We have evaluated the logarithmic expressions log3 (1/81), log7(√7), and log5(0.2) and simplified our answers completely. Logarithmic expressions often arise in mathematical modeling and can be used to solve equations that involve exponential growth or decay. They have numerous applications in fields such as finance, engineering, and physics.
(a) To evaluate the expression log3 (1/81), we need to find the exponent to which we must raise 3 to obtain 1/81. In other words, we are solving the equation 3^x = 1/81. We know that 1/81 is the same as 3^-4, so we can write 3^x = 3^-4. Therefore, x = -4. Hence, log3 (1/81) = -4.
(b) To evaluate the expression log7(√7), we need to find the exponent to which we must raise 7 to obtain √7. In other words, we are solving the equation 7^x = √7. We can rewrite √7 as 7^(1/2), so we have 7^x = 7^(1/2). Therefore, x = 1/2. Hence, log7(√7) = 1/2.
(c) To evaluate the expression log5(0.2), we need to find the exponent to which we must raise 5 to obtain 0.2. In other words, we are solving the equation 5^x = 0.2. We can rewrite 0.2 as 1/5, so we have 5^x = 1/5. Therefore, x = -1. Hence, log5(0.2) = -1.
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(a)log3 (1/81) = -4
(b)log7(√7) = 1/2
(c)log5(0.2) =-1
(a) log3 (1/81)
To evaluate this expression, we need to find the exponent that 3 needs to be raised to in order to get 1/81. Since 81 = 3^4, we have 1/81 = 3^(-4). Therefore, log3 (1/81) = -4.
(b) log7(√7)
To evaluate this expression, we need to find the exponent that 7 needs to be raised to in order to get √7. Since √7 = 7^(1/2), we have log7(√7) = 1/2.
(c) log5(0.2)
To evaluate this expression, we need to find the exponent that 5 needs to be raised to in order to get 0.2. Since 0.2 = 1/5 and 1/5 = 5^(-1), we have log5(0.2) = -1.
So, the answers are:
(a) -4
(b) 1/2
(c) -1
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Systematic random sampling has become a popular method of drawing samples in research practices because _____.
it is a relatively easy way to draw a sample while ensuring randomness is the answer.
Systematic sampling is a probabilistic sampling method in which a researcher selects members of a population at regular intervals. For example, select every 15 people from the list of populations. If the population is in random order, this can mimic the benefits of a simple random sample.
These are generally preferred by researchers because they are easy to implement and understand. The important assumption that the results represent the majority of the normal population ensures that the entire population is sampled equally. The process also provides a higher level of control for systematic sampling compared to other sampling methods. systematic sampling also has a lower risk factor because the data is unlikely to be contaminated.
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The elimination method is ideal for solving this system of equations. By which number must you multiply the second equation to eliminate the
y-varlable, and what is the solution for this system?
x+3y=42
2x-y=1
=======================================================
Explanation:
The 3y in the first equation must add to -3y so the y terms go away. We have -y in the second equation, which is why we triple everything in that equation
2x-y = 1 becomes 6x - 3y = 3 after tripling everything. This is the same as multiplying both sides by 3.
This is the updated equivalent system
[tex]\begin{cases}x+3y = 42\\6x-3y = 3\end{cases}[/tex]
Add the terms straight down
x+6x becomes 7x3y+(-3y) becomes 0y or 0. The y variables are eliminated.The right hand sides 42 and 3 add to 45We have the equation 7x = 45 which solves to x = 45/7.
Unfortunately it doesn't turn into a nice single whole number because 45 isn't a multiple of 7. So I would leave it as a fraction.
Optionally you could note that 45/7 = 6.42857 approximately. But I prefer the fraction form since it's most exact.
--------------
Use this x value to find y. Pick any equation involving x and y. Plug in that x value and solve for y.
x + 3y = 42
45/7 + 3y = 42
3y = 42 - 45/7
3y = 42*(7/7) - 45/7
3y = 294/7 - 45/7
3y = (294 - 45)/7
3y = 249/7
y = (249/7)*(1/3)
y = 83/7
Like with x, we also don't get a nice whole number.
I used WolframAlpha to confirm the solutions. GeoGebra is another tool you could use.
The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ?
Answer:
The prime factors of 13195 are 5, 7, 13 and 29. The largest prime factor of the number 600851475143 is 6857
PLEASE HELP IM SERIOUSLY STUCK E
Answer: 2.12 × [tex]10^{-3}[/tex]
The coefficient (in green) will be 2.12
Step-by-step explanation:
Scientific notation is written by multiplying the number by a power of 10. This number is a number between 1 and 10.
Since this is a smaller number, we will be multiplying it by a power of 10 to a negative number.
To get this value to a number between 1 and 10, we must multiply it by 10 3 times (also shown as 10³) which gives us 2.12.
To get back to the original value, we multiply this by [tex]10^{-3}[/tex]. This gives us our answer.
Please solve for X: 11/2-x = 1/3 + 1/6
Answer: 5
Step-by-step explanation:
11/2-x = 1/3 + 1/6
-x+11/2 = 1/2
- 11/2 - 11/2
-x = -5
Divide -1 by both sides
And it gives you the answer 5.
A lifeguard sitting in a tower 10ft off the ground spots swimmer in trouble at a 55 angle of depression. If the lifeguard tosses a ring in a 15ft rope to the swimmer, can the ring reach the swimmer? Finish solving the problem below to determine your answer
Based on the given parameters, the 15 ft rope will reach the swimmer
How to determine if the ring reach the swimmer?From the question, we have the following equation:
sin 55 = 10/x
Multiply both sides of the equation by x
x * sin 55 = 10/x * x
Evaluate the product
x * sin 55 = 10
Divide both sides by sin 55
x = 10/sin 55
Evaluate sin 55
x = 10/0.8192
Evaluate the quotient
x = 12.21
From the question, the lifeguard tosses a ring in a 15ft rope to the swimmer
15 is greater than 12.21
This means that the 15 ft rope will reach the swimmer
Hence, the 15 ft rope will reach the swimmer
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Help solve these (find the slope of each line) 8 problems don’t just give the answer show your work please
Answer:
Khan Academy.
Step-by-step explanation:
You can go on khan academy and search up "area and graphs." The videos should immediately pop up. there are also lessons if you don't want to risk getting your problem wrong. If you are still confused and do not understand please just comment and I will respond.
Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm pretty good at it: If I shoot $5$ pieces of paper at the recycling bin, at least one of them will make it inside the recycling bin with probability $\frac{211}{243}$. If I shoot $6$ pieces of paper at the recycling bin, what's the probability at least two of them make it inside the recycling bin
Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.With 5 shoots, the probability of making at least one is [tex]\frac{211}{243}[/tex], hence the probability of making none, P(X = 0), is [tex]\frac{232}{243}[/tex], hence:
[tex](1 - p)^5 = \frac{232}{243}[/tex]
[tex]\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}[/tex]
1 - p = 0.9908
p = 0.0092
Then, with 6 shoots, the parameters are:
n = 6, p = 0.0092.
The probability that at least two of them make it inside the recycling bin is:
[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]
In which:
[P(X < 2) = P(X = 0) + P(X = 1)
Then:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461[/tex]
[tex]P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527[/tex]
Then:
P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988
[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012[/tex]
0.0012 = 0.12% probability at least two of them make it inside the recycling bin.
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On the 405 freeway one can travel 65 miles per hour (mph), how many kilometers per hour (kph) is the car travelling
Answer:
104.607kph
Step-by-step explanation:
Conversion from mph to kph = 1.609mph
The volume of the cylindrical water tank shown below is 490π feet^3. If the tank is 10 feet high, what does its radius r equal?
The cylindrical water tank with a volume of 490π feet³, and a height of 10 feet, has a radius of 7 feet.
The volume of a cylinder having a radius of r units, and a height of h units, is given by the formula, V = πr²h.
In the question, we are asked to find the radius (r), of a cylindrical water tank, with a volume of 490π feet³, and a height of 10 feet.
Substituting the value of V = 490π feet³, and h = 10 feet, in the formula for the volume of a cylinder, V = πr²h, we get:
490π feet³ = π.(r²)(10 feet).
Rearranging this, we can write:
r² = (490π)/(10π) feet²,
or, r² = 49 feet²,
or, r = √49 feet,
or, r = 7 feet.
