its in the pic plz help

Answer:

they amplitude modulation

and they ferequency modulation

Explanation:

The difference is in how the carrier wave is modulated, or altered. With AM radio, the amplitude, or overall strength, of the signal is varied to incorporate the sound information. With FM, the frequency (the number of times each second that the current changes direction) of the carrier signal is varied.

hope it helps

Answer:

heart

Explanation:

Answer:

the velocity of the brick when it hits the ground is 39.60 m/s

Explanation:

Given;

height through which the ball is dropped, h = 80.0 m

the initial velocity of the brick, u = 0

The final velocity of the brick when it hits the ground is calculated as;

v² = u² + 2gh

v² = 0 + 2 x 9.8 x 80

v² = 1568

v = √1568

v = 39.60 m/s

Therefore, the velocity of the brick when it hits the ground is 39.60 m/s

Answer:

chemical resemblance is physically indolence

Explanation:

Due to H2O hypermolecules

Answer:

The two basic families of simple machines are the lever family and the inclined plane family. Within the lever family are the simple lever, the pulley and the wheel and axle. Within the inclined plane family are the simple inclined plane, the wedge and the screw. These simple machines create mechanical advantage when you use them, as they allow you to exert more force with less energy on loads that you could not ordinarily move.

Explanation:

Answer:

I believe c and d is the answer because a and b are more material properties.

Answer:

-140

Explanation:

A gas loses 80joules of heat.

The gas also does 60 joules of work

Therefore the change in internal energy can be calculated as follows

= -80 + (-60)

= -80-60

= -140

Hence the change in internal energy is -140

Answer:

59.18 kg

Explanation:

use f=ma

f= 580 N

a = 9.8 m/s 2

weigh(m) doesn't change only force(F) changes

Answer: 219.6N

Explanation:

Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma

580 = m*9.8

m = 59.18kg

Then multiply the mass by the new gravitational acceleration on Mars.

59.18*3.711 = 219.6N

Red shirt appears red because:

a. The shirt reflects red light

A red shirt appears red because the shirt reflects red light.

Thus, An important topic for astronomers is "red shift." The phrase can be taken literally; when the light's wavelength is extended, the light is perceived as having "shifted" toward the red portion of the spectrum.

When a source of sound moves in relation to an observer, sound waves experience a similar phenomenon.

The frequency of sound waves varies if the source of the sound and the observer are moving relative to one another, according to Austrian mathematician Christian Andreas Doppler, who made this discovery.

The observer hears a frequency that is higher when the two are moving closer together and lower when they are moving farther apart and red shift.

Thus, A red shirt appears red because the shirt reflects red light.

Learn more about Red shift, refer to the link:

https://brainly.com/question/30847331

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Answer:

The free-body diagram of the cannonball is found in the attachment below

Note The question is incomplete. The complete question is as follows:

A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglected.

Draw the free-body diagram of the cannonball.

Explanation:

Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation.

In order to construct free-body diagrams, it is important to know the various types of forces acting on the object in that situation. Then, the direction in which each of the forces is acting is determined. Finally the given object is drawn using any given representation, usually a box, and the direction of action of the forces are represented using arrows.

In the given situation of a cannonball which has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction., the forces acting on it are:

F = force exerted by the cannon acting in the direction of angle of projection

Fdrag = drag force. The drag force acts in a direction opposite to the force exerted by the cannon

Fw = weight of the cannonball acting in a downward direction

The free body diagram is as shown in the attachment below.

The final velocity of the bus  is 9.83 m/s

The given parameters;

initial velocity of the bus, = 30 km/h

constant increase in speed, = 1.5 m/s

time of motion, t = 6.8 s

The initial velocity of the bus in m/s;

[tex]v = 30 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 8.33 \ m/s[/tex]

The acceleration of the bus;

[tex]a = \frac{\Delta v}{\Delta t} = \frac{1.5 \ m/s}{6.8 \ s } = 0.22 \ m/s^2[/tex]

The final velocity of the bus at the given time of motion;

[tex]v= u + at\\\\v = 8.33 + (0.22 \times 6.8)\\\\v = 9.83 \ m/s[/tex]

Thus, the final velocity of the bus  is 9.83 m/s

Learn more here: https://brainly.com/question/17956487

Answer:

2.5 k

Explanation:

Answer:Number of waves =2.2

Explanation:

The frequency of A wave is defined as the number of waves moving  a fixed point per second which is given as

f=[tex]\frac{N}{t}[/tex]

F= Frequency

N= number of waves

t= time

We first find the frequency

Given velocity of the wave, v = 13m/s

and wavelength, λ as 6meters(distance between two consecutive crest)

, we fiind the frequency using

v= f  λ

frequency = v /  λ

= (13m/s ) / 6

=2.16s-1

f =  [tex]\frac{N}{t}[/tex]

2.16s₋¹=  [tex]\frac{N}{1s}[/tex]

Therefore N, Number of waves =  2.16 waves  rounded up to 2.2 waves

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

Answer:

bhgyg 78 gt78gyug

Explanation:

Answer:77.98

Explanation:

Answer:

Water vapor is steam. An example of water vapor is the floating mist above a pot of boiling water. Water in the form of a gas; steam.

