From the Ksp for Na3PO4, the solubility of the ions is determined to be 27S4. Solubility is a term used in chemistry to describe a substance's capacity to mix with another substance, the solvent.
Na+ and PO4-3 are the ions found in Na3PO4. Since sodium is listed on the periodic table as an alkali metal, it will create a positive charge in solution. A polyatomic ion is one that requires its charge to be remembered, such as the phosphate ion. Therefore, each unit of sodium phosphate that dissolves produces 4 ions. As a result, each molecule of Na3PO4 has a total of four ions in the solution.
Na3PO4 -> 3Na+ + [PO4 3-]
Let the solubility of each ion be S such that
Ksp = [Na+]^3 [(PO4)3-]
Ksp = (3S)^3 (S) = 27S^4 as there are 3 sodium ions and 1 phosphate ion.
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You have 3L of a 2 molar magnesium chloride solution. How many moles of chloride ions are present?
Show all work!
Answer:
12 moles Cl⁻
Explanation:
To find the moles Cl⁻, you need to (1) calculate the moles of magnesium chloride (MgCl₂) using the molarity equation and then (2) convert moles MgCl₂ to moles Cl⁻ (via the mole-to-mole ratio from formula subscripts). It is important to arrange the conversions in a way that allows for the cancellation of units.
Molarity (M) = moles / volume (L)
2 M = moles / 3 L
6 = moles MgCl₂
1 MgCl₂ = 1 Mg²⁺ and 2 Cl⁻
6 moles MgCl₂ 2 moles Cl⁻
------------------------ x ----------------------- = 12 moles Cl⁻
1 mole MgCl₂
Lactic acid has a pKa of 3.08. What is the approximate degree of dissociation of a 0.35 M solution of lactic acid?
A) 1.1%
B) 2.2%
C) 4.8%
D) 14%
E) none of the above
Your answer would be C, 4.8%.
3. What is the molar mass of Li2SO4? (2 points)
O 54.9 g/mol
103.0 g/mol
O109.9 g/mol
O 206.1 g/mol
Answer:
C.) 109.9 g/mol
Explanation:
The molar mass is the sum of each element's atomic weight times their quantity. There is one atom of each element unless denoted by subscripts.
Atomic Mass (Li): 6.9410 g/mol
Atomic Mass (S): 32.065 g/mol
Atomic Mass (O): 15.998 g/mol
Molar Mass (Li₂SO₄): 2(6.9410 g/mol) + 32.065 g/mol + 4(15.998 g/mol)
Molar Mass (Li₂SO₄): 109.939 g/mol
An ion of an element can have the same as another element.
A. number of protons
B. None of these
OC. electron configuration
D. atomic mass
Answer:
A
Explanation:
In a simple perspective, an ion of an element is an element +- [tex]n[/tex] amount of electrons.
We know that electrons have atomic mass, so we can mark off D
We know that with more or fewer electrons, the electron configuration would change
However, the number of protons won't change in the ion of an element, this is because an ion is only the change in electrons, not protons or neutrons (the particles that make up a nucleus of an atom)
Suppose a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O). The total pressure of the mixture is 2.00 atm. A mole fraction is defined as the moles of a specific component divided by the total number of moles present. What is the mole fraction of O₂ in this mixture?
Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.
Definition of mole fractionThe molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:
[tex]mole fraction=\frac{moles of substance}{moles of solution}[/tex]
Mole fraction of O₂ in this mixtureIn this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).
So, the total moles of the solution can be calculated as:
Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)
Then:
Total moles= 4.60 moles + 6 moles
Total moles= 10.60 moles
Finally, the more fraction of O₂ can be calculated as follow:
[tex]Mole fraction of O_{2} =\frac{moles of O_{2}}{total moles}[/tex]
[tex]Mole fraction of O_{2} =\frac{4.60 moles}{10.6o moles}[/tex]
Solving:
Mole fraction O₂ = 0.434
Finally, the mole fraction of O₂ in the mixture is 0.434.
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QUESTION 18
A container with a volume of 3.76 L holds 0.574 moles of nitrogen gas at 2.88 atm. What is the temperature of the gas in °C?
Answer:
-43.3 °C
Explanation:
To find the temperature, you need to use the Ideal Gas Law equation. The equation looks like this:
PV = nRT
In this formula,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Law constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
By plugging the given values into the equation and simplifying, you can find the temperature. After you get a temperature, you need to convert it into Celsius.
