Help help help help help pleases pelass thank you

Answer:

2, -6

Step-by-step explanation:

x^2 + 4x - 12

A = 1

B = 4

C = -12

i used the "X" method to solve for the solutions. i think it's easier than using the quadratic formula but it doesn't always work

for the "X" method you have to multiply your A value and your C value together so 1 x (-12) = -12. that is going to be the top part of the X

the bottom part of the x will be your B value which is 4

we have to find multiples of -12 that will also add to 4

so -2 and 6 multiply to -12 but also add to 4 so we know these numbers will work

i added added two drawings to show how i found the solutions using the "X" method and the quadratic formula

Answer:

3,280/38650 x 100% = 8%

=5/3   =−1

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

Answer:

B

Step-by-step explanation:

it is the opposite of A, which is true, as |-8| = 8

Answer:

[tex]f(x) = \left \{ {{x + 3} \quad \text{if} \ -3 \leq x < -1\atop {5} \quad \text{if} \ -1 \leq x \leq1} \right.[/tex]

Step-by-step explanation:

You can find the first function if you know the general form of a line:

[tex]y = mx + b[/tex]

where [tex]m[/tex] is the slope and [tex]b[/tex] the intercept point with the [tex]y[/tex]-axis.

So in the first case the slope is 1 because the next formula

[tex]m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2-0}{-1+3} = 1[/tex]

And you can find the interception point if extend the line, then in our case is  3.

So the function is:

[tex]f(x) = x + 5[/tex]

In the other case is constant function that's mean that the function has the next form

[tex]f(x) = k[/tex]

Where [tex]k[/tex] is a constant.

So you only have to observe what is the value for each point in the interval, in this occasion is 5.

So the final answer is:

[tex]f(x) = \left \{ {{x + 3} \quad \text{if} \ -3 \leq x < -1\atop {5} \quad \text{if} \ -1 \leq x \leq1} \right.[/tex]

[tex]\begin{array}{cccccccc}\\ \underline{-3}&,&12&,&-33&,&102\\ \cline{1-7} &&(-3)(\underline{-3})+3&&(-3)(12)+3&&(-3)(-33)+3 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{ccc} -303&,&912\\ \cline{1-3} (-3)(102)+3&&(-3)(-303)+3 \end{array}[/tex]

Using simple interest, it is found that:

a) The monthly payment will be of $222.57.

b) In total, the car will cost $18,251.9275.

c) $16,025.1775 will be paid in interest.

The amount of money accrued after t years, using simple interest, with an initial value of P and a decimal rate of r is given by:

[tex]A(t) = P(1 + rt)[/tex]

In this problem:

Item a:

The amount of money accrued will be of:

[tex]A(6) = 12618.25[1 + 0.045(6)] = 16025.1775 [/tex]

Payment over 6 x 12 = 72 months, hence, the monthly payment will be of:

[tex]m = \frac{16025.1775}{72} = 222.57[/tex]

The monthly payment will be of $222.57.

Item b:

The total cost is composed by:

Hence:

[tex]T = 0.15(14845) + 16025.1775 = 18251.9275[tex]

In total, the car will cost $18,251.9275.

Item c:

As found in item a, $16,025.1775 will be paid in interest.

A similar problem is given at https://brainly.com/question/13176347

Step-by-step explanation:

The first step is to Know the condition for two lines be parallel is that have the same slope, and this form the slope given is 2, therefore the new function has its slope too

2)  with the slope and the two points givens, you can find the equation

Y-Y1 = m( X-X1) ,   Y-6 = 2[(X-(-3)]  ⇒Y-6 = 2X+6 ⇒Y = 2X+12, AND THIS IS THE EQUATION PARALLEL TO THE LINE Y = 2X-7

Check the picture below.

The amount that will be spent is $24.50, the amount saved will be $10.50, and the percentage saved will be 30%.

The amount that will be spent will be:

= 7/10 × $35 = $24.50

The amount that will be saved will be:

= $35 - $24.50 = $10.50

The fraction of the original price that is saved will be:

= 10.50/35 × 100

= 30%

Read related link on:

https://brainly.com/question/25763817

Answer:

Step-by-step explanation:

No . B'  (reflection of B) and C' (reflection of C) are in the right position,  but D' should be at  (4, 1) and A' should be at (-2,-4).

