After lunch, you see the bumper cars and want to ride them. Here’s what the sign says:

Bumper Cars:

6 minutes: 8 tickets

8 minutes:12 tickets

Which one gives you more time for your money?

Answer:

235÷18=

how many classes of 18 students for each teacher

Step-by-step explanation:

The solution to the question is 265.

Logarithm of a number A is the exponent or power or index n, a given number called the base B would be raised to give the number A.

So n is the logarithm of A to base B.

Analysis:

log 2( log2(x-9)) = 3

log2(x-9) = [tex]2^{3}[/tex]

log2(x-9) = 8

x-9 = [tex]2^{8}[/tex]

x-9 = 256

x = 256 + 9

x = 265

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The piece-wise linear functions can be written as follows:

A linear function is modeled by:

y = mx + b

In which:

For x equal or less than -2, the line passes through (-3,-3) and (-2,-2), hence the rule is:

[tex]f(x) = x, x \leq -2[/tex].

For x greater than -2 up to 1, the y-intercept is of -7, and the line also passes through (1,-8), hence the rule is:

[tex]f(x) = -x - 7, -2 < x \leq 1[/tex].

For x greater than 1, the function goes through (2,-5) and (3,-3), hence the slope is:

m = (-3 - (-5))(3 - 2) = 2.

The rule is:

y = 2x + b.

When x = 2, y = -5, hence:

-5 = 2(2) + b

b = -9.

Hence:

[tex]f(x) = 2x - 9, x > 1[/tex].

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Answer:

None of these is not true

The line segment in the figure can be named as: IYM and MYI.

If we have three points on a line segment, the point on the middle will be the alphabet in the center when naming the line, while the alphabets of both endpoints can be written either at the beginning or ending.

Given the figure above, Y will be at the center. The endpoints are I and M. Therefore, the line segment can be named as: IYM and MYI.

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x=regular selling price

X×80/100=380

= X×8/10=380

= 8X=380×10=3800

X=3800/8

X=475

the regular selling price is 475

Before the 20% discount, the TV's regular selling price was $475 as per the concept of percentage.

Let's denote the regular selling price of the plasma TV as "x". When the TV was marked down by 20%, the sale price became $380.

To find the regular selling price, we can set up an equation using the information given:

Sale Price = Regular Selling Price - (Discount Percentage × Regular Selling Price)

$380 = x - (0.20x)

Now, let's solve for "x" (the regular selling price):

$380 = x - 0.20x

$380 = 0.80x

To isolate "x," we divide both sides of the equation by 0.80:

x = $380 / 0.80

x = $475

The regular selling price of the plasma TV is $475.

Therefore, before the 20% discount, the TV's regular selling price was $475. After the discount, the sale price was reduced to $380, which is 20% less than the regular price.

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Answer:

the rectangles area is 24 meters

Step-by-step explanation:

area = length x width

length is 6 using the words long and width is 4

Answer:

area = 24 cm²

Step-by-step explanation:

The area of a rectangle can be found using the formula:

[tex]\boxed {area = length \times width}[/tex].

Substituting the values into the equation:

[tex]area = 6 \space\ cm\times 4 \space\ cm[/tex]

       ⇒ [tex]\bf 24 \space\ cm^2[/tex]

The equation for a circle is:

[tex](x-a)^{2} + (y-b)^{2} + = r^{2}[/tex]

Where (a,b) is the circle's center and r is the circle's radius.

First, we can find the center point of the circle. Because the two points from the problem are the endpoints of a diameter, the midpoint of the line segment is the center point of the circle.

The formula to find the mid-point of a line segment giving the two endpoints is:

M = [tex](\frac{x_{1} + x_{2} }{2}[/tex], [tex]\frac{y_{1} + y_{2} }{y} )[/tex]

Where M is the midpoint and the given points are:

[tex](x_{1}, y_{1} )[/tex] and [tex](x_{2} , y_{2})[/tex]

Substituting the values from the two points in the problem gives:

[tex]M = (\frac{11+9}{2}[/tex],[tex]\frac{-2+4}{2} )[/tex]

[tex]M = (\frac{11+9}{2}[/tex],[tex]\frac{2-4}{2})[/tex]

[tex]M = (\frac{20}{2} , \frac{2}{2})[/tex]

[tex]M = (10,1)[/tex]

If you randomly purchase one item, the probability it will last longer than 9 years is; 11.12%

The formula for Z-score is;

z = (x' - µ)/σ

where;

x' = sample mean

µ = population mean

σ = standard deviation

Thus;

z = (9 - 7.9)/0.9

z = 1.22

From online p-value from z-score calculator, we have;

probability = 0.1112 = 11.12%

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Answer:4x/5-1/5 = y

Step-by-step explanation:

We need to get y by itself

4x+2=5y+3

subtract 3 from both sides

4x-1=5y

divide both sides by 5

4x/5-1/5 = y

Answer:

[tex]4x + 2 = 5y + 3[/tex]

[tex]5y + 3 = 4x + 2[/tex]

[tex]5y = 5x + 2 - 3[/tex]

[tex]5y = 4x - 1[/tex]

[tex] \frac{5y}{5} = \frac{4x - 1}{5} [/tex]

[tex]y = \frac{4x - 1}{5} [/tex]

The length and width of the rectangle are 5 inches and 1 inches respectively.