P = 2.88 atm R = 0.08206 atm*L/mol*K
V = 3.76 L T = ? K
n = 0.574 moles
PV = nRT
(2.88 atm)(3.76 L) = (0.574 moles)(0.08206 atm*L/mol*K)T
10.8288 = (0.04710244)T
230. K = T
Kelvin - 273.15 = Celsius
230 K - 273.15 = -43.3 °C
Suppose you experimentally calculate the value of the gas constant R
as 0.0878 L-atm/mol-K. The known value is 0.0821 L-atm/mol-K.
What is the percent error of your experimentally determined R?
Answer: 5.72%
Explanation:
Given:
Experimental value of gas constant, R = 0.0878 L.atm/mol⋅K
Known value of gas constant, R = 0.0821 L.atm/mol⋅K
This percent error is defined as the difference in percentage between a measurement's real value and its observed value.
[tex]\text { Percent Error }=\frac{\mid \text { Experimental Value }-\text { Known Value } \mid}{\text { Known Value }} * 100[/tex]
[tex]\text { Percent Error }=\frac{\mid \text {0.0878}-\text { 0.0821 } \mid}{\text { 0.0821 }} * 100[/tex]
[tex]\bf{Percent \ Error = 5.72\%}[/tex]
Calculate the mass in grams of benzophenone required to make a solution of 2.5 mmoles
Answer:
0.46 grams (C₆H₅)₂CO
Explanation:
To find the mass of benzophenone ((C₆H₅)₂CO), you need to (1) convert mmoles to moles and then (2) convert moles to grams (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 2 sig figs to match the sig figs of the given value (2.5 mmoles).
Molar Mass ((C₆H₅)₂CO): 13(12.011 g/mol) + 10(1.008 g/mol) + 15.998 g/mol
Molar Mass ((C₆H₅)₂CO): 182.221 g/mol
2.5 mmoles (C₆H₅)₂CO 1 mole 182.221 g
----------------------------------- x ------------------------ x ------------------- =
1,000 mmoles 1 mole
= 0.46 grams (C₆H₅)₂CO
Part A
How much heat is required to convert 4.88 g of ice at-14.0°C to water at 23.0°C? (The heat capacity of ice is 2.09 J/(g- "C). AHp (H₂O) = 40.7 kJ/mol, and AH (H₂O) = 6.02 kJ/mol.)
Express your answer with the appropriate units.
?
Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 2.243974 kJ or 2,243.974 J.
Definition of calorimetry, sensible heat and latent heatCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Latent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
-14 °C to 0°CIn firts place, you know that the melting point is 0°C. So, first of all you must increase the temperature from -14 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
c(solid)= heat capacity of ice= 2.09 [tex]\frac{J}{gC}[/tex]m= 4.88 gΔT= Tfinal - Tinitial= 0 °C - (-14) °C= 14 °CReplacing:
Q1= 2.09 [tex]\frac{J}{gC}[/tex] × 4.88 g× 14 °C
Solving:
Q1=142.7888 J= 0.1427888 kJ
Change of stateThe heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
In this case, you know:
n= 4.88 g×[tex]\frac{1 mole}{18 g}[/tex] = 0.2711 moles, where 18 [tex]\frac{g}{mole}[/tex] is the molar mass of H₂O, that is, the amount of mass that a substance contains in one mole.ΔHfus= 6.02 [tex]\frac{kJ}{mol}[/tex]Replacing:
Q2= 0.2711 moles×6.02 [tex]\frac{kJ}{mol}[/tex]
Solving:
Q2= 1.632022 kJ
0 °C to 23 °CSimilar to sensible heat previously calculated, you know:
c(liquid)= specific heat of water= 4.18[tex]\frac{J}{gC}[/tex]m= 4.88 gΔT= Tfinal - Tinitial= 23 °C - 0 °C= 23 °CReplacing:
Q3= 4.18[tex]\frac{J}{gC}[/tex] × 4.88 g× 23 °C
Solving:
Q3= 469.1632 J= 0.4691632 kJ
Total heat requiredThe total heat required is calculated as:
Total heat required= 0.1427888 kJ + 1.632022 kJ + 0.4691632 kJ
Total heat required= 2.243974 kJ= 2,243.974 J
In summary, the amount of heat required is 2.243974 kJ or 2,243.974 J.
