The angle must be formed if the tension in each cable is equal to 0.75 of the frame weight is 83.6⁰.
By using the parallelogram law of vector addition, it is possible to calculate the angle between the two wires.
a² + b² - 2abcosθ = R²
Where;
R = is the outcome vector = the frame's weight ⇒ W
Angle between the two wires equals 0.75W for the first wire's tension and 0.75W for the second wire's tension.
(0.75W)² + (0.75W)² - 2(0.75W x 0.75W) cosθ = W²
1.125W² - 1.125W² cosθ = W²
= 1.125W²(1 - cosθ)
W²/1.125W² = 1 - cosθ
0.8889 = 1 - cosθ
cosθ = 1 - 0.8889
cos θ = 0.1111
θ = arc cos(0.1111)
θ = 83.6⁰
So, the angle must be formed if the tension in each cable is equal to 0.75 of the frame weight is 83.6⁰
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When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. What is the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d?
plsss help
According to Newton's law of gravitation, the new gravitational force will be F/9
Newton's Law of GravitationIt states that, the force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. That is,
F = GMm/d²
Where
M = mass of the earthm = mass of the satelliteG = universal gravitational constantThe magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d can be expresses as follow
f = GMm/(3d)²
f = GMm/9d²
f = GMm/d² × 1/9
Since GMm/d² = F
f = F × 1/9
f = F/9
Therefore, the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d is F/9 Newton
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Please help
How does sound move from the source to the receiver? (a slinky moving back and forth)
Answer:
through a chain reaction of particle collisions in a medium.
Explanation:
1) Renatta Gass is out with her friends misfortune occurs and renatta and her Friends find themselves getting a workout. They apply a cumulative force Of 1580N to push the car 288m to the nearest fuel station. Determine the work done on the car.
Work is characterized as a force that causes an object to move or be displaced. The work done would be 455040.
What is Work?Work is the scalar product of the force acting on an object and the displacement that force causes when the force is constant.
Despite the fact that work lacks a direction due to the scalar product (or dot product) aspect of vector mathematics, force and displacement are both vector quantities.
"W" stands for work, "F" is the force, and "d" represents displacement (or the distance the object travels).
Therefore, Work is characterized as a force that causes an object to move or be displaced. The work done would be 455040.
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the first artificial satellite to orbit the earth was sputnik 1, launched october 4, 1957. the mass of sputnik 1 was 83.5 kg, and its distances from the center of the earth at apogee and perigee were 7300 km and 6610 km, respectively. find the difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee
The difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee is 193 kJ.
The gravitational potential energy of an object in orbit around the Earth can be calculated using the equation:
U = -GMm/r
where U is the gravitational potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object.
The difference in gravitational potential energy as the satellite moves from apogee to perigee can be found by calculating the potential energy at each point and subtracting the two values:
U(apogee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (7300 x 10^3 m)
U(perigee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (6610 x 10^3 m)
U(apogee) = -1.865 x 10^5 J
U(perigee) = -2.058 x 10^5 J
The difference in gravitational potential energy is:
= U(perigee) - U(apogee)
= -2.058 x 10^5 J - (-1.865 x 10^5 J)
= 193 x 10^3 J
So, the difference in gravitational potential energy for Sputnik 1 as it moved from apogee to perigee is 193 kJ.
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You went to move a 41 kg bookcase to a different place in the living room. If you push with a force of 65 N and the bookcase accelerates at 0. 12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet?
If you push with a force of 65 N and the bookcase accelerates at 0. 12 m/s2. The answer to the given question is A65=41×A.A=1.2m.
Explanation of the given answer:Functions and co efficients are: Ff=μkFN F f = μ k F N
The equation for kinetic friction, where FN is the object's normal force and k is the coefficient of kinetic friction.
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula which is fr = Fr/N serves as a representation of kinetic friction.
The primary distinction between static and kinetic friction is that kinetic friction occurs when there is relative motion between the surfaces, whereas static friction occurs when the surfaces are at rest.
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Ammeters that respond to the average value convert the alternating current into direct current. This value must be increased by a factor of _____ to change the average reading into the rms value for a sine wave current.
The average reading must be multiplied by a multiplier of 1.111 to become the rms value for just a sine wave flow.
