Answer:
The answer is 2 : 3.
Step-by-step explanation:
First, you have to convert the units to minutes :
1 hr = 60 min
1/2 hr = 60 × 1/2 = 30 min
Then, you have to simplify the ratio to simplest form :
30 : 45
= (30÷15) : (45÷15)
= 2 : 3
Answer:
To see the ratio, we should have both in the same unit. We can pass 1/2 hour to minutes, as we know one hour are 60 minutes:
60/2 = 30
So we know half hour are 30 minutes.
Now, we know the ratio 30:45, but we can simplify it, as a fraction.
To simplify it, we will divide both numbers by the same quantity, in this case, divide 30 and 45 by 15 (a it's a divisor):
30/15 = 2 and 45/15 = 3, so the ratio is 30:45, which is equivalent to 2:3
Solve The Equation !
‐5x – 3 < 2x – 18
Answer:
x>15/7
Step-by-step explanation:
Can anyone help with this it is for Geometry
Answer:
three angle one slide
Step-by-step explanation:
LOTS OF POINTS plz help due today!!!!!
Answer:
what numbers do you need answering??
Step-by-step explanation:
The answer to a subtraction problem
Answer:
The answer in a subtraction problem is called the difference.
Step-by-step explanation:
Hi there!
The answer to a subtraction problem is called rest or difference while the top thats being subtracted is called the minuend and the middle one is called the subtrahend.
1/ The Hotel is 163 miles from your house.your car travels 10.5 miles for every litre of petrol. Work out approximately how many litres of petrol the journey will use.
2/The price of petrol is 138.9 pence per litre Work out the approximate cost for the petrol to the hotel .
3/ you expect to travel 50 miles in each hour of a jurney how long the whole journey should take
please help.
Answer:
1. The journey will use 15.52 liters of petrol.
2. The approximate cost of petrol to hotel will be 2155.73 pence
3. The whole journey will take 3.36 hours
Step-by-step explanation:
Given that:
Distance of hotel from house = 163 miles
Distance covered by per liter = 10.5 miles
1/ The Hotel is 163 miles from your house.your car travels 10.5 miles for every litre of petrol. Work out approximately how many litres of petrol the journey will use.
Petrol used for total distance = [tex]\frac{Total\ distance}{Distance\ per\ liter}[/tex]
Petrol used for total distance = [tex]\frac{163}{10.5}=15.52\ liters[/tex]
The journey will use 15.52 liters of petrol.
2/The price of petrol is 138.9 pence per litre Work out the approximate cost for the petrol to the hotel .
Cost of per liter petrol = 138.9 pence
Cost for petrol to hotel = Petrol used for journey * Price per liter
Cost of petrol = 138.9 * 15.52 = 2155.73 pence
The approximate cost of petrol to hotel will be 2155.73 pence
3/ you expect to travel 50 miles in each hour of a jurney how long the whole journey should take.
Distance covered per hour = 50 miles
Time taken in whole journey = [tex]\frac{total\ distance}{distance\ per\ hour}[/tex]
Time taken in whole journey = [tex]\frac{168}{50}[/tex]
Time taken in whole journey = 3.36 hours
The whole journey will take 3.36 hours
Hence,
1. The journey will use 15.52 liters of petrol.
2. The approximate cost of petrol to hotel will be 2155.73 pence
3. The whole journey will take 3.36 hours
Estimate the quotient for:
4,819÷68
Answer:
≈ 70.87 (rounded to the nearest hundredth)
Step-by-step explanation:
-When you do 4,819 ÷ 68, you’ll get:
70.867647058....
-So, just round it to the nearest hundredth:
70.87
In triangle $XYZ,$ $\angle Y = 45^\circ$ and $\angle Z = 60^\circ.$ If $XZ = 4,$ then what is $XY$?
[asy]
unitsize(3 cm);
pair X, Y, Z;
X = (0,1);
Y = (-1,0);
Z = (1/sqrt(3),0);
draw(X--Y--Z--cycle);
label("$45^\circ$", Y + (0.3,0.1), fontsize(10));
label("$60^\circ$", Z + (-0.2,0.1), fontsize(10));
label("$X$", X, N);
label("$Y$", Y, SW);
label("$Z$", Z, SE);
label("$4$", (X + Z)/2, NE);
[/asy]
Answer:
[tex]XY = 4.9[/tex]
Step-by-step explanation:
[tex]\angle Y = 45^\circ[/tex]
[tex]\angle Z = 60^\circ[/tex]
[tex]XZ = 4[/tex]
Required
Determine the length of XY?
This question is supported with the attachment.