Answer:

1799 members in the art club i think but i don't have a bar graph

Step-by-step explanation:

^^

The element which should be used to help clarify a complicated idea in a text is ; A research question.

According to the question;

A research question is the best fit which should be used to help clarify a complicated idea in a text.

This is so because; a research question provides a basis for accessing all perspectives there is to the complicated idea.

Read more:

brainly.com/question/18675306

Answer:

D

Step-by-step explanation:

how is this math? 0-0

Answer: 18

Step-by-step explanation:

The question is asked to know 30% of 60, we get

60 x 30% = 60 x 0.3 = 18

Answer:

18

Step-by-step explanation:

We know that 30% means 30/100

30/100 multiplied by 60

hence, the answer is 18

Step-by-step explanation:

7 √(1/3) - 2 1/3 √(1/3) +3√147

→7(1/√3) - (7/3)(1/√3) +3√(3×7×7)

→ (7/√3) - (7/3√3) +3×7√3

→ (7/√3) - (7/3√3) + 21√3

On Rationalising the denominators then

→ [ 7√3/(√3×√3)]-[7√3/(3×√3×√3) +21√3

The Rationalising factor of√3 =√3

→ (7√3/3)-[7√3/(3×3)]+21√3

→ (7√3/3)-(7√3/9)+21√3

LCM of 3 and 9 = 9

→ [(3×7√3)-(7√3)+(9×21√3)]/9

→ (21√3-7√3+189√3)/9

→[(21-7+189)√3]/9

→ [(210-7)√3]/9

→ 203√3/9 Ans.

Hope this helps.

Answer:

i think 9900

Step-by-step explanation:

225x20 = 4500

180x30 = 5400

5400+4500 = 9900

Step-by-step explanation:

Answer:

it would be c because its moved 2x up

Step-by-step explanation:

[tex]\int {12x+5} \, dx[/tex]

For this problem, let's first apply the intergral sum rule.

[tex]\int {12x+5} \, dx = \int{12x} \, dx + \int{5}x \,dx[/tex]

Then, we'll use the reverse power rule on each of these integrals.

[tex]\int{12x} \,dx = 6x^2+C[/tex]

[tex]\int{5} \,dx = 5x+C[/tex]

So the indefinite integral of [tex]\int{12x+5} \,dx[/tex] is [tex]6x^2+5x+C[/tex].

Remember that we need our constant of integration, [tex]C[/tex], because of if we take the derivative of a constant, it'll be 0.

Hope this helps!

Hi there!

[tex]\int\limits {12x+5} \, dx[/tex]

Recall the following rules:

[tex]\int\limits {x^n} \, dx = \frac{x^{n+1}}{n+1}[/tex]

Use this rule to evaluate. Remember to include the constant:

[tex]\int\limits {12x+5} \, dx = \frac{12x^{1+1}}{1+1} + 5x +C[/tex]

[tex]\int\limits {12x+5} \, dx = 6x^2 + 5x + C[/tex]

Answer:

21.4m

Step-by-step explanation:

Circumference : x diameter

is approximately 3.142

3.142 x 6.8 = 21.3656

Nearest tenth = 21.4m

Answer:

-23 over 10

Step-by-step explanation:

Hope this helped :)

Answer:

253/20

Step-by-step explanation:

(−2 1/5) × (−5 3/4) =

1. change both mixed numerals into fractions.

= -11/5 × (-23/4)

2. Since both numbers are negative, the product is positive. Multiply both numerators together. Multiply both denominators together.

= 253/20

253 is the product of 2 prime numbers, 11 and 23. 20 is the product of 2² and 5. There are no common factors in the numerator and denominator, so this fraction cannot be reduced.

Answer: 253/20

Answer:

6^3

Step-by-step explanation:

3 × 3 × 3 × 3 × 3 × 3=729

6^3=216

3 × 3 × 3 × 3 × 3 × 3=729

3^6=729

Hope this helps :)

3 × 3 × 3 × 3 × 3 × 3

63

9 × 9 × 9

36

Answer: Yes

Step-by-step explanation:

A: 12 minutesAnswer to B: 36 minutesAnswer to C:

Answer:

the answer is 24.23 $ thats what i got

Answer:

A. 2.11 and  B. 26.39+2.11=28.50

Step-by-step eplanation:

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Answer:

A

Step-by-step explanation:

5 times 10= 50

5 times -5= -25

50-25=25