To earn an A grade, a student needs to score at least 82.8 , calculated using the inverse normal cumulative distribution function with a mean of 70, a standard deviation of 10, and a 10th percentile of 0.10.
Given that the grades are normally distributed with a mean of 70 and a standard deviation of 10.
We need to find the score which is at the 10th percentile of the distribution.
Using the standard normal distribution table, we can find the z-score that corresponds to the 10th percentile.
From the table, we can see that the z-score is approximately -1.28.
Using the formula for standardizing a normal distribution:
z = (x - μ) / σ
where z is the z-score, x is the raw score, μ is the mean, and σ is the standard deviation.
Substituting the given values, we have:
-1.28 = (x - 70) / 10
Solving for x, we get:
x = (-1.28 * 10) + 70
x = 82.8
Therefore, a student would need to earn a score of approximately 82.8 to receive an A grade.
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A parent donated 36 fruit cups and 24 bananas to fifth grade. The teacher wanted to make field trip snack bags with the donated food and wondered about the ways snacks could be packed. To be fair the teacher wants to make sure that all bags are exactly the same.
A) What is the greatest number of snack bags that the teacher can make, if each bag is identical? How do you know ?
B) What other numbers of snack bags could she make? How do you know?
2) Another parent also donated 24 bananas, so there are 48 bananas total. Now what is the greatest number of snack bags can that can be made?
3) The teacher realized that she miscounted and had only 30 fruit cups. How many snack bags can she make with 48 bananas and fruit cups?
4) What do the different numbers of snack bags that can be made have to do with the number of fruit cups and number of bananas?
true/false. when the population variance is not known (i.e., must be estimated from data), we use a z-statistic instead of a t-statistic for our hypothesis tests.
The given statement " when the population variance is not known (i.e., must be estimated from data), we use a z-statistic instead of a t-statistic for our hypothesis tests. " is false. Because in distribution of sample means, population variance is unknown.
When the population variance is not known and must be estimated from the data, we use a t-statistic instead of a z-statistic for our hypothesis tests.
This is because the distribution of the sample means follows a t-distribution when the population variance is unknown, whereas it follows a standard normal distribution (z-distribution) when the population variance is known.
The t-distribution has fatter tails than the z-distribution to account for the extra uncertainty introduced by estimating the population variance from the sample.
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The Millers have hired an interior designer to decorate their family room. They want to have a 29" by 29" oil painting framed and incorporated in the design plan. If the designer chooses molding that is 4" wide and is priced at $3.65 per inch, how much will the molding cost (before tax)?
Answer: I really don't know i'm just trying to get a quest done sorry
Use implicit differentiation to find an equation of the tangent line to the curve sin(x+y)=8x−8y at the point (π,π)
The equation of the tangent line to the curve sin( x y) = 8x- 8y on the factor( π, π) is y = (7/9) x-( 2π/ 9).
To discover the equation of the tangent line to the curve sin( x y) = 8x- 8y on the point( π, π), we want to apply implicit differentiation to discover the pitch of the tangent line at that point.
We begin through differencing both sides of the equation with reference to xcos( x y)( 1 dy/ dx) = eight- 8dy/ dx
After, we can simplify the expression by isolating the terms beholding dy/ dx on one aspect
cos( x y) cos( x y) dy/ dx = 8- 8dy/ dx
8 cos( x y)) dy/ dx = 8- cos( x y)
dy/ dx = ( 8- cos( x y))( 8 cos( x y))
Now we're suitable to discover the pitch of the tangent line at the factor( π, π) by plugging in x = π and y = π into the expression we simply derived
dy/ dx = ( 8- cos( 2π))( 8 cos( 2π))
dy/ dx = ( 8- 1)/( 8 1)
dy/ dx = 7/ nine
Thus, the pitch of the tangent line to the curve sin( x y) = 8x- 8y at the factor( π, π) is7/9.
To find the equation of the tangent line, we can use the point- slope form of the equation
y- y1 = m( x- x1)
In which m is the pitch we simply set up, and( x1, y1) is the point( π, π). Plugging in the values, we get
y- π = ( 7/ nine)( x- π)
Simplifying, we get
y = ( 7/ nine) x-( 2π/ nine)
Thus, the equation of the tangent line to the curve sin( x y) = 8x- 8y on the factor( π, π) is y = (7/9) x-( 2π/ 9).
