A spring is attached to the floor and pulled straight up by a string. The string's tension is measured. The graph in the figure shows the tension in the spring as a function of the spring's length L (Figure 1)

If the spring obeys Hooke's Law, what is the spring contract?

The power of the motor in watts is 4000 W.

Power (P) = Work (W) / Time (t)

P = 4000 J / 1 min

P = 4000 J/s

1 J/s = 1 W

P = 4000 W

What is power?

Power is a measure of energy transfer over time. In physics, it is the rate of energy transfer, usually measured in Watts (W) or Joules per second (J/s). Power is the rate at which work is done or energy is converted from one form to another. It can be calculated by multiplying the force applied to an object by the speed at which it moves. Power is related to work, as work is equal to the amount of energy transferred, divided by time. Power is an important concept in physics as it is used to calculate the energy required to perform a task.

Therefore, The power of the motor in watts is 4000 W.

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Answer:

Wc = 7.84    weight of crown

Ww = 7.84 - 6.86 = .98       weight of water displaced

Density = 7.84 / .98 = 8     crown is 8 X that of water

Since gold has a density of 19.3 that of water the crown is certainly not 100 percent (if any) gold  

The period of M2, in years. is mathematically given as

T2= 134.3968years

M1 = 4.00 kg

M2 = 1.00 kg

T1 = 34.0 years.

Generally, the equation for is  mathematically given as

T2 = T1 (a2/a1)3/2

T2=  34.0  * (5/2)^{3/2}

T2= 134.3968years

In conclusion, the period of M2, in years

T2= 134.3968years

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Since volume grows as a cube of radius, a planet with a 1.5 earth radius would have a volume that is 1.53, or roughly 3.375 times that of the current Earth.

Given that Earth has a density of 5.513 g/cm3, its new density would be around 1.63 g/cm3 if its radius were doubled by 50% but its mass remained constant. Jupiter has a density of 1.326 g/cm3 as a point of comparison. However, it's possible that you're referring to what would happen if both size and mass were scaled appropriately, making this new Earth identical to existing super-earths with 1.5 earth radii. The density would then be around 6-7 g/cm3.

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Answer:

velocity is a hell of a drug treatment classes in the position you are offering to help you with your medical needs and your needs and your needs and your needs and your needs for the future and to be getting your son in a better place for the better of the richest of his family and his life in the world.

Explanation:

no exceptions

The density of the planet is determined as 1,974.26 kg/m³.

√(⁴/₃πGρ) = 2π/(2.35 x 3600)

where;

√(⁴/₃πGρ) = 2π/(2.35 x 3600)

√(⁴/₃πGρ) = 2π/8460

(⁴/₃πGρ)  = (2π/8460)²

⁴/₃πGρ = 4π²/(8460)²

ρ = 12π/(8460² x 4G)

ρ = (12π) / (8460² x 4 x 6.67 x 10⁻¹¹)

ρ = 1,974.26 kg/m³

Thus, the density of the planet is determined as 1,974.26 kg/m³.

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Answer:

See below

Explanation:

To change C to F°

  F = 9/5 C   + 32

     = 9/5 ( 45) + 32 = 113° F

To change F to C°   <= you could use the same equation...or re-earrange to:

C = 5/9 (F-32)

   = 5/9 ( 98.6 - 32) = 37° C

Similarly

100 C = 212 ° F

 to change C °  to  K    add 273.15   =  373.15 K    

Answer:

Yes.

Explanation:

When you move your hand from the cold water to the “warmer” (room temp) water, one hand feels warm.

As you move your hand from the warm water to the “colder” (room temp) water, that hand feels colder.

Although both hands experience the last bowl of water at the same temperature, your brain senses two

separate sensations. So the water feels “warm” or “cold” relative to the water your hand was in previously.

The greater the difference in temperature, the easier it is to sense a difference.

Answer:  proposing the existence of "bridges" through space-time

Sorry if this isn't helpful.

Explanation:

Moving from an area of lower potential to a region of higher potential causes electrons to accelerate. The law of conservation of energy controls the acceleration of the electrons from rest. The final speed can then be determined from the conservation rule by using the electron's speed shortly before it reaches the screen.

