Sanborn Inc. is a new manufacturing company founded on February 2, 2012. The company had to choose between the LIFO and FIFO methods for its inventory. Inventory costs were rising during 2012, so the company decided to use the LIFO method. Which of the following items would be decreased by the choice of LIFO (compared to what would have happened if they chose to use FIFO)? (check all that apply)

The best description of that term 29.4 in the expression is the initial velocity of the test shell. That is option B.

A pyrotechnician is defined as the individual that has been trained for safe storage, handling, and functioning of pyrotechnics such as fireworks.

While testing the display of the fireworks, he took note of the following:

The elevation in meters

The time in seconds

The change in velocity should be noted as the velocity of distance covered by a moving object with time.

Therefore, the term 29.4 is the initial velocity of the fireworks he projected.

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f(x) = -4(x + 7) is the equation for a parabola with x-intercepts at (1/4,0) and (-7,0) and a point of intersection of (0,7). (x - 0.25).

An equation is a mathematical statement containing two algebraic expressions flanked by equal signs (=) on either side.

It shows that the relationship between the left and right printed expressions is equal.

All formulas hav LHS = RHS (left side = right side).

You can solve equations to determine the values ​​of unknown variables that represent unknown quantities.

If a statement does not have an equals sign, it is not an equation. A mathematical statement called an equation contains the symbol "equal to" between two expressions of equal value.

y = f(x) = A(x - a)(x - b)

We have -

a = 1/4

b = -7

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Answer:

4/3 or d

Step-by-step explanation:

The nearest whole number, which is 9. So the middle apartment number for house 17 is 9.

An apartment is a self-contained housing unit that occupies only part of a building. Apartments typically consist of one or more bedrooms, a kitchen, a living room, and a bathroom, and usually include amenities such as heating, air conditioning, and appliances. Apartments are usually rented, though some are owned. Living in an apartment can be a great way to save money, as apartments are often more affordable than larger homes.

The rule is to take the house number and divide it by two and round up to the nearest whole number. This will give the middle apartment number. For example, if the house number is 17, divide it by two which equals 8.5, and then round up to the nearest whole number, which is 9. So the middle apartment number for house 17 is 9.

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Answer:

[tex] 9^{\frac{7}{8}} [/tex]

Step-by-step explanation:

[tex] (9^{\frac{1}{4}})^{\frac{7}{2}} = [/tex]

[tex] = 9^{\frac{1}{4} \times \frac{7}{2}} [/tex]

[tex] = 9^{\frac{7}{8}} [/tex]

Answer:

A. For g(x) to be differentiable, the derivative of g(x) must exist at every point in its domain. The derivative of a sin x + b is a cos x, which exists for all values of x. Therefore, any values of a and b will make g(x) a differentiable function.

B. To find the equation of the tangent line to g(x) at x = 2π, we need to find the slope of the tangent line, which is the derivative of g(x) evaluated at x = 2π.

g'(x) = a cos x, so g'(2π) = a cos(2π) = a

Therefore, the slope of the tangent line at x = 2π is a. To find the y-intercept of the tangent line, we can plug in x = 2π into g(x) and subtract a times 2π:

y = g(2π) - a(2π)

= (a sin 2π + b) - a(2π)

= b - 2aπ

So the equation of the tangent line is:

y = ax + (b - 2aπ)

C. We can use the tangent line equation to approximate g(6) by plugging in x = 6 and using the equation of the tangent line at x = 2π.

First, we need to find the value of a. Since g'(2π) = a, we can use the derivative of g(x) to find a:

g'(x) = a cos x

g'(2π) = a cos (2π) = a

g'(x) = a = 2

Now, we can plug in a = 2, b = any value, and x = 2π into the tangent line equation:

y = ax + (b - 2aπ)

g(2π) = 2πa + (b - 2aπ)

a sin 6 + b ≈ 12π + (b - 4π)

Since we don't know the value of b, we can't find the exact value of g(6), but we can use the approximation:

g(6) ≈ 12π + (b - 4π)

Answer:

We can use similar triangles to solve this problem. Let's denote the height of the tree as h. Then, we can set up the following proportion:

h / 120 = 6 / 10

Cross-multiplying and simplifying, we get:

10h = 720

h = 72

Therefore, the height of the tree is 72 feet

The Venn diagram here shows the cardinality of each set. The cardinality of the  n(A∩B∩C) is 6.

