Question 3 of 5
The gravitational pull of the Moon is much less than the
gravitational pull of Earth.
Which two statements are true for an object with a mass of 20 kilograms that
weighs 44 pounds on Earth?
A. The object's mass would be less on the Moon.
B. The object's mass would be the same on the Moon.
C. The object's weight would be the same on the Moon.
D. The object's weight would be less on the Moon.

Answer: The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2.00 103 N with an effective perpendicular lever arm of 3.40 cm, producing an angular acceleration of the forearm of 165 rad/s2. Then, the moment of inertia of the boxer's forearm will be 0.412Nm/rad/sec2.

Explanation: To find the correct answer, we have to know more about the moment of force or torque.

                        [tex]T=rFsin\alpha[/tex], where, [tex]\alpha[/tex] will be the angle between r and F.

                                   [tex]T=I\beta[/tex]

                     Where,  [tex]I=r[/tex]×m

                  [tex]F=2*10^3N\\r=3.40*10^-2m\\\beta =165 rad/sec^2[/tex]

                          [tex]I=\frac{T}{\beta } =\frac{rFsin\alpha }{\beta } \\where, sin\alpha =1.\\Thus,\\T=\frac{rF}{\beta } =\frac{68}{165} =0.412Nm/rad/s^2.[/tex]

Thus, we can conclude that, moment of inertia of the boxer's forearm will be, 0.412Nm/rad/sec².

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Nuclear decay results in the change in the mass number of a nucleus. In precise it is alpha decay.

The process through which an unstable atomic nucleus loses energy through radiation is known as radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration.

How is mass number of nucleus is changed by alpha decay?

When a nucleus emits an alpha particle, these changes happen:

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Answer:

A speed is a scalar quantity because it only has magnitude.

Answer:

what is electronic configuration

The work done in moving the chair from x = 2.4 to x = 4.1 ft using a force of F = 13 lbs is 29.98 J

This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as

Workdone (Wd) = force (F) × distance (d)

Wd = Fd

1 lb = 4.45 N

Therefore,

13 lbs = 13 × 4.45

13 lbs = 57.85 N

1 ft = 0.3048 m

Therefore,

1.7 ft = 1.7 × 0.3048

1.7 ft = 0.51816 m

Wd = Fd

Wd = 57.85 × 0.51816

Workdone = 29.98 J

Thus, the workdone in moving the chair is 29.98 J

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The X and Y components are as follows;

1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s

2. X = 12 * -cos 34  = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s

3. X = 8 * -cos 90  = 0 m/s; Y = 12 -sin 90 = -8 m/s

4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) =  -19.3 m/s

The horizontal and vertical components of the velocities are given as follows:

1. 35 m/s at  57° from x-axis

X = 35 * cos 57 = 19. 1m/s

Y = 35 * sin 57 = 29.4 m/s

2. 12m/s at 34° S of W

X = 12 * -cos 34  = -10 m/s

Y = 12 * -sin 34 = -6.7 m/s

3. 8 m/s at South

X = 8 * -cos 90  = 0 m/s

Y = 12 -sin 90 = -8 m/s

4. 20 m/s at  275° from x-axis

X = 20 * cos 75 = 5. 2m/s

Y = 20 * (-sin 75) =  -19.3 m/s

In conclusion, the X and Y components are found by taking cosines and sine of the angles.

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you can use the graph to estimate the value of x when y is required to start a doubles match with the sun and the sky very well from her childhood and a kind young women who lives with her wearing a black and a veil and shows to be in that position or they have a bad past or bad life that they want to take revenge on every one by murder goes on by them in the streets of St and St Mary's Church and its followers are known as Sikhs and the other children claim she

The work done by the force is 140 J.

Calculation:

It is given that, an 80-N crate is pushed a distance of 5.0 m upward along a smooth incline that makes an angle of [tex]30^\circ[/tex] with the horizontal. The force pushing the crate is parallel to the slope and the acceleration is 1.5 [tex]\text{ m/s}^2[/tex].

It is required to find the work done by the force.

The free-body diagram is shown below,

Here, W=80 N, a=-1.5 [tex]\text{ m/s}^2[/tex]

We can write the net force equation as,

[tex]\begin{gathered}F-W \sin 30^{\circ}=m a \\F-m g \sin 30^{\circ}=\left(\frac{W}{g}\right) a\end{gathered}[/tex]

Here W is the weight of the object, m is the mass of the body, and F is the applied force.

Thus,

[tex]\begin{aligned}F-(80 \mathrm{~N}) \sin 30^{\circ} &=\left(\frac{80 \mathrm{~N}}{9.8 \mathrm{~m} / \mathrm{s}^{2}}\right)\left(-1.5 \mathrm{~m} / \mathrm{s}^{2}\right) \\F &=27.755 \mathrm{~N}\end{aligned}[/tex]

It is known that the work done by the force is calculated as the multiplication of the applied force and the displacement.