The passage of electrons (or other charge carriers) through a conductor in the presence of a potential difference or an electric field is commonly referred to as electricity. There are several interpretations of this flow's pace. While the electrons themselves move far more slowly in common electrical and electronic devices, the signals do so as electromagnetic waves that typically travel between 50% and 99% of the speed of light in a vacuum. For further information, see drift velocity and electron mobility. The speed of an electromagnetic wave flowing along (being steered by) a cable is the pace at which energy or signals go down the wire. In other words, a cable is a type of waveguide. The interaction of the wave with the material(s) inside and around the cable.

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Rank from largest to smallest, To rank items as equivalent, overlap them is Pd>Pa>Pb>Pc.

What is quantum particles ?

A quantum particle has a complex wave function that is square-integrable and has the form (x1,... xN), where ||2 is the probability density of finding N particles at positions x1,x2,... xN. These places are taken to be inside a square box of size d, with side length L, periodic boundary conditions, and position V.

What is potential energy ?

Potential energy is a form of energy that can be stored but is affected by the way a system's component elements are assembled.  A steel ball is more energetic when it is raised above the ground than when it is lowered.

Therefore, rank from largest to smallest, To rank items as equivalent, overlap them is Pd>Pa>Pb>Pc.

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The bigger object will move some distance because the initial and final momentum of the colliding particles are not zero.

The term momentum has to do with the product of mass and velocity. We know that during a collision, momentum is conserved. This implies that the momentum before collision is equal to the momentum after collision. Thus, the total momentum of the system is constant.

Given the fact that the initial and final momentum of the colliding particles are not zero, the  the big object is not going to stop immediately but must move some distance towards the smaller object.

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The resultant displacement of the car can be determined using Pythagorean theorem. The magnitude of car's displacement here is 47.3 Km.

Displacement is a vector quantity measuring the change in position of an object. It can be used in short  term distances. Displacement have both magnitude and direction.

Given , distance to travelled to east = 15 km

to the north = 45 km

then,  the two points if connected will form a triangle where we can use the Pythagorean theorem to find the resultant vector.

The resultant displacement = √(45² + 15 ²) = 47.3 km

Therefore, the displacement of the car is 47.3 km.

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The magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.

The acceleration of bock m2 is calculated from Net force exerted by the pulley.

F - T = m2a

F - m1a = m2a

F = m2a + m1a

F = a(m2 + m1)

a = F/(m1 + m2)

a = (0.03) / (0.04 + 0.02)

a = 0.5 m/s²

T = m1a

T = 0.04 x 0.5

T = 0.02 N

Thus, the magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.

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Answer:

pictures please

Explanation:

I need a picture so I can tell you

The work done during expansion is 2.73×10³J and the heat transferred to the surrounding is -2.73×10³ J

The thermodynamic process which takes place in constant temperature of the system is called isothermal process.

n= number of moles

R= universal gas constant

V2= volume of the system after expansion

V1= volume of the system before expansion

= 2.73×10³ J.

Thus, we can conclude that a) the amount of work done is 2.73×10³J and b) the amount of heat transferred to the surrounding is -(2.73×10³J).

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Answer:

B. Weight

Explanation:

Weight is the force of gravity exerted on a body

OR

It's the force exerted on a body by the influence of the earth's gravitational force

The required horsepower engine is 32 horsepower.

The force of the 30 skiers is calculated as follows:

Mass of the skiers = 30 * 67kg = 2010 kg

Net force acting on the skiers along the x-axis

where f is the frictional force

The kinetic frictional force, f = μN

where

μ = The coefficient of the kinetic friction

N = normal reaction

Net force acting on the skiers along y axis, the

Fy = ma

N = mg cos θ

Substituting for N above

f = μk mg cos θ

Substituting for f in  (1)

F = mg sin θ + μk mg cos θ

F = mg(sinθ + μk cos θ)

Work done by the engine in pilling up the skiers, W = Fx

W = mg ( sinθ + μk cos θ)x

x = 300 m

W = (2010 kg) (9.81 m/s²) (sin 23° + (0.10) cos 23°) (300 m)

Work done, W = 2.86 * 10⁶ J

Time taken, t = 2.0 * 60sec = 120 s

1 horsepower = 746 W

Power = 2.86 * 10⁶/ 120 * 1/746

Power = 31.9 horsepower

In conclusion, the power of the engine is the ratio of the work done and time taken.

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The speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.

v = √(GM/r)

where;

v = √(6.67 x 10⁻¹¹ x 5.98 x 10²⁴/3.57 x 6.37x 10³)

v = 1.32 x 10⁵ m/s

Thus, the speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.

