In a certain candy store, 3 pounds of candy and 2 pounds of mints cost $10.80, and 1 pound of candy and 3 pounds of mints cost $5.35. What is the cost per pound of the mints?

Answers

Answer 1

Answer:

Step-by-step explanation:

we will set up two equations:

let c be candy

let m be mints

3c+2m=10.80

c+3m=5.35, c=5.35-3m

3(5.35-3m)+2p=10.80

c=3.10

m=0.75

Answer 2

Let x be the cost of candy per pound and y be the cost of mint per pound.

[tex]\left \{ {{3x + 2y = 10.80} \atop {{x + 3y = 5.35}} \right.[/tex]

Rewrite the second equation for substitution:

x = 5.35 - 3y

Substitute the equation above into the first equation:

3(5.35 - 3y) + 2y = 10.80

16.05 - 9y + 2y = 10.80

-7y = -5.25

7y = 5.25

y = 0.75

∴ The price of mint per pound is $0.75.


Related Questions

Triangle DEF is congruent to triangle UVW. The length of side DE is 6 cm, EF is 7.5 cm, and DF is 5 cm. What is the length of side VW?

Answers

The length of side VW is 7.5 cm

What is the length of side VW?

The given parameters are:

DE is 6 cm, EF is 7.5 cm, and DF is 5 cm

Since the two triangles are congruent, then it means that:

D corresponds to UE corresponds to VF corresponds to W

So, we have:

VW= EF

The side EF is

EF = 7.5 cm

So, we have:

VW = 7.5 cm

Hence, the length of side VW is 7.5 cm

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Sam is rowing a boat away from a dock. The graph shows the relationship between time and Sam’s distance from the dock. Evaluate the function for an input of 6.

Answers

Answer:

See below

Step-by-step explanation:

Go across the 'x' axis to '6'....then go UP to the graph to find y = 60

 after 6 minutes he has rowed 60 meters

Can someone help me please

Answers

The domain of the function will therefore be 0≤x<∞

Domain of a function

Domain of a function are the independent value for which a function exists. Given the function below;

f(x) = [tex]\sqrt[4]{x}[/tex]

Since the value in the root cannot be negative hence the domain of the function will be all positive real numbers.

The domain of the function will therefore be 0≤x<∞

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If the area of the rectangle avove is 180 spuare inches, then x =

Answers

Given the dimension of the length and area of the rectangle, the dimension of the breadth x is 9in.

Hence, option A is the correct answer.

This question is incomplete, the missing diagram is uploaded along this answer below.

What is the value of x?

Area of a rectangle is expressed as; A = l × b

Given that;

Length of the rectangle l = 20inBreadth b = xArea A = 180in²

A = l × b

180in² = 20in × x

x = 180in² / 20in

x = 9in

Given the dimension of the length and area of the rectangle, the dimension of the breadth x is 9in.

Hence, option A is the correct answer.

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DOES ANYONE KNOW THE ANSWER

Answers

Answer:

D. none

Step-by-step explanation:

we only know about the right angle at the bottom right.

that is not enough information.

we always need 3 pieces of confirmed information of each triangle to be able to say that the 2 triangles are indeed of the same shape and size.

like the other answer options would indicate :

SAS : side - angle - side.

2 sides and the enclosed angle. if we know they are equal, then the rest of the triangles follow automatically.

SSS : all 3 sides. with 3 defined sides there is only one possible shake and size for that triangle.

HL : Hypotenuse and a leg of a right-angled triangle (also 3 pieces of information - 2 sides and the right angle).

since we have only the right angle and nothing else, we cannot prove that the triangles are congruent.

I need this problem solved

Answers

Answer:

AP = 12, and FQ = 8

Step-by-step explanation:

The proportion between AB:FG and AP:FQ is the same.

--> 9:6 = AP:FQ

I'll say that FQ is x and AP is x+4 (since AP is 4 longer than FQ)

--> 9:6 = x+4:x

--> 6(x+4) = 9x

--> 6x + 24 = 9x

--> 24 = 3x

--> x = 8

Since AP= x+4 and FQ= x. AP becomes 12 and FQ becomes 8.

