac{\pi}{12} }_0 {1} \, d\theta\\= [2(-cos2\theta)/2 - \theta]_{0}^{\frac{\pi}{12} } \\= [-cos2\theta - \theta]_{0}^{\frac{\pi}{12} } \\= -cos2\frac{\pi}{12} - \frac{\pi}{12} - ( -cos2(0) - 0)\\[/tex]

[tex]= -cos2(\frac{\pi}{12}) - \frac{\pi}{12} - ( -cos2(0) - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -cos0 - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -1)\\= -(\frac{\sqrt{3} }{2} ) - \frac{\pi}{12} + 1\\= -0.8660 - 0.2618 + 1\\= -1.1278 + 1\\= -0.1278[/tex]

So, the area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

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The inverse of the demand function is; P = 9 - 0.25Q

The profit-maximizing price and quantity are; $8.5 and 2 units.

The maximum profit is; $1

A) The demand function we are given is;

Q = 36 - 4P

Making P the subject gives the inverse demand function;

P = (36 - Q)/4

P = 9 - Q/4

P = 9 - 0.25Q

B) The profit-maximization point is the point at which MR = MC.

MR refers to the marginal revenue and MC is the marginal cost.

MC can be calculated as the first derivative of the cost function:

C(Q) = 4 + 4Q + Q²

MC = C'(Q) = 2Q + 4

Total Revenue = Price * Quantity

Total Revenue = (9 - 0.25Q) * Q

Total Revenue = 9Q - 0.25Q²

MR is gotten by differentiating Total Revenue to get;

MR = 9 - 0.5Q

Applying the condition MR = MC, we have;

9 - 0.5Q = 4 - 2Q

Solving for Q gives Q = 2

Thus, profit maximizing quantity is 2.

Thus, profit maximizing price will be;

P(2) = 9 - 0.25(2)

P(2) = $8.5

C) Formula for Maximum Profit is;

Profit = Total Revenue - Total Cost

Total Revenue = 8.5 * 2

Total revenue = $17

Total Cost is;

C(2) = 4 + 4(2) + 2²

C(2) = $16

Thus;

Maximum Profit = 17 - 16 = $1

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Take the prime factorization of each factor in the product.

[tex]\dfrac{72 \times 78 \times 85 \times 90 \times98}{68 \times 84 \times 91 \times 108} \\\\ ~~~~~~~~ = \dfrac{(2^3\times3^2)\times(2\times3\times13)\times(5\times17)\times(2\times3^2\times5)\times(2\times7^2)}{(2^2\times17)\times(2^2\times3\times7)\times(7\times13)\times(2^2\times3^3)} \\\\ ~~~~~~~~ = \dfrac{2^6 \times 3^5 \times 5^2 \times 7^2 \times 13 \times 17}{2^6 \times 3^4 \times 7^2 \times 13 \times 17} \\\\ ~~~~~~~~ = 3 \times 5^2 = \boxed{75}[/tex]

Answer:

(-1,7)

Step-by-step explanation:

Use elimination, x = -1, y = 7

Answer:

(-1, 7)

Step-by-step explanation:

Elimination: Step 1

Write in standard form (you can have negatives)

(standard form= Ax+By=C)

Elimination: Step 2

Create(find) opposites

Elimination: Step 3

Add to cancel one variable

Elimination: Step 4

Solve for variable

Elimination: Step 5

Substitute into other equation to find other variable

In a linear system of equations, substitution results in one equation with one variable. The solution to a linear system is an ordered pair, not just a single value.

Problem:

Solve 2x+y=5;x+y=6

Steps:

I will solve your system by substitution.

(You can also solve this system by elimination.)

2x+y=5;x+y=6

Step: Solve 2x+y=5 for y:

2x+y+−2x=5+−2x(Add -2x to both sides)

y=−2x+5

Step: Substitute −2x+5 for yin x+y=6:

x+y=6

x+−2x+5=6

−x+5=6(Simplify both sides of the equation)

−x+5+−5=6+−5(Add -5 to both sides)

−x=1

-x/-1 = 1/-1 (Divide both sides by -1)

x=−1

Step: Substitute −1 for x in y=−2x+5:

y=−2x+5

y=(−2)(−1)+5

y=7(Simplify both sides of the equation)

Answer:

x=−1 and y=7

Answer:

89.4 - 13.621 = 75.779

Explanation:

Subtract 13.621 from 89.4 to get 75.779.

El dinero que le falta a Maritza y su esposo para viajar es 330.

Para calcular el dinero que les falta debemos identificar la cifra total que les va a costar el viaje:

El valor total del viaje es s/3,130, entonces les faltarían s/330.

3,130 - 2,800 = 330

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The area of the circle with the given circumference is: 42.25π in.².

Area = πr²

Circumference = 2πr.

Given the following:

Circumference of the circle = 13π in.

Find the radius (r):

2πr = 13π

Divide both sides by 2π

2πr/2π = 13π/2π

r = 13/2

r = 6.5

Area = πr² = π(6.5²) = 42.25π in.²

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