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Change the following equation of a line into slope-intercept form.
y + 4 = 2x
Answer:
Step-by-step explanation:
[tex]y=2x-4[/tex] (slope-intercept form is [tex]y=mx+b[/tex] where m=gradient
and b is where line intercepts y-axis)
Zaheer had a set of marbles, he used 2/3 to make a design and he had 14 left. How many did he used to make the design?
Answer: 42
Step-by-step explanation:
1. 1/3=14
2. 14x3=42
Solve using the correct order of
operations.
P
E
MD
AS
15-(4-3) 2= [?]
Enter
Help
Here using the correct order of operations that is PEMDAS, we get the value to be 13.
Define PEMDAS?PEDMAS can be summed up as a mathematical acronym that lists the various arithmetic operations in order of greatest to least practical use.
The letters stand for:
P stands for parentheses.
Exponents are shown as E.
D stands for division.
The letter M stands for multiplication.
A stand for addition.
S stands for subtraction.
Now in the given question,
15 - (4-3)2
First the parentheses
15 - (1)2
Next is exponents.
15 - 2
At last, after subtracting, we get:
13
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Find dz/dt in two ways: by using the Chain Rule, and by first substituting the expressions for x and y to write z as a function of t. Do your answers agree?z= x^2y+xy^2, x = 3t y = t^2
The derivative of the function z= x^2y+xy^2, x = 3t y = t^2 using the chain rule is given by dz/dt = 36t^3 + 15t^4.
Expressions are equals to,
z= x^2y+xy^2
x = 3t
y = t^2
Using the chain rule calculate dz/dt,
which states that if z is a function of x and y,
And x and y are both functions of t, then,
dz/dt = (dz/dx)(dx/dt) + (dz/dy)(dy/dt)
Using these expressions, calculate the value of dz/dt using the chain rule,
z= x^2y+xy^2
This implies,
dz/dx = 2xy + y^2
dz/dy = x^2 + 2xy
x = 3t
⇒ dx/dt = 3
y = t^2
⇒ dy/dt = 2t
Substituting these values into the chain rule formula, we get,
dz/dt = (2xy + y^2)(3) + (x^2 + 2xy)(2t)
= [2(3t)(t^2 ) + (t^2)^2 ]3 + [(3t)^2 + 2(3t)(t^2)](2t )
= [ 6t^3 + t^4 ]3 + [ 9t^2 + 6t^3 ]2t
= 18t^3 + 3t^4 + 18t^3 + 12t^4
= 36t^3 + 15t^4
Substituting the given expressions for x and y into z, we get,
z = (3t)^2(t^2) + (3t)(t^2)^2
= 9t^4 + 3t^5
here also,
dz/dt = 36t^3 + 15t^4
Therefore, the value of the function using the chain rule dz/dt is equals to 36t^3 + 15t^4.
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Conduct a survey with a minimum of 20 people. Complete the designed questionnaire in 1.2. Remind participants why you are doing survey and that their information will be kept confidential. Submit 20 original completed questionnaires.
Some of the tips which is used to conduct a survey are:
Determine the purpose of the survey and define the population of interest.Design the questionnaire and ensure that the questions are clear and concise.Select a sample from the population and distribute the questionnaire to the participants.Remind participants why you are conducting the survey and assure them that their responses will be kept confidential.What is the need to conduct a survey (questionnaire)?Conducting a survey is an important tool for gathering information from a large and diverse group of people. Its allows allow researchers to obtain data from a representative sample of the population, which can then be used to make informed decisions, identify trends, and measure changes over time.
Also important, its can provide insight into people's attitudes, beliefs, and behaviors, which can be valuable in developing marketing strategies, designing programs and policies, and making important decisions.
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I will mark you brainiest!
A concave polygon can never be classified as a regular polygon.
A) True
B) False
Answer:
False.
Step-by-step explanation:
A concave polygon can never be a regular polygon as it can never be equiangular. Each side of a regular polygon must be the same length, and all interior angles must also be equal.
Parts A-D. What is the value of the sample mean as a percent? What is its interpretation? Compute the sample variance and sample standard deviation as a percent as measures of rotelle for the quarterly return for this stock.
