problem 11.143 a race car enters the circular portion of a track that has a radius of 70 m. when the car enters the curve at point p, it is travelling with a speed of 120 km/h that is increasing at 5 m/s2 . three seconds later, determine (a) the total acceleration of the car in xy components, (b) the linear velocity of the car in xy components.

1. As the Tsunami wave approaches the beach, water levels will start to rise, and the ocean may appear to recede away from the shoreline.

2. The ocean may become very calm, and the surface may appear glassy.

3. Strong currents may be felt, and debris such as seaweed, branches, and shells may be seen rushing away from the shoreline.

4. Animals such as birds may be seen fleeing from the shoreline, and a loud roar may be heard as the wave approaches.

5. The wave will eventually reach the beach, and the water levels will quickly rise to a high level. The wave will then crash into the shore, causing destruction and flooding.

A  Tsunami is a powerful series of ocean waves caused by an underwater disturbance, such as an earthquake, volcano, or landslide. These waves travel across the ocean at high speeds and can reach up to hundreds of feet in height when they reach coastlines, causing severe flooding and destruction. Tsunamis are also known as seismic sea waves, and they can occur anywhere in the world.As the wave energy travels, it causes the sea level to rise and creates a “wave” that can travel up to 500 miles per hour. Tsunamis can reach heights of up to 100 feet and can cause extensive damage to coastal areas. The strength of the wave depends on the intensity of the earthquake or eruption that caused it.

Tsunamis usually arrive onshore suddenly and without warning, leaving little time for people to evacuate to safety and are often accompanied by strong currents and large amounts of debris, making them even more destructive.

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Answer:

Fc=mv2/r v=√(Fcr/m) v=√[(3.6 N)(0.38 m)/(0.0012kg)] v=33.76388603 m/s v=38 m/s

Explanation:

The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

Gravity is a fundamental force of nature that exists between all objects that have mass or energy. It is the force that pulls two objects towards each other, and it is what keeps objects like planets, stars, and galaxies in their orbits.

The force of gravity is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This means that the greater the mass of the objects and the closer they are to each other, the greater the force of gravity between them.

Gravity is responsible for many phenomena that we observe in our daily lives, such as keeping us and other objects on the surface of the Earth, causing tides in the ocean, and making objects fall to the ground when we drop them. It is also a key concept in the fields of astronomy and astrophysics, as it is what allows us to understand the motion and behavior of celestial objects in the universe.

Hence, The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

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a. Upthrust on the solid:

[tex]Upthrust = volume of solid * density of fluid * g = 1000 kg/m^3 * volume of solid * 10 m/s^2[/tex]

b. Volume of the solid:

[tex]volume = mass/density = 1.3 kg / (1000 kg/m^3) = 1.3 x 10^-3 m^3[/tex]

c. Density of the solid:

So,[tex]density = mass/volume = 1.3 kg / (1.3 x 10^-3 m^3) = 1000 kg/m^3[/tex]

Upthrust is the upward force exerted on an object immersed in a fluid. It is equal to the weight of the fluid displaced by the object and acts in the opposite direction to gravity. Upthrust helps to counteract the weight of the object and keep it afloat.

a. The upthrust on an object immersed in a fluid is equal to the weight of fluid displaced by the object. The weight of fluid displaced can be calculated using the formula:

Weight of fluid = volume of fluid * density of fluid * g

Since the solid is completely immersed in water, the volume of the fluid displaced is equal to the volume of the solid. The density of water is given as 1000 kg/m^3, and the acceleration due to gravity is given as[tex]10 m/s^2.[/tex]

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The magnitude of the acceleration of each block is given by the absolute value of a

In a system with a massless string and pulley, the forces acting on each block must be taken into account in order to calculate the amount of each block's acceleration.

Assume that the mass of block 1 is m1, the mass of block 2 is m2, and the string's tension is T.

Block 1 is being pulled up and down by the tension in the string (T) and its weight (m1g), respectively.

Block 2 is being pulled up and down by the tension in the string (T) and its weight (m2g), respectively.

The tension in the string remains constant throughout due to the masslessness of the string and the pulley as well as the absence of friction, which causes the blocks to accelerate in opposing directions at the same rate (a).

As a result, we may express the two blocks' motion equations as follows:

m1g - T = m1a for block 1.

