Answer:
where is the image?
Explanation:
Answer:
the first one
Explanation:
The north pole of a magnet is brought near to the current-carrying solenoid.
State whether the north pole is attracted or repelled by the solenoid. Explain why.
Answer:
The north and south pole of a solenoid depends on two factors. One, the direction of the current flow and two, the direction of the winding (clockwise or counter-clockwise). ... If clockwise in relation to the positive wire then is the south pole, if anti-clockwise then is the north pole.
Explanation:
The north and south pole of a solenoid depends on two factors. One, the direction of the current flow and two, the direction of the winding (clockwise or counter-clockwise). ... If clockwise in relation to the positive wire then is the south pole, if anti-clockwise then is the north pole.
Review. As it passes over Grand Bahama Island, the eye of a hurricane is moving in a direction 60.08 north of west with a speed of 41.0 km/h. (a) What is the unit-vector expression for the velocity of the hurricane
Answer:
Velocity = -20.45 i + 35.54 j km/h
Explanation:
given data
speed v = 41.0 km/h
direction = 60.08 north of west
solution
first we get here Speed in west direction that is express as
Speed in west direction = v × cos(60.08) ..........................1
Speed in west direction = 41 × cos(60.08)
Speed in west direction = 20.45 km/h
now we get Speed in north direction that is
Speed in north direction = v × sin(60.08) ............................2
Speed in north direction = 41 × sin(60.08)
Speed in north direction = 35.54 km/h
so Velocity will be here
Velocity = -20.45 i + 35.54 j km/h
James makes a treasure map to locate a secret item on McEachern Campus. He uses the
following displacement vectors to locate the treasure
A student wants to simplify this information
5 m East
7 m North
5 m South
7 m East
3 m South
2 m West
A. Determine the Displacement Vector Components. (x componenty component)
Show all work. 2 pts
B. Use the Pythagorean Theorem to calculate the resultant vector. Show all work. 2 pts
Answer format:
a. work & answer...
b. work and answer...
(4 Points)
Answer:
south
Explanation:
Question 6
2 pts
Jenny loves puffed rice cereal. As she is pouring the cereal, two little pieces of cereal each with
equal charges of 1.85 x10-18 coulombs fall into the bowl 0.025 meters apart. Use Coulomb's Law
to find the electrostatic force between them. (Remember, Coulomb's constant is 8.99 x10
N*m²/C2)
4.9 x 10-23 N
6.2 x 10-15 N
9.0 x 10-3N
2.5 x 10-23 N
Answer:
4.9 x 10-23 N
Explanation:
I took the test
A volleyball player spiking is it kinetic or potential
Answer:
It is kinetic energy.
Explanation:
The kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate the volleyball from rest to its stated velocity. Having gained this energy from the player spiking it during its acceleration, the body maintains this kinetic energy unless its speed changes.
1. Calculate the electric field due to a single +1nC point charge at a distance of lm, 2m, and 3m
Answer:
Approximately [tex]9.0\; \rm N \cdot C^{-1}[/tex] at [tex]1\; \rm m[/tex] from this charge, pointing away from the point charge.Approximately [tex]2.2\; \rm N \cdot C^{-1}[/tex] at [tex]\rm 2\; \rm m[/tex] from this charge, pointing away from the point charge.Approximately [tex]1.0\; \rm N \cdot C^{-1}[/tex] at [tex]3\; \rm m[/tex] from this charge, pointing away from the point charge.Assumption: there is no object between this point charge and the observer.
Explanation:
The electric field of a point charge is inversely proportional to the square of the distance from that point charge.
Let [tex]k[/tex] denote Coulomb's constant ([tex]k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}[/tex].) Let the magnitude of that point charge be [tex]q[/tex]. At a distance of [tex]r[/tex] from this charge, the electric field due to this charge would be:
[tex]\displaystyle E = \frac{k \cdot q}{r^{2}}[/tex].
Convert the magnitude of the point charge in this question to standard units:
[tex]q = 1\; \rm nC = 10^{-9}\; \rm C[/tex].
Apply that equation to find the magnitude of the electric field due to this point charge:
[tex]r = 1\; \rm m[/tex]:
[tex]\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}[/tex].
[tex]r = 2\; \rm m[/tex]:
[tex]\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}[/tex].
[tex]r = 3\; \rm m[/tex]:
[tex]\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}[/tex].
The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.
Because the [tex](+1\; \rm nC)[/tex] point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this [tex](+1\; \rm nC)\![/tex] point charge at any point in the field would point away from this charge.