Suppose the shipping weight of your cheese shop's customized gift baskets is asymmetrically distributed with unknown mean and standard deviation. For a sample of 70 orders, the mean weight is 57 ounces and the standard deviation is 7.1 ounces. What is the lower bound of the 90 percent confidence interval for the gift basket's average shipping weight

Answers

The lower bound of the 90% confidence interval for the gift basket's average shipping weight is 55.605.

Given mean weight of 57 ounces ,sample size 70 ,confidence level 90% and standard deviation of 7.1 ounces.

We have to find the lower bound of the confidence interval for the gift's basket's avrage shipping weight.

We can easily find the confidence interval and its lower bound through theformula of margin of error.

Margin of error is the difference between real values and calculated values.

Margin of error=z*σ/[tex]\sqrt{n}[/tex]

where z is the critical value of confidence level

σ is standard deviation,

n is the sample size

We have to first find the z value for 90% confidence level which is 1.645.

Margin of error=1.645*7.1/[tex]\sqrt{70}[/tex]

=11.6795/8.3666

=1.395

Lower bound of the confidence interval = Mean - margin of error

=57-1.395

=55.605.

Hence the lower bound of the confidence interval for the gift basket's average shipping weight is 55.605.

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Move the sliders to set the values of r, h, and k, and record at least three different sets of data. also record the equations of the corresponding circles.

Answers

The equations of the corresponding circles can be any equation only have to satisfy the  general equation for circle .

The question seems incomplete and complete question given in the image !!!!

A circle is the set of all points in a plane at a given distance (called the radius) from a given point (called the center.)

We know that the general equation for a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where ( h, k ) is the center and r is the radius.

According to the question

The equation of circle given is [tex]x^2+y^2=1[/tex]

Center at origin

i.e

(h,k) = (0,0)

and radius = 1 unit

Now ,

By changing changing center (h,k) and radius of equation it will give following equations

h                      k                       r                            equation of circle

0                       1                       3                      [tex](x-0)^2+(y-0)^2=3^2[/tex]  

2                       2                       3                       [tex](x-2)^2+(y-2)^2=3^2[/tex]

1                        1                        1                     [tex](x-1)^2+(y-1)^2=1^2[/tex]  

-2                      -1                       2                      [tex](x+2)^2+(y+1)^2=2^2[/tex]

3                       2                       1                        [tex](x-3)^2+(y-2)^2=1^2[/tex]      

-5                      1                        3                       [tex](x+5)^2+(y-1)^2=3^2[/tex]

Hence, the equations of the corresponding circles can be any equation only have to satisfy the general equation for circle .

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Calculate x for each of the following right angled triangles.
Give your answer as a simplified surd (or integer).

Answers

[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}[/tex]

(a) x = 6.5 cm (b) x = 10 cm(c) x = 7 cm(d) x = 7.9 cm

Step-by-step explanation:

To find an unknown side of a right angled triangle we use a theorum called pythagorus theorum..

Formula :

(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2

(h)^2 = (p)^2 + (b)^2

therefore,

(a) hypotenuse = x cm, base = √30 cm, perpendicular = √12 cm.

by formula,

→ h^2 = p^2 + b^2

→ (x)^2 = (√12)^2 + (√30)^2

→ x^2 = 12 + 30

→ x^2 = 42

→ x = √42

→ x = 6.480...

→ x = 6.5 cm. (approx)

___________________________

(b) hypotenuse = √300 cm, base = √200 cm,perpendicular = x cm.

by formula,

→ h^2 = p^2 + b^2

→ (√300)^2 = (x)^2 + (√200)^2

→ 300 = x^2 + 200

→ x^2 = 300 – 200

→ x^2 = 100

→ x = √100

→ x= 10 cm.

___________________________

(c) hypotenuse = √66 cm, base = √17 cm,perpendicular = x cm.

by formula,

→ h^2 = p^2 + b^2

→ (√66)^2 = (x)^2 + (√17)^2

→ 66 = x^2 + 17

→ x^2 = 66 – 17

→ x^2 = 49

→ x = √49

→ x = 7 cm.

