Help me with this please!!!

Hello,

3m + 5 > 2(m - 7) =

3m + 5 > 2m - 14

3m - 2m > - 14 - 15

x > - 29

Step-by-step explanation:

3m±2m>-14-5

5m>-19

m>-19/5

m>3.8

Using trigonometry, the height of the lighthouse from the top of the cliff is approximately 617.38 meters.

Trigonometry is a tool we can utilize to tackle this issue. Let's use "h" to represent the lighthouse's height and "x" to represent the distance between both the boat and the cliff's edge. Next, we have:

tan(24.7º) = h/x (1)

tan(28.4º) = (h + y)/x (2)

where "y" is the height of the cliff.

We want to find "h + y". To eliminate "x", we can use equation (1) to express "x" in terms of "h", and substitute it into equation (2):

x = h/tan(24.7º)

tan(28.4º) = (h + y)/(h/tan(24.7º))

Simplifying and solving for "h", we get:

h = y/tan(28.4º - 24.7º)

Now we can substitute this expression for "h" into equation (1) to find "y":

tan(24.7º) = y/(y/tan(28.4º - 24.7º))

Simplifying and solving for "y", we get:

y = 750 tan(24.7º) / (tan(28.4º - 24.7º))

y ≈ 237.78 meters

Therefore, the height of the lighthouse from the top of the cliff is:

h + y ≈ y/tan(28.4º - 24.7º) + y ≈ 617.38 meters.

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The question is -

A lighthouse is located at the edge of a cliff, as shown. A boat at sea level is 750 meters away from the base of the cliff. The angle of elevation between sea level and the base of the lighthouse measures 24.7º. The angle of elevation between sea level and the top of the lighthouse measures 28.4°. Find the height of the lighthouse from the top of the cliff.

Answer:28/445 or 6.2921 %

Step-by-step explanation:

There are 90 nuts all together. There are 14 pecans so it would be a 14/90 chance. Then since you are not replacing the nut there are 89 nuts. There are 36 cashews which would be a 36/89 chance. Because in the problem it says to find the probability of the selecting a pecan and then a cashew we know it is an and situation. Since it is an and situation you would multiply. You would do 14/90 times 36/89. This gives you 504/8010 which reduced is 28/445 or 6.2921%. Do you have and questions?

To see if there is a significant difference in the costs of airline flights between the west and east coasts to Lincoln, Nebraska, one can use a two-sample t-test. It is okay to perform the inference procedure, but the following assumptions and conditions must be checked.

Assumptions: Independence: The airfares for each coast should be independent of each other. Normality: The populations of airfares for both coasts should be approximately normally distributed .Equal variances: The population variances for both coasts should be equal.

Conditions: Sample sizes: Both samples should be large enough so that the Central Limit Theorem applies. Rule of thumb for t-tests is that the sample size should be at least 30.Random sampling: Both samples should be random .To test if the conditions are met, one can create a boxplot for each coast, check the normal probability plots, perform the F-test to check for equal variances, and check the sample sizes. If the assumptions and conditions are met, a two-sample t-test can be used to determine if there is a significant difference in the costs of airline flights between the west and east coasts to Lincoln, Nebraska.

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The probability of 0.0475 is less than 0.05, so it is unlikely to happen. Hence, it would be unusual if less than 30% of the sampled teenagers owned smartphones.

