HELP WILL GIVE BRAINLIEST
Which of the following adaptations would most likely help an animal survive the stressful environmental conditions found in the
Arctic?
OA
Ducks have webbed feet and an elongated body
OB.
Rattlesnakes have modified scales on the tips of their tails that form a rattle.
OC.
Bats can emit high-pitched sounds and navigate by echolocation
OD.
Reindeer have dense, woolly fur and hooves with high traction

Answer: All igneous rocks the basis of the rock cycle is formed by plate tectonics. ... This movement from igneous to sedimentary back to igneous is a major part of the rock cycle. The heat from the mantle that fuels plate tectonics causes both igneous and sedimentary rocks to be turned into metamorphic rocks.

Explanation: BRAINLEST?

Answer: The answer is Skill

Explanation:

Answer:

away from each other

Explanation:

Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges. The size of the force varies inversely as the square of the distance between the two charges.

here's the first part but for the 2nd one all I know is that the word "compression" goes on the spirals that are closer together.

hope this helps!

Answer:

An object is in motion when its distantance from another object is changing

Answer:

when an object is moving..

Explanation:

mark me as brainlist

Answer:

d

Explanation:

Answer:

D: wire

Explanation:

Answer:

Continents move

Explanation:

Answer:

87, not very hard but u have to keep trying ❤❤❤❤❤❤❤

Answer:

  v₂ = 2,665 m / s

Explanation:

This is an exercise of conservation of the momentum, we define a system formed by the two cars, so that the forces during the collision are internal and the moment is conserved.

Initial instant. Before the crash

           p₀ = m v_o

Final moment. Right after the crash

           p_f = m v₁ + M v₂

where the first car uses subscript 1 and has a mass m = 1 kg and the second car uses the subscript 2 with a mass M = 2kg

how the moment is preserved

        p₀ = p_f

         m v_o = m v₁ + M v₂

They indicate that the collision is elastic, therefore the kinetic energy is conserved, the velocity of the first car is v1 = -1.33 me / S

         v₂ = [tex]\frac{ m ( v_o - v_1)}{M}[/tex]

we calculate

        v₂ = [tex]\frac{ 1 ( 4 + 1.33)}{2}[/tex]

        v₂ = 2,665 m / s

The total amount of energy remains the same.

Answer:

atoms

Explanation:

they are the smallest

Answer:

4000 kg m/s

Explanation:

p=mv

substitute values into the formula above to get:

p=1000x4

p=4000 kg m/s

Answer:

imperial system

Explanation:

Answer:

british system

Explanation:

A P E X

Answer: Cuts and Scrapes

Explanation:

If something happens you could be hospitalized. You could get an amputation

Answer:

Specific heat capacity, = 2.1J/g°C

Explanation:

Given the following data;

Mass = 250g

Quantity of heat = 34.125kJ = 34.125 * 1000 = 34125 Joules.

Change in temperature = 65.0∘C

To find the specific heat capacity;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making c the subject of formula, we have;

[tex] c = \frac {Q}{mdt} [/tex]

Substituting into the equation, we have;

[tex] c = \frac {34125}{250*65} [/tex]

[tex] c = \frac {34125}{16250} [/tex]

Specific heat capacity, = 2.1J/g°C

Answer:

NARUTO IS A DIME GOD

Explanation:

Answer:

Explanation:

F = qE

F is the force in Newtons

q is the test charge

E is the electrical field produced by the source charge

[tex]5=q(50)\\q=1*10^-^1Coulombs[/tex]

The magnitude of charge on the object is of 0.1 C.

Given Data:

The magnitude of electric field is, E = 50 N/C.

The magnitude of Electric force is, F = 5 N.

The region where any particle feels the effect of electric force on itself, due to other charged entities, is known as Electric field. And the relation between the electric force and electric field is given as,

F = E × q

Here,

q is the magnitude of charge on the object.

Solving as,

q = F/E

q = 5 / 50

q = 0.1 C

Thus, we can conclude that the magnitude of charge on the object is of 0.1 C.

Learn more about the electric field here:

https://brainly.com/question/8971780

Answer:

A

My logic:

Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Universe.

Hope this helps!

An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.

Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.

Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.

Therefore, the correct option is C.

Learn more about Physical Weathering here:

https://brainly.com/question/29616084

#SPJ2

Answer:

0.33 hz

Explanation:

the formula for the frequency in this situation is f=v/wavelength

Answer:

My answer will be (D) . A few thousand years

Explanation:

Carbon-14 is a radioactive isotope of carbon, containing 6 protons and 8 neutrons, that is present in the earth's atmosphere in extremely low concentrations.2

It is naturally produced in the atmosphere by cosmic rays (and also artificially by nuclear weapons), and continually decays via nuclear processes into stable nitrogen atoms.

Suppose we have a sample of a substance containing some carbon-14. Let m be the mass of carbon-14 in nanograms after t years. 3

It turns out that, if the sample is isolated, then m and t approximately 4 satisfy the differential equation

dmdt=−0.000121m.

Suppose our sample initially contains 100 nanograms of carbon-14. Let's investigate what happens to the sample over time.

First, we can solve the differential equation. Since m has a continuous decay rate of −0.000121, a general solution to the differential equation is

m(t)=Ce−0.000121t,

where C is a constant. Substituting the initial condition t=0, m=100 gives C=100, so

m(t)=100e−0.000121t.

With this formula, we can calculate the amount m of carbon-14 over the years.

Mass of carbon-14 in sample

t (years) m (ng to 4 decimal places)

0 100.0000

100 98.7973

1000 88.6034

2000 78.5056

5000 54.6074

10 000 29.8197

20 000 8.8922

Every year, the mass m of carbon-14 is multiplied by e−0.000121≈0.999879. After 100 years, 98.7973 nanograms still remain. After 1000 years, we still have 88.6034 nanograms. But after 5000 years, however, almost half of the carbon-14 has decayed.

Graph showing the decay of 100 nanograms of Carbon-14.

Detailed description

half-life of carbon-14  

Example

How long does it take for precisely half of the carbon-14 in the sample to decay; that is, when does m=50? Give the answer to three significant figures.

Solution

The mass of carbon-14 in our sample is given by

m(t)=100e−0.000121t.

So we solve 50=100e−0.000121t, which gives e−0.000121t=12. Hence,

t=loge12−0.000121≈5730 years (to three significant figures).

The time period calculated in this example is called the half-life of carbon-14. In fact over any period of 5730 years, the amount of carbon-14 in an isolated sample will decay by half. This fact is used in radiocarbon dating to determine the age of fossils up to 60 000 years old. Roughly speaking, while an organism is alive, its interactions with its environment maintain a constant ratio of carbon-14 to carbon-12 in the organism; but after it dies, the carbon-14 is no longer replenished, and the ratio of carbon-14 to carbon-12 decays in a predictable way. (See Wikipedia Open new window for more on radiocarbon dating.)

Exercise 1

Explain why the mass of carbon-14 in the sample is given (approximately) by

m(t)=100(12)t5730,

and hence explain why the amount of carbon-14 in the sample decays by half over any period of 5730 years.

Half-life in general

In general, whenever a quantity x(t) obeys an exponential decay equation

x(t)=Cekt,

where the continuous decay rate k is negative, then the quantity x has a half-life T. After any time period of length T, the quantity x decreases by half. Let us see why.

As k is negative, the factor ekt decreases from 1 (at t=0) towards 0 (as t approaches ∞). Therefore there is a time t=T such that

ekT=12.

We now solve for T and obtain

kT=loge12=−loge2,

so

T=−1kloge2.

This T is the half-life. From time t=0 to time t=T, the factor ekt decreases from e0=1 to ekT=12, that is, decreases by half. Similarly, over any time period of length T, the term ekt decreases by half. 5

Note that, when k=−0.000121, we obtain T=5730, in agreement with our calculation for carbon-14.

Hope this work

If I'm wrong I'm sorry

If I'm right thank you (brainliest plz )

Answer & Explanation:

The acceleration due to gravity is about 10 m/s^2.

That means a the speed of a falling object will increase by 10 m/s every second that it falls.

We know that the lamp hits the ground at 15 m/s.

That means the lamp has been falling for

[tex]\frac{15 m/s}{10 m/s^{2} } = 1.5 s[/tex]

Now we use the formula  [tex]h = \frac{1}{2} gt^{2}[/tex]  to calculate the height, where

h is the height

g is the acceleration due to gravity and

t is the time taken to fall a height of h.

h = 1/2 x 10 x 1.5^2 = 11.25 m

Complete Question:

A coin is dropped off of a building landing on its side. It hits with a pressure of 400 N/m². It hits with a force of 0.1N. Calculate the area of the coin?

Answer:

Area = 0.00025 m²

Explanation:

Given the following data;

Pressure = 400N/m²

Force = 0.1N

To find the area of the coin;

Pressure = Force/area

Area = Force/pressure

Substituting into the equation, we have;

Area = 0.1/400

Area = 0.00025 m²