Thus the work one is,

[tex]\begin{aligned}W &=(27.755 \mathrm{~N})(5 \mathrm{~m}) \\& \approx 140 \mathrm{~J}\end{aligned}[/tex]

Thus the last option is the correct one.

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OPTION (C) IS CORRECT

ANSWER - UNIFORM MOTION

If there is no change in the velocity of the object then it is known to be in UNIFORM MOTION.

EXPLORE MORE:-

EXAMPLE - A CAR COVERS A DISTANCE OF 15 KM WE'D EVERY 2 HOURS

FOR AN UNIFORM MOTION, ACCELERATION IS ZERO , AS THERE IS NO CHANGE IN VELOCITY....

-THANKS.!!

When the absolute value of the price elasticity of demand falls in the range 0 to 1, demand is said to be inelastic.

A good or service that has an income elasticity of demand between zero and 1 is considered a normal good and income inelastic. If a good or service has an income elasticity of demand below zero, it is considered an inferior good and has negative income elasticity.

Inelastic is an economic term referring to the static quantity of a good or service when its price changes. Inelastic means that when the price goes up, consumers' buying habits stay about the same, and when the price goes down, consumers' buying habits also remain unchanged.

Price elasticity of demand is a measurement of the change in consumption of a product in relation to a change in its price. A good is elastic if a price change causes a substantial change in demand or supply.

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The speed of the airplane, v is 144.2 m/s

The height, H of the roof above the head of the man is 66.4 m.

The speed of the airplane is determined using the Pythagoras theorem.

The speed of the airplane, v is calculated as follows:

v = √(80² + 120²0

v = 144.2 m/s

The height, H of the roof above the head of the man is calculated as follows:

tan 38° = H/85

H = tan 38° * 85 m

H = 66.4 m

In conclusion, the tangent ratio is used to find the height of the roof above the head of the man.

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The velocity of the object s calculated as 22.1 m/s.

Given that we can write that;

v^2 = u^2 + 2gh

Now u = 0 m/s because the object was dropped from a height

v^2 = 2gh

v = √2 * 9.8 * 25

v = 22.1 m/s

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Answer:

a whole new glacier will start because the other one is melting

When they meet the 40-kg boy would have moved a distance of 6 m.

Apply the principle of center mass;

Take the 40 kg mass as the reference point;

X(40 kg) = (40kg x 0  + 60kg x 10 m)/(40 kg + 60 kg)

X(40 kg) = (600)/(100)

X(40 kg) = 6 m

Thus, when they meet the 40-kg boy would have moved a distance of 6 m.

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Status refers to a person's prestige, social honor, or reputation in society. Weber stated that political strength become now not rooted entirely in capital fees, but additionally in a single's individual popularity. Poets or saints, for example, can own a massive impact on society, often with little monetary worth.

The German sociologist Max Weber formulated a three-component theory of stratification that defines a status group (additionally status class and status estate) as a group of humans within a society who can be differentiated by means of non-financial characteristics along with honor, prestige, ethnicity, race, and religion.

Social stratification entails society as a system of hierarchical categories. Max Weber defined stratification because the division of a society into distinct communities, that have varying assignments of “status honor” or status.

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In the NEC Code, 210.8 indicates article 210, section 8 and is denoted as option A.

This is referred to the standards which are required for the safe installation of electric wires and equipment in USA.

This comprises of several articles covering different topics and sections which gives it a more elaborate meaning and understanding.

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Highest to lowest number:

-less than 1 solar mass

-between 1 and 10 solar masses

-between 10 and 30 solar masses

-between 30 and 60 solar masses

Stellar mass is a phrase that is used by astronomers to describe the mass of a star. It is usually enumerated in terms of the Sun's mass as a proportion of a solar mass (M☉).

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It takes four times the work and four times the stopping distance.

Given:

original speed of car = x

brakes applied so final speed = 0

moving speed of another car = 2x

To Find:

work done to stop the car

Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

Work done is given by

W = KE(final) - KE(initial)

W = 1/2m(v)^2 - 1/2m(u)^2

W = 1/2m(0 - (x)^2)

W = 1/2m(4x^2)

W = 4(1/2mx^2)

W = 4W

So, work done will be 4 times initial work

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Answer: Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through angle [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of n .

Explanation: To find the correct answer, we need more clarifications about the Malu's law.

                                 [tex]I=I_0cos^2\alpha[/tex]

where, [tex]I_0[/tex] is the maximum intensity of transmitted light.

                                            [tex]I=I_0cos^2\alpha[/tex]

                                 [tex]\alpha =cos^-1\sqrt{(\frac{I}{I_0}} )=cos^-1\sqrt{\frac{I}{nI} } \\\alpha =cos^-1\sqrt{\frac{1}{n} }[/tex]

Thus, we can conclude that, the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n will be,

                                 [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] .

