A pizza delivery man has to lift a very large pizza a height of 3.85cm higher than he is already holding it to meet the outstretched arms of the customer. if it takes 116 kj of work on the pizza to lift it this high, what force does he exert on the pizza

Answers

Answer 1

Answer:

To solve this problem, we can use the formula:

Work = Force x Distance x cos(theta)

where Work is the amount of work done on the pizza, Distance is the distance the pizza is lifted, theta is the angle between the force and the displacement, and cos(theta) is the cosine of the angle between the force and displacement.

We are given that the work done on the pizza is 116 kJ, the distance the pizza is lifted is 3.85 cm (which is 0.0385 m), and the angle between the force and the displacement is 0 degrees (since the force is applied in the same direction as the displacement).

Plugging in these values, we get:

116 kJ = Force x 0.0385 m x cos(0)

Simplifying and converting the units of work to joules, we get:

116,000 J = Force x 0.0385 m

Solving for Force, we get:

Force = 116,000 J / 0.0385 m

Force = 3,012,987.01 N

Therefore, the delivery man exerts a force of approximately 3,012,987.01 Newtons on the pizza to lift it 3.85 cm higher.


Related Questions

Canon launch is a 4.0 kg bowling ball with 50 J of kinetic energy what is the bowling ball speed

Answers

Answer:

5 m/s

Explanation:

50=1/2*4v^2

4*1/2=2

25*2=50

so...

square rood of 25 is 5

answer 5 m/s

sorry if that didn't make since

What does Neil Degrasse Tyson mean when he says "Wolves domesticated humans" 15000 years ago?

Answers

Answer:

Explanation:

fufuu6u

A proud new Jaguar owner drives her car at a speed of 35 m/s into a corner. The coefficients of friction between the road and the tires are 0.70 (static) and 0.40 (kinetic). What is the minimum radius of curvature for the corner in order for the car not to skid

Answers

Answer:

178.6 m

Explanation:

Since the car moves in a circular path, it experiences a centripetal force, F = mv²/r where m = mass of car, v = speed of car = 35 m/s and r = radius of curvature of path.

Now, for the car not to skid, this centripetal force must be equal to the frictional force, F' acting in the opposite direction.

So, F' = μN where μ = coefficient of static friction(since the car does not move in this direction) and N = normal force = mg where m = mass of car and g = acceleration due to gravity = 9.8m/s²

F' = μmg

Since F = F'

mv²/r = μmg

dividing both sides by m, we have

v²/r = μg

multiplying both sides by r, we have

v² = μgr

dividing both sides by μg, we have

r = v²/μg

Here we use μ = coefficient of static friction(since the car does not move in this direction) = 0.70. Substituting the other variables into the equation, we have

r = v²/μg

r = (35 m/s)²/(0.70 × 9.8m/s²)  

r = 1225 m²/s²/6.86m/s²)  

r = 178.6 m

So, the minimum radius of curvature of the corner is 178.6 m

The force that is applied to other objects from the electric field *
A. ions
B. electric field
C. electric force
D. static charge

Answers

electric force hope this helps!!!

Plzz help me with this
I’ll give brainliest

Answers

Answer:

B. Objects with more mass have more gravitational force acting upon them.

Answer:

Should be A but it can be B as well.

4. Kenny Kinematic notes that he is at mile marker 334 on the highway. He travels south to mile marker 181. What is his displacement?

Answers

Answer:

153miles

Explanation:

Distance on the highway = +334miles

Distance through south = -181miles (towards the negative direction)

Displacement will be the sum of the distances

Displacement = +334-181

Displacement = 153miles

Hence the displacement is 153miles

Acceleration is the rate ot change of the velacity a -dejdt so it is the slope of the Velocity vs. Time graph Because it is dficult to drag the person in a consistent and reproducible way use the Expression Evakaator under the Special Features menu for this question lick Reset A and type in the hr on z t * t * t " t in the Expression Evaluator Click the Play button and let the simulation run roughly 5 sin ulation seconds before ressing the Pause but use the zoom buttons to a 쪄 the p s they the screen You should see 8 p at s ar l what you got in the previous question, but much smoother Look at the Postion vs Time. Velocity vs Time and Acceleration vs. Time piets h
a) the velocity is zero but the acceleration is negative
When the person is 8 to to the tight of the origin
b) the velocity is zero but the acceleration is positive
c) both the velocity and the acceleration are zero
d) both the velocity and the acceleraton are nonzero

Answers

Answer:

a) the body  is changing direction,

b)the body must go to the left and the acceleration to the right

c) the movement has not started.

d) all points of the motion

Explanation:

In this exercise you are asked to find in which position you have the following characteristics of the movement

a) The velocity is zero and the acceleration is negative

This is when the body reaches the end of the travel and turns around, in this case the speed is zero and the acceleration has the opposite direction to the movement.

