Need help can someone plz help me

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

The given vertex and Focus are of a vertical parabola having an opening downward as the focus is in downward direction as the vertex.

Focus of the parabola can be written as :

[tex]\qquad \sf  \dashrightarrow \: (h ,k+ a )[/tex]

where, h and k are coordinates of vertex

so,

So, the equation of parabola can be written as :

[tex]\qquad \sf  \dashrightarrow \: (x - h) {}^{2} = 4a(y - k)[/tex]

plug in the values ~

[tex]\qquad \sf  \dashrightarrow \: (x - 1) {}^{2} = 4(- 1)(y + 1) {}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \: (x - 1) {}^{2} = - 4(y + 1)[/tex]

Answer:

[tex](x-1)^2=-4(y+1)[/tex]

Step-by-step explanation:

Standard form of a parabola with a vertical axis of symmetry:

[tex](x-h)^2=4p(y-k) \quad \textsf{where}\:p\neq 0[/tex]

Given:

Comparing with the formulas:

⇒ h = 1

⇒ k = -1

⇒ k + p = -2  ⇒ -1 + p = -2  ⇒ p = -1

Substituting the values into the formula:

[tex]\implies (x-1)^2=4(-1)(y-(-1))[/tex]

[tex]\implies (x-1)^2=-4(y+1)[/tex]

Answer:

Step-by-step explanation:

hello :

x² +5x+3=0

delta = b²-4ac   when :  a =1  and b=5    c=3

delta =5²-4(1)(3) =13

X1 =(-b-sqrt(delta))/2a

X2 =(-b+sqrt(delta))/2a

continu.....

Answer:

1/21

Step-by-Step Explanation:

Let's solve your equation step-by-step.

3(1−5x)=2(3x+1)

Step 1: Simplify both sides of the equation.

3(1−5x)=2(3x+1)

(3)(1)+(3)(−5x)=(2)(3x)+(2)(1)(Distribute)

3+−15x=6x+2

−15x+3=6x+2

Step 2: Subtract 6x from both sides.

−15x+3−6x=6x+2−6x

−21x+3=2

Step 3: Subtract 3 from both sides.

−21x+3−3=2−3

−21x=−1

Step 4: Divide both sides by -21.

-21x/-21=-1/-21

x=1/21

[tex]\boldsymbol{\sf{3(1-5x)=2(3x+1)}}[/tex]

Reorder terms

Distribute

Subtract 3x from both sides.

Simplify

Subtract 6x from both sides.

Simplify

Divide both sides by the same factor

Simplify

Answer:

A = -5

B = 1

Step-by-step explanation:

Hello!

You simply plug in the given x-value into the equation to find the missing y-value.

Plug in -1 for x into y = 2x - 3.

Plug in 2 for x into y = 2x - 3.

The equivalent of the expression [ (z−3)4z−6 ] is 4z² - 12z - 6.

Given the expression; (z−3)4z−6

First, we apply distributive property.

(z−3)4z−6

(z−3)4z−6

z(4z) - 3(4z) - 6

We remove the parentheses

4z² - 12z - 6

Therefore, the equivalent of the expression [ (z−3)4z−6 ] is 4z² - 12z - 6.

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Answer:

2nd option

Step-by-step explanation:

to find f(h(x)) substitute x = h(x) into f(x) , that is

f(h(x))

= f(2x + 3)

= 2x + 3 - 7

= 2x - 4

Answer: m > -16

Step-by-step explanation:

[tex]\frac{3}{4}m > -12\\\\m > -\frac{4}{3}(12)=-16[/tex]

Answer:

x = ±√10i (i outside the radical), or approximately ±3.62i, or no solution depending on your class.

Step-by-step explanation:

x^2 + 10 = 0

x^2 = -10

x = ±√-10

x = ±√10i (i outside the radical), or approximately ±3.62i.

The solution is not real.

If you meant x^2 - 10 = 0 then x = ±√10 or approximately ±3.62. This solution is real.

Answer:

It is the second answer.

Step-by-step explanation:

When numbers with the same base are multiplied, you add the bases.

1/2 + 3/4 is the same as

2/4 + 3/4 = 5/4

So now we have 2 ^5/4^2.  When we have a power raised to a power.  We multiply the powers.