Venn diagrams can be used to visually represent many different types of information, such as mathematical relationships, logical relationships, and sets of data. They are a useful tool for organizing and visualizing complex information.

A Venn diagram is a graphical representation of the relationships between different sets of objects. It consists of overlapping circles or other shapes that represent each set. The portions of the circles that overlap represent the objects that are in common to the corresponding sets.

Using the principle of inclusion-exclusion, we have:

n(A∩B∩C) = n(An) + n(B∩C) + n(C∩A) - 2n(A∩B) - 2n(B∩C) - 2n(C∩A) + 3n(A∩B∩C)

Substituting the given values, we get:

n(A∩B∩C) = 10 + 9 + 7 - 2(4) - 2(9) - 2(7) + 3(3) = 6

Therefore, n(A∩B∩C) = 6.

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The estimated volume of the coffee cup is approximately 152.8 cubic centimeters.

It is the perimeter of the circle, which can be found by multiplying the diameter of the circle by pi (π), a mathematical constant that is approximately equal to 3.14.

The volume of a right cylinder is:

V = πr²h

We are given the height of the coffee cup as h = 8.3 cm. To find the radius,

C = 2πr

We are given the circumference of the coffee cup as C = 14.9 cm. Solving for r, we have:

14.9 = 2πr

r = 14.9 / (2π) ≈ 2.372 cm

Now we can substitute these values into the formula for the volume of a cylinder:

V = πr²h

V = π(2.372)²(8.3)

V ≈ 152.8 cubic centimeters

Therefore, the estimated volume of the coffee cup is approximately 152.8 cubic centimeters.

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Answer:

Step-by-step explanation:

t+t+t= 3t

3t = 12

12/3=t

4=t

A. The capacity of most of the trimmer Sara sells is [tex]1\tfrac{1}{5}[/tex]

B. The total gas she needs to fill all trimmers is  [tex]$22 \frac{7}{8}[/tex]

Expressiοns are used extensively in mathematics, including arithmetic, calculus, and geοmetry. They are used in mathematical fοrmula representatiοn, equatiοn sοlutiοn, and mathematical relatiοnship simplificatiοn.

Part A

The capacity of most of the trimmer Sara sells is [tex]1\tfrac{1}{5}[/tex]

Part B

The total gas she needs to fill all trimmers is:

[tex]$\Rightarrow (1 \times 1\frac{1}{2}) + (5 \times 1\frac{5}{8}) + (1 \times 1\frac{7}{8} )+ (3 \times 2\frac{1}{8} ) + (2 \times 2\frac{1}{2} )[/tex]

⇒ [tex]$22 \frac{7}{8}[/tex]

Thus, The total gas she needs to fill all trimmers is  [tex]$22 \frac{7}{8}[/tex]

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The poles of the function F(s) are -2 and 0, both of which are real and negative. Therefore, the poles can be expressed in radians per second as -2.000 and 0.000.

To find the poles of the function F(s), we need to find the values of s that make the denominator equal to zero. So we need to solve the equation:

s(s+2)² = 0

The solutions to this equation are:

s = 0 (double pole)

s = -2 (double pole)

Therefore, the poles of the function F(s) are -2 and 0, both of which are real and negative. So the poles can be expressed in radians per second as:

-2.000

0.000

(Note that the poles are not specified in units of radians per second, but the values are the same whether or not we include the units.)

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No, the relation is not a function, because for each input there is not exactly one output.

A graph is a visual representation of data that shows the relationship between variables or sets of data. It consists of a set of points, called vertices or nodes, which are connected by lines or curves, called edges or arcs. Graphs are commonly used to display numerical information, such as trends, patterns, or relationships, and can be used to analyze and interpret data.

The relation is not a function because for the input x = -1, there are two different output values, y = 3 and y = -2. A function is a relation where each input has exactly one output, but in this case, the input -1 has two different outputs, violating the definition of a function.

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The image of R after a reflection over the x-axis is the point S(-2, -1).

To reflect a point over the x-axis, we simply negate its y-coordinate while keeping its x-coordinate the same.

