Solve for x.

x-2.13 = 5.3

The probability that it will have an annual snowfall greater than 170 inches is 0.4.

The information is incomplete and the complete question wasn't found. An overview will be given. It should be noted that a probability means the likelihood of the occurence of an event.

Probability is calculated as:

= Number of ways of achieving success/Total number of possible outcomes

Let's assume that the total number of resort is 10 and those that have more than 170 inches are 4.

In this case, the probability will be:

= 4/10

= 0.4

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Yes a Linear Equation can be used and the slope and the y-intercept of the equation are respectively; B: slope = 10, y-intercept = 25

How to Write an equation in Slope Intercept Form?

We are given the coordinates;

(n, p) = (1, 35), (5, 75), (20, 225), (100, 1025)

Now, the way to find the slope is;

m = (y2 - y1)/(x2 - x1)

m = (75 - 35)/(5 - 1)

m = 10

The equation that models this is;

(y - 35)/(x - 1) = 10

y - 35 = 10x - 10

y = 10x + 25

Thus, y-intercept is at x = 0.

y = 10(0) + 25

y = 25

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Let [tex]S(t)[/tex] denote the amount of salt (in lbs) in the tank at time [tex]t[/tex] min up to the 10th minute. The tank starts with 100 gal of fresh water, so [tex]S(0)=0[/tex].

Salt flows into the tank at a rate of

[tex]\left(0.5\dfrac{\rm lb}{\rm gal}\right) \left(2\dfrac{\rm gal}{\rm min}\right) = 1\dfrac{\rm lb}{\rm min}[/tex]

and flows out with rate

[tex]\left(\dfrac{S(t)\,\rm lb}{100\,\mathrm{gal} + \left(2\frac{\rm gal}{\rm min} - 2\frac{\rm gal}{\rm min}\right)t}\right) \left(2\dfrac{\rm gal}{\rm min}\right) = \dfrac{S(t)}{50} \dfrac{\rm lb}{\rm min}[/tex]

Then the net rate of change in the salt content of the mixture is governed by the linear differential equation

[tex]\dfrac{dS}{dt} = 1 - \dfrac S{50}[/tex]

Solving with an integrating factor, we have

[tex]\dfrac{dS}{dt} + \dfrac S{50} = 1[/tex]

[tex]\dfrac{dS}{dt} e^{t/50}+ \dfrac1{50}Se^{t/50} = e^{t/50}[/tex]

[tex]\dfrac{d}{dt} \left(S e^{t/50}\right) = e^{t/50}[/tex]

By the fundamental theorem of calculus, integrating both sides yields

[tex]\displaystyle S e^{t/50} = Se^{t/50}\bigg|_{t=0} + \int_0^t e^{u/50}\, du[/tex]

[tex]S e^{t/50} = S(0) + 50(e^{t/50} - 1)[/tex]

[tex]S = 50 - 50e^{-t/50}[/tex]

After 10 min, the tank contains

[tex]S(10) = 50 - 50e^{-10/50} = 50 \dfrac{e^{1/5}-1}{e^{1/5}} \approx 9.063 \,\rm lb[/tex]

of salt.

Now let [tex]\hat S(t)[/tex] denote the amount of salt in the tank at time [tex]t[/tex] min after the first 10 minutes have elapsed, with initial value [tex]\hat S(0)=S(10)[/tex].

Fresh water is poured into the tank, so there is no salt inflow. The salt that remains in the tank flows out at a rate of

[tex]\left(\dfrac{\hat S(t)\,\rm lb}{100\,\mathrm{gal}+\left(2\frac{\rm gal}{\rm min}-2\frac{\rm gal}{\rm min}\right)t}\right) \left(2\dfrac{\rm gal}{\rm min}\right) = \dfrac{\hat S(t)}{50} \dfrac{\rm lb}{\rm min}[/tex]

so that [tex]\hat S[/tex] is given by the differential equation

[tex]\dfrac{d\hat S}{dt} = -\dfrac{\hat S}{50}[/tex]

We solve this equation in exactly the same way.

[tex]\dfrac{d\hat S}{dt} + \dfrac{\hat S}{50} = 0[/tex]

[tex]\dfrac{d\hat S}{dt} e^{t/50} + \dfrac1{50}\hat S e^{t/50} = 0[/tex]

[tex]\dfrac{d}{dt} \left(\hat S e^{t/50}\right) = 0[/tex]

[tex]\hat S e^{t/50} = \hat S(0)[/tex]

[tex]\hat S = 50 \dfrac{e^{1/5}-1}{e^{1/5}} e^{-t/50}[/tex]

After another 10 min, the tank has

[tex]\hat S(10) = 50 \dfrac{e^{1/5}-1}{e^{1/5}} e^{-1/5} = 50 \dfrac{e^{1/5}-1}{e^{2/5}} \approx \boxed{7.421}[/tex]

lb of salt.