How much time will it take for a bug to travel 2 meters across the floor if it is traveling at 0.5 m/s?
Answer:
it will take 4 seconds to travel 2 meters.
A 20.0 newton force is used to push a 2.00 kilogram cart a distance of 5.00 meters how much work is done on the cart
Answer:
100
w=f*s
20*5=100....
100 Joules of work is done on the cart.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the applied force on the object in the direction of displacement. When we push a block with some force, the body moves with some acceleration, so it is called work done.
Work done is expressed as W=Fd and its unit is joules which can be defined as the amount of work done by a force in Newton is applied to an object, as a result of which it is displaced in meter.
For above given information,
Force= 20 N
Distance= 5 m
So, work done= 20*5= 100 Joules
Thus, 100 Joules of work is done on the cart.
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Observer A, who is at rest in the laboratory, is studing a particle that is moving through the laboratory at a speed of 0.624c and determines its lifetime to be 159ns a) Obsever A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory? b) Obsever B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
Answer:
a) the markers are 29.76 m far apart in the laboratory
b) According to B, the markers are 23.21 m far apart in the laboratory
Explanation:
Given that;
speed of particle = 0.624c = (0.624 × 3×10⁸m/s)
{ where c is the speed of light}
lifetime of the particle t = 159ns = 1.59 × 10⁻⁷
a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory
lets apply the formula distance = velocity × time
lets substitute
distance = (0.624×3×10⁸ m/s) × (1.59 × 10⁻⁷ s)
distance = 29.76 m
Therefore, the markers are 29.76 m far apart in the laboratory
b) Observer B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
lifetime of the particle t = 124ns = 1.24 × 10⁻⁷
distance = (0.624×3×10⁸ m/s) × (1.24 × 10⁻⁷ s)
distance = 23.21 m
Therefore, According to B, the markers are 23.21 m far apart in the laboratory
Suppose a meteor of mass 2.50 x 1013 kg is moving at 33.0 km/s relative to the center of the Earth and strikes the Earth. Suppose the meteor creates the maximum possible decrease in the angular speed of the Earth by moving toward the west and striking a point on the equator tangentially. What is the change in the angular speed of the Earth due to this collision
Answer:
change is imperceptible
w_f = 7.272 10⁻⁵ rad / s
Explanation:
For this exercise we can use the conservation of angular momentum.
Initial. Before the crash
L₀ = I w₀
final. After the crash
L_f = I w_f + p r
where the moment is
p = mv
As the system is formed by the two bodies, the forces during the impact are internal, therefore the angular momentum is conserved
L₀ = L_f
I w₀ = I w_f + m v r
w_f = w₀ - [tex]m \frac{ v \ r }{I}[/tex]
We can approximate the Earth to a sphere, so its angular momentum is
I = 2/5 M r²
we substitute
w_f = w₀ - [tex]\frac{5 \ m \ v}{2 \ M \ r}[/tex]
We can find the angular velocity of the Earth with the duration of a spin which is the period of one day
w₀ = 2π / T
T = 24 h (3600 s / 1h) = 86 400 s
w₀ = 2π / 86400
w₀ = 7.272 10⁻⁵ rad / s
let's calculate
w_f = 7.27 10⁻⁵ - [tex]\frac{5 \ 250 \ 10^{13} \ 33.0 \ 10^{3} }{ 2 \ 5.98 \ 10^{24} \ 6.37 10^{6} }[/tex]
w_f = 7.272 10⁻⁵ - 1.0829 10⁻¹³
w_f = 7.27199999 10⁻⁵
this change is imperceptible
w_f = 7.272 10⁻⁵ rad / s
Explain why stones are strong in compression but weak in tension
Answer:
Gigantic towers, monuments and tall structures are always supported by a very thick layer of concrete that’s blended into their foundation. The purpose of this is quite straightforward: nothing provides greater support to a super heavy (and stationary) structure than a layer of concrete. There may be other things that, in theory, could provide a stronger foundation, but they wouldn’t be nearly as cost effective as concrete.
Answer:
Because it has essentially zero strength in tension, it is almost always used as reinforced concrete, a composite material. It is a mixture of sand, aggregate, cement and water.
Convert the arc length of 3.05 degrees into meters.
That depends on the circle's radius, which you neglected to mention.
If the radius is 1 meter, then an arc of 3.05 degrees is 5.32 centimeters long.
If the radius is 1 kilometer, then an arc of 3.05 degrees is 53.2 meters long.