Starting with point R(-2, 1):

The x-coordinate remains the same: -2

The y-coordinate is negated: -1

So the image of R after a reflection over the x-axis is the point S(-2, -1).

To graph the reflection, we can plot the original point R and then draw a dashed line to represent the x-axis. Finally, we can plot the reflected point S on the other side of the x-axis.

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Answer:

i think side AC is 14 because if you do subtract BC (18) from EF(12) you get 6, so u add 6 to DF(8) and get 14.

if its confusing ask me questions!!

Answer:

12

Step-by-step explanation:

When triangles are similar, their side ratios are the same. The ratio of EF to BC is 18/12, or 3/2. To find the side AC, we would multiply the corresponding part of DEF by 3/2, the same ratio. The corresponding part of DEF would be DF. DF = 8. 8 times 3/2 is 12. So AC is 12.

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In linear equation, 48720 is  the tread life covered under the warranty.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

1)  µ = 60,000 and σ = 6000 miles.

P ( X >= 55000 )  = 1 - P ( X < 55000 )

Standardizing the  value

 Z = ( X - μ)/σ

  Z = ( 55000 - 60000 ) / 6000

Z = -0.83

 P((X - μ)/σ > ( 55000 - 60000)/6000

P ( Z > -0.83 )

P ( X >= 55000 )  = 1 - P ( Z < -0.83 )

P ( X >= 55000 )  =  1 - 0.2033

P ( X >= 55000 )  = 0.7967

Part v)   What proportion of the tires will need to be replaced under warranty?

 X ~ N ( μ = 60000 , σ = 6000 )

P ( X < 52000 )

Standardizing the value

  Z = ( X - μ)/σ

  Z = ( 52000 - 60000 ) / 6000

Z = -1.33

   P((X - μ)/σ > ( 55000 - 60000)/6000

P ( X < 52000 ) =  P ( Z < -1.33 )

P ( X < 52000 ) = 0.0918

Part c)  If you buy 36 tires,  what is the probability that the  average life of your 36 tires will exceed  61,000?

     X ~ N ( μ = 60000 , σ = 6000 )

 P ( X > 61000 )  = 1 - P ( X < 61000 )

Standardizing the  value

   Z = ( X - μ)/(σ/√n)

  Z = (61000 - 60000)/(6000/√36)

    Z = 1

 P(( X - μ)/(σ/√n) > (61000 - 60000)/(6000/√36)

P ( Z > 1 )

P ( X > 61000 )  = 1 - P ( Z < 1 )

P ( X > 61000 )  = 1 - 0.8413

P ( X > 61000 )  =  0.1587

Part d)  The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life.  Find the tread life covered under the warranty.

P ( Z < ? ) = 3% = 0.03

Looking for the probability 0.03 in standard normal table to find the critical value Z

Z = - 1.88

Z = (X - μ)/σ

- 1.88 = ( X - 60000)/6000

 X = 48720

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The calculated value of the indicated missing length x in the right triangle is 12

Given the right triangle

We can start by calculating the value of x using the following equivalent ratio

x : 9 = 25 - 9 : x

Evaluate the difference

This gives

x : 9 = 16 : x

Next, we express the equivalent ratio as a fraction

So, the ratio becomes

x/9 = 16/x

Cross multiply the equation to calculate x

So, we have the following

x * x = 9 * 16

Evaluate the product

x² = 144

Take the square root of both sides

So, we have the solution to be

y = 12

Hence, the value of x is 12

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Sylvia's dad bought [tex]2\frac{2}{3}[/tex] pounds of potatoes for the thanksgiving meal using division and multiplication.

One of the four fundamental mathematical processes, along with addition, subtraction, and multiplication, is division. Division is the process of dividing a larger group into smaller groups so that each group contains an equal amount of items. It is a mathematical procedure used for equal distribution and equal grouping. Repetitive subtraction is the procedure of division. It is the multiplying operation's opposite. It is described as the process of creating equitable organizations. When dividing numbers, we break a bigger number down into smaller ones so that the larger number taken will be equal to the multiplication of the smaller numbers.

In this question,

1 bag of potatoes= 1/3 pounds

8 bags of potatoes= 8* 1/3

                               =8/3

                             =  [tex]2\frac{2}{3}[/tex] pounds

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(a) The area under the standard normal curve to the left of 1.73 is 0.9582.