The radius and the center of the circle are 4 units and (1,2), respectively

The center of the circle is on

y = 2x and x = 1

Substitute x = 1 in y = 2x

y = 2 * 1

Evaluate

y = 2

This means that the center is

Center = (1, 2)

Also, we have the point of tangency to be:

(x, y) = (1, 6)

This point and the center have the same x-coordinate.

So, the distance between this point and the center is

d = 6 - 2

d = 4

This represents the radius

Hence, the radius and the center of the circle are 4 units and (1,2), respectively

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The large cone can hold more ice cream than the four smaller cones combined.

The large cone is a better deal.

A cone is a three-dimensional structure with a round base and a point at the top, known as the vertex.

A cone is a three-dimensional solid geometric object with a point at the top and a circular base. A cone has a vertex and one face. For a cone, there are no edges.

The radius, height, and slant height of the cone are its three constituent parts.

For the supersized cone,

Volume = π(5)(5)(12)/3 = 314.29 cubic inches

For a small cone,

Volume= π(2.5)(2.5)(6)/3 = 39.29 cubic inches

Combined volume of 4 such cones = 4*39.29 = 157.16 cubic inches

As the volume of the larger cone is more, thus it holds more ice cream. Also it is a better deal, as it costs less than 4 small cones.

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Answer: [tex]160^{\circ}[/tex]

Step-by-step explanation:

By the exterior angle theorem,

[tex]4x-14+5x-182=5x-100\\\\9x-196=5x-100\\\\4x=96\\\\x=24\\\\\implies m\angle BCD=20^{\circ}\\\\\implies m\angle BCA=160^{\circ}[/tex]

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

By Exterior angle property :

[tex]\qquad❖ \: \sf \:4x - 114 + 5x - 182 = 5x - 100[/tex]

[tex]\qquad❖ \: \sf \:9x -29 6 = 5x - 100[/tex]

[tex]\qquad❖ \: \sf \:9x - 5x = - 100 + 296[/tex]

[tex]\qquad❖ \: \sf \:4x = 96[/tex]

[tex]\qquad❖ \: \sf \:x = 24 \degree[/tex]

Next, Angle BCA = 180° - Angle BCD

( linear pair )

[ let angle BCA = y ]

[tex]\qquad❖ \: \sf \:y = 180 - (5x- 100)[/tex]

[tex]\qquad❖ \: \sf \:y = 180 - (5(24) - 100)[/tex]

[tex]\qquad❖ \: \sf \:y = 180 - (120 - 100)[/tex]

[tex]\qquad❖ \: \sf \:y = 180 - 20[/tex]

[tex]\qquad❖ \: \sf \:y = 160 \degree[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

================================================

Explanation:

These are the steps to focus on

step 3: -6x - 8 < -2

step 4: -6x < 6

The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.

That property has four forms

It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c

We add the same thing to both sides to keep things balanced.

[tex]\underset{\leftarrow \qquad \textit{\LARGE 4x}\qquad \to }{R\stackrel{4x-4}{\rule[0.35em]{7em}{0.25pt}} S\stackrel{2x}{\rule[0.35em]{20em}{0.25pt}}T} \\\\\\ RT~~ - ~~ST~~ = ~~RS\implies \stackrel{RT}{4x} - \stackrel{ST}{2x}~~ = ~~\stackrel{RS}{4x-4} \\\\\\ -2x=-4\implies x=\cfrac{-4}{-2}\implies \boxed{x=2}~\hfill \stackrel{4(2)~~ - ~~4}{RS=8}[/tex]

The correct answer is Yes. The graph represents a function. The function given is: F(x) = y(-5). Note that the value of x is zero.

A function's graph is the set of all points in the plane of the form (x, f(x)). The graph of f might similarly be defined as the graph of the equation y = f. (x).

Thus, the correct answer or function represented in the graph is f(x) = y(-5)

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The fraction of the remaining marbles in the bag will be blue is 6/17.

The first step is to determine the initial number of marbles in the bag:

Initial number of red marbles in the bag : (5/8) x 240 = 150

Initial number of blue marbles in the bag : (2/8) x 240 = 60

Initial number of green marbles in the bag : 240 - 150 - 60 = 30

Number of red marbles remaining after 1/3 is removed = (1 - 1/3) x 150

2/3 x 150 = 100

Number of green marbles remaining after 2/3 is removed = (1 - 2/3) x 30

1/3 x 30 = 10

Total number of marbles now in the bag : 100 + 10 + 60 = 170

Fraction of blue marbles = 60 / 170 = 6/17

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The period of the function y = 2∕3 cos(4∕7x) + 2. is 7/2π

The function is given as:

y = 2∕3 cos(4∕7x) + 2.

The above function is a cosine function

A cosine function is represented as:

y = A cos(B(x + C)) + D

Where the period is

Period = 2π/B

By comparing the equations, we have

B = 4/7

Substitute B = 4/7 in Period = 2π/B

Period = 2π/(4/7)

Express as product

Period = 2π * 7/4

Divide 4 by 2

Period = π * 7/2

Evaluate the product

Period = 7/2π

Hence, the period of the function y = 2∕3 cos(4∕7x) + 2. is 7/2π

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Given the length of the ladder and the angle it made with the ground, it will reach 16.7 ft up the wall.

Given that;

To determine the length wall from the tip of the ladder to the ground level, we use trigonometric ratio since the scenario forms a right angle triangle.

Sinθ = Opposite / Hypotenuse

Sin( 71° ) = x / 17ft

x = Sin( 71° ) × 17ft

x = 0.9455 × 17ft

x = 16.1 ft

Given the length of the ladder and the angle it made with the ground, it will reach 16.7 ft up the wall.

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Based on the amounts that Janet Lopez has to invest in stocks and bonds, the linear programming model would be:

The return on stocks (x) is 18% and the return on bonds (y) is 6%, The objective function:

= 0.18x + 0.06y

There are constraints to watch out for:

Maximum to lose on stocks is 22% and on bonds is 5% but these are to be less than the total amount of $100,000.

0.22x + 0.05y ≤ 100,000

The total amount to invest is $72,000 which means that both bonds and stocks need to be less than this amount:

x + y ≤ 720,000

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Using equivalent angles, we have that the measures are given as follows:

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

120º is in the second quadrant, hence the equivalent on the first quadrant is:

180º - 120º = 60º.

The sine on the second quadrant is positive, hence:

[tex]\sin{120^\circ} = \sin{60^{\circ}} = \frac{\sqrt{3}}{2}[/tex]

The cosine on the second quadrant is negative, hence:

[tex]\cos{120^\circ} = \cos{60^{\circ}} = -\frac{1}{2}[/tex]

The tangent is given by the sine divided by the cosine, hence:

[tex]\tan{120^\circ} = \frac{\sin{120^\circ}}{\cos{120^\circ}} = -\sqrt{3}[/tex]

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[tex](g-f)(x)=g(x)-f(x)=2x-(-x)=3x[/tex]

The graph is shown in the attached image.

Answer:

45°

Step-by-step explanation:

Angles in a triangle add to 180 degrees, so

So, the measure of angle X is 2(14)+17=45°

The number of 150-pound gas cylinders are used each year  for the well is 22.

V = 500 gal/min x 1 year x 525600 min/year

V = 262,800,000 gallons =  994,806,216.835 liters

mass = density x volume

mass = 1.5 mg/L x 994,806,216.835 L

mass = 1,492,209,325 mg = 3289.75 lb

n = 3289.75 lb/150 lb

n = 21.9

n ≈ 22 gas cylinders

Thus, the number of 150-pound gas cylinders are used each year  for the well is 22.

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Answer:

Step-by-step explanation:

According to the distribution table, the percent values within the interval of [- 2, 2] are:

Add them together to get the required answer:

The answer is 0.6 or 60%.

The respective probabilities that lie in the interval [-2, 2] are 0.33, 0.16, and 0.11. Therefore, the probability it lies in the interval is equal to the sum of the probabilities.

The net gain of the stock for these three days is 1 points

Net gain / net loss = Monday + Tuesday + Wednesday

= - 8 1/4 + (-2 3/4) + 12

= - 8 1/4 - 2 3/4 + 12

= -11 + 12

Net gain = 1 point

Therefore, the net gain of the stock for these three days is 1 points

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The type of reflection performed and the scale factor of dilation of the diagram are; Reflection over the x-axis and a scale factor dilation of 2.

From the given diagram, we are told that triangle ABC is transformed into Triangle A"B"C".

Now, we are told that both triangles are similar and as such if they are similar then, it means each corresponding side has the same ratio. Thus, there was a dilation by a scale factor of 2.

Now, the reflection that took place after the dilation would be a reflection over the x-axis.

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The test statistic is 27.8484, the p-value is 0, and the final conclusion is that the null hypothesis H is rejected.

Given that 914 babies were born to parents who used the new method, and 877 of them were girls, the significance level to test the claim that the new method is effective in increasing the likelihood of a baby being a girl, is 0.01.

The following information is provided: the sample size is N = 914, the number of favorable cases is X = 877, and the sampling ratio is

pˉ = X / N

Pˉ = 877/914

pˉ = 0.9595 and the significance level is α = 0.01

(a) Hypothesis Zero and Alternative

The following null and alternative hypotheses should be tested:

null: p = 0.5

Alternative: p> 0.5

This is equivalent to a right-tailed test, which requires a z-test for a proportion of the population.

(b) Critical Value

Based on the information provided, the significance level is α = 0.01, so the critical value for this right-tailed test is Zc = 2.3263. This can be found using Excel or the Z distribution table. Region of rejection

The rejection area for this test on the right side is Z> 2.3263

Test statistics

The z-statistic is calculated as follows:

[tex]\begin{aligned}Z&=\frac{\bar{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\ &=\frac{0.9595-0.50}{\sqrt{\frac{0.5(1-0.5)}{914}}}\\ &=\frac{0.4595}{0.0165}\\ &=27.8484\end[/tex]

(c) The p-value

The p-value is the probability that the sample results are extreme or more extreme than the sample results obtained, assuming the null hypothesis is true. In this case,

the p-value is p = P (Z> 27.8484) = 0

(d) The decision on the null hypothesis

Using the traditional method

Since we observe that Z = 27.8484> Zc = 2.3263, we conclude that the null hypothesis is rejected.

Using the p-value method

Using the approximation of the P-value: the p-value is p = 0, and since p = 0≤0.01 we conclude that the null hypothesis is rejected.

(e) Conclusion

It is concluded that the null hypothesis H is rejected. Therefore, there is sufficient evidence to state that the population proportion p is greater than 0.5, at the significance level of 0.01.

Hence, for 914 babies born to parents using the new method, of which 877 were girls, the test statistic is 27.8484, the p-value is 0, and the final conclusion is that the null hypothesis is rejected.

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well, when it comes to fractions or rationals, they can never have a denominator that's 0, because if that ever happens, the fraction becomes undefined, so the values of "x" or namely the domain values, that we cannot have because they make the fraction undefined are those values that make the denominator 0, we can simply get them by setting the denominator to 0 and check what's "x".

[tex]x^2-9=0\implies x^2=9\implies x=\pm\sqrt{9}\implies x=\pm 3 \\\\[-0.35em] ~\dotfill\\\\ g(x)=\cfrac{x+6}{x^2-9}\hspace{5em} x\ne \begin{cases} 3\\ -3 \end{cases}[/tex]

Answer:

1000

Step-by-step explanation:

Answer:

[tex]x[/tex] = 67°

Step-by-step explanation:

As we can see in the diagram, ∠[tex]x[/tex] and the 78° angle together make up the 145° angle.

∴ [tex]x[/tex] + 78° = 145°

⇒ [tex]x[/tex] = 145° - 78°

⇒ [tex]x[/tex] = 67°

Answer: (0,1/3)

Step-by-step explanation:

Answer:

The y-intercept of the function f(x) = -2/9x + 1/3 is 1/3.

Step-by-step explanation:

Given, function is

f(x) = -2/9x + 1/3.

The y-intercept is the point where the graph intersects the y-axis.

The y-intercept of a graph is (are) the point(s) where the graph intersects the y-axis.

We know that the x-coordinate of any point on the y-axis is 0.

So the x-coordinate of a y-intercept is 0.

To find the y - intercept set x = 0.

f(0) = (2/9 . 0) + 1/3

f(0) = 0 + 1/3

f(0) = 1/3.

The rotation of the triangle [tex]\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\end{array}\right][/tex] 270° counter-clockwise about the origin gives [tex]\left[\begin{array}{ccc}-1&-1&3\\1&-2&-2\end{array}\right][/tex]

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

If a point (x, y) is rotated 270° counter-clockwise about the origin, the new point is (y, -x)

The rotation of the triangle [tex]\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\end{array}\right][/tex] 270° counter-clockwise about the origin gives [tex]\left[\begin{array}{ccc}-1&-1&3\\1&-2&-2\end{array}\right][/tex]

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The coordinate of each point is just the number it corresponds to.

a) 6

b) -5

c) 9

d) 0

Answer:

0.000862

Hope this helps :) If you have anymore questions just comment

Answer:

0.000862384670817 that is the answer

The complete proof for part D is given in the attached text. Hence, by the nature of the converse corresponding angle,

OP is parallel to MN. (OP ║ MN).

A mathematical proof is an argument that is inferential with respect to a mathematical assertion that demonstrates that the provided assumptions logically ensure the conclusion.

The complete proof for part D is given as follow:

If a transversal line "t" divides through OP and MN as given in the attached image, and SE and "T.F" are the divider of ∠QSD and ∠STM, then:

∠QSE = 1/2 ∠QSO; and

∠"STF" = 1/2 ∠STM

If the corresponding angle is ∠QST = "STF", then

QSD = "STF"

Hence, by the nature of the converse corresponding angle,

OP is parallel to MN

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Answer:

D

Step-by-step explanation: