the battery and ODC input voltages, as well as the main parameters for the power source, fireworks, relays, anti-static resistances, etc. The statements below refer to the design and operation of the power sub-system on a spacecraft.
How do spaceship electric power systems work?Solar panels on these spacecraft convert solar energy into the electricity they require for propulsion. The electricity generated by the solar panels is used to recharge a battery within the spacecraft. These batteries can power the spaceship even as it is traveling away from the sun.
What make up a spacecraft's subsystems?The engine, temperature management, power and power distribution, attitude control, telemetry command and control, transmitters/antenna, computers/on-board processing/software, and structural components are only a few of the many subsystems that make up a spaceship bus.
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A 400-ft equal tangent sag vertical curve has its PVC at station 100 00 and elevation 450 ft. The initial grade is -4.0% and the final grade is 2.5%. Determine the elevation of the lowest point of the curve g
The elevation of lowest point of the curve is 445.077 ft.
What is elevation?Height above or below the mean sea level is referred to as elevation. A map's elevation can be depicted either by labelling the precise elevations of specific points or by using contour lines, which link points of the same elevation. Topographic maps are depicted as having elevations.
Calculate rate of change of the curve as below:
[tex]$$\begin{aligned}r & =\frac{g_2-g_1}{L} \\& =\frac{2.5-(-4.0)}{\left(\frac{400}{100}\right)} \\& =1.625 \%\end{aligned}$$[/tex]
Calculate distance from PC to the lowest point as below:
[tex]$$\begin{aligned}X & =\frac{-g_1}{r} \\& =\frac{-(-4.0 \%)}{1.625 \%} \\& =2.462 \mathrm{ft}\end{aligned}$$[/tex]
Calculate the elevation of the lowest point of the curve as below:
[tex]$$\begin{aligned}Y & =Y_{P C}+g_1 X+\frac{r}{2} X^2 \\& =450\mathrm{ft}+(-4.0 \times 2.462)+\frac{1.625}{2}(2.462)^2 \\& =450\mathrm{ft}-9.848 \mathrm{ft}+4.925 \mathrm{ft} \\& =\mathbf{445.077} \mathrm{ft}\end{aligned}$$[/tex]
Thus, the elevation of lowest point of the curve is 445.077ft.
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The top of the tee joint heats up faster than the bottom because?
Answer: the bottom is a harder material than, the actual w33d inside it
Explanation:
Raw sugar cane is taken into a process to create sugar, which is essentially sucrose. the raw cane is approximately 16% sucrose, 63% water, and the rest fiber by mass. juice from the cane is extracted by passing the cane through a series of crushers. about 5% extra mass of water is added to the sugar cane prior to this step to help in the extraction process. the crushed cane and liquid juice is sent to a filter press that creates a cake that contains 4% of the weight of the cane juice, which has a composition similar to the overall non-fiber content of the raw cane. the filtrate is sent to an evaporator where enough water is evaporated to obtain a pale yellow juice that is 41% water. A series of vacuum processes removes enough water without damaging the sugars until you obtain a solution that is 91% sucrose. At this point, the mixture is fed to a crystallizer to produce a final product of sucrose that is 97.8% crystal. You control the process by measuring the flowrate of the solution into the crystallizer using a manometer that has mercury as the working fluid. The open-ended manometer shows a mercury height difference of 6.3 inches, , while the height of the sucrose solution in the manometer between the mercury and the pipe is 15.3 in.
The flowrate of the mixture into the crystallizer is related to the pressure with the following equation:
q(m^3/s) = 0.0307 m^3/hr atm^1/2 √ Pmanometer
What is the mass of sugar cane being fed to the process with this flowrate, in kg/s?
The mass of sugar cane being fed to the process with this flowrate is 0.0014 kg/s.
What is flowrate?Flowrate is the rate at which a fluid or gas passes through a given space or container over a period of time. It is usually expressed in terms of volume per unit of time, such as liters per second or gallons per minute. Flowrate is an important factor in many engineering and scientific applications, such as fluid dynamics, hydroelectric power generation, and chemical processing. It is also used to measure the flow of liquids and gases through pipes, valves, and other components of a system.
