a) Probability that the flight will accommodate all ticketed passengers who show up is 0.16
b) Probability that not all ticketed passengers who show up can be accommodated is 0.67
c) The probability that you will be able to take the flight is 96%
Probability is a powerful tool to understand the likelihood of different outcomes in various situations, including overbooking of flights
In this scenario, the random variable y represents the number of ticketed passengers who actually show up for the flight, out of a total of 55 ticketed passengers for a plane with only 50 seats. The probability mass function of y provides the probabilities for each possible outcome.
(a) The probability that the flight will accommodate all ticketed passengers who show up is the probability of y being equal to 50, which is 0.16.
(b) The probability that not all ticketed passengers who show up can be accommodated is the sum of the probabilities of y being greater than 50, which is
=> 0.05 + 0.10 + 0.13 + 0.14 + 0.25 = 0.67.
(c) If you are the first person on the standby list, the probability of being able to take the flight is the probability of y being less than or equal to 50, which is 0.89. This means that there is an 89% chance that you will get on the plane. If you are the third person on the standby list, the probability is the probability of y being less than or equal to 52 (since two people need to cancel or not show up for you to get on), which is 0.96. This means that there is a 96% chance that you will get on the plane.
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Find an autonomous differential equation with all of the following properties:equilibrium solutions at y=0 and y=3,y' > 0 for 0 y' < 0 for -inf < y < 0 and 3 < y < infdy/dx =
An autonomous differential equation with equilibrium solutions at y=0 and y=3, and y' > 0 for 0 < y < 3 and y' < 0 for -inf < y < 0 and 3 < y < inf is dy/dx = 3y(1-y).
An autonomous differential equation is a type of ordinary differential equation that does not depend on any other variable but time. It has a single variable, usually denoted as y, and a single independent variable, usually denoted as t or x. An autonomous differential equation with equilibrium solutions at y=0 and y=3, and y' > 0 for 0 < y < 3 and y' < 0 for -inf < y < 0 and 3 < y < inf is dy/dx = 3y(1-y). This equation will have two equilibrium solutions at y=0 and y=3. The derivative of the equation, y’, is greater than 0 for 0 < y < 3, which means that the equation is increasing in this range. The derivative of the equation is less than 0 for -inf < y < 0 and 3 < y < inf, which means that the equation is decreasing in this range. This equation is a type of logistic equation and is often used to model population growth. It is also used to describe other phenomena such as the spread of an epidemic or the number of species in an ecosystem. Using the initial conditions y(0) = 2 and y(1) = 3, we can calculate the values of y at other time points using the equation dy/dx = 3y(1-y). At t=0.5, the value of y is y(0.5) = 2.5; at t=1.5, the value of y is y(1.5) = 2.875; and at t=2.5, the value of y is y(2.5) = 2.9375.
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Ruby read 7 books in 14 months. What was her rate of reading in books per month?
Short Answer:
Ruby's rate if reading the books is:
2 months per book.
Long Answer:
If you look at it this way, two months per book means that by the time 14 months come you should have 7 books read.
Easy check to verify:
7 (books) X( mutltiply) 2(# of books) = 14 (total of months) - This shows that the number lead back to the original numbers
Hope this helps :)
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that P(A) = 0.7 and P(B) = 0.4.
A. Could it be the case that P(A ∩ B) = 0.5? Pick one:
i. Yes, this is possible. Since B is contained in the event A ∩ B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
ii. Yes, this is possible. Since A ∩ B is contained in the event B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
iii. No, this is not possible. Since B is equal to A ∩ B, it must be the case that P(A ∩ B) = P(B). However 0.5 > 0.4 violates this requirement.
iiii. No, this is not possible. Since B is contained in the event A ∩ B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
v. No, this is not possible. Since A ∩ B is contained in the event B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
A) No, P(A ∩ B) = 0.5, is not possible. In this case that P(A ∩ B) ≤ P(B). So, the correct choice is option (iii).
B) Probability that the selected student has at least one of these two types of cards is 0.8.
The probability of an event has different properties. If two events take place at the simultaneously, then we calculate their joint probabilities. The individual probabilities are called the marginal probabilities. Let us consider two events :
A : Event that the selected student has Visa card
B : Event that selected student has Master Card
Probability of occurrence of event A, P(A) =0.7
Probability of occurrence of event B, P(B) =0.4
A) P(A ∩ B) = 0.5 ,
No, this is not possible. Since, B is contain in the event (A ∩ B), it must be the case that
P( A ∩ B)≤ P(B). However, 0.5 > 0.4, violate this requirement. So, correct choice is option (iii).