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Identify the potential products NH4Cl+NaClO3
Answer:
NH₄ClO₃ and NaCl
Explanation:
This appears to be a double-displacement reaction. In these reactions, the cation of one compound is swapped with the cation of another.
So, NH₄⁺ from NH₄Cl is swapped with Na⁺ from NaClO₃. It is important that the resulting ionic compound has an overall charge of 0. In this case, the charges perfectly balance, so there only needs to be one atom of each ion in the compounds.
1.) NH₄ClO₃
-----> NH₄⁺ and ClO₃⁻
-----> +1 + (-1) = 0
2.) NaCl
-----> Na⁺ and Cl⁻
-----> +1 + (-1) = 0
The chemical equation:
NH₄Cl + NaClO₃ -----> NH₄ClO₃ + NaCl
Which of the following aqueous solutions are good buffer systems?
(Select all that apply.)
a. 0.18 M nitrous acid + 0.13 M sodium nitrite
b. 0.27 M nitric acid + 0.25 M sodium nitrate
c. 0.29 M ammonia + 0.40 M potassium hydroxide
d. 0.15 M sodium hydroxide + 0.30 M sodium chloride
e. 0.32 M sodium chloride + 0.20 M calcium chloride
0.18 M nitrous acid + 0.13 M sodium nitrite is a good buffer system.
Hence, Option A is correct answer.
What is Buffer Solution ?It is a solution that prevent any changes in the pH of the solution on the addition of an acidic and basic components.
What are the conditions for the goof buffer system ? a weak acid and its conjugate base.a weak base and its conjugate acid.Now lets check all options one by one:
Option (A): 0.18 M nitrous acid + 0.13 M sodium nitrite
Nitrous acid is a weak acid and sodium nitrate is a conjugate base. This is a buffer.
Option (B): 0.27 M nitric acid + 0.25 M sodium nitrate
Nitric acid is a strong acid and sodium nitrate is neutral salt. So this is not good buffer.
Option (C): 0.29 M ammonia + 0.40 M potassium hydroxide
Potassium hydroxide is a strong base and Ammonia is also a strong base. So this is not a good buffer.
Option (D): 0.15 M sodium hydroxide + 0.30 M sodium chloride
Sodium hydroxide is a strong base and Sodium chloride is a ionic salt. So this is not a good buffer.
Option (E): 0.32 M sodium chloride + 0.20 M calcium chloride
Sodium chloride is a ionic salt and calcium chloride is a salt of strong acid. So this is not a good buffer.
Thus from the above conclusion we can say that 0.18 M nitrous acid + 0.13 M sodium nitrite is a good buffer system.
Hence, Option A is correct answer.
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balance the redox reaction in alkaline medium & identify the oxidizing & reducing agents
I- + MnO4- ——> IO3- + MnO2
The balanced redox equation of the reaction is given below:
I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻The oxidizing agent is MnO₄ while the reducing agent is I⁻.
What are redox equations?Redox equations are equations in which oxidation and reduction reactions occur together.
Redox reactions can take place in alkaline or acidic mediums.
The balanced redox equation of the reaction is given below:
I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻The oxidizing agent is MnO₄ while the reducing agent is I⁻
In conclusion, a balanced redox equation is one in which the atoms and the change in oxidation state is equal on both sides of the reaction.
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if you had 5 moles of ethanol, how many grams of carbon dioxide would be produced?
The mass of carbon dioxide, CO₂ that would be produced from 5 moles of ethanol, C₂H₅OH is 440 g
How to determine the moles of carbon dioxide, CO₂ producedWe'll begin by calculating the moles of carbon dioxide, CO₂ produced. This can be obtained as follow:
C₂H₅OH + 3O₂ --> 2CO₂ + 3H₂O
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce 2 moles of CO₂
Therefore,
5 moles of C₂H₅OH will react to produce = 5 × 2 = 10 moles of CO₂
How to determine the mass of carbon dioxide, CO₂ producedThe mass of carbon dioxide, CO₂ produced from the reaction can be obtained as follow:
Mole of carbon dioxide, CO₂ = 10 molesMolar mass of carbon dioxide, CO₂ = 44 g/molMass of carbon dioxide, CO₂ =?Mole = mass / molar mass
10 = Mass of carbon dioxide, CO₂ / 44
Cross multiply
Mass of carbon dioxide, CO₂ = 10 × 44
Mass of carbon dioxide, CO₂ = 440 g
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When you balance the equation FeCl₃ + NH₄OH ---> Fe(OH)₃ + NH₄Cl, what is the coefficient of ammonium chloride?
