Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3-2i}{1+i}\cdot\dfrac{1-i}{1-i} - \dfrac{5+3i}{1+2i}\cdot\dfrac{1-2i}{1-2i}[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{(3-2i)(1-i)}{1-i^2} - \dfrac{(5+3i)(1-2i)}{1-(2i)^2}[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 2i - 3i + 2i^2}{1-(-1)} - \dfrac{5 + 3i - 10i - 6i^2}{1-4(-1)}[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2 - \dfrac{11 - 7i}5[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{5 - 25i - 22 + 14i}{10}[/tex]
[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = -\dfrac{17 + 11i}{10}[/tex]
So, the equation is simplified to
[tex]-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5[/tex]
Let's combine the fractions on the right side:
[tex]\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22[/tex]
[tex]\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}[/tex]
Then
[tex]-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}[/tex]
reduces to
[tex]-(17+11i) z = 5-4i[/tex]
Multiply both sides by -1/(17 + 11i) :
[tex]\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}[/tex]
[tex]z = -\dfrac{5-4i}{17+11i}[/tex]
Finally, simplify the right side:
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}[/tex]
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{(5-4i)(17-11i)}{17^2-(11i)^2}[/tex]
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44i^2}{289-121(-1)}[/tex]
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44(-1)}{410}[/tex]
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 123i}{410}[/tex]
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 41\cdot3i}{410}[/tex]
[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{1 - 3i}{10}[/tex]
So, the solution to the equation is
[tex]z = -\dfrac{1-3i}{10} = \boxed{-\dfrac1{10} + \dfrac3{10}i}[/tex]
The force in Newtons acting on a particle located x meters from the origin is given by the function F(x)=12x2+7. What is the work done in Joules when moving the particle from x=2 to x=5?
[tex]W = \displaystyle \int^{5}_{2} F(x) ~ dx\\\\\\= \displaystyle \int^{5}_{2} \left(12x^2 +7\right) ~dx\\\\\\= 12\displaystyle \int^{5}_{2} x^2 ~dx + \displaystyle \int^{5}_{2} 7~ dx\\\\\\=12 \left[\dfrac{x^3}3 \right]^{5}_{2} + 7\left[x\right]^{5}_{2}\\\\\\=4(5^3-2^3) + 7(5-2) = 468 + 21 = 489~ J[/tex]
Precalculus graph function help please
2x+5y=(-24),3x+y=(-10) solve for using elimination method
Answer:
x equals -2 and y equals−4
 Missed 10 days of Algebra 2. I think they did some Long Division stuff but i need help figuring out how to do this stuff...
I attached an image below of some example problems
"Find all real solutions of" basically means solve for x. You're looking for the real numbers x such that the given equation is satisfied. "Zeros" is synonymous with "solutions".
It looks like the first equation is
3x³ + x² - 38x + 24 = 0
It's not immediately obvious whether this can be factorized, so we first carry out the rational zero test to see if there are any rational solutions. *If* this equation has any rational solutions, then they must take the form of (divisor of 24)/(divisor of 3). That is, take any divisor of the constant coefficient and divide it by any divisor of the leading term's coefficient.
We have
• divisors of 24 : ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24
• divisors of 3 : ±1, ±3
Sadly, there are 64 possible roots to test, but we only need one to make the rest of the problem easier.
• Let x = +1 / +1 = 1. Then plugging x = 1 into the equation gives
3•1³ + 1² - 38•1 + 24 = -10 ≠ 0
so x = 1 is *not* a solution
• Let x = +2 / +1 = 2. If x = 2, then
3•2³ + 2² - 38•2 + 24 = -24 ≠ 0
so x = 2 is *not* a solution.
• Let x = +3 / +1 = 3. If x = 3, then
3•3³ + 3² - 38•3 + 24 = 0
so x = 3 is a solution.
By the remainder theorem, this means that x - 3 divides 3x³ + x² - 38x + 24. Using long or synthetic division,
(3x³ + x² - 38x + 24) / (x - 3) = 3x² + 10x - 8
so that
3x³ + x² - 38x + 24 = 0
is the same as
(x - 3) (3x² + 10x - 8) = 0
We factorize the remaining quadratic to get
3x² + 10x - 8 = (3x - 2) (x + 4)
and so the original equation is equivalent to
(x - 3) (3x - 2) (x + 4) = 0
Solve for x :
x - 3 = 0 or 3x - 2 = 0 or x + 4 = 0
x = 3 or x = 2/3 or x = -4
The other equations can be solved similarly, though some of the others you included are much simpler.
For the second problem (note that you left out an exponent), we solve the equation
x³ - 2x² - 23x + 60 = 0
Again, not immediately obvious how to factorize this. But using the rational root test, we have
• divisors of 60 : ±1, ±2, ±3, ±4, ±5, ±6, ±10, ±12, ±15, ±20, ±30, ±60
• divisors of 1 : ±1
If you follow the same steps as before, you'll find the first rational solution with x = 3. So x - 3 divides x³ - 2x² - 23x + 60, and long division gives
(x³ - 2x² - 23x + 60) / (x - 3) = x² + x - 20
and the resulting quadratic is easily factored,
x² + x - 20 = (x - 4) (x + 5)
So, we have
x³ - 2x² - 23x + 60 = (x - 3) (x - 4) (x + 5) = 0
which means
x - 3 = 0 or x - 4 = 0 or x + 5 = 0
x = 3 or x = 4 or x = -5
For the third problem, we can factor by grouping.
x³ - 4x² - x + 4 = 0
x² (x - 4) - (x - 4) = 0
(x² - 1) (x - 4) = 0
(x - 1) (x + 1) (x - 4) = 0
Then
x - 1 = 0 or x + 1 = 0 or x - 4 = 0
x = 1 or x = -1 or x = 4
For the fourth problem, we use the rational root test again, but twice this time.
x⁴ - 6x³ + 7x² + 6x - 8 = 0
• divisors of -8 : ±1, ±2, ±4, ±8
• divisors of 1 : ±1
We find that x = 1 and x = 2 are both rational roots, so both x - 1 and x - 2 divide x⁴ - 6x³ + 7x² + 6x - 8. By long division,
(x⁴ - 6x³ + 7x² + 6x - 8) / ((x - 1) (x - 2)) = x² - 3x - 4
and factoring this gives
x² - 3x - 4 = (x + 1) (x - 4)
So, we have
x⁴ - 6x³ + 7x² + 6x - 8 = (x - 1) (x - 2) (x + 1) (x - 4) = 0
which means
x - 1 = 0 or x - 2 = 0 or x + 1 = 0 or x - 4 = 0
x = 1 or x = 2 or x = -1 or x = 4
For the last problem,
x⁴ + 4x³ + 7x² + 16x + 12 = 0
we use the rational root test again.
• divisors of 12 : ±1, ±2, ±3, ±4, ±6, ±12
• divisors of 1 : ±1
We find that both x = -1 and x = -3 are rational solutions, and dividing gives
(x⁴ + 4x³ + 7x² + 16x + 12) / ((x + 1) (x + 3)) = x² + 4
which we cannot factorize further over the real numbers. So we end up with
x⁴ + 4x³ + 7x² + 16x + 12 = (x + 1) (x + 3) (x² + 4) = 0
so that
x + 1 = 0 or x + 3 = 0 or x² + 4 = 0
x = -1 or x = -3
(We omit the third equation here because it has no real solution since x² + 4 ≥ 4 for all real x.)
this cubiod is made from 6 small cubes write how many small cubes there are in this cubiod
Pleas help
Answer:
16 I guess.
Step-by-step explanation:
lolololololol?
Miles is 33 year old and single in 2020 his only income consisted of $10500 in wages what is the maximum amount he can contribute to a traditional ira for 2020
Answer:
$6,000
Step-by-step explanation:
$6,000 Because miles younger than 50
Fiill in the table using this function rule. Y=-3x+3
Answer:
3(x+1)
Step-by-step explanation:
Find the value of x that makes the equation true.
2 = -x
9514 1404 393
Answer:
x = -2
Step-by-step explanation:
Multiply both sides of the equation by -1.
(-1)(2) = (-1)(-x)
-2 = x
The value of x that makes the equation true is x = -2.
Pls answer will give brainiest
Answer:
D. is your answer
1. Reducing the original price of an item is often called
discounting
selling
bartering
originating
15 mm
4. You are decorating the Red Cross logo
shown for a float in a parade.
a) The Red Cross logo consists of 5 congruent
squares. Find the area of the Red Cross logo.