B) Now, it is specific that the probability A and B is 0.3. The probability that the selected student has atleast one of these two types of cards will be, P(A∪B)
= P(A) + P(B) − P(A∩B)
= 0.7 + 0.4v− 0.3 = 0.8
So the probability is 0.8.
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Complete question:
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that P(A) = 0.7 and P(B) = 0.4.
A) Could it be the case that P(A ∩ B) = 0.5? Pick one:
i. Yes, this is possible. Since B is contained in the event A ∩ B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
ii. Yes, this is possible. Since A ∩ B is contained in the event B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
iii. No, this is not possible. Since B is equal to A ∩ B, it must be the case that P(A ∩ B) = P(B). However 0.5 > 0.4 violates this requirement.
iiii. No, this is not possible. Since B is contained in the event A ∩ B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
v) No, this is not possible. Since A ∩ B is contained in the event B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
B) From now on, suppose that P(A ∩ B)
= 0.3. What is the probability that the selected student has at least one of these two types of cards?
In a recent frisbee tournament, Hybrid scored 8 less points than Rival. Their
combined scores were 25. Let h represent Hybrid and rrepresent Rival
Which pair of equations can be used to determine their scores?
h+ 25 = r
h=8
h+r=25
h=r-8
h-r = 25
h=r-8
Oh+r=25
The pair of equation that can be used to determine their various scores would be = h+r = 25 and h = r-8. That is option B.
How to derive the equation that can be used to determine the scores?The total scores of the both student = 25
The score by Hybrid = h = r-8 (scored 8 less points than Rival).
The score by Rival = r
The total score of both student = h+r = 25 and h = r-8
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The system of equations used to determine the scores is given as follows:
h = r - 8.h + r = 25.How to model the system of equations?The variables of the system of equations are given as follows:
Variable h: number of points scored by Hybrid.Variable r: number of points scored by Rival.Hybrid scored 8 less points than Rival, hence:
h = r - 8.
Their combined scores were 25, hence:
h + r = 25.
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A questionnaire provides 58 Yes, 42 No, and 20 no-opinion answers. a. In the construction of a pie chart, how many degrees would be in the section of the pie showing the Yes answers? b. How many degrees would be in the section of the pie showing the No answers?
The tax money given by Andy is equivalent to $151.83.
What is pie chart?A pie chart is used to describe the data converted to equivalently proportional circle sectors.
Given is that a questionnaire provides 58 Yes, 42 No, and 20 no-opinion answers.
Total opinion polls - 58 + 42 + 20 = 120.
120 opinions cover 360°.
1 opinion will cover - (360/120)°.
58 opinions will cover - (360/120 x 58)° = 3 x 58 = 174°
Therefore, the 58 yes opinions will cover 174 degrees.
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Ms Jackson has 35 students in her class this is 9 more students than me Lopez has.
how many students does Miss Lopez have choose the correct equation and answer
Answer:
x+9=35
x = 26
Miss Lopez has 26 students in her class.
Step-by-step explanation:
this question has several parts that must be completed sequentially. if you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. a heavy rope, 30 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 80 ft high. approximate the required work by a riemann sum, then express the work as an integral and evaluate it(a) How much work W is done in pulling the rope to the top of the building?(b) How much work W is done in pulling half the rope to the top of the building?
(a). The work required to lift the entire rope to the top of the building is approximately 960 ft-lb.
(b). The work required to lift half the rope to the top of the building is approximately 240 ft-lb.
(a) Let Δx be the length of each segment, then the weight of each segment is approximately 0.6 Δx lb/ft, and the height of each segment is approximately 80 Δx / 30 ft. The work required to lift each segment is then approximately (0.6 Δx lb/ft) * (80 Δx / 30 ft) ft = 1.6 Δx^2 lb-ft.
W ≈ ∑ (1.6 Δx^2), where the sum is taken over all segments.
As Δx → 0, the Riemann sum approaches the integral:
W = ∫ [0,30] (0.6x/30) (80 - x) dx
where x represents the length of rope lifted above the ground level.