(b) The area under the standard normal curve to the left of -0.69 is 0.2454.

(c) The area under the standard normal curve to the right of 1.3 is 0.0968.

(d) The area under the standard normal curve to the right of -2.82 is 0.9974.

(e) The area under the standard normal curve between -2.22 and 0.52 is 0.6851.

(f) The area under the standard normal curve between -1 and 1 is 0.6826.

(g) The area under the standard normal curve between -4 and 4 is 0.9998.

(a) Using a standard normal table, the area under the standard normal curve to the left of 1.73 is 0.9582.

(b) Similarly, the area under the standard normal curve to the left of -0.69 is 0.2454.

(c) The area to the right of 1.3 is the same as the area to the left of -1.3. Using a standard normal table, this area is 0.0968.

(d) The area to the right of -2.82 is the same as the area to the left of 2.82. Using a standard normal table, this area is 0.9974.

(e) To find the area under the standard normal curve between -2.22 and 0.52, we need to find the area to the left of 0.52 and subtract the area to the left of -2.22. Using a standard normal table, we find that the area to the left of 0.52 is 0.6990 and the area to the left of -2.22 is 0.0139. Therefore, the area between -2.22 and 0.52 is 0.6990 - 0.0139 = 0.6851.

(f) To find the area under the standard normal curve between -1 and 1, we need to find the area to the left of 1 and subtract the area to the left of -1. Using a standard normal table, we find that the area to the left of 1 is 0.8413 and the area to the left of -1 is 0.1587. Therefore, the area between -1 and 1 is 0.8413 - 0.1587 = 0.6826.

(g) The area under the standard normal curve between -4 and 4 is the same as the area to the left of 4 minus the area to the left of -4. Using a standard normal table, we find that the area to the left of 4 is 0.9999 and the area to the left of -4 is 0.0001. Therefore, the area between -4 and 4 is 0.9999 - 0.0001 = 0.9998.

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The answer of the given question based on statistics to find the  most appropriate size of the bin from the data the answer is , the most appropriate bin size for this data set would be A. 69.

Statistics is  the practice of collecting, analyzing, and interpreting the data. It involves  use of mathematical tools and techniques to gather insights and knowledge from numerical and categorical information. Statistics is essential in many fields, like  business, medicine, social sciences, and engineering, as it enables researchers to draw conclusions from data and make informed decisions based on evidence.

It includes topics like probability, hypothesis testing, regression analysis, and data visualization. The application of statistical methods can help identify patterns, relationships, and trends in data, allowing researchers to make predictions and solve problems.

To determine the appropriate bin size, we need to consider the range of values in the data. The range is the difference between the largest and smallest values, which in this case is 192 - 123 = 69.

To get the bin size, we divide the range by the number of bins. So the bin size would be 69/4 = 17.25. However, since we can't have a fraction of a unit for bin size, we should round up to the nearest whole number. Therefore, the most appropriate bin size for this data set would be A. 69.

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The answer of the given question based on statistics to find the  most appropriate size of the bin from the data the answer is , the most appropriate bin size for this data set would be A. 69.

Statistics is  the practice of collecting, analyzing, and interpreting the data. It involves  use of mathematical tools and techniques to gather insights and knowledge from numerical and categorical information. Statistics is essential in many fields, like  business, medicine, social sciences, and engineering, as it enables researchers to draw conclusions from data and make informed decisions based on evidence.

It includes topics like probability, hypothesis testing, regression analysis, and data visualization. The application of statistical methods can help identify patterns, relationships, and trends in data, allowing researchers to make predictions and solve problems.

To determine the appropriate bin size, we need to consider the range of values in the data. The range is the difference between the largest and smallest values, which in this case is 192 - 123 = 69.

To get the bin size, we divide the range by the number of bins. So the bin size would be 69/4 = 17.25. However, since we can't have a fraction of a unit for bin size, we should round up to the nearest whole number. Therefore, the most appropriate bin size for this data set would be A. 69.

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The complete question is as fpllows:

123, 185, 143, 137, 192, 185, 129, 143, 154, 165, 143, 138, 187, 176

A bin size of is most appropriate for the data shown above.