The sample mean is 2.1, the sample variance is 212.5% and the standard deviation is 14.57%
What is the sample mean?a. The sample mean can be computed as the average of the quarterly percent total returns:
[tex](11.2 - 20.5 + 13.2 + 12.6 + 9.5 - 5.8 - 17.7 + 14.3) / 8 = 2.1[/tex]
So the sample mean is 2.1%, which can be interpreted as the average quarterly percent total return for the stock over the sample period.
b. The sample variance can be computed using the formula:
[tex]s^2 = sum((x - mean)^2) / (n - 1)[/tex]
where x is each quarterly percent total return, mean is the sample mean, and n is the sample size. Plugging in the values, we get:
[tex]s^2 = (11.2 - 2.1)^2 + (-20.5 - 2.1)^2 + (13.2 - 2.1)^2 + (12.6 - 2.1)^2 + (9.5 - 2.1)^2 + (-5.8 - 2.1)^2 + (-17.7 - 2.1)^2 + (14.3 - 2.1)^2 / (8 - 1) = 212.15[/tex]
So the sample variance is 212.15%. The sample standard deviation can be computed as the square root of the sample variance:
[tex]s = \sqrt(s^2) = \sqrt(212.15) = 14.57[/tex]
So the sample standard deviation is 14.57%.
c. To construct a 95% confidence interval for the population variance, we can use the chi-square distribution with degrees of freedom n - 1 = 7. The upper and lower bounds of the confidence interval can be found using the chi-square distribution table or calculator, as follows:
upper bound = (n - 1) * s^2 / chi-square(0.025, n - 1) = 306.05
lower bound = (n - 1) * s^2 / chi-square(0.975, n - 1) = 91.91
So the 95% confidence interval for the population variance is (91.91, 306.05).
d. To construct a 95% confidence interval for the standard deviation (as percent), we can use the formula:
lower bound = s * √((n - 1) / chi-square(0.975, n - 1))
upper bound = s * √((n - 1) / chi-square(0.025, n - 1))
Plugging in the values, we get:
lower bound = 6.4685%
upper bound = 20.1422%
So the 95% confidence interval for the standard deviation (as percent) is (6.4685%, 20.1422%).
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Prove that the diagonals of rectangle are equal vectorically in easy way
Answer: Imagine a rectangle with its centre (point of intersection of diagonals) situated at the origin of the XY plane and it's each of the sides being aligned with the co-ordinate axis.
Find the value of X using the picture below.
Answer:
x = 7
Step-by-step explanation:
The two angles are equal so the opposite sides are equal.
5x-2 =33
Add two to each side.
5x-2+2 = 33+2
5x=35
Divide by 5
5x/5 =35/5
x = 7
A weight is attached to a spring that is oscillating up and down. It takes 2 seconds for the spring to complete one cycle, and the distance from the highest to the lowest point is 5 in. What equation models the position of the weight at time t seconds?
The equation that models the position of the weight at time t seconds is y(t) = 2.5 sin (πt) + 2.5
The equation that models the position of the weight at time t seconds is
y(t) = 2.5 sin (πt) + 2.5
The position of the weight at time t seconds can be modeled by a sinusoidal function of the form
y(t) = A sin (ωt + φ) + C
where
A is the amplitude of the oscillation (half the distance between the highest and lowest points), which is 2.5 in.
ω is the angular frequency of the oscillation, which is 2π divided by the period (the time for one complete cycle), which is 2 seconds. So, ω = 2π/2 = π radians/second.
φ is the phase angle, which depends on the initial position of the weight. We can assume that the weight starts at the highest point (the crest), so φ = 0.
C is the vertical shift, which is the midpoint of the oscillation (half the distance between the highest and lowest points added to the starting point). So, C = 2.5 + 0 = 2.5 in.
Putting it all together, we get
y(t) = 2.5 sin (πt) + 2.5
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Suppose Set A contains 98 elements and Set B contains 93 elements. If Sets A and B have 35 elements in common, what is the total number of elements in either Set A or Set B.
The total number of elements in either Set A or Set B is 156.
How are sets and subsets different from one another?A set is a collection of unique items, but a subset is a set that contains only components that belong to another set, termed the superset. In other words, set A is a subset of set B if all of its items are also found in set B.
Given that, Set A contains 98 elements and Set B contains 93 elements.
Total number of elements in either Set A or Set B = number of elements in Set A + number of elements in Set B - number of common elements
Total number of elements in either Set A or Set B = 98 + 93 - 35
Total number of elements in either Set A or Set B = 156
Hence, the total number of elements in either Set A or Set B is 156.
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A cube of sugar is 2cm wide. Calculate the number of cube in a box 720cm³
Answer:
V=lwh
=2×2×2=8
720÷8=90
90 cubes
Increase £16470.45 by 3.5%
Give your answer rounded to 2 DP
Step-by-step explanation:
"increase" means to take the original 100% and put an additional 3.5% of these 100% on top of it.
so, we have to calculate
100% + 3.5% of £16470.45
100% of £16470.45 = £16470.45 × 100/100
3.5% of £16470.45 = £16470.45 × 3.5/100
the sum is therefore
£16470.45 × (100/100 + 3.5/100) =
= £16470.45 × (1 + 0.035) = £16470.45 × 1.035 =
= £17,046.91575 ≈ £17,046.92
What was your recommended intake of carbohydrates (grams), and how far were you from it? Show the mathActual Intake Recommended Intake Percentage159.00 115-166 100%
The actual intake of carbohydrates is 138% as compare to recommended intake.
Recommended intake of carbohydrates or any other nutrient are,
Based on the information provided,
Consumed 159 grams of carbohydrates,
Recommended intake is between 115 and 166 grams.
Calculate the percentage of actual intake compared to the recommended intake, use the following formula,
Percentage = (Actual Intake / Recommended Intake) x 100%
Substituting the values in the formula we have,
⇒Percentage = (159 / 115) x 100%
⇒Percentage ≈ 138.3%
Therefore, the actual intake of carbohydrates is about 138% of the recommended intake, indicating that consumption of more carbohydrates than recommended.
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Se depositan $ 8.000 en un banco que reconoce una tasa de interés del 36% anual, capitalizable mensualmente. ¿Cuál será el monto acumulado en cuatro años?
Answer:
Se depositan $ 8.000 en un banco que reconoce una tasa de interés del 36% anual, capitalizable mensualmente. ¿Cuál será el monto acumulado en cuatro años?
Step-by-step explanation:
Para resolver este problema, podemos utilizar la fórmula del interés compuesto:
A = P*(1 + r/n)^(n*t)
Donde:
A: el monto acumulado después de t años
P: el capital inicial
r: la tasa de interés anual
n: el número de veces que se capitaliza el interés por año
t: el tiempo en años
En este caso, tenemos:
P = $8.000
r = 36% = 0.36
n = 12 (ya que la tasa de interés se capitaliza mensualmente)
t = 4 años
Sustituyendo estos valores en la fórmula, obtenemos:
A = $8.000*(1 + 0.36/12)^(124)
A = $8.000(1 + 0.03)^48
A = $8.000*(1.03)^48
A = $16.751,83
Por lo tanto, el monto acumulado en cuatro años será de $16.751,83.
Bhujangrao invested Rs. 2,50,590 in shares of F.V. Rs. 10 when M.V. is Rs. 250. [Nov 2020]
Rate of brokerage is 0.2% and GST is 18%, then find:
a. the number of shares purchased,
b. the amount of brokerage paid, and
c. GST paid for the trading
a. The number of shares purchased can be calculated as:
Number of Shares = (Investment Amount / Face Value)
= 25,059/ 10 = 2,505.9 = 2,506 (to the nearest whole number)
b. The amount of brokerage paid can be calculated as:
Brokerage = (Investment Amount x Brokerage Rate)
= 2,50,590 x 0.002 = Rs. 501.18
c. The GST paid for the trading can be calculated as:
GST = (Brokerage Amount x GST Rate)
= 501.18 x 0.18 = Rs. 90.22
In the New York State Numbers Lottery, you pay $1 and pick a number from 000 to 999. If your number comes up, you win $750, which is a profit of $749. If you lose, you lose $1. Your probability of winning is 0.001.
The expected value of playing this game is -$0.251. This means that, on average, you can expect to lose 25.1 cents every time you play this game.
What is outcome?The term "outcome" generally refers to the result or effect of an action, process, or event. It refers to what happens as a consequence of a particular decision, activity, or circumstance.
According to question:To calculate the expected value, we multiply the possible outcomes by their probabilities and then sum them up.
Let's start with the possible outcomes:
If you win, you make a profit of $749, so the outcome is $749.
If you lose, you lose $1, so the outcome is -$1.
The probabilities are:
Probability of winning is 0.001.
Now we can calculate the expected value:
Expected value = (0.001 * $749) + (0.999 * -$1)
Expected value = $0.748 - $0.999
Expected value = -$0.251
Therefore, the expected value of playing this game is -$0.251. This means that, on average, you can expect to lose 25.1 cents every time you play this game.