T - m2g = m2a for block 2.

These equations for T and a can be resolved:

T = (m1 + m2)g / 2

m1 + m2 / (m2 - m1)g = a

The absolute value of a, which is as follows, determines the extent of each block's acceleration:

A is equal to (m1 + m2)g / (m2 - m1)g.

This formula indicates that the acceleration of each block is a function of both the total and difference of their masses.

A negative acceleration means that block 1 is travelling downhill and block 2 is moving upward if m1 is bigger than m2.

A positive acceleration means that block 1 is going upward and block 2 is falling downward if m2 is larger than m1.

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half I think that's just a guess though

By supplying the distance travelled and the quantity of gasoline spent as inputs, Shubham may write a Python function to get the current mileage of his automobile. The statement is true.

Shubham can create a function in Python to calculate the current mileage of his car by passing the distance traveled and the amount of petrol consumed as parameters. He can define the function to take two arguments: distance and petrol, and then calculate the mileage by dividing the distance by petrol.

If the function is written correctly, it will return the current mileage of his car in km/l. By passing the appropriate values to this function, he can easily calculate the mileage of his car at any time, which can help him keep track of his car's fuel efficiency and plan his journeys accordingly.

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This statement refers to the value of the function f(t) at t = 6, which represents the amount of rainfall that has fallen since midnight up to 6 AM.

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Answer:

The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N

Explanation:

Answer:

Average force of gravitation between Mercury and the Sun is approximately 3.54 x 10^20 N.

Explanation:

The following equation determines the gravitational force between two objects:

F = G * (m1 * m2) / d^2

In this equation, F is the gravitational force, G is the gravitational constant (G = 6.67 x 10-11 Nm2/kg2), m1 and m2 are the objects' masses, and d is the space between their centres.

We need the masses of Mercury and the Sun as well as their typical separation in order to compute the average gravitational force between them.

The Sun's mass is roughly 1.989 x 1030 kg, while Mercury's mass is roughly 3.285 x 1023 kg. Mercury and the Sun are typically separated by around 57.9 million kilometres (0.39 astronomical units).

With these values entered into the formula, we obtain:

F is equal to G * (3.285 x 1023 kg) * (1.989 x 1030 kg) * (57.9 x 106 m) * 2

F is equal to G * (3.285 x 1023 kg) * (1.989 x 1030 kg) * (57.9 x 106 m) * 2

F = 3.54 x 10^20 N

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Answer:

Explanation:

The Root Mean Square (RMS) pressure of a waveform can be defined as the square root of the average of the square of the pressure values over one period of the wave. The RMS pressure provides a measure of the effective pressure of a waveform and is often used to compare the strength of different waveforms.

For a square wave, the RMS pressure can be found as follows

P_RMS = sqrt((1/T) * ∫_0^T (P_square(t))^2 dt)

Where T is the period of the waveform and P_square(t) is the pressure value of the square wave at time t. The integral is taken over one period of the waveform.

For a triangular wave, the RMS pressure can be found as follows:

P_RMS = sqrt((1/T) * ∫_0^T (P_triangular(t))^2 dt)

Where T is the period of the waveform and P_triangular(t) is the pressure value of the triangular wave at time t. The integral is taken over one period of the waveform.

The RMS pressure of a sinusoidal wave is given by the equation:

P_RMS = (A/sqrt(2))

Where A is the amplitude of the waveform.

Comparing the RMS pressures of the three waveforms, it can be seen that the RMS pressure of a sinusoidal wave is (A/sqrt(2)) which is smaller than the RMS pressure of a square wave or a triangular wave. This is because the square wave and triangular wave have sharper transitions from positive to negative values compared to the sinusoidal wave, which results in higher peak pressure values and hence a higher RMS pressure.

It is worth noting that while the RMS pressures of the three waveforms are different, they provide a measure of the effective pressure of the waveforms and can be used to compare their strengths.

Here is a definition of each variable used in the equation:

P_RMS: The Root Mean Square (RMS) pressure of the waveform. It is a measure of the effective pressure of the waveform.

T: The period of the waveform. It is the time it takes for the waveform to repeat itself.

P_square(t): The pressure value of the square wave at time t.

P_triangular(t): The pressure value of the triangular wave at time t.

∫_0^T: The integral symbol. It represents the sum of the pressure values over one period of the waveform, from time t = 0 to time t = T.

