In baseball, each time a player attempts to hit the ball, it is recorded. the ratio of hits compared to total attempts is their batting average. each player on the team wants to have the highest batting average to help their team the most. for the season so far, jana has hit the ball 7 times out of 10 attempts. tasha has hit the ball 10 times out of 16 attempts. which player has a ratio that means they have a better batting average? tasha, because she has the lowest ratio since 0.7 < 0.625 tasha, because she has the highest ratio since 56 over 80 is greater than 50 over 80 jana, because she has the highest ratio since 56 over 80 is greater than 50 over 80 jana, because she has the lowest ratio since 0.7 < 0.625

Answer:

Step-by-step explanation:

2A. 3x=6 ⇒ x=2

2B. 3n=2(n-3) ⇒ 3n=2n-6 ⇒ n= -6

1. cross multiplication method

An arithmetic sequence is a sequence of numbers in which the difference between any two successive members of the sequence is a constant value. The general form of an arithmetic sequence is:

a, a + d, a + 2d, a + 3d, ...

where "a" is the first term of the sequence, and "d" is the common difference between successive terms.

Given the function f(n) = 2n - 1, we can see that the function outputs a sequence of integers, with a common difference of 2. So f(n) is not an arithmetic sequence.

Arithmetic sequence is a list of numbers in which each number is the sum of the previous number and a constant number.

Example: 1,3,5,7,9 is an arithmetic sequence because the constant difference is 2.

If you have any other question feel free to ask.

Answer:

Step-by-step explanation:

Rewrite the function as an equation.

y

=

3

x

−

4

Use the slope-intercept form to find the slope and y-intercept.

Tap for fewer steps...

The slope-intercept form is

y

=

m

x

+

b

, where

m

is the slope and

b

is the y-intercept.

y

=

m

x

+

b

Find the values of

m

and

b

using the form

y

=

m

x

+

b

.

m

=

3

b

=

−

4

The slope of the line is the value of

m

, and the y-intercept is the value of

b

.

Slope:

3

y-intercept:

(

0

,

−

4

)

70-70-40 is an isosceles triangle.

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The greatest poible value of b is (72-14)/(14-(-2))×(x+2)+14.

Possible value is the potential for something to have a particular outcome, result, or consequence. It is the amount of beneficial or desirable result that can be achieved, given the available resources. Possible value is often determined by assessing various factors such as cost, risk, and time. It is an important concept in economics, finance, and business, as it helps to identify the most beneficial course of action.

The greatest possible value of b is found by solving the equation of the line through A and B, which is y = (72-14)/(14-(-2))×(x+2)+14.

Setting the y-value to 0 and solving for x gives x = -14, which means b = 14. Therefore, the greatest possible value of b is 14.

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The slope of the line that passes through the points (-5, 8)and (−5,4) is undefined.

In mathematics, a line's slope, also known as its gradient, is a numerical representation of the line's steepness and direction.

Given:

A line that passes through the points (-5, 8)and (−5,4).

If a line passes through two points (x₁ ,y₁) and (x₂, y₂),

then the equation of line is

y - y₁ = (y₂- y₁) / (x₂ - x₁) x (x - x₁)

To find the slope;

m =  (y₂- y₁) / (x₂ - x₁)

m = (4-8) / (-5 + 5)

m = -4/0

The slope is undefined.

Therefore, the slope is undefined.

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Answer:

5% of 120 is 6, so you would add that 6 to 120.

120 + 6 = 126.

The total cost will sales tax would be $126.00.

Step-by-step explanation:

Hope it helps! =D

The common difference is 0.42. The comparison of each ratio's successive values over time for a single firm.

Now, According to the question:

What is meant by ratio?

Therefore, simplifying the equation then we get,

if you take the ranges (y) and subtract one from the other you get 0.42.

(22.84 - 22.42)/(2 - 1) = 0.42/1 = 0.42

(23.26 - 22.84)/(3 - 2) = 0.42

(23.68 - 23.26)/(4 - 3) = 0.42

Hence, The common difference is 0.42

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The value of x is 7 and value of y is 8

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Given data set is {4, 6, x, y, 10}

The mean and the median are the same value.