a) Find the probability that the proportion of the sampled teenagers who own a smartphone is between 0.35 and 0.45b) Find the probability that less than 45% of sampled teenagers own smartphonesc) Would it be unusual if less than 30% of the sampled teenagers owned smartphones?a)Find the probability that the proportion of the sampled teenagers who own a smartphone is between 0.35 and 0.45We know that the proportion of teenagers aged 12-17 who own smartphones is 0.38. Now, we need to find the probability that the proportion of sampled teenagers who own smartphones is between 0.35 and 0.45.The sample size is 120.Let P be the probability that a teenager has a smartphone. The population mean is P = 0.38, while the standard deviation is σ =√((P (1 - P)) /n).P (0.38) and n (120) are given, so σ is calculated as follows:σ=√((P (1 - P)) /n) =√((0.38 (1 - 0.38)) /120) =√((0.38 × 0.62) /120) =0.048Now, let us define the Z scores for both sides, i.e. for 0.35 and 0.45.z1 = (0.35 - 0.38) /0.048 = -0.625z2 = (0.45 - 0.38) /0.048 = 1.458Hence, P(0.35 < p < 0.45) is equal to P(-0.625 < z < 1.458).The probability can be calculated using standard normal tables, which gives 0.5763. Therefore, the probability that the proportion of the sampled teenagers who own a smartphone is between 0.35 and 0.45 is 0.5763.b) Find the probability that less than 45% of sampled teenagers own smartphonesLet P be the probability that a teenager has a smartphone. The population mean is P = 0.38, while the standard deviation is σ =√((P (1 - P)) /n).P (0.38) and n (120) are given, so σ is calculated as follows:σ=√((P (1 - P)) /n) =√((0.38 (1 - 0.38)) /120) =√((0.38 × 0.62) /120) =0.048Now, let us define the Z score as follows:z = (0.45 - 0.38) /0.048 = 1.458We must find the probability that a randomly selected teenager from the sample has less than 0.45 probability of owning a smartphone. This probability can be calculated using a standard normal table. P(z < 1.458) = 0.9265, thus, the probability that less than 45% of sampled teenagers own smartphones is 0.9265.c) Would it be unusual if less than 30% of the sampled teenagers owned smartphones?For this, we need to find the Z-score of 0.30.z = (0.30 - 0.38) /0.048 = -1.667The probability is obtained using a standard normal table. The probability is 0.0475. The probability of 0.0475 is less than 0.05, so it is unlikely to happen. Hence, it would be unusual if less than 30% of the sampled teenagers owned smartphones.

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Let n be a positive integer. We can use the properties of modular arithmetic to calculate this remainder. Let's start with a = (32n + 4)-1 mod 9. We can rewrite this as a = 9 - (32n + 4)-1 because 9 = 0 mod 9.

We can use Fermat's Little Theorem to calculate (32n + 4)-1. This theorem states that (32n + 4)-1 mod 9 = (32n + 4)8 mod 9.

Using the identity (a + b)n mod m = ((a mod m) + (b mod m))n mod m, we can simplify the equation to (32n mod 9 + 4 mod 9)8 mod 9.

32n mod 9 = 0, so (32n mod 9 + 4 mod 9)8 mod 9 = 48 mod 9 = 1.

Finally, a = 9 - 1 = 8 mod 9, so the remainder when a is divided by 9 is 8.

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Answer:

Para calcular el precio original de los auriculares antes del descuento, podemos usar la fórmula:

Precio original = Precio después del descuento / (1 - Porcentaje de descuento)

Donde "Precio después del descuento" es el costo de los auriculares después del descuento, y "Porcentaje de descuento" es el porcentaje aplicado como descuento. En este caso, el porcentaje de descuento es del 20%, es decir, 0.2 en términos decimales.

Sustituyendo los valores conocidos, obtenemos:

Precio original = 260 / (1 - 0.2)

Precio original = 260 / 0.8

Precio original = 325

Por lo tanto, el costo original de los auriculares antes del descuento era de $325.:

Answer:

The answer is D. (1-0.2)h=260

Step-by-step explanation:

The approximate slope and y-intercept of the line of best fit is y = -0.17x + 33.3.

In Mathematics, the point-slope form of a straight line can be calculated by using the following mathematical expression:

y - y₁ = m(x - x₁) or [tex]y - y_1 = \frac{(y_2- y_1)}{(x_2 - x_1)}(x - x_1)[/tex]

Where:

At data point (20, 20), a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:

[tex]y - y_1 = \frac{(y_2- y_1)}{(x_2 - x_1)}(x - x_1)\\\\y - 20 = \frac{(10- 20)}{(80-20)}(x -20)[/tex]

y - 20 = -1/6(x - 20)

y = -x/6 + 20/6 + 20.

y = -x/6 + 200/6

y = -0.17x + 33.3

In this context, we can reasonably infer and logically deduce that a linear function that represent the line of best fit in slope-intercept form is y = -0.17x + 33.3.

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$17.5 price should she charge in order to make the highest possible gross income.

