Gerardo changed a $100 at the bank. He received $20 bills and $10 bills.
$20 bills was 2 more than the number of $10 bills. How many bills of each kind did he
receive?
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Answers

Answer 1

Answer:

• Two $10 bills

• Four $20 bills

Step-by-step explanation:

We are told that Gerardo received a number of $20 and $10 bills upon changing a $100 bill at the bank. We are also told that he received 2 more $20 bills than $10. Then we are asked to find the number of each kind of bill.

To solve this problem, let's consider the number of $10 bills he received was [tex]x[/tex]. Since he received 2 more $20 bills, he got [tex](2 + x)[/tex] $20 bills. Therefore, in total he received:

[tex]10 \times x + 20 \times (x +2)[/tex]

This should add up to $100 since that is the amount he changed. Solving the resulting equation for [tex]x[/tex] will give us the number of $10 bills he received.

[tex]10 \times x + 20 \times (x +2) = 100[/tex]

⇒ [tex]10x + 20x + 40 = 100[/tex]

⇒ [tex]30x +40 = 100[/tex]

⇒ [tex]30x + 40 - 40 = 100 - 40[/tex] [Subtracting 40 from both sides of equation]

⇒ [tex]30x = 60[/tex]

⇒ [tex]\frac{30}{30}x = \frac{60}{30}[/tex]              [Dividing both sides of the equation by 30]

⇒ [tex]x = \bf 2[/tex]

Therefore, he received 2 $10 bills.

Since the number of $20 bills is 2 more than the number of $10 bills,

no. of $20 bills = 2 + 2

                         = 4


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