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Colin buys gas for her car at $4 a gallon. Write an equation using two variables to show the relationship between the number of gallons of gas, g, and the total amount of amount she spends, s.
Answer:
s = 4g ..........................................................
PLEASE HELP ME YOU WILL BE MARKED BRAINLIEST!!!1
The experimental probability of winning the contest based on the data of all 3 games is 0.432.
What is experimental probability ?
Experimental probability is a measure of the likelihood of an event occurring based on the results of an experiment or observation. It is determined by dividing the number of times the event occurred by the total number of trials or observations. The more trials or observations conducted, the more accurate the experimental probability will be. Experimental probability is often used in situations where the probability of an event cannot be determined theoretically or where the theoretical probability is difficult to calculate. It is also commonly used in scientific experiments, market research, and other fields where the results of an experiment or observation can be used to make predictions or inform decisions.
Finding the experimental probability of winning the contest :
In this case, the event is winning the contest by choosing a marble from a bag, and the trials are the three games played by Hal.
Total number of players in all three games = 123 + 155 + 172 = 450
Total number of winners in all three games = 52 + 63 + 65 = 180
Experimental probability of winning the contest = Number of winners / Total number of players = 180/450 = 0.432
Therefore, the experimental probability of winning the contest based on the data of all 3 games is 0.432.
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A bucket contains three slips of paper. One of the following colors is written on each slip of paper: Red, Blue, and Yellow.
List 1 List 2 List 3 List 4
Red Red, Blue Red, Red Red, Red, Red
Blue Red, Yellow Red, Blue Red, Blue, Yellow
Yellow Blue, Red Red, Yellow Red, Yellow, Blue
Red Blue, Yellow Blue, Blue Blue, Blue, Blue
Blue Yellow, Red Blue, Red Blue, Red, Yellow
Yellow Yellow, Blue Blue, Yellow Blue, Yellow, Red
Red Red Yellow, Yellow Yellow, Yellow, Yellow
Blue Blue Yellow, Red Yellow, Red, Blue
Yellow Yellow Yellow, Blue Yellow, Blue, Red
Which list gives the sample space for pulling two slips of paper out of the bucket with replacement?
List 1
List 2
List 3
List 4
The list that gives the sample space for pulling two slips of paper out of the bucket with replacement is List 4.
What is probability?Probability is a branch of mathematics that deals with the study of randomness and uncertainty in events. It is the measure of the likelihood or chance that an event will occur. Probability is expressed as a number between 0 and 1, where 0 indicates that the event will not occur and 1 indicates that the event will occur with certainty.
According to the given information:The sample space for pulling two slips of paper out of the bucket with replacement means that after drawing the first slip of paper, it is returned to the bucket before drawing the second slip. This means that each draw is independent of the previous draw, and the possible outcomes of each draw remain the same for all subsequent draws.
The possible outcomes for each draw are {Red, Blue, Yellow}, and there are three possible outcomes for each draw.
Since we are drawing with replacement, each draw has the same possible outcomes and the same number of outcomes. So, the total number of possible outcomes for two draws is simply the number of outcomes for a single draw raised to the power of 2:
[tex]3^2 = 9[/tex]
Therefore, the list that gives the sample space for pulling two slips of paper out of the bucket with replacement is List 4.
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when comparing the distribution of the population of individual scores to the distribution of means, the distribution of means will always have
The population distribution of scores has a similar average as the distribution of means.
In a sample distribution of means, the distribution will roughly resemble a normal distribution, the sampling distribution's mean will be equal to the population's mean, and the sampling distribution's standard deviation is based on the Central Limit Theorem.
The central limit theorem (CLT) of probability theory states that the distribution of a sample variable tends towards a normal distribution (i.e., a "bell curve") as the sample size increases, under the premise that all samples are of equal size and regardless of the population's actual distribution shape.
In other terms, the central limit theorem (CLT) is a statistical presumption that the mean of all sampled variables from the same population will be substantially equal to the mean of the entire population, given a large enough sample size from a population with little volatility. These samples likewise resemble a normal distribution in accordance with the law of large numbers, with their variances nearly matching the variance of the population as the sample size rises.