Given two points are (400, 10) and  (392, 10.5)

slope = (10.5-10)/(392 -400) = 0.5/ - 8 = -0.0625

Equation is

p -10 = -0.0625(x-400)

p-10 = -0.0625x + 25

p = -0.0625x + 35

find revenue as

R=x*p

-0.0625x² + 35x

To maximize,

R'(x) =0

-0.125x + 35 = 0

35/0.125  = x

280 = x

when x is equal to 280, find

p= -0.0625(280) + 35

p= -17.5 +35

p= 17.5

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The required answers are 19) c = 8√2 units 20) a = b =a = [tex]\frac{\sqrt{10} }{14}[/tex].

A right triangle or right-angled triangle, or more formally an orthogonal triangle, formerly called a rectangled triangle, is a triangle in which one angle is a right angle, i.e., in which two sides are perpendicular. The relation between the sides and other angles of the right triangle is the basis for trigonometry.

19) Using Pythagoras theorem

[tex]c^2=a^2+a^2[/tex]

[tex]c^2=\sqrt{a^2+a^2}[/tex]

[tex]c=\sqrt{8^2+8^2}[/tex]

c = 8√2 units

20) It is isosceles triangle,So a = b

Now

[tex]$Sin(45) =\frac{a}{\frac{\sqrt{5}}{7} }[/tex]

a = [tex]\frac{\sqrt{10} }{14}[/tex]

Thus, required answers are 19) c = 8√2 units 20) a = b =a = [tex]\frac{\sqrt{10} }{14}[/tex].

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The equation that can be used to find d, the diameter of a new soccer ball, is: |d - 8.65| = 0.05

What is diameter ?

Diameter is the distance across a circle passing through its center, and it is defined as the length of a straight line passing through the center of a circle and connecting two points on the circumference of the circle. In the case of a soccer ball, the diameter is the distance between two opposite points on the surface of the ball, passing through its center.

Radius is a term used in geometry to refer to the distance from the center of a circle to any point on its circumference. It is defined as half of the diameter of a circle. In the case of a soccer ball, the radius is the distance from the center of the ball to its surface. The radius is related to the diameter by the formula:

radius = diameter / 2

The minimum possible diameter of a soccer ball is:

d = 8.65 - 0.05 = 8.60 inches

The maximum possible diameter is:

d = 8.65 + 0.05 = 8.70 inches

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Calculating the expected value of payout using the probabilities given, we can bet on blue for all 10 races, bet on red for all 10 races and bet on purple for all 10 races

To determine the most efficient bets to increase your money during the 10 rounds, we need to consider the probability and potential payout for each racecar. We can start by calculating the expected value of each racecar's payout:

Blue: 0.3 x 2 = 0.6

Red: 0.25 x 2.5 = 0.625

Purple: 0.18 x 3 = 0.54

Yellow: 0.1 x 5 = 0.5

Black: 0.08 x 7 = 0.56

Green: 0.05 x 10 = 0.5

Orange: 0.03 x 15 = 0.45

Pink: 0.01 x 50 = 0.5

Based on the expected value of payout, the most efficient bets would be on the racecars with the highest expected value. However, we also need to consider the probability of each racecar winning or placing in the top 3.

To maximize our chances of winning, we should bet on the racecars with the highest probability of winning or placing in the top 3, even if their expected payout is not the highest.

Assuming that if one racecar is likely to win but doesn't win, they are statistically most likely to come second, and so on, we can rank the racecars in terms of their probability of winning or placing in the top 3:

1. Blue - 30% chance of winning

2. Red - 25% chance of winning

3. Purple - 18% chance of winning

4. Black - 8% chance of winning

5. Yellow - 10% chance of winning

6. Green - 5% chance of winning

7. Orange - 3% chance of winning

8. Pink - 1% chance of winning

Based on this ranking, the most efficient bets would be as follows:

1. Bet on Blue for all 10 races. The expected payout is not the highest, but the probability of winning is the highest at 30%.

2. Bet on Red for all 10 races. The probability of winning is the second-highest at 25%.

3. Bet on Purple for all 10 races. The probability of winning is the third-highest at 18%.

Betting on these three racecars will give you the highest chance of winning or placing in the top 3, and therefore, the most efficient bets to increase your money. However, keep in mind that gambling always carries risks, and there is no guarantee of winning.

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Jerry will have $1825 in his account after 3 years and Jerry will have $6125 in his account after 10 year when compounded.