4
1
3
2
Answer:
3
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of the reaction. You can change these amounts by adding coefficients.
The unbalanced equation:
FeCl₃ + NH₄OH ---> Fe(OH)₃ + NH₄Cl
Reactants: 1 iron, 3 chlorine, 1 nitrogen, 5 hydrogen, 1 oxygen
Products: 1 iron, 1 chlorine, 1 nitrogen, 7 hydrogen, 3 oxygen
The balanced equation:
FeCl₃ + 3 NH₄OH ---> Fe(OH)₃ + 3 NH₄Cl
Reactants: 1 iron, 3 chlorine, 3 nitrogen, 15 hydrogen, 3 oxygen
Products: 1 iron, 3 chlorine, 3 nitrogen, 15 hydrogen, 3 oxygen
Ammonium Chloride = NH₄Cl
Which organelle in the table is correctly matched with its function?
which one is it??
Answer:
[tex]\huge\boxed{\sf Ribosomes}[/tex]
Explanation:
Organelles and their function:Lysosomes:Lysosomes functions in the digestion of food of the cell.It contains hydrolytic enzymes.Vacuole:Vacuole mostly functions in storage.Mitochondrion:Mitochondrion is the power house of the cell.Ribosome:Ribosome functions in protein synthesis.[tex]\rule[225]{225}{2}[/tex]
What is the pressure in a 5.00 L tank with
7.10 moles of oxygen at 39.3 °C?
Answer:
36.4 atm
Explanation:
To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = constant (0.0821 L*atm/mol*K)
-----> T = temperature (K)
Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.
P = ? atm R = 0.0821 L*atm/mol*K
V = 5.00 L T = 393 °C + 273.15 = 312.45 K
n = 7.10 moles
PV = nRT
P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)
P(5.00 L) = 182.130
P = 36.4 atm
Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lithium found on the periodic table to determine which isotope is more abundance
The isotope that is more abundant, given the data is isotope Li7
AssumptionLet Li6 be isotope ALet Li7 be isotope BHow to determine whiche isotope is more abundantMolar mass of isotope A (Li6) = 6.02 uMolar mass of isotope B (Li7) = 7.02 uAtomic mass of lithium = 6.94 uAbundance of A = A%Abundance of B = (100 - A)%Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]
6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]
6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]
6.94 = [6.02A% + 702 - 7.02A%] / 100
Cross multiply
6.02A% + 702 - 7.02A% = 6.94 × 100
6.02A% + 702 - 7.02A% = 694
Collect like terms
6.02A% - 7.02A% = 694 - 702
-A% = -8
A% = 8%
Thus,
Abundance of B = (100 - A)%
Abundance of B = (100 - 8)%
Abundance of B = 92%
SUMMARY
Abundance of A (Li6) = 8%Abundance of B (Li7) = 92%From the above, isotope Li7 is more abundant.
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 what will happen to mangroves if nearby a coral reefs are destroyedSedimentation will occur in international zones instead of mangroves mangroves will improve without the filter ration that coral reefs provide mangrove receive less sunlight due to the increased true Bility in the water storm surges can just write mangroves along the coast line during storms
The thing that will happen to mangroves if nearby a coral reefs are destroyed is that:
Option C: Reefs will receive less sunlight due to increased turbidity in the water.How does the destruction of coral reefs occurs?The destruction that is known to have taken place in mangrove forests in the area of the coastal wetlands is known to be one that is highly depleting the amount of natural tannins in the water.
Due to the above, this is known to have subjected the close by coral reefs to have what we call an undue UV radiation. Its effect is that the reefs are said to be sunburned a lot and then the coral bleaching takes place.
Therefore, The thing that will happen to mangroves if nearby a coral reefs are destroyed is that Option C: Reefs will receive less sunlight due to increased turbidity in the water.
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A solution is prepared by mixing 200.0 g of water, H2O, and 300.0 g of
ethanol, C2H5OH. Determine the mole fractions of each substance.