The median is the middle value, which is x, and the mean is:

M = (4 + 6 + x + y + 10)/5

Then we have that:

(4 + 6 + x + y + 10)/5 = x

Now let's solve this:

(4 + 6 + x + y + 10) = 5x

20 + x + y = 5x

20 + y = 4x

And x and y are whole numbers. Then we can take x = 7 to get:

20 + y = 4*7

y = 28 - 20 = 8

Then we have x = 7 and y = 8.

Hence, the value of x is 7 and value of y is 8 in the data set 4 6 x y 10

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If the pickup charge for taxi is $3.50 and additional charge of $0.75 per mile , then the cost for riding 5 miles is $7.25  and cost for riding m miles is $[tex]3.50+0.75m[/tex]   .

The pickup charge that taxi service charges is = $3.50  ;

the additional charge for per miles driven is = $0.75  ;

we have to find the cost for riding 5 miles ;

So , the total cost for riding 5 miles is = [tex]Pickup Charge + (Additional Charge)\times(Number Of Miles Driven)[/tex] ;

substituting the values , the total cost equation becomes ;

[tex]Total Cost = 3.50 + 0.75\times5[/tex]

= [tex]3.50+3.75[/tex]

= 7.25

So , the cost for 5 miles is = $7.25  ;

to find cost for driving "m" miles ,we substitute the number of miles = m;

[tex]Total Cost = 3.50+0.75\times m[/tex]

= [tex]3.50+0.75m[/tex]

Therefore , the cost for riding m miles is $ [tex]3.50+0.75m[/tex] .

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The radius of convergence R = 1/b

The radius of convergence for a power series is given by the formula:

1/R = lim sup |bn|^(1/n)

In this case, the radius of convergence is given by:

1/R = lim sup |bn|^(1/n) = lim sup b^(1/n) = b^(1/n) as b > 0.

So R = 1/b

As for the interval of convergence, it is the set of values of x for which the series converges. The series converges when |x-a| < R, and diverges when |x-a| > R. So the interval of convergence is (a-R, a+R) which is (a-1/b, a+1/b)

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Even though this relationship is proportional, not all of these ratios are equal.

Verify that the ratios provided are equal. The ratios of 3:5 and 15:25 are both equal. Because the first ratio 3: 5 can be derived by multiplying the ratio 15: 25 by 5 on both the numerator and denominator. The initial ratio of 3: 5 can be multiplied by 5 to get the ratio 15: 25, and vice versa.

This indicates that you would require an 8 fl oz can (a quarter of a quart) of Part B if you were ordering a quart of Part A. You will have 1.25 after combining Parts A and B.

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The number that should be added to the polynomial 2x³ - 3x² - 8x is 12x

When a polynomial is divided by a linear factor, the remainder is equal to the constant term of the polynomial multiplied by the reciprocal of the linear factor.

In this case, the polynomial is 2x³ - 3x² - 8x, and the linear factor is 2x-1.

To find the remainder when this polynomial is divided by 2x-1, we need to multiply the constant term of the polynomial, which is -8, by the reciprocal of 2x-1, which is 1/(2x-1).

So the remainder should be -8*(1/(2x-1)) = -8/(2x-1) = -4/(x-0.5)

To make the remainder 12, we will add 12x to the polynomial so that the new constant term is 12.

The polynomial 2x³ - 3x² - 8x + 12x will have a remainder of 12 when divided by 2x-1.

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The movie need to earn $ 1,512,500 in the next 7 weeks.

The unitary technique involves first determining the value of a single unit,

followed by the value of the necessary number of units.

For Example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

A company spent 762500 to make a movie.

The total movie will be earned

= 762500 + 2000000

= 2,762,500

First week the movie earned 1, 250,000.

So, in 7 weeks the movie needs to earned

= 2,762,500 - 1, 250,000

= 1,512,500

Hence, the movie earn 1,512,500 more.

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The population of bacteria after 8 days is 7088

Here, we have been given an equation for the rate of growth of a population of bacteria

dP/dt = k√t

where P is the population size

and t is the time in days (0 ≤ t ≤ 10)

We rewrite above equation as,

dP = k√t dt

Integrating both sides, we get,

P = (2/3) × kt^(3/2) + C

We find the value of C.

