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Answer:

The coefficient of  correlation=0.5

Step-by-step explanation:

We are given that

Covariance between the variable  x and y=18

Variance of x=16

Variance of y=81

We have to find the coefficient of correlation

We know that

Coefficient of correlation

[tex]r=\frac{covariance(x,y)}{\sqrt{variance(x)}\times \sqrt{variance(y)}}[/tex]

Using the formula

[tex]r=\frac{18}{\sqrt{16}\times \sqrt{81}}[/tex]

[tex]r=\frac{18}{4\times 9}[/tex]

[tex]r=0.5[/tex]

Hence, the coefficient of  correlation=0.5

Answer:

im not sure im sorry

Step-by-step explanation:

not sure

Answer:

i got you.

whats up

Step-by-step explanation:

Answer:

[tex]A = 2[/tex]

[tex]B = -1[/tex]

[tex]C = -9[/tex]

Step-by-step explanation:

Given

[tex]2x\² + 15x + 19 = Ax\² + 8Ax + 16A + Bx + 4B + C[/tex]

Required

Find A, B and C

Rearrange the expression

[tex]2x\² + 15x + 19 = Ax\² + 8Ax + 16A + Bx + 4B + C[/tex]

[tex]2x\² + 15x + 19 = Ax\² + 8Ax + Bx + 16A + 4B + C[/tex]

To do this, we simply compare the expressions on both sides of the equation.

So, we have:

[tex]Ax\² = 2x\²[/tex] --- (1)

[tex]8Ax + Bx = 15x[/tex] --- (2)

[tex]16A + 4B + C = 19[/tex] --- (3)

Divide both sides by x² in (1)

[tex]Ax\² = 2x\²[/tex]

[tex]A = 2[/tex]

Divide both sides by x in (2)

[tex]8Ax + Bx = 15x[/tex]

[tex]8A + B = 15[/tex]

Substitute 2 for A.

[tex]8*2 + B = 15[/tex]

[tex]16+ B = 15[/tex]

Make B the subject

[tex]B = 15 - 16[/tex]

[tex]B = -1[/tex]

Substitute 2 for A and -1 for B in (3)

[tex]16A + 4B + C = 19[/tex]

[tex]16*2 + 4*-1 + C = 19[/tex]

[tex]32 - 4 + C = 19[/tex]

[tex]28 + C = 19[/tex]

Make C the subject

[tex]C = 19 - 28[/tex]

[tex]C = -9[/tex]

Answer:

it D

Step-by-step explanation:

I just used elimination like a small brain

like so

when a = 1, b = 0, c = 3, d = -3

x^3 + 8x – 3 = Ax^3 + 5Ax + Bx^2 + 5B + Cx + D

Answer:

X=.5

Step-by-step explanation:

First, I rewrite the equation:

[tex]\frac{19x}{x+9}[/tex]= [tex]\frac{x+9}{x}[/tex]

Next, Cross Multiply:

19x times x is 19x^2

x+9 times x+9 equals (x+9)^2

Write the Formula Again, Revised:

19x^2=(x+9)^2

Square Root Both Sides:

19x=x+9

Subtract x from both sides:

18x=9

Divide Both Sides by 18:

X=.5

.5 is the answer

i hope this helps!

Please Give ,e feedback (or brainliest) to let me know if im right!

Answer:

120mm

Step-by-step explanation:

Thank u....

............

Answer:

B.

Step-by-step explanation:

It is the right answer, I promise.

Answer:

It is B. Length = 22 Feet, Width = 20 Feet

Step-by-step explanation:

I got it right once

Answer:

no entender veri mucho......aaaa

Step-by-step explanation:

step 1. 24x - 38 = 46 (distributive property)

step 2. 24x = 84 (add 38 to both sides)

step 3. x = 84/24 = 21/6 = 7/2 (divide by 24 and simplify).

Answer:

122.6 m

Step-by-step explanation:

Shadow cast by the man = 3.1 m

Height of the man = 1.9 m

Shadow cast by the lighthouse = 200 m

Height of the lighthouse = x

If two shapes are similar, the ratio of their corresponding sides would be equal.