5/4(2)

(5/4(2/1) = 10/4 = 5/2.  The second answer is the same way to describe

2^(5/2)

Answer:

they are the same line

Step-by-step explanation:

if you divide the first line by 2 you'll get:

2(3x)+2y=2(23)===> 3x+y=23

Given the money invested and the interest rate, the value of the interest earned after 8 months is $82.50.

From the equation of simple interest; I = PRT

Given that;

I = PRT

I = $4,500 × 0.0275 × 8/12

I = $82.50

Given the money invested and the interest rate, the value of the interest earned after 8 months is $82.50.

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$9.75

Given the information, we know that for the first 3 days, she spends a total of $7.25. On the fourth day, she deposits $10 before buying lunch for $3.

This means she had $20, but spent $10.25. $20-$10.25=$9.75 is the amount she has in her account.

Answer:

18.5 miles

Step-by-step explanation:

the Sun at an average speed of 67,000 mph, or 18.5 miles a second.

The situation presented can be represented using the following letters CC, CP, PC, and PP.

The possible combinations are:

Based on this, the option that represents the situation is:

CC, CP, PC, and PP.

Note: This question is incomplete; here is the missing section:

What is the sample space of the event described above?

Answer choices:

a. CC, CP, PC, PP

b. CC, PP

c. CC, CP, PC

d. C, P

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Answer: 1/5

Step-by-step explanation:

There are 10 numbers, out of 50, which have a 4 in their tens place: 40, 41, 42, 43, 44, 45, 46, 47, 48, and 49.

Therefore our desired probability is 10/50 or 1/5.

Considering the given proportion, the value of [tex]\frac{a}{a - b}[/tex] is:

C) 2

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The proportion between a and b is given by:

a/b = 2.

Then:

a = 2b.

The expression is:

[tex]\frac{a}{a - b} = \frac{2b}{2b - b} = \frac{2b}{b} = 2[/tex]

Hence option C is correct.

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Answer:

12.5 inches

Step-by-step explanation:

We use proportion to calculate the scale drawing

27 feet = 5 inches, so

67.5 feet = more inches (we know that it would be bigger than 5 inches)

We then put the bigger number on top and crossmultiply by saying:

67.5 over 27 × 5

Your answer should come out as 12.5 inches.

The completion of the following table under different depreciation methods is as follows:

Method                           Year 1                     Year 2

Straight line                   $18,000                 $18,000

Units of production      $54,000                 $13,500

Declining balance        $37,600                $22,560

MACRS (5-year class)   $18,800                $30,080

Cost of machine = $94,000

Residual value = $4,000

Depreciable value = $90,000 ($94,000 - $4,000)

Estimated useful life = 5 years

Depreciation expense:

Straight-line method = $18,000 ($90,000/5)

Estimated units of produciton = 100,000

Unit depreciation rate = $0.90

Actual production   Depreciation

Year 1 = 60,000      $54,000 ($0.90 x 60,000)

Year 2 = 15,000      $13,500 ($0.90 x 15,000)

Declining Balance:

Year 1 = $37,600 ($94,000 x 40%)

Year 2 = $22,560 ($94,000 - $37,600) x 40%

MACRS:

Year 1 = $18,800 ($94,000 x 20%)

Year 2 = $30,080 ($94,000 x 32%)

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Answer:

Part A

1. A third degree polynomial has exactly three zeros. This is because its highest power (or degree) is 3. Ray would only be correct in saying that a polynomial can have 4 zeros if it is a 4th degree polynomial. Since in this case, a 4rd degree polynomial is being discussed, Kelsey is correct.