A long, thin metal tube of cross-sectional area 1.60 cm2 is sealed into the top of a hollow cube of edge length 0.150 m. Water fills the cube and extends upward a distance h into the tube. Find h if the water exerts a force of 1.00 103 N on the base of the cube. What is the weight of the water?
Answer:
Explanation:
Given that:
The area of the metal tube = 1.60 cm² = 1.60 × 10⁻⁴ m²
Length of cube L = 0.150 m
The exerted force by water = 1.00 × 10³ N
At the top of the cube;
The force on water is F = pgL
F = 9.8 m/s² × (1000 kg/m³) (0.150 m)(0.150 m)²
F = 33.075 N
∴
[tex]pgh = \dfrac{F}{A}[/tex]
[tex]h = \dfrac{F}{Apg}[/tex]
[tex]h = \dfrac{33.075}{(1.60 \times 10^{-4} \ m^2) \times (1000 \ kg/m^3)(9.8)}[/tex]
h = 21.09 m
The volume of the water V = L³
V = (0.150 m)³
V = 0.003375 m³
weight of the water w = p(V + Ah)
w = 1000 (0.003375 + (1.60 × 10⁻⁴ × 21.09))
w = 6.75 kg
often occurs at subduction zones. Check all that apply:
O convergence
trench
upward convection currents in the mantle below it
Orifts
most volcanoes...Pacific Ring of Fire
continental plate subducts because it's less dense
Answer:
convergence and trench
Explanation:
LOL
The specific heat of water is 4,186 J/kg.'C. Approximately how much heat must
be removed from 0.500 kg of water to change its temperature from 24.0°C to
5.00°C?
Explanation:
Q= mc∆T
∆T= 5-24=- 19
Q= 0.5*4186*-19
Q= -39767 J
negative sign show heat releases
Two carts collide and have a perfectly inelastic collision. Cart1 has a mass of 500 grams and
Cart2 has a mass of 600 grams. Cart1 has an initial westward velocity of 1.6 m/s and collides
with Cart2 which was initially at rest. What is was the final velocity of the two cart system (SI
units)?
Answer: look at the file
The amount of energy a substance has depends on the state of matter
the substance is in at the time.
True
or False
(b) The efficiency of the pump which operates the fountain is 70%.
Calculate the power supplied to the pump.
Answer:
Power supplied to the pump is 980000 W or 980 KW
Note: The question is incomplete. The complete question is given below:
On a day with no wind, a fountain in Switzerland propels 30000 kg of water per minute to a height of 140 metres.
a)Calculate the power used in raising the water?
b)The efficiency of the pump which operates the fountain is 70%
calculate the power supplied to the pump?
Explanation:
Efficiency = Power output/Power input * 100%
Power output = work done/ time
where work done = mass * acceleration due to gravity (g) * height
time = 1 minute = 60 seconds
mass of water = 30000 kg, height = 140 meters, g = 9.8 m/s²
Then, work done = 30000 * 140 * 9.8 = 41160000 J
Power output then = 41160000 J / 60 s
Power output = 686000 W
The power input can then be derived from the formula of efficiency
Power input = (Power output * 100)/Efficiency
Power input = (100 * 686000) / 70
Power input = 980000 W
Therefore, power supplied to the pump is 980000 W or 980 KW
An astronaut on a spacewalk pushes off of the outside of the spaceship. Compare the force of the astronaut on the ship to the force of the ship on the astronaut. Compare the astronaut's change in momentum to the spaceship's change in momentum. Compare the astronaut's change in velocity to the spaceship's change in velocity
Answer:
and yes, sound travels at the speed of entity expressions is whhy you need math for a job in mc donalds :
293 x gj -2 = 23r = velocity of rocket ship is 2.74
Using a simple model of an electromagnet, describe the factors that increase the magnetic field strength of an electromagnet.(2 points)
Answer:
Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core
Explanation:
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The following factors affect the strength of an electromagnet; number of turns, wire size, current and the presence of iron core.
What is electromagnet?This is a type of magnet in which the magnetic field is produced by an electric current.
Factor affecting electromagnetThe following factors affect the strength of an electromagnet;
Number of turnsWire sizeCurrentPresence of iron core.Learn more about electromagnet here: https://brainly.com/question/12555869
Which activities demonstrate speed the most?
Answer:I think sprinting
Explanation:
Sound will travel fastest in air at _____.
-5°C
0°C
10°C
15°C
The following table lists the speed of sound in various materials. Use this table to answer the question.