Evaluating this integral, we get:
W = 960 ft-lb
(b) Let x represent the length of the rope lifted above the ground level, then we need to find the work required to lift the rope from x = 0 to x = 15.
W = ∫ [0,15] (0.6x/30) (80 - x) dx
Evaluating this integral, we get:
W = 240 ft-lb
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A set of scores ranges from a high of X = 96 to a low of X = 27. If
these scores are placed in a grouped frequency distribution table
with an interval width of 10 points, the top interval in the table
would be
Answer: 90-99
Step-by-step explanation:
The top interval in the table would be 90-99. This is because the highest score (X = 96) falls within this interval, and the interval width is 10 points, which means that all scores between 90 and 99 would be included in this interval.
using the disk method, determine the volume of a solid formed by revolving the region bounded above by the line , on the left by the line , on the right by the curve , and below by the line the about the -axis.
The volume of a solid formed by revolving the region bounded above by the line is (932π/15)
To use the disk method, we need to integrate over the axis of revolution, which is the y-axis in this case. We can break the solid into vertical disks of thickness dy.
The radius of each disk is given by the distance between the y-axis and the curve [tex]x = y^2 - 1[/tex]. So the radius is:
[tex]r = y^2 - 1[/tex]
The height of each disk is the difference between the y-coordinate of the top curve y = 3 and the y-coordinate of the bottom curve y = 1. So the height is:
h = 3 - 1 = 2
The volume of each disk is then:
[tex]dV = \pi r^2h dy[/tex]
Substituting r and h, we have:
[tex]dV = \pi (y^2 - 1)^2 (2) dy[/tex]
To find the total volume, we integrate over the range of y from 1 to 3:
[tex]V = \int_{1}^{3} \pi(y^2 - 1)^2 (2) dy[/tex]
This integral can be simplified by expanding the squared term:
[tex]V = \int_{1}^{3} \pi (y^4 - 2y^2 + 1) (2) dyV = 2\pi \int_{1}^{3}(y^4 - 2y^2 + 1) dyV = 2\pi [(1/5)y^5 - (2/3)y^3 + y]^3_1[/tex]
V = [tex]2\pi [(1/5)(3^5 - 1^5) - (2/3)(3^3 - 1^3) + (3 - 1)][/tex]
V = 2π [(1/5)(242) - (2/3)(26) + 2]
V = 2π [(242/5) - (52/3) + 2]
V = 2π [(726/15) - (260/15) + 30/15]
V = 2π [(466/15)]
V = (932π/15)
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Note: The full question is
Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graphs of the equations about the given lines. y = 1, y = 3, x = y^2 - 1.
Use the Quotient Rule to find the derivative of the given function Simplify your answers. 31. f(x) =x^4 +1/x^3 32. f(x) = x^5 -1/x^2 33. f(x) = x+1/x-134. f(x) = x - 1/x + 1 35. f(x) = 3x + 1/2+x36. f(x) = x+1/ 2x^2 +1 37. f(t) = t^2 -1/t^2 +1 38. f(t) = t^2 + 1/ t^2 - 1
By the quotient rule the derivative of all functions can be found in an easy way,
(1) [tex]f'(x)=\frac{x^6+128x^3-3x^2}{(x^3+32)^2}[/tex]
(2) [tex]f'(x)=\frac{5}{(2+x)^2}[/tex]
(3) [tex]f'(t)=\frac{4t}{(t^2+1)^2}[/tex]
The Quotient Rule in calculus is a technique for figuring out a function's derivative (differentiation) as the ratio of two differentiable functions. It is a formal rule applied to issues involving differentiation where one function is split in half by another function. The definition of the limit of the derivative is followed by the quotient rule. Keep in mind that the bottom function is where the quotient rule starts and where it finishes.
The quotient rule is similar to the product rule. A Quotient Rule is stated as the ratio of the quantity of the denominator times the derivative of the numerator function minus the numerator times the derivative of the denominator function to the square of the denominator function. In short, the quotient rule is a way of differentiating the division of functions or the quotients
We have the functions
(1) [tex]f(x)=\frac{x^4+1}{x^3+32}[/tex]
derivative with respect to x by the quotient rule.