___________________________

(d) hypotenuse = x cm, base = 5√12 cm,perpendicular = 2√3 cm.

by formula,

→ h^2 = p^2 + b^2

→ (x)^2 = (2√3)^2 + (5√12)^2

→ x^2 = 12 + 50

→ x^2 = 62

→ x = √62

→ x = 7.874...

→ x = 7.9 cm. (approx)

___________________________

Hope it helps you!!

18. The area of a right triangle is 30 cm². The length
of one leg of the triangle is 5 cm. What is the
length of the other leg?
(A) 6 cm
(B) 12 cm
(C) 18 cm
(D) 24 cm

Answers

Answer:

12

Step-by-step explanation:

The area of a triangle is calculated with the following formula:

[tex]\frac{1}{2} *b*h[/tex] (b: base, h: height (or legs))

We can use this formula to find the length of the other leg:

30 = [tex]\frac{1}{2} *b*h[/tex] multiply both sides with 2 to get rid of fraction

60 = b*h one of the leg's length is given as 5 so

60 = 5*h divide both sides by 5

12 = h is the length of the missing leg.

Solve the system of equations using substitution. 6x=−6y−30−3x−3y=15

Answers

The system of equation have an infinite solution.

How to solve system of equation?

6x   = -6y - 30

-3x -3y = 15

Therefore, let's rearrange the system of equations.

6x + 6y = -30

-3x - 3y = 15

multiply equation(ii) by 2

6x + 6y = -30

-6x - 6y = 30

add the equations

0 = 0

Since 0 = 0 for any value of x, the system of equations has infinite solutions.

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What is the equation of the line that passes through (4,11) and is perpendicular to the line with the following equation

Answers

Your question is incomplete. please read below for the missing content

y = -3/4x + 14 is the answer.

y = 4/3x+ 7...slope here is 4/3. A perpendicular will have a negative reciprocal slope. All that means is to flip the slope and change the sign.

4/3....flip it....3/4....change the sign....-3/4. So our perpendicular equation has to have a slope of -3/4

y = mx + b

slope(m) = -3/4

(4,11)...x = 4 and y = 11

now we sub and find b, the y int

11 = -3/4(4) + b

11 = - 3 + b

11 + 3 = b

14 = b

so ur line is : y = -3/4x + 14

The perpendicular line has the opposite slope of the reciprocal, so the slope of the line you want to find is 1/2. Inserting the given points into the equation y = 1 / 2x + b and solving b yields b = 6. Therefore, the linear equation is y = ½x + 6. When relocated, it becomes –x / 2+. y = 6.

Q)  What is the equation of the line that passes through the point (4,11) and is perpendicular to the line with the following equation y = 4/3x + 7

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Which of the following is equal to m^5/2, for all value of m?

Answers

The equivalent expression is:

[tex](m^5)^{1/2} = \sqrt{m^5}[/tex]

Which is the one in option A.

How to identify the equivalent expression?

Here we start with the expression:

[tex]m^{5/2}[/tex]

Now, remember that:

[tex]\sqrt{x} = x^{1/2}[/tex]

[tex](x^a)^b = x^{a*b}[/tex]

if we define a = 5 and b = 1/2, we get:

[tex]m^{5/2} = (m^5)^{1/2}[/tex]

Using the first property, we get:

[tex](m^5)^{1/2} = \sqrt{m^5}[/tex]

Then we conclude that the correct option is A.

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Three less than a number x is more than 15. an inequality that represents this word sentence is

Answers

Answer:

x - 3 > 15

Step-by-step explanation:

Convert the exponential to a logarithmic form: 10 ^ 4 = 10000

Answers

Answer:

10^4 =  10 × 10 × 10 × 10
       =  10000

log_10(10000) =4

[_10] means log of base 10

The sum of three numbers is 69. If the second number is equal to the first diminished by 8, and the third number is 5 times the first. What are the numbers?



If x represents the first number, then which of the following equations could be used to solve the problem?