+
b) You estimate that on average a red carnation
will cover 2 square inches and a red rose will cover
3 square inches. How many roses do you need to
cover the logo on the float?
36 in
c) You are on a budget. Carnations cost $1.00 and
roses cost $1.50. Should you cover the logo with
carnations or roses? Justify your answer.
The picture below shows the graph of which inequality?
Answer A is correct.
Step-by-step explanation:
Negative one is less than one.
Use the GCF and the distributive property to find each sum 15 + 57
Answer:
(3*5)+(19*3)
Step-by-step explanation:
both numbers GCF is 3.
(3*5)=15
(19*3)=57
15+57=72
Hope that helps
1/4 of students in a class play a musical instrument of those students 2/5 also speak a second language. What fraction of the whole class plays a musical instrument and speak a second language
Answer:
Step-by-step explanation:
Say the class has 20 students
20(1/4) = 5 play instruments
5(2/5) = 2 speak a second language
2 / 20 = 1/10
the table shows the pricing for four different types of gasoline which type cost the least per gallon a $20.20 for 10 galb $26.04 for 12 gal c $28.14 for 14 gal d $30.45 for 15 gal
Answer:
A is the cheapest deal.
Step-by-step explanation:
find unit rate; cost / quantity
20.20 / 10 = $2.02 per gallon
26.04 / 12 = $2.17 per gallon
28.24 / 24 = $2.01 per gallon
30.45 / 25 = $2.03 per gallon
the price of 10 chairs is equal to that of 4 tables. the price of 15 chairs and two tables together is 4000$ the total price ( in $) of a chair and table is?
Answer:
$700 for a chair and a table
Step-by-step explanation:
Let t and c represent the price of a table and a chair, respectively. The given relations are ...
10c = 4t
15c +2t = $4000
Divide the first equation by 2 and substitute for 2t:
5c = 2t
15c +5c = $4000
20c = $4000
c = $200
t = 5c/2 = 5($200)/2 = $500
The total price of a chair and a table is ...
$200 +500 = $700 . . . . price of a chair and a table
Please use image above ^^
Answer:
D or answer choice 4
Step-by-step explanation:
is {(-2,1),(-1,2),(0,3),(1,4) } a function?
Think of it this way, a function must pass the vertical line test. There may not be 2 outputs for one input for example (0, 1) (0, 2) However, you can have something like this (1, 0) (2, 0)
This is indeed a function as it meets those criterion. There are no two outputs for one input.
82.1 / 7.8= What is the answer yall
Answer:
10.5
Step-by-step explanation:
Hope I helped please mark brainliest if I did and thanks! <3
WILL MARK BRAINLIEST AND GIVE 75 POINTS!!!
Summer is thinking about buying a car for $45,000. The table below shows the projected value of two different cars for three years.
Number of years 1 2 3
Car 1 (value in dollars) 40,500 36,450 32,805
Car 2 (value in dollars) 42,000 39,000 36,000
Part A: What type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? Explain your answer. (2 points)
Part B: Write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points)
Part C: Summer wants to purchase a car that would have the greatest value in 13 years. Will there be any significant difference in the value of either car after 13 years? Explain your answer, and show the value of each car after 13 years. (4 points)
Answer:
A) 1: exponential; 2: linear
B) 1: f(x) = 45000·0.9^x; 2: f(x) = -3000x+45000
C) The difference is significant. 1: $11,348; 2: $6,000
Step-by-step explanation:
Part AThe values for Car 1 have a common ratio of 40500/45000 = 0.9. An exponential function is used to describe a sequence where the terms have a common ratio.
The values for Car 2 have a common difference of 42000-45000 = -3000. A linear function is used to describe a sequence where the terms have a common difference.
__
Part BAn exponential function can be written as ...
f(x) = (initial value)·(common ratio)^x
A linear function can be written as ...
f(x) = (common difference)x + (initial value)
The functions are ...
Car 1: f(x) = 45000·0.9^x
Car 2: f(x) = -3000x +45000
___
Part CThe formulas for the different car values after 13 years give ...
Car 1: f(13) = 45000·0.9^13 ≈ 11,348
Car 2: f(13) = -3000(13) +45000 = 6,000
The value of Car 1 will be almost double the value of Car 2 after 13 years. Yes the difference in value is significant.
