Find the slope of the line that passes through the two points.

Answer:

Step-by-step explanation:

[tex]f(x)=x^3+x^2\\\\g(x)=x^4+x^2+x[/tex]

[tex]f(x)-g(x)=(x^3+x^2)-(x^4+x^2+x)=x^3+x^2-x^4-x^2-x\\\\=-x^4+x^3-x\\\\x=1\\\\-1^4+1^3-1=-1+1-1=-1[/tex]

[tex]x=1\\\\f(1)=1^3+1^2=1+1=2\\\\g(1)=1^4+1^2+1=1+1+1=3\\\\f(1)-g(1)=2-3=-1[/tex]

Answer:

500ml

Step-by-step explanation:

[tex]2000 \div 4 = 500[/tex]

Answer:

500 ml

Step-by-step explanation:

2 litres= 2000 millilitres divided into 4 bowls=2000÷4=500 millilitres

Answer:

yes ikow

Step-by-step explanation:

you can do that if you want to buy

Answer:

where the graph?

Step-by-step explanation:

Answer:

1.13

2.19

3.31

Step-by-step explanation:

Let the length of the shortest side be a.

a+a+6+a+6+12=63

3a=39

a=13

Answer:

I think is A or B I don't know

Answer:

a

Step-by-step explanation:

Answer:

1/3 because they have only colored on out of three, so the answer will be 1/3. Hope this helped!

Step-by-step explanation:

Answer:15/16 > 1/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: omg yes I ate like 10 wings last night. Your answer should be 20

Step-by-step explanation:

Answer:

It will take $ 989.59 in Canadian funds to buy $ 800.

Step-by-step explanation:

If one Canadian dollar is equivalent to US $ 0.8150, in order to determine how much money is needed in Canadian funds to buy US $ 800.00 the following calculation must be performed:

0.8150 = 1

800 = X

(800 x 1) / 0.8150 = X

800 / 0.8150 = X

981.59 = X

Therefore, it will take $ 989.59 in Canadian funds to buy $ 800.

Answer:

The Pooled Standard Deviation for these data sets is 1.09

Step-by-step explanation:  

Given that;

Standard Deviation 1 = 1.11

Standard Deviation 2 = 0.99

Standard Deviation 3 = 1.15

pooled standard deviation is given as;

[tex]S_{pooled}[/tex] = (n1 - 1 )s1² + ..... + ( nk - 1 )sk² / n1 + ..... + nk - 1

where n1, n2....., nk are the sample sizes of k groups and s1, s2, ....., sk are the standard deviations of k groups respectively

so for the 3 groups;

[tex]S_{pooled}[/tex]² =   (n1 - 1 )s1² + (n2 - 1 )s2² + ( n3 - 1)s3² / n1 + n2 + n3 - 3

we substitute

[tex]S_{pooled}[/tex]² =   (5 - 1 )1.11² + (5 - 1 )0.99 ² + ( 5 - 1)1.15² / 5 + 5 + 5 - 3

[tex]S_{pooled}[/tex]² =   (4.9284 + 3.9204 + 5.29) / 12

[tex]S_{pooled}[/tex]² =   14.1388 / 12

[tex]S_{pooled}[/tex]² =   1.1782

[tex]S_{pooled}[/tex] = √1.1782

[tex]S_{pooled}[/tex] = 1.08544 ≈ 1.09

Therefore, The Pooled Standard Deviation for these data sets is 1.09

Answer:

Step-by-step explanation:

2x(x - 3) + 7(x - 3)

2x^2 - 6x + 7x - 21

reduce

2x^2 + x - 21

if this is equal to 0 then:

2x^2 + x - 21 = 0

factored:

(2x + 7)(x - 3) = 0

How that was done:

Divide the (2x^2) into (2x) and (x).

Divide the (-21) into (+7) and (-3). You choose these numbers so that their sum, when multiplied by (2x) and (-3), adds up to (+x).  

Answer:

(x,y)= ( 5 over 273, - 265 over 273)

Step-by-step explanation:

After solving the obtained equation with the elimination method the obtained value of x and y will be 2 and 1 respectively.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that,

8x-5y=11  ------ (1)

4x-3y=5 --------- (2)

In order to solve the above equation with the elimination method, we have to apply the multiplicative distribution law as,

Multiply by 2 in equation 2

2(4x-3y=5)

8x- 6y = 10  ----- (3)

Subtract equation 3 from equation 1,

(8x- 6y)-(8x-5y) = 10 - 11

8x-8x-6y+5y = -1

-y = -1

y=1

Substitute the value of y in any of the equations 1  to get the value of x

8x-5y=11

8x-5(1)=11

8x-5=11

8x=16

x=2

Thus, after solving the obtained equation with the elimination method the obtained value of x and y will be 2 and 1 respectively.

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Answer: I can give you the volume: 480. But to find the area I need more context to know which are the length and width.

Answer:

Step-by-step explanation:

No solution. Lines M and P have the same slope but different y-intercepts., so they are parallel lines.

Parallel lines don’t intersect each other, so there is no solution.

Answer:

Charles

Step-by-step explanation:

Answer: Angle I is congruent to angle L

Step-by-step explanation:

Did da test

To prove ΔGHI and ΔJKL are similar following statements must be true,

i) angle I and angle L are congruent.

ii) angle G and angle J are congruent

iii) sides of the triangles are in proportion

⇒[tex]\frac{GH}{JK}= \frac{HI}{KL}= \frac{IG}{LJ}[/tex][tex]\frac{GH}{JK}= \frac{HI}{KL}= \frac{IG}{LJ}[/tex]

"Two or more triangles are similar if and only if the corresponding angle measures same and their corresponding side lengths are in proportion.."

For given example,

ΔGHI is dilated to form new ΔJKL.

Also, angle H is congruent to angle K.

To prove ΔGHI and ΔJKL are similar.

i) angle I and angle L are congruent.

ii) angle G and angle J are congruent

iii) sides of the triangles are in proportion

⇒[tex]\frac{GH}{JK}= \frac{HI}{KL}= \frac{IG}{LJ}[/tex]

Therefore, to prove ΔGHI and ΔJKL are similar following statements must be true,

i) angle I and angle L are congruent.

ii) angle G and angle J are congruent

iii) sides of the triangles are in proportion

⇒[tex]\frac{GH}{JK}= \frac{HI}{KL}= \frac{IG}{LJ}[/tex]

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Answer:

[tex]\frac{5}{18} pound of snack mix is eaten by Rachel.[/tex]

Step-by-step explanation:

Given

Total snack mix with Rachel [tex]\frac{2}{3}[/tex] Pounds

Snack mix eaten by Rachel [tex]= \frac{5}{12}[/tex] of the total snack mix

[tex]\frac{5}{12}[/tex] of the total snack mix accounts for

[tex]\frac{5}{12} * \frac{2}{3} = \frac{5}{18}[/tex] Pound

Answer:

5/12

Step-by-step explanation:

Answer:

Kindly check attached picture for barchart and piechart distribution

Step-by-step explanation:

Given the name data:

Name ____ freq ___R/Freq ____% frequency

Brown ____7 ______0.14 ______14

Smith ____ 12 -____ 0.24 ______24

Williams__ 8 ______0.16 ______ 16

Miller ____6 ______0.12 ______ 12

Jones ___ 7 ______ 0.14 ______ 14

Johnson _ 10 _____ 0.20 ______20

The three most popular last names are :

Smith, Johnson and Miller

Based on the information given in the bar chart, it should be noted that the most popular last names are Smith, Johnson, and Williams.

It should be noted that the information given in the question is used in solving the bar chart and pie chart.

The name with the least number of people is Miller. On the other hand, the most popular last names are Smith, Johnson, and Williams.

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Answer:

X     Y    

0     -1

2     -0.5

4     0

6     0.5

8     1

Step-by-step explanation:

I hope i got that right

Answer:

3.5

Step-by-step explanation:

3.5 is the y-intercept because the point is (0,3.5). This is where it intercepts with the y-axis.

Hope it helps!

Answer:

x + 50 × 10 = 150

x+500=150

x=150-500=-350

Step-by-step explanation:

solution,

here,

given,

x+50*10 = 150

or, x+500=150

or, x= 150 -500

therefore, x= -350

hope this helps u..

One of the two basic types of animal locomotion: powered flight, actual flight, or gliding. Real wings are only found in most bird species, most insect orders, and bats.

A category listing is a list of various product categories, such as children's clothing, women's clothing, and men's clothing. Any form of a category can be simply created

Soaring and gravitational gliding are two distinct types of gliding flight.

In controlled gravitational gliding, a creature propels itself in a precise direction after delaying its descent and relying on the wind for horizontal motion (parachuting).

Adaptations for guided gliding are primarily made to increase glide ratio (the amount of horizontal distance covered per unit descent)

Therefore, powered flight or true flight are the two basic categories of animal locomotion.

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Answers:

11.) 0.25

12.) 3:20

13.) 0.75

14.) 19

Answer:

Question 11: 0.25

Question 12: 3:20

Question 13: 0.75

Question 14: 19

Answer:

H0: μ ≥ 16

H1: < 16

−2.748749;

0.011275;

Reject the Null

Step-by-step explanation:

Given the data:

15.87, 16.02, 15.78, 15.83, 15.69, 15.81, 16.04, 15.81, 15.92, 16.10

Null hypothesis ; H0: μ ≥ 16

Alternative hypothesis ; H1: < 16

Sample size, n = 10

From the data:

Using calculator,

Sample mean, m = 15.887

Standard deviation, s = 0.13

The test statistic, T

(m - μ) / s/sqrt(n)

(15.887 - 16) / (0.13/sqrt(10))

= −2.748749

Using the p value from test statistic calculator :

Degree of freedom (df) = 10 - 1 = 9 at 0.05 significance level is 0.011275

Since the p value is < 0.05

0.011 < 0.05

We reject the Null and conclude that the mean fill weight is less than 16 oz