Select the correct answer.
Which expression is equivalent to the given expression?
In(2e/x)

A. In 2 - In x
B. In 1 + In 2 - ln x
C. 1 + In 2 - In x
D. In 2 + ln x

domain is  (- infinity, infinity)

range is (- infinity, infinity)

Answer:

B, 8 (2a+3b).

Step-by-step explanation:

First, let's let A=1 and B=2. 16a+24b would equal 64, and so would B, which is 8 (2a+3b). Then lastly you solve, and you get 64 for both of them, which means B is equal to that expression.

Answer:

B

Step-by-step explanation:

8(2a) = 16a

8(3b) = 24b

16a + 24b

Answer:

The monthly payment will be $ 162.50. In turn, the interest paid will be $ 33,750, constituting 69.23% of the total amount paid.

Step-by-step explanation:

Since there is a student loan of 15,000 at a fixed APR of 9% for 25 years, to calculate the monthly payment, determine the tiaras amount paid over the term of the loan, and determine, of the total amount paid, what percentage is paid toward the principal and what percentage is paid for interest, the following calculations must be performed:

((15,000 x 0.09) x 25) + 15,000 = X

33,750 + 15,000 = X

48,750 = X

48,750 / (25x12) = X

48,750 / 300 = X

162.5 = X

48,750 = 100

33,750 = X

33,750 x 100 / 48,750 = X

69.23 = X

Therefore, the monthly payment will be $ 162.50. In turn, the interest paid will be $ 33,750, constituting 69.23% of the total amount paid.

Answer:

The second choice

Step-by-step explanation:

For this, we can use the process of elimination. The first choice is crossed out, since they are mix and matching the numbers. The third choice is also crossed out since the second choice is correct. The second choice is correct because 9/11*3=27/33.

Answer:

They are similar because 9/11 = 27/33

The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

The function is given as:

y = 6x^2 + x - 35

Expand the function

y = 6x^2 + 15x - 14x - 35

Factorize the function

y = (2x + 5) * (3x - 7)

Set the function to 0

(2x + 5) * (3x - 7) = 0

Split

2x + 5 = 0 or 3x - 7 = 0

Solve for x

x = -2.5 or x = 7/3

Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

Read more about quadratic functions at:

https://brainly.com/question/1214333

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Answer: Isolate the term that contains the squared variable. Then, take the square root of both sides and solve.

Step-by-step explanation:

To solve an equation by using the square root property, you will first isolate the term that contains the squared variable. You can then take the square root of both sides and solve for the variable. Make sure to write the final answer in simplified form.

Answer/Step-by-step explanation:

1.

✔️Coordinates of vertices ABC:

A(2, 2)

B(6, 2)

C(2, -1)

✔️AC = |2 - (-1)| = 3 units

AB = |2 - 6| = 4 units

2. Distance formula => [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Distance between B(6, 2) and C(2, -1):

[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] B(6, 2) = (x_1, y_1) [/tex]

[tex] C(2, -1) = (x_2, y_2) [/tex]

[tex] BC = \sqrt{(2 - 6)^2 + (-1 - 2)^2} [/tex]

[tex] BC = \sqrt{(-4)^2 + (-3)^2} [/tex]

[tex] BC = \sqrt{16 + 9} = \sqrt{25} [/tex]

[tex] BC = 5 units [/tex]

Answer:

The person above me has the correct answer and solves it in the correct way.

Step-by-step explanation:

This is what I used as my answer though.

Distance Formula: d = √(x2-x1)^2 + (y2-y1)^2 

BC = √(x2-x1)^2 + (y2-y1)^2 

B = (6,2)

C = (2,-1)

BC = √(2-6)^2 + (-1-2)^2 

BC = √(-4)^2 + (-3)^2 

BC = √16+9

BC = √25

BC = 5

Answer:

i cant see the photo

Step-by-step explanation:

9514 1404 393

Answer:

  (1, 155)

Step-by-step explanation:

Let f(x) = 17n(x) +2, where n(1) = 9.

Then we have ...

  f(1) = 17n(1) +2 = 17×9 +2 = 153 +2

  f(1) = 155

A point on the new graph would be (1, 155).

Answer:

no we can't

Step-by-step explanation:

(-4)÷(-2). (-16÷(-2)

2. 8

[tex]\longrightarrow{\blue{[( - 16)\div 4) \div ( - 2)] \:is\:not\:equal\:to\:( - 16) \div [4 \div( - 2) ] }}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex][( - 16 )\div 4) \div ( - 2)] = ( - 16) \div [4 \div( - 2) ][/tex]

Let us first solve for L. H. S.

[tex] = [( - 16 )\div 4) \div ( - 2)][/tex]

[tex] = [ (\frac{ - 16}{4} )\div ( - 2)][/tex]

[tex] = \frac{( - 4)}{( - 2)} [/tex]

[tex] = 2[/tex]

Now, R. H S.

[tex]( - 16) \div [4 \div ( - 2)][/tex]

[tex] = \frac{ - 16}{ - 2} [/tex]

[tex] = 8[/tex]

[tex]\sf\purple{L. H. S.\: ≠ \:R. H. S. }[/tex]

Hence, [tex][( - 16) \div 4) \div( - 2)] ≠(-16)\div [4 \div( - 2) ][/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Step-by-step explanation:

Derive an expression for the equivalent width in a saturated line. Assume a Voigt profile, with the difference in optical depth between the center of the line and the wings being ~104. The wings of the line can be ignored. Define a frequency x1 = (v1 − v0)/ΔvD, where the optical depth τv = 1. Inside of x1 the line is fully saturated, and outside x1 the line is optically thin. Show that the equivalent width is



Note that the equivalent width is practically insensitive to the number density of absorbing material.