69 = 7x - 8
x = 6x - 8
69 = 6x - 8

Answers

Answer:

[tex]69 = 6x - 8[/tex]

Step-by-step explanation:

All 3 numbers must sum to 69, so we can draw out the second option [tex]x = 6x - 8[/tex]

Let the first number be x, adding 5x to the first x would give you 6x for the sum of the first and third numbers, therefore you can remove [tex]69 = 7x - 8[/tex] from your considerations as it includes 7x not 6x.

This leaves you with the one final answer [tex]69 = 6x - 8[/tex]

The field width of thestadium is 40m lessthan its length. The total length of the rectangular boundary of the open space in canopy is 420m. Frame a suitable
equation for the given situation and also find the length and width of the field in the stadium.

Answers

Answer:

I may have misubderstood the question, so review carefully.

width = 380 m

length is 420 m

Step-by-step explanation:

Let w and l stand for the width and length of the stadium.

We are told that w = l - 40 m

We also learn that l = 420 m

w = l - 40 m

w = (420 m) - 40 m

width = 380 m

length is 420 m

A table showing gallons of solution, acid concentration, and amount of acid. the first row shows 10 percent acid, and has the entries, 0.5, 0.10, and 0.10 times 0.5. the second row shows 35 percent, and has the entries, g, 0.35, and 0.35 g. the third row shows. mixture, and has the entries, g plus 0.5, 0.15, and 0.15 left parenthesis g plus 0.5 right parenthesis. eli wants to combine 0.5 gallon of a 10% acid solution with some 35% acid solution to make a 15% acid solution. which equation can you use to determine how many gallons of the 35% acid solution eli should add?

Answers

The number of gallons of the 35% acid solution eli should add is; 0.125 gallons

How to Simplify Basic Algebra?

From the given table, since Eli wants to combine 0.5 gallon of a 10% acid solution with some 35% acid solution to make a 15% acid solution, then we can say that;

(0.10)(0.5) + 0.35g = 0.15(g + 0.5)

where g is number of gallons

Now,  for us to determine how many gallons of the 35% acid solution eli should add, we will solve the word problem earlier to get;

(0.10)(0.5) + 0.35g = 0.15(g + 0.5)

⇒ 0.05 + 0.35g = 0.15g + 0.075

⇒ 0.35g - 0.15g = 0.075 - 0.005

⇒ 0.2g = 0.025

g = 0.025/0.2

g = 0.125 g

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please give the answer

Answers

The function can be solved as follows:

f(6 + 4) = 25f(6) - f(4) = 20f(6 - 4) = 1f(6) - f(4) = 6f(6) . f(4) = 91

How to solve function?

f(x) = 3x - 5

Therefore, the function can be solved as follows:

f(6 + 4) = f(10) = 3(10) - 5 = 25

f(6) + f(4) = 3(6) - 5 + (3(4) - 5)

f(6) - f(4) = 13 + 7

f(6) - f(4) = 20

f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1

f(6) - f(4) = 3(6) - 5 - (3(4) - 5)

f(6) - f(4) = 18 - 5  - (12 - 5)

f(6) - f(4) = 13 - 7

f(6) - f(4) = 6

f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67

f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)

f(6) . f(4) = (18 - 5)(12 - 5)

f(6) . f(4) = (13)(7) = 91

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Select all the correct answers.
The table shows points on the graph of the function f (x) = 3 sin (x- pi/2) + 1

Answers

Answer:

B,C and E

Step-by-step explanation:

The period can be calculated by dividing 2pi by the coefficfient of the x, so in this case 1. And we'll get 2pi/1 = 2pi.

The function clearly has a minimum of -2, you can see that from the table.

Same thing for the maximum = 4.

Answer:

See Photo

Step-by-step explanation:

Plato/Edmentum

The function of f(x) = 3x + 6,000 represents the amount of money a tablet is being sold for, where x is the number of tablets being manufactured. The function g(x) = 20x - 400 represents the cost of production, where x is the number of tablets being manufactured. The function g(x) = 20x - 400 represents the cost of production, where x is the number of tablets being manufactured. What is (f - g)(300)? Explain.

