PLSSSSSSSSSSS HELP FOR 100 point and thebrainlist PLSSSSSS Anticipation Guide
Last Slide
Before completing the lesson, read the statements below, think about your prior knowledge, and put an x in the box for true or false (column I and 2). As you go through the lesson, look for evidence to support or refute your ideas. You will revisit this anticipation guide after completing this lesson. For now, only complete columns I and 2.

Answer:

(D)  the frictional force must be greater than the component of the gravitational force that acts down the ramp

If an equal amount of heat energy is applied to all the substances at the same time, aluminum will heat up more quickly compared to the other substances.

What is Specific Heat ?

Specific heat is the amount of heat energy required to raise the temperature of a substance by a certain amount, usually one degree Celsius or one Kelvin, per unit mass of the substance. It is a physical property that determines how much energy is needed to change the temperature of a material. Different materials have different specific heat values, which can be used to predict how they will behave when heated or cooled.

Looking at the table, we can see that water has the highest specific heat capacity of all the substances listed, at 4.18 J/g°C. This means that it requires more energy to raise the temperature of water compared to the other substances. Therefore, if an equal amount of heat energy is applied to all the substances at the same time, water will heat up more slowly compared to the other substances.

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The pressure exerted by the man on the lilo is 450 pascals (Pa).

The pressure is the force per unit area, so we can calculate it using the formula:

pressure = force / area

In this case, the force is the weight of the man, which is 900 N, and the area is the surface area of the lilo, which is 2 m². Therefore, we can substitute these values into the formula:

pressure = 900 N / 2 m²

Simplifying, we get:

pressure = 450 Pa

Therefore, the pressure exerted by the man on the lilo is 450 pascals (Pa).

What is pressure?

Pressure is the amount of force applied per unit area over a surface. It is defined as the force per unit area perpendicular to the surface on which the force is acting. The unit of pressure is pascal (Pa), which is equivalent to one newton per square meter (N/m²).

What is force?

Force is a physical quantity that describes the interaction between two objects that can change the state of motion or shape of an object. It is defined as an influence that causes an object to undergo acceleration, or a change in velocity, or deformation.

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Explanation:

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A. The hockey puck moved at a constant speed away from Janine.

The hockey puck is in equilibrium as a result of moving at a steady pace. Dynamic equilibrium is the name given to this form of equilibrium. Hence, if the hockey puck is moving over the ice at a constant pace, it is in equilibrium.

There is no connection between velocity and speed; velocity is the direction that an object moves in. Velocity is the combination of speed and direction. Speed and velocity are very similar to each other.

The sum of the forces exerted on an object must be zero since, in accordance with Newton's first law of motion, an object moving at a constant speed experiences no net external force.

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the given values, we get va = sqrt((350 kg * 9.81 m/s² - 0)))

Since the cable is inextensible, the distance moved by both blocks is the same.

Let's denote the distance moved by both blocks as "d". Then, the distance moved by block A is "1m + d" to the right.

Using conservation of energy, we can write:

(1/2) * ma * va² + (1/2) * mb * vb²= (ma + mb) * g * d

where ma and mb are the masses of blocks A and B, va and vb are their velocities, and g is the acceleration due to gravity.

Since the system is released from rest, va = 0, and we can solve for vb:

(1/2) * mb * vb²= (ma + mb) * g * d

vb²= 2 * (ma + mb) * g * d / mb

vb = sqrt(2 * (ma + mb) * g * d / mb)

Now, we need to find the velocity of block A after it has moved 1m + d to the right. To do this, we can use the equations of motion. Since block A is moving to the right, we take the positive x direction to be to the right. Then, we have:

ma * a = T - fa

where a is the acceleration of block A, T is the tension in the cable, and fa is the frictional force acting on block A due to the incline.

The tension in the cable is the same throughout, so we can write:

T = mb * g

The frictional force fa can be calculated using:

fa = µ * ma * g * cos(theta)

where µ is the coefficient of friction, theta is the angle of the incline, and cos(theta) = 1/sqrt(2) since the incline makes a 45 degree angle with the horizontal.

Substituting these values, we get:

ma * a = mb * g - µ * ma * g / sqrt(2)

Solving for a, we get:

a = (mb * g - µ * ma * g / sqrt(2)) / ma

Now, we can use the equations of motion again to find the final velocity of block A after it has moved 1m + d to the right. We have:

d = (1/2) * a * t²

where t is the time taken by block A to move 1m + d to the right.