For t = 0, P = 300 as the initial size of the population is 300.

Substitute t = 0 in above equation.

300 = 0 + C

C = 300

So, the above equation becomes,

P = 300 + (2/3) × kt^(3/2)                .......(1)

Now we find the value of k.

After 1 day the population has grown to 600.

substitute t = 1, P = 600 in equation (1)

600 = 300 + (2/3) × k

(2/3)k = 300

k = 900/2

k = 450

So, the equation of population of bacteria after time t is:

P = 300 + [(2/3) × 450 × t^(3/2)]

P = 300 + 300 × t^(3/2)

P = 300 (1 + t^(3/2))

To find the population after 8 days, substitute t = 8

P = 300 (1 + 8^(3/2))

P = 7088.22

P ≈ 7088

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Answer:

$18

Step-by-step explanation:

To find how many times she has saved money, you would do 27/3=9. This means that she worked 9 times. Since she worked 9 times, she earned $45 in total. To find how much she saved you would do 45-27=$18

Answer:

Step-by-step explanation:

factoring

e =

(a+1)(a-1-3(a+1))
= (a+1)(a-1-3a-3)

= (a+1)(-2a-4)

= -2(a+1)(a+2)

The value of a is [tex]-\frac{12}{5}[/tex] if 2 is a zero of the polynomial [tex]$4 x^2-2 x+5 a$[/tex].

As per the given data, the polynomial is p(x) = [tex]$4 x^2-2 x+5 a$[/tex]

The polynomial is zero polynomial if x is 2

The places where a polynomial becomes zero overall are known as the zeros of the polynomial. The term "zero polynomial" refers to a polynomial with a value of zero (0).

Replace x with 2 we get

Therefore [tex]4(2)^2-2(2)+5 \mathrm{a}=0[/tex]

[tex]\Rightarrow[/tex] 4 (4) - 2 (2)+5 (a) = 0

[tex]& \Rightarrow[/tex] 16 - 4 + 5 (a) = 0

[tex]& \Rightarrow[/tex] 12 + 5 (a) = 0

Add -12 on both sides we get

12 + 5 (a) - 12 = 0 - 12

5 (a) = -12

Divided by 5 into both sides we get

a = [tex]-\frac{12}{5}[/tex]

Therefore the value of a is [tex]-\frac{12}{5}[/tex]

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The term "revolution" is often used to refer to a dramatic and sudden change in a situation, especially  number of a political situation. It is derived from the Latin word revolutio, which means "a turn around". The term was first used in the 1500s to describe a political movement of overthrowing a government or social system and replacing it with another.

Revolution is a term used to refer to a dramatic and sudden change in a situation, especially a political situation. It is derived from the Latin word revolutio, which means "a turn around". The term was first used in the 1500s to describe a political movement of overthrowing a government or social system and replacing it with another, thus making it a revolution.

The term "revolution" is often used to refer to a dramatic and sudden change in a situation, especially number of a political situation. It is derived from the Latin word revolutio, which means "a turn around". The term was first used in the 1500s to describe a political movement of overthrowing a government or social system and replacing it with another.

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Answer: To find an equation for a parabola that passes through three specific points, we can use the method of algebraic manipulation.

Since the parabola is symmetric about the y-axis, the equation of the parabola will have the form y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.

Given three points (-2,7), (1, 10), and (2,27), we can use the vertex form of the equation and substitute the x, y values of the three points to find the values of a, h and k

y = a(x-h)^2 + k

Since it is passing through (-2,7), we can substitute the values of x and y in the equation and get

7 = a(-2 - h)^2 + k

It passing through (1, 10), we can substitute the values of x and y in the equation and get

10 = a(1 - h)^2 + k

It passing through (2,27), we can substitute the values of x and y in the equation and get

27 = a(2 - h)^2 + k

Now we have three equations with three variables, we can solve it using any of the techniques such as substitution, elimination or matrix. But the final equation will be in the form of y= a(x-h)^2 + k

Here, x= (-2, 1, 2) and y = (7, 10, 27) . Therefore it has a unique parabola passing through these points.

Step-by-step explanation:

On solving the provided proportionality question we got that, U = 7.72, is rounded off nearest to tenth digit.

When two quantities or variables are linearly related in mathematics, the term "proportional" is used. Both quantities increase by two times when one increases by two. Each variable decreases in proportion to the other when it falls to 1/100th of its previous value.We must determine the ratio of the two quantities for each value supplied in order to determine if two quantities are proportionate. The proportionate link between them is evident if their proportions are equal. Their connection is not proportionate if all the ratios are out of balance.

Here,

U/5 = 17/11

U = 17/11 X 5

U = 7.72

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Using the mean value theorem, the least possible value of f(3) is - 2

The mean value theorem states that for a function f(x) on the interval (a, b), there exists a value c such that

f'(c) = f(b) - f(a)/(b - a)

Since ƒ(−1) = 10 and ƒ'(x) ≥−3 for all values of x, we require the least possible value of f(3).

Using the mean value theorem where

We choose f'(c) = 3 since f'(x) = 3 is the minimum value of f'(x).

So, substituting the values of the variables into the equation, we have that

f'(c) = f(b) - f(a)/(b - a)

f'(x) = f(3) - f(-1)/(3 - (-1))

f'(x) = f(3) - f(-1)/(3 + 1)

f'(x) = f(3) - f(-1)/4

So, making f(3) subject of the formula, we have that

f(3) = f(-1) + 4f'(x)

Since

Substituting the values of the variables into the equation, we have that

f(3) = f(-1) + 4f'(x)

f(3) = 10 + 4(-3)

f(3) = 10 - 12

f(3) = - 2

So, the least possible value is - 2

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Answer:

Step-by-step explanation:

A half of a cup is greater than 1/3 of a cup. This is because if you convert the fractions to the nearest common denominator (6) you can see that 1/2 = 3/6 and 1/3 = 2/6, so 1/2 of a cup is greater.

I hoped this helped!!

Answer:

L' = (-1,2)

M' = (1,2)

L'M' = 2

The slope of the original segment and dilated segment are both zero

Step-by-step explanation: just did it on edge!

The values of x , y and z are 80,2,110 respectively from the given figure where JKLM ~ EFGH

What is Quadrilateral ?

Quadrilateral can be defined as the type of the polygon in which it contains four sides.

Given ,

JKLM ~ EFGH

Since , JKLM ~ EFGH

3/30 = 11/z

 z = 30*11/3

z =110

3 / 30 = 8/ x

3 * x = 8 * 30

x = 80

3 / 30 = y/ 20

y = 20 * 3 / 30

y = 2

Hence the values of x , y and z are 80,2,110 respectively.

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By translating, stretching and contracting, or reflecting, two functions from the same function family can become one another. Any function from a function family can be obtained by applying one or more transformations to a parent function.

By altering the graph of the parent absolute value function, many other absolute value functions can be created. The resulting absolute value functions take the following form:

[tex]y = |x-h| + k[/tex], where h and k are real numbers.

Absolute value functions can be created using the same kinds of operations that produce new linear functions. They also have a similar impact on absolute value functions. The transformations may, however, appear differently graphically due to some important discrepancies between linear functions and absolute value functions.

Here are some of the transformations:

Vertical Transformations

Horizontal Transformations

This is how we graph the transformation of an absolute value function.

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Therefore , the solution of the given problem of tractable problem comes out to be Undecidable troubles are those for which there will never be a computer solution.

a technique that completes a manageable task in a polynomial period of time. Utilizing the polynomial upper bound is advantageous. A problem is said to be intractable if it cannot be solved in a polynomial amount of time. The bound has a minimum that is exponential.

Here,

Intractable problems would be those in which there is significant proof that, while they can be solved by a desktop, they cannot be solved quickly enough to be actually useful in practice.

Undecidable troubles are those for which there will never be a computer solution, whereas undecidable difficulties are those for which there will never be a computer solution.

Therefore , the solution of the given problem of tractable problem comes out to be Undecidable troubles are those for which there will never be a computer solution.

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Answer:

Step-by-step explanation:

b