Simple interest is computed just using the principle, which is the initial sum borrowed or put into an investment. The interest rate is constant throughout time and solely applies to the principal sum. Short-term loans or investments frequently employ simple interest.

The given situation can be modeled as a linear equation given by:

y = mx + c

For Jerry we have:

y = 50x + 125

For 3 years = 36 months we can substitute x = 36:

y = 50(36) + 125

y = 1825

For x = 10:

y = 50(120) + 125

y = 6125

Hence, Jerry will have $1825 in his account after 3 years and Jerry will have $6125 in his account after 10 year.

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Answer:

Step-by-step explanation:

To find the normal plane and osculating plane, we first need to find the required derivatives.

x = 5t, y = t^2, z = t^3

dx/dt = 5, dy/dt = 2t, dz/dt = 3t^2

So, the velocity vector v and acceleration vector a are:

v = <5, 2t, 3t^2>

a = <0, 2, 6t>

Now, let's evaluate them at t = 1 since the point (5, 1, 1) is given.

v(1) = <5, 2, 3>

a(1) = <0, 2, 6>

The normal vector N is the unit vector in the direction of a:

N = a/|a| = <0, 1/√10, 3/√10>

Using the point-normal form of the equation for a plane:

normal plane equation = 0(x-5) + 1/√10(y-1) + 3/√10(z-1) = 0

Simplifying this equation we get:

5x + 2y + 3z = 30

The osculating plane can be found using the formula:

osculating plane equation = r(t) · [(r(t) x r''(t))] = 0

where r(t) is the position vector, and x is the cross product.

At t = 1, the position vector r(1) is <5, 1, 1>, v(1) is <5, 2, 3>, and a(1) is <0, 2, 6>.

r(1) x v(1) = <-1, 22, -5>

r(1) x a(1) = <12, -6, -10>

v(1) x a(1) = <-12, 0, 10>

Substituting these values into the formula, we get:

osculating plane equation = (x-5, y-1, z-1) · <12, -6, -10> = 0

Simplifying this equation we get:

3x - 15y + 5z = 5

Therefore, the equations for the normal plane and osculating plane at (5, 1, 1) are:

(a) 5x + 2y + 3z = 30

(b) 3x - 15y + 5z = 5

Decibel is a relative measure of signal loss or gain and is used to measure the logarithmic loss or gain of a signal.

What is a decibel?

Decibel, also known as dB, is a logarithmic unit that measures the intensity of a sound or the strength of an electrical or electromagnetic signal. A decibel measures the relative amplitude of a sound or signal, rather than its absolute magnitude. Because decibels are logarithmic, they are used to express both large and small differences in amplitude. A difference of 1 decibel corresponds to a power ratio of approximately 1.26 to 1.

Logarithmic measure: A logarithmic scale is a scale that has a constant ratio between successive values. Decibels, for example, are a logarithmic scale. The decibel scale is used to measure the amplitude of sound waves and electrical or electromagnetic signals. Because decibels are logarithmic, they can be used to express a wide range of signal levels, from very weak to very strong.

Relative measure: Relative measure is a measure that compares one value to another. It is used in a variety of fields, including statistics, physics, and engineering. Decibels are a relative measure because they compare one signal to another. They are used to express the relative gain or loss of a signal, rather than its absolute magnitude.

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To work out the percentage reduction, we need to find the difference between the original price and the reduced price, and express that difference as a percentage of the original price:

Original price = £12500

Reduced price = £11625

Difference = £12500 - £11625 = £875

Percentage reduction = (Difference / Original price) x 100%

= (£875 / £12500) x 100%

= 7%

Therefore, the percentage reduction in the price of the car is 7%.

Answer:

Step-by-step explanation:

Discount [tex]= \pounds12,500 -\pounds11625= \pounds875[/tex]

Percentage reduction [tex]=\frac{875}{12500} \times 100 = 7[/tex]

The price of a new car was reduced by 7%.

The function f(x) = x⁴ - 2x³ + 5 is concave downwards on the interval (0,1) and concave upwards everywhere else.

To determine the concavity of the function f(x) = x⁴ - 2x³ + 5, we need to find its second derivative f''(x).

f(x) = x⁴ - 2x³ + 5

f'(x) = 4x³ - 6x²

f''(x) = 12x² - 12x

The concavity of the function is determined by the sign of its second derivative.

