Answer: on
Explanation:5
The price of sodium chloride per 5 kg is 179 dollars. The experiment requires 65 g of NaCl. The price of65 g or 0.065 kg is 2.3 dollars.
What is sodium chloride?Sodium chloride is an ionic compound formed by the combination of sodium metal and chlorine atom. Sodium metal has extra one electron in its valance shell and chlorine needs one more electron into its valence shell. Hence sodium donates its valence electron to chlorine forming NaCl.
NaCl is used as the table salt in food. It is a very important compound in our daily diet. Similarly NaCl is industrially important for many reaction especially in electrochemical processes.
It is given that, the price of 5 kg of NaCl = $179
required mass of NaCl = 65 g = 0.065 Kg
then , price of 0.065 kg = (0.065 × 179 /5) = $2.31
Therefore, the cost of NaCl in the experiment is 2.31 dollars.
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Balancing chemical reactions, what is it and two examples!!
PLEASE HELP I NEED THE ANSWER!!!
Giving lots of POINTS
Answer:
A balanced chemical reaction is an equation where the number of atoms of each type in the response is the same on both reactants and product sides.
Explanation: Burning, and cooking are two examples. :)
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What mass of 65% and 20% nitric acid must be mixed to produce 4.5 kg of 30% nitric acid?
The mass of 65% and 20% nitric acid that must be mixed to produce 4.5 kg of 30% nitric acid are 1.306 kg and 3.189 kg respectively.
What is the volume of 4.5 kg of 30% nitric acid?The volume of 4.5 kg of 30% nitric acid is determined using the formula below:
Volume = mass/densityThe density of 30% nitric acid is 1.18 g/mL
The mass of the 30% nitric acid is 4.5 kg or 4500 g
Hence, the volume will be:
The volume of 30% nitric acid = 4500 / 1.18
The volume of 30% nitric acid = 3813.56 mL
The volume of 65% and 20% nitric acid required is then determined.
Let the volume of the 65% and 20% nitric acid be x and y respectively;
x + y = 3813.56 ---(1)
amount of acid in 3813.56 ml solution = 30% * 3813.56
amount of acid in 3813.56 ml solution = 1144.07 mL
therefore;
60% * x + 20% * y = 1144.07 mL
0.6x + 0.2y = 1144.07 ----(2)
Solving for x and y in the two equations
From (1), x = 3813.56 - y
Substitute x = 3813.56 - y in (2)
0.6(3813.56 - y) + 0.2y = 1144.07
0.4y = 1144.07
y = 2860.18 mL
x = 3813.56 - 2860.18
x = 953.38 mL
The mass of the acids required is then determined as follows:
The density of 60% nitric acid is 1.37 g/mL
Mass of 60% nitric acid required = 953.38 mL * 1.37 g/mL
Mass of 60% nitric acid required = 1306 g or 1.306 kg
The density of 20% nitric acid is 1.115 g/mL
Mass of 20% nitric acid required = 2860.18 mL * 1.115 g/mL
Mass of 20% nitric acid required = 3189 g or 3.189 kg
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Compared to a human, what is similar about how blue whales get molecules from food and air?
Answer: Blue whales, like humans, obtain molecules from food and air through a process of digestion and respiration. During digestion, molecules in food are broken down and absorbed into the bloodstream, while during respiration, oxygen molecules in the air are absorbed into the bloodstream. Both processes enable blue whales to obtain the necessary molecules for energy, growth, and development.
The information provided below was obtained from the label of the commercial stock
bottle of concentrated tetraoxosulphate (VI) acid. Calculate the volume of the acid that
is needed to prepare 8dm3
of 0.5moldm-3
solution of the compound from the stock.
Specific gravity of H2SO4 = 1.84gcm-3
% purity of acid =97%
Molar mass = 98gmol-1
The volume of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is 203 cm3.
What is volume?Volume is the amount of space that an object or substance occupies. It is typically measured in cubic units, such as metres cubed (m³). Volume is an important concept in mathematics, physics, and engineering. Volume plays an important role in everyday life; for example, the volume of water in a swimming pool can be measured to determine how much water needs to be added or subtracted. Volume is also used to measure the amount of a substance, such as oil or gas. The volume of a container can also be used to measure the amount of material contained within it. Volume can also be used to measure the capacity of a container, such as a bucket or a tank. In addition, volume can be used to calculate the mass of an object by measuring its density.
The mass of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is:
M = 8 x 0.5 x 98 = 392 g
The volume of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is:
V = 392 / (1.84 x 0.97) = 203 cm3
Therefore, the volume of acid required to prepare 8dm3 of 0.5moldm-3 solution of the compound is 203 cm3.
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What is the first quantum number of the 3p¹ electron in aluminum,
1s²2s²2p63s²3p¹?