A. 69

B. 2

C. 10

D. 1​

Answer: 32

Step-by-step explanation: got you broski

The approximate value of R'(5) is -716 vehicles per hour per hour.

To approximate Rʹ(5), we can use the formula for the average rate of change

Rʹ(5) ≈ (R(6) - R(4))/(6-4)

We use the values given in the table to get

R(6) = 3010 vehicles per hour

R(4) = 3442 vehicles per hour

Therefore, Rʹ(5) ≈ (3010 - 3442)/(6-4) = -716 vehicles per hour per hour.

So, the approximate rate of change of the rate at which vehicles cross the bridge at 5:00 a.m. is -716 vehicles per hour per hour. This means that the rate at which vehicles cross the bridge is decreasing at a rate of 716 vehicles per hour every hour around 5:00 a.m.

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The given question is incomplete, the complete question is:

On a certain weekday, the rate at which vehicles cross a bridge is modeled by the differentiable function R for 0 ≤ t ≤ 12, where R(t) is measured in vehicles per hour and t is the number of hours since 7:00 a.m. (t = 0). Values of R(t) for selected values of t are given in the table above. t(hours) 0 2 4 6 8 10 12 R(t) (vehicle per hours ) 2935 3653 3442 3010 3604 1986 2201 . Use the data in the table to approximate Rʹ(5)

The cosine of 330 degrees is sqrt(3)/2.

To find the cosine of 330 degrees, we need to use the concept of reference angles. A reference angle is the acute angle formed between the terminal side of an angle and the x-axis.

First, we need to determine the reference angle for 330 degrees. Since 330 degrees is in the fourth quadrant, we can subtract it from 360 degrees to find the equivalent acute angle in the first quadrant

360 degrees - 330 degrees = 30 degrees

Therefore, the reference angle for 330 degrees is 30 degrees.

Next, we need to use the trigonometric function values for angles in special right triangles. For a 30-60-90 degree triangle, the ratios of the sides are

sin(30 degrees) = 1/2

cos(30 degrees) = sqrt(3)/2

tan(30 degrees) = 1/sqrt(3)

Since the reference angle for 330 degrees is 30 degrees, we can use the cosine value of 30 degrees to find the cosine value of 330 degrees

cos(330 degrees) = cos(360 degrees - 30 degrees) = cos(30 degrees) = sqrt(3)/2

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The given question is incomplete, the complete question is:

Use reference angles and the trigonometric function values for angles in special right triangles to find each trigonometric value . cos 330 degrees

Since I added three 4 kg weights and one 1 kg weight to the left side of the fulcrum, the blue mass is 13 kg and is completely balanced. In light of this, the blue mass's mass is 13 kg.

To keep the beam horizontal for a beam balance, a body with gravitational mass m1 and a standard weight of m2 are placed in the left and right pans, respectively. If a1 = a2, then m1 = m2, and vice versa. Alternatively, the gravitational mass of the body in the left pan is equal to the gravitational mass in the right pan.

For calibrating masses between 13 mg and 4+1 = 5 kg, a beam balance is utilised. Depending on the calibre and sharpness of the knife edge used to make the pivot, a given measurement can be made with a given resolution and accuracy.

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The actual question is :

Determine the amount of mass possessed by the blue mass. Show your data and explainyour reasoning or show the math. The amount of the blue mass is 13 kg since I placed three 4 kg and 1 kg on the left side of the fulcrum and it is completely balance . Therefore the mass possessed by the blue mass is 13 kg .

Marvin won the game by 30 points.

Marvin tossed three times and got the following numbers: 5, 2, 4.

For the first toss, he tossed a 5, which is 4 or above, so he gains 4 times the number that turns up. Therefore, he gains:

4 x 5 = 20

For the second toss, he tossed a 2, which is below 3, so he loses 3 times the number that turns up. Therefore, he loses:

3 x 2 = 6

For the third toss, he tossed a 4, which is 4 or above, so he gains 4 times the number that turns up. Therefore, he gains:

4 x 4 = 16

To find out whether Marvin won or lost the game, we need to add up his gains and losses.

His total gain is:

20 + 16 = 36

His total loss is:

6

Therefore, his net gain is:

36 - 6 = 30

Marvin won the game by 30 points.