The length and width of the rectangle can be found as follows;

l = 3 + 2w

area of a rectangle = lw

where

Therefore,

5 = lw

5 = (3 + 2w)w

5 = 3w + 2w²

2w² + 3w - 5 = 0

Hence,

2w² + 3w - 5 = 0

Therefore,

w = 1  and w = - 5 / 2

width = 1 inches

length =  3 + 2(1) = 5 inches

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Answer:

4.6 minutes

Step-by-step explanation:

Average = the sum of the numbers/ the number of numbers

Plug in the numbers: 2+3+6+8+4/5 = 23/5 = 4.6 minutes

The monthly payments for this add on interest loan are of $164.71.

Given Information and Formula Used

It is given that for an add on interest loan,

Principal Amount, p = $8,276.17

Annual Interest Rate, r = 5.7%

Term of the loan, T = 5.5 years

The formula for simple interest is given as follows,

I = (p)(r)(t)/100 ............... (1)

The formula for total amount of add on interest is given by,

A = p + I ....................... (2)

Computing the Interest

Substitute the given values of p, r, and t in the formula (1) of interest to get,

I = (8276.17)(5.7)(5.5)/100

I = 259457.9295/100

I = $2,594.58

Computing the Monthly Payment for Add-on Interest Loan

Substituting the values of p and I in the formula (2), we obtain the total amount as,

A = $ (8276.17 + 2594.58)

A = $ 10,870.75

Monthly payment for the add on interest loan = A/t(in months)

=  $ (10,870.75/66)

= $164.71

Therefore, monthly payments of $164.71 are to be made for the add on interest loan.

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The values of a and b of the exponential function are 10000 and 0.6 respectively

We are given that the exponential function is expressed in general form as; f(x) = abˣ

where;

a is a non-zero real number called the initial value

b is any positive real number such that

b ≠ 1.

The domain of f is all real numbers.

The range of f is all positive real numbers if a > 0.

The range of f is all negative real numbers if a < 0.

The y-intercept is (0, a)

The horizontal asymptote is; y = 0.

We are told that this exponential function passes through the coordinate points (0, 10000) and (3, 2160).

At coordinate point (0, 10000), we have;

10000 = ab⁰

a = 10000

Now, at the coordinate point (3, 2160), we have;

2160 = 10000(b)³

2160/10000 = b³

0.216 = b³

b = ∛0.216

b = 0.6

Thus, we can conclude that the values of a and b of the given exponential function are respectively 10000 and 0.6.

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Answer:

30624; 1514,6; a1,6.

Answer:

87.5%

Step-by-step explanation:

Given:

Area of triangle NCM

⇒ 1/2 × base × height

⇒ 1/2 × CN × CM

⇒ 1/2 × 5 × 4

⇒ 10cm²

Length of rectangle ⇒ 10

Breadth of the rectangle ⇒ 8

↓

Area of rectangle ⇒ Length × Breadth

Area of rectangle ⇒ 10 × 8 = 80cm²

Area of shaded region ⇒ Area of rectangle  -  Area of triangle

Area of shaded region ⇒ 80 - 10 = 80cm²

Percentage of the shaded region = Shaded/complete rectangle × 100

⇒ 70/80 × 100 = 87.5

⇒ The percent of the area of the rectangle shaded is therefore 87.5%.

The current stock price is $54.15.

Given that  RLX Company just paid a dividend of $2.85 per share on its stock and dividends are expected to grow at a constant rate of 4.5 percent per year, indefinitely.

Stock valuation alludes to the valuation of the natural worth per portion of an organization's stock which can help the organization in deciding its reasonable worth in case of twisting up or consolidation. One of the models used to esteem the stock cost is the profit development model. It expects the cost of the stock to be the current worth representing things to come profits of the stock accepted to develop at a consistent rate.

Dividend (D0) = $2.85

Growth rate (g) = 4.5%

Required return (r) = 10%

Firstly, we have to calculate the value of the current stock price.

The current stock price can be calculated by using the dividend growing model.