Therefore,

x/1.9 = 200/3.1

Multiply both sides by 1.9

x = (200*1.9)/3.1

x = 122.6 m (nearest tenth)

The lighthouse is 122.6 m tall

Answer:

(x+y+z)(a+3)

Step-by-step explanation:

ax+ay+az+3x+3y+3z

=(ax+ay+az)+(3x+3y+3z)

=a(x+y+z)+3(x+y+z)

=(x+y+z)(a+3)

Answer:

1) 7/12

2) 35/132

Step-by-step explanation:

1) 7/12

2) 7/12x5/11=35/132

Answer:

the last one

Step-by-step explanation:

the input cannot be negative

Answer:

D im pretty sure. "Uses a convex eyepiece lens”

Step-by-step explanation:

I am taking quiz rn

The correct label that could be written in the area marked X is "Uses a convex eyepiece lens".

The Venn diagram is a mathematical representation of the system of scenarios.

Here,
The overlapping area between the two circles represents the features that both types of telescopes share. Reflecting telescopes use concave eyepiece lenses the primary optical element while refracting telescopes use a convex eyepiece lens. So the X in the overlapping area represents the fact that there are some telescopes that “Use a convex eyepiece lens".

A concave mirror is used in reflecting telescopes to collect and focus light, while a convex eyepiece lens is used to magnify the image. The other two options ("Uses a convex mirror" and "Uses a concave mirror") are not accurate for both types of telescopes.

Learn more about Venn diagrams here:

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#SPJ6

9514 1404 393

Answer:

  S > 2

Step-by-step explanation:

In this context, "over" means "greater than." The problem statement tells you the weight (S) is greater than 2 kilograms:

  S > 2

Answer:

13,243

Step-by-step explanation:

hope this helps

i am bad at math

Answer:

The correct answer is (-1,-3)

Step-by-step explanation:

its right i think lol

Answer:

1

Step-by-step explanation:

-16 + x = -15

+16          +16

x = 1 because -15 + 16 is 1

Answer:

slope is 5

Step-by-step explanation:

use formula (y2-y1)/(x2-x1) to find the slope

(2-(-3))/(6-5)

= 5/1

=5

if you want the equation to the graph here:

y=mx+b

2=5(2)+b

2=10+b

b=-8

equation: y=5x-8

Answer:

7, 22

Step-by-step explanation:

3!=6+6=12/3=4!=24-4=20-10=10-3=7

11-1=10+2=12/6=2x11=22

Answer:

Mathematical expectation is to get  %280%2B3%2B7%2B22%29%2F4 = 32%2F4 = 8 dollars from the envelopes.

Statistically, it is loosing game.Step-by-step explanation:

Answer:

7.7

Step-by-step explanation:

I did it on edu!

You can use the fact that area of a rectangle is its length times its width.

The length of the given rectangle is 28 feet.

Area of a rectangle is its length times its width.

If a rectangle has length x units and width y units, then we have:

[tex]Area = x \times y \: \rm unit^2[/tex]

Most of the times, you will get some other facts or information by which the unknown values of those items can be known. For simple daily life cases, we can use variables, which are nothing but just placeholders for those unknown values. We can then operate on those variables assuming them to be actual values, thus, getting near to their original values.

Let the length of the given rectangle be x units, and let its width be y

Then as it is given that

Length of the rectangle = 2 times width of the rectangle

or

[tex]x = 2 \times y[/tex]

We have area= 392 square feet

Since area = length times width, thus, we have

[tex]Area = x \times y\\392 = 2 \times y \times y\\\\\dfrac{392}{2} = y^2\\\\y^2 = 186\\\\\text{\:(Taking positive root on both the sides since y is width, a non negative quantity)}\\\\y = \sqrt{196} = 14[/tex]

Thus, the width of the rectangle is 14 feet

And thus, the length of the rectangle = double of width = 28 feet.

Thus,

The length of the given rectangle is 28 feet.

Learn more about area of rectangle here:

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Answer:

14 dimes and 4 quarters

Step-by-step explanation:

x= number of dimes

y=number of quarters

x-10=y

0.10x+0.25y=2.40

substitute for y

0.10x+0.25(x-10)=2.40

0.35x-2.50=2.40

0.35x=4.90

x=14

y=4

Answer:

i feel like the answer is d srry if im wrong

Step-by-step explanation:

Answer:

Step-by-step explanation:

The equation for that is

[tex]x^2+3x=70[/tex]

If we subtract over the 70, we have a quadratic that we can factor to solve for the values of x that will make that equation true.

