Answers
Answer:
neap tide
Explanation:
There are two different types of tides, which are the spring tide and the neap tide.
Neap tides are weak tides which occur when the gravitational forces of the sun and the moon are at right angles to each other with respect to the earth. Since the sun and moon are at right angles, it causes a difference between the low and high tide.
The spring tide are strong tides which occur when the moon, sun and earth are in straight line. The spring tide occur during full moon and new moon.
Answer:
Neap Tides
The result is a neap tide. The same effect happens during third quarter. These occur during first and last quarter moons. The gravitational pull is not as strong.
Explanation:
the first answer is correct
Related Questions
117 milligrams (mg) of purified product was isolated from a chemical reaction. This experimental yield of product represents a 89.0% yield for the reaction. Calculate the theoretical yield, in milligrams (mg), for this reaction. Enter your answer as digits only, no units, using the proper number of significant figures.
Answers
Answer:
131 mg
Explanation:
Percent yield = 89%
Actual yield = 117 mg
Percent yield is given by
[tex]\text{Percent yield}=\dfrac{\text{Actual yield}}{\text{Theoretical yield}}\times 100\\\Rightarrow 89=\dfrac{117}{\text{Theoretical yield}}\times 100\\\Rightarrow \text{Theoretical yield}=\dfrac{117}{89}\times 100\\\Rightarrow \text{Theoretical yield}=131.46\approx 131\ \text{mg}[/tex]
The theoretical yield, for this reaction is 131 mg.
can u bang a teacher in class
Answers
Answer:
Explanation:
Feel free to bang me- your teacher
Answer:
depends lol
Explanation:
pls help me i really need help
Answers
Answer:
13. t = 1183 min and 0.50 M.
14. [tex]t_{1/2}=2.67x10^{-8}hr[/tex]
Explanation:
Hello!
13. In this case, according to the units, we infer this is a second-order reaction which has the following integrated rate law:
[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +kt[/tex]
Which can be solved for the time as shown below:
[tex]t=\frac{ \frac{1}{[A]}-\frac{1}{[A]_0}}{k}[/tex]
Thus, we plug in the given concentrations and rate constant to obtain:
[tex]t=\frac{ \frac{1}{0.250M}-\frac{1}{0.850M}}{0.002387M^{-1}min^{-1}}\\\\t= 1183min[/tex]
For the second part, we proceed by using the same rate constant and the new initial concentration as follows:
[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +kt\\\\\frac{1}{[A]} =\frac{1}{0.750M} +0.680M^{-1}min^{-1}*0.996min\\\\\frac{1}{[A]} =1.99,M[/tex]
[tex][A]=0.50M[/tex]
14. In this case, according to the units of the rate constant, we infer this is a zeroth-order reaction, therefore we compute the half-life has shown below:
[tex]t_{1/2}=\frac{[A]_0}{2k}[/tex]
Thus, we plug in to obtain:
[tex]t_{1/2}=\frac{2.696x10^{-6}M}{2*50.5M*hr^{-1}}[/tex]
[tex]t_{1/2}=2.67x10^{-8}hr[/tex]
Best regards!
How many grams of sulfur must be burned to give 100.0 g of So2
Answers
Answer:
50 g of S are needed
Explanation:
To star this, we begin from the reaction:
S(s) + O₂ (g) → SO₂ (g)
If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.
According to stoichiometry, we can determine the moles of sulfur dioxide produced.
100 g. 1mol / 64.06g = 1.56 moles
This 1.56 moles were orginated by the same amount of S, according to stoichiometry.
Let's convert the moles to mass
1.56 mol . 32.06g / mol = 50 g
How many grams of a nonelectrolyte (78.2 g/mol) must be dissolved in 1 kg of solvent to obtain a freezing point of solution of 1.57ºC? The freezing point of the pure solvent is 4.72ºC and the freezing point depression constant of the solvent is 3.89 ºC/m
Answers
Answer Tu mama por si acaso
Explanation:
jkand
A student measures a boiling water bath with two different thermometers. The digital thermometer records the temperature as 100.2°C and has an uncertainty of 0.1°C. The analog thermometer records the temperature as 99.0°C and has an uncertainty of 0.5°C. What is the percent uncertainty of each thermometer? And what is the percent error given that water boils at 100.0°C?