[tex]f'(x)=\frac{(x^3+32)(4x^3)-(x^4+1)(3x^2)}{(x^3+32)^2}\\\\f'(x)=\frac{4x^6+128x^3-3x^6-3x^2}{(x^3+32)^2}\\\\f'(x)=\frac{x^6+128x^3-3x^2}{(x^3+32)^2}[/tex]
2) derivative with respect to x of the below function
[tex]f(x)=\frac{3x+1}{2+x}\\\\f'(x)=\frac{(x+2)(3)-((3x+1))}{(2+x)^2}\\\\f'(x)=\frac{5}{(2+x)^2}[/tex]
3)
[tex]f(t)=\frac{t^2-1}{t^2+1}[/tex]
derivative with respect to t,
[tex]f'(t)=\frac{(t^2+1)(2t)-(t^2-1)(2t)}{(t^2+1)}\\\\f'(t)=(2t^3+2t-2t^3+2t)/(t^2+1)^2\\\\f'(t)=4t/(t^2+1)^2[/tex]
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I need help with this question
1) Note that the fire advanced 2697.55 ft. in the 6 minutes that the ranger was observing it.
2) the speed in MILES/HR that the fire advanced towards the ranger is 5.11 miles per hour. Note that this prompt is a unit conversion prompt.
What is the rationale for the above problem?1) Let 'd' represent the distance that the fire advance during the 6 minutes.
d = 3334/(tan(10.5)) - 3334 (tan (12.3)
d = (3334/0.18533904493) - (3334 /0.21803526043)
d = 17988.6542593289 - 15291.1047205155
d = 2697.5495388134
d [tex]\approx[/tex] 2697.55 ft.
2) to compute the speed, in Miles/ Hours, we need to first convert both distance and time into Miles and Hours respectively.
Recall that:
1 foot = 0.000189394 miles; thus,
2697.55 = 0.5108997847 Miles
Also, recall that
1 minute = 0.0166667 hours.
Thus, 6 minutes in hours =
0.0166667 * 6
= 0.1000002 hours.
Since speed = distance/time
Thus, the speed = 0.5108997847/ 0.1000002
= 5.1089876290 thus,
Speed [tex]\approx[/tex] 5.11 miles/Hour
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ALL I NEED IS LETTER A PLEASE HELP I GIVE BRAINLIEST
Answer:
a is b+g=30.
Step-by-step explanation:
You don't know how many boys and girls so you can only assume that together, they add up to 30. so using the equation b+g=30 you can say that the number of boys (B) and the number of girls (G) combined equal to 30.
Determine whether or not each of the following continuous-time signals is periodic. If the signal is periodic, determine its fundamental period. (a) x(t) 3 cos(4t (c) x(t) = [cos(2t--)]2 (d) x(t) &'{cos(4m)u(t)} + 풀) (b) x(t) e/m-I)
The signal, (a) x(t) = 3cos(4t) is periodic with period T = pi/2. To see this, we can compute:
x (t + T) = 3cos (4(t + pi/2)) = 3cos (4t + 2pi) = 3cos(4t)
which shows that the signal repeats itself every T = pi/2 seconds.
[tex](b) \times (t) = e^{( - t)} [/tex]
This signal is not periodic.
[tex]e^{(-t)} = e^{(-(t+T))} [/tex]
for all t.
However, this is not possible since e^(-t) approaches 0 as t approaches infinity. Therefore, the signal is not periodic.
[tex](c) \times (t) = [cos (2t - \frac{\pi}{3}] ^2[/tex]
This signal is periodic with period T = pi. To see this, we can compute:
[tex]x (t + T) = [cos (2(t + \pi) - \pi/3)] ^2 = [cos (2t + 5\pi/3)] ^2 = [cos (2t - pi/3)] ^2 = x(t) \\
(d) x(t) = cos(4t) u(t) + sin(4t) u(-t)[/tex]
This signal is not periodic. To see this, suppose that there exists a period T such that x(t) = x (t + T) for all t. Then we must have:
cos(4t) u(t) + sin(4t) u(-t) = cos(4(t+T)) u(t+T) + sin(4(t+T)) u(-(t+T)) for all t.
However, this is not possible since the two terms on the left-hand side have different signs for t < 0, whereas the two terms on the right-hand side have the same sign for t < -T.
Therefore, the signal is not periodic.
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NEED HELP FAST I WILL GIVE THE BRAINLIEST AND 15 pts
The length of PJ in the right triangle PNJ is determined as 24 inches.
How to calculate the length of PJ?The length of PJ is calculated by applying Pythagoras theorem as follows;
PJ² = PN² + NJ²
The given parameters;
NJ = 10 in
The length of PN = The length of PL = The length of PM
PL = 3x + 4
PM = 6x - 14
3x + 4 = 6x - 14
3x - 6x = -14 - 4
-3x = -18
x = 18/3
x = 6
Length PN = 3x + 4
PN = 3(6) + 4
PN = 22
Length PJ is calculated as follows;
PJ² = PN² + NJ²
PJ² = 22² + 10²
PJ² = 584
PJ = √584
PJ = 24.17 in
PJ ≈ 24 in
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the walls are fixed to the ground which wall is the most stable when the same lateral force is applied
The wall that is most stable when the same lateral force is applied is the wall that is anchored to the ground with the most support.
The wall that is anchored to the ground with the most support is the one that is most stable when the same lateral force is applied. This could include walls that are reinforced with steel beams or are built with heavier materials such as brick or concrete.
Lateral force is a force that acts perpendicular to the direction of motion of an object. It is usually caused by friction, gravity, or air resistance. The most common example of a lateral force is the force of friction between two objects when they are in contact.
This force can cause an object to move in a different direction than the one it was initially moving in. Lateral force can also cause an object to rotate or change its direction of motion entirely.
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which has the lowest unit rate
$0.27: 1
$ 0.18:1
$0.21:1
Select the correct answer.
Which of the following is a reason for needing to acquire a 1040X form?
O A.
O B.
O C.
to report income from interest
O D. to correct a bank routing number on a tax return
to request additional withholding from paychecks
to increase the number of allowances claimed
The reason for needing to acquire a 1040X form is D. to correct a bank routing number on a tax return
What is income tax?Income tax is a tax applied on individuals or entities concerning income or profit earned by them.
An IRS Form 1040-X is a form that refers to filled by citizens of a country who wish to make some changes in their tax return.
Also, to report payments received and payments due from the paying students.
Therefore, from the given option, reason for needing an 1040x form is to correct a bank routing number on a tax return
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3/8 + (-4/5)+(-3/8)+5/4
Answer : 9/20 or 0.45
Consider two connected tanks shown below. Tank 1 initially contains 300 L of brine (with unknown concentration), while tank 2 initially contains 300 L of pure water. Pure water flows into tank 1 at the rate of 500 L/hr into tank 1. The mixture in tank 1 flows into tank 2 at the rate of 500 L/hr, and the mixture in tank 2 leaves tank 2 at the same rate.
Describe how the amount of salt in tank 1 and tank 2 change over time.
Let x1(t) and x2(t) be the mass (in oz) of salt in tank 1 and tank 2, respectively. Solve x1(t) and x2(t).
Determine when the amount of salt in tank 2 reaches its maximum. (Note that the answer does not depend on the initial concentration in tank 1!)
We have also determined when the amount of salt in tank 2 reaches its maximum, which is when[tex]e^{t/180} = 6, \text{or}[/tex] t ≈ 1,080 minutes.
A mixture is a combination of two or more substances that are physically intermingled with each other, but not chemically bonded.
To determine when the amount of salt in tank 2 reaches its maximum, we can set the derivative of x2(t) with respect to time to zero and solve for t.
[tex]dx_2(t)/dt = (x_1(t)/500) * 500 * (1/180) * e^{t/180} - (x_2(t)/300) * 500 * (1/180) * e^{t/180} = 0[/tex]
Simplifying, we get:
[tex]x_1(t) * e^{-t/180} - (300/5) = x_2(t)[/tex]
Substituting the expression for x2(t) in terms of x1(t), we get:
[tex]x_1(t) * e^{-t/180} - (300/5) = (x_1(t) - (300/5)) * e^{t/18} + (300/5)[/tex]
Simplifying, we get:
[tex]2x_1(t) * e^{-t/180} = (600/5) * e^{t/180}[/tex]
Dividing by [tex]e^{t/180}[/tex] on both sides, we get:
[tex]2x_1(t) * e^{-t/180 - t/180} = (600/5)[/tex]
Simplifying, we get:
[tex]x_1(t) = (300/5) * e^{t/180}[/tex]
Substituting this value of x₁(t) in the expression for x₂(t), we get:
[tex]x_2(t) = (300/5) * (e^{t/180} - 1)[/tex]
This expression for x₂(t) gives us the amount of salt in tank 2 at any time t, and we can see that it increases with time until it reaches its maximum value of 300 oz. This occurs when [tex]e^{t/180}=6,[/tex], or t ≈ 1,080 minutes (or 18 hours), which is independent of the initial concentration in tank 1.
