A neutral atom has high electronegativity.

Describe what happens to this atom during ionic bond formation.

Answer:

56.6g

Explanation:

Given that :

Mass of water, m1= 300.0 g

Temperature of water, T1= 22°C

Specific heat capacity of water, C= 4.184 J/g°C

Mass of polystyrene, m2=?

Temperature of polystyrene = 94.9

Specific heat capacity of polystyrene, c2= 1.88 J/g°C

Final temperature = 27.7 oC

Heat lost by polystyrene = Heat gained by water

mc(dT) = mc(dT)

m2 * 1.88 * (94.9 - 27.7) = 300 * 4.184 * (27.7 - 22)

m2 * 1.88*67.2 = 300*4.184*5.7

126.336 * m2 = 7154.64

m2 = 7154.64 / 126.336

m2 = 56.631838

Hence, mass of polystyrene = 56.6g

Answer:

It is 148.82 L

Explanation:

I need more points. And I hope this helps.

Answer:

oh ok

Explanation:

Answer:

pressure

volume

was constant

Boyle's

Explanation:

Answer:

the first one is pressure &volume the second one is was constant the third one is Boyle's

Explanation:

Answer:

balancing the equation?

[tex]\displaystyle 6 \ mol \ N_2[/tex]

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Balanced] N₂ + 3H₂ → 2NH₃

[Given] 12 mol NH₃

[Solve] x mol N₂

Step 2: Identify Conversions

[RxN] 1 mol N₂ → 2 mol NH₃

Step 3: Stoich

Answer:

[tex]\boxed {\boxed {\sf 6 \ moles \ of \ N_2}}[/tex]

Explanation:

1. Balance Equation

We are given the reaction:

[tex]1 N_2+3H_2 \rightarrow 2 NH_3[/tex]

The equation is already balanced. Both sides have 2 moles of nitrogen and 6 moles of hydrogen.

2. Conversions

In this reaction, 1 mole of nitrogen produces 2 moles of nitrogen tryhdride:

[tex]1 \ mol \ N_2 \rightarrow 2 \ mol \ NH_3[/tex]

3. Stoichiometry Calculations

Use the conversion rate as a fraction.

[tex]\frac{ 1 \ mol \ N_2}{2 \ mol \ NH_3}[/tex]

Multiply the number of moles of nitrogen trihydride produced: 12 moles.

[tex]12 \ mol \ NH_3 *\frac{ 1 \ mol \ N_2}{2 \ mol \ NH_3}[/tex]

The moles of nitrogen trihydride cancel.

[tex]12 *\frac{ 1 \ mol \ N_2}{2} = \frac{ 12 \ mol \ N_2}{2}[/tex]

[tex]6 \ mol \ N_2[/tex]

6 moles of nitrogen are needed to produce 12 moles of nitrogen trihydride.

Answer:

how to rapidly separate red#40 from ZnO

Red #40 is soluble in water while zinc oxide is not. 4- heat the solution of red #40 and water until water evaporates and red#40 remains

hope it's help

Answer:

the answer is C

Explanation:

Answer:

118.85 degrees celsius (not sure if it is)

Answer:

118 is correct

Explanation:

:)

Answer:

5230 J

Explanation:

m = 25 g = 0,025 kg

c = 4,184 J /(g * °C) = 4184 J /(kg * °C)

[tex]t_{1}[/tex] = 80 °C

[tex]t_{2}[/tex] = 30 °C

The formula is Q = c *m * ([tex]t_{2} - t_{1}[/tex])

Calculating:

Q = 4184 * 0,025 * (30 - 80) = 5230 J

Note that we get a negative heat (-5230 J). It just means that it is released.

The amount of heat will be 5230 j.

What is heat?

Heat is a type of energy that is transferred between both the system and its surroundings as a result of temperature variations.

Calculation of heat.

Given data:

Mass = 25.0 g = 0.025 kg

C = 4.184 J/g°C

[tex]T_{1}[/tex] =  80.0°C

[tex]T_{2}[/tex] = 30.0°C

Q= ?

