How did Hypatia contribute to the study of philosophy? She became a teacher at Alexandria. She improved upon the works of Plato. She was educated in both science and mathematics. She studied Euclid’s theories and proved them incorrect.

Answers

Answer 1

Answer:

she improved upon the works of plato

Answer 2

Answer: A she became a teacher at Alexandria

Explanation:


Related Questions

The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat's average kinetic energy? (1 kJ = 1000 J)

Answers

Answer:

69.44kJ

Explanation:

Kinetic energy is expressed as;

KE = 1/2mv^2

m is the mass = 500kg

v is the velocity

Get the velocity;

v = displacement/time

velocity = 2000/120

velcoity = 16.7m/s

Gt the kinetic energy

KE = 1/2 * 500 * 16.7²

KE = 250*277.78

KE = 69,444.4Joules

Since 1000J = 1kJ

69,444.4Joules = 69,444.4/1000

69,444.4Joules = 69.44kJ

Hence the Secretariat's average kinetic energy is  69.44kJ

Answer:C 69.0kJ

Explanation:

Which of the four spheres is this pictures/scene?
A) hydrosphere
B) biosphere
C) geosphere
D) atmosphere

Answers

I believe the correct answer is atmosphere (D).

Answer:

D) atmosphere

Explanation:

but the correct answer is troposhare

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What is a selectively permeable membrane?????????????

Answers

Answer:

It is that kind of permeable membrane that allows certain molecules to pass through. Not every molecules can pass through it

Explanation:

If a current of 2.5 Ampere flow through a circuit in 15 minutes calculate amount of charge through a crcuit

Answers

Answer:

Q = 2250 Coulombs

Explanation:

We are given;

Current: I = 2.5 A

Time: t = 15 minutes = 15 × 60 seconds = 900 s

Now formula for the amount of charge through the circuit is given by:

Q = It

Thus;

Q = 2.5 × 900

Q = 2250 Coulombs

John is pushing (horizontally) on a 100 kg (Fw = 980N) bench with an unknown force. If the coefficient of static friction is 0.20 and the acceleration is 1.84m/s/s, what is the applied force?

Answers

Answer:

1176N

Explanation:

Given parameters:

Mass of bench  = 100kg

Forward force  = 980N

Coefficient of static friction = 0.2

Acceleration  = 1.84m/s²

Unknown:

Magnitude of the applied force  =?

Solution:

Frictional force is a force that opposes motion, for a body to move, the applied force must be greater than the frictional force;

The Force applied;

  Force applied  = Frictional force + Weight of the body

   Frictional force  = umg

     u is the coefficient of static friction

      m is the mass

        g is the acceleration due to gravity

    Force applied  = 0.2 x 100 x 9.8 + 980 = 1176N

A hunter shoots a tranquilizer dart straight at a monkey who is
hanging on a tree branch that is 1.5 meters high. The tree is 16 meters
away from the hunter. The man shot the dart at the monkey with an
initial sideways velocity of 40 m/s, and at the same time, the monkey
let go of the branch. what time will the monkey reach the same height
of the arrow?
t= _S

Answers

Answer:

The donkey might be dead

What is a joule? Pls only answer if you know the answer.

Answers

Answer:

the SI unit of work or energy, equal to the work done by a force of one newton when its point of application moves one meter in the direction of action of the force, equivalent to one 3600th of a watt-hour.

Explanation:

Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.

what are the uses of X-rays.​

Answers

Explanation:

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A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11- Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.

Answers

Answer:

[tex]a=2.4\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]

So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].

A man pushes a crate along a factory floor by exerting a force of 55 N. If
the crate moves a distance of 4.0 m, how much work does the man
perform?

Answers

Answer:

it's 220 J

the second one

The dead sea has a very high salt content. Explain why it is easier for a swimmer to float in the dead sea than in a swimming pool containing fresh water

Answers

Answer:

Dead sea is full of salt.

Explanation:

The water of the Dead Sea is full of salt, which makes it much denser and heavier than freshwater. If you swim in it, you float very easily.

When salt is dissolved in water, for example sea water, dissolved salt adds to the mass of the water and makes the water denser than it would be without salt. Because objects float better on a dense surface, they float better on salt water than fresh water.

On an air track, a 4-kg cart moving at 3 m/s collides with a 2-kg cart that is
initially at rest. If the two carts stick together, what will be their velocity
after the collision? Show all calculations, including any equation(s) used,
and include correct measurement units. *
Your answer

Answers

Answer:

v₃ = 2 [m/s]

Explanation:

To solve such problems we must use the principle of conservation of momentum. That is, the linear momentum is conserved before and after the collision.

P = m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

The momentum is conserved before and after the collision, in this way we can obtain the following equation.

[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]

where:

m₁ = mass of the cart moving = 4 [kg]

v₁ =  velocity of the cart moving before the collision = 3 [m/s]

m₂ = mass of the cart initially at rest = 2 [kg]

v₂ = velocity of the cart at rest = 0

v₃ = velocity of the two carts combined (carts stick together) after the collision [m/s]

[tex](4*3)+(2*0)=(4+2)*v_{3}\\v_{3}=12/6\\v_{3}=2[m/s][/tex]

At which point is the kinetic energy the greatest?

Answers

Answer:

Kinetic energy is energy an object has because of its motion and is equal to one-half multiplied by the mass of an object multiplied by its velocity squared (KE = 1/2 mv2). Kinetic energy is greatest at the lowest point of a roller coaster and least at the highest point.

Explanation:

here is an example Where is the apple when it has the most kinetic energy? When the apple is falling and is right before it hits the ground. As an object falls under the influence of gravity, kinetic energy and potential energy are equal everywhere/at the halfway point only. 10. As an object falls under the influence of gravity, potential energy is greater than kinetic energy after halfway point/ before the halfway point

In the roller coaster, the kinetic energy is greatest at point X.

The kinetic energy of a body is given by 1/2mv^2.

Where;

m = mass of the object

v =velocity of the object.

For a roller coaster, the velocity is maximum at the lowest points of the roller coaster. If the velocity is maximum at the lowest point, it also follows that the kinetic energy is also maximum at the lowest point. Hence point X has the highest kinetic energy.

Learn more: https://brainly.com/question/999862

1. Why do we need to travel?​

Answers

Answer:

We're like children who move away from their parents - then back,

HUMANS LOVE to travel. Mentally or physically, they escape to other places. They crave adventure. They seek the unknown. They want to see new places, learn new things, enjoy new experiences and then return home to the familiar, the predictable, the secure, before taking off again on their travels.

This departure-return behaviour has its origins, perhaps, in the early exploratory behaviour of the child. Research has shown that children who are "securely attached" to their parents, sure of their affection and protection, and who know that their parents will respond to their needs, are more independent, adventurous and exploratory in their play and behaviour.

Observations of infants show that from the safe base of having a parent present and available, the infant dares to move away a short distance and then return to the parent, to move a little further and return, until in incremental and amazingly measurable distances it explores the environment that surrounds it and has the courage to move beyond it.

This may be the first symbolic travel: the first departure, the first expedition and the possible beginning of the travel bug for those for whom their initial independent voyaging was successful.

With these first independent steps away from the parental presence lies the atavistic or recurring wish to reach out beyond the current confines of space and relationship

and see what is further away. And yet further again to see what is not visible, what is around the next corner, in the next room and eventually on

the other side of our geographical or psychological world. This is a human need. It is why we have uncovered our world, travelled its length, hiked to the top of its mountains and the depth of its oceans. It is why we became discontent with exploring our own plant but had to move beyond it into the unknown. It is why, as poet TS Eliot reminds us, we will "not cease from exploration".

It is our nature to travel. It is our joy to travel. It is our paradoxical psychological disposition to wish for the contradictory conditions of stability and change: to stay and to go, to be and to explore, to rest and to travel unceasingly.

Travel is more than going somewhere. It is a psychological event. It requires motivation and imagination. It begins in childhood with faltering first steps and with imagination fired by the tales of "long, long ago in a faraway land".

We emerge from these fantasies of childhood determined to cross the oceans, to find those faraway lands, the characters they containand the magic they hold. Determined to find the adventures they promise and the prospect of returning home triumphant with trophies having vanquished all fear, overcome all obstacles and live happily eve after.

Answer:

to see the world and experience new things. it opens your mind and you can meet more people. you have a new view on the world after seeing it from other places, not only new views on the world but new cultures, and languages.

Explanation:

What is a gravitational field, and how does it apply to Earth? what is its formula​. and what is an example of how you can use it?

Answers

Answer:

Explanation:

a gravitational field is the region of space surrounding a body in which another body experiences a force of gravitational attraction.

The formula is: weight/mass = gravitational field strength. On Earth the gravitational field strength is 10 N/kg.

an example of how you can use it if you need to find the gravitational force from earth.