A. $1,300 is the cost of manufacturing 300 tablets

B. $12,500 is the cost of manufacturing 300 tablets.

C. $1,300 is the profit made from 300 tablets.

D. $12,500 is the profit made from 300 tablets.

Answers

Answer:

(f - g)(300) = $1,300 is the profit made from 300 tablets

Step-by-step explanation:

(f - g)(300) is the profit made from 300 tablets

(f - g)(x) = (3 x + 6,000) - (20 x - 400)

- Simplify it

(f - g)(x) = 3 x + 6,000 - 20 x + 400

- Add like terms

(f - g)(x) = -17 x + 6,400

Substitute x by 300

(f - g)(300) = -17(300) + 6,400

(f - g)(300) = -5,100 + 6,400

(f - g)(300) = $1,300

The profit is $1,300

Which is the best first step to factor….?

Answers

Answer:

A

Step-by-step explanation:

By using greatest common factor you are able to take a 2 out of all the numbers

A cylindrical package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section) of 123 inches. Find the dimensions of the package of maximum volume that can be sent. (The cross section is circular.)

Answers

The height of package is 34 inches.

According to the statement

we have given that the perimeter of cylinderical package is 123 inches.

and we have to find the volume of this package.

So,

According to the perimeter

2(Pi)r + h = 123

and then

h = 123 - 2(Pi)r

then the volume become

V = (Pi) r^2h

V= (Pi) r^2 * [ 123 - 2(Pi)r ] = 123 (Pi) r^2  - 2(Pi)r^3

then differentiate it

dV/dr = 246(Pi) r - 6(Pi)r^2

Now take

r(246(Pi) - 6(Pi)r) = 0

then neglect r=0 and then find another value of r.

r = 246(Pi) / 6(pi)

here r=41 then

h = 123 - 2(Pi)r

h = 123 - 2(3.14)41

h = 123 - 2(Pi)r

Then put the value of r then h = 34 inches.

So, The height of package is 34 inches.

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Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes
respectively: (a) 3 /2 and 5

Answers

The quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively as 3 /2 and 5 is 2x² - 3x + 10

What is a quadratic polynomial?

A quadratic polynomial is a polynomial of the form ax² + bx + c

How to find the quadratic polynomial?

For any given quadratic polynomial we have

x² - (sum of zeros)x + (products of zeros) = 0

Given that the sum and product of its zeroes respectively 3/2 and 5,

We have that

sum of zeroes = 3/2 and product of zeros = 5

Substituting the values of the variables into the equation, we have

x² - (sum of zeros)x + (products of zeros) = 0

x² - (3/2)x + (5) = 0

x² - (3/2)x + (5) = 0

Multiplying through by 2, we have

2 × x² - 2 × (3/2)x + 2 × (5) = 0 × 2

2x² - 3x + 10 = 0

So, the quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively as 3/2 and 5 is 2x² - 3x + 10

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HELP ASAP!!
Select the two values of x that are roots of this equation.
x²+2x-5=0
A. x--1+2√√6
B. x=-1+√6
C. x=-1-√6
D. x=-1-2√6


Answers

Answer:

Step-by-step explanation:

hello:

here an solution

PLS HELP ASAP

42. Use the graph below to answer all questions. Assume the graph is incremented by one.




Does the graph represent a function? How do you know?

What is the domain?

What is the range?

What is the maximum?

What is the minimum?

Identify the intervals where the graph is increasing. What does this mean in the context of the problem?

Identify the intervals where the graph is decreasing. What does this mean in the context of the problem?

Answers

See below for the solution to each question

Is the graph a function?

Yes, the graph is a function.

This is because all x values have different y values

The domain

This is the set of input values of the graph.

From the graph, we have

x = 0 to x = 17

Hence, the domain is [0, 17]

The range

This is the set of output values of the graph.

From the graph, we have

y = 0 to y = 10

Hence, the range is [0, 10]

The maximum

This is the maximum point on the graph.

From the graph, we have

Maximum = (12, 10)

The minimum

This is the minimum point on the graph.

From the graph, we have

Minimum = (0, 0)

The increasing intervals

These are the intervals where the y values increase as x increase.

From the graph, we have

Increasing intervals = (0, 5) ∪ (10, 12) ∪ (14, 15)

The decreasing intervals

These are the intervals where the y values decrease as x increase.

From the graph, we have

Decreasing intervals = (7, 10) ∪ (12, 14) ∪ (15, 17)

The constant intervals

These are the intervals where the y values remain unchanged as x changes.

From the graph, we have

Constant intervals = (5, 7)

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Order the set of numbers from least to greatest: -
--5, -√26.-31
6

Answers

Answer:

-31, /~26, -5, 6

Step-by-step explanation:

a. Use the properties of right triangles and AABC to prove the Law of Sines.
b. Find the length of BC, rounded to the nearest tenth of a unit.
In your final answer for parts A and B, Include all of the necessary steps and calculations.

Answers

The Law of sines defines that in a triangle, (Sin A)/a = (Sin B)/b = (Sin C)/c and as per law of sines the length of BC is 24.

The given triangle is ΔABC, we split the given triangle into two right-angled triangle ΔABD and ΔBCD.

In the triangle ΔABD,

sin θ = opposite side/hypotenuse

sin A=BD/AB

BD=(sin A)/AB

And in the triangle ΔBCD,

sin θ = opposite side/hypotenuse

sin B=BD/BC

BD=(sin B)/BC

Hence, BD=(sin A)/AB=(sin B)/BC

Let say, (sin A)/a=(sin B)/b

As per law of sine, (sin A)/a=(sin B)/b

Then,

(sin 46°)/a=(sin 31°)/17

a=(17 × sin 46°)/(sin 31°)

a=23.74

a=24

Hence, the value of BC, rounded to the nearest tenth of a unit is 24.

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What is the range of the following set of ordered pairs?
{(-1,7), (6,2), (0,4), (5,2), (-3,1)}
O a. {7,2,4,1}
b.
O c.
O d.
{-1,6, 0, 5, -3}
{-1, -3, 1, 7,6}
{2, 0, 4, 5)

Answers

Answer:

range of the given set is { 7,2,4,2,1}

Step-by-step explanation:

. Hello !

When the above kind of set is given the second values of each elements belongs to the range or the y whereas, the first values of the elements belongs to the domain or x.

Thus, domain = {-1,6,0,5,-3}range ={7,2,4,2,1}

Answer is 7,2,4,1 is the set of ordered pairs

The hotel staff is decorating the lobby by placing one row of string lights along the outer edge of the rectangular ceiling. A member of the staff maps the ceiling on a coordinate grid as shown, where each unit represents 1 meter.

Answers

The length of string used to decorate the ceiling = 40.5 meters.

According to the statement

we have given that the hotel staff is decorating the lobby by placing one row of string lights along the outer edge of the rectangular ceiling.

And the coordinates of rectangular ceiling is A(5,16), B(17,10), C(14,4), D(2,10).

And we have to find the total length for string is used to decorate the rectangular ceiling.

We know that the Total length of string = Area of the rectangular ceiling.

And area of rectangular ceiling = L*B

So, Length of rectangular ceiling = A+B

Length of rectangular ceiling = (17-5) + (16-10)

Length of rectangular ceiling = (12+6)/2

Length of rectangular ceiling = 9.

So,

Breadth of rectangular ceiling = B+C

Breadth of rectangular ceiling = (17-14)+(10-4)

Breadth of rectangular ceiling = (3+6) /2

Breadth of rectangular ceiling = 4.5

So, the length of string used = 4.5*9

the length of string used = 40.5 meters.

The length of string used to decorate the ceiling = 40.5 meters.

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Question:

The hotel staff is decorating the lobby by placing one row of string lights along the outer edge of the rectangular celling. A member of the s⊥aff maps the celling on a coordinate grid as shown, where each unit represents . What is the approximate length of string lights the staff needs to decorate the ceiling?

A 20.25 meter

B. 35 meter

C. 40.5 meter

D. 14 meter

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