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No digestion is needed in alcohol absorption. Is statement about alcohol's path through the human body .

What is absorption in biology?

Absorption is the process by which the products of digestion are absorbed by the blood to be supplied to the rest of the body. During absorption, the digested products are transported into the blood or lymph through the mucous membrane.

What is meant by adsorption and absorption?

Adsorption and absorption mean quite different things. Absorption is where a liquid is soaked up into something like a sponge, cloth or filter paper. The liquid is completely absorbed into the absorbent material. Adsorption refers to individual molecules, atoms or ions gathering on surfaces.

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Given a current loop, find the direction of the magnetic field using the right-hand rule  The magnetic field created by the current loop goes from right to left.

Current travels clockwise (relative to the magnet), so now bend the fingers of your right hand clockwise and point your thumb in the direction of the magnetic field.

This creates a magnetic dipole with the north pole on the left and the south pole on the right.

Now, in a magnet, opposite poles attract and like poles repel, so if we move the magnet towards the loop as shown in the figure, his south pole of the magnet will be repelled by the nearest south pole of the current loop. increase.

A current in a circular loop creates a magnetic field that is more concentrated in the center of the loop than outside it. Stacking multiple loops further concentrates the field in what is called a solenoid.

The magnetic moment m of a current loop is a vector whose magnitude is equal to the area of ​​the loop times the magnitude of the current flowing through it (m = IA) and whose direction is perpendicular to the plane through which the current flows. .

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A. The acceleration of the ball while it is in flight?

magnitude is 0 m/s² (magnitude is zero)

B. The velocity of the ball when it reaches its maximum height is 0 m/s (magnitude is zero)

C. The initial velocity of the ball 8.036 m/s upward

D. The maximum height reached by the ball is 3.29 m

Considering that the ball came to rest after 1.64s, it means the entire acceleration of the flight is zero as the ball was not moving in any form again.

At maximum height, the velocity of the ball is zero as it no longer has magnitude to keep going upwards. Hence the ball begins to ball down.

v = u - gt (since the ball is going against gravity)

0 = u - (9.8 × 0.82)

0 = u - 8.036

Collect like terms

u = 0 + 8.036

u = 8.036 m/s upward

h = ½gt²

h = ½ × 9.8 × 0.82²

h = 3.29 m

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Thus, the distance traveled by automobile is [tex]=1.31m[/tex]

The mass of the person is [tex]m=65kg[/tex]

The deceleration of the automobile is [tex]a=30g[/tex]

The acceleration due to gravity is [tex]g=9.81m/s.[/tex]

The initial velocity of the automobile is [tex]v_{i}=100 km/h*\frac{1m/s}{3.6km/h} =27.78m/s[/tex]

Determination of the force exerted on the person:

The force applied to the person can be calculated using Newton's second law as follows:

[tex]F=ma[/tex]

[tex]30g[/tex]Here, m denotes the person's mass, while a denotes the car's acceleration. Because the driver is moving at 30g, the car's acceleration is assumed to be positive.

Substitute the values as 70 kg for [tex]m,(30g)[/tex] for a, and[tex]9.81m/s^{2}[/tex]

for g in the above equation.

[tex]F=70kg*30g[/tex]

   [tex]=70kg*30g*9.81m/s^{2} (\frac{1N}{1kg*m/s^{2} })[/tex]

   [tex]=20,601N[/tex]

Thus, the force acting on the person is [tex]=20,601N[/tex]

Determination of the distance traveled by automobile:

The final velocity of the car can be calculated using Newton's third law and represented as follows:

[tex]v_{f} ^{2}=v_{i} ^{2}+2ad[/tex]

[tex]d=\frac{v_{f} ^{2}=v_{i} ^{2}}{2a}[/tex]

Here [tex]v_{f}[/tex] is the final velocity of the automobile. The final velocity of the automobile becomes 0 m/s as the automobile comes to rest. The acceleration is taken to be negative because the automobile is decelerating at [tex]30g[/tex]

Substitute the values as [tex]0 m/s[/tex] for[tex]v_{f} =27.78m/s[/tex], for[tex]v_{i} ,(-30g)[/tex],  for a, and  [tex]9.81m/s^{2}[/tex]for g in the above equation.

[tex]d=\frac{(0 m/s)^{2} - (27.78m/s)^{2} }{2*(-30)*9.81m/s^{2} }[/tex]

[tex]=1.31m[/tex]

Thus, the distance traveled by automobile is[tex]=1.31m[/tex]

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(a) The work done by the applied force is 26.65 J.