A long-jumper leaves the ground at an angle of 20.0° above the horizontal and at a speed of 11.0 m/s.How far does he jump in the horizontal direction?(Assume his motion is equivalent to that of a particle.).
a. 12m
b. 7.94m
c. 10m
d. 0.384m​

Answers

Answer:

The correct option is;

b. 7.94 m

Explanation:

The given parameters of the jump of the long jumper are;

The angle above the horizontal with which the long jumper leaves the ground, θ = 20.0°

The speed with which the long jumper leaves the ground, u = 11.0 m/s

The furthest horizontal distance the long jumper jumps, given that the motion is equivalent to that of a particle, is given by the formula for the range, R, of a projectile motion as follows;

[tex]R = \dfrac{u^2 \times sin \left (2 \cdot \theta \right )}{g}[/tex]

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

u = The initial velocity of the long-jumper = 11.0 m/s

θ = The angle of the direction above the horizontal the long-jumper jumps = 20.0°

Plugging in the values, gives;

[tex]R = \dfrac{(11.0 \ m/s)^2 \times sin \left (2 \times 20.0 ^{\circ} \right )}{9.8} = \dfrac{121 \ m^2/s^2 \times sin \left (40.0 ^{\circ} \right )}{9.8 \ m/s^2} \approx 7.94 \ m[/tex]

How far the long-jumper goes = The range, R, of the projectile motion ≈ 7.94 m.

A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum of the box? (unit = kg*m/s)

Answers

Answer:

63.8454kgm/s

Explanation:

According to Newton's second law;

Force = mass ×acceleration

Fore = m(v-u)/t

Force = mv-mu/t

MV is the final momentum

mu is the initial momentum = 38kgm/s

Force = 88.3N

Time = 0.338s

Substitute and get mv

88.3 = mv-38/0.338

88.3×0.338 = mv-38

29.8454 = mv-38

MV = 29.8454+34

mv = 63.8454kgm/s

Hence the final momentum is 63.8454kgm/s

Answer:

67.8

Explanation:

im an acellus student, and this is the answer that i got when doing the problem.

Which term best matches the description of an earthquake?

Where all mass movements occur

Acts as a lubricant to reduce friction between soil grains

Determines how much material is available for mass movement

Occurs when a sheet of rock moves downhill on a sliding surface

Can trigger a sudden mass movement

A force that works to pull material downslope

Answers

can tigger sudden mass movement

help please 10 pts and quick!

Answers

Answer:

A

Explanation:

A child's first bicycle has 12-inch tires. These tires have a 6-inch radius. How fa r does the bicycle move forward each time the wheel makes one complete rotation? Give your answer in meters. (1 inch = 0.022 meters) b. A woman's ten-speed bicycle has 27-inch tires (13.5-inch radius). How far does this bicycle …

Answers

Answer:

a. s = 0.96 m

b. s = 2.15 m

Explanation:

a.

The relationship between the linear displacement and the angular displacement is given as follows:

[tex]s = r\theta[/tex]

where,

s = linear distance covered = ?

r = radius of wheel = (6 in)(0.0254 m/1 in) = 0.1524 m

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad

Therefore,

[tex]s = (0.1524\ m) 2\pi[/tex]

s = 0.96 m

b.

Assuming, we have to find linear displacement here, as well:

[tex]s = r\theta[/tex]

where,

s = linear distance covered = ?

r = radius of wheel = (13.5 in)(0.0254 m/1 in) = 0.3429 m

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad

Therefore,

[tex]s = (0.3429 \ m) 2\pi[/tex]

s = 2.15 m

A 1000-kg car comes to a stop without skidding. The car's brakes do 50,000 J of work to stop the car. Which of the following was the car's velocity when the brakes were initially applied?

Answers

Answer:

10m/s

Explanation:

What scientific law did Archimedes establish? the law of geometry the law of astronomy the law of lever and balance the law of Earth and universe

Answers

Answer:

Archimedes discovered the buoyancy laws

Explanation:

when asked by King Hiero of Syracuse to determine whether his new crown was pure gold (SG = 19.3). Archimedes measured the weight of the crown in air to be 11.8 N and its weight in water to be 10.9 N.

Answer:

The correct answer is C

Explanation:

What is the correct answer?

Answers

Answer:3

Explanation:

how high above the ground is a 3 kg object that has 147 J (joules) of potential energy

Answers

Answer:

4.9949

Explanation:

M = 3 kg

P.E = 147 joules

G = 9.81 ms^-2

H = ?

P.E = MGH

147 = 3 x 9.81 x H

147 = 29.43H

147/29.43 = 29.43H/29.43

4.9949 = H

:. H = 4.9949

where would you expect light waves to move faster?