[tex]\begin{aligned}\text{Current stock price}&=\frac{D_{0}\times(1+g)}{r-g}\\ &=\frac{2.85\times (1+0.045)}{0.10-0.045}\\ &=\frac{2.85\times 1.045}{0.055}\\ &=\frac{2.97825}{0.055}\\ &=54.15\end[/tex]

Hence, the current stock price when dividend of $2.85 are expected to grow at a constant rate of 4.5 percent per year, indefinitely is $54.15.

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Answer:

A

Step-by-step explanation:

the sum to n terms of a geometric series is

[tex]S_{n}[/tex] = [tex]\frac{a_{1}(r^{n}-1) }{r-1}[/tex] , then for n = 7

S₇ = [tex]\frac{-1(2^{7}-1) }{2-1}[/tex] = [tex]\frac{-1(128-1)}{1}[/tex] = - 1 (127) = - 127

12 inches

A regular polygon is any 2-D shape where all the sides and angles are congruent.

Regular Hexagon

As denoted by the prefix "hexa-", hexagons have 6 sides and internal angles. The perimeter is equal to all 6 sides added together. However, we know that these sides must be congruent because it is a regular hexagon.

Solving for Perimeter

We can create an equation that describes the perimeter of this shape, with "x" representing the length of one side.

Since all the sides are equal we can use multiplication instead of addition. To solve this equation, divide both sides by 6.

This means that all sides must be 12 inches.

Answer:

  D. y+5=2(x−4)

Step-by-step explanation:

The point-slope form of the equation of a line is useful for writing an equation for a line through a given point with a given slope.

The point-slope form of the equation of a line is ...

  y -k = m(x -h) . . . . . . line through point (h, k) with slope m

We want a line through point (h, k) = (4, -5) with slope m = 2. Putting these numbers into the form gives ...

  y -(-5) = 2(x -4)

  y +5 = 2(x -4) . . . . . . simplifying the signs

The area of the interior above the polar axis is -0.858 square units

The area bounded by a polar curve between θ = θ₁ and θ = θ₂ is given by

[tex]A = \int\limits^{\theta_{2} }_{\theta_{1} } {\frac{1}{2}r^{2} } \, d\theta[/tex]

Now, since we have the curve r = 1 - sinθ and we want to find the area of the interior above the polar axis, we integrate from θ = 0 to θ = π, since this is the region above the polar axis.

So, [tex]A = \int\limits^{\theta_{2} }_{\theta_{1} } {\frac{1}{2}r^{2} } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}(1 - sin\theta)^{2} } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}[1 - 2sin\theta + (sin\theta)^{2}] } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}\, d\theta - \int\limits^{\pi}_{0} 2sin\theta \, d\theta+ \int\limits^{\pi}_{0} (sin\theta)^{2} } \, d\theta\\[/tex]

[tex]A = \int\limits^{\pi}_{0} {\frac{1}{2}\, d\theta - 2\int\limits^{\pi}_{0} sin\theta \, d\theta+ \int\limits^{\pi}_{0} \frac{(1 - cos2\theta)}{2} } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}\, d\theta - 2\int\limits^{\pi}_{0} sin\theta \, d\theta+ \int\limits^{\pi}_{0} \frac{1}{2} } \, d\theta -\int\limits^{\pi}_{0} \frac{cos2\theta}{2} } \, d\theta\\[/tex]

[tex]A = \int\limits^{\pi}_{0} \, d\theta - 2\int\limits^{\pi}_{0} sin\theta \, d\theta -\int\limits^{\pi}_{0} \frac{cos2\theta}{2} } \, d\theta\\= [\theta]_{0}^{\pi} - 2[-cos\theta]^{\pi} _{0} - [\frac{sin2\theta}{4}]_{0}^{\pi} \\= [\theta]_{0}^{\pi} + 2[cos\theta]^{\pi} _{0} - [\frac{sin2\theta}{4}]_{0}^{\pi}\\= [\pi - 0] + 2[cos\pi - cos0] - \frac{ [sin2\pi - sin0]}{4}\\= \pi + 2[-1 - 1] - \frac{ [0 - 0]}{4}\\= \pi + 2[-2] - \frac{ [0]}{4}\\= \pi - 4 - 0\\= \pi - 4\\= 3.142 - 4\\= -0.858[/tex]

So, the area of the interior above the polar axis is -0.858 square units

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It is an example of Type I error.

About Type I error

The rejection of a null hypothesis (H0) when it is actually true is a Type I error. It is represented by the following condition,

Failure to reject a null hypothesis when it is true that it is false which is a Type II error.

How is this an example of Type I error?

The given case's hypothesis is described as follows:

H₀: The product has no effect on the plant's height.

Hₐ: The substance causes the plant to enlarge.

The sample claims that the product causes the plant to grow taller, however in reality, it has no effect on the plant's height.

Therefore, the sample recommends rejecting the null hypothesis even though it is true. Consequently, a result, this error is a Type I error.

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The province's population is growing at the rate of  58.34 %

Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable. The calculation for ROC is simple in that it takes the current value of a stock or index and divides it by the value from an earlier period.

Given:

Initial Population = 4.2 million

Population after 20 years = 6.65 million

Change in population = 6.65 - 4.2 = 2.45 million

Rate at which the province's population growing is

= [tex]\frac{Change in population}{Inital Population}[/tex] x100 %

= [tex]\frac{2.45}{4.2}\\[/tex] x 100%

= 58.34 %

Thus the province's population is growing at the rate of  58.34 %

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Answer:

u = -225

Step-by-step explanation:

36 - u = 261

-u = 261 - 36

-u = 225

u = -225

It is to be noted that the determination of whether or not there is a significant difference between the two groups will be done using a t test.

A t-test is a statistical test that juxtaposes two samples' means. It is used in hypothesis testing, using a null hypothesis that the variance in group means is zero and an alternative hypothesis that the difference is not zero.

The conditions to use the t test are:

The degrees of freedom (k) to be utilized for this text will be derived using the conservative method given below:

df = [(s₁²/n₁) + (s₂²/n²)/[((s₁²/n₁)²/((n₁-1)) + (s₂²/n₂)²/((n₂-1))]

= [(3.0952/15) + (6.4095/15)]² / [((3.0952/15)²/14) + ((6.4095/15)²/14)]

= 24.965

Hence,

df ≈ 24 (if approximated to the floor)

Recall the the standard deviation of the population are unequal and unknown. This thus requires that we utilize the two-sample unpooled t-test.

Here, H₀ is given as;

[tex]t = \frac{\bar{x_{1} -\bar{x_{2}}}}{\sqrt{\frac{s_{1}^{2} }{n_{1} } + \frac{S_{2}^{2} }{n_{2}} } } \sim t_{df}[/tex]

t = [(3.33333 - 4.13333)]/√[(3.0952/15) + (6.4095/15)]

= - 0.8/√0.6337

t = - 1.005

The 95% confidence interval is computed using the following formula:

[tex](\bar x_{2} - \bar x_{1}) \pm t_\alpha_/_2_,_df \left({\sqrt{\frac{S_{1}^{2} }{n_{1} } + \frac{S_{2}^{2} }{n_{2}} } } \right)[/tex]

= - 0.8 ± t₀.₀₂₅,₂₄ (√0.6337)

= - 0.8 ± 2.064 (√0.6337)

= -2.4429, 0.8429

To derive the 90% interval, we state:

[tex](\bar x_{2} - \bar x_{1}) \pm t_\alpha_/_2_,_df \left({\sqrt{\frac{S_{1}^{2} }{n_{1} } + \frac{S_{2}^{2} }{n_{2}} } } \right)[/tex]

= - 0.8 ± t₀.₀₅₀,₂₄ (√0.6337)

= - 0.8 ± 0.685 (√0.6337)

= -2.162, 0.562

From the intervals computed, we must fail to reject H₀

H₀ : μ₁ = μ₂

It is clear from the above intervals computed from that the differences between the mean of both groups is significant. This is because, zero is included on the two intervals.

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Given :

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \gray{ \frak{The \: given \: two \: \: points \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}[/tex]

[tex] \: [/tex]

Let's solve by using midpoint formula :

[tex] \: [/tex]

[tex] \bf \boxed{\color{red}\frak{Midpoint \: \: Formula : {( \: x ,\:y \: ) = }( \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}[/tex]

[tex] \: [/tex]

[tex] \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}[/tex]

[tex] \: [/tex]

[tex] \: \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}[/tex]

[tex] \: [/tex]

[tex]\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \cancel\frac{ -4}{2} , \cancel\frac{ - 5}{2} )}}[/tex]

[tex] \: \: [/tex]

[tex] \underline{ \boxed{ \large \red{ \frak{option \: d }( \frak{ - 2, - 2.5)}}}}✓[/tex]

Hope Helps! :)

The solution to the inequality expression is x>5 and the correct representation is a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Inequality expressions are expression not separated by an equal sign

Given the following inequality expression

–3(2x – 5) < 5(2 – x)

Expand

-6x + 15 < 10 - 5x

Collect the like terms

-6x + 5x < 10 -15

-x < -5

x > 5

Hence the solution to the inequality expression is x>5 and the correct representation is a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

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The function g(x) is g(x)= (3x)^2

The complete question is in the image

From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

So, we have:

g(x)= (3x)^2

Hence, the function g(x) is g(x)= (3x)^2

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