a railroad crew can replace 400 meters of rail in 5 days. How many kilometers can they replace in 20 days?

[tex]\\ \rm\longmapsto 1/2(10x+20y+10z)[/tex]

[tex]\\ \rm\longmapsto 10x/2+20y/2+10z/2[/tex]

[tex]\\ \rm\longmapsto 5x+10y+5z[/tex]

Answer:

5x+10y+5z

Step-by-step explanation: it was on khan academy and it was right  

Answer: 4.00, 9.00, 11.00, 4.00

Step-by-step explanation:

When we round, we round from the digit one smaller than the one we're rounding to. In this case, since we're rounding to the dollar, we round from the 10th place. To round, we need to know whether the number we're rounding from is smaller than, equal to, or larger than 5. If the number is smaller than 5, we round down. Larger, and we round up. If the number is equal to 5, we also round up.

Step-by-step explanation:

The 53rd ball will be blue. I don't really know how to explain but I'll try.

So there are black, white and blue balls. If you look closer you'll see that the words 'black,white,blue,black, blue were repeated twice. So let's say that the first 5 letters are a set. To get the 50th color, all you have to do is 5 × 10 which is 50 and the 50th term is blue. Just add black(51st), white(52nd) and you'll get the 53rd color to be Blue.

I don't know how to do <2>.

Hope this helps!

Please mark me brainliest :)

Answer:

-2.2y-1.8

Step-byStep-byStep-byStep-byStep-byStep-byStep-byStep-byStep-by

1.2y-3.4y=-2.2y

4.5-6.3=-1.8

ssoso:-2.2y-1.8

Answer:

-2x^2 + 4x + 11

Step-by-step explanation:

whats 2x2 ? do you mean 2x^2 ? if so then...

8x + 4 - 2x^2 - 4x + 7

4x + 11 - 2x^2

-2x^2 + 4x + 11

Answer:

this is the answers 2x^2+4x+11

= (7+20+9+35+12+15+7+10+20+25) : 10

with 10 = number of values

average distance = 160 : 10 = 16

Answer:

Colombian coffee bought = 0.5 lbs

French roast coffee beans bought = 0.5 lbs

Step-by-step explanation:

Let Colombian coffee bought = [tex]x[/tex] lbs

Total weight of mixture bought = 1 lbs

Therefore, French roast coffee beans bought = (1 - [tex]x[/tex]) lbs

Price of 1 lb Colombian coffee = $4.25

Price of [tex]x[/tex] lbs of Colombian coffee = $[tex]4.25x[/tex]

Price of 1 lb French roast coffee beans = $3.75

Price of (1 - [tex]x[/tex]) lbs French roast coffee beans = $3.75(1 - [tex]x[/tex])

It is given that total money spent is $4.

As per given statement:

[tex]4.25x+3.75(1-x)=4\\\Rightarrow 0.50x=0.25\\\Rightarrow x=\bold{0.5\ lbs}[/tex]

Colombian coffee bought = 0.5 lbs

French roast coffee beans bought = 0.5 lbs

Answer:

31 degrees

Step-by-step explanation:

A line has angle of 180 degrees.

So

[tex](2z+17)+(4z-23)=180\\6z-6=180\\6z=186\\z=31[/tex]

Using a t-distribution calculator, it is found that the critical value of t* for a 98% confidence interval with 25 observations is given by:

B. t* = 2.492

It is found using a calculator, with two inputs, which are given by:

In this problem, we have a confidence level of 98% and 25 - 1 = 24 df, hence the critical value is of t* = 2.492, which means that option B is correct.

More can be learned about the t-distribution at https://brainly.com/question/16162795

#SPJ2

Answer:$51.5

Step-by-step explanation:

Answer:

[tex]\boxed {x_{1} = 3}[/tex]

[tex]\boxed {x_{2} = -4}[/tex]

Step-by-step explanation:

Solve the following equation:

[tex]\left[\begin{array}{ccc}3&2\\5&5\\\end{array}\right] \left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right] + \left[\begin{array}{ccc}1\\2\\\end{array}\right] = \left[\begin{array}{ccc}2\\-3\\\end{array}\right][/tex]

-In order to solve a pair of equations by using substitution, you first need to solve one of the equations for one of variables and then you would substitute the result for that variable in the other equation:

-First equation:

[tex]3x_{1} + 2x_{2} + 1 = 2[/tex]

-Second equation:

[tex]5x_{1} + 5x_{2} + 2 = -3[/tex]

-Choose one of the two following equations, which I choose the first one, then you solve for [tex]x_{1}[/tex] by isolating

[tex]3x_{1} + 2x_{2} + 1 = 2[/tex]

-Subtract [tex]1[/tex] to both sides:

[tex]3x_{1} + 2x_{2} + 1 - 1 = 2 - 1[/tex]

[tex]3x_{1} + 2x_{2} = 1[/tex]

-Subtract [tex]2x_{2}[/tex] to both sides:

[tex]3x_{1} + 2x_{2} - 2x_{2} = -2x_{2} + 1[/tex]

[tex]3x_{1} = -2x_{2} + 1[/tex]

-Divide both sides by [tex]3[/tex]:

[tex]3x_{1} = -2x_{2} + 1[/tex]

[tex]x_{1} = \frac{1}{3} (-2x_{2} + 1)[/tex]

-Multiply [tex]-2x_{2} + 1[/tex] by [tex]\frac{1}{3}[/tex]:

[tex]x_{1} = \frac{1}{3} (-2x_{2} + 1)[/tex]

[tex]x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}[/tex]

-Substitute [tex]-\frac{2x_{2} + 1}{3}[/tex] for [tex]x_{1}[/tex] in the second equation, which is [tex]5x_{1} + 5x_{2} + 2 = -3[/tex]:

[tex]5x_{1} + 5x_{2} + 2 = -3[/tex]

[tex]5(-\frac{2}{3}x_{2} + \frac{1}{3}) + 5x_{2} + 2 = -3[/tex]

Multiply [tex]-\frac{2x_{2} + 1}{3}[/tex] by [tex]5[/tex]:

[tex]5(-\frac{2}{3}x_{2} + \frac{1}{3}) + 5x_{2} + 2 = -3[/tex]

[tex]-\frac{10}{3}x_{2} + \frac{5}{3} + 5x_{2} + 2 = -3[/tex]

-Combine like terms:

[tex]-\frac{10}{3}x_{2} + \frac{5}{3} + 5x_{2} + 2 = -3[/tex]

[tex]\frac{5}{3}x_{2} + \frac{11}{3} = -3[/tex]

-Subtract [tex]\frac{11}{3}[/tex] to both sides:

[tex]\frac{5}{3}x_{2} + \frac{11}{3} - \frac{11}{3} = -3 - \frac{11}{3}[/tex]

[tex]\frac{5}{3}x_{2} = -\frac{20}{3}[/tex]

-Multiply both sides by [tex]\frac{5}{3}[/tex]:

[tex]\frac{\frac{5}{3}x_{2}}{\frac{5}{3}} = \frac{-\frac{20}{3}}{\frac{5}{3}}[/tex]

[tex]\boxed {x_{2} = -4}[/tex]

-After you have the value of [tex]x_2[/tex], substitute for [tex]x_{2}[/tex] onto this equation, which is [tex]x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}[/tex]:

[tex]x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}[/tex]

[tex]x_{1} = -\frac{2}{3}(-4) + \frac{1}{3}[/tex]

-Multiply [tex]-\frac{2}{3}[/tex] and [tex]-4[/tex]:

[tex]x_{1} = -\frac{2}{3}(-4) + \frac{1}{3}[/tex]

[tex]x_{1} = \frac{8 + 1}{3}[/tex]

-Since both [tex]\frac{1}{3}[/tex] and [tex]\frac{8}{3}[/tex] have the same denominator, then add the numerators together. Also, after you have added both numerators together, reduce the fraction to the lowest term:

[tex]x_{1} = \frac{8 + 1}{3}[/tex]

[tex]x_{1} = \frac{9}{3}[/tex]

[tex]\boxed {x_{1} = 3}[/tex]

Answer:

x^2 + 8 = 64 is not a linear function

Step-by-step explanation:

using the process of elimination and a graphing calculator, you can see that the rest of the functions give you a linear function. therefore, the answer is x^2 + 8 = 64 is not a linear function!! i hope this helps you!! <3

The [tex]x^2 + 8 = 64[/tex] is not the liner function.

The following information regarding the linear function is:

Therefore we can conclude that the [tex]x^2 + 8 = 64[/tex] is not the liner function.

Learn more about the linear function here: brainly.com/question/20286983

Answer:

the complement of 37 degrees is 53 degrees.

Step-by-step explanation:

90-37=53

Answer:

its true, depending on the times table.

Answer:

True

Step-by-step explanation:

This statement is always true.

Check the picture below.

[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=26\\ \theta =\stackrel{180+34}{214} \end{cases}\implies \begin{array}{llll} A=\cfrac{\pi (214)(26)^2}{360}\implies A=\cfrac{18083\pi }{45} \\\\\\ A \approx 1262.43 \end{array}[/tex]

Answer: 628571%.

Step-by-step explanation:

Answer:

1722

Step-by-step explanation:

Answer:

Value of x = 8

(3x - 7) = (5x - 23)

-2x = -16

x = 8

Value of m 8 = 17 degrees

5(8) - 23

40 - 23 = 17

Answer:

the answer is b b is the answer I did this before

Answer:(1,2)

Step-by-step explanation: The signs may not be right(positive, negative) Sorry it’s been a long time since I did this

[tex]ratio-of-red-blocks-to-yellow-blocks = \frac{number-of-red-blocks}{number-of-yellow-blocks} =\frac{12}{8} =\frac{3}{2}[/tex]

Answer: [tex]\frac{3}{2}[/tex] or   3 : 2

Hope it helps!

Answer:

3 : 2

Step-by-step explanation:

Answer:

[tex]y=11x-3[/tex]

Step-by-step explanation:

Given ordered pairs:

(1, 8)  (2, 19)  (3, 30)  (4, 41)

As the y is directly proportional to x (y values increase +11 for every +1 increase for the x-values) then the equation will be linear.

Point-slope form of a linear equation:  [tex]y-y_1=m(x-x_1)[/tex]

(where [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is a point on the line)

[tex]\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

Let:

[tex]\implies \textsf{slope }m=\dfrac{19-8}{2-1}=11[/tex]

Using point-slope equation with m = 11 and point (1, 8):

      [tex]y-y_1=m(x-x_1)[/tex]

[tex]\implies y-8=11(x-1)[/tex]

[tex]\implies y=11x-3[/tex]

Hey there!

[tex]⇢ \: A = 2wl + 2lh + 2hw[/tex]

Substitute

[tex]⇢ \: = 2(8)(17) + 2(17)(12) + 2(12)(8)[/tex]

[tex]⇒872[/tex]

Surface area = 872 square inches

Check the picture below.

[tex]~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&5\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&9\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-4.9t^2+5t+9\implies \stackrel{h(t)}{0}=-4.9t^2+5t+9 \implies 4.9t^2-5t-9=0[/tex]

since we don't get any neat integer values from it hmmm let's plug that in the quadratic formula to see what we get as h(t) = 0.

[tex]~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{4.9}t^2\stackrel{\stackrel{b}{\downarrow }}{-5}t\stackrel{\stackrel{c}{\downarrow }}{-9}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ t= \cfrac{ - (-5) \pm \sqrt { (-5)^2 -4(4.9)(-9)}}{2(4.9)}\implies t=\cfrac{5\pm\sqrt{25+176.4}}{9.8} \\\\\\ t=\cfrac{5\pm \sqrt{201.4}}{9.8}\implies t\approx \begin{cases} 1.96~~\checkmark\\ -0.94 \end{cases}[/tex]

notice, we do not use the negative value for "t", since the seconds cannot be less than 0.

Answer:

His March Earnings is $20000

Step-by-step explanation:

Given

[tex]Salary = \$1500[/tex]

[tex]Commission = 5\%\ of\ sales[/tex]

[tex]March\ Earnings = \$2500[/tex]

Required

Determine the monthly sales

Represent the monthly sales with x

The march earnings can be determined using:

[tex]March\ Earnings = Salary + Commission[/tex]

[tex]March\ Earnings = Salary + 5\%\ of\ x[/tex]

Substitute values of March Earnings and Salary

[tex]2500 = 1500 + 5\% * x[/tex]

[tex]2500 = 1500 + 0.05 * x[/tex]

[tex]2500 = 1500 + 0.05x[/tex]

Solve for 0.05x

[tex]0.05x = 2500 - 1500[/tex]

[tex]0.05x = 1000[/tex]

Solve for x

[tex]x = 1000/0.05[/tex]

[tex]x = 20000[/tex]

Hence:

His March Earnings is $20000

Hope this helps

Good luck

2x - 5 + 3x = 35

simplify

5x - 5 = 35

add 5 to both sides

5x - 5 + 5 = 35 + 5

simplify

5x = 40

divide both sides by 5

5x/5 = 40/5

simplify

x = 8