Find the surface area of the space figure represented by the net.

245.5 cm2

263 cm2

173.5 cm2

191 cm2

Answer:

[tex]fg(7)=143.95[/tex]

Step-by-step explanation:

We are given that

[tex]f(x) = (x -2)^2 -3[/tex] for x > −2

[tex]g(x) = 2x+6x^{-2}[/tex] for x > 2

We have to find fg(7)

[tex]fg(7)=f(g(7))[/tex]

[tex]=f(2(7)+6(7)^{-2})[/tex]

=[tex]f(14+\frac{6}{49})[/tex]

=[tex]f(\frac{692}{49})[/tex]

692/49>-2

fg(7)=[tex](\frac{692}{49}-2)^2-3[/tex]

=[tex]146.95-3[/tex]

Hence, [tex]fg(7)=143.95[/tex]

Answer:

What is the question?

Step-by-step explanation:

I will edit this and answer when you comment the question in this answer.

Answer:

16 pots

Step-by-step explanation:

We first need to find out the amount of dirt that can be filled into a single flowerpot.

We use the formula to find the cylinder's volume.

π[tex]r^{2}[/tex][tex]* h[/tex]

Height is equal to ten, Radius is equal to 7.

49π [tex]* 10[/tex]

≈ 1539.38

25,000 divided by 1539.38

≈ 16.24

He can fill 16 pots fully.

Answer:

go a head what can i help you with

Answer:

Step-by-step explanation:

[tex]y_A = 9x -3x - 4 \\y_A = 6x - 4\\\\y_B = 12x - 4\\\\y_C = 5x + x - 4\\y_C = 6x -4[/tex]

Standard equation of a line with slope, m and y - intercept b is y = mx + b.

Clearly. for  the second equation has a different coefficient for x.

a ) The coefficient for x , is the slope of the line.

     Though the y - intercept for each equation is same = - 4.

    For example :

  Expression A = 2 , when x = 1

  Expression B = 8 , when x = 1

  Expression C = 2 , when x = 1

b) From above :

        [tex]y_A \ and \ y_C \ are \ the \ same \ expression.[/tex]

c) Expression A and  C are equivalent because the coefficient of x

    is the same  for A and  C.

Answer:

[tex]y = \frac{ - 13 - \sqrt{489} }{10} [/tex]

Answer:

Step-by-step explanation:

5y^2+15y-2y+4=20

5y^2-13y+4=20

5y^2-13y+4-20=0

5y^2-13y-16=0

This equation is in standard form: ax^2+bx+c=0. Substitute 5 for a, 13 for b, and −16 for c in the quadratic formula.

Answer:

85 miles

Step-by-step explanation:

He needed to travel a total of 210 miles

He had already traveled 125 miles on bus

And he traveled the rest of the length on the train

If we want to find the distance he traveled on train we simply subtract total distance by distance traveled on bus

So distance traveled on train = 210 - 125 = 85

So he traveled a total of 85 miles on train

Answer:

Substitute your answer for Step 1 into the second equation to solve for Z.

Answer:

(2, -3)

Step-by-step explanation:

YEAH

Answer:

x=2; y=-3

Step-by-step explanation:

submitdjememendixodme ejej

Answer:

yes what would u like help with

Answer:y=x-5

Step-by-step explanation: Use (y2-y1)/(x2-x1) fill those in and get (4-1)/(9-6) which is 3/3 and that is 1 for the slope. Now fill in y=1x with a given coordinate and try to find the y-intercept so we would do 1=1(6) and we need to make the right side equal to the left so we subtract 5. Ending us with y=x-5.

Answer:

{F, G, H, I, J, K, L, M, N, O, P}

are the points between segment EQ :)

Answer:

B

Step-by-step explanation:

i think it is.....................

Answer:

253.75 square feet

Answer:

width is 1 cm

Step-by-step explanation:

The SA of a rectangular prism is SA = 2(lw + wh + hl)

We are given the length, the height, and the SA, and we need to find the width. So we plug in the known values into this equation:

10 = 2(2w + w + 1*2)

10 = 2(3w+2)

10 = 6w+4

6=6w

w=1

We can check the answer by plugging in all the values into the equation:

10 = 2(2*1+1*1+1*2)

10 = 2(5)

10 = 10

Answer:

[tex]8 \frac{1}{3} \div 4 \frac{1}{2} = \frac{50}{27} = 1.851 = 1 \frac{23}{27} [/tex]