Explanation:

the number is 1 I hope this help

Answer:

Explanation

The work done by the lifter is equal to its potential energy since he is covering a height and under the influence of gravity.

potential energy = mass * acceleration due to gravity * height

m is the mass

g is the acceleration due to gravity

h is the height

Hence the required workdone = PE = mgh

Answer:

A molecule is defined as two or more atom of same element or different element grouped together

Answer:

20 kg

More force required after placing weight in trunk to accelerate the trunk than before when the trunk is empty.

Explanation:

We are given that

Mass of empty trunk, m=10 kg

Mass of a weight, m'=10 kg

We have to find the total mass after placing weight in trunk and how will this affect the force needed to accelerate the trunk.

Total mass =m+m'

Total mass=10+10=20 kg

We know that

Force, F=ma

Force is directly proportional to mass.

When we placed weight in trunk then the mass of trunk increases .Therefore, now more force required to accelerate the trunk than before when the trunk is empty.

Answer:

Evaporation is the vaporization of a liquid to the gaseous phase which occurs at the liquid's surface when the gas above the surface is unsaturated or contains less amount of the evaporating substance and the molecules at the surface absorbs enough energy during the transfer of energy from internal collision to withstand the vapor pressure of the surrounding and exist as a gas

a) Evaporation can explain the decrease in mass as follows;

Given that evaporation is the conversion of a liquid to a gas, the loss in mass of the ethanol can be explained by the conversion of some of the ethanol liquid to gas by evaporation such that the volume of ethanol remaining, and therefore, the mass of ethanol is reduced

b) The evaporation of the energized ethanol molecules from the surface of the ethanol results in a loss of energy of the remaining ethanol in the beaker, which can be observed as a reduction in temperature of the ethanol

Explanation:

Answer:

Gravity

Explanation:

Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all

Answer:

A force is a push or pull on an object. Forces usually cannot be seen but their effects can.

Nothing moves, changes speed, stops or changes direction without force. Heavier objects need more

force to get them to move or change direction.

Explanation:

Answer:

given..

m= 3.5

t= 3

d=25

f=?

now....a...

25=1/2a×9

a=50/9

f=ma=35/10×50/9=19.4N

Answer:

B) Synthesis

Explanation:

A combination reaction, also known as a synthesis reaction in chemistry, is when two or more substances, or reactants, combine with each other to form a new product. The product will always be a compound.

Answer:

1) q₃ is approximately -7.58 nC

2) The direction of the net force on 'q₃' is the negative '-' direction

3) For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m

Explanation:

1) The force, 'F', between two charged spheres is given as follows;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]

The net force acting on the point charge, 'q₃', is given as follows;

[tex]F_{NET} = \dfrac{k \cdot q_1 \cdot q_3}{x_1^2} + \dfrac{k \cdot q_2 \cdot q_3}{x_2^2}[/tex]

By substituting the given values, we have;

[tex]F_{NET} = 3.10 \ \mu N = \dfrac{k \cdot (-4.10 \ nC) \cdot q_3}{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC \cdot q_3}{(-0.320 \ m)^2}[/tex]

[tex]3.01 \ \mu N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC }{(-0.320 \ m)^2} \right) = -\dfrac{14117 \ nC \cdot K}{320}[/tex]

[tex]\therefore q_3 = 3.01 \ \mu N \times -\dfrac{320 \ m^2}{14117 \ nC \cdot K}[/tex]

K = 9 × 10⁹ N·m²·C⁻²

[tex]\therefore q_3 = 3.01 \ \times 10^{-6} \ N \times -\dfrac{320 \ m^2}{14117 \times 10^{-9} \ C \times 9 \times 10^9 \ N \cdot m^2 \cdot C^{-2}}= -7.58 \ nC[/tex]

q₃ ≈ -7.58 nC

2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin

The net force's direction on q₃ will be in the '-' direction

3) For zero net force, we have;

The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m

Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1

By substitution, we have;

[tex]0 \ N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.57 - r_1 ) ^2} + \dfrac{k \cdot 2.20 \ nC }{(r_1)^2} \right)[/tex]

[tex]\therefore \dfrac{k \cdot 4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{k \cdot 2.20 \ nC }{(r_1)^2}[/tex]

From which we have;

[tex]\dfrac{4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{2.20 \ nC }{(r_1)^2}[/tex]

(r₁)²×4.10 = 2.20 × (0.57 - r₁)²

From the above equation, we have;

95,000·r₁²+ 125,400·r₁-35739 = 0

Solving, using a graphing calculator we get;

r₁ ≈ 0.241 or r₁ ≈ -1.561

Where, 'r₁', is measured from 'q₂', therefore, we have;

r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881

Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero