if you were a doughnut shop owner and wanted to find out which doughnut you should make more of, which measure of central tendency would you use.​

Answer:

The simplest form of 84/96 is 7/8.

Step-by-step explanation:

Thus, 7/8 is the simplified fraction for 84/96 by using the GCD or HCF method. Thus, 7/8 is the simplified fraction for 84/96 by using the prime factorization method.

Answer:

False

Step-by-step explanation:

4/2 = 2/1 = 2

And 2 ≠ 1

Hence, 4/2 ≠ 1

Hope it helps :)

Answer:

no .

Step-by-step explanation:

4/2 is equivalent to 2 , if it were 2/2 then it would be yes .

Answer:

8,9,10

Step-by-step explanation:

Answer:

The answer would be 28

Step-by-step explanation:

You would plug 8 in where k is and 2 where j is

so (8)3 - 4(2) +12

answer is 28

Answer:

Step-by-step explanation:

vertex and focus are horizontally aligned, so parabola is horizontal.

focal length p = distance between focus and vertex = 0.25

focus lies to the left of vertex, so the parabola opens to the left.

x = a(y-k)² + h,

vertex (h,k)

a = -1/(4p)

vertex (-6,5)

h = -6

k = 5

p = 0.25

a = -1/(4·0.25) = -1

x = -(y-5)² - 6

Answer:

option 2

4/7

Step-by-step explanation:

Multiply 4/3x3/7 = 12/21

now simplify  12/21 = 4/7

Answer:

Step-by-step explanation:

Answer: need a pic or more info

Step-by-step explanation:

Answer:

top choice

Step-by-step explanation:

For SAS, you need a side followed by an angle followed by another side of one triangle to be congruent to the corresponding parts of another triangle.

The top choice shows side-angle-side.

The middle choice shows angle-side-angle.

The bottom choice shows side-side-side.

Answer: top choice

Answer:

Cos(a - b) = 0.959

Step-by-step explanation:

We know that:

Sin(a) = 4/5

Such that a is on the first quadrant (between 0° and 90°)

then:

Sin(a) = 4/5

Asin(sin(a)) = Asin(4/5)

a = Asin(4/5) = 53.13°

And:

Cos(b) = 2/5

Then:

Acos(Cos(b)) = Acos(2/5)

b = Acos(2/5) = 36.67°

Then:

Cos(a - b)

where:

a = 53.13° and b = 36.67°

Then:

Cos(a - b) = Cos(53.13° - 36.67°) = 0.959

Answer:

3x+7x

Step-by-step explanation:

Answer:

D) 3x+7x

Step-by-step explanation:

D) 3x+7x

Answer:

Step-by-step explanation:

increase ≤ 55-43.5

increase ≤ 11.5

Elanor can increase her speed by 11.5 miles per hour.

Answer: Jenny would have to work 5 hours to get $85

Step-by-step explanation:

Jenny makes $17 an hour (221/13 = 17) and 85/17 is 5

Answer:

a. Is the answer..

Let's solve for y.

y=−x+3

Answer:

y = −x + 3 = y = −x + 3

Hence f(x) = -x + 3 is equivalent to y = −x + 3

Hope it helps

Please mark me as the brainliest

Thank you

Answer: 6 2/3 pounds.

Step-by-step explanation:

Answer:

6 2/3 pounds

Step-by-step explanation:

Area of shaded region = area of circle - area of segment

(where "segment" refers to the unshaded region)

Area of circle = π (11.1 m)² ≈ 387.08 m²

The area of the segment is equal to the area of the sector that contains it, less the area of an isosceles triangle:

Area of segment = area of sector - area of triangle

130° is 13/36 of a full revolution of 360°.  This is to say, the area of the sector with the central angle of 130° has a total area equal to 13/36 of the total area of the circle, so

