An investigation into the fair valuation of jewelry of two Pawn Shops used a random sample of 32 pieces of expensive jewelry selected from a very large jewelry collection of a wealthy woman. Each of the 32 pieces of jewelry was taken, one at a time, by different people into to two different pawn shops for assessment. The goal was to estimate the mean difference in assessed value.

Answer:

how are you in high school and cant solve this, its -4

Step-by-step explanation:

the length of the other leg is 7m and the length of the hypotenuse is 7√2 m.

In the right-angled triangle, the square of the hypotenuse side is equals to the sum of the squares of the other two sides, according to Pythagoras's Theorem. This triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Because to its position opposite the 90° angle, the hypotenuse in this case is the longest side.

The definition yields the following as the Pythagoras Theorem formula:

Hypotenuse² = Perpendicular² + Base²

c² = a² + b²

Length of one leg=7m

Angles of triangle are 45°,45° and 90°

According to Pythagoras theorem,

x²=7²+7²

x=7√2

the length of the other leg is 7m and the length of the hypotenuse is 7√2 m.

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Answer: y+y=7

Step-by-step explanation:

7 is as big as 2 y's therefore y+y would be equal to 7

So the answer is 1.3 after rounding to 10.

Answer:

D. -1/8

Step-by-step explanation:

Look at the coordinates on the graph

(-4,8)

(-2,1)

(0,0)

(2,-1)

(4,-8)

These will correspond to

y = kx^3

=> k = y/x^3

When you substitute the coordinates, you find k = -1/8

y = -1/8x^3

Let X and Y be two matrices in A. We can write X = ((x,0),(0,y)) and Y = ((z,0),(0,w)). If we add X and Y, we get((x+z,0),(0,y+w)). The sum is in A if and only if x+z+y+w=5.

Subset of M2x2:A subset of M2x2 is a set that contains some elements of M2x2.

A subset of M2x2 can be considered as a subspace if it meets the following conditions:

To determine if A is a subspace of M2x2, we need to verify that A meets the following conditions:

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(a) The differential equation that is satisfied by y is:

[tex]\frac{dy}{dt} = ky(1-y)[/tex]

(b) To solve the differential equation, we separate the variables and integrate both sides:

[tex]\frac{dy}{y*(1-y)} = k*dt[/tex]

Integrating both sides, we get:

[tex]\frac{lnly}{1-y} = k*t +c1[/tex]

where C1 is an arbitrary constant of integration.

We can rewrite the equation in terms of y:

[tex]\frac{y}{1-y} = e^{(k*t+c1)}[/tex]

Multiplying both sides by (1-y), we get:

[tex]{y} = e^{(k*t+c1)} *(1-y)[/tex]

[tex]y= \frac{C}{(1+(c-1)e^{-kt} }[/tex]

where C = y(0) is the initial fraction of the population who have heard the rumor.

(c) In this case, the initial fraction of the population who have heard the rumor is y(0) = [tex]\frac{100}{1300}[/tex] = 0.077. At noon, half the town has heard the rumor, so y(4) = 0.5.

Substituting these values into the equation from part (b), we get:

[tex]0.5= \frac{0.077}{1+(0.777-1) e^{-k4} }[/tex]

Solving for k, we get:

[tex]k= ln(\frac{12.857}{4} )[/tex]

Substituting this value of k into the equation from part (b), and setting y = 0.9 (since we want to find the time at which 90% of the population has heard the rumor), we get:

[tex]0.9= \frac{0.077}{1+(0.777-1) e^{-ln(12.857}*\frac{t}{4} }[/tex])

Solving for t, we get:

t = 8.7 hours after the beginning (rounded to one decimal place)

A differential equation is a mathematical equation that relates a function to its derivatives. It is a powerful tool used in many fields of science and engineering to describe how physical systems change over time. The equation typically includes the independent variable (such as time) and one or more derivatives of the dependent variable (such as position, velocity, or temperature).

Differential equations can be classified based on their order, which refers to the highest derivative present in the equation, and their linearity, which determines whether the equation is a linear combination of the dependent variable and its derivatives. Solving a differential equation involves finding a function that satisfies the equation. This can be done analytically or numerically, depending on the complexity of the equation and the available tools.

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In mathematical induction, prove that n lines separate the plane into (n^2 + n + 2)/2 regions if no two of these lines are parallel and no three pass through a common point.

Mathematical induction is a mathematical proof method that is used to demonstrate a statement or formula for all values of n, where n is a positive integer. If we use induction, we can show that the formula is true for n = 1, and we can also show that if the formula is true for n = k, then it is also true for n = k + 1.

Proof for n lines separating the plane into (n^2 + n + 2)/2 regions is given below:

Base Case: The theorem is true for n = 1. When we draw one line in the plane, we see that it splits the plane into two regions. Hence the formula is true for n = 1.

Induction Hypothesis: We believe that the formula is true for k lines. That is, k lines split the plane into (k^2 + k + 2)/2 regions.

Induction Step: We want to demonstrate that the formula is also true for k + 1 lines. We first take an arbitrary line from these k + 1 lines, which we call l. We notice that this line splits the plane into two regions.

Now, for the remaining k lines, we make an induction argument. We are sure that the formula is true for k lines. Thus, the k lines split the plane into (k^2 + k + 2)/2 regions. We know that these k lines intersect the line l at k points. Thus, by adding line l, we create k + 1 regions on the plane between these lines.

We now consider the line l itself. It can't cross any of the other k lines, or it would not meet our requirements. Therefore, it crosses each of the k existing lines, generating k + 1 areas. Thus, with the inclusion of line l, the number of regions on the plane is (k^2 + k + 2)/2 + k + 1 = (k^2 + 3k + 4)/2.

The formula for k + 1 is (k + 1)^2 + (k + 1) + 2 = k^2 + 3k + 4, and it is thus identical to the formula for the number of regions when k lines are drawn on the plane.

Therefore, the statement is true for all positive integers n.

Therefore, we have proved that n lines separate the plane into (n^2 + n + 2)/2 regions if no two of these lines are parallel and no three pass through a common point, by using mathematical induction.

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After about 73.08 years, the population of each community will be approximately equal to 18,408 people.

The first equation is y = 10,000(1.01)ˣ, and the second equation is y = 8,000(1.02)ˣ. These equations are exponential functions, which means that the population is growing or increasing over time at a certain rate.

To solve this problem, we need to find the point at which the population of both communities is approximately equal. In other words, we need to find the values of x and y that satisfy both equations at the same time. This is known as finding the point of intersection of the two equations.

We can do this by setting the two equations equal to each other and solving for x. This gives us:

10,000(1.01)ˣ = 8,000(1.02)ˣ

We can simplify this equation by dividing both sides by 8,000 and taking the natural logarithm of both sides. This gives us:

ln(1.01)/ln(1.02) ≈ 73.08

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Complete Question:

City officials use the given system of equations to estimate the population of two neighboring communities, where y is the population and x is

the time, in years.

y = 10,000(1.01)ˣ

y = 8,000(1.02)ˣ

Use this system to complete the statement.

After about _________ years, the population of each community will be approximately _________ people.

Using the given percentages we can see that 150 people likes grapes.

To find this, we need to take the product between the percentage of people that likes grapes (in decimal form) and the total number of people surveyed.

To get the decimal form of the percentage we just need to divide it by 100%, we will get:

20%/100% = 0.2

And there were 750 people surveyed, then the total number of people that likes grapes is:

N = 750*0.2 = 150.

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Answer: it is b

Step-by-step explanation:

it is b bec if you do that by 10x9 90=a a x x =1 90/s

Answer:

C

Step-by-step explanation:

To determine the number of distinct triangles that can be made with the given measurements, we can use the Law of Sines, which states:

a/sin(A) = b/sin(B) = c/sin(C)

where a, b, c are the lengths of the sides opposite to the angles A, B, and C, respectively.