By using the formula of heat.

Q = MC ([tex]T_{2} - T_{1}[/tex])

Put the value of given data in heat equation.

Q(heat)  = 0.025  × 4.184  ( 30 - 80)

Q(heat) = 5230 J.

Therefore, the amount of heat will be 5230 J.

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Scientists uses scientific methods and well designed experiments to solve a scientific question. They can use some laws and previous scientific records as an aid.

A scientific question arises from selected topic under study. A scientific question addresses a natural phenomenon, a socially relevant problem or a any personal curiosity.

The scientific question must be testable. The first prediction for the question based on observation and scientific records is called the hypothesis.

The hypothesis must be tested using a well designed scientific experiment based on a scientific method. The methodology should be clearly specify what to collect and how to use them. Hence, option B is correct.

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Answer:

0.415 j/g°C

Explanation:

Given that :

Mass of water, m1= 250.0 g

Temperature of water, T1= 25°C

Specific heat capacity of water, C= 4.184 J/g°C

Mass of brass , m2= 51.1g

Temperature of brass = 95.4°C

Specific heat capacity of brass , c2=?

Final temperature = 26.4°C

Heat lost by brass = Heat gained by water

mc(dT) = mc(dT)

51.1 * c * (95.4 - 26.4) = 250 * 4.184 * (26.4 - 25)

51.1 * 69 * c = 250 * 4.184 * 1.4

3525.9c = 1464.4

c = 1464.4 / 3525.9

c = 0.4153265

c = 0.415 j/g°C

Specific heat capacity of Brass for the experiment = 0.415 j/g°C

Answer:

c

Explanation:

Answer:

Number three, because precipitation is rain, which comes from cumulonimbus clouds. Precipitation happens when clouds have accumulated enough evaporated water for the cloud to get heavy and need to get rid of some of the water, which it does through condensing the water and then delivering it as rain.

Hope this helps! Have a wonderful day! (Please give me brainliest and thank you!)

:)

Answer: 15.0 g of [tex]CCl_4[/tex] will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Cl_2=\frac{27.7g}{71g/mol}=0.390moles[/tex]

The balanced chemical reaction is:

[tex]CS_2(g)+4Cl_2(g)\rightarrow CCl_4(l)+2SCl_2(s)[/tex]

[tex]Cl_2[/tex] is the limiting reagent as it limits the formation of product and [tex]CS_2[/tex] is the excess reagent.

According to stoichiometry :

4 moles of [tex]Cl_2[/tex] give=  1 mole of [tex]CCl_4[/tex]

Thus 0.390 moles of  will give = [tex]\frac{1}{4}\times 0.390=0.0975moles[/tex] of [tex]CCl_4[/tex]

Mass of [tex]CCl_4=moles\times {\text {Molar mass}}=0.0975\times 154=15.0g[/tex]

Thus 15.0 g of [tex]CCl_4[/tex] will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide

Answer:

methyl, ethyl,

Explanation:

that should be the case

Answer:

Numbers after atoms are subscripts. Numbers before atoms are coefficients.

Equation: 2Na +Cl2 -> 2NaCl

Given: 6.8 grams of Na  

Unknown: moles of NaCl

Set up: [tex]6.8g Na *\frac{1 mole Na}{22.99 g Na}*\frac{2 moles NaCl}{2 moles Na} =.2957 moles NaCl[/tex]

Explanation:

We know that the reactants are Na and Cl and that what is being produced, the products, is NaCl.

Na + Cl -> NaCl

CAREFUL! Cl is a diatomic ion, is it gets a subscript of 2! This means there need to be 2 cl atoms on the right side as well. But now there are 2 Na on the right side. So we multiply Na by 2 on the left so that both sides have two Na atoms.

2Na +Cl2 -> 2NaCl

B)

We know that there are 6.8 grams of Na. This is our given.

