help me! i’ll give brainliest

Answer:

patingin po ng problem maam

Answer:

3.15

Step-by-step explanation:

If you take away 2.85 dollars away from 5 dollars you'd get 3.15 dollars

Answer:

$2.15

Step-by-step explanation:

5 - 2.85 is 2.15. So, the amount of change you should receive is $2.15.

Answer:

A) No, because the determinant of the coefficient matrix is 0

Step-by-step explanation:

I think tell me if it's right

Answer:

C - 130

Explanation:

Hope you have a great day!

Answer:

y=1.5x+1

Step-by-step explanation:

Answer:

$8,046.37

Step-by-step explanation:

4,537*0.0455= 206.4335

206.4335*17=3509.3695

4537+3509.3695=8046.3695

8046.3695 rounded = $8,046.37

Answer:

angle 2 = 133

angle 3 = 47

Step-by-step explanation:

angle 2 and angle 1 are supplementary, so they equal 180. 180- 47=133

angle 3 and angle 4 are supplementary, so they equal 180. 180- 133=47

Answer:

16 meters

Step-by-step explanation:

1 3/5 x 10=10 30/5=16

Answer:

36

Step-by-step explanation:

Given that :

Rotation about polygon's center = 20°

To carry the polygon onto itself Angle of rotation is obtained by :

360° / n

Where n is the number of sides in the polygon :

360° / n = 20°

360° = 20 * n

360 = 20n

n = 360 / 20

n = 18

Hence, the polygon has 18 sides or a multiple of 18

Answer:

90 peanut butter

Step-by-step explanation:

Total number of cookies [tex]=240[/tex]

Number of chocolate cookies [tex]=\frac{1}{4}(240)=60[/tex]

Therefore,

Number of remaining cookies [tex]=240-60=180[/tex]

Number of raisins [tex]=\frac{1}{2}(180)=90[/tex]

So,

Number of peanut butter [tex]=180-90=90[/tex]

Answer:

[tex]\displaystyle B \approx 36.87^\circ[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Identify Variables

Angle θ = B

Adjacent Leg = 4

Hypotenuse = 5

Step 2: Solve for θ

Answer:

y=16x+9

Step-by-step explanation:

y-y1=m(x-x1)

y-9=16(x-0)

y-9=16(x)

y-9=16x

y=16x+9

Answer:

The rectangular pan will hold more batter

Step-by-step explanation:

To find the volume of a rectangular prism, such as the first cake pan, you need to multiply all of the dimensions. The equation looks like this: "V = l * w * h" substituting the variables with the numbers would make it say "13 * 9 * 2" which would be 234 [tex]in^{3}[/tex]

To find the volume of a cylinder, the equation is "V=π[tex]r^{2}[/tex]h". The radius is half the diameter, so "r" would be 4, being half of 8. The substituted equation would read "π[tex]4^{2}[/tex]2", making the cylinder's volume roughly 100.53 [tex]in^{3}[/tex]

When you take those two numbers, you are able to see that 234 is bigger than 100.53, therefore making the rectangular pan larger.

Answer:

t - (t x24%)

Step-by-step explanation:

Value of truck at the time of purchase was t dollars

value decreased by 24%

current value = t x 24%

t - (t x 24%).

current value = t -(t x 24%).

Answer:

1.   y = -10x - 5

2.  [tex]y = \frac{9}{5}x - 4[/tex]

3.  [tex]y = -\frac{5}{4}x + 5[/tex]

4. y = 7x + 5

Step-by-step explanation:

use y = mx + b

m = slope

b = y-intercept

1. Slope= -10, y- intercept = -5

   y = -10x - 5

2. Slope= - 9/5, y- intercept = -4

   [tex]y = \frac{9}{5}x - 4[/tex]

3. Slope= -5/4, y- intercept = 5

    [tex]y = -\frac{5}{4}x + 5[/tex]

4. Slope= 7, y- intercept = 5

    y = 7x + 5

Answer:

x = -55

Step-by-step explanation:

7 + x/5 = -4

Combine the constants.

x/5 = -11

Multiply both sides by 5 to simplify the denominator.

x = -55

Check.

7 + (-55)/5 = -4

7 + (-11) = -4

7 - 11 = -4

-4 = -4

Your answer is correct.

Hope this helps!

Answer:

[tex]7 + \frac{x}{5} = - 4 \\ \frac{x}{5} = - 4 - 7 \\ = - 11 \\ x = - 11 \times 5 \\ = - 55[/tex]

Answer:

D: Divide both sides by 2 to solve for x

Step-by-step explanation:

Answer:

800. is the answer

Step-by-step explanation:

ur welcome.