Answer:
Mole Fraction (H₂O) = 0.6303
Mole Fraction (C₂H₅OH) = 0.3697
Explanation:
(Step 1)
Calculate the mole value of each substance using their molar masses.
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
200.0 g H₂O 1 mole
--------------------- x ------------------ = 11.10 moles H₂O
18.014 g
Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol
Molar Mass (C₂H₅OH): 46.068 g/mol
300.0 g C₂H₅OH 1 mole
---------------------------- x -------------------- = 6.512 moles C₂H₅OH
46.068 g
(Step 2)
Using the mole fraction ratio, calculate the mole fraction of each substance.
moles solute
Mole Fraction = ------------------------------------------------
moles solute + moles solvent
11.10 moles H₂O
Mole Fraction = -------------------------------------------------------------
11.10 moles H₂O + 6.512 moles C₂H₅OH
Mole Fraction (H₂O) = 0.6303
6.512 moles C₂H₅OH
Mole Fraction = -------------------------------------------------------------
11.10 moles H₂O + 6.512 moles C₂H₅OH
Mole Fraction (C₂H₅OH) = 0.3697
What would the hydroxide ion concentration be if the hydrogen ion concentration was 1 x 10-3 M?
Taking into account the definition of pH and pOH, the hydroxide ion concentration will be 1×10⁻¹¹ M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Hydroxide ion concentrationA solution had a hydrogen ion concentration of 1×10⁻³ M. In other words [H⁺]= 1×10⁻³ M.
Replacing in the definition of pH, it is calculated as:
pH= - log (1×10⁻³ M)
Solving;
pH= 3
Replacing in the relationship established between pH and pOH, the pOH can be calculated as:
pOH + 3= 14
Solving:
pOH= 14 - 3
pOH= 11
Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:
- log [OH⁻]= 11
Solving:
[OH⁻]= 10⁻¹¹
[OH⁻]= 1×10⁻¹¹ M
In summary, the hydroxide ion concentration will be 1×10⁻¹¹ M.
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Which of the following sublevels contains only orbitals that are shaped like bells?
6f
4d
3p
5s
The sublevels that contains only orbitals that are shaped like bells are the 3p. That is option C.
What are atomic orbitals?Atomic orbitals are defined as the mathematical terms that are used to describe the positions of electrons on the atoms.
Examples of sublevels of atomic orbitals are s, p, d, and f. The 3p are the only orbitals that are bell like in shape
Therefore, sublevels that contains only orbitals that are shaped like bells are the 3p.
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What two properties affect the
density of ocean water?
Answer: temperature and salinity.
Explanation:
If U-235 decays into Cs-135 and 4 neutrons, what other nuclide will be produced?
Fr-223
Pu-244
Ra-226
Rb-96
If U-235 decays into Cs-135 and 4 neutrons, the other nuclide that will be produced is Rb-96 (option D).
What is radioactive decay?A radioactive decay is the process by which an unstable large nuclei emit subatomic particles and disintegrate into one or more smaller nuclei.
According to this question, a radioactive material Uranium- 235 undergoes radioactive decay into Cs- 135 and 4 neutrons (1/0n).
This means that the mass of the products we have is 135 + 4 = 139.
The mass of the nuclide left must be 235 - 139 = 96, hence, the other nuclide that will be produced is Rb-96.
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58. Which of the following aqueous solutions has the lowest freezing point? A. 0.2 M NaCl B. 0.2 M FeCl3 C. 0.2M sucros D. 0.2 M CaCl2
The correct option is D. 0.2 M CaCl2 is has the lowest freezing point.
What is aqueous solution?When one significance liquefies into another, a solution is formed. A solution is a homogenous mixture consisting of a solute dissolved into a solvent. The solute is the essence that is being dissolved, while the solvent is the dissolving medium. Solutions can be formed with multiple different classifications and forms of solutes and solvents. In this branch, we will focus on a resolution where the solvent is water.
An aqueous solution is a moisture that contains one or more dissolved essence. The dissolved importance in an aqueous solution may be solids, gases, or different liquids.In directive to be a true solution, an assortment must be stable. When sugar is fully dissolved into moisture, it can stand for an undetermined amount of time, and the sugar will not recompense out of the solution. Further, if the sugar-water solution is passed through a filter, it will stay with the water. This is because the liquefied particles in a resolution are very small, usually less than 1nm in diameter. Solute particles can be atoms, ions, or molecules, counting on the type of essence that has been dissolved.To learn more about aqueous solution, refer to:
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why second ionization energy of second group elements is lower than alkali metals.
Answer:
The removal of second electron from alkaline earth metals leads to the stable octet state in M2+ ions. In case of alkali metals it is not so. Since the removal of electron leads to stability, hence it can easily removed leading to lowering of second ionization enthalpy in alkaline earth metals.
Explanation:
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The value of the entropy change for the process N₂ (g) + 3H₂ (g) --> 2NH₃ (g) is ________.
negative
positive
unchanged
zero
The entropy change will be negative because the number of particles in the system decreased from left to right.
What is the entropy change?The term entropy refers to the degree of disorder in a system. We know that the production of gases would lead to an increase in the entropy of the system.
Now given the equation; N₂ (g) + 3H₂ (g) --> 2NH₃ (g), the entropy change will be negative because the number of particles in the system decreased from left to right.
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Which equation obeys the law of conservation of mass? H2(g) + O2(g) → H2O(g)
H2(g) + O2(g) → H2O(g) +4He(g)
2H2(g) + O2(g) → 2H2O(g)
H2(g) → H2O(g)
H2(g) + O2(g) → 2H2O(g)
Answer:
2H2(g) + O2 -> 2H2O
Explanation:
According to the law of conservation of mass, mass cannot be created nor destroyed in a chemical formula.
The only chemical reaction of the five options that follows this law is
2H2(g) + O2 -> 2H2O because the mass of the compounds stays the same before the reaction (arrow) and after.
Before reaction (reactants) we have:
2 (H2) = 4H
1 (O2) = 2O
After reaction takes place (products) we have:
2 (H2O) = 4H and 2O
and so mass is conserved.
Answer: its the 3rd option
Explanation: on edge hope this helps
Which of the following rules is applicable for balancing a chemical equation?
Change only the coefficients
Add the coefficients and change the subscripts
Change only the subscripts
Change the coefficients and the subscripts
Answer:
A.) Change only the coefficients
Explanation:
An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.
The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.
Question 6
To what temperature must 15 L of oxygen gas at -30°C be heated at 1 atm pressure in order to occupy a
volume of 23 L, assuming that the pressure increases by 58 mm Hg?
unit:
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Question 7
0/1 pt10 Deta
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1/1 pt Details
Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law states that the multiplication of pressure by volume is constant:
P×V=k
Charles's lawCharles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles' law states that the ratio of volume to temperature is constant:
[tex]\frac{V}{T} =k[/tex]
Gay-Lussac's lawGay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.
Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:
[tex]\frac{P}{T} =k[/tex]
Combined law equationCombined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{PxV}{T} =k[/tex]
Considering an initial state 1 and a final state 2, it is fulfilled:
[tex]\frac{P1xV1}{T1} =\frac{P2xV2}{T2}[/tex]
New temperatureIn this case, you know:
P1= 1 atm= 760 mmHgV1= 15 LT1= -30 °C= 243 K (being 0 °C= 273 K)P2= 58 mmHgV2= 23 LT2= ?Replacing in the combined law equation:
[tex]\frac{760 mmHgx15 L}{243 K} =\frac{58 mmHgx23 L}{T2}[/tex]
Solving:
[tex]T2x\frac{760 mmHgx15 L}{243 K} =58 mmHgx23 L[/tex]
[tex]T2 =\frac{58 mmHgx23 L}{\frac{760 mmHgx15 L}{243 K}}[/tex]
T2= 28.44 K= -244.56 °C
Finally, the new temperature is -244.56 °C or 28.44 K.
Learn more about combined law equation:
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An ideal gas in a closed container initially has a volume V and Temperature T the final tempera is 5/4T and the final pressure is 2P what is the final gas
Answer:
[tex]V_2 = \frac{5V}{8}[/tex]
Explanation:
I am assuming you are saying what is the final volume of the gas
Known :
Initial volume (V1) = V
Initial temperature (T1) = T
Final temperature (T2) = 5/4 T
Initial pressure (P1) = P
Final pressure (P2) = 2P
Wanted: Final volume (V2)
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{PV}{T} = \frac{(2P)V_2}{(5/4)T}\\\frac{V}{1} = \frac{(2)V_2}{5/4}\\5/4V = 2V_2\\\\V_2 = \frac{5V}{8}[/tex]