A spring with an unknown spring constant is hung vertically, and a 200 g (0.200 kg) mass is attached to the bottom. If the spring stretches 0.250 m from its resting position to the position at which the hanging mass is in equilibrium, what is the spring constant of this spring?

Explanation:

1.

We use the equation

h = [tex]\frac{gt^2}{2}[/tex], where

h is the height traveled,

g is the acceleration due to gravity and

t is the time taken to reach height h.

We can now calculate t to be

[tex]\sqrt{\frac{2*1.2 m}{9.81 m/s^2} }[/tex]

= 0.495 s

Let v be the initial velocity of the player.

The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.

v = 9.81 m/s^2 x 0.495 s = 4.85 m/s

2.

The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is

4.85 m/s / 0.3 s = 16.2 m/s^2

Answer:

0.16

Explanation:

Given data

Force F= 80N

Mass m= 50kg

Reaction R= Weight= mg= 50*9.81= 490.5N

We know that

F=UR

Substitute and solve of U

U=F/R

U= 80/490.5

U=0.16

Hence the coefficient of friction is 0.16

The initial speed of the bullet = v₁= 511.07 m/s

Given

17.4 g bullet

5506 g wooden

The velocity of the block+bullet :1.61 m/s

Required

The initial speed

Solution

Momentum

m₁v₁+m₂v₂=m₁v₁'+m₂v₂'

v₂=0 ⇒block at rest

v₁'=v₂'=1.61 m/s

the equation becomes :

m₁v₁=(m₁+m₂)v'

17.4v₁=(17.4+5506)1.61

v₁= 511.07 m/s

Answer:

See calculation below

Explanation:

Average speed = Distance/Time

a) Given

Distance = 17.9km

Time = 26.6minutes

Time = 26.6/60 hr

Time = 0.443hr

Average speed  = 17.9/0.443

Average speed = 40.38km/hr

b) If she returned home by the same path 7 h 30 min after she left, the distance will be the same;

Distance = 17.9km

Time = 7.5hr

Average speed = 17.9/7.5

Average speed = 2.387km/hr

Velocity of the entire trip = 40.38km/hr + 2.387km/hr

Velocity of the entire trip = 42.77km/hr

Hence the velocity of the entire trip is 42.77km/hr

Answer:

Participant 1 wins

Explanation:

Coefficient of static, μ = F/N, where F is the frictional force and N is the normal force.

The force exerted by each participant is the sum of the frictional force acting on each of them and the maximum force with which each participant pulls on the rope.

Frictional force, F =  μ * N

Normal force, N = mass * acceleration due to gravity, g

For Participant 1; μ = 2.0, mass = 60 kg, g = 9.8 m/s²

Frictional force = 2.0 * 60 * 9.8 = 1176 N

Total force = (1176 + 1000) = 2176 N

For Participant 2; μ = 1.2, mass = 80 kg, g = 9.8 m/s²

Frictional force = 1.2 * 80 * 9.8 = 940.8N

Total force = (940.8 + 1200) N = 2140.8 N

From the values obtained above, Participant 1 exerts more force than Participant 2, therefore, Participant 1 wins

Answer:

The added mass will mean a longer period of oscillation.

Explanation:

The period of oscillation here is given by the formula;

T = 2π√(m/k)

Where m is mass and k is spring constant

From the equation of oscillation period above, it's obvious that when we increase the mass, the oscillation period will also increase.

Thus, the added mass will mean a longer period of oscillation.

Answer:

just use y = mx + b to create an equation of the line in the graph.

then you can plug in 15 for x and then convert 1.5 hours into minutes and plug it in as well.

you dont even need to make an equation for a line. just add 0.2 for every 3 mins.

at 9, it's 0.6, so at 12 it would be 0.8, and then 15 it would be 1.0.

go again all way for 1. 5 hours.

Explanation:

the slope is 0.1/1.5 so you equation would be y = 0.1/1.5x

the slope is rise/run.

Answer:

b gases

Explanation:

this is because gases spread out through out the entire container because they have no definite shape and are always moving.

Answer and Explanation:

(a) The fre-body diagrams for each block is shown below. In the block of mass 3.60 kg, there are 3 forces acting on it: horizontal force due to the rope ([tex]F_{t}[/tex]), vertical gravitational force ([tex]F_{g}[/tex]) and vertical normal force ([tex]F_{n}[/tex]), due to the surface. Since there is no vertical movement, [tex]F_{g}[/tex] and [tex]F_{n}[/tex] cancels it out. So, for this block, net force is horizontal due to the rope [tex]F_{t}[/tex].

The block of mass m is hanging from the pulley, so there is the force of the rope ([tex]F_{t}[/tex]) and the gravitational force ([tex]F_{g}[/tex]). Both are vertical, because there is no surface "holding" block m.

(b) Since both blocks are attached to each other, the acceleration will be the same. To calculate it, we use the Second Law of Motion:

[tex]F_{r}=m.a[/tex]

[tex]a=\frac{F_{r}}{m}[/tex]

[tex]a=\frac{18.8}{3.6}[/tex]

a = 5.22

The acceleration of either block is 5.22 m/s².

(c) Block m has 2 forces acting on it: tension and gravitational force. Gravitational force is the force of attraction the Earth does over an object. It is calculated as the product of mass and gravitational acceleration, which has magnitude g = 9.8 m/s².

Suppose positive referential is going up. To determine mass:

[tex]F_{r}=m.a[/tex]

[tex]F_{t}-F_{g}=m.a[/tex]

[tex]F_{t}-m.g=m.a[/tex]

[tex]18.8-9.8m=5.22m[/tex]

[tex]15.02m=18.8[/tex]

m = 1.25

Block m has 1.25 kg.

(d) Gravitational force is also called weight. So, as described above: [tex]F_{g}=m.g[/tex].

The weight for the hanging block is

[tex]F_{g}=1.25*9.8[/tex]

[tex]F_{g}=[/tex] 12.25 N

Comparing tension and weight:

[tex]\frac{12.25}{18.8}[/tex] ≈ 0.65

We can see that, weight of the hanging block is almost 0.65 times smaller than the tension on the rope.

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

[tex] T = \frac{PV}{nR} [/tex]

[tex] T_{i} = T_{f} [/tex]

[tex] \frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR} [/tex]

Where:

[tex]P_{i}[/tex]: is the initial pressure = 5.79 atm

[tex]P_{f}[/tex]: is the final pressure =?

[tex]V_{i}[/tex]: is the initial volume = 420 cm³

[tex]V_{f}[/tex]: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

[tex] P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm [/tex]

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

[tex] W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J [/tex]

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

Option 3.) Increasing the voltage across the wire.

I know that the other answers are incorrect because, for one thing, the more resistance in a substance, the less flow of the current there is. Also, using a longer wire doesn't change anything, it just makes a electrical current go on longer. Lastly decreasing the voltage would make the current decrease in the atoms that flow through it to power an object.

-R3TR0 Z3R0

Answer:

the speed of the electron from charge q1 is 7.17×10⁶ m/s

Explanation:

Given the data in the question;

the potential at the center of the two charges will be;

V = k( q1/(d/2) + q2/(d/2)

so we substitute

V = (9×10⁹)( (3.95×10⁻⁹/(0.39/2) + 1.80×10⁻⁹/(0.39/2)

V = 265.4 V

the potential at a distance of 10 cm from the charges will be

V = k( q1/(d1) + q2/(d2)

(d1 = 10cm = 0.1m and d2 = 39cm - 10cm = 29cm = 0.29m )

V' = (9×10⁹)( (3.95×10⁻⁹/0.1 + 1.80×10⁻⁹/0.29

V' = 411.4 V

Now, from the conservation of energy the speed of the electron from charge q1 will be;

E = ( V' - V) qe

1/2mv² = ( V' - V) qe

v² = [( V' - V) qe] / 1/2m

v =√ ([( V' - V) qe] / 1/2m)

v =√ ([2( V' - V) qe] / m)

we substitute

v =√ (2[( 411.4  - 265.4) 1.6×10⁻¹⁹] / 9.1×10³¹)

v = 7.17×10⁶ m/s

Therefore, the speed of the electron from charge q1 is 7.17×10⁶ m/s

Answer:

The net force on the hovercraft is 11200 N.

Explanation:

Given;

force exerted on the hovercraft by wind, F₁ = 5000 N north

force exerted on the hovercraft by the propeller, F₂ = 10,000 N west

The net force on the hovercraft is calculated as;

[tex]F_{net} = \sqrt{F_1^2 + F_2^2} \\\\F_{net} = \sqrt{5000^2 + 10,000^2} \\\\F_{net} = 11180.34 \ N\\\\F_{net} = 11200 \ N \ (3.s.f)[/tex]

Therefore, the net force on the hovercraft is 11200 N.

Answer:

Explanation:

a ) from San Antonio to Houston let distance be d km .

Average speed = total distance / total time

time = distance / speed

Total time = (d / 2 x 75 ) +( d / 2 x 106 )

= .0067 d + .0047 d

= .0114 d

Average speed  = d / .0114 d = 87.72 km /h

b ) from Houston back to San Antonio

Total time = (d / 2 x 106 ) +( d / 2 x 75 )

= .0047 d + .0067 d

= .0114 d

Average speed  = d / .0114 d = 87.72 km /h

c )

For entire trip :

total distance = 2d

total time = 2 x .0114 d

Average speed  = 2 d / 2 x .0114 d

= 87.72 km /h .

Answer:

suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale. Denaturation, in biology, the process of modifying the molecular structure of a protein. Denaturation involves the breaking of many of the weak linkages, or bonds (e.g., hydrogen bonds), within a protein molecule that is responsible for the highly ordered structure of the protein in its natural (native) state.

Explanation:

hope this helps have a good rest of your day :) ❤

Explanation:

HW1. For example, suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale.

HW2. The word denature means to render food unpleasant or dangerous to consume, it is denatured by adding a substance known as a denaturant. Aversive agents—primarily bitterants and pungent agents—are used to produce an unpleasant flavor.

Hope It Helps U

Please Mark As Brainl

Answer:

I found it!

Explanation:

Answer:

Explanation:

displacement vessels

The can is filled to the top with water and the object placed in it. The volume of the object is equal to the volume of the water that is forced through the spout. Eureka cans are named after a scientist called Archimedes who first recorded this idea. They are sometimes also called displacement vessels.

Answer:

B light is produced by chemical change

Explanation:

im not the smartest but if you think about it, fireworks make bright lights. And what do they have: powders.

(but I still could wrong, sorry if I am)

Answer:

Explanation:

individual and then net

hope that helps I could be wrong about this one though

Among the options given, the choice that would make the best soundproofing for a room is option C: two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them.

Soundproofing is achieved by reducing the transmission of sound waves from one side of the wall to the other. In this case, the combination of two layers of glass with a vacuum between them helps to reduce sound transmission effectively.

Glass is a denser material compared to air or vacuum, so it naturally provides some sound insulation. Adding an extra layer of glass creates a barrier that helps to further dampen sound vibrations. The vacuum between the glass layers acts as an additional sound barrier, as sound waves have difficulty propagating through a vacuum due to the absence of a medium for transmission.

On the other hand, a single layer of 1.0 centimeter thick glass (option A) or two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them (option B) would provide some sound reduction but not as effective as the combination of glass layers with a vacuum in option C.

1.0 centimeter thick steel (option D) would have high density and mass, which could help with sound insulation to some extent. However, steel can still transmit vibrations and might not be as effective as the combination of glass layers with a vacuum in option C for soundproofing a room.

For more such questions on Soundproofing

https://brainly.com/question/30258610

#SPJ8

Answer:

Its the sum of the potential energy and the kinetic energy

Answer:

The shift in the emission spectra of the relative velocity between the star and our planet, is called the relativistic doppler effect

Explanation:

The absorption and emission spectra are measured differently, the emission spectrum is the spectrum emitted by the star and the absorption spectrum is the absorption of these lines by the gases of our atmosphere, this absorption occurs for relatively broad Δλ.

The shift in the emission spectra of the relative velocity between the star and our planet, is called the relativistic doppler effect and has a red shift if the star moves away from us.

           [tex]f_o = f_s \sqrt{\frac{1- v/c}{1 + v/c} }[/tex]

Answer:

Option D. is correct.

Explanation:

The object's mechanical energy refers to the sum of the potential and kinetic energies of the object. When an object falls, its potential energy (PE) decreases, and its kinetic energy (KE) increases. The increase in kinetic energy is exactly equal to the decrease in potential energy.

Option D. is correct.

The spring constant : k = 40 N/m

Given

Force = 20 N

The displacement of the spring=x=0.5 m

Required

The spring constant = k

Solution

Hooke's Law

F = k.x

k = F/x

Input the value :

k = 20/0.5

k = 40 N/m

Answer:

3. Fructose

Explanation:

Fructose is a sugar found naturally in fruits, fruit juices, some vegetables and honey.

it is number 3 (Fructose)

Answer:

v = 4.0 m/s

Explanation:

       [tex]p_{f} = m_{w} * v_{w} + m_{g+w} *v_{g+w} = 0 (1)[/tex]

       [tex]v_{g+w} =- \frac{m_{w} *v_{w}}{m_{g+w} } = - \frac{36.0kg *6.5m/s}{58.0kg } = -4.0m/s (2)[/tex]

Answer:

A, C, D and E are the true statement about current flowing.

Answer:

If A + B = C for the vector equation then substituting for B gives

A + (-A) = C = 0

The only thing that can be said about "C" is that it has zero magnitude.

Answer: [tex]r = \sqrt{\frac{p}{4pil}}[/tex]

Explanation:

[tex]l = \frac{p}{4pir^2} \\4pir^2l=p\\r^2 = \frac{p}{4pil} \\r = \sqrt{\frac{p}{4pil}}[/tex]