If f''(x) > 0 for all x, the function is concave upwards.

If f''(x) < 0 for all x, the function is concave downwards.

Let's solve for f''(x) = 12x² - 12x:

12x² - 12x = 0

12x(x - 1) = 0

x = 0 or x = 1

When x < 0, f''(x) > 0, so the function is concave upwards.

When 0 < x < 1, f''(x) < 0, so the function is concave downwards.

When x > 1, f''(x) > 0, so the function is concave upwards.

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The given statements are True , False, False, True and True.

They are elaborated in points below:

(a) True:

Let x and y be even integers.

Then, by definition, x = 2a and y = 2b for some integers a and b.

Adding these equations, we get x + y = 2a + 2b = 2(a + b), which is an even integer. Therefore, the statement is true.

(b) False:

A counterexample is x = 1 and y = 3. Then x + y = 4, which is even, but neither x nor y is even.

Therefore, the statement is false.

(c) False:

A counterexample is x = -2 and y = 4. Then x² = (-2)²= 4 and y = 4² = 16, but x ≠ y. Therefore, the statement is false.

(d) True:

Since x < y, we have y - x > 0. Multiplying both sides by y + x, we get y² - x² > 0.

Rearranging the terms, we have x² < y².

Since x and y are both non-negative, we can take the square root of both sides to get x < y.

Therefore, the statement is true.

(e) True:

Since x and y are positive, we can take the square root of both sides of the inequality x < y to get √x < √y.

Then, multiplying both sides by √x + √y, we get x + 2√xy + y > x + y.

Since x + y is positive, we can divide both sides by x + y to get 1 + 2√(xy)/(x+y) > 1.

Rearranging the terms, we get √(xy) < (x + y)/2. Squaring both sides, we get xy < (x + y)²/4.

Simplifying, we get x²/4 - xy + y²/4 > 0. Rearranging the terms, we get (x - y/2)² > 0, which is always true since the square of any non-zero number is positive. Therefore, the statement is true.

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In the following question, among the conditions given, It can be given by Ymax = H(N*)So the maximum sustainable yield for a population governed by a Gompertz model and subjected to harvesting (either constant yield or constant effort) can be calculated using the above formula.

To find the maximum sustainable yield for a population governed by a Gompertz model and subjected to harvesting (either constant yield or constant effort) we will start with the formula of the Gompertz model that is, IN = r Nlog(K)Solution: Given that the population is governed by a Gompertz model = r Nlog(K)We know that the harvesting term that is responsible for the overexploitation of the resources, hence we can write the Gompertz model as dN/dt = rN[1 - N/K] - H(x)WhereH(x) can be a constant yield or constant effort in the harvesting term.

To find the maximum sustainable yield, we will use the concept of steady-state or equilibrium population level. Steady-state condition:dN/dt = 0Solving this equation gives us the steady-state population level, say N*.Now we need to calculate the maximum amount of resources that can be harvested sustainably. This maximum amount of resources harvested sustainably is called the maximum sustainable yield (MSY). It can be given by Ymax = H(N*)So the maximum sustainable yield for a population governed by a Gompertz model and subjected to harvesting (either constant yield or constant effort) can be calculated using the above formula.

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The probability that the 3rd card is a heart if the first card was a heart and the second card was a club is approximately 0.0152. It is the product of the probabilities.

The probability that the 3rd card is a heart if the first card was a heart and the second card was a club when three cards are drawn without replacement from an ordinary deck of 52 playing cards.

There are 13 hearts in a deck of 52 cards.

Therefore, P(1st card is a heart) = 13/52 = 1/4

There are 13 clubs in a deck of 52 cards. Since one heart is already drawn in the first card, there are only 51 cards left in the deck.

Therefore, P(2nd card is a club) = 13/51

There are only 12 hearts remaining in the deck since one heart is already drawn in the first card. There are only 50 cards left in the deck since two cards are already drawn.

Therefore, P(3rd card is a heart) = 12/50 = 6/25

The probability that the 3rd card is a heart if the first card was a heart and the second card was a club is:

P(3rd card is a heart | 1st card is a heart and 2nd card is a club) = P(1st card is a heart) × P(2nd card is a club) × P(3rd card is a heart) = (1/4) × (13/51) × (6/25) = 39/5,775 = 0.0152 (rounded to 5 decimal places)

Therefore, the probability that the 3rd card is a heart if the first card was a heart and the second card was a club is approximately 0.0152.