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As a result, the probability of a 45-54-year-old motorist becoming involved in an accident is 5.38%, rounded to two decimal places.

Probabilistic theory is a branch of mathematics that calculates the likelihood of an event or proposition occurring or being true. A risk is a number between 0 and 1, with 1 indicating certainty and a probability of around 0 indicating how probable an event appears to be to occur. Probability is a mathematical term for the likelihood or likelihood that a certain event will occur. Probabilities can also be expressed as numbers ranging from 0 to 1 or as percentages ranging from 0% to 100%. In relation to all other outcomes, the ratio of occurrences among equally likely alternatives that result in a certain event.

To determine the likelihood that a driver aged 45-54 was involved in an accident, divide the number of drivers in that age group who were engaged in an accident by the total number of drivers in that age group:

Probability = Number of 45-54-year-old drivers involved in an accident / Total number of 45-54-year-old drivers

We can observe that 7 drivers aged 45 to 54 were engaged in an accident, with a total of 130 drivers in that age group:

The probability is 7/130 = 0.0538.

To convert this to a percentage, multiply by 100:

Probability = 0.0538 * 100 = 5.38 percent

As a result, the likelihood of a 45-54-year-old motorist becoming involved in an accident is 5.38%, rounded to two decimal places.

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Answer:

m = 0

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Pick 2 points (0,2) (1,2)

We see the y stay the same and the x increase by 1, so the slope is

m = 0/1 = 0

So, the slope is 0

For Fund T: Expected Return = 11.32% For Fund U: Expected Return = 8.94%,,For Fund T:Expected return (11.32%) > Our forecasted return (8%) .

Thus, Fund T is priced below the SML and is undervalued. For Fund U Expected return (8.94%) < Our forecasted return (10%) Thus, Fund U is priced above the SML and is overvalued and  Fund T is undervalued and Fund U is overvalued.

a. To calculate the expected return for each mutual fund according to the CAPM, we can use the following formula:

Expected Return = Risk-free rate + (Market Risk Premium × Beta)

For Fund T:

Expected Return = 3.9% + (6.1% × 1.20) = 11.32%

For Fund U:

Expected Return = 3.9% + (6.1% × 0.80) = 8.94%

b. To determine whether Fund T and Fund U are currently priced to fall directly on the security market line (SML), above the SML, or below the SML, we need to compare their expected returns with our own return forecasts. Let's assume that we have forecasted returns of 8% for Fund T and 10% for Fund U.

If the expected return for a mutual fund is higher than our own return forecast, it is considered to be priced below the SML and thus undervalued. Conversely, if the expected return is lower than our own forecast, the mutual fund is considered to be priced above the SML and therefore overvalued. If the expected return and our own forecast are the same, the mutual fund is priced directly on the SML and is considered to be properly valued.

Using the CAPM expected returns calculated in part (a), we can compare with our own return forecasts:

For Fund T:

Expected return (11.32%) > Our forecasted return (8%)

Thus, Fund T is priced below the SML and is undervalued.

For Fund U:

Expected return (8.94%) < Our forecasted return (10%)

Thus, Fund U is priced above the SML and is overvalued.

c. Based on our analysis, Fund T is undervalued and Fund U is overvalued. This suggests that investors should consider buying Fund T, as it is expected to provide higher returns than the market return, while Fund U may not provide sufficient returns to compensate for the higher risk. However, it is important to note that other factors such as fund expenses, management quality, and investment strategy should also be considered when making investment decisions.

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The conditions in which is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal : (C) A random sample of 10 taken from a population distribution that is skewed to the right.

In statistics, the normal or Gaussian distribution is a continuous probability distribution for real-valued random variables.

The normal distribution is important in statistics and is often used in the natural and social sciences to represent real-valued random variables whose distribution is unknown. Their importance is partly due to the central limit theorem. It states that in some cases the average of many samples (observations) of a random variable with finite mean and variance is itself a random variable - whose distribution converges to a normal distribution as the size of the l sample increases.

Now,

If we look at the options given below, we see that the random samples in options A and B are normally distributed, so their sample means will be approximately normally distributed.

Similarly, option E indicates that the population is uniform, so the sample mean will also be approximately normal.

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