Answer:

c. 36·x

Step-by-step explanation:

Part A

The details of the circle are;

The area of the circle, A = 12·π cm²

The diameter of the circle, d = [tex]\overline {AB}[/tex]

Given that [tex]\overline {AB}[/tex] is the diameter of the circle, we have;

The length of the arc AB = Half the the length of the circumference of the circle

Therefore, we have;

A = 12·π = π·d²/4 = π·[tex]\overline {AB}[/tex]²/4

Therefore;

12 = [tex]\overline {AB}[/tex]²/4

4 × 12 = [tex]\overline {AB}[/tex]²

[tex]\overline {AB}[/tex]² = 48

[tex]\overline {AB}[/tex] = √48 = 4·√3

[tex]\overline {AB}[/tex] = 4·√3

The circumference of the circle, C = π·d = π·[tex]\overline {AB}[/tex]

Arc AB = Half the the length of the circumference of the circle = C/2

Arc AB = C/2 = π·[tex]\overline {AB}[/tex]/2

[tex]\overline {AB}[/tex] = 4·√3

∴ C/2 = π·4·√3/2 = 2·√3·π

The length of arc AB = 2·√3·π cm

Part B

The given parameters are;

The length of [tex]\overline {OF}[/tex] = The length of [tex]\overline {FB}[/tex]

Angle D = angle B

The radius of the circle = 6·x

The measure of arc EF = 60°

The required information = The perimeter of triangle DOB

We have;

Given that the base angles of the triangles DOB are equal, we have that ΔDOB is an isosceles triangle, therefore;

The length of [tex]\overline {OD}[/tex] = The length of [tex]\overline {OB}[/tex]

The length of [tex]\overline {OB}[/tex] = [tex]\overline {OF}[/tex] + [tex]\overline {FB}[/tex] = [tex]\overline {OF}[/tex] + [tex]\overline {OF}[/tex] = 2 × [tex]\overline {OF}[/tex]

∴ The length of [tex]\overline {OD}[/tex] = 2 × [tex]\overline {OF}[/tex] = The length of [tex]\overline {OB}[/tex]

Given that arc EF = 60°, and the point 'O' is the center of the circle, we have;

∠EOF = The measure of arc EF = 60° = ∠DOB

Therefore, in ΔDOB, we have;

∠D + ∠B = 180° - ∠DOB = 180° - 60° = 120°

∵ ∠D = ∠B, we have;

∠D + ∠B = ∠D + ∠D = 2 × ∠D = 120°

∠D = ∠B = 120°/2 = 60°

All three interior angles of ΔDOB = 60°

∴ ΔDOB is an equilateral triangle and all sides of ΔDOB are equal

Therefore;

The length of [tex]\overline {OD}[/tex] = The length of [tex]\overline {OB}[/tex] = The length of [tex]\overline {DB}[/tex]  = 2 × [tex]\overline {OF}[/tex]

The perimeter of ΔDOB = The length of [tex]\overline {OD}[/tex] + The length of [tex]\overline {OB}[/tex] + The length of [tex]\overline {DB}[/tex] = 2 × [tex]\overline {OF}[/tex] + 2 × [tex]\overline {OF}[/tex] + 2 × [tex]\overline {OF}[/tex] = 6 × [tex]\overline {OF}[/tex]

∴ The perimeter of ΔDOB = 6 × [tex]\overline {OF}[/tex]

The radius of the circle = [tex]\overline {OF}[/tex] = 6·x

∴ The perimeter of ΔDOB = 6 × 6·x = 36·x

Answer:

y = 3x - 1

Step-by-step explanation:

Slope-intercept form: y = mx + b

m = slope

b = y-intercept

Answer:

first option is correct

Step-by-step explanation:

finding area for upper rectangle

length = 16 miles

breadth = (2x - 1) miles

area of rectangle = l*b

=16 *(2x - 1)

16*2x - 16*1

=32x - 16

finding area for another rectangle

length = (5x + 5) miles

breadth = 4 miles

area of rectangle = l*b

= (5x + 5) * 4

=5x*4 + 5*4

=20x + 20

area of the figure = area of upper rectangle + area of another rectangle

=32x - 16 + 20x + 20

= (52x + 4) sq mi

I think c because from what remember taking this test

simplest form 4 : 2 : 2 is 2:1:1

Answer:

3/5 is expressed as 60% in terms of Percentage.

Let's convert the fraction 3/5 into percent. Now, 60/100 is expressed as 65% in terms of percentage.

Answer:

$625.6

Step-by-step explanation:

Information about the holiday:

7 night holiday

$340 per person

8% discount if you book before 31 March

Number of people Naseem booked the holiday for = 2

Date of booking of the holiday = 15 February

Total cost of the holiday per person = cost per person - discount before March 31

= $340 - 8% of $340

= 340 - 8/100 * 340

= 340 - 0.08 * 340

= 340 - 27.2

= $312.8

Total cost of the holiday for 2 persons = 2 × Total cost of the holiday per person

= 2 * $312.8

= $625.6

Given:

[tex]PQRS\sim TUVW[/tex]

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

[tex]PQRS\sim TUVW[/tex]

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

[tex]k=\dfrac{VW}{RS}[/tex]

[tex]k=\dfrac{25}{35}[/tex]

[tex]k=\dfrac{5}{7}[/tex]

Therefore, the scale factor from PQRS to TUVW is [tex]k=\dfrac{5}{7}[/tex].

Answer:

1/3

Step-by-step explanation:

If it was supposed to be a negative answer, there would be negative numbers in the sequence. So that narrows it do to 3 and 1/3. And now we know that 27*3 isn't 9 but 27*1/3=9 and so on.

Answer:

your answer will have to be 3

Step-by-step explanation:

from 27 to 9, we divided by 3

from 9 to 3, we divided by 3

from 1 to 1/3, we divided by 3

from 1/3 to 1/9, we divided by 3

from 1/9 to 1/27, we divided by 3

so basically the common ratio will have to be 3

Answer:

The equation of the line is [tex]y = 2\cdot x + 3[/tex].

Step-by-step explanation:

The data of the table represents a line, also known as a linear function or a first order polynomial if and only if the following property is satisfied:

[tex]\frac{y_{i+1}-y_{i}}{x_{i+1}-x_{i}} = m, m \in \mathbb{R}[/tex] (1)

Now we proceed to check if the table represents a line instead of another kind of function:

[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{7-5}{2-1} = 2[/tex]

[tex]\frac{y_{3}-y_{2}}{x_{3}-x_{2}} = \frac{9-7}{3-2} = 2[/tex]

[tex]\frac{y_{4}-y_{3}}{x_{4}-x_{3}} = \frac{13-9}{5-3} = 2[/tex]

[tex]\frac{y_{5}-y_{4}}{x_{5}-x_{4}} = \frac{15-13}{6-5} = 2[/tex]

Hence, the data represents a line. From Geometry we know that the equation of the line can be obtained by knowing two distinct points. The formula of the line is described below:

[tex]y = m\cdot x + b[/tex] (2)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]m[/tex] - Slope.

[tex]b[/tex] - y-Intercept.

If we know that [tex](x_{1}, y_{1}) = (1, 5)[/tex] and [tex](x_{2}, y_{2}) = (6, 15)[/tex], then we have the following system of linear equations:

[tex]m + b = 5[/tex] (1)

[tex]6\cdot m + b = 15[/tex] (2)

The solution of the system of linear equations is: [tex]m = 2[/tex], [tex]b = 3[/tex].

The equation of the line is [tex]y = 2\cdot x + 3[/tex].

Answer:

y = 3/2 x -3

Step-by-step explanation:

the line passes (0, -3) and (2, 0)

the slope = (0+3)/(2-0) = 3/2

the equation :

y-0= 3/2(x -2)

y = 3/2 x - 3

Answer:

See explanation

Step-by-step explanation:

The question has conflicting details

[tex]f(x) = 2x + 5[/tex]

[tex]f(x) = 2x + 5[/tex] and three halves doesn't sound correct.

So, I will take f(x) as

[tex]f(x) = 2x + 5[/tex]

Next, solve for the inverse function

Replace f(x) with y

[tex]y = 2x + 5[/tex]

Swap x and y

[tex]x = 2y + 5[/tex]

Make 2y the subject

[tex]2y = x-5[/tex]

Make y the subject

[tex]y = \frac{x-5}{2}[/tex]

Replace y with the inverse sign

[tex]f^{-1}(x) = \frac{x-5}{2}[/tex]

So, now we can calculate any value from the original function and from the inverse function.

For instance:

[tex]f^{-1}(7) = \frac{7-5}{2} = \frac{2}{2} = 1[/tex]

[tex]f(1) = 2*1 + 5 = 2+5=7[/tex]