find the expected value of a random variable with the following probability distribution :
2
3
4
5
6
7
8
9
10
11
12
———
1/36
1/18
1/12
1/9
5/36
1/6
5/36
1/9
1/12
1/18
1/36
Answers
Answer:
7
Step-by-step explanation:
correct with acellus
The expected value of a random variable with the following probability distribution will be 7.
How to calculate the expectation of a discrete random variable?Expectation can be taken as a weighted mean, weights being the probability of occurrence of that specific observation.
Thus, if the random variable is X, and its probability mass function is given being f(x) = P(X = x), then we have:
[tex]E(X) = \sum_{i=1}^n( f(x_i) \times x_i)[/tex]
[tex]\rm E(X)=2 \times \frac{1}{36} +3 \times \frac{1}{28} +4 \times \frac{1}{12} +5 \times \frac{1}{9} +6 \times \frac{5}{36} + 7 \times \frac{1}{6} +8 \times \frac{5}{36}+9 \times \frac{1}{9} +10 \times \frac{1}{12} +11 \times \frac{1}{18} +12 \times \frac{1}{36} \\\\ E(X)=7[/tex]
Hence the expected value of a random variable will be 7.
To learn more about the expected value refer to the link:
https://brainly.com/question/4515179
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