2. Function chosen: g(x) = (x + 2)(x - 1)(x - 2)

End behaviour: x —> ∞, g(x) —> ∞

                         x —> - ∞, g(x) —> -∞

Zeros/x intercepts of the function: -2, 1, 2

y intercept: g(x) = (x + 2)(x - 1)(x - 2)

                   g(x) = (0 + 2)(0 - 1)(0 - 2)

                   g(x) = (2)(-1)(-2)

                   g(x) = 4

3. See Graph 1

Part B

4. f(x) = (x + 5)(x + 3)

Direction: opens upward

Zeros/x intercepts: -5, -3

y intercept: 15

5. See graph 2

Part C

You can draw the roller coaster yourself using the graphs below

Answer: 22

Step-by-step explanation:

[tex]f(f^{-1}(x))=f^{-1}(f(x))=x[/tex]

Using translation concepts, function g(x) is given as follows:

g(x) = x² - 3.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

Researching this problem on the internet, g(x) is a shift down of 3 units of f(x) = x², hence:

g(x) = x² - 3.

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Answer:

(0,3)

(-1,1)

Step-by-step explanation:

Hello!

Since both equations are equal to y, we can set the right-hand side of the equations equal to each other.

X can either be 0 or -1. Remember, a solution to a system is not complete without a y-value. Plug in 0 and -1 for x in the first equation, and find the corresponding y-values.

[tex]y = 2(0) + 3\\y = 3[/tex]

And

[tex]y = 2(-1) + 3\\y = -2 + 3\\y = 1[/tex]

So the solutions to the system are (0,3) and (-1,1)

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

There is one angle and an adjacent side of the triangle given equal to corresponding angle and side of the other triangle and if we observe the figure we can see that there's also a adjacent side XY common in both the Triangles.

Hence, the two triangles are congruent by SAS congruency criteria.

[tex] \qquad \large \sf {Conclusion} : [/tex]

Answer:

angles of the triangle are equal 180

so 42+82=124

180-124=56

so the answer is 56

Step-by-step explanation:

The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the number of children and y represent the number of adult, hence:

5.2x + 9.9y = 1303.5     (1)

Also:

x + y = 163    (2)

From both equations:

x = 66, y = 97

The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.

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The cost given shows that the amount left is £12.

From the information given, it was stated that the person saved £60 and spent £42 on coat and £6 on scarf

The amount that the person has left will be:

= £60 - £42 - £6

= £12

In conclusion, the person has £12 left.

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Step-by-step explanation:

8.√128/√2

ans √64

10.3√81

3√3*3*3*3(find factor)

3 √3(this is cube root therefore we kept one out of three then we kept remaining inside of root.this is surds because one factor is inside the surds if factor is not remaining inside the surds then this is not surds)

For the circular cover we have:

A) The area is 379.94 ft²

B) The length of the rope must be 68.2 ft

Remember that the area of a circle of radius R is given by the formula:

[tex]A = pi*R^2[/tex]

Where pi = 3.14

In this case, the diameter of the pool is 20ft, then the radius is:

R = 20ft/2 = 10ft

And it must extend 12 inches beyond, then the radius of the cover must be:

R = 10ft + 12in

Now, we know that 1ft = 12 in, then we can rewrite the radius as:

R = 10ft +1ft = 11ft

Then the area of the cover is:

[tex]A = 3.14*(11ft)^2 = 379.94 ft^2[/tex]

B) now we want to get the length of the rope, we know that the rope runs along the cover, then the length of the rope must be equal to the circumference of the cover.

Remember that the circumference of a circle of radius R is:

[tex]C = 2*pi*R[/tex]

Then the length of the rope will be:

[tex]C = 2*3.14*11ft = 68.2ft[/tex]

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If I deposit $400 each month into an account earning 8% interest compounded monthly, I will have $6,517 in my account in 35 years. The total money that I will put into the account is $168,000. I will earn a total compound interest of $6,117.

Given information is as follows,

Principal, P = $400

Rate = 8%

Time, T = 35 years

n = 12 (Compounded monthly)

The amount for compound interest is given as,

A = [tex]P\frac{(1+\frac{R}{n} )^{nT} -1}{R/n}[/tex]

A = [tex]400\frac{(1+\frac{0.08}{12} )^{12.35} -1}{0.08/12}[/tex]

A = 6,517.02

A = $6,517 (to the nearest cents)

Since, $400 is deposited every month for 35 years,

Amount Put in 35 years for this compound interest =$400 × 12 × 35

= $168,000

A = P + CI

Thus, the compound interest is given by,

CI = A - P

CI = 6517 - 400

CI = $6,117

I will earn a total interest of $6,117

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