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The answer is option C: 109 shares. If the broker charges a set free of $7 per transaction. If the shares are worth $7.69/sh and you have $850 to invest 109 shares can you purchase.

What is probability?

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event.

To calculate the number of shares you can purchase, you need to subtract the broker's fee from the total amount you have to invest and then divide that by the share price:

$850 - $7 = $843 (the amount available to purchase shares)

$843 ÷ $7.69/share = 109.48

Since you cannot purchase a fraction of a share, you would be able to purchase 109 shares.

Therefore, the answer is option C: 109 shares.

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Answer:

proofs attached to answer

Step-by-step explanation:

proofs attached to answer

To solve the question asked, you can say:  So the dolphin's new location expressions is 3 feet above sea level. Option OD explains this process correctly and gives the correct answer. 

In mathematics, an expression is a set of numbers, variables, and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation that represent quantities or values. Expressions can be as simple as "3 + 4" or as complex as they can contain functions like "sin(x)" or "log(y)" . Expressions can be evaluated by substituting values ​​for variables and performing mathematical operations in the order specified. For example, if x = 2, the expression "3x + 5" is 3(2) + 5 = 11. In mathematics, formulas are often used to describe real-world situations, create equations, and simplify complex math problems. 

Move 3 units to the right on the outer diameter number line. Exit with -3. The dolphin was 3 feet below sea level.

To find the dolphin's new location, we need to determine the dolphin's direction of movement and distance traveled. In this case the dolphin swam to the bottom. This means it has moved in the negative direction on the number line. Then she swam three feet. This means she has moved 3 units to the right (or positive side) on the number line.

So we need to start at the dolphin's original position of -6 and move it 3 units to the right to -3. So the dolphin's new location is 3 feet above sea level. Option OD explains this process correctly and gives the correct answer. 

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Answer:

Let's use algebra to solve this problem.

Let's start by defining some variables to represent the number of cows and chickens the farmer sold. Let c be the number of cows and h be the number of chickens. We know that the farmer sold a total of 11 animals, so:

c + h = 11 (Equation 1)

We also know that the total amount of money the farmer received was $2475. The amount he received from selling cows was $350 times the number of cows, or 350c. The amount he received from selling chickens was $75 times the number of chickens, or 75h. So:

350c + 75h = 2475 (Equation 2)

Now we have two equations with two unknowns. We can solve for one variable in terms of the other in the first equation:

c + h = 11

c = 11 - h

We can substitute this expression for c into the second equation:

350c + 75h = 2475

350(11 - h) + 75h = 2475

Simplifying and solving for h:

3850 - 350h + 75h = 2475

-275h = -1375

h = 5

So the farmer sold 5 chickens. We can substitute this value of h back into the first equation to find c:

c + h = 11

c + 5 = 11

c = 6

Therefore, the farmer sold 6 cows and 5 chickens.

The value of the standard error of the mean in each of the following cases:

a. The population size is infinite = 1.4142

b. The population size is N = 50,000 = 1.4135

c. The population size is N = 5000 = 1.4073

d. The population size is N = 500 = 1.343

The standard error is a statistical technique used to measure variability. SE is the abbreviation. A statistic's or parameter estimate's standard error is the standard deviation of its sample distribution. It can be defined as an approximation of that standard deviation.

Standard error calculation:

σ = 10

n = 50

A) when size is infinite, the standard deviation of the sample mean is given by the formula;

σ_x' = σ/√n

Thus,

σ_x' = 10/√50

σ_x' = 1.4142

B) size is given, thus, the standard deviation of the sample mean is given by the formula;

σ_x' = (σ/√n)√((N - n)/(N - 1))

Thus, with size of N = 50,000, we have;

σ_x' = 1.4142 x √((50000 - 50)/(50000 - 1))

σ_x' = 1.4142 x 0.9995

σ_x' = 1.4135

C) at N = 5000;

σ_x' = 1.4142 x √((5000 - 50)/(5000 - 1))

σ_x' = 1.4073

D) at N = 500;

σ_x' = 1.4142 x √((500 - 50)/(500 - 1))

σ_x' = 1.343

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Therefore, the transfer function of the system is:

G(s) = Y(s) / U(s) = U(s) / (s^3 + 0.25s + 1.25)

In summary, the differential equation depicting the dynamics of a fourth Single-Input-Single-Output (SISO) system is y'''(t) + 0.25y'(t) + 1.25y(t) = u^2(t), and the transfer function of the system is G(s) = U(s) / (s^3 + 0.25s + 1.25).

The differential equation describing the dynamics of a single-input-single-output (SISO) system is given by ddy(t) + ay'(t) + by(t) = cdu(t), where y(t) is the output of the system, u(t) is the input of the system, and d, a, b, and c are constant coefficients representing the system dynamics.

For the given differential equation, which is the dynamics of four Single-Input-Single-Output (SISO) systems, we have:

[tex]y(t) + ay'(t) + by''(t) + cy'''(t) = u(t)[/tex]
Here, we have the third-order differential equatior : [tex]y'''(t) + 0.25y'(t) + 1.25y(t) = u^2(t)[/tex]

The given equation is a third-order, linear, time-invariant (LTI) differential equation. In control theory, a differential equation that relates the input u(t) to the output y(t) of a system is known as the transfer function.

The transfer function of the given system can be found by applying the Laplace transform to the differential equation:

s^3Y(s) + 0.25sY(s) + 1.25Y(s) = U^2(s)

where Y(s) and U(s) are the Laplace transforms of y(t) and u(t), respectively.

Solving for Y(s), we get:

Y(s) = U^2(s) / (s^3 + 0.25s + 1.25)

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Answer:

not sure if this sign � was important did it the best way I could

Step-by-step explanation:

To solve this problem graphically, we will first set up a system of inequalities based on the given information:

x ≥ 8 (Fatoumata must work at least 8 hours lifeguarding)

y ≤ 12 - x (Fatoumata can work at most 12 total hours)

15x + 10y ≥ 140 (Fatoumata must earn a minimum of $140)

To graph these inequalities, we can plot the points (8,0), (12,0), and (0,14) on a coordinate plane and draw lines connecting them. The line between (8,0) and (12,0) represents the constraint on the number of hours Fatoumata can work, while the line between (8,0) and (0,14) represents the constraint on the amount of money she must earn. The shaded region that satisfies all three inequalities is the feasible region.

To find one possible solution, we can pick any point within the feasible region. One such point is (8,6), which represents working 8 hours lifeguarding and 6 hours tutoring. This point satisfies all three inequalities:

x ≥ 8 is true since x = 8

y ≤ 12 - x is true since y = 6 ≤ 12 - 8

15x + 10y ≥ 140 is true since 15(8) + 10(6) = 180 ≥ 140

Therefore, one possible solution is for Fatoumata to work 8 hours lifeguarding and 6 hours tutoring to earn at least $140 while not exceeding 12 total hours worked.

If triangle ABC has points A(2, -4) B(-3, 1) C(-2, -6) and you perform the following transformations, B' would be located at B' (3, 2).

In Geometry, a reflection over or across the y-axis is represented and modeled by this transformation rule (x, y) → (-x, y). This ultimately implies that, a reflection over or across the y-axis would maintain the same y-coordinate (y-axis) while the sign of the x-coordinate (x-axis) would change from positive to negative or negative to positive.

By applying a reflection over the y-axis to the coordinate of the given point B (-3, 1), we have the following coordinates:

Coordinate B = (-3, 1)   →  Coordinate B' = (-(-3), 1) = (-3, 1).

Next, we would apply a rotation of 90° clockwise as follows;

(x, y)                               →            (y, -x)

Coordinate B' = (-3, 1) → Coordinate B' = (1, (-3)) = (1, 3)

Lastly, we would apply a translation (x + 2, y - 1) as follows:

Coordinate B' = (1, 3) → (1 + 2, 3 - 1) = B' (3, 2).

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Answer:

y = 90°

x = 63°

Step-by-step explanation:

The unknown y angle is a right angle, meaning it is a 90° angle.

We know a triangle is 180°. We know 2 angles one is 90°, one is 27°, so to find the other missing angle

We Take

180 - (27 + 90) = 63°

So,  x = 63°      y = 90°