(b) The work done by the normal force exerted by the table is 0.

(c) The work done by the force of gravity is 0.

(d) The work done by the net force on the block is 26.65 J.

W = Fdcosθ

W = 14 x 2.1 x cos25

W = 26.65 J

W = Fₙd

W = mg cosθ x d

W = (2.5 x 9.8) x cos(90) x 2.1

W = 0 J

The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.

∑W = 0 + 26.65 J = 26.65 J

Thus, the work done by the applied force is 26.65 J.

The work done by the normal force exerted by the table is 0.

The work done by the force of gravity is 0.

The work done by the net force on the block is 26.65 J.

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A wave in which the particles of the medium move in the same direction as the wave is a longitudinal wave.

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Earth's most recent glacial period ended about 11,500 years ago.

The Great Oxygenation Event began about 2.3 billion years ago.

About 160 years ago  carbon dioxide began increasing exponentially to unprecedented levels.

A glacial period is described as an interval of time within an ice age that is marked by colder temperatures and glacier advances.

There are three types of continental glaciers, and they include:

An ice sheet covers an area larger than 50,000 square kilometers. Greenland and Antarctica and are covered by massive ice sheets today.

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The kind of equation that can be used to differentiate the kind of separatrix that shows change on motion is

H = 2g/l.

A simple pendulum can be defined as the equipment that displays an oscillatory motion when a mass is tied on a rope and is suspended from it.

The various movements that occur using a simple pendulum is translational ( side to side) or continuous circle (oscillatory motion).

The equation that show that a change from one type of motion to another is H = 2g/l.

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Answer:

Every 15 minutes, remove the cover and check the temperatures of the samples using the three thermometers. Wait 30 seconds before recording the thermometer reading. Once the temperatures of the three samples are no more than a degree apart, record the temperatures.

(three 100-milliliter containers (each with a thermometer) in an ice bath inside an uncovered basin, with one container holding 50 grams of sand, one holding 50 grams of cold water, and one holding 100 grams of cold water)

Next, prepare the hot water.

-Fill each of the three 200-milliliter containers with 100 grams of hot tap water. Measure the mass using the mass scale.

(100 grams of hot water in a 200-milliliter container atop a mass scale)

-Prepare a hot-water bath by boiling water in a pot. Use the heat mitts to pour the hot water from the pot into the second tub. Fill the tub to a depth of about 2 inches. Carefully place the three containers of hot water into the bath without submerging them. Cover and wait for five minutes until the temperatures stabilize.

(three 200 mL containers (each holding 100 grams hot water) in a covered tub containing 2 inches of boiling water)

Prepare to mix the cold samples with hot water:

-Have three empty 300-milliliter mixing containers and three thermometers ready. Timing is important. Uncover the cold-water bath, and pour each cold sample into a different mixing container.

(three 300-milliliter containers (each with a thermometer), one holding 50 grams of sand, one holding 50 grams of cold water, and one holding 100 grams of cold water)

-Uncover the hot-water bath, and use a heat mitt to remove the three containers of hot water from the hot-water bath. Pour 100 grams of hot water into each mixing container.

(three 300 mL containers (each with a thermometer), one holding a 150-gram mixture of sand and hot water, one holding a 150-gram mixture of cold water and hot water, and one holding a 200-gram mixture of cold water and hot water)

Explanation:

The angle of refraction in the glass is 37.51 degree

The angle of incidence when light travels from air to water of refractive index 4/3 and then to glass of refractive index 1.60 is 60 degrees. To calculate the angle of refraction in the glass, we can use Snell's law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two materials.

Sin(incident angle) / Sin(refraction angle) = (refractive index of air) / (refractive index of glass)

sin(60) / sin(x) = 1 / 1.60

where x is the angle of refraction in the glass.

Solving for x,

x = sin^-1(sin(60) / 1.60)

= sin^-1(1 / 1.60)

= sin^-1(0.625)

=37.51 degree

Therefore, the angle of refraction in the glass is 37.51 degree.

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The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Apply the principle of conservation of energy,

E(up) - E(friction) = E(bottom)

mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²

[tex]v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }[/tex]

where;

u = √2gh

u = √(2gL sin15)

u = √(2 x 9.8 x 28 x sin 15)

u = 11.92 m/s

[tex]v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s[/tex]

Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

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