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the actual question is :
When comparing the size of the standard error of the mean with the size of the standard deviation of the underlying distribution of individual scores:
a. the standard error of the mean is always larger
b. the standard error of the mean is always smaller
c. the standard error of the mean is sometimes larger and sometimes smaller, depending on the sample size
d. none of these
Evaluate the logarithmic expression without using a calculator. Answer exactly. log 2 ( 1/16 ) + 4 =
[tex]\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ \stackrel{ \textit{we'll use this one} }{log_a a^x = x}\qquad \qquad a^{log_a (x)}=x \end{array} \\\\[-0.35em] ~\dotfill\\\\ \log_2\left( \cfrac{1}{16} \right)+4\implies \log_2\left( \cfrac{1}{2^4} \right)+4\implies \log_2(2^{-4})+4\implies -4+4\implies \text{\LARGE 0}[/tex]
[tex]\rule{34em}{0.25pt}\\\\ \textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b\qquad\qquad \\\\[-0.35em] ~\dotfill\\\\ \log_2\left( \cfrac{1}{16} \right)=y\implies 2^y=\cfrac{1}{16}\implies 2^y=2^{-4}\implies y=-4[/tex]
x P(x)
0 0.1
1 0.05
2 0.1
3 0.75
Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places
Answer: To find the standard deviation of a probability distribution, we need to first calculate the mean or expected value of the distribution, which is given by:
E(X) = Σ [xi * P(xi)]
where xi is the ith outcome and P(xi) is its probability.
So, for the given distribution:
E(X) = (0 * 0.1) + (1 * 0.05) + (2 * 0.1) + (3 * 0.75) = 2.4
Next, we need to calculate the variance of the distribution, which is given by:
Var(X) = Σ [(xi - E(X))^2 * P(xi)]
So, for the given distribution:
Var(X) = (0 - 2.4)^2 * 0.1 + (1 - 2.4)^2 * 0.05 + (2 - 2.4)^2 * 0.1 + (3 - 2.4)^2 * 0.75 = 0.69
Finally, the standard deviation of the distribution is the square root of the variance:
SD(X) = sqrt(Var(X)) = sqrt(0.69) ≈ 0.83
Therefore, the standard deviation of this probability distribution is approximately 0.83, rounded to 2 decimal places.
Step-by-step explanation:
I don’t understand please help me with this
Answer:
Greg bought a pack of X jumbo stickers during the back - to - school sale at Crafty's craft store. He ( uses 4 ( -4 ), ( you didn't give options ). There were 8 stickers left in the pack.
Hope this helps!
Step-by-step explanation:
Students at a virtual school are allowed to sign up for one math class each year. The numbers of students signing up for various math classes for the next school year are given in the following table:
Grade Geometry Algebra I Pre-Calculus AP Statistics Total
A student calculated the joint relative trequency of 10th grade students in geometry as being 71.4%. What did the student actually calculate and what is the correct answer?
A) The student calculated the conditional relative frequency for students who are in 10th grade, given that they are enrolled in Geometry. The correct value of the joint relative frequency of 10th grade students in geometry is 20.7%.
B) The student calculated the conditional relative frequenc for students who are in 10th grade, given that they are enrolled in Geometry. The correct value of the joint relative frequency of 10th grade students in geometry is 29%.
C) The student calculated the marginal relative frequency for 10th grade students in geometry. The correct value of the joint relative trequency of 10th grade students in geometry is 20.7%.
D) The student calculated the marginal relative frequency for 10th grade students in geometry. The correct value of the joint relative frequency of 10th grade students in geometry is 29%
Option C) The student calculated the marginal relative frequency for 10th grade students in geometry. The correct value of the joint relative frequency of 10th grade students in geometry is 20.7%.
How to calculate a relative frequency?Relative frequency is a measure of the proportion or percentage of times an event occurs in a given sample. It is calculated by dividing the frequency of an event by the total number of events in the sample. The formula for relative frequency is given as follows:
Relative frequency = Frequency of an event / Total number of events in the sample
For the joint relative frequency of 10th grade students in geometry, the parameters are given as follows:
Frequency of 10th grade students in geometry: 20.7%.Total number of events in the sample: 100% of students.Hence the joint relative frequency is obtained as follows:
20.7/100 x 100%= 20.7%.
Hence option C is correct.
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2(x-6)²
could you please explain this to me, thanks!
Answer:
expand the square
2(x-6) (x-6)
2(x(x-6)-6(x-6)
2(x²-6x-6(x-6)
2(x²-6x-6x+36)
2(x²-12x+36)
2x²-24x+72
Step-by-step explanation:
hope this helps