[tex]x^2+3x-70=0[/tex]

Now we need the factors of 70 that will either add or subtract to give us the linear term of 3. The factors of 70 that will work are 10 and 7. 10 times 7 is 70, and 10 - 7 = 3:

[tex]x^2+10x-7x-70=0[/tex] and now we will factor by grouping:

[tex](x^2+10x)-(7x-70)=0[/tex] and factor out what's common:

[tex]x(x+10)-7(x+10)=0[/tex]

The factor (x + 10) is common, so we will now factor that out:

[tex](x+10)(x-7)=0[/tex]

By the Zero Product Property, either x + 10 = 0 or x - 7 = 0, so x = -10 or 7

Those are the 2 numbers that will work.

[tex](-10)^2+3(-10)=70[/tex] simplifies to

100 - 30 which does in fact equal 70. OR

[tex](7)^2+3(7)=70[/tex] which simplifies to

49 + 21 which also equals 70.

So you're done!

The values of the unknown number is 7 or - 10

The given expression from words to algebra;

let the unknown number = n

the square of the number = n²

three times the number = 3n

n² + 3n = 70

To find:

The values of n is calculated as follows;

[tex]n^2 + 3n = 70\\\\n^2 + 3n - 70 = 0\\\\factorize \ the \ equation;\\\\n^2 + 10n - 7n - 70 = 0\\\\n(n + 10) - 7(n + 10) = 0\\\\(n-7)(n+ 10) = 0\\\\n = 7 \ or \ - 10[/tex]

Thus, the values of the unknown number is 7 or - 10

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Answer:

c

Step-by-step explanation:

none of them equal (x+y)-(-z)

Answer:

The sample proportion of size 177 is more likely to exceed 22%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Suppose both populations of hellbenders are known to have ranavirus infections at a rate of 25%.

This means that [tex]\mu = p = 0.25[/tex]

Sample of size 118:

[tex]n = 118, so [tex]s = \sqrt{\frac{0.25*0.75}{118}} = 0.0399[/tex]

Probability of sample proportion above 22%.

This is 1 subtracted by the pvalue of Z when X = 0.22. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.22 - 0.25}{0.0399}[/tex]

[tex]Z = -0.75[/tex]

[tex]Z = -0.75[/tex] has a pvalue of 0.2266

1 - 0.2266 = 0.7734

0.7734% probability that a random sample of size 118 exceeds 22%.

Sample of size 177:

[tex]n = 177, so [tex]s = \sqrt{\frac{0.25*0.75}{118}} = 0.0325[/tex]

Probability of sample proportion above 22%.

This is 1 subtracted by the pvalue of Z when X = 0.22. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.22 - 0.25}{0.0325}[/tex]

[tex]Z = -0.92[/tex]

[tex]Z = -0.92[/tex] has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that a random sample of size 177 exceeds 22%.

82.12% > 77.34%, so the sample proportion of size 177 is more likely to exceed 22%.

The sample proportion that is more likely to exceed 22% is; the sample proportion with a sample size of 177

We are given;

Population proportion; p = 25% = 0.25

Now, in central limit theorem, the formula for standard deviation is;

σ = √(p(1 - p)/n)

For a sample size of 118, we have;

σ = √(0.25(1 - 0.25)/118)

σ = √0.001588983

σ = 0.03986

Similarly, for a sample size of 177, we have;

σ = √(0.25(1 - 0.25)/177)

σ = √0.001059322

σ = 0.032547

Since we want to find which of the two sample proportions will likely exceed 22% which is p₀ = 0.2, we will use the formula;

z = (p₀ - p)/σ

For sample size of 118, we have;

z = (0.22 - 0.25)/0.03986

z = -0.75

From online p-value from z-score calculator, we have;

p-value = 0.7734 or 77.34%

For sample size of 177, we have;

z = (0.22 - 0.25)/0.032547

z = -0.92

From online p-value from z-score calculator, we have;

p-value = 0.8212 or 82.12%

The p-value of the sample of 177 is higher than the p-value for the sample of 118 and so we can say that the sample proportion with a sample size of 177 is more likely to exceed 22%

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