What do we want to find out? We want to find how many moles of NaCl there are, so that is our unknown.

C) A mole ratio is exactly what it sounds like. From our balanced equation, we can see that there are 2 moles of Na  and 2 moles of NaCl. In other words, there are 2 moles of Na for every 2 moles Nacl. In notation, this is [tex]\frac{2 mole Na}{2 Mole NaCl}[/tex] or 2:2. You can simplify to 1:1 ratio, but as equations get more complex I find it easier to not. It depends on what your teacher wants and what you find easier.  

D)

By set up I assume they mean stoichiometry (chemistry conversion) . First I'm going to split up the set up so that it is easier to understand.

We start with the given and convert that into moles Na. We can do this by remembering that there are 22.99 grams for every 1 mole Na:

6.8 g Na* [tex]\frac{1 mole Na}{22.99g Na} = .2957 moles Na[/tex]

Now we can use that mole ration we found in part C to convert moles of Na into moles of NaCl:

[tex].2957 moles Na *\frac{2 moles NaCl}{2 moles Na}= .2957[/tex]

Usually, we will put these together to get

[tex]6.8g Na *\frac{1 mole Na}{22.99 g Na}*\frac{2 moles NaCl}{2 moles Na} =.2957 moles NaCl[/tex]

Tip: in Stoichiometry, it is important to remember that your units should cancel out until you only have the units you want. If there are moles of Na in the numerator, there should be moles of Na in the denominator of the following fraction. If there are grams Na in the numerator, there should be grams Na in the denominator and so and so on until you are only left with the unit you want, which, in this case, is moles of NaCl.  

Answer:

B

Explanation:

"The temperature increases cause the rate of a reaction to increases the kinetic energy"

What is rate of reaction?

The reaction rate, also known as the rate of reaction, is the rate for which a chemical reaction occurs, and is proportional to increase in product concentration per unit time and the reduction in reactant concentration per unit time. The rate of reaction varies greatly.

What is kinetic energy?

An object's kinetic energy is the energy it has as a result of its motion. It is the amount of work required to push a body of a given mass from rest to a certain velocity. The body keeps its kinetic energy gained during acceleration unless that speed changes.

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Answer:

rocket fuel burning i think

Answer:

Distillation columns are used to separate mixed feed streams into their own distinct products.

Explanation:

The primary function of the distillation column is to separate the feed stream into (at least) one highest level product stream and one bottom product stream. The performance of the column separation can be justified by the purity of the upper and lower product streams.

Answer:

1)4180j

2)15000kj

Explanation:

[tex]1) E=100*(30-20)*4.18=4180j\\2)Q=.5*30*1000=15000kj[/tex]

Answer:

the work done on the gas is 4,988.7 J.

Explanation:

Given;

number of moles of the monoatomic gas, n = 4 moles

initial temperature of the gas, T₁ = 300 K

final temperature of the gas, T₂ = 400 K

The work done on the gas is calculated as;

[tex]W = \Delta U = nC_v(T_2 -T_1)[/tex]

For monoatomic ideal gas: [tex]C_v = \frac{3}{2} R[/tex]

[tex]W = \frac{3}{2} R \times n(T_2-T_1)[/tex]

Where;

R is ideal gas constant = 8.3145 J/K.mol

[tex]W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W = \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J[/tex]

Therefore, the work done on the gas is 4,988.7 J.

Answer:

B carbon

Explanation:

guessed

Explanation:

2,6-Dibromo-4-isopropylphenol

2432-16-8

2,6-dibromo-4-propan-2-ylphenol

Phenol, 2,6-dibromo-4-(1-methylethyl)-

4-isopropyl-2,6-dibromophenol

Answer:

0.093 M

Explanation:

First, we assume that the density of household hydrogen peroxide is 1 g/mL. We also assume that there's no reaction between hydrogen peroxide and sodium carbonate, if there were, in the end all hydrogen peroxide would be consumed.