Describe the wave current?Wave-current interaction in fluid dynamics is the interaction of a mean flow with surface gravity waves.After the interaction begins, both the waves as well as the average flow are impacted since the contact implies an energy exchange.
What are the tide and the wave?While the tide is a type of vertical motion of the ocean's water, waves and ocean circulation represent horizontal movements of the water.
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Define the following
a. Velocity:
b. Inertia:
c.Speed:
e Force:
f. Balanced force:
g. Net force:
h. Displacement:
Answer:
Explanation:
a.speed with direction associated
b.the ability to resist motion
c.The rate of change of position of an object
e.any influence object's motion
f.forces cancel out, create equilibrium
g.total force acting on an object
h. change in position of an object (total distance from starting point)
Write down whether quantity of potential kinetic and total energy
Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
What is Potential energy?The earth can pull you down through the force of gravity while doing work in the process, being at the top of a stairwell gives you more potential energy than standing at the bottom.
Two magnets have more potential energy when they are held apart than when they are near to one another. They will migrate near each other and begin working if you let them go.
The force acting on the two objects affects the potential energy formula. P.E. = mgh, where m is the mass in kilograms and g is the acceleration due to gravity, is the formula for gravitational force.
Therefore, Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
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A meter‑long wire of mass 185 g is attached to a 60. 0 Hz mechanical wave oscillator operating at 139 W. The far end of the wire is strung over a frictionless, massless pulley, and a 306 g mass is hung from it. When the oscillator is turned on, it produces a sinusoidal wave in the wire. Calculate the amplitude of oscillation of the wire. Use the value 9. 81 m/s2 for the acceleration due to gravity
The tension in the wire is 2.99986 N. The amplitude of the oscillation of the wire is approximately 0.01067 meters.
The tension (T) can be calculated using the equation:
T = m × g
T = 0.306 × 9.81
T = 2.99986 N
The linear mass density (μ) of the wire is given by the mass per unit length of the wire. It is calculated as:
μ = m(wire) ÷ L(wire)
μ = 0.185 ÷ 1
μ = 0.185 kg/m
The speed (v) of the wave on the wire can be determined using the equation:
v = √(T ÷ μ)
v = √(2.99986 ÷ 0.185 )
v = 7.351 m/s
The power (P) transmitted by the wave is related to the amplitude (A) and the speed (v) of the wave through the equation:
P = 2π² × μ × v × A² × f²
A² = P ÷ (2π² × μ × v × f²)
A² = 139 ÷ (2π² × 0.185 × 7.351 × (60.0)²)
A² = 1.138 × 10⁻⁴
A = √(1.138 × 10⁻⁴)
A = 0.01067 m
Therefore, The amplitude of the oscillation of the wire is approximately 0.01067 meters.
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A 50 kg person and a 70 kg person are sitting on a bench close to each other about .5 m apart.
Estimate the magnitude of the gravitational force each exerts on the other.
Answer:
1.0 x 10-6 N.
Explanation:
The gravitational force
Fg = G m1 m2 / r2 = (6.673 x 10-11) (50 kg) (75 kg) / (0.50 m)2 = 1.0 x 10-6 N.
What is the velocity of the particle at time t 0?
The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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can u pls solve this question thank u!! i having my physics paper tomorrow!!
Answer:
13.875Ω & 5Ω
Explanation:
in the first diagram:-
R = Rs + Rp + Rs'
Rp => [tex]\frac{1}{7} + \frac{1}{1} = \frac{1+7}{7} = \frac{8}{7} \\[/tex]
Rp = [tex]\frac{7}{8}[/tex] = 0.875
4 + 0.875 + 9 = 13.875Ω
in the second diagram:-
R= Rp + Rs + Rp'
Rp => 1/6 + 1/3 = 1+2/6 = 3/6 => 2
Rp' => 1/3+1/3+1/3 = 3/3 => 1
R = 2 + 2 + 1 = 5 Ω
A student is connecting three resistors of various resistances together in a circuit. In one configuration, the resistors are connected in a series. In another configuration, the resistors are connected in parallel. Explain which configuration results in a higher total resistance.
Most circuits contain more than one resistor, which restricts the passage of charge inside the circuit. Resistance is a unit of measurement for this charge flow restriction.
What is Resistance?When a current, or flow of charge, must pass through a sequence of devices, resistors are used. For instance, if a person holding a screwdriver allows current to flow through them and into the Earth, then
Resistors are connected in series to a voltage source. Given that the current must flow sequentially through each resistor, it makes sense that the total resistance is equal to the sum of the individual resistances.
This fact would be helpful to someone trying to prevent an electrical shock since they could wear high-resistance rubber-soled shoes to lower the current.
Therefore, Most circuits contain more than one resistor, which restricts the passage of charge inside the circuit. Resistance is a unit of measurement for this charge flow restriction.
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The human ear canal is about 2. 8 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the frequency around which we would expect hearing to be best when the speed of sound in air is 344. 5 m/s? (hint: find the fundamental frequency for the ear canal. )
The human ear canal is closed at one end. Thus, the fundamental frequency of the given ear canal is 3044.64Hz 3044.64 Hz .
Calculation and Explanation:Under air conduction (AC) excitation, the mean resonance frequency of the human middle ear is estimated to be between 0.8 and 1.2 kHz. The typical resonance frequency under bone conduction (BC) excitation, according to research, is higher, at 1.5–2 kHz.
It is a tube with an open end (the concha section) and a closed end (the tympanic membrane), which responds to a quarter-wave by behaving as a resonator. The resonance frequency is described by the equation F=v/4L, where "v" stands for the speed of sound and "L" for the length of the EAC.
The EAR formula should be used: EAR = (1+ i/n)n - 1. I = Stated interest rate, etc.
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anthony walks to the pizza place for lunch. he walks 1 km east then 2 km south and then 1 km east again. what distance did he cover and what was his displacement
Answer:
3 km displacement
Explanation:
I'm pretty sure that's the answer, I'm so sorry if it's not
A wheel rotates at 2 rad/s. What is its period and frequency?
(1) The frequency of the oscillation is 0.32 Hz.
(2) The period of the oscillation is 3.13 seconds.
What is the period of the wheel's oscillation?
The period of the wheel's oscillation is the time taken for the wheel to make one complete oscillation.
The period of an oscillatory motion is the reciprocal of the frequency of the oscillation.
The frequency of the oscillation is the number of cycles completed by the oscillatory object in a given second.
The frequency of the wheel undergoing oscillatory motion is calculated by using the following formula.
f = ω / 2π
where;
ω is the angular speed of the wheelf is the frequencyf = ( 2 rad/s ) / 2π
f = 0.32 Hz
The period of the oscillation is calculated as follows;
T = 1 / f
T = 1 / 0.32 s
T = 3.13 seconds
Thus, the period of oscillation and frequency of the oscillation are inversely proportional.
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A 64 g plastic ball is moving to the left at 24 m/s . How much work must be done on the ball to cause it to move to the right at 24 m/s
The ball requires a total of zero work to go to the right at 24 m/s.
Take into account the ball's kinetic energy.
Vi = -24 ms-1 for the initial velocity
Final velocity: vf = +24ms⁻¹
K = 12mvf²- 12mvi² = 12m(vf² - vi²) = 12m(242 - 242) = 0,
meaning that the ball does not undergo any effort.
As an alternative, think about the effort made to stop the ball.
W1 = ½m(0 – 24²) = 0.5 × 0.06 × –576 = –17.28J
Work required to accelerate the ball from rest to +24 milliseconds per second was W2 = 12m(242 - 0) = 0.5 0.06 576 = +17.28 J.
Therefore, the sum of the work is W = W1 + W2 = -17.28 + 17.28 = 0 J.
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A 600 g steel block rotates on a steel table (μk = 0.6) while attached to a 1.0 m long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.2 N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 50 N. If the block starts from rest, how many revolutions does it make before the tube breaks?
If the block starts from rest, then revolutions that it make before the tube breaks is 0.947 rotations.
What is meant by revolution?When object turns around an internal axis, it is called a rotation. When object circles an external axis, it is called revolution.
Given mass of block = 600 g = 0.6 kg ; Radius of rotation = 1.0 m-long
Given thrust force of 4.2 N
The maximum tension is 50 N.
As thrust is perpendicular to the tube. So, tangential component of the thrust force is Ft=4.2 N and radial component Fr=0
As we know, α = F/m r
= 4.2/0.6 * 1
α = 7 rad/s²
As, m r ω²= 50 N
ω² = 50/ 0.6 * 1.0
ω = 9.128 rad/s
Ф = ω² - ω0²/2α
= (9.128² - 0)/2 * 7
Ф = 5.951 rad
As 1 Radians = 0.1592 Rotations,
5.951 rad = 0.947 rotations.