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Answer:

KE = 1/2 M v^2

KE = 60/2 * 25^2 = 18750 Joules         initial Kinetic Energy

W = Fs * d        distance thru which friction acts

d = W / Fs = 18750 J / 50 N = 375 m

Answer:

[tex]\huge\boxed{\sf v = 448\ m/s}[/tex]

Explanation:

Frequency = f = 16 Hz

Wavelength = λ = 28 m

Speed = v = ?

v = fλ

Put the givens.

v = (16)(28)

v = 448 m/s

[tex]\rule[225]{225}{2}[/tex]

Astronomers explain the energetic jets that come out of quasars and active galactic nuclei(AGN) in opposite directions in a way that the supermassive black holes' chaotic accretion discs "spit out" jets in directions perpendicular to the disc.

Quasar : A supermassive black hole with a mass between millions and tens of billions of solar masses that is fueled by an extraordinarily bright active galactic nucleus (AGN) and encircled by a gaseous accretion disc is known as a quasar.

An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum.

Hence, astronomers propose that the chaotic accretion discs of supermassive black holes "spit out" jets in directions perpendicular to the disc, explaining the intense jets that emerge from quasars and active galactic nuclei in different directions.

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It starts fusing hydrogen in a shell around a helium core

Eventually, a star will run out of hydrogen fuel in its core, nuclear fusion will stop, and the star will enter a new stage of its lifetime.

Faster hydrogen burning means the star will grow larger and more luminous to allow the extra energy created to escape but since the temperature of the core remains constant the star's surface temperature will drop.

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The object will drop 5 cm if released  before coming to rest.

We know from Hooke's law that the work that is done when the spring is stretched is given by the formula;

W = 1/2 kx^2

k= 100 N/m

x =  1.00 cm or 0.01 m

W = 0.5 * 100 * 0.01

W = 0.5 J

Now;

W = mgh

h = W/mg

m =  1.00 kg

g = 9.8 m/s^2

h =  0.5 J/1.00 kg  * 9.8 m/s^2

h = 0.05 m or 5 cm

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Water flows through a pipe with a cross-sectional area of 0.002 m^2 at a mass flow rate of 4 kg/s. The density of water is 1 000 kg/m^3 . The average velocity will be 2m/s

The flow rate of a liquid is how much fluid passes through an area in a particular time. Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume.

Flow rate = Volume of fluid / time

               = (Area * distance) / time

               =  Area * average velocity      (distance / time = average velocity)

Given

Cross-sectional area  = 0.002 [tex]m^{2}[/tex]

Flow rate =  4 kg/s

Average velocity = Flow rate / (Area * density)

                            = 4 / (0.002 * 1000)

                           = 2m/s

hence , the  average velocity will be 2 m/s

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The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

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Answer:

The final temperature is [tex]29.6^oC[/tex].

Explanation:

When the two masses come in contact, one releases heat and the other absorbs it. The former can be modelled with the equation [tex]HeatLost = (Mass1 (kg))(c1)(T1-T)[/tex], and the latter by [tex]HeatGained=(Mass2(kg))(c2)(T-T2)[/tex]

m1=0.15 kg

m2=0.06 kg

T1 = 70 degrees Celsius = 343 K

T2 =  20 degrees Celsius = 293 K

T= Final temperature

c1 = Specific heat capacity of copper

c2 = Specific heat capacity of water

Because there is no heat lost into the surroundings, the heat removed from one substance is the same as the heat gained in the other. Therefore:

[tex](Mass1)(c1)(T1-T)=(Mass2)(c2)(T-T2)[/tex]

[tex](0.150)(400)(343-T)=(0.06)(4184)(T-293)[/tex]

[tex](60)(343-T)=(251.04)(T-293)[/tex]

[tex]20580-60T=251.04T-73554.72[/tex]

[tex]-311.04T=-94134.72[/tex]

[tex]T=302.6 K[/tex]

[tex]T=29.6^oC[/tex]

Hope this helps! (My apologies if the answer is wrong, it has been a while since I've done this)

The charge on the particle is 5.6 × 10⁻¹¹ C.

The magnitude of an electric field produced by a charge is given by:

                                                 E = q/ 4πε₀r²

where,

E = electric field

q = charge

r = distance

1/4πε₀ = 8.99 × 10⁹ Nm²/C²

Given,

E = 2.0 N/C

r = 50 cm = 0.5 m

To find,

q =?

Put the values in the above equation:

E = q/ 4πε₀r²

q = E (4πε₀r²)

q = 2.0 × (0.50²)/ 8.99 × 10⁹

q = 5.6 × 10⁻¹¹ C

Therefore, the particle has a charge of 5.6 × 10⁻¹¹ C.

The physical field that surrounds each electric charge and acts to either attract or repel all other charges in the field is known as an electric field. Electric charges or magnetic fields with different amplitudes are the sources of electric fields.

I understand the question you are looking for is this:

A charged particle produces an electric field with a magnitude of 2.0 N/C at a point that is 50 cm away from the particle. What is the magnitude of the particle's charge?

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Answer:

the rock will probably sink in water because density of rock heavier than the density of water.

Density of water=1g/cm

density of rock=1.73g/cm

1g/cm< 1.73g/cm