Answers
Answer:
Explanation:
Measurement made = 100.2 °C
uncertainty = 0.1°C
percent uncertainty = .1 x 100 / 100.2
= .099 %
2 nd thermometer :
Measurement made = 99.0 °C
uncertainty = 0.5°C
percent uncertainty = .5 x 100 / 99
= .505 %
Percent error :
1 st thermometer
Error = 100.2 - 100 = .2 °C
measurement = 100.2
percent error = .2 x 100 / 100.2
= .1996 %
2 nd thermometer
Error = 100.00 - 99 = 1.00 °C
measurement = 99
percent error = 1 x 100 / 99
= 1.01 %
The percent error of digital thermometer is 0.1996 %. The percent error of analog thermometer is 1.01 %.
Percent uncertainty is the measure of degree of error region with the uncertainty in the measurement.
The percentage error is the difference in the measurement of the values with actual value.
Computation for percent uncertainty and percent errorThe percent uncertainty (%U) is calculated by:
[tex]\% U=\rm \dfrac{Uncertainty}{Measurement}\;\times\;100[/tex]
The percent error (%E) is calculated by:
[tex]\%E=\rm \dfrac{error\;value-actual\;value}{error\;value}\;\times\;100[/tex]
The percent uncertainty and error for digital thermometer is given as:The Recorded temperature = 100.2 degree Celsius
The actual temperature = 100 degrees Celsius
The uncertainty in the readings is 0.1 degree Celsius
The percent uncertainty is given by:
[tex]\%U=\dfrac{0.1}{100.2}\;\times\;100\\\\ \%U=0.099\;\%[/tex]
The percent uncertainty of digital thermometer is 0.099 %.
The percent error is given by:
[tex]\% E=\dfrac{100.2-100}{100.2}\;\times\;100 \\\\\% E=\dfrac{0.2}{100.2}\;\times\;100\\\\ \% E=0.1996\;\%[/tex]
The percent error of digital thermometer is 0.1996 %.
The percent uncertainty and error for analog thermometer is given as:The Recorded temperature = 99 degree Celsius
The actual temperature = 100 degrees Celsius
The uncertainty in the readings is 0.5 degree Celsius
The percent uncertainty is given by:
[tex]\%U=\dfrac{0.5}{99}\;\times\;100\\\\ \%U=0.505\;\%[/tex]
The percent uncertainty of analog thermometer is 0.505%.
The percent error is given by:
[tex]\% E=\dfrac{100-99}{99}\;\times\;100 \\\\\% E=\dfrac{1}{99}\;\times\;100\\\\ \% E=1.01\;\%[/tex]
The percent error of analog thermometer is 1.01 %.
Learn more about percent error, here:
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The lattice energy of a salt is 350 kJ/mol and the solvation energies of its ions add up to 320 kJ/mol for the preparation of a 0.50 M solution. In the preparation of this solution would the solution get colder or warmer
Answers
Answer:
It would get colder
Explanation:
The lattice energy is the energy involved in the disruption of interactions between the ions of the salt. In this case, we have: ΔHlat = 350 kJ/mol > 0, so it is an endothermic process (the energy is absorbed).
The solvation energy is the energy involved in forming interactions between water molecules and the ions of the salt. In this case, we have: ΔHsolv = 320 kJ/mol > 0, so it is an endothermic process (the energy is absorbed).
The dissolution process involve both processes: the disruption of ion-ion interactions of the salt and the solvation process. Thus, the enthalphy change (ΔHsol) in the preparation of the solution is calculated as the addition of the lattice energy and solvation energy:
ΔHsol= ΔHlat + ΔHsolv = 350 kJ/mol + 320 kJ/mol = 370 kJ/mol
370 kJ/mol > 0 ⇒ endothermic process
Since the preparation of the solution is an endothermic process, it will absorb energy from the surroundings, so the solution would get colder.
Ethanol, the alcohol in alcoholic beverages, has a density of 0.7893 g/mL. What is the shipping weight of a 5.0-gallon container of pure ethanol if the bottle weighs 1.82 lb and the shipping container and packaging weigh 0.76 lb
Answers
Answer:
16.09 kg
Explanation:
To solve this problem first we convert those 5.0 gallons of ethanol into liters:
5.0 gallons * [tex]\frac{3.78L}{1gallon}[/tex] = 18.9 LNow we calculate the mass of that volume of ethanol, using its density:
We convert 18.9 L ⇒ 18.9 * 1000 = 18900 mL
Mass = Density * VolumeMass = 0.7893 g/mL * 18900 mL = 14917.77 gFinally we convert the masses of the bottle and shipping container and packaging and add them to the mass of ethanol:
1.82 lb * 453.592 = 825.54 g0.76 lb * 453.592 = 344.73 gTotal Mass = 14917.77 g + 825.54 g + 344.73 g = 16088.04 gSo the shipping weight would be 16088.04 g, or 16.09 kg
How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe? Equation Fe2O2(g) + 3CO(g) -> 3CO2(g) + 2Fe(g)
Answers
Answer: 157.3 g CO
Explanation:
Fe2O3 + 3CO —> 3CO2 + 2Fe [1 mol + 3 mol —> 3 mol + 2 mol]
3 mol CO —> 2 mol Fe
3*28g —> 2*56g
amt CO 3*28*209.7/(2*56) = 157.3g
Determine the chemical equation for the reaction between Fe3+ and Cu2+ with NH3
Answers
Answer:
Cu2 + 4 NH3 = Cu (NH3) 42+
so - - >
[Cu (NH3) 6] ^ 2+
Explanation:
How many particles are in 67.9 grams of water (H2O)?
Answers
Answer:
3.769022740695677
Explanation:
Answer:We get 1.81×1024 water molecules... Explanation: We assess the molar quantity of water in the usual way... Number of moles=massmolar mass.
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A chemistry student needs 50.0ml of tetrahydrofuran for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of tetrahydrofuran is . Calculate the mass of tetrahydrofuran the student should weigh out. Be sure your answer has the correct number of significant digits.
Answers
Answer:
44.45 g of tetrahydrofuran.
Explanation:
From the question given above, the following data were obtained:
Volume of tetrahydrofuran = 50 mL
Density of tetrahydrofuran = 0.889 g/mL
Mass of tetrahydrofuran =?
Density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, density is expressed as shown below:
Density = mass / volume
With the above formula, we shall determine the mass of tetrahydrofuran needed. This can be obtained as follow:
Volume of tetrahydrofuran = 50 mL
Density of tetrahydrofuran = 0.889 g/mL
Mass of tetrahydrofuran =?
Density = mass / volume
0.889 = mass / 50
Cross multiply
Mass = 0.889 × 50
Mass of tetrahydrofuran = 44.45 g
Therefore, the student should weigh out 44.45 g of tetrahydrofuran.
Which of the following is considered a complex (Macro)molecule?
Glucose
DNA
Carbon dioxide
Answers
Answer:
it is Glucose hope it helps
Answer:
Glucose and DNA
Explanation:
Complex macromolecules are the combination of more than two molecules which are large and complex. The major types of complex macromolecules consists of 4 types which are carbohydrates, lipids, proteins, and nucleic acids.
Glucose is one of the carbohydrates, while DNA is another form of nuclei acid.
5. Which model shows the progression of the movement of particles from fastest to slowest as thermal energy is removed?
Answers
Answer:
A nivel microscópico y en el marco de la Teoría cinética, es el total de la energía cinética media presente como el resultado de los movimientos aleatorios de átomos y moléculas o agitación térmica, que desaparecen en el acto.
Explanation:
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What is the definition of lava?
Answers
Answer:
Lava, magma (molten rock) emerging as a liquid onto Earth's surface. The term lava is also used for the solidified rock formed by the cooling of a molten lava flow.
Explanation:
How do you balance this equation?
Answers
Answer:
HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O
The coefficients are: 1, 1, 1, 1, 1
Explanation:
_HC₂H₃O₂ + _NaHCO₃ —> _NaC₂H₃O₂ + _CO₂ + _H₂O
To balance an equation, we simply do a head count of the individual elements and ensure they are balanced on both side.
For the above equation, we shall balance it as :
HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O
Reactant:
H = 5
C = 3
O = 5
Na = 1
Product:
H = 5
C = 3
O = 5
Na = 1
From the above, we can see that each element is the same on both side of the equation. Thus the equation is already balanced
HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O
The coefficients are: 1, 1, 1, 1, 1
What is true about the inertia of two cars, Car A of mass 1,500 kilograms and Car B of mass 2,000 kilograms?