Area of sector = 13/36 π (11.1 m)² ≈ 139.78 m²

Use the law of cosines to find the length of the chord (the unknown side of the triangle, call it x) :

x ² = (11.1 m)² + (11.1 m)² - 2 (11.1 m)² cos(130°)

x ² ≈ 404.82 m²

x = 20.12 m

Call this length the base of the triangle. Use a trigonometric relation to determine the corresponding altitude/height, call it y. With a vertex angle of 130°, the two congruent base angles of the triangle each measure (180° - 130°)/2 = 25°, so

sin(25°) = y / (11.1 m)

y = (11.1 m) sin(25°)

y ≈ 4.69 m

Then

Area of triangle = xy/2 ≈ 1/2 (20.12 m) (4.69 m) ≈ 47.19 m²

so that

Area of segment ≈ 139.78 m² - 47.19 m² ≈ 92.59 m²

Finally,

Area of shaded region ≈ 387.08 m² - 92.59 m² ≈ 294.49 m²

Answer:

Step-by-step explanation:

1/5

Answer: 1/5

Step-by-step explanation:

Answer:

The inverse Laplace transform of [tex]F(s) = \frac{3\cdot s + 9}{s^{2}+9}[/tex] is [tex]f(t) = 3\cdot \cos \omega t + 3\cdot \sin \omega t[/tex].

Step-by-step explanation:

In this case, we should use the following direct and inverse Laplace Transforms:

[tex]F(s) = G(s) + H(s)[/tex] (1)

[tex]\mathcal{L}^{-1} \{\frac{s}{s^{2}+\omega^{2}} \} = \cos \omega t[/tex] (2)

[tex]\mathcal{L}^{-1}\{\frac{\omega}{s^{2}+\omega^{2}} \} = \sin \omega t[/tex] (3)

[tex]\mathcal\{L\}^{-1}\{c\cdot F(s)\} = c\cdot \mathcal\{L\}^{-1}\{F(s)\}[/tex] (4)

Then, we apply all these trasforms:

[tex]F(s) = \frac{3\cdot s + 9}{s^{2}+9}[/tex]

[tex]F(s) = 3\cdot \left(\frac{s}{s^{2}+9} \right)+3\cdot \left(\frac{3}{s^{2}+9} \right)[/tex]

[tex]f(t) = 3\cdot \cos \omega t + 3\cdot \sin \omega t[/tex]

The inverse Laplace transform of [tex]F(s) = \frac{3\cdot s + 9}{s^{2}+9}[/tex] is [tex]f(t) = 3\cdot \cos \omega t + 3\cdot \sin \omega t[/tex].

Answer:

x = 8

Step-by-step explanation:

Answer:

equal, tell me if I'm wrong

Answer: 240

Step-by-step explanation:

Suppose in a math class of 22 students, 14 are boys and 8 are girls. ... for a girl you have a 8 out of 22 students chance....for an A you have an additional ... 8/22+4/22 = 12/22 = 6/11. for a boy there is a 14 out of 22 chance of being a boy and an ... 14/22 + 6/22 = 20/22= 10/11 ... How to display latex properly

Answer:

you are right

Step-by-step explanation:

Use the law of law of cos

c^2=a^2+b^2﹣2abcos√angle

(2√13)^2=52=4+36-24cos(a)

cos(a) = -12/24 =  -1/2

a = 120 degrees

so yes, you are right

Answer:

Both of them are NOT equivalent.

Step-by-step explanation:

Use the distributive property to see if 5(x - 1) and 5x - 1 were equivalent.

5(x - 1)

= 5x - 5

This tells us 5(x - 1) is not equivalent to 5x - 1.

Answer: Scale of 2:1

Step-by-step explanation:

All the angles are the same. So its the same polygon just bigger.

Line DA multiplied by a factor of 2 will make is as long as Line ZW.

Line AB multiplied by 2 will also make it equal to Line WX

From that we can assume that Lines XY and YZ are equal to Lines BC and CD