Answers

Answer:

In space

Explanation:

I took the quiz

Answer:

in space

Explanation:

Madeline fires a bullet horizontally. The rifle is 1.9 meters above the ground. The bullet travels 200 meters horizontally before it hits the ground. What speed did Madeline's bullet have when it exited the rifle?

Answers

Answer: 321.027 m/s

Explanation:

First let´s analyze the vertical problem:

Always when an object is above the ground and nothing is holding it (like the bullet after being fired) the gravitational force will start acting on it.

Then the vertical acceleration of the bullet will be the gravitational acceleration, we can write this as:

a(t) = -g

Where g = 9.8m/s^2

and the negative sign is because this acceleration pulls the bullet downwards.

To get the vertical velocity we need to integrate over time, this will lead to:

v(t) = (-9.8m/s^2)*t + v0

where v0 is the initial vertical velocity, as the bullet is fired horizontally, there is no initial vertical velocity, then we have v0 = 0m/s

And the velocity equation is:

v(t) = (-9.8m/s^2)*t

Now for the vertical position, we need to integrate again, to get:

p(t)  =(1/2)*(-9.8m/s^2)*t^2 + p0

Where p0 is the initial vertical position, in this case, is 1.9 meters above the ground, then p0 = 1.9m

And the vertical position equation will be:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + 1.9 m

Now we want to find the time such that the vertical position is equal to zero, this will mean that the bullet it the ground.

p(t) = 0m = (1/2)*(-9.8m/s^2)*t^2 + 1.9 m

    (1/2)*(9.8m/s^2)*t^2 = 1.9m

    (4.9m/s^2)*t^2 = 1.9m

                  t = √(1.9m/(4.9m/s^2)) = 0.623 seconds.

This means that the bullet will travel for 0.623 seconds before hitting the ground.

Now we also can ignore the air friction for the horizontal motion, then we can assume that the horizontal speed does not change.

Then we can use the relationship:

Distance = speed*time

We know that:

time = 0.623 seconds

distance = 200m

now we can replace that in the equation to find the horizontal speed.

200m = speed*0.623s

200m/0.623s = speed = 321.027 m/s

 

You used 100 N of force to push a shopping cart 5m down the aisle in the grocery store. How much work did you do? *

Answers

Answer:

[tex]\boxed {\boxed {\sf 500 \ Joules}}[/tex]

Explanation:

Work can be found by multiplying the force by the distance.

[tex]W=F*d[/tex]

The force is 100 Newtons and the distance is 5 meters. Therefore,

[tex]F= 100 \ N \\d= 5 \ m[/tex]

We can substitute the values into the formula.

[tex]W= 100 \ N * 5 \ m[/tex]

Multiply.

[tex]W= 500 \ N*m[/tex]

1 Newton meter is equal to 1 Joule. Thus, our answer of 500 Newton meters is equal to 500 Joules.

[tex]W= 500 \ J[/tex]

You did 500 Joules of work to push a shopping cart 5 meters with a force of 100 Newtons.

Answer:

Given :-Force (F) = 100 NDisplacement (D) = 5 mTo Find :-

Work done

Solution :-

As we know that Work done is the product of Force and displacement

[tex] \tt \: w = force \: \times displacement[/tex]

[tex] \tt \: w = 100 \times 5[/tex]

[tex] \tt \: w = 500 \: j[/tex]

Therefore, Work done is 500 Joule

a_______ is a region where the magnetic fields of a large number of atoms are lined up parallel to a magnets field.

Answers

Answer:

Magnetic Domain

Explanation:

magnetic domain is the answer

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How are ribosomes different from other complex animal cell organelles?

Answers

Explanation:

Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing

How long does it take the lava bomb to reach its maximum height? Answer with three significant digits and the correct unit. A small volcano's steam pressure belches vertically upward a lava bomb from an initial height of 64.4 m and with an initial upward velocity of 31.4 m/s. Remember gravity's acceleration near earth is g = 9.8 m/s2 down.

Answers

Answer:

The time taken to reach the maximum height is 3.20 seconds

Explanation:

The given parameters are;

The initial height from which the volcano erupts the lava bomb = 64.4 m

The initial upward velocity of the lava bomb = 31.4 m/s

The acceleration due to gravity, g = 9.8 m/s²

The time it takes the lava bomb to reach its maximum height, t, is given by the following kinematic equation as follows;

v = u - g·t

Where;

v = The final velocity  = 0 m/s at maximum height

u = The initial velocity = 31.4 m/s

g = The acceleration due to gravity = 9.8 m/s²

t = The time taken to reach the maximum height

Substituting the values gives;

0 = 31.4 - 9.8 × t

∴ 31.4 = 9.8 × t

t = 31.4/9.8  ≈ 3.204

The time taken to reach the maximum height rounded to three significant figures = t ≈ 3.20 seconds

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zapatos son azules. * el la los las Fractions please help ? one more ferda yk +100 cause i love you Should japen be considered a nation Is it true that students should be smartand self-aware enough that teachers like Mr. Blessingtonshouldn't affect them? A wave on a lake has a wavelength of 5.0 M and a Frequency of 4 Hz. What is the speed of the wave in m/s? What is the slope of a line perpendicular to the given line plz define light-dependent reactions Boy In The Bubble By Alec Benjamin.It was 6:48, I was walking homeStepped through the gate, and I'm all aloneI had chicken on the plate, but the food was coldThen I covered up my face so that no one knowsI didn't want trouble, I'm the boy in the bubbleBut then came troubleWhen my mom walked into the living roomShe said, "Boy, you gotta tell me what they did to you"I said, "You don't wanna know the things I had to do"She said, "Son, you gotta tell me why you're black and blue"I said I didn't want trouble, I'm the boy in the bubbleBut then came troubleAnd my heart was pumping, chest was screamingMind was running, air was freezingPut my hands up, put my hands upI told this kid I'm ready for a fightPunch my face, do it 'cause I like the painEvery time you curse my nameI know you want the satisfaction, it's not gonna happenKnock me out, kick me when I'm on the groundIt's only gonna let you downCome the lightning and the thunderYou're the one who'll suffer, sufferWell, I squared him up, left my chest exposedHe threw a quick left hook and it broke my noseI had thick red blood running down my clothesAnd a sick, sick look 'cause I like it thoughI said I didn't want trouble, I'm the boy in the bubbleBut then came troubleAnd my heart was pumping, chest was screamingMind was running, nose was bleedingPut my hands up, put my hands upI told this kid I'm ready for a fightPunch my face, do it 'cause I like the painEvery time you curse my nameI know you want the satisfaction, it's not gonna happenKnock me out, kick me when I'm on the groundIt's only gonna let you downCome the lightning and the thunderYou're the one who'll sufferIt was 6:48, he was walking homeWith the blood on his hands from my broken noseBut like every other day, he was scared to goBack to his house 'cause his pops was homeDrowning his troubles in whiskey bubblesJust looking for troubleWell, there's no excuse for the things he didBut there's a lot at home that he's dealing withBecause his dad's been drunk since he was a kidAnd I hope one day that he'll say to him"Put down those bubbles and that belt buckleIn this broken bubble"Punch my face, do it 'cause I like the painEvery time you curse my nameI know you want the satisfaction, it's not gonna happenKnock me out, kick me when I'm on the groundIt's only gonna let you downCome the lightning and the thunderYou're the one who'll suffer, suffer Betty is three times as old as her son now. In 12 years, Betty's age will be three years less than twice her son's age. How old is Betty's son now? For a field trip 5 students rode in cars and the rest filled ten buses. How many students were in each bus if 215 students were on the trip? Determine the velocity of a wave with frequency 10Hz and a wavelength of 10m. What is the mean of the measures of the three exterior angles of a triangle if two of the interior angles have measures of 63 and 78 degrees? Automobiles arrive at the drive-through window at a post office at the rate of 7 every 10 minutes. The average service time is 7 minutes. The Poisson distribution is appropriate for the arrival rate and service times are exponentially distributed. (Note: the given equations are NOT necessarily in the correct order.) What is the average time a car is in the system?Formulas for 13.17 What is the average number of cars in the system? What is the average time cars spend waiting to receive service? What is the average number of cars in line behind the customer receiving service? What is the probability that there are no cars at the window? What percentage of the time is the postal clerk busy? What is the probability that there are exactly two cars in the system? Which of the following observations does NOT support the nebular hypothesis for the formation of the solar system?A the planets revolve around the Sun in the same directionB the orbital planes of the planets are nearly the sameC huge tidal waves on the SunD inner planets are small and rocky and the outer planets are made of ice and gas Plz answer this(5x^2-3x+1)-(4x+2x^2-2) You pay $18.00 for 30 text messages. At the same rate, how much would 12 text messages cost? * For the chemical reaction:N2 (g)+H2(g)=NH3 (g)Calculate the volume of NH; that will form from 200 dm cubed of N2 at STP. (N = 14; H - 1)[At STP. 1 mole of any gas occupies volume of 22 A dm cubed Is NaHCO3 a compound? Explain pls! Which of the following is equal to 16.4 ?O A. 32O B. V16.4O c.D. 64