Thus, the cylindrical water tank with a volume of 490π feet³, and a height of 10 feet, has a radius of 7 feet.
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Let your dependent variable in the function be y. Write the function that models the independent variable in terms of y, using logarithms.
Function: [tex]f(x)=2.56(1.04)^x[/tex]
The function that models the independent variable, x, in terms of y, is:
[tex]x = ln(\frac{y}{2.56})/ln(1.04)[/tex]
How to write the independent variable in terms of y?
Here we have the relation:
[tex]y = 2.56*(1.04)^x[/tex]
We want to write x in terms of y, so we just need to isolate x.
We have:
[tex]\frac{y}{2.56} = (1.04)^x[/tex]
Now we can apply the natural logarithm in both sides, so we get:
[tex]ln(\frac{y}{2.56}) = ln((1.04)^x)\\\\ln(\frac{y}{2.56}) = ln((1.04))*x[/tex]
Now we can just isolate x.
[tex]x = ln(\frac{y}{2.56})/ln(1.04)[/tex]
That is the function that models the independent variable, x, in terms of y.
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What is the logarithmic form of 13^2=169
The logarithmic form of 13^2=169 is [tex]\log_{13}(169) = 2[/tex]
How to determine the logarithmic form?The equation is given as
13^2=169
Take the logarithm of both sides
log(13^2) = log(169)
This gives
2log(13) = log(169)
Divide both sides by log(13)
[tex]\log_{13}(169) = 2[/tex]
Hence, the logarithmic form of 13^2=169 is [tex]\log_{13}(169) = 2[/tex]
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In your rectangular backyard, you know the width of the yard is three less than four times the length. If the perimeter of your yard is 24 yards, what is the width?
Answer: 9 yards
Step-by-step explanation:
Let's make equations to represent each situation.
The first equation says that the width is 3 less than 4 times the length, so let's put that into an equation:
[tex]w=4l-3[/tex]
Next, we can use the perimeter equation that [tex]P=2l+2w[/tex]. Since we know the perimeter is 24 yards, we can replace it for P.
[tex]24=2l+2w[/tex]
Now that we have two equations with two variables, we can use either elimination or substitution to solve them. Since w is already solved for in the first equation, let's plug it in the second equation.
[tex]24=2l+2(4l-3)\\ 12=l+4l-3\\ 12=5l-3\\ 15=5l\\ l=3[/tex]
Now, let's put l back into the first equation to solve for w.
[tex]w=4(3)-3\\ w=12-3\\ w=9[/tex]
The width is 9 yards
Kiran is driving on a long road trip. he currently has 13 gallons of gas in his car. each hour that he drives, his car uses up 2 gallons of gas. how much gas would be in the tank after driving for 5 hours? how much gas would be left after t t hours?
Step-by-step explanation:
"t t hours" ????
you mean 11 hours ?
13 gallons now.
2 gallons are used (and therefore disappear from the tank) per hour.
so, in 5 hours 5×2 = 10 gallons will be used.
that leaves 13 - 10 = 3 gallons in the tank.
in 11 hours 11×2 = 22 gallons would have been used.
but there are only 13 gallons in the tank.
so, if he does not fill up, he will have 0 gallons left after 11 hours. in fact, already after 13/2 = 6.5 hours.
the point :
when you use 2 gallons per hour, that means in t hours you are using t × 2 or 2t gallons.
i need help with this page
Step-by-step explanation:
what is not clear that you cannot answer this by yourself ?
please let me know what you need explained.
1. Rhombus
2. rectangle
3. square
4. rhombus
5. square
6. rectangle
7. rhombus
8. parallelogram
Area=
Help me please asap thanks
Answer:
10 unit^2.
Step-by-step explanation:
The base of the triangle (CE)
= 6 - 2 = 4 units
The height = 5
Area = 1/2 * 4 * 5
= 10 unit^2.
Answer:
10
Step-by-step explanation:
area = hight ×base÷2
hight = 5-0
= 5
base = 6-2
= 4
area = 4×5÷2
=10
Write an equation of a line in slope intercept form going through the points (1,6) and (3,0)
Answer:
y = -3x + 9
Step-by-step explanation:
The slope is
[tex] \frac{6 - 0}{1 - 3} = - 3[/tex]
Substituting into point-slope form, we get
y = -3(x-3)
y = -3x + 9
Can someone help me
Answer: Choice B
All real numbers except 2 and 5
===========================================================
Explanation:
Factor the denominator. We need to find two numbers that multiply to 10 and add to -7.
Through trial and error, those two numbers are -2 and -5
-2 times -5 = 10
-2 plus -5 = -7
This means the denominator [tex]\text{x}^2 - 7\text{x} + 10[/tex] factors to [tex](\text{x}-2)(\text{x}-5)[/tex]. You can use the FOIL rule to confirm this.
Then each piece is set equal to zero to solve for x
x-2 = 0 leads to x = 2
x-5 = 0 leads to x = 5
------------
In short, if x = 2 or x = 5, then it causes the the denominator [tex]\text{x}^2 -7\text{x}+10[/tex] to turn into 0.
Dividing by 0 is not allowed; therefore, x = 2 nor x = 5 is allowed in the domain. Any other x value is valid.
A fair die is tossed 5 times. Let $\dfrac{m}{n}$ be the probability that at least two consecutive tosses have the same number, where $m$ and $n$ are relatively prime positive integers. Find $m$.
The probability that no two consecutive heads will occur is 13/32.
What is probability?It should be noted that probability simply means the likelihood of the occurence of an event based on chance.
In this case, the fair coin is tossed 5 times and we simony want it find the probability that no two consecutive heads will occur.
This will be:
Let n be the number of strings of h
Let t be the length n with two adjacent H's.
Therefore, the probability will be:
= (8+5)/2^5
= 13/32
In conclusion, the probability that no two consecutive heads will occur is 13/32.
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Solve the following linear system algebraically. State why you chose the method you used.
x + 3y = 7
2x + 4y = 11
There are two methods of solving systems of equations:
substitutioneliminationSubstitution is where we substitute one equation into the other by isolating a certain variable, or a group of terms.
Elimination is where we subtract the two equations. Before doing this, we may have to multiply one equation by a certain number to make sure one variable cancels out.
Solving the QuestionWe're given the following equations:
[tex]x + 3y = 7[/tex][tex]2x + 4y = 11[/tex]Because they are organized in the same manner (i.e. x [operation] y [equals] number), it is easier for us to use elimination.
First, multiply the first equation by 2:
[tex]x + 3y = 7\\2(x + 3y) = 2(7)\\2x + 6y = 14[/tex]
Now, subtract the second equation from the one we just created:
[tex]\hspace{10}2x + 6y = 14\\-2x + 4y = 11\\\rule{67}{0.3}\\2y=3[/tex]
Solve for y:
[tex]y=\dfrac{3}{2}[/tex]
To solve for x, we can use substitution in the first equation:
[tex]x + 3y = 7\\\\x + 3(\dfrac{3}{2}) = 7\\\\x + \dfrac{9}{2} = 7\\\\x = 7- \dfrac{9}{2}\\\\x = 7- 4.5\\\\x = 2.5\\\\x=\dfrac{5}{2}[/tex]
Answer[tex]x=\dfrac{5}{2}[/tex]
[tex]y=\dfrac{3}{2}[/tex]
What is the reason for statement 7 in the given proof?
A) definition of midpoint
B) definition of slope
C) parallel lines have equal slopes.
D) using point-slope formula
Answer: definition of slope
Step-by-step explanation:
The results in step 7 come from substituting the coordinates into the slope formula.
In the given circle the m∠DFB is 41°, mArc EF is 52° what is the m∠C ?
Check the picture below.
The requried measure of the angle m∠C in the given circle is 15°.
In the given circle the m∠DFB is 41°, mArc EF is 52°
To find out the measure of the angle m∠C.
Following the properties of arcs in the circle,
arc BD = 2m∠BFD
arc BD=2*41 = 82
Now we know that,
The angle subtended by two sectants drawn from the single point that lies outside the circle is given by the difference in larger and minor arcs divided by 2.
∠c= BD- EF / 2
∠c = 82°-52°/2
∠c = 15°
Thus, the requried measure of the angle m∠C in the given circle is 15°.
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Given: AD BC and ZBCD ZADC
Prove: DE CE
D
Assemble the proof by dragging tiles to
the Statements and Reasons columns.
Intro
Angles Segments Triangles Statements Reasons
ZADC
ZDEA
Statements
ZECD
ZBCD
ZEDC
ZCBE
Reasons
ZCEB
ZDAE
The proofing of the triangle is illustrated below.
How to illustrate the triangle?Based on the information, the reflexive property of equality states that an angle or shape is always congruent to itself.
The alternate interior angle theorem is that when two parallel lines are cut by a transversal, then the alternate interior angles are the same.
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Answer:
answer in picture
Step-by-step explanation:
Solve m=10x−x for x.
Answer:
x=m/9
Steps:
m=9x
m/9=x
x=m/9
Is there a way to find the intersections only by the equations?
I just know how to find the intersections by graphing them.
Answer:
see explanation
Step-by-step explanation:
to find the intersection equate g(x) and h(x) , that is
(x + 7)(x - 5) = x - 5 ← expand left side using FOIL
x² + 2x - 35 = x - 5 ( subtract x - 5 from both sides )
x² + x - 30 = 0 ← in standard quadratic form
(x + 6)(x - 5) = 0 ← in factored form
equate each factor to zero and solve for x
x + 6 = 0 ⇒ x = - 6
x - 5 = 0 ⇒ x = 5
substitute these values into either g(x) or h(x) for corresponding values of y
substituting into h(x)
h(- 6) = - 6 - 5 = - 11 ⇒ (- 6, - 11 )
h(5) = 5 - 5 = 0 ⇒ (5, 0 )
Which of the following sets is equal to {1, 2, 3, ...}?
{x | x R, x ≥ 1}
{x | x R, x > 1}
{x | x N, x ≥ 1}
From the list of options, the set that is equal to the set {1, 2, 3, ...} is {x | x N, x ≥ 1}
How to determine the set?The set is given as:
{1, 2, 3, ...}
The three dots (...) after 3 implies that the elements of the set include other values such as 4, 5, 6 and so on
Using the above scenario, we can see that the set {1, 2, 3, ...} contains only positive integers.
All positive integers are natural numbers and they are denoted by N
From the list of options, we have:
{x | x R, x ≥ 1}
This represents the set of all real numbers greater than or equal to 1.
Note that this set includes decimal numbers i.e. 1, 1.5, 1.89 and so on
This does not represent the set {1, 2, 3, ...}
{x | x R, x > 1}
This represents the set of all real numbers greater than 1.
Note that this set includes decimal numbers i.e. 1.5, 1.89 and so on
This does not represent the set {1, 2, 3, ...}
{x | x N, x ≥ 1}
This represents the set of all natural numbers greater than or equal to 1.
Note that this set does not include decimal numbers i.e. 1, 2, 3, 4 and so on
This does represent the set {1, 2, 3, ...}
Hence, the set that is equal to the set {1, 2, 3, ...} is {x | x N, x ≥ 1}
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M<2=7x+,m<3=4y,and m<4=122 , find the values of x and y.
The values of x and y in the equation are 15 and 28 respectively
How to find the variables in an equation?Let's find the x and y values in the equation,
m = 7x + 7
m = 4y
m = 112
Therefore,
4y = 7x + 7
4y - 7x = 7
4y = 112
y = 112 / 4
y = 28
Therefore,
4(28) - 7x = 7
112 - 7x = 7
112 - 7 = 7x
105 = 7x
x = 105 / 7
x = 15
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Write the quotient in scientific notation and in
standard form.
(3.64 x 10000000) (2.6 x 10000)
Answer:
3.64 × 10(raised to the power 7)
2.6 × 10⁴
In which quadrant is the point ( - 2, 3) located?
O Quadrant II
Quadrant III
O Quadrant I
O Quadrant IV
ANSWER:
Quadrant ll
________________________________
________________________________HOPE IT HELPS
Can someone please help me
Answer:
Right option is B.
Step-by-step explanation:
[tex] \sf \longrightarrow \frac{ \sec x \sin( - x) + \tan( - x) }{1 + \sec( - x) } \\ \\ \sf \longrightarrow \frac{ \sec x( - \sin x) - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \frac{1}{ \cos x } \times \sin x - \tan x }{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \tan x - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - 2 \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{1 + \frac{1}{ \cos x} } \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} } \\ \\ \boxed{ \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1} }}[/tex]