In this case the body moves to the right and the acceleration is to the left, therefore the speed decreases

b) The velocity is zero, but the acceleration is positive

This occurs at the points where the speed is changing direction, specifically for this case the body must go to the left and the acceleration to the right

c) Both are zero

This only occurs where the body is stopped and the movement has not started.

d) both the velocity and the relation are nonzero.

This is at all points of the motion since the velocity is constantly changing as long as there is an acceleration

Thermodynamic Processes

Two moles of a monatomic ideal gas at (5 MPa, 5 L) is expanded isothermally until the volume is doubled (step 1). Then it is cooled isochorically until the pressure is 1 MPa (step 2). The temperature drops in this process. The gas is now compressed isothermally until its volume is back to 5 L, but its pressure is now 2 MPa (step 3). Finally, the gas is heated isochorically to return to the initial state (step 4). (a) Draw the four processes in the pV plane. (b) Find the total work done by the gas.

Answers

Answer:

A. Part a is the attachment

B. total work = 10.4kj

Explanation:

[tex]workdone=nRT1ln\frac{Vb}{Va}[/tex]

T1 = constant temperature

nRT1 = PaVa = PbVb

We write equation as

[tex]workdone =(PaVa)ln\frac{Vb}{Va}[/tex]

5ma = Pa, 5L = Va, Vb = 10L(temperature is doubled)

[tex]w1 = workdone =(5mpa*5L)ln\frac{10L}{5L}[/tex]

W1 = 25 ln2

W1 = 25 x 0.693

= 17.327kj

The isochoric expansion has no change in volume. So,

W2 = 0

Isothermal compression

[tex]w3=nRT3ln\frac{Vd}{Vc}[/tex]

T3 = constant temperature

nRT3 = PcVc = PdVd

[tex]workdone=(PcVc)ln\frac{Vd}{Vc}[/tex]

Pc = 1mpa Vc = 10L Vd = 5L

[tex]w3=(1)(10)ln\frac{5L}{10L}[/tex]

= 10x-0.693

= -6.93kj

Isochoric compression has no change in volume. Workdone w4 = 0

Total workdone = w1 + w2 + w3 + w4

= 17.33 + 0 + (-6.93) + 0

= 10.4kj

Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; both students move away from each other. What law of motion is this. (Newton's laws)

Answers

Answer:

forcing in act

Explanation:

Plzzz answer this correctly

Answers

Answer:

D, the acceleration  of A is twice that of b.

Explanation: in four seconds b got to ten, in two seconds a got to 20. Going  10m/s faster in half the time is going twice the acceleration

Which of the following is not an example of energy transfer?
A. Riding a bike down a hill.
B. Sliding a table across a floor.
C. Holding a sign in the air.

Answers

Answer:

c.holding a sign in the air

Explanation:

because b is kinetic energy and a is also kinetic energy

C holding a sign in the air

HELPPPPP
What can you infer about the strength and direction of forces experienced by the pod and space station when they collided? What evidence from today’s activities supports your inference?

Answers

Answer:

In the collision, the strength of the force exerted on the pod is greater than the strength of the force exerted on the space station, but those forces are exerted in opposite directions.

Explanation:

Three joules of work is needed to shift 10 C of charge from one place to another. The potential difference between the places is ______. *
0.3 V
0.5 V
5 V
3 V​

Answers

Answer:

The potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

Explanation:

Given

Work done W = 3J

Amount of Charge q = 10C

To determine

We need to determine the potential difference V between the places.

The potential difference between the two points can be determined using the formula

Potential Difference (V) = Work Done (W) / Amount of Charge (q)

or

[tex]\:V\:=\:\frac{W}{q}[/tex]

substituting W = 3 and q = 10 in the formula

[tex]V=\frac{3}{10}[/tex]

[tex]V=0.3[/tex] V

Therefore, the potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

How does the Law of Conservation of Energy (or energy transformation) relate to the home?

Answers

Answer:

"The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. ... The only way to use energy is to transform energy from one form to another."

Explanation:

Brainliest?

Matter is made of small particles to small to be seen. Which of these best describe evidence of this statement? 1. Tara’s crayons melted when she left them under the sun. 2. Kerris glass of water overflowed when she added ice. 3. Sams basketball expands as he pumps air into it. 4. Stephanie dropped a vase and it broke into pieces.

Answers

Answer:

Explanation:

I think the answer is statement no 3.

Hope it helps.

Answer:

1 Tara's crayons melted when she left them under the sun

Use Newton's laws of motion to explain why it is important that baseballs and softballs each have a small acceptable range of masses.​

Answers

Explanation:

new non law neutron means neutral then it's important that baseball and softball features small respectable range of masses soft it means that when a ball hits anything hard it comes back by the Newton Law if the baseball is big and the small boy small and then if the contract with each other they ignore triple so when a ball hits the wall if the comeback because of the Mutants and when a big ball if we throw it to the wall it doesn't come that it comes back but in a very low way because it contains less neutrons in it if it is helpful please share with me

This is the build up of substance such as pesticides in an organism and occurs when an organism absorb a substance at a rate faster than that at which the substance is lost

Answers

Answer:

which the substance is lost by catabolism and excretion.

Explanation:

Galileo
o did not believe friction existed
o believed that friction stopped objects in motion
o believed that friction kept objects in motion
О
assumed that in a frictionless environment objects would never move

Answers

Answer:

object would move but it could be difficult to slow down or stop.

what is the mystery Greene discussion and why does he say it is something we should all care about ​

Answers

Answer:

The mystery that Greene discusses is that dark energy is causing the expansion of the universe to accelerate. However, this cannot be explained by the laws of Physics.

Explanation:

I majored in Physics

Please help I don’t get this give me answers please

Answers

Answer:

c

Explanation:

a body of mass 20kg initially at rest is subjected to a force of 40N for 1sec calculate the change in kinetic energy showing the solution​

Answers

Answer:

Change in KE is 40 J

Explanation:

Recall that the impulse exerted on an object equal the change of momentum of the object (ΔP), which in time is defined as the product of the force exerted on it times the time the force was acting:

Change in momentum is:   ΔP = F * Δt

In our case,

ΔP = 40 N * 1 sec = 40 N s

Since the object was initially at rest, its initial momentum was zero, and the final momentum should then be 40 N s.

So, the initial KE was 0, and the final (KEf) can be calculated using:

KEf = 1 /(2 m) Pf^2 = 1 / (40) 40^2 = 40 J

So, the change in kinetic energy is:

KEf - KEi = 40 J - 0 j = 40 J

HURRY!!!
I need helppppp!!!

Answers

Answer:

ok i think the answer would be C. or B. hope im right

something that orbiys other things in space​

Answers

Answer: well we all orbit the sun all the planets do so the

SuN

Explanation: two words common sense

what is borh's postulates for the hydrogen atom​

Answers

Answer:

An atom has a number of stable orbits in which an electron can reside without the emission of radiant energy. ... Each orbit corresponds, to a certain energy level.

Explanation:

Hope it is helpful....

Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1.0m/s and vy=3.0m/svy=3.0m/s and that at time t2=2.5st2=2.5s the components are vx=4.0m/svx=4.0m/s and vy=3.0m/svy=3.0m/s . Find (a) the components of average acceleration and (b) the magnitude and direction of the average acceleration during this interval.

Answers

Answer:

[tex]a_x=6\ \text{m/s}^2[/tex] and [tex]a_y=0\ \text{m/s}^2[/tex]

Magnitude of accleration is [tex]6\ \text{m/s}^2[/tex] and the direction is [tex]0^{\circ}[/tex]

Explanation:

[tex]t_1=2\ \text{s}[/tex]

[tex]v_x=1\ \text{m/s}[/tex]

[tex]v_y=3\ \text{m/s}[/tex]

[tex]t_2=2.5\ \text{s}[/tex]

[tex]v_x=4\ \text{m/s}[/tex]

[tex]v_y=3\ \text{m/s}[/tex]

Average acceleration in the different axes

[tex]a_x=\dfrac{\Delta v_x}{\Delta t}\\\Rightarrow a_x=\dfrac{4-1}{2.5-2}\\\Rightarrow a_x=6\ \text{m/s}^2[/tex]

[tex]a_y=\dfrac{\Delta v_y}{\Delta t}\\\Rightarrow a_y=\dfrac{3-3}{2.5-2}\\\Rightarrow a_y=0\ \text{m/s}^2[/tex]

The components of the acceleration is [tex]a_x=6\ \text{m/s}^2[/tex] and [tex]a_y=0\ \text{m/s}^2[/tex]

The magnitude of acceleration

[tex]a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2[/tex]

Direction

[tex]\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}[/tex]

The magnitude of accleration is [tex]6\ \text{m/s}^2[/tex] and the direction is [tex]0^{\circ}[/tex].

1
What kind of adaptation is a long neck on a tortoise? *
(10 Points)
O
A. Structural
B. Behavioral
a
C. Functional
a
D. Physiological

Answers

Answer:

The answer is ......... structural adaptation

Explanation:

because structural adaptations is a physical thinng in their  body so its A please give me brainliest  

EASY WORK! Yes it’s easy for other people but not me for people asking.Also click on the photo.

Answers

B force and D. Velocity because 1 is a force that push and pulls obviously makes since and D. A force that is size

Answer: Force and Direction

Explanation:

alex often draws his dream house​

Answers

Answer:

hopefully alex quackity hahhaa

Explanation:

i hope this was free points and not an actual thing

Answer:

cool, cool for alex .....

If used with godly wisdom, the earth has sufficient resources to sustain its human population.

Answers

Yeah I mean people think it’s wrong to take from the earth like shells or plants but the universe provides for us you aren’t steeling from the earth she provides for us

Help plz with both I’ll mark brainliest

Answers

The first one is to save your ears from the decibels
Save wars from decaibles and the second is C
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