Substituting the value of a, we get:

d = (1/2) * [(mb * g - µ * ma * g / sqrt(2)) / ma] * t²

Solving for t, we get:

t = sqrt(2 * d * ma / (mb * g - µ * ma * g / sqrt(2)))

Finally, we can use the equations of motion again to find the final velocity of block A. We have:

1m + d = (1/2) * a * t²

Substituting the values of a and t, we get:

1m + d = (1/2) * [(mb * g - µ * ma * g / sqrt(2)) / ma] * [2 * d * ma / (mb * g - µ * ma * g / sqrt(2))]²

Solving for the final velocity of block A, we get:

va = sqrt((mb * g - µ * ma * g / sqrt(2)) / ma * (1m + d) / 2)

Substituting the given values, we get:

va = sqrt((350 kg * 9.81 m/s² - 0

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Answer:

F.  The forces exerted by the meteor and the spacecraft on each other will be of equal strength.

Cleats or dogs are pieces of metal that are temporarily attached to the weldment’s parts to enable them to be forced into place. Anytime these pieces of metal are used, they must be removed, and the area around Smooth

In this case option D

Cleats or dogs are pieces of metal that are commonly used in welding to temporarily attach the parts of the weldment in place. They are typically small metal pieces with angled ends that can be clamped or welded onto the parts being joined to hold them in the correct position during the welding process.

Once the welding is completed, the cleats or dogs must be removed and the area where they were attached must be ground smooth.

This ensures that the final welded joint has a smooth and even surface and that there are no residual metal pieces that could interfere with the joint's structural integrity.

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Answer:

Explanation:

The work-energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we can use this theorem to calculate the final kinetic energy of the ball in each case.

We know that the work done by a constant force is given by the equation W = Fd cos(theta), where F is the magnitude of the force, d is the displacement of the ball, and theta is the angle between the force and displacement vectors.

Using the work-energy theorem, we can write:

W = ΔK = Kf - Ki

where ΔK is the change in kinetic energy, Kf is the final kinetic energy, and Ki is the initial kinetic energy.

We can rearrange this equation to solve for Kf:

Kf = Ki + W = Ki + Fd cos(theta)

a) Kf = 150 J + (10 N)(15 m)cos(90°) = 150 J

b) Kf = 300 J + (200 N)(1.5 m)cos(180°) = 0 J

c) Kf = 200 J + (25 N)(4 m)cos(0°) = 300 J

d) Kf = 450 J + (15 N)(30 m)cos(150°) = 112.5 J

Ranking from greatest to least final kinetic energy:

c) Ki=200J F=25N d=4m theta=0 degrees

a) Ki=150J F=10N d=15m theta=90 degrees

d) Ki=450J F=15N d=30m theta=150 degrees​

b) Ki=300J F=200N d=1.5m theta=180 degrees

The perimeter of the pool is approximately 206.85 feet if we use 3.14 as the approximation of the value of π.

In this case, the angle AOB is 360 degrees, so the arc length is:

arc length = (360/360) x 2π(25) = 50π feet

Finally, we can find the perimeter of the pool by adding up the lengths of the two semicircles and the arc AB:

perimeter = 2πr + 2r + arc length

perimeter = 2π(25) + 2(25) + 50π

perimeter = 50π + 50

Perimeter is a measurement of the distance around the edge of a two-dimensional shape, such as a square, rectangle, or circle. It is the sum of the lengths of all the sides that make up the shape. The perimeter is an important concept in geometry and is used to determine the amount of material needed to enclose or surround a shape, as well as to calculate the distance around a given route or path.

To find the perimeter of a shape, you simply add up the lengths of its sides. For example, if you have a square with sides that are each 5 units long, the perimeter would be 5 + 5 + 5 + 5 = 20 units. Similarly, if you have a circle with a radius of 10 units, the perimeter (also known as the circumference) would be 2πr or approximately 62.8 units.

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Complete Question: -

If AO is 50 feet, find the perimeter of the pool. (O is the center of the sector AOB. OA and OB are the diameters of two semi-circles.)

The answers to the questions are:

Operant conditioning is a type of learning in which behavior is modified by its consequences. It involves the association of a behavior with its consequences, either reinforcement or punishment.

Reinforcement is when a consequence strengthens or increases the likelihood of a behavior occurring again in the future.