Which of the following is the equation of a line that passes through the point
(3,2) and is parallel to the yaxis?
A. y = 2
B. y= 3
C. x= 3
D. x = 2
solve pls brainliest
4.
Which of the following equations has
both -1 and 4 as solutions?
A) x²+4x+4 B) x2-4x+3
C) x2-3x-4 D) x2+3x-4
Solve the equation: c + -22 = 16
Answer:
c=38
Step-by-step explanation:
Answer:
c = 38
Step-by-step explanation:
c+(-22) = 16c-22 = 16c = 16+22c = 38Harley has 60 beads. There are 11 beads that are NOT round. The rest are round. How many round beads does Michelle have?
Help please
Answer:
49
Step-by-step explanation:
If there's 60 beads in total and 11 are round and the rest aren't all you have to do is subtract 11 from 60.
Like This: 60-11=49
To check your answer you can add them to see if you get 60. Like this: 11+49=60
Addition and subtraction of fractions! find the missing number of 5/6= -/12
Gven: f(x) = 4x +1 and (x)= x^2 + 1.
find (fog)(x)
Answer:
Step-by-step explanation:
27836?+_68_729+_8978
There are 13 pieces of chicken at the dinner table. After dinner, only 3 pieces are left. How many pieces were eaten at dinner?
16
8
7
10
Answer:
10
Step-by-step explanation:
13 pieses - 3 pieces = 10 pieces that are eaten
Answer:
10
Step-by-step explanation:
Expand the function.
f(x) = (2x + 3)4
Answer:
y = 8x + 12
Step-by-step explanation:
y = (2x + 3)4
Distribute the 4 to the 2x and 3
y = 8x + 12
^ Expanded form
Lara made the table below of the predicted values for h(t), the height, in meters, of a penny t seconds after it is dropped off of the back of the bleachers.
A 2-column table with 9 rows titled Height of Penny over Time. The first column is labeled t with entries 0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8. The second column is labeled h(t) with entries 2, 1.951, 1.804, 1.559, 1.216, 0.775, 0.236, negative 0.401, negative 1.136.
To the nearest tenth of a second, how much time would it take the penny to hit the ground?
0.5 seconds
0.6 seconds
0.7 seconds
0.8 seconds
Answer:
Step-by-step explanation:
as the chart is broken into steps with the same precision we're looking for. Just choose the one where height is closest to zero or 0.6 s
To do it mathematically
The equation is
h = 2 - ½gt²
to find g, plug in a time and height
0.236 = 2 - ½g(0.6²)
g = 9.8 m/s
check another one just to be sure
1.559 = 2 - ½(9.8)0.3²
1.559 = 1.559
now plug in zero elevation with an unknown time
0 = 2 - ½(9.8)(t²)
-2 = - ½(9.8)(t²)
t² = 4/9.8
t = 0.6388765...
t = 0.6 s
The time it takes for the penny to hit the ground is about 0.6 seconds.
Option B is the correct answer.
What is an equation of a line?The equation of a line is given by:
y = mx + c
where m is the slope of the line and c is the y-intercept.
Example:
The slope of the line y = 2x + 3 is 2.
The slope of a line that passes through (1, 2) and (2, 3) is 1.
We have,
To determine the time it takes for the penny to hit the ground, we need to find the point where the height of the penny is equal to zero.
Looking at the table,
We can see that the height of the penny is negative when t = 0.7 and becomes more negative for larger values of t.
So the penny must hit the ground between t = 0.6 and t = 0.7 seconds.
Now,
We can use linear interpolation to estimate the time at which the height of the penny is zero by finding the equation of the line that passes through the two points closest to zero on the table, namely (0.6, 0.775) and (0.7, -0.401).
So,
The slope of the line passing through these points.
= (change in height) / (change in time)
= (-0.401 - 0.775) / (0.7 - 0.6)
= -1.176
The equation of the line passing through these points.
y - 0.775 = -1.176(x - 0.6)
Simplifying
y = -1.176x + 1.438
Setting y to zero and solving for x.
0 = -1.176x + 1.438
x = 1.438 / 1.176
x ≈ 1.22
Therefore,
To the nearest tenth of a second, the time it takes for the penny to hit the ground is about 0.6 seconds.
Learn more about equation of a line here:
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