Mathematics High School

In ARST, r = 52 cm, s = 55 cm and ZT=48°. Find the length of t, to the nearest
centimeter.

Answers

Answer 1

9514 1404 393

Answer:

  44 cm

Step-by-step explanation:

The law of cosines is applicable.

  t^2 = r^2 + s^2 -2rs·cos(T)

  t^2 = 52^2 +55^2 -2·52·55·cos(48°) ≈ 1901.57

  t ≈ √1901.57 ≈ 43.607

The length of t is about 44 cm.

In ARST, R = 52 Cm, S = 55 Cm And ZT=48. Find The Length Of T, To The Nearestcentimeter.
Answer 2

Hey there!

[tex]\dagger \: \sf\red{Question:}[/tex]

In ARST, r = 52cm, s = 55cm and ZT = 48°. Find the length of T, to the nearest centimeter.

[tex]\dagger \: \sf\blue{Solution:}[/tex]

By the law of cosines,

[tex]{\underline{\boxed{\frak{\pmb{\quad {t}^{2} = {r}^{2} + {s}^{2} - 2rs \times cos(T) }}}}} [/tex]

[tex]\implies\tt[/tex] t² = (52)² + (55)² - 2 × 52 × 55 × cos(48°)

[tex]\implies\tt[/tex] t² ≈ 1901.57

[tex]\implies\tt[/tex] t² = √1901.57

[tex]\implies\tt[/tex] t² = 43.607

[tex]\implies\tt[/tex]t = 44 cm

Therefore;

The length of t is 44 cm.

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