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a force of 15 N is used to push a box along the floor a distance of 3 meters. find the amount of work done
Answer:
The amount of work done is 45 J.
Explanation:
We know that the force applied is 15N. The amount of displacement experienced by the box is 3 metres along the floor.
Thus, F= 15N
D= 3 metres
The formula for calculating work done is W= F×D
Thus, W=15×3
W=45J
Thus, the amount of work done is 45J.
two objects gravitationally attract with a force of 36 N if the distance between the two objects centers is decreased by a factor of threee then the new force of attraction is
The new force of attraction is 324N if the distance between the centres of the two objects is reduced by a factor of 3e.
The equation for the force of gravitational attraction between two objects is: F = G*(m1*m2)/r^2 Where F is the force of attraction, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers. If the distance between the two objects' centers is decreased by a factor of three, the new force of attraction will be: F' = G*(m1*m2)/(r/3)^2The ratio of the new force of attraction to the original force of attraction is:
F'/F = (r/3)^2 If we substitute in the original force of attraction, we have:
F'/36 = (r/3)^2 = F' = 36 * (r/3)^2
As we decrease the distance by a factor of 3, the new force of attraction will increase by a factor of 9.
F' = 36*9 = 324 N
Therefore, the new force of attraction is 324 N.
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In a football game, a 140 kg linebacker runs at a speed of 4 m/s while a 70kg safety runs at 8m/s. It is correct to say
Yes, the given statement is correct in a football game, a 140 kg linebacker runs at a speed of 4 m/s while a 70kg safety runs at 8m/s.
What connection exists between mass and velocity?Momentum is directly proportional to mass and velocity. The momentum of the object increases proportionally as either mass or velocity are increased. The momentum is doubled for every unit increase in mass or speed.
In first case
Momentum = mass × velocity
Momentum = 140 × 4
Momentum = 560 kg.ms⁻¹
In second case
Momentum = mass × velocity
Momentum = 70 × 8
Momentum = 560 kg.ms⁻¹
In both cases momentum is same so the given statement is correct.
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The centripetal force on object M as it passes
through the rest position is approximately
Since the particle always moves in a circular motion in a direction perpendicular to the radial direction.
The work done by the centripetal force in a circular motion is therefore always zero since the dot product is always zero. A force known as the centripetal force acts on a particle when it is revolving around a specific axis or point. The circular path's center is where this force is directed. The ideal decision is (d) Therefore, the body's weight will be equal to the centripetal force when the angular acceleration reaches the same level as the acceleration caused by gravity. It should be noted that for the centripetal force to equal the weight, there must be a uniform circular motion.
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At an outdoor physies demonstration, a delay of 0.50 second was observed between the time sound waves left a loudspeaker and the time these sound waves reached a student through the air. If the air is at STP, how far was the student from the speaker? (1) 1.5 × 10-m (91.7 × 102 m (3) 6.6 × 10? m (4) 1.5 × 108 m
The distance that is covered by the sound is 1.66 * 10^2 m.
What is the distance?We know that sound is a mechanical wave. The implication of this is that sound woulod need to have a medium through which the sound can be able to travel. The speed of sound in the various media through which the sound travels is not the same.
We know that the speed of sound in air is 331 m/s and we have to use this in our calculations.
Distance = speed * time
Distance = 331 m/s * 0.5 s
= 1.66 * 10^2 m
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Stephen has to drive 8 miles south and 3 miles east to get to work.What is his distance and displacement?
Since the displacement is a vector quantity, the distance is 11 miles while displacement is 8.5 miles
What is Displacement ?Displacement is a distance travelled in a specific direction. Distance is a scalar quantity while displacement is a vector quantity.
Given that Stephen has to drive 8 miles south and 3 miles east to get to work.
His distance will be 8 miles + 3 miles = 11 miles
While his displacement can be calculated by using Pythagoras theorem. That is,
Displacement D = √(8² + 3²)
D = √(64 + 9)
D = √73
D = 8.5 miles
Therefore, his distance is 11 miles and his displacement is 8.5 miles.
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Assume air resistance is negligible unless otherwise stated. Calculate the displacement in m and velocity in m/s at the following times for a rock thrown straight down with an initial velocity of 14.4 m/s from the Verrazano Narrows bridge in New York City. The roadway of this bridge is 70.0 m above the water. (Enter the magnitudes.) (a) 0.500 s displacement m velocity m/s (b) 1.00 s displacement m velocity m/s (c) 1.50 s displacement m velocity m/s (d) 2.00 s displacement m velocity m/s (e) 2.50 s displacement m velocity m/s
Answer:
(a) 0.500 s displacement 70.0 m - 7.2 m velocity 7.2 m/s
(b) 1.00 s displacement 70.0 m - 28.8 m velocity -13.6 m/s
(c) 1.50 s displacement 70.0 m - 57.6 m velocity -20.4 m/s
(d) 2.00 s displacement 70.0 m - 92.8 m velocity -24.0 m/s
(e) 2.50 s displacement 70.0 m -134.4 m velocity -25.2 m/s
What causes diffusion in cells?
The causes diffusion in cells are, temperature, area of interaction, the size of the concentration gradient.
1) Temperature, The rate of diffusion increases as temperature rises.
2) Area of Interaction: The rate of diffusion increases as the surface area of interacting molecules increases.
3) The Size of the Concentration Gradient: The rate of diffusion is higher the greater the concentration gradient between the regions.
Higher the rate of diffusion, the more concentration between the locations. The movement is forced because of the increased pressure that the higher concentration creates. The movement of molecules from a location of higher concentration to a region of lower concentration can be used to define diffusion. The continuous motion (or kinetic energy) of atoms in matter is the primary cause of diffusion.
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two blocks are connected by a string of negligible mass that passes over massless pulleys
If two blocks are connected by a string of negligible mass that passes over massless pulleys, the system can be analyzed using the principles of Newton's second law and the conservation of energy.
In this scenario, the net force acting on each block is the tension in the string, which is equal in magnitude for both blocks.
Therefore, if the blocks have different masses, they will have different accelerations.
In this scenario, the mechanical energy of the system is the sum of the gravitational potential energy and the kinetic energy of the blocks. If the pulleys are massless and frictionless, then the mechanical energy of the system will be conserved.
In summary, the two blocks will move together with the same acceleration if the pulleys are massless and frictionless.
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A point particle of charge -5.40 nC is located at the origin of a Cartesian coordinate system. Determine the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge.
The magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is 918.7 N/C.
Given that,
Charge on point particle Q = -5.4 nC = -5.4 × 10⁻⁹ C
Distance from the charge r = 23 cm = 23 × 10⁻² m
The relation between distance charge and electric field is known to be,
E = 1/4πε₀ × Q/r² = 9 × 10⁹ × (-5.4 × 10⁻⁹)/(23 × 10⁻²)² = (9 × 5.4)× 10⁴/(23)² = 918.7 N/C
Thus, the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is calculated to be 918.7 N/C.
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4. A 55.0 g object connected to a spring with a force constant of 35.0 N/m oscillates on a horizontal, frictionless surface with an amplitude of 8.00 cm. a) Find the total energy of the system. 112 mJ b) Find the speed of the object when the position is 1.20 cm.
According to the given data the total energy (E) of the system is 11.2 m J.
What is an illustration of oscillation?A periodic movement between two sites is what is referred to as oscillation in this type of behavior. Examples of oscillating motion include plucking a guitar string, pendulum swinging, and pogo stick bouncing. The major distinction between oscillation, vibration, and simple harmonic motion is that oscillation is a general term for any repeating fluctuation about a central value, whereas vibration is a term used especially to describe mechanical oscillations.
Energy is given by-
E= 1/2KA²
E = 1/2 ×N/m× (8×10∧-2 m)²
E = 11.2 m J
Speed of the object-
v = ω[tex]\sqrt{A2-x2}[/tex]
v = [tex]\sqrt{K/m}[/tex] [tex]\sqrt{A2 - x2}[/tex]
v = [tex]\sqrt{35/55*10-3}[/tex] ×( (8×10-2)∧-2 - (1.20 × 10-2)∧2 )[tex]^{-1/2}[/tex]
v = 25.22 × 0.079
v = 2 m/s.
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What is the acceleration of the particle at t 0?
The acceleration of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Acceleration is the rate of change of velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction. Acceleration of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of wee can calculate. Hence by the primary information that we have we can formerly consider that the acceleration which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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