OA.
Car A and Car Bhave the same inertia.
B.
Car A has more inertia than Car B.
Oc.
Car Bhas more inertia than Car A.
ОО
D.
Both the cars have negligible inertia.
I’m
Answers
Answer:
Car B has more inertia than Car A
Explanation:
Given that,
Mass of car A = 1500 kg
Mass of car B = 2000 kg
Inertia is directly proportional to the mass of an object. Inertia is the measure of the mass of an object.
In this case, the mass of car B is more than that of car A, it means the inertia of car B is more than that of car A.
Hence, the correct option is (c) "Car B has more inertia than Car A".
f) How many neutrons are there in the nucleus of arsenic?
1. Neodymium
2. Selenium
3. Strontium
Answers
Explanation:
How many neutrons are there in the nucleus of arsenic?42 neutrons
The nucleus consists of 33 protons (red) and 42 neutrons (blue).
An element has isotopes, which means the same number of protons but different numbers of neutrons.
Iron is a metal. The structure of iron is described as a lattice of positive ions in a sea of
electrons. Which of the following statements about iron are correct?
1 iron conducts electricity because the electrons are free to move
2 iron has a high melting point due to the strong covalent bonds
3 iron is an alloy
4 iron is malleable because the layers of atoms can slide over one another
A. 1 only
B. 1 and 3
C. 1 and 4
D. 2, 3 and 4
Answers
Answer: 1and 4
Explanation: iron is an element not an alloy. An ionic lattice is not bonded covalently.
What is the name of the compound O7I9
Answers
Answer:
question not clear can u rewrite
Convert 9.24 x 1023 molecules CO2 to moles
Answers
1.53 mol CO₂
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
9.24 × 10²³ molecules CO₂
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
Set up: [tex]\displaystyle 9.24 \cdot 10^{23} \ molecules \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ molecules \ CO_2})[/tex]Multiply/Divide: [tex]\displaystyle 1.53437 \ mol \ CO_2[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.53437 mol CO₂ ≈ 1.53 mol CO₂
What amount of heat (in kJ) is required to convert 14.0 g of an unknown liquid (MM = 67.44 g/mol) at 43.5 °C to a gas at 128.2 °C? (specific heat capacity of liquid = 1.18 J/g･°C; specific heat capacity of gas = 0.792 J/g･°C; ∆Hvap = 30.1 kJ/mol; normal boiling point, Tb = 97.4°C)
Answers
Answer:
1.24 kJ is required to convert 14 g of liquid from 43.5°C to 128.2°C
Explanation:
This is a typical calorimetry problem:
We have to assume, no heat is lost to sourrounding.
First of all, we need to go from 43.5°C to 97.4°C, the boiling point.
Q = Ce . m . ΔT
We replace data, 1.18° J/g . 14 g . (97.4°C - 43.5°C)
Heat for the first stage is: 890.4 Joules
Now we have to change the state, and we need the ΔH. As we do not have latent heat, we can proceed like this:
1 mol release 30.1 kJ at vaporization.
We convert the mass to moles → 14 g. 1mol/ 67.44g = 0.207 mol
0.207 mol will release (0.207 . 30.1 kJ) = 6.25 kJ
Now, we are at gaseous phase.
Q = Ce . m . ΔT → 0.792 J/g°C . 14g . (128.2°C - 97.4°C)
Q = 341.5 Joules
To determine the amount of heat, we sum all the obtained values:
890.4 Joules + 6250 Joules + 341.5 Joules = 1238.2 J
We convert to kJ → 1238.2 J . 1kJ / 1000J = 1.24 kJ
The heat required to convert 14.0 g of an unknown liquid at 43.5 °C to gas at 128.2 °C is 7.48 kJ.
We want to calculate the heat required to convert 14.0 g of an unknown liquid at 43.5 °C to gas at 128.2 °C.
We can divide this process in 3 steps.
Heating of the liquid from 43.5 °C to 97.4 °C (normal boiling point).Vaporization of the liquid at 97.4 °C.Heating of the gas from 97.4 °C to 128.2 °C.1. Heating of the liquid from 43.5 °C to 97.4 °CWe will calculate the heat for this step (Q₁) using the following expression.
Q₁ = c(l) × m × ΔT
Q₁ = (1.18 J/g･°C) × 14.0 g × (97.4 °C - 43.5 °C) = 890 J = 0.890 kJ
where,
c(l) is the specific heat capacity of the liquid.m is the mass of the substance.ΔT is the change in the temperature.2. Vaporization of the liquid at 97.4 °C.We will calculate the heat for this step (Q₂) using the following expression.
Q₂ = (m/M) × ΔHvap
Q₂ = [14.0 g/(67.44 g/mol)] × 30.1 kJ/mol = 6.25 kJ
where,
m is the mass of the substance.M is the molar mass of the substance.ΔHvap is the enthalpy of vaporization of the substance.3. Heating of the gas from 97.4 °C to 128.2 °C.We will calculate the heat for this step (Q₃) using the following expression.
Q₃ = c(g) × m × ΔT
Q₃ = (0.792 J/g･°C) × 14.0 g × (128.2 °C - 97.4 °C) = 342 J = 0.342 kJ
where,
c(g) is the specific heat capacity of the gas.m is the mass of the substance.ΔT is the change in the temperature.4. Total amount of heat required (Q)Q = Q₁ + Q₂ + Q₃ = 0.890 kJ + 6.25 kJ + 0.342 kJ = 7.48 kJ
The heat required to convert 14.0 g of an unknown liquid at 43.5 °C to gas at 128.2 °C is 7.48 kJ.
Learn more about heating curves here: https://brainly.com/question/10481356
Which of the following properties do solids and liquids have in common?
definite volume
definite temperature
definite smell
definite shape
Answers
Answer:
definite volume
Explanation:
Both solids and liquids have a definite volume: The difference is that solids have definite shape while liquids do not -liquids take the shape of their containers-.
Having a definite volume is why liquids cannot be compressed, a property that is used in hydraulic systems.
please help. im freaking out rn. i have like 40 missing assignments please
Answers
Answer:
I'm pretty sure its the one that says very little at the beginning but if I get it wrong I'm sorry
What key assumption of Bohr’s model would a Solar S y stem model of the atom violate? What was the theoretical basis for this assumption?
Answers
Answer:
See explanation
Explanation:
The solar system consists of the sun at the core surrounded by all the planets in their proper order. Similarly, the Bohr model of the atom upholds Rutherford's planetary model in which the atom was said to have a positive core surrounded by electrons moving in orbits just as the planets orbit round the sun.
The difference between the two models is that electrons are able to move from one energy level to another. This assumption violates the principles of the solar system because the position of the planets are fixed in their orbits.
The theoretical basis behind this assumption is that each spectral line is produced by the transition of electrons from one energy level to another.
Please match the correct type of reaction to its name.
Answers
2. Decomposition reaction
3. Double replacement reaction
4. Combustion reaction
5. Single replacement reaction
A car is traveling 100 miles per hour. How many feet does this car travel in 5 seconds?
Answers
Answer:
5280 feet per mile. 5280 feet divided 60 minutes then divide by 60 gives you the feet per second. multiply by 5.... 7 and 1/3 feet in 5 seconds.
What is the term for the chemical reaction that makes soap?
Answers
Answer: soaps are a sodium or potassium salts of long chain fatty acids.when triglycerides in fat/oil react with aqueous NaOH or KOH,they are converted into soap and glycerol.This is called alkaline hydrolysis of esters.Since this reaction leads to formation of soap, it is called the saponification process.
Explanation:
Western art criticism unique in that
Answers
Answer:
they are a lot tougher and are expecting only greatness, sort of like theater critiques.
Explanation:
Some antacid tables contain aluminum hydroxide. The aluminum hydroxide reacts with stomach acid according to the equation: Al(OH)3 + 3HCl →AlCl3 + 3H2O. Determine the moles of stomach acid (HCl) required if a tablet contains 8.89 moles of Al(OH)3.
Answers
Answer:
26.67 mol HCl
Explanation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
In order to solve this problem, we need to convert Al(OH)₃ moles to HCl moles.
To do so we use the stoichiometric ratios of the balanced reaction:
8.89 mol Al(OH)₃ * [tex]\frac{3molHCl}{1molAl(OH)_{3}}[/tex] = 26.67 mol HClThus 26.67 moles of HCl would react completely with 8.89 moles of Al(OH)₃.