A: The amplitude of the waveform. It is the maximum positive or negative deviation from the zero line of the waveform.

sqrt: The square root symbol. It is used to find the square root of a value.

(A/sqrt(2)): The RMS pressure of a sinusoidal wave. It is calculated as the amplitude divided by the square root of 2.

Answer: A bear

Explanation:

I think it is a bear because in the North pole it swims to get food and walks in land to hide.

Answer: Most of them need water to help reproduce & Most of them live in shady, moist, or humid areas.

Explanation:

Bryophytes are non-vascular plants, meaning they do not have specialized tissue for transporting water and nutrients throughout their bodies. Instead, they absorb nutrients and water from the environment. Bryophytes are usually short-lived and don't grow tall, and they prefer to live in shady, moist, or humid areas because they require water to help them reproduce.

It will take the car 3.2 seconds to hit the ground.

Using the kinematic equation,

y = yo + vot + 1/2a*t^2

where y is the displacement (in this case, y = -58 m), yo is the initial displacement (yo = 0), vo is the initial velocity (vo = 0), a is the acceleration due to gravity (a = -9.81 m/s^2), and t is the time we want to find.

We can solve for t by rearranging the equation:

t = sqrt(2*y/a)

t = sqrt(2*(-58)/(-9.81))

t = 3.2 seconds (to two significant figures)

Time taken is 3.2 seconds.

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According to the statement, on the assumption of requesting help from a statistical software consultant, the given case that P(A) + P(B) = 1 is not true, since A and B are not mutually exclusive events.

It is possible for the next request to be related to both SPSS and SAS, in which case it would be included in both A and B.  Therefore, we cannot simply add their probabilities to get the total probability of either event.

B. P(A') represents the probability that the next request is NOT related to the SPSS package. We can find this by subtracting P(A) from 1, since the sum of the probabilities of an event and its complement is always equal to 1:

P(A') = 1 - P(A) = 1 - 0.30 = 0.70

Therefore, the probability that the next request is NOT related to SPSS is 0.70.

C. P(A ∪ B) represents the probability that the next request is related to either SPSS or SAS or both. We can find this by using the formula:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Where P(A ∩ B) represents the probability that the next request is related to both SPSS and SAS. Since we don't have information about the probability of this intersection, we cannot calculate P(A ∪ B) exactly. However, we know that the probability of the intersection must be between 0 and the minimum of P(A) and P(B), which in this case is 0.30. Therefore, we can say:

0 ≤ P(A ∩ B) ≤ 0.30

and use this range to get a lower and upper bound for P(A ∪ B):

P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ≤ 0.30 + 0.50 - 0 = 0.80

P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ≥ 0.30 + 0.50 - 0.30 = 0.50

Therefore, the probability that the next request is related to either SPSS or SAS (or both) is between 0.50 and 0.80.

D. P(A' ∩ B') represents the probability that the next request is NOT related to either SPSS or SAS. We can find this using the formula:

P(A' ∩ B') = P((A ∪ B)')

Where (A ∪ B)' represents the complement of the event that the next request is related to either SPSS or SAS (or both). We can find (A ∪ B)' using the formula:

(A ∪ B)' = A' ∩ B'

Which represents the event that the next request is NOT related to either SPSS or SAS. Therefore:

P(A' ∩ B') = P((A ∪ B)') = 1 - P(A ∪ B)

From part c, we know that 0.50 ≤ P(A ∪ B) ≤ 0.80, so:

P(A' ∩ B') = 1 - P(A ∪ B) ≤ 1 - 0.50 = 0.50

P(A' ∩ B') = 1 - P(A ∪ B) ≥ 1 - 0.80 = 0.20

Therefore, the probability that the next request is NOT related to either SPSS or SAS is between 0.20 and 0.50.

Complete question:

Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A) =. 30 and P(B) = .50.

a. Why is it not the case that P(A) + (B) = 1?

b. Calculate P(A ′).

c. Calculate P(A ∪B).

d. Calculate P(A′ ∩B′).

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Answer:

Potential energy has several advantages and disadvantages, which are as follows:

Advantages:

1. High Energy Density: Potential energy has a high energy density, meaning that a small amount of mass can store a large amount of energy. This makes it ideal for applications where energy needs to be stored in a compact space, such as batteries or hydroelectric dams.

2. Clean Energy: Potential energy sources, such as hydro, wind, and solar power, are clean and renewable sources of energy. They do not produce harmful pollutants or contribute to climate change like fossil fuels do.

3. Stable and Predictable: Unlike some other forms of energy, such as wind and solar, potential energy sources are generally stable and predictable. For example, hydroelectric dams produce a steady and consistent supply of energy.

4. Cost Effective: Once built, potential energy sources are often low-cost sources of energy. For example, the cost of producing electricity from hydroelectric dams is typically lower than from fossil fuels.

Disadvantages:

1. Initial Investment Costs: The main disadvantage of potential energy is the high initial investment required to build the infrastructure needed to harness it. For example, building a hydroelectric dam or a wind farm is expensive and takes time.

2. Limited Availability: Potential energy sources are limited by the availability of resources. For example, hydroelectric power can only be generated where there is a suitable source of running water, such as a river or stream.

3. Environmental Impacts: Although they are clean sources of energy, potential energy sources can have negative environmental impacts. For example, the construction of large hydroelectric dams can displace communities and disrupt ecosystems, while wind turbines can be a source of noise pollution and pose a risk to bird and bat populations.

4. Technical Challenges: Harnessing potential energy can also be technically challenging. For example, the efficient and effective storage of energy from wind and solar sources is still a challenge that engineers and scientists are working to overcome.

The east would be the location of the Sun's rising and setting are the changes would you anticipate seeing.

Annual motion, which is a direct result of the Earth's rotation around the sun, is the visible yearly move of the stars as seen from Earth. The ecliptic is a line on the surface of a sphere around which the revolves around the sun 360 degrees each year.

We, the watchers on Earth, whirl past this foreground of far-off stars as the planet rotates on its axis. The stars seem to travel throughout our darkness of space from east to west as Earth spins for the same reason.

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Let's call the speed of the current "c". Then, the speed of the boat relative to the water when it is going upstream is 24 - c mph, and the speed of the boat relative to the water when it is going downstream is 24 + c mph.

Using the time it takes to travel the given distances, we can set up the following equation:

(54) / (24 - c) = (90) / (24 + c)

Expanding and solving for c, we find that:

c = 4 mph

So the speed of the current is 4 mph.

Answer: Upstream: 24 - 6 = 18  --->   54 = 18 x?  --->  ? = 54/18 = 3 hours

   (24 - 6)x 3 = 18 x 3 = 54 miles

   (24 + 6) x 3 = 30 x 3 = 90 miles

The speed of the current is 6 mph.

Time is 3 hours

 (c) n=3,1=2,m=1,s=+1/2 this set of quantum number represents the highest energy of atom

Correct option is C)

The sets of the quantum numbers and the corresponding orbitals are as shown below.

a)n=3,l=0 means 3s− orbital

b)n=3,l=1 means 3p− orbital

c)n=4,l=2 means 4d− orbital

d)n=4,l=0 means 4s− orbital

Increasing order of energy among three orbitals is 3s<3p<4s<4d

∴4d has highest energy.

Hence, the set c of quantum numbers (n=4,l=2,m=1,s=+1/2)  represents the highest energy of an atom.

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The distance from the point charge is 0.425 m using relationship of electric potential and field.

Using relationship between electric field and electric potential, electric field magnitude becomes negative gradient of the electric potential.

[tex]|E| = -dV/dr[/tex]

where |E| : electric field magnitude, V: electric potential, and r: point charge distance

We are given that[tex]|E| = 17.9 V/m[/tex]and V = 7.6 V. Put values:

[tex]17.9 V/m = -dV/dr = -d(7.6 V)/dr[/tex]

Solving for d, we get:

[tex]d = -7.6 V / (17.9 V/m) = -0.425 m[/tex]

Since distance cannot be negative, we take the absolute value to get:

d = 0.425 m

Therefore, the distance from the point charge is 0.425 m.

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If the half-life of an isotope is found to be 6 days, then the isotope whose initial weight is 95 and the final weight is 5.9. It would take approximately 24 days.

Isotope may be defined as the type of atom in which the number of neutrons differs and the number of protons is the same. They are atoms of the same element, having the same atomic number but different mass numbers.

According to the context of this question,

The initial weight of an isotope = 95

The final weight of an isotope = 5.9

The half-life = 6 days

After 6 days, the weight of 95 reduced to 47.5.

After 6 days, the weight of 47.5 was reduced to 23.75.

After 6 days, the weight of 23.75 reduced to 11.87

After 6 days, the weight of 11.87 was reduced to 5.93.

Therefore, if the half-life of an isotope is found to be 6 days, then the isotope whose initial weight is 95 and the final weight is 5.9. It would take approximately 24 days.

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Your question is incomplete, but most probably your full question is as follows:

An isotope A has an initial weight of 95g, but after some time its weight was reduced to 5.9g being a half-life of 6 days. On what day it was measured?

The angular momentum of the system is  225,540 kg [tex]m^{2} /s[/tex] and the distance between the modules that would give an effective acceleration of gravity equal to g is 24.8 m.

(a) The angular momentum of the system is given by L = Iω.

The moment of inertia of an equilateral triangle of mass M and side length a is I = (1/6)M[tex]a^{2}[/tex]

The mass of each capsule is 100 people × 75.0 kg/person = 7,500 kg.

Therefore, the total mass of the system is M = 3 × 7,500 kg = 22,500 kg.

The radius of the circle is half the side length of the equilateral triangle, so r = 41.0 m.

Therefore, the angular velocity of rotation is given by ω = (g/2)/r = 0.120 rad/s.

Using these values, the angular momentum of the system is L = (1/6)M[tex]a^{2}[/tex]ω = (1/6) × 22,500 kg × (82.0 [tex]m^{2}[/tex]) × 0.120 rad/s = 225,540 kg[tex]m^{2} /s[/tex]

(b) If the modules are pulled closer together, the moment of inertia of the system will decrease, because the mass of the system will be closer to the axis of rotation. According to the conservation of angular momentum, if the moment of inertia decreases, the angular velocity of rotation must increase in order to keep the angular momentum constant. Therefore, pulling the modules closer together would increase the rotational rate of the space station.

(c) The effective acceleration of gravity is given by g_eff = (g/2) + ([tex]v^{2}[/tex]/r), where v is the linear velocity of the space station. At the current rotational rate, the linear velocity of the space station is v = rω = 41.0 m × 0.120 rad/s = 4.92 m/s.

g.eff = (g/2) + ([tex]v^{2}[/tex]/r) = g

([tex]v^{2}[/tex]/r) = (g/2)

r = (2[tex]v^{2}[/tex])/g

Substituting the values for v and g, we get:

r = (2 × [tex]4.92m/s ^{2}[/tex])/9.81 [tex]m/s^{2}[/tex] = 24.8 m

Therefore, the distance between the modules that would give an effective acceleration of gravity equal to g is 24.8 m.

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The maximum length of runway needed and tension in the towrope will be 175.05 m and 5999N.

For solving this question we will use the laws of Kinematics as well as the Newton's Laws of Motion. According to the third law of Kinematics

v² = u² + 2aS ; where v is the final velocity, u is the initial velocity, a is the acceleration and S is the displacement.

According to Newton's Laws of Motion we know that the net force is equal to product of mass and acceleration that is

F = ma ; where F is net force, m is mass of the body and a is the acceleration.

Now, form the free body diagram of the gliders, we balance the forces by Newton's law of motion as:

For glider 1 the forces in x axis will be:

T₁ - T₂ - f = ma                                                    ......(1)

where T₁ and T₂ are tensions on glider 1 and 2 respectively and f is the frictional force.

In y axis the forces will be:

N₁ - W = 0 ; where N₁ is the normal on first glider and W is the weight due to gravity.

For glider 2 the forces in x axis will be:

T₂ - f = ma                                                           ......(2)

where T₂ is tensions on glider 2 and f is the frictional force.

In y axis the forces will be:

N₂ - W = 0 ; where N₂ is the normal on second glider and W is the weight due to gravity.

From equation (1) and (2) we get

T₁ - 2f = 2ma

a = T₁ - 2f/2m

a = 12000 - 2(2800)/2(700)

a = 6400/1400

a = 4.57 m/s²

Now from laws of Kinematics we have

v² = u² + 2aS; here the initial velocity is zero so u = 0 and v = 40 m/s

(40)² = 0 + 2 × 4.57 × S

S = 1600/9.14

S = 175.05 m

Now for the tension in the second rope of glider we use equation (2) that is

T₂ - f = ma

T₂ = ma + f

T₂ = 700 × 4.57 + 2800

T₂ = 3199 + 2800

T₂ = 5999 N

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The charge on each identical bead is calculated to be q = √[4πε/√3× (R² m g)].

The mass of the two identical beads is given as m.

The charge on each bead is q.

The radius of the hemispherical bowl is R.

The beads are said to be in equilibrium.

For the charges to balance at a point, the force of electric repulsion along the tangent should balance the force of gravitation along the tangent.

1/4πε q²/R² cos 30° = m g cos 60°

1/4πε q²/R² (√3/2) = m g (1/2)

√3/4πε q²/R² = m g

q² = (4πε)/√3 × (R² m g)

q = √[4πε/√3× (R² m g)]

Thus, the charge on each bead is calculated to be √[4πε/√3× (R² m g)].

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The estimated total amount of positive charge in a 70 kg person is 5.88 Coulombs (C).

Since the human body is mostly made of water, we can assume that the total amount of positive charge is equal to the total amount of sodium ions (Na+) and other positively charged ions in the body.

The concentration of sodium ions in the human body is approximately 140 milliequivalents per liter (mEq/L), which is equivalent to 0.140 moles per liter (mol/L).

Assuming that the total volume of water in a 70 kg person is approximately 42 liters, we can estimate the total amount of sodium ions in the body as follows:

Total amount of sodium ions = concentration x volume of water
Total amount of sodium ions = 0.140 mol/L x 42 L
Total amount of sodium ions = 5.88 mol

Since each sodium ion has a charge of +1, the total amount of positive charge in a 70 kg person is also 5.88 C.

Therefore, the estimated total amount of positive charge in a 70 kg person is 5.88 Coulombs (C).

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The resulting amplitude of the two waves is 1.25 m

When two waves of different amplitudes interfere, the resulting wave pattern is determined by the relative phase and amplitude of the two waves. If the two waves are in phase, meaning that their peaks and troughs line up, they will reinforce each other and produce a wave with a larger amplitude. This is known as constructive interference.

In this case the amplitude of the resulting wave would be a combination of two amplitudes of the waves and that would be 1.25 m

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Answer:

sorry I'm not smart

Explanation:

(1) The potential difference between the two spheres will cause charges to flow from Sphere 1 to Sphere 2 until their potentials are equal.(2)  Since the total charge is conserved, the total charge on both spheres after the switch is closed will be equal to the charge on Sphere 1 before the switch is closed.

a) The potential difference between the two spheres will cause charges to flow from Sphere 1 to Sphere 2 until their potentials are equal. Since Sphere 1 has a positive charge, electrons will flow from Sphere 2 to Sphere 1 until their potentials are equal. This means that Sphere 1 will end up with a lower potential than its initial potential and Sphere 2 will end up with a higher potential than its initial potential. Therefore, Vi is smaller than V2.

b) Since the total charge is conserved, the total charge on both spheres after the switch is closed will be equal to the charge on Sphere 1 before the switch is closed. Therefore, the final charge on Sphere 2, Q2, will be equal to the initial charge on Sphere 1. Hence, Qi is equal to Q2.

c) The electric field strength at the surface of a charged conductor is proportional to the surface charge density. Since Sphere 1 has a larger radius than Sphere 2, it has a larger surface area and therefore a lower surface charge density. This means that E1 will be smaller than E2. Additionally, as charges move from Sphere 1 to Sphere 2, the surface charge density on Sphere 1 decreases, leading to a decrease in E1. Therefore, E1 will be smaller than E2 after the switch is closed.

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part a.

the work done by gravity is approximately 1690 J.

part b.

the work done by the normal force is 0.

part c.

the work done by friction is approximately -671 J

part d.

the total work done is approximately 1019 J

work done is described  as the multiplication of magnitude of displacement d and the component of the force that is in the direction of displacement.

For part a, the work done by gravity can be found using the formula:

W_gravity = mgh

h = dsin(37°) = 8sin(37°) = 4.83 m

W_gravity = (35 kg) * (9.81 m/s^2) * (4.83 m) ≈= 1690 J

In conclusion, the same pattern can be followed to calculate for b, c and d.

Learn more about work done at: https://brainly.com/question/8119756

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