The mass of sugar cane being fed to the process can be calculated using the following equation:
Mass (kg/s) = Flowrate (m^3/s) * Density of the mixture (kg/m^3)
The flowrate can be calculated using the equation given:
q(m^3/s) = 0.0307 m^3/hr atm^1/2 √ Pmanometer
Therefore, the flowrate is:
q(m^3/s) = 0.0307 m^3/hr * (atm^1/2 * (6.3 in/12 in/ft)^1/2)
q(m^3/s) = 0.0015 m^3/s
The density of the mixture can be calculated using the following equation:
Density of the mixture (kg/m^3) = Mass of sugar (kg) / Volume of the mixture (m^3)
The mass of sugar can be calculated using the following equation:
Mass of sugar (kg) = Mass of the mixture (kg) * (Mass fraction of sugar (kg/kg) / Mass fraction of the mixture (kg/kg))
The mass of the mixture can be calculated using the following equation:
Mass of the mixture (kg) = Volume of the mixture (m^3) * Density of the mixture (kg/m^3)
The volume of the mixture can be calculated using the following equation:
Volume of the mixture (m^3) = Flowrate (m^3/s)
The mass fraction of sugar can be calculated using the following equation:
Mass fraction of sugar (kg/kg) = Mass of Sugar (kg) / Mass of the mixture (kg)
The mass fraction of the mixture can be calculated using the following equation:
Mass fraction of the mixture (kg/kg) = Mass of the mixture (kg) / Mass of the mixture (kg)
Substituting the values into the equation, we get:
Mass (kg/s) = 0.0015 m^3/s * (0.91 kg/m^3)
Mass (kg/s) = 0.0014 kg/s
Therefore, the mass of sugar cane being fed to the process with this flowrate is 0.0014 kg/s.
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a 90° elbow in a horizontal pipe is used to direct water flow upward at a rat of 40 kg/s.
About 296.5 N of anchoring force is required to keep the elbow in place. About 134.8 is the direction of the anchoring force.
What are the object's size and direction?The speed of an object is its magnitude (or value), which is the velocity. The item is traveling in the direction indicated by the velocity vector. Imagine a circle (or, better yet, draw one) and an object traveling along the path it defines.
How do you calculate the force's magnitude?Units of mass times length over time squared are used to express the strength of a force. The most used unit in metric measurements is the newton (N), which is equal to one-kilogram times one meter over one second squared.
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Part A
Determine the force in member DE of the truss, and state if the member is in tension or compression. Take F1 = 564 N , F2 = 905 N .
(Figure 1)
Express your answer to three significant figures and include the appropriate units. Assume positive scalars for members in tension and negative scalars for members in compression.
Part B
Determine the forces in members DC and CB of the truss, and state if the members are in tension or compression.
Express your answer to three significant figures and include the appropriate units. Assume positive scalars for members in tension and negative scalars for members in compression.
Part C
Determine the force in member CE of the truss, and state if the member is in tension or compression.
Express your answer to three significant figures and include the appropriate units. Assume positive scalars for members in tension and negative scalars for members in compression.
Part D
Determine the force in member EB of the truss, and state if the member is in tension or compression.
Express your answer to three significant figures and include the appropriate units. Assume positive scalars for members in tension and negative scalars for members in compression.
Part E
Determine the force in member EA of the truss, and state if the member is in tension or compression.
Express your answer to three significant figures and include the appropriate units. Assume positive scalars for members in tension and negative scalars for members in compression.
Find the weight W needed to hold the wall shown in Fig. P2.76 upright. The wall is 10 m wide.
The weight needed to hold the wall is equal to 14.9285 N.
What is force equilibrium?The force equilibrium can be described as the addition of the forces about x, y, and z-axis will be equal to zero and the sum of the moment also equal to zero.
Given, the width of the wall, b = 10 m
The height of the water, d = 4 m
The height of the wall, l = 7m
The area of the wall, A = bd = 10(4) = 40 m²
The expression of the centroid of the wall, [tex]\displaystyle \bar x = \frac{d}{2}[/tex]
[tex]\displaystyle \bar x = \frac{4}{2} = 2 m[/tex]
The hydrostatic force, F = ρgAx
F = (1000) (9.81) (40) (2)
F = 784,000 N
The expression for the moment of inertia: [tex]\displaystyle I_C =\frac{bd^3}{12}[/tex]
[tex]I_c = 10\times 4/12 = 53.34 m^4[/tex]
The relation of the center of the pressure gate can be written as:
[tex]\displaystyle \bar h = \bar x +\frac{I_C}{A\bar x}[/tex]
[tex]\bar h = 2 + \frac{53.34}{40\times 2} = 2.667 \; m[/tex]
The moment about point: l × W - F(d - h) = 0
Substitute the values in the above equation:
7 × W - 78400 (4 - 2.667) = 0
7 W = 78400 (4 - 2.667)
W = 14.92 kN
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