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What was the difference between the highest guess and the lowest guess? Write your answer as a fraction, mixed number, or whole number
The difference between the highest guess and the lowest guess, in the whole number, is 120.
What is subtraction?Subtraction is a mathematical operation. Which is used to remove terms or objects in the expression.
Given:
A table that shows the relationship between the guessed amount and the number of weeks.
Week Amount
1 120
2 140
3 160
4 240
Here, the highest guess is 240.
And the lowest guess is 120.
The difference between the highest guess and the lowest guess,
= 240 - 120
= 120
120 is a whole number.
Therefore, 120 is the required number.
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The complete question:
A table that shows the relationship between the guessed amount and the number of weeks.
Week Amount
1 120
2 140
3 160
4 240
What was the difference between the highest guess and the lowest guess? Write your answer as a fraction, mixed number, or whole number
Answer this question
Answer:
x+22
Step-by-step explanation:
3(x+4)+2(5-x)
3x+12 +2(5-x)
3x+12+10-2x
1x+12+10
1x+22
x+22
Thomas has a loan with a nominal interest rate of 6.4624% and an effective interest rate of 6.4715%. Which of the following must be true?
I. The loan has a duration greater than one year.
II. The interest on Thomas’s loan is compounded more than once yearly.
III. The economy was strong when Thomas took out the loan.
a.
I and II
b.
II only
c.
I and III
d.
III only
Please select the best answer from the choices provided
A
B
C
D
In the scanario where Thomas has a loan with a nominal interest rate of 6.4624% and an effective interest rate of 6.4715%; the statement true that occurs is that: II. The interest on Thomas’s loan is compounded more than once yearly.
Why is Statement II true based on the interest rated?Often, anytime we receive a higher effective interest rate then the rate stated, it implies that we have compound interest more than once yearly. , so, the makes the Statement II is true.
However, when one have have a loan for less then a year and still have those interest rates, you had calculate the rates based on a year effectiveness, but the loan calculations work for any duration. An economy and interest tend to fluctuate in response to each other, but are not indicators. Therefore, the statements I and III are not necessarily true.
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Write xxxxyyyzzzzz in exponential form.
The exponential form of xxxxyyyzzzzz is [tex]x^4 y^3 z^5[/tex].
What are exponential functions?When the expression of function is such that it involves the input to be present as exponent (power) of some constant, then such function is called exponential function. There usual form is specified below. They are written in several such equivalent forms.
For example, , where a is a constant is an exponential function.
Given that
The function with 3 variables xxxxyyyzzzzz
Now,
xxxx=[tex]x^4[/tex]
yyy=[tex]y^3[/tex]
zzzzz= [tex]z^5[/tex]
Substituting the following values in the function
= [tex]x^4 y^3 z^5[/tex].
Therefore, the exponential function will be [tex]x^4 y^3 z^5[/tex].
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david buys fruits and vegetables wholesale and retails them at davids produce. one of the more difficult decisions is the amount of bananas to buy. let us make some simplifying assumptions, and assume that david purchases bananas once a week at 10 cents per pound and retails them at 30 cents per pound during the week. bananas that are more than a week old are too ripe and are sold for 5 cents per pound. suppose the demand for the good bananas follows the same distribution as d given in the first question. assume that david buys 8 pounds of banana every week.
The expected profit per week for David is $4.25, with a standard deviation of $4.28.
Based on the given information, David purchases 8 pounds of bananas every week at 10 cents per pound, which costs $0.80 per week. The demand for good bananas follows the same distribution as d given in the first question. Using the probabilities given in d, we can calculate the expected revenue from selling the bananas. The expected revenue from selling good bananas is (0.30.6 + 0.050.3) * 8 = $1.56. The expected revenue from selling bad bananas is 0.05 * 8 = $0.40.
Thus, the expected total revenue is $1.96. The expected profit is the difference between the total revenue and the cost of purchasing the bananas, which is $1.16. The standard deviation of the profit can be calculated using the formula for the standard deviation of a linear combination of random variables, which gives a standard deviation of $4.28.
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find the volume of a pyramid with height 28 and rectangular base with dimensions 2 and 7 using integration
The volume of a pyramid can be calculated using integration is [tex]V = (1/3)(7*282 - 2*282) = 224 cubic units..[/tex]
The formula for the volume of a pyramid with a rectangular base with dimensions l and w, and height h is given by V = (lwh)/3. Using this formula, the volume of a pyramid with a rectangular base with dimensions 2 and 7 and height 28 can be calculated to be 224 cubic units.
To calculate this using integration, we can use the formula V = (1/3)∫b a y2dx, where a and b are the lower and upper limits of the rectangular base, and y is the height of the pyramid. In this case, a = 2, b = 7, and y = 28. Therefore, V = (1/3)(7*282 - 2*282) = 224 cubic units.
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John is selling tickets to an event. Attendees can either buy a general admission ticket, x, or a VIP ticket, y. The general admission tickets are $85 and the VIP tickets are $90. If he knows he sold a total of 28 tickets and made $2,425, how many of each type did he sell?
Enter a system of equations to represent the situation, then solve the system.
The system of equations to represent the situation is x + y = 28,85x + 90y = 2425, John sold 19 general admission tickets and 9 VIP tickets.
What is a system of equations?A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
We are given that;
Price of general ticket= $90
Number of tickets sold=28
Total price= $2425
Now,
Let x be the number of general admission tickets sold.
Let y be the number of VIP tickets sold.
From the problem, we know:
x + y = 28 (the total number of tickets sold is 28)
85x + 90y = 2425 (the total revenue from ticket sales is $2425)
We can use the first equation to solve for one of the variables in terms of the other:
y = 28 - x
Substituting this into the second equation:
85x + 90(28 - x) = 2425
Expanding and simplifying:
85x + 2520 - 90x = 2425
-5x = -95
x = 19
y = 28 - 19 = 9
Therefore, the system of equations will be x + y = 28,85x + 90y = 2425 and the solution is 19,9.
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I need answer now 20 point d
a
if you flip it the c point will be the opposite of the original coordinates
Solve the following equation:
2/3 + 1/x = 2/5 - 3/x
-15
-10
-45/19
Answer: To solve this equation, we'll start by getting all the terms with x on one side and all the constant terms on the other side. To do this, we'll subtract the 1/x terms from both sides:
2/3 + 1/x - 1/x = 2/5 - 3/x - 1/x
Simplifying the left side:
2/3 = 2/5 - 4/x
Adding 4/x to both sides:
2/3 + 4/x = 2/5
Multiplying both sides by the least common multiple of the denominators, which is 15:
10 + 60/x = 30/5
Expanding the right side:
10 + 60/x = 6
Subtracting 10 from both sides:
60/x = -4
Dividing both sides by 60:
1/x = -4/60
Dividing both sides by -1:
x = 15/4
So the solution to the equation is x = 15/4.
Step-by-step explanation:
A)
Nancy drew the triangle below.
a
с
A a= 2
B a=5
C a=6
D a=9
Which of the following could be the
measurements of the triangle's sides?
b
b=7
b=7
b=2
b=3
c= 10
c=9
c = 10
c = 12
Note that the option that could then be the measurement of the triangle with sides a, b, and c is (Option G)
A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. Triangle ABC denotes a triangle with vertices A, B, and C. In Euclidean geometry, any three non-collinear points define a unique triangle and, by extension, a unique plane.
The formula is given as follows:
a + b > c
a + c > b and
b + c > a.
Thus:
F ) is incorrect because:
2 + 7 < 10
G) is correct because
5 + 7 > 9
H) is incorrect because:
6 + 2 < 10
J) is Incorrect because
9 + 3 = 12 it ought to be greater than 12.
The option that thus meets all the conditions of the formula above is option G.
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Full Question:
See the attached
2.
Solve for x. Round to one
decimal place (nearest
tenth).
11
X
45°
5 is the measure of the value of x from the diagram
Solving triangles using trigonometry identityThe given diagram is a triangle with the following parameters
Opposite = 5
Adjacent = x
Using the trigonometry identity
tan theta = opp/adj
tan45 = 5/x
x = 5/tan45
x = 5/1
x = 5
Hence the measure of the value of x is 5.
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