Using this formula, we can solve for sin(B) as follows:

sin(B) = b*sin(A)/a

sin(B) = 8*sin(42°)/3

sin(B) ≈ 0.896

Since sin(B) is a positive value, we know that there are two possible angles B that satisfy this equation: one acute angle and one obtuse angle. To find the acute angle B, we take the inverse sine of sin(B):

B = sin^(-1)(0.896)

B ≈ 63.8°

To find the obtuse angle, we subtract the acute angle from 180°:

B' = 180° - 63.8°

B' ≈ 116.2°

Now, we can use the fact that the sum of the angles in a triangle is 180° to find the possible values for angle C. For the acute triangle, we have:

C = 180° - A - B

C = 180° - 42° - 63.8°

C ≈ 74.2°

For the obtuse triangle, we have:

C' = 180° - A - B'

C' = 180° - 42° - 116.2°

C' ≈ 21.8°

Therefore, we have found two distinct triangles that can be made with the given measurements: one acute triangle with angles A = 42°, B ≈ 63.8°, and C ≈ 74.2°, and one obtuse triangle with angles A = 42°, B' ≈ 116.2°, and C' ≈ 21.8°. Thus, the answer is C. 2.

Answer:

141.3m^2

Step-by-step explanation:

We have radius = 8

Area of a sector of circle = πr^2(θ/360º)

A = π x 8^2 x (270/360) = 48π

Smaller circle has radius equal to 1/4 of large circle's radius = 8/4 = 2

A = π x 2^2 x (270/360) = 3π

Area of the shape = 48π - 3π = 45π = 45(3.14) = 141.3m^2

If the school has population of 2,462, then approximately 1,784 students at the school wore their school shirt on Friday.

If 19 out of 26 students wore their school shirt on Friday, then the fraction of students who wore their school shirt is:

[tex]\frac{19}{26}[/tex]

We can use this fraction to estimate the number of students who wore their school shirt on Friday. If there are approximately 2,462 students in the school, then the estimated number of students who wore their school shirt on Friday is:

[tex](\frac{19}{26}) * 2,462 = 1,783.69[/tex]

Rounding this to the nearest whole number, we get an estimate of 1,784 students who wore their school shirt on Friday.

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Answer:

The graph is a dotted line from (  0, 12  ) to (  15  , 0 )

The shaded region is above the boundary line. The origin is not in the shaded region.

===================================================

Explanation:

x = number of shirts

y = number of pants

16x = amount made from the shirts only

20y = amount made from the pants only

16x+20y = total amount made, aka revenue

16x+20y > 240

This is because Giselle needs to make more than $240 to be profitable.

------------------

The graph is a dotted line because the "or equal to" is not part of the inequality sign. If Giselle could make $240 and be profitable, then we would use a solid line instead and use "or equal to". But in this case, she must make above $240.

Let's consider the boundary line 16x+20y = 240. Plug in x = 0 to get

16x+20y = 240

16*0+20y = 240

20y = 240

y = 240/20

y = 12

Therefore we can say (0,12) is one point on the dotted boundary line. It is the y intercept.

Use similar steps for y = 0 to find x.

16x+20y = 240

16x+20*0 = 240

16x = 240

x = 240/16

x = 15

The x intercept is (15,0) where the dotted line crosses the x axis.

Therefore, the dotted boundary line goes through (0,12) and (15,0).

------------------

Now to the question: where to shade?

Let's check the origin point (0,0). Meaning we plug in x = 0 and y = 0.

16x+20y > 240

16*0+20*0 > 240

0+0 > 240

0 > 240

Clearly that's false so (0,0) is NOT in the shaded solution region. We shade the opposite region of the origin. We'll shade above the boundary as indicated in the diagram below. I used GeoGebra to make the graph. Desmos is another good option.

Hence, the abbreviated formula is -7 + 0i, or just -7.

The terms in the parentheses can be immediately simplified. So, we can carry out the operations indicated by the brackets in the following order: multiplication, addition, subtraction, division. Note: The brackets should be shortened in the following order: (),, []. Simplify: 14 + (8 - 2 3) for Example 2.

We must combine like terms in order to make the phrase simpler.

First, we can individually merge the real and made-up parts:

The genuine parts add out to -3 - 4 = -7.

i - i = 0 is the imaginary part's total.

Hence, the abbreviated formula is -7 + 0i, or just -7.

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Complete question:

Please simplify the following expression while performing the given operation. (-3+i)+(-4-i)

As we have prove that the triangle has ΔEAB is congruent to ΔFDC.

Next, we can use the fact that AC = DB to prove that ΔEAB and ΔFDC have a pair of congruent sides. Specifically, since AC = DB and AE is parallel to DF, we know that triangles ACD and BDF are congruent by the Side-Angle-Side (SAS) congruence theorem. Therefore, we can conclude that AD = BC and CD = BD.

Now we can use the congruent angles and sides to prove that the remaining sides and angles of ΔEAB and ΔFDC are congruent. Specifically, we know that ∠AEB is congruent to ∠FDC and ∠EAB is congruent to ∠FDC because of the angle congruence we established earlier.

Additionally, we know that AB is congruent to CD and AD is congruent to BC because of the side congruence we established earlier. Finally, we know that AC = DB because this was given in the problem statement.

By using these angle and side congruences, we have shown that ΔEAB and ΔFDC are congruent by the Side-Angle-Side (SAS) congruence theorem.

Therefore, we have proven that ΔEAB is congruent to ΔFDC.

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Complete Question:

Given: ΔAEB and ΔDFC, ABCD, AE || DF, EB || FC, AC = DB

Prove: ΔEAB ≅ ΔFDC

Answer: the answer is $83.82

Step-by-step explanation:

To calculate the total interest paid, we need to first calculate how long it will take to pay off the balance. We can use the formula for the present value of an annuity to find this:

PV = PMT x [(1 - (1 + r/n)^(-nt)) / (r/n)]

Where:

PV = present value (the amount borrowed)

PMT = payment amount

r = annual interest rate

n = number of times interest is compounded per year

t = time in years

In this case, PV = $1,215.49, PMT = $125, r = 19.95%, n = 12 (monthly compounding), and we want to solve for t.

1,215.49 = 125 x [(1 - (1 + 0.1995/12)^(-12t)) / (0.1995/12)]

Simplifying this equation, we get:

12t = 27.9275

t = 2.3273 years

So it will take about 2.33 years to pay off the balance.

Now, we can calculate the total amount paid by multiplying the monthly payment by the number of payments:

Total amount paid = $125 x 28 (2.33 years x 12 months/year) = $3,500

The total interest paid is the difference between the total amount paid and the amount borrowed:

Total interest paid = $3,500 - $1,215.49 = $2,284.51

Finally, we can calculate the average monthly interest paid by dividing the total interest paid by the number of payments:

Average monthly interest paid = $2,284.51 / 28 = $81.59

Rounding this to the nearest cent, we get $81.58, which is closest to $83.82. Therefore, the answer is $83.82.

Answer:

b

Step-by-step explanation:

To calculate the interest paid, we need to find out how many months it will take to pay off the balance and what the total payments will be.

Using the formula:

n = -log(1 - i/p) / log(1 + r)

where:

p = monthly payment ($125)

i = initial balance ($1,215.49)

r = monthly interest rate (19.95% / 12 = 0.016625)

n = number of months to pay off the balance

n = -log(1 - 125/1215.49) / log(1 + 0.016625) = 11.02 (rounded up to 12)

So it will take 12 months to pay off the balance. The total payments will be:

12 x $125 = $1,500

The total interest paid will be:

$1,500 - $1,215.49 = $284.51

Therefore, the answer is closest to option B, $180.83.

$700. If the costs (C) of the outfits is $175, then we can create an equation that looks like this.

C x .25 = $175

To find C, taking the derivative of the equation by.25, and you get...

C = $700

By multiplying the value by the entire value and multiply that number by 100, the percentage may be calculated.

Sample percentages include:

10% is equal to 10/100, or 1/10 of the total.

20% is equal to 20/100, or 1/5 of the total.

30% is equal to 30/100, or 3/10 of the total.

40% is equal to 40/100, or 2/5 of the total.

50% is equal to 50/100, or half of the number.

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The closest estimate for the experimental probability of rolling a 4 on the cube is 0.116.

Probability is a metric used to determine how likely an event is to take place. Often, it is stated as a number between 0 and 1, with 0 denoting an impossibility and 1 denoting a certainty. With a typical six-sided dice, for instance, the likelihood of rolling a 1 is 1/6 or around 0.167.

Several techniques can be used to determine probability, depending on the circumstance. When rolling a fair die, for example, the likelihood of each potential result is equal and may be estimated using the formula:

Amount of favorable outcomes / Total number of potential outcomes is how you calculate an event's probability.

Given that, cube numbered from 1 through 6 is rolled 500 times.

The experimental probability of 4 landing face-up on the cube is:

Experimental probability = Number of times 4 lands face-up / Total number of rolls

Experimental probability = 58 / 500 = 0.116.

Hence, the closest estimate for the experimental probability of rolling a 4 on the cube is 0.116.

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If all other factors are held constant, then the true parameter is farther from the value of the null hypothesis which is an increase in the probability of a Type II error.The correct option is A.

The true parameter is farther from the value of the null hypothesis.

When the true parameter is farther away from the value of the null hypothesis, it increases the probability of a Type II error. This is because the null hypothesis will have a harder time rejecting the true parameter.

The other factors - increasing sample size, decreasing significance level, and decreasing standard error - all result in a decreased probability of a Type II error.

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The error bound for the 95% confidence interval is (1.96 x Standard Deviation/√n), which in this case is (1.96 x 11/√50) = 2.56. This means that the true mean weight of newborn elephant calves lies within +/-2.56 pounds of the interval range.

The 95% confidence interval for the population mean weight of newborn elephants can be calculated using the sample mean of 244 pounds and the sample standard deviation of 11 pounds. The confidence interval is calculated using the following formula:
Confidence Interval = (Mean - (1.96 x Standard Deviation/√n)), (Mean + (1.96 x Standard Deviation/√n))
Where n is the sample size.
Therefore, the 95% confidence interval for the population mean weight of newborn elephants is (231.14, 256.86).
This can also be represented in a graph. The graph would have the x-axis representing the confidence interval, with a range from 231.14 to 256.86, and the y-axis representing the probability, which would be 0.95.

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It will take Eric 2.5 minutes to add 15 gallons of water to the pool and fill it to at least 27 gallons.

To fill the pool with at least 27 gallons of water, Eric needs to add:

27 - 12 = 15 gallons of water

The rate at which the water flows is 6 gallons per minute, so we can set up the equation:

6x = 15

where x is the number of minutes it will take for Eric to add 15 gallons of water to the pool.

Solving for x, we get:

x = 15/6

x = 2.5

This is the inequality that represents the situation because it shows that the amount of time Eric needs to add water to the pool must be greater than or equal to 15/6 minutes (or 2.5 minutes), which is the minimum time required to add 15 gallons of water.

The gallon has been in use since at least the 14th century and has undergone several changes in its size and definition over the centuries.  It is commonly used in the United States, United Kingdom, and other countries that use the imperial system of measurement. One gallon is equal to 3.785 liters, and it is divided into four quarts or eight pints. In the US, a gallon is often used to measure the volume of gasoline, milk, and other liquids.

The word "gallon" has its roots in the Old French word "galon," which meant "measure of liquid." In the US, there are two different types of gallons: the US gallon, which is based on the Winchester gallon used in the late 18th century, and the imperial gallon, which is used in the UK and other Commonwealth countries.

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Answer:

A = 32 ft²

Step-by-step explanation:

the area (A ) of a square is calculated as

A = s² ( s is the side length )

the diagonal divides the square into 2 right triangles

using Pythagoras' identity on the lower right triangle with hypotenuse 8 and sides s , then

s² + s² = 8²

2s² = 64 ( divide both sides by 2 )

s² = 32

Then

A = s² = 32 ft²

The probability of all will fail is the lowest.

The given problem states that a missile guidance system has seven fail-safe components, and the probability of each failing is 0.2. The given variable is binomial. We need to find the following probabilities:

(a) Exactly two will fail.

(b) More than two will fail.

(c) All will fail.

(d) Compare the answers for parts a, b, and c, and explain why these results are reasonable.

(a) Exactly two will fail.

The probability of exactly two will fail is given by;

P(exactly two will fail) = (7C2) × (0.2)2 × (0.8)5
= 21 × 0.04 × 0.32768
= 0.2713

Therefore, the probability of exactly two will fail is 0.2713.

(b) More than two will fail.

The probability of more than two will fail is given by;

P(more than two will fail) = P(X > 2)
= 1 - P(X ≤ 2)
= 1 - (P(X = 0) + P(X = 1) + P(X = 2))
= 1 - [(7C0) × (0.2)0 × (0.8)7 + (7C1) × (0.2)1 × (0.8)6 + (7C2) × (0.2)2 × (0.8)5]
= 1 - (0.8)7 × [1 + 7 × 0.2 + 21 × (0.2)2]
= 1 - 0.2097152 × 3.848
= 0.1967

Therefore, the probability of more than two will fail is 0.1967.

(c) All will fail.

The probability of all will fail is given by;

P(all will fail) = P(X = 7) = (7C7) × (0.2)7 × (0.8)0
= 0.00002

Therefore, the probability of all will fail is 0.00002.

(d) Compare the answers for parts a, b, and c, and explain why these results are reasonable.

The probability of exactly two will fail is the highest probability, followed by the probability of more than two will fail. And, the probability of all will fail is the lowest probability. These results are reasonable since the more the number of components that fail, the less likely it is to happen. Therefore, it is reasonable that the probability of exactly two will fail is higher than the probability of more than two will fail, and the probability of all will fail is the lowest.

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A,C and D

Step-by-step explanation:

Option A,C and D are not polynomials.

Step-by-step explanation:

Polynomial functions are given by

             p(x) = a₀ + a₁x¹+ a₂x²+ ...........+aₙxⁿ

             Where a₀, a₁, a₂, ..., an are constant coefficients and n is non negative integer.

Option A

        Here one exponent of x is -2, so this is not a polynomial function.

Option B

        Here all the exponents are non negative integer, so this is a polynomial.

Option C

        Here one exponent of x is 0.5, so this is not a polynomial function.

Option D

      p(x)= x⁻²+x+1

        Here one exponent of x is -2, so this is not a polynomial function.

Option E

        Here all the exponents are non negative integer, so this is a polynomial.

Option A,C and D are not polynomials.

Answer:

A

D

Step-by-step explanation:

I believe those are correct however im not that good at this soooooo.

Good luck

Answer:

7

Step-by-step explanation:

x  + 3 = 10

x + 3 - 3 = 10 - 3

x = 7

the probability of no defective components being in the batch when one of the two tested components is defective is [tex](0.48 x 0.5) + (0.27 x 0.5) + (0.25 x 0) = 0.384 (38.4%)[/tex]. The probability of one defective component in the batch is [tex](0.48 x 0.5) + (0.27 x 0.5) + (0.25 x 1) = 0.504 (50.4%)[/tex]. Lastly, the probability of two defective components in the batch is [tex](0.48 x 0) + (0.27 x 0) + (0.25 x 1) = 0.112 (11.2%).[/tex]

(a) Neither tested component is defective:
No Defective Components: 0.48 (48%)
One Defective Component: 0.27 (27%)
Two Defective Components: 0.25 (25%)

(b) One of the two tested components is defective:
No Defective Components: 0.384 (38.4%)
One Defective Component: 0.504 (50.4%)
Two Defective Components: 0.112 (11.2%)

To calculate the probabilities of (b), a tree diagram can be drawn with three first-generation branches for the three different types of batches. For the case where one of the two tested components is defective, there are three possible outcomes, none of which can be ruled out before the test is completed.

The probability of none of the two components being defective is the sum of the probabilities of all three possible batches (no defective, one defective, two defective) times the probability that none of the two components are defective given that one of them is defective.

The same calculation holds for the probability of one defective and two defective components.

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Answer:

A. $12.45

Step-by-step explanation:

$20.00 - $7.55 = $12.45

The shaded area should be adjusted to reflect the new producer surplus for Micronesian firms, which will be larger than it was before trade due to higher price they can receive by exporting their timber to world market.

The measure of the size of a two-dimensional surface or shape is area. It is typically measured in square units, such as square meters or square feet, and represents the amount of space that is enclosed by the shape or surface.

To shift the world price line in a way that results in Micronesia exporting timber, we need to assume that the world price of timber is higher than the domestic price in Micronesia before trade. This would create an incentive for Micronesian firms to sell their timber on the world market, where they can receive a higher price.

Shift the world price line upward to a point where it intersects with Micronesia's supply curve.

This will create a new equilibrium point where the quantity of timber supplied by Micronesia equals the quantity demanded by the world market.

To adjust the shaded area to correctly represent producer surplus for Micronesia's firms once the country is open to international trade, we need to consider the changes in producer surplus resulting from the new equilibrium price.

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