Now we calculate how many grams of H₂O₂ were added, using the given volume, concentration and density:

We convert grams to moles:

0.45 g H₂O₂ ÷ 34 g/mol = 0.013 mol H₂O₂

Now we divide the number of moles by the final volume, to calculate the molarity of H₂O₂:

Based on the given concentration of the original hydrogen peroxide solution, the molarity of the hydrogen peroxide (in mol/L) of the final solution is 0.093 M.

Assuming that the density of household hydrogen peroxide is 1 g/mL and that no reaction occurs between hydrogen peroxide and sodium carbonate.

The mass in grams of H₂O₂ added is first determined using the given volume, concentration and density:

mass = 15 mL *  1 g/mL * 3g/100g  = 0.45 g H₂O₂

Moles of H₂O₂ is determined as follows:

molar mass of H₂O₂ = 34 g/mol

moles of H₂O₂ = 0.45 g H₂O₂ / 34 g/mol

moles of H₂O₂ = 0.013 mol H₂O₂

molarity of H₂O₂ is then calculated as follows:

final volume = 15 mL + 120 mL + 5 mL = 140 mL

final volume = 140 mL / 1000 = 0.140 L

molarity = 0.013 mol H₂O₂ / 0.140 L

molarity of H₂O₂ = 0.093 M

Therefore, the molarity of the hydrogen peroxide (in mol/L) of the final solution is 0.093 M.

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Answer:

The two spots will move up the plate.

Explanation:

We have to first understand the rudiments of chromatography. In chromatography, there is a stationary phase and a mobile phase. The stationary phase does not move. In this case, the stationary phase is the TLC plate.

The mobile phase is the solvent used to perform the chromatography. The movement of the spots depends on the composition of the solvent.

When neat hexane was used, only one spot was moved. This must be due to the interaction of the nonpolar hexane with the less polar compound. However, when a 50/50 mixture of hexanes and ethyl acetate is used, the both compounds are found to move up the plate.

Answer:

A. 2.65 atm.

B. 18.11 g/L.

Explanation:

A. Determination of the pressure

Mass of N₂O = 21.3 g

Volume = 5.76 L

Temperature (T) = 111 °C

Pressure (P) =.?

First, we shall determine the number of mole in 21.3 g of dinitrogen monoxide, N₂O. This can be obtained as follow:

Mass of N₂O = 21.3 g

Molar mass of N₂O = (14×2) + 16

= 28 + 16

= 44 g/mol

Mole of N₂O =?

Mole = mass /Molar mass

Mole of N₂O = 21.3/44

Mole of N₂O = 0.484 mole

Next, we shall convert 111°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 111 °C

Temperature (T) = 111 °C + 273

Temperature (T) = 384 K

Finally, we shall determine the pressure. This can be obtained as follow:

Number mole of N₂O = 0.484 mole

Volume = 5.76 L

Temperature (T) = 384 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =.?

PV = nRT

P × 5.76 = 0.484 × 0.0821 × 384

Divide both side by 5.76

P = (0.484 × 0.0821 × 384) / 5.76

P = 2.65 atm

B. Determination of the density of CFCl₃

Temperature (T) = 157°C

Pressure (P) = 4.65 atm.

Density of CFCl₃ =?

First, we shall determine the molar mass of CFCl₃. This can be obtained as follow:

Molar mass of CFCl₃ = 12 + 19 + (35.5×3)

= 12 + 19 + 106.5

= 137.5 g/mol

Next, we shall convert 157°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 157 °C

Temperature (T) = 157 °C + 273

Temperature (T) = 430 K

Finally, we shall determine the density of CFCl₃. This can be obtained as follow:

Temperature (T) = 430 K

Pressure (P) = 4.65 atm.

Molar mass of CFCl₃ (M) = 137.5 g/mol

Gas constant (R) = 0.0821 atm.L/Kmol

Density (D) of CFCl₃ =?

D = PM / RT

D = (4.65 × 137.5) / (0.0821 × 430)

D = 18.11 g/L

Answer:

0.0723371390261859