Substance
Speed (m/s)
Glass
5,200
Aluminum
5,100
Iron
4,500
Copper
3,500
Salt water
1,530
Fresh water
1,500
Mercury
1,400
Hydrogen at 0°C
1,284
Ethyl Alcohol
1,125
Helium at 0°C
965
Air at 100°C
387
Air at 0°C
331
Oxygen at 0°C
316
Answer:
iron/copper
iron faster because it in the core so iron is the answer with would be 15C because its the hottest in the core and is very quick there to being moved by the core so iron being 15C is the answer.
Explanation:
Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)
Answer:
Potential difference [tex]V=1.6\times 10^{-10}\ V[/tex]
Explanation:
Capacitance of capacitor, C = 0.9 MF
Charge, [tex]Q=1.4\times 10^{-4}\ C[/tex]
We need to find the amount of potential difference. We know that,
[tex]Q=CV[/tex]
V is potential difference
So,
[tex]V=\dfrac{Q}{C}\\\\V=\dfrac{1.4\times 10^{-4}}{0.9\times 10^6}\\\\V=1.6\times 10^{-10}\ V[/tex]
So, the required potential difference is [tex]1.6\times 10^{-10}\ V[/tex].
My dream house
Read the text. Drag the words to fill in the gaps to complete it.
stay
electronic
porch
My dream house has lots of rooms and windows. It has a big red front door. There is also a
with a round table and several chairs around it.
There is a living room with comfortable sofas and a big TV screen on the wall. My family likes to spend time together watching TV. In the attic, there is a game room for me and my friends. It has a fridge for drinks and snacks. There are extra bedrooms. My friends can
there at night.
My bedroom is green. Green is my favourite colour. There are lots of shelves for my toy car collection. I am a fan of old cars.
There are lots of posters of my favorite actors and singers. And there is also an
clock that shows the time on the screen.
There is also a new computer, a sound system, and a telescope because I love astronomy. My bed is special. It is in the shape of a car, and it is very comfortable. My bed is next to the window.
Back
Check
Answer:
1 - porch, 2 - stay, 3 - electronic
Help me guys please
Answer:
The answer is B
Explanation:
keep it up
Gamma rays are dangerous because they
a.can breakdown molecules and cells
b. fluoresce
c. cause food to spoil
d. cause sunburn
Answer:
A.
Explanation:
A large fraction of astronomical gamma rays are screened by Earth's atmosphere. Gamma rays are ionizing radiation and are thus biologically hazardous. Due to their high penetration power, they can damage bone marrow and internal organs.
The extremely high energy of gamma rays allows them to penetrate just about anything. They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.
During heavy rain, a section of a mountainside measuring 1.9 km horizontally (perpendicular to the slope), 0.55 km up along the slope, and 2.4 m deep slips into a valley in a mud slide. Assume that the mud ends up uniformly distributed over a surface area of the valley measuring 1.4 km x 1.4 km and that the mass of a cubic meter of mud is 1900 kg. What is the mass of the mud sitting above a 3.5 m2 area of the valley floor
Answer:
the mass of the mud sitting above a 3.5 m2 area of the valley floor is 8509273.5 kg
Explanation:
Given the data in the question;
first we compute the total volume of mud
V = ( 1.9×1000)m × (0.55×1000)m × (2.4×1000)m
V = 2.508 × 10⁹ m³
same volume of mud spread uniformly over 1.4 × 1.4 km² area
Hence,
V = (1.4×1000)m × (1.4×1000)m × depth
2.508 × 10⁹ = 1400m × 1400m × depth
2.508 × 10⁹ m³ = 1960000m² × depth
depth = 2.508 × 10⁹ m³ / 1960000 m²
depth = 1279.59 m
so volume of the mud sitting above 3.5 m² area of the valley floor will be;
⇒ 3.5 m² × 1279.59 m
⇒ 4478.565 m³
so mass will be
m = 4478.565 × 1900 kg
m = 8509273.5 kg
Therefore, the mass of the mud sitting above a 3.5 m2 area of the valley floor is 8509273.5 kg
Can heating cooking oil you’ll be classified as producing a chemical change?
yes it is boiling creating bubbles that aren't their originally
Explanation:
When cooking oils are subjected to heat in the presence of air and water (from food), such as in deep-fat frying and sautéing (pan frying), they can undergo at least three chemical changes: 1) oxidation of the fatty acids, 2) polymerization of the fatty acids, and 3) breaking apart of the triglyceride molecules into free fatty acids and glycerol by hydrolysis (reaction with water from the food being cooked) (Choe and Min 2007)
A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is the initial height of the bob?
Answer:
h = 18.4 cm
Explanation:
Given that,
The speed of the bob at the bottom of the swing is 1.9m/s.
We need to find the initial height of the bob. Let it is h.
We can find it using the conservation of energy i.e.
[tex]mgh=\dfrac{1}{2}mv^2[/tex]
Where
v is speed of the bob
So,
[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m[/tex]
or
h = 18.4 cm
So, the initial height of the bob is 18.4 cm.
The initial height of bob will be "18.4 cm".
Speed and height:Speed would be the scalar quantity that describes "how quickly an attribute moves." This could sometimes be defined as this same rate whereby an object travels a given distance.
According to the question,
The speed of the bob = 1.9 m/s
Let,
The initial height be "h".
By using the conservation of energy, we get
→ mgh = [tex]\frac{1}{2}[/tex]mv²
or,
→ h = [tex]\frac{v^2}{2g}[/tex]
By substituting the values, we get
= [tex]\frac{(1.9)^2}{2\times 9.8}[/tex]
= 0.184 m or,
= 18.4 cm
Thus the above answer is correct.
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PLEASE HELP ASAP EXPLAIN PLEASE
you’ve learned about the intricate network of structures that comprise the respiratory system and how crucial it is to ensure that all pieces of this system remain in top condition. You also learned that smoking tobacco, cannabis, or other substances can have a significant impact on not only the overall health of the lungs but also has negative effects on all body systems. Using this new information, and with independent research, you are now asked to develop a learning package for someone who has come to you for health teaching. Imagine that you are either a nurse in a clinic, a personal trainer, a physiotherapist, or any other health practitioner who has just done an initial consultation with a patient. Your patient has disclosed that they smoke tobacco and they have indicated that they believe that the information about lung disease and smoking is fabricated and that it must be exaggerated. You are now tasked with showing them through a diagram and a verbal demonstration the true scientific facts around smoking and lung disease. Make sure to discuss the symptoms, prevention, diagnosis, and treatment in your demonstration. You will use either a diagram of the respiratory system that you’ve found online or one that you’ve drawn by hand to support your teaching. You will develop a script and teach the material to either an imaginary person or someone else and videotape your lesson.
Answer:
How can smoking affect the respiratory system?
Smoking and Respiratory Disease
Smoking can cause lung disease by damaging your airways and the small air sacs (alveoli) found in your lungs. Lung diseases caused by smoking include COPD, which includes emphysema and chronic bronchitis. Cigarette smoking causes most cases of lung cancer.
Explanation:
I cannot create videos. However, I can help you develop a script for your health teaching package.
Your lungs and general health can be significantly impacted by smoking tobacco and other substances. It's crucial to comprehend the actual scientific data and take action to manage and avoid respiratory illnesses. Do not hesitate to ask if you have any queries or concerns.
What is the impact of smoking tobacco and other substances on the lungs and general health?Hello, and thank you for coming to me for health teaching. I understand that you smoke tobacco, and you may have doubts about the impact it can have on your lungs and overall health. I'm here to show you the true scientific facts around smoking and lung disease.
Let's start with the respiratory system. The respiratory system is made up of many intricate structures that work together to deliver oxygen to your body and remove carbon dioxide. When you inhale smoke from tobacco or other substances, you introduce harmful chemicals into your lungs that can damage these structures.
Over time, smoking can lead to a range of respiratory diseases, including chronic bronchitis, emphysema, and lung cancer. Symptoms of these diseases can include coughing, wheezing, shortness of breath, and chest pain. These symptoms can significantly impact your quality of life and even be life-threatening.
Prevention is key when it comes to respiratory diseases caused by smoking. The best way to prevent these diseases is to quit smoking altogether. If you're struggling to quit, there are many resources available to help you, including nicotine replacement therapy and counseling.
If you're experiencing symptoms of a respiratory disease, it's important to seek medical attention. Your doctor can diagnose the disease and recommend a treatment plan that may include medication, lifestyle changes, and possibly surgery. Early diagnosis and treatment can greatly improve your chances of recovery and help you manage your symptoms.
Now, let me show you a diagram of the respiratory system so you can see how smoking affects it. [At this point, you can show the diagram and point out the different structures affected by smoking, such as the bronchi and alveoli.]
Therefore, smoking tobacco and other substances can have a significant impact on your lungs and overall health. It's important to understand the true scientific facts and take steps to prevent and manage respiratory diseases. If you have any questions or concerns, please don't hesitate to ask.
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