To solve for the length of XY, we make use of the sine law which states:
[tex]\frac{sin\ A}{a} = \frac{sin\ B}{b} = \frac{sin\ C}{c}[/tex]
In this case:
[tex]\frac{sin\ \angle Y}{XZ} = \frac{sin\ \angle Z}{XY} = \frac{sin\ X}{YZ}[/tex]
Substitute in, the following values:
[tex]\angle Y = 45^\circ[/tex]
[tex]\angle Z = 60^\circ[/tex]
[tex]XZ = 4[/tex]
The expression becomes:
[tex]\frac{sin\ 45}{4} = \frac{sin\ 60}{XY}[/tex]
Cross multiply
[tex]XY * \sin\ 45 = 4 * \sin\ 60[/tex]
Make XY the subject
[tex]\frac{XY * \sin\ 45}{\sin\ 45} = \frac{4 * \sin\ 60}{\sin\ 45}[/tex]
[tex]XY = \frac{4 * \sin\ 60}{\sin\ 45}[/tex]
[tex]XY = \frac{4 * 0.8660}{0.7071}[/tex]
[tex]XY = \frac{3.4640}{0.7071}[/tex]
[tex]XY = 4.89888276057[/tex]
[tex]XY = 4.9[/tex] --- approximated
Answer:
XY = 4.9
Step-by-step explanation:
A person places $6860 in an investment account earning an annual rate of 2.9%, compounded continuously. Using the formula
V
=
P
e
r
t
V=Pe
rt
, where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 11 years.
9514 1404 393
Answer:
$9,437.65
Step-by-step explanation:
Fill in the given numbers and do the arithmetic.
[tex]V=Pe^{rt}\\\\V=\$6860\cdot e^{0.029\cdot 11}=\$6860\cdot 1.375751\\\\\boxed{V=\$9{,}437.65}[/tex]
5) A student answered 81 problems on a test correctly and received a grade 90%.
How many problems were on the test, if all the problems were worth the same
number of points?
Answer:
90
Step-by-step explanation:
81/x=90/100
8100=90x
90=x
The total number of problems given in exam was 90.
PercentageWhat is percentage?Percentage, which is a relative figure used to denote hundredths of any quantity. One percent (symbolised as 1%) is equal to 100 parts; hence, 100 percent denotes the complete amount, and 200 percent designates double the amount specified.
How to calculate percentage?Divide one number by the other, then multiply the result by 100 to get the percentage of the two numbers.
Calculation for the total number of question given:A student correctly answered 81 problems.
Grade received by student is 90%
Let the total number of question given in the test be 'x'.
Thus,
90% of x = 81
(90/100)x = 81
x = (81×100)/90
x = 90
Therefore, the total number of question allotted to the student is 90.
To know more about how to conver percent to fraction?, here
https://brainly.com/question/317717
#SPJ2
Depreciation is the decrease or loss in value of an item due to age, wear, or market conditions. We usually consider depreciation on expensive items like cars. Businesses use depreciation as a loss when calculating their income and taxes. One company buys a new bulldozer for $109600. The company depreciates the bulldozer linearly over its useful life of 16 years. Its salvage value at the end of 16 years is $17600. A) Express the value of the bulldozer, V, as a function of how many years old it is, t. Make sure to use function notation. B) The value of the bulldozer after 7 years is $
Answer:
a. V = $109,600 - $5,750(t)
b. $69,350
Step-by-step explanation:
a. The expression of the value of the bulldozer is as follows
V = $109,600 - (m) × (t)
where,
m = depreciation
t = time in years
Now the equation would be
$109,600 - 16(m) = $17,600
m = ($109,600 - $17,600) ÷ (16)
= $5,750
Now the expression would be
V = $109,600 - $5,750(t)
b. Now the value of the bulldozer is
= $109,600 - $5,750 × 7 years
= $109,600 - $40,250
= $69,350
what is equivalent to 1/2 (2x + 7)
Asap, show the shaded area of the graf of lines 7x+10y=70, x-2y=0, 2x+y=0...
Answer:
The answer is i have no clue
The inter quartile range of a distribution is 7. If the 25th percentile is 16. Find the upper quartile
Given:
Inter quartile range(IQR) of a distribution = 7
25th percentile = 16
To find:
The upper quartile.
Solution:
We have,
IQR = 7
25th percentile = lower quartile = 16
We know that,
IQR = Upper quartile - Lower quartile
Let the upper quartile be [tex]Q_3[/tex].
Using the above formula, we get
[tex]7=Q_3-16[/tex]
Adding 16 on both sides, we get
[tex]7+16=Q_3-16+16[/tex]
[tex]23=Q_3[/tex]
Therefore, the upper quartile of the distribution is 23.
What is a equivalent expression for 10(y² + 2.45)
Answer:
10y²+24.5
Step-by-step explanation:
distribute.
10y²+24.5
Hope this helps plz hit the crown :D
The equivalent expression for the given expression is 10y²+24.5.
The given expression is 10(y² + 2.45).
What is an equivalent expression?Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.
The equivalent expression is
10(y² + 2.45)
=10y²+24.5
Therefore, the equivalent expression for the given expression is 10y²+24.5.
To learn more about an equivalent expression visit:
https://brainly.com/question/28170201.
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what's a slop in math
Answer:
Its the division of x axis divided by y axis
Answer:
The slope of the line is a measure of its steepness. You can find it with rise/run. The formula for slope is m=y2-y1/x2/x1
At a concert, the band has 18 men's T-shirts and 16 women's T-shirts. The band wants to set up tables to sell the shirts, with an equal number of men's and women's shirts available at each table and no shirts left over. What is the greatest number of tables the band can sell shirts from?
Tom got on a scale while on a vacation in France and noticed he weighed 75 kg. He read in a guidebook that 1 lb. = 0.45 kg. How much does Tom weigh in pounds
Answer:
166.67 pounds
Step-by-step explanation:
Set up a proportion where x is Tom's weight in pounds:
[tex]\frac{75}{x}[/tex] = [tex]\frac{0.45}{1}[/tex]
Cross multiply and solve for x:
75 = 0.45x
166.67 = x
So, Tom weighs approximately 166.67 pounds
The ratio of teachers needs to be 1:30. If there were 120 students, how many teachers would be needed?
Answer:
4:120
Step-by-step explanation:
for 120 student they would be 4 teacher needed per 30 student
4:120
There are 60 seconds in a minute use a tape diagram to find the total number of seconds in 5 minutes and 45 seconds
60 x 5 + 45 = 345 Seconds
Find the slope of the line containing the points in the table below
Answer:
slope = 3
Step-by-step explanation:
Choose any two points: For example, (2, 4) and (4, 10)
Find the difference in y. This is called the "rise."
rise = 10 - 4 = 6
In the same order, find the difference in x. this is called the "run."
run = 4 - 2 = 2
slope = rise/run
slope = 6/2
slope = 3
BRAINLIST HELP TIMED
Answer:
its the second one
Step-by-step explanation:
u just mulitply the terms together and add the exponents
Which measurement is most likely to be the mass of a strawberry?
Answer:
is there anything to go with this?
Step-by-step explanation:
Answer: D
Step-by-step explanation: Saw your recent comment on this
Pretty please help!!!
The table shows the relationship of how many pounds of apples are needed to make a certain number of pies:
Number of pies: 5 10 15
Pounds of apples: 2 4 6
`y=2x+1` was a positive slope because...
Step-by-step explanation:
.....because the coefficient of x is 2, a positive number.
I need help with this question thanks!
Answer:
n= -10
Step-by-step explanation:
50-20= 30 so -3n=30. So n= -10.
Answer:
n=-10
Step-by-step explanation:
-3n+20=50 move constant to the right hand side
-3n=50-20 subtract the numbers
-3n=30 divide both sides by -3 and the answer is n=-10
3.3^(2x+1)-103^x+1=0 need value of x
Answer:
The value of [tex]x[/tex] is approximately -1.531.
Step-by-step explanation:
Let [tex]3.3^{2\cdot x + 1}-103^{x+1} = 0[/tex], we proceed to solve this expression by algebraic means:
1) [tex]3.3^{2\cdot x + 1}-103^{x+1} = 0[/tex] Given
2) [tex]3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0[/tex] [tex]a^{b}\cdot a^{c} = a^{b+c}[/tex]
3) [tex](3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0[/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]
4) [tex](3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0[/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]/Commutative property
5) [tex]\left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0[/tex] Existence of multiplicative inverse/Definition of division/Modulative property/[tex]a^{b}\cdot a^{c} = a^{b+c}[/tex]
6) [tex]\left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3}[/tex] Existence of additive inverse/Modulative property/[tex](a^{b})^{c} = a^{b\cdot c}[/tex]
7) [tex]\log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3}[/tex] Definition of logarithm.
8) [tex]2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}[/tex] [tex]\log_{b} a^{c} = c\cdot \log_{b} a[/tex]
9) [tex]2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3[/tex] [tex]\log_{b} \frac{a}{d}[/tex]
10) [tex]x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3[/tex] [tex]\log_{b} a^{c} = c\cdot \log_{b} a[/tex]/Associative property
11) [tex]x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}[/tex] Existence of multiplicative inverse/Definition of division/Modulative property
12) [tex]x \approx -1.531[/tex] Result
The value of [tex]x[/tex] is approximately -1.531.
6) Calculate the slope of a line containing the points (-3,5) and (-7,11).
slopev=
[tex]diffrence \: in \: y \: coordinate \\ diffrence \: in \: x \: coordinate[/tex]
so
Y=11_5 =6
X = -7_(-3) = -4.
slope = (-4,6)
make as brainlist
. Ruiz wants to buy a coffee machine that costs
$45.00. How much would the cashier give Ruiz if she
gives the cashier a $100 bill?
Ruiz would get back 55 dollars 0 cents
A rectangle I has a perimeter of 28 units, an area of 48 square units, and sides that are either horizontal or vertical. If one vertex is the point (-5,-7) and the origin is in the interior of the rectangle, fi the vertex of the rectangle is opposite of (-5,-7).
Answer:
B, C, E
Step-by-step explanation:
On edge 2021
Find percentage of .20
Answer: The percentage of 0.20 is 20%.
Step-by-step explanation: 0.20 represents the 20% of 100%.
Answer: 20%
Step-by-step explanation: You just move the dot 2 times to the right and it will be 20%