A. n=0
B. n = 1
C. n=3
D. n = 2
Quantum number of the 3p¹ electron in aluminum is n=3.
What is the quantum number?Quantum numbers in quantum physics and chemistry explain the values of conserved quantities in a quantum system's dynamics. Quantum numbers are quantities that can be precisely known at the same time as the system's energy and are related to the eigenvalues of operators that commute with the Hamiltonian and their corresponding eigenspaces. A base state of a quantum system is fully described by the specification of all of its quantum numbers, which can theoretically be measured collectively.
The quantization of numerous interesting observable quantities is a crucial component of quantum physics.
This specifically results in quantum numbers, though they may occasionally reach infinity, that take values in discrete sets of integers or half-integers. This sets quantum mechanics apart from conventional mechanics.
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18-38 Name the following ketones and aldehydes. When possible, give both a common name and an IUPAC name.
(a) CH₃CO(CH₂) ₄CH₃
(b) CH₃(CH₂)₂CO(CH₂)₂CH₃
(c) CH₃(CH₂)CHO₅
(d) PhCOPh
(e) CH₃CH₂CH₂O
(f) CH₃COCH₃
(g) CH₃CH₂CHBrCH₂CH(CH₃)CHO
(h) Ph --- CH = CH ----CHO
(i) CH₃CH= CH---CH = CH --CHO
The IUPAC name of the following organic compounds are,a) hept-2-one b) hept-4-one c) heptanal d) diphenylmethanone e) propan-1-one f) acetone g) 3-bromo-1-hexanal h) 3-phenylprop-2-enal i) 2,4-hexdiene-1-al.
What is a compound?Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.
Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.
They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.
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Combustion of 1.125 of an unknown compound containing carbon, hydrogen, and oxygen resulted in 1.649g of CO2 and 0.675g of H2O. If the molar mass is 180g/mol What is the molecular formula?
CxHyOz + O2 → CO2 + H2O
The molecular formula of the unknown compound, given that it contains carbon, hydrogen, and oxygen is C₆H₁₂O₆
How do I determine the molecular formula?First, we'll begin by obtaining the mass of carbon, hydrogen and oxygen. Details below:
For Carbon
Mass of CO₂ = 1.649 gMolar mass of CO₂ = 44 g/mol Molar of C = 12 g/mol Mass of C =?Mass of C = (12 / 44) × 1.649
Mass of C = 0.45 g
For Hydrogen
Mass of H₂O = 0.675 gMolar mass of H₂O = 18 g/mol Molar of H = 2 × 1 = 2 g/mol Mass of H =?Mass of H = (2 / 18) × 0.675
Mass of H = 0.075 g
For Oxygen
Mass of compound = 1.125 gMass of C = 0.45 gMass of H = 0.075 gMass of O =?Mass of O = (mass of compound) - (mass of C + mass of H)
Mass of O = 1.125 - (0.45 + 0.075)
Mass of O = 0.6 g
Next, we shall determine the empirical formula. details below:
C = 0.45 gH = 0.075 gO = 0.6 gEmpirical formula =?Divide by their molar mass
C = 0.45 / 12 = 0.0375
H = 0.075 / 1 = 0.075
O = 0.6 / 16 = 0.0375
Divide by the smallest
C = 0.0375 / 0.0375 = 1
H = 0.075 / 0.0375 = 2
O = 0.0375 / 0.0375 = 1
Thus, the empirical formula of the compound is CH₂O
Finally, we shall determine the molecular formula. Details below:
Molar mass of compound = 180 g/molEmpirical formula = CH₂OMolecular formula =?Molecular formula = empirical × n = mass number
[CH₂O]n = 180
[12 + (2×1) + 16]n = 180
30n = 180
Divide both sides by 30
n = 180 / 30
n = 6
Molecular formula = [CH₂O]n
Molecular formula = [CH₂O]₆
Molecular formula = C₆H₁₂O₆
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For the reaction C + 2H2 → CH4, how many grams of carbon are required to produce 14 moles of methane, CH4 ?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element Molar Mass
Hydrogen 1
Carbon 12
The amount, in grams, of carbon required to produce 14 moles of methane according to the reaction would be 168.0 grams.
Stoichiometric problemFrom the balanced equation of the reaction, the mole ratio of the carbon that reacts and the methane produced is 1:1. In other words, 1 mole of carbon will produce 1 mole of methane.
Thus, for the production of 14 moles of methane:
1 mole methane = 1 mole carbon
14 moles methane = 14 x 1/1 = 14 moles carbon.
Recall that, mass = mole x molar mass.
The molar weight of carbon is given as 12 g/mol
Mass of 14 moles carbon = 14 x 12 = 168 grams
In other words, for the illustrated reaction, the amount of carbon required to produce 14 moles of methane would be 168.0 grams.
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