Answer:

[tex]\frac{22}{30} = \frac{11}{15}[/tex]

and

[tex]\frac{176}{7} = 25 \frac{1}{7}[/tex]

Step-by-step explanation:

First make all the fractions into improper fractions

[tex]1\frac{5}{6} = \frac{11}{6} \\\\2\frac{1}{2} = \frac{5}{2} \\\\3\frac{1}{7} = \frac{22}{7}[/tex]

After doing that put them back into the problems

Problem 1)

[tex]1\frac{5}{6}[/tex]  ÷ [tex]2\frac{1}{2}[/tex] , plug in the improper fractions

[tex]\frac{11}{6}[/tex] ÷ [tex]\frac{5}{2}[/tex]

to divide, you need to flip the second fraction and multiply

[tex]\frac{11}{6}[/tex]· [tex]\frac{2}{5}[/tex] = [tex]\frac{22}{30}[/tex]

then reduce

[tex]\frac{22}{30} = \frac{11}{15}[/tex]

Problem 2)

[tex]3\frac{1}{7}[/tex]÷ [tex]\frac{1}{8}\\[/tex]

Plug in improper fraction

[tex]\frac{22}{7}[/tex] ÷ [tex]\frac{1}{8}\\[/tex]

Then flip second fraction and multiply

[tex]\frac{22}{7}[/tex] · [tex]\frac{8}{1}[/tex]

Multiply

[tex]\frac{176}{7}[/tex]

Reduce, or make it a mixed number

[tex]\frac{176}{7} = 25 \frac{1}{7}[/tex]

Answer:

Answer:

Area of the running track = 6900 m²

Step-by-step explanation:

Length of a football pitch = 120 m

Width of the football pitch = 80 m

Area of the football pitch (Inner rectangle) = Length × Width

                                                                      = 120 × 80

                                                                      = 9600 m²

If a running track (width = 15 m) is built around the football pitch,

Length of the outer rectangle = 120 + 2×(15)

                                                  = 120 + 30

                                                  = 150 m

Width of the outer rectangle = 80 + 2×(15)

                                                = 110 m

Area of the outer rectangle = 150 × 110

                                              = 16500 m²

Therefore, area of the track around the football pitch = Outer rectangle - Inner rectangle

= 16500 - 9600

= 6900 m²

Area of the running track = 6900 m²

Answer:

A

Step-by-step explanation:

We are given:

[tex]\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}[/tex]

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

[tex]o=\sqrt{13^2-12^2}=\sqrt{25}=5[/tex]

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

[tex]\displaystyle \csc(\theta)=\frac{13}{5}[/tex]

Since θ is in QIII, cosecant must be negative:

[tex]\displaystyle \csc(\theta)=-\frac{13}{5}[/tex]

Our answer is A.

Answer:

A

Step-by-step explanation:

I took the quiz!

Answer:

78, 51, 51

or

78, 78, 24

Step-by-step explanation:

78, 51, 51

or

78, 78, 24

Answer:

what site is this on?

Step-by-step explanation:

Answer:

159/20

Step-by-step explanation:

Answer:

[tex]m^{4}n^{5}[/tex]

Step-by-step explanation: ( I'm a student, I'm not really good at explaining maths )

When dividing variables with exponents, you subtract the exponents that has the same variables, like this:

[tex]m^{16-12}n^{10-5}[/tex]

Simplifying this becomes:

[tex]m^{4}n^{5}[/tex]

Answer:

a = 1.125

is your compleate full answer

Answer:

the factorised form is 4(8a+9)

Answer:

I believe it is: 6n+8+7y+4m

Step-by-step explanation:

You can't do anything about the numbers with variables afterwards, so you just list those and you just add and subtract the numbers without variables.  Since the top and bottom are the same, you just list it once.  Sorry, not the best explanation.  Please let me know if I am wrong.  It's been a while since I had to any type of algebra.

Answer:

x=4, y=0. (4, 0).

Step-by-step explanation:

3x-4y=12

x=-2y+4

-----------

3(-2y+4)-4y=12

-6y+12-4y=12

-10y=12-12

-10y=0

y=0/-10=0

x=-2(0)+4=0+4=4

Answer:

Step-by-step explanation:

if x=-2y+4

3x-4y=12 becomes

3(-2y+4)-4y=12

-6y+12-4y=12

-10y+12=12

-10y=0

y=0

since x=-2y+4

x=-2(0)+4

x=4

so the solution is the point (4,0)

The answer is 208 4/25 or if you need decimal form 208.16

answer is

[tex]208 \frac{4}{25} [/tex]

in decimal form.. it will be,

[tex]208.16[/tex]