Answer:

The corrects answers are: C, D, E, F

Step-by-step explanation:

Answer:

m = +/- 12

Step-by-step explanation:

A quadratic function has only one x-intercept when the discriminant is equal to 0. The discriminant is b^2 - 4(a)(c).

When we plug in what we know, we have:

m^2 - 4(18)(2) = 0.

Then using algebraic properties, solve for m.

m^2 - 144 = 0

m^2 = 144

m = +/- 12

When you plug in positive or negative 12, and then factor you will see that it comes out to a difference of squares, proving that there is only one x-intercept.

Answer: C

Step-by-step explanation:

EDGE 2023

Answer:

domain of function refers to the various values that can be passed through to the function.

Step-by-step explanation:

Answer:

8x+(-20x)

Step-by-step explanation:

Answer:

Yes, because they are identical to eachother

Step-by-step explanation:

Answer:

27

Step-by-step explanation:

every 30 men = 9 men with beards

you have 30 3 times in 90 so you get 27

60÷2=30

18÷2=9

30 men normal = 9 men with beards

90÷30=3

3×9=27

Answer:

Step-by-step explanation:

b = sqrt(2 * L)                 Given

L = 4.5                            Given

b = sqrt(2 * 4.5)

b = sqrt(9)

b = 3

Answer:

b = 9

Step-by-step explanation:

Given :-

[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]

[tex] \small \: l = 4.5[/tex]

Solution :-

[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]

plug the values of l in the equation

[tex] \small \sf \leadsto \: b = \sqrt{2 × 4.5} [/tex]

[tex] \small \sf \leadsto \: b = \sqrt{9} [/tex]

[tex] \small \sf \leadsto \: b = 9 [/tex]

Answer:

Eighty thousand

Step-by-step explanation:

Look at the place value chart.

Answer:

x ≥ 12

Step-by-step explanation:

-3/4x +2 ≤ -7

Subtract 2 from each side

-3/4x +2-2 ≤ -7-2

-3/4x  ≤ -9

Multiply each side by -4/3, remembering to flip the inequality

-3/4x * -4/3 ≥ - 9 *(-4/3)

x ≥ 12

Answer:

x>=12

Step-by-step explanation:

-3/4x + 2<=-7

-3/4x <= -7 -2

-3/4x<=-9

cross multiply

-3x<=-36

dividing throughout by -3

x>=12

Answer:

The value of equipment after 2 years is $58,800

Step-by-step explanation:

f(n) = 67,500(14/15)ⁿ

where f(n) is the value after n years.

1 – 1 / 15 = 14 / 15.

Answer:

hello ok I will share u the link where u can find step by step answers

Answer:

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

A Let tower be AB

Let point be C

Distance of point C from foot of tower = 30m Hence,

BC = 30m

Angle of elevation = 30°

So < ACB = 30°

Since tower is vertical,

< ABC = 90°

Answers:

=======================================================

Explanation:

So far that accounts for 15+30+35 = 80 people who work in the field, the office, or both.

The remaining 90-80 = 10 people are absent.

The venn diagram is below.

Answer:

x = 18

y = 38

Step-by-step explanation:

Let the smaller number be = x

Let the larger number be = y

Sum of the number, x + y = 56 --------- ( 1 )

Seven  times smaller number = 7x

Three times larger number = 3y

Seven times smaller = 12 more than 3times larger , 7x = 12 + 3y ----- ( 2 )

Solve ( 1 ) and ( 2 )

x + y = 56  => x = 56 - y

Substitute x in ( 2 )

7x - 3y = 12

7(56 - y) - 3y = 12

392 - 7y - 3y = 12

-10y =  12 - 392

-10y = - 380

y = 38

Substitute y in ( 1 )

x + y = 56

x + 38 = 56

x = 56 - 38

x = 18

Answer:

The derivative of any constant number is 0.

So,

Differentiating with respect to "x",

d f(x)/dx

=d 25/dx

=0

Answer:

x = 12

Step-by-step explanation:

g(x) - × + 4 =0

put g(x) = 8

so, 8 - x + 4 = 0

x = 12

Answer:

x = - 4

Step-by-step explanation:

Given g(x) = - x + 4 and g(x) = 8 , the equate the right sides, that is

- x + 4 = 8 ( subtract 4 from both sides )

- x = 4 ( multiply both sides by - 1 )

x = - 4

I can't understand tell me in english

Given:

The system of equations is:

[tex]x+3y=5[/tex]

[tex]x-3y=-1[/tex]

The given matrices are [tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex], [tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex], [tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex].

To find:

The correct names for the given matrices.

Solution:

We have,

[tex]x+3y=5[/tex]

[tex]x-3y=-1[/tex]

Here, coefficients of x are 1 and 1 respectively, the coefficients of y are 3 and -3 respectively and constant terms are 5 and -1 respectively.

In the x-determinant, the coefficients of x are in the first column and the constant terms are in the second column. So, the x-determinant is:

[tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex]

In the y-determinant, the constant terms are in the first column and the coefficients of y are in the second column. So, the y-determinant is:

[tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex]

In the system determinant, the coefficients of x are in the first column and the coefficients of y are in the second column. So, the system determinant is:

[tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex]

Therefore, the first matrix is y-determinant, second matrix is x-determinant and the third matrix is the system determinant.