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(1a) The potential energy of the body is 980 J

(1b) The kinetic energy of the body halfway down is 490 J and

(1c) The kinetic energy just before impact is 9807 J.

(2) The work done by the trailer on the car is 15,750,000 J.

(3)The initial speed of the vehicle was 10.6 m/s and the work required to stop the car is 269.9 kJ.

Problem 1:

The potential energy of the body is given by the formula:

potential energy = mass x gravity x height

where mass = 50 kg, gravity = 9.8 m/s², and height = 2 m

So, potential energy = 50 x 9.8 x 2 = 980 J

When the body is halfway down, its height above the ground is 1 m. At this point, the potential energy is:

potential energy = mass x gravity x height

potential energy = 50 x 9.8 x 1 = 490 J

The total energy of the body (at any point) is the sum of its potential energy and kinetic energy.

Therefore, the kinetic energy of the body halfway down is:

kinetic energy = total energy - potential energy

kinetic energy = (50 x 9.8 x 2) - (50 x 9.8 x 1) = 490 J

Just before impact with the floor, the height of the body above the ground is zero, so the potential energy is also zero.

At this point, the total energy of the body is equal to its kinetic energy:

kinetic energy = (1/2) x mass x velocity²

where mass = 50 kg, and velocity = ?

To find the velocity, we can use the conservation of energy principle:

total energy at the top = total energy just before impact

potential energy at the top = kinetic energy just before impact

potential energy at the top = 50 x 9.8 x 2 = 980 J

kinetic energy just before impact = 980 J

So, (1/2) x 50 x velocity^2 = 980 J

Solving for velocity, we get:

velocity = √(2 x 980 / 50) = 19.8 m/s

Therefore, the kinetic energy just before impact is:

kinetic energy = (1/2) x 50 x (19.8)^2 = 9,807 J

Problem 2:

The work done by the trailer on the car is given by the formula:

work = force x distance

where force = 900 N, and distance = (70 km/h) x (15/60) h = 17.5 km

Converting km to meters, we get:

distance = 17.5 km x 1000 m/km = 17,500 m

So, work = 900 x 17,500 = 15,750,000 J

Problem 3:

The work done by the brakes is equal to the change in kinetic energy of the vehicle:

work done by brakes = change in kinetic energy

Let the initial speed of the vehicle be v m/s. Then, the initial kinetic energy of the vehicle is:

kinetic energy = (1/2) x 1600 x v²

After the brakes are applied, the final kinetic energy of the vehicle is zero (since the vehicle comes to a stop).

Therefore, the work done by the brakes is equal to the initial kinetic energy:

work done by brakes = (1/2) x 1600 x v²

Given that the work done by the brakes is 90 kJ, we can solve for the initial speed:

90,000 J = (1/2) x 1600 x v²

v² = 112.5

v = √(112.5) = 10.6 m/s

So, the initial speed of the vehicle was 10.6 m/s.

The work required to stop the car:

W = ¹/₂(1600)(15² + 10.6²)

W = 269,888 J = 269.9 kJ

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Answer:

Explanation:

R/^5*r^6 Ok so  then this is simple once u get the answer u need to use the given formula in order to plug in the numbres sorry .

So basically

12 x r^6(u must fill in the number s ) and then u need to do `13x14xr the answer and use the rest of the numbers in order to figure out the quantities of each side for the shape . Then ur answer would be the r^x + x = ???

So yeah hope this helped

I think

Kind of

K Thanks Bye

The positions marked by the straight arrows in the image are the first quarter and third quarter phases of the Moon the tide that occurs is called a "neap tide".

What is neap tide?

During these phases, the Moon and the Sun are at right angles to each other with respect to the Earth, which causes the gravitational forces of the Moon and the Sun to partially cancel out. As a result, the tidal range is at its minimum, and the tide that occurs is called a "neap tide". Therefore, the answer is "neap".

What is gravitational forces?

Gravitational forces refer to the attractive force that exists between any two objects in the universe that have mass. This force is governed by Newton's law of universal gravitation, which states that the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This means that the larger the mass of the objects, the stronger the gravitational force between them, and the farther apart they are, the weaker the gravitational force. Gravitational forces are responsible for keeping celestial bodies, such as planets, moons, and stars, in their orbits, and for the phenomena of tides on Earth caused by the gravitational pull of the Moon and the Sun.

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Complete question is: "neap tide" type of tide occurs when the moon is in the positions marked by the straight arrows in this image.

Answer:

Explanation:

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. We can use this principle to determine the resulting velocity of Kaylyn's puck after the collision.

Before the collision, Sharon's puck has a momentum of:

p1 = m1 * v1 = 0.3 kg * 6 m/s = 1.8 kg m/s

where m1 is the mass of Sharon's puck and v1 is its velocity.

Kaylyn's puck is at rest before the collision, so its momentum is:

p2 = m2 * v2 = 0.3 kg * 0 m/s = 0

where m2 is the mass of Kaylyn's puck and v2 is its velocity.

After the collision, Sharon's puck is at rest, so its momentum is:

p1' = m1 * v1' = 0.3 kg * 0 m/s = 0

where v1' is the velocity of Sharon's puck after the collision.

The total momentum after the collision is the momentum of Kaylyn's puck:

p2' = m2 * v2'

where v2' is the resulting velocity of Kaylyn's puck after the collision.

Using the conservation of momentum principle, we can write:

p1 + p2 = p1' + p2'

Substituting the values we have calculated:

1.8 kg m/s + 0 = 0 + 0.3 kg * v2'

Solving for v2':

v2' = (1.8 kg m/s) / (0.3 kg) = 6 m/s

Therefore, the resulting velocity of Kaylyn's puck after the collision is 6 m/s, which is equal to the velocity of Sharon's puck before they collided. The correct answer is option A.

A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N , against a friction force of 210 N . The acceleration of the box is 0.667 m/s².

The acceleration of the box can be calculated using the formula:

acceleration = (Net force) / (mass)

The given values in the question are:

mass of the box = 30.0 kg

force applied on the box = 230 N

friction force acting on the box = 210 N

Now, let's calculate the net force acting on the box:

Net force = (force applied) - (friction force)= 230 N - 210 N= 20 N

Thus, the net force acting on the box is 20 N.

Using the formula mentioned above, the acceleration of the box can be calculated as:

acceleration = (Net force) / (mass)

                    = 20 N / 30.0 kg

                    = 0.667 m/s²

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At position 2, ion B falls. It is less deflected because it has a lesser mass than ions C, D, and E and the same charge as ion A.

A force perpendicular to the charged particle's velocity and the magnetic field's direction is applied when it reaches the magnetic field. The right-hand rule asserts that the palm will face the direction of the force if the thumb of the right hand points in the direction of the particle's velocity and the fingers point in the direction of the magnetic field. The particle's charge, velocity, and magnetic field intensity all affect how much force is generated.

Since all ions are moving at the same speed in this scenario, the force exerted on each ion is proportional to its charge to mass ratio. Ion B has the smallest mass of all the ions, so the least force and is least deflected of the ions, falling at position 2.

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The initial elongation of the material described by the Maxwell model is given by the formula, initial elongation = [tex]F_0[/tex]/k.

The initial elongation value at t=0 for the material described by the Maxwell model is given by the formula, initial elongation = [tex]F_0[/tex]/k.

Here, k represents the spring constant of the material.

Let's understand this in detail.

The Maxwell model is a type of viscoelastic model that is used to describe the behavior of certain materials. It is made up of a spring and a dashpot in series.

The spring represents the elastic component of the material and the dashpot represents the viscous component of the material.

In this model, the deformation of the material depends on the applied force as well as the time duration for which the force is applied.

The formula to calculate the initial elongation of the material is given by:

initial elongation = [tex]F_0[/tex]/k

where [tex]F_0[/tex] is the force applied to stretch the material and k is the spring constant of the material. The spring constant of a material is defined as the amount of force required to stretch the material by one unit.

The initial elongation of the material is calculated using the spring constant of the material. The spring constant represents the amount of force required to stretch the material by one unit.

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The equivalent capacitance of the combination is 2.2405 μF.

To find the equivalent capacitance of the combination, we can use the formula:

1/C = 1/C1 + 1/C2 + 1/C3

where C1, C2, and C3 are the capacitances of the three capacitors.

Plugging in the values, we get:

1/C = 1/5.2μF + 1/7μF + 1/9μF

1/C = 0.1923077 + 0.1428571 + 0.1111111

1/C = 0.4462759

C = 1/0.4462759

C = 2.2405 μF (rounded to 4 significant figures)

Therefore, the equivalent capacitance of the combination is 2.2405 μF.

A system's capacitance is its capacity to store an electric charge. The proportion of the electric charge held on a conductor to the difference in potential between the conductors is what is meant by this term.

The farad (F), which is equal to one coulomb per volt, is the unit of capacitance.

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Using the triangle of forces to get the system of the forces;

If three forces acting on a body are in equilibrium, then they can be represented in magnitude and direction by the three sides of a triangle taken in order.

In other words, the three forces can be drawn as vectors, and these vectors can be arranged to form a closed triangle.

We know that we have the other end of the triangle to be;

100 Kg * 10 m/s^2 = 1000 N

The missing angle is;

180 - (30 + 60)

= 90 degrees

Thus;

1000/Sin 90 = T1/Sin 60

T1 = 100 Sin 60/Sin 90

T1 = 866/1

T1 = 866 N

1000/Sin 90 = T2/Sin 30

T2 = 1000 Sin 30/Sin 90

T2 = 500 N

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the work done is 24,442 J.

As for the second part of the question, putting on a bigger engine could have other benefits besides increasing the distance traveled. For example, it could increase the speed of the cart or allow it to carry heavier loads. Additionally, the purpose of the cart may have changed, requiring a bigger engine to meet new demands.

The work done is calculated using the formula:

work = force x distance x cos(theta)

where force is the net force acting on the cart, distance is the distance traveled, and theta is the angle between the direction of force and the direction of motion.

Assuming that the cart moves along a horizontal surface, theta is 0 and cos(theta) is 1. Therefore, the work done is:

work = force x distance

To calculate the force, we can use Newton's second law, which states that force is equal to mass times acceleration:

force = mass x acceleration

The acceleration can be calculated using the equation:

acceleration = net force/mass

Since the cart moves forward, the net force must be in the forward direction. Therefore, the force is equal to the maximum force that the engine can provide, which is 1111 N.

The mass of the cart is not given, so we cannot calculate the acceleration and force precisely. However, we can use the distance traveled to estimate the force.

If the cart moves forward 22 m and the engine provides a constant force, then the work done is:

work = force x distance = (1111 N) x (22 m) = 24,442 J

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Answer:

To solve this problem, we can use the equation for rotational motion:

Δθ = (1/2) α t^2 + ω0 t

where Δθ is the change in angle, α is the angular acceleration, t is the time, and ω0 is the initial angular velocity.

In this case, we know that the initial angular velocity is 0 (since the blade is at rest), the final angular velocity is 80.0 rev/s, and the number of revolutions is 240.0 rev. We can use these values to find the angular acceleration:

ωf = ω0 + αt

80.0 rev/s = 0 + α(240.0 rev)

α = 80.0 rev/s / 240.0 rev

α = 1/3 rev/s^2

Now that we know the angular acceleration, we can use the moment of inertia and the torque equation:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

Substituting the given values, we get:

τ = (1.41×10^-3 kg.m^2)(1/3 rev/s^2)

τ = 4.70×10^-4 N.m

Therefore, the net torque the motor must apply to the blade is 4.70×10^-4 N.m.

The angular speed of the Frisbee is 21.33 rad/s.

What is Angular speed ?

Angular speed is a measure of how fast an object is rotating or moving around a central point or axis. It is a scalar quantity, which is defined as the rate of change of the object's angular displacement over time, expressed in units of radians per second (rad/s).

Angular speed is calculated using the formula:

Angular speed (ω) = Δθ / Δt

The linear speed of the outer edge of the Frisbee is given by:

v = 3.2 m/s

The diameter of the Frisbee is given by:

d = 30 cm = 0.3 m

The radius of the Frisbee is half the diameter:

r = d/2 = 0.15 m

The linear speed of a point on the edge of a rotating object is related to the angular speed by the formula:

v = ωr

where ω is the angular speed in radians per second.

Substituting the given values, we can solve for ω:

ω = v/r

ω = 3.2 m/s / 0.15 m

ω = 21.33 rad/s (rounded to two decimal places)

Therefore, the angular speed of the Frisbee is 21.33 rad/s.

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When the snow melts, it will form liquid water, and the volume of the water will be equal to the volume of the original snow sample. Therefore, the volume of liquid water produced by the melting of the 24 ml sample of snow is also 24 ml.

If the snow has a density of 0.5 g/ml, then the mass of the snow is:

mass = density x volume = 0.5 g/ml x 24 ml = 12 g

Therefore, the volume of liquid water produced by the melting of the 24 ml sample of snow is also 24 ml.

What is volume?

Volume of liquid refers to the amount of space that a liquid occupies. It is a measure of the three-dimensional space that the liquid occupies and is usually measured in units such as liters, milliliters, gallons, or fluid ounces. The volume of a liquid is determined by the shape of the container in which it is placed, and it can be measured directly using a graduated cylinder or other volumetric measuring device.

What is density?

Density is a physical property of matter that describes how much mass is present in a given volume of a substance. It is defined as the mass of a substance per unit volume, and is typically measured in units such as grams per milliliter (g/mL) or kilograms per cubic meter (kg/m³).

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Based on what you learned about the roller coaster ride, the following statements about energy transformations that are true are: A. Kinetic energy can be converted into several other types of energyC. A change in an object's speed is evidence that the object's kinetic energy is changing.

The process of energy transformation is the conversion of one form of energy into another. This term describes the scientific process by which energy, in various forms, is transformed to do work. Energy transformation occurs in every physical system in the universe.

Kinetic energy can be converted into several other types of energy.Kinetic energy is the energy of a moving object. The energy is converted into various types of energy, such as electrical and thermal energy, as a result of movement. In a roller coaster, kinetic energy is converted into potential energy as the train goes up the lift hill. The potential energy is converted back into kinetic energy as the train goes down the first drop.

A change in an object's speed is evidence that the object's kinetic energy is changing.Kinetic energy changes when an object's speed changes. If an object slows down, its kinetic energy decreases, while if it speeds up, its kinetic energy increases. On the roller coaster, as the train moves up and down the track, its speed varies, causing changes in its kinetic energy.

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The final velocity of the combined mass after the collision is 15 m/s to the right.

This can be calculated using the equation for Conservation of Momentum.

The momentum of the combined mass before the collision is the sum of the momentums of the truck and car individually:

Momentum of Truck = 2000kg x 10 m/s = 20000 kgm/s

Momentum of Car = 500 kg x 20 m/s = 10000 kgm/s

Total Momentum before Collision = 30000 kgm/s

The total momentum after the collision is the same as before, so the final velocity of the combined mass is:

Final Velocity = Total Momentum/Combined Mass

Final Velocity = 30000 kgm/s / 2500 kg

Final Velocity = 15 m/s

therefore, the final velocity is 15 m/s.

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From the given figure of the quadrupole, it is seen that option A is correct. In an electric circuit, charges move from the negative pole (terminal) to the positive pole (terminal) of a battery or power source.

In physics, a quadrupole is a type of electric or magnetic field with a specific configuration of poles or charges. A quadrupole consists of two sets of charges or poles that are aligned in opposite directions, with each set having two charges or poles of equal magnitude but opposite signs. The charges or poles can be either electric or magnetic, and they are separated by a fixed distance. Quadrupoles can be used to manipulate charged particles, such as ions, in various applications, including mass spectrometry, particle accelerators, and ion traps. In particular, quadrupole mass spectrometry is a widely used technique in analytical chemistry and biochemistry for identifying and quantifying small molecules and biomolecules.

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The number of earths that could fit  inside Jupiter is 6000 where the radius of Jupiter is 71492 km.

Given the volume of a sphere is (V) =[tex](4/3)*\pi*R^3[/tex]

The radius of Jupiter is (RJupiter) = 71492 km

Then the volume of Jupiter is (VJupiter) = [tex](4/3)*\pi*(71492)^3[/tex]

VJupiter = [tex]6.6 * 10^{15} km^3.[/tex]

We know the radius of earth = Re = 6371km

Then the volume of earth (Ve) =[tex]4/3 * \pi * (6371)^3[/tex]

Ve =  [tex]1.08 * 10^{12} km^3.[/tex]

Let the number of earths that could fit inside Jupiter = n

Therefore, n = VJupiter/VEarth

n = [tex]6.6 * 10^{15} km^3/1.08 * 10^{12} km^3 = 6 * 10^3[/tex], = 6,000 Earths.

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Answer:

both are only physical changes

Explanation:

Physical changes are changes that do not alter the identity of a substance.

The liquid soap is still liquid soap when mixed into water.

The dry ice is still dry ice when it changes state from solid to gas.

Answer:1st one 3N to the left to achieve equilibrium

2nd one 5N to the left to achieve equilibrium

3rd one 2N to the top to achieve equilibrium

4th one 2N to the top to achieve equilibrium

5th one 8N to the right to achieve equilibrium

Explanation: