Share £32 in the ratio 1 : 5 : 2.

The volume of the quarter-sphere tank is approximately 1,387,244 cubic feet.

The volume of tank 1 is 353h cubic feet, and the volume of tank 2 is  31,416 cubic feet.

The main tank is in the shape of a quarter-sphere, which means it is a quarter of a full sphere.

The volume of a sphere is given by the formula V = (4/3)πr³, where r is the radius of the sphere.

Given that the radius of the main tank is 95 feet

we can substitute this value into the formula to calculate the volume:

V = (4/3)π(95³) = 1,387,244 cubic feet.

The holding tanks are in the shape of cylinders that have been cut in half vertically.

The volume of a cylinder is given by the formula V = πr²h, where r is the radius of the base and h is the height.

For tank 1, the radius is given as 15 feet. Since it is a half-cylinder, we divide the volume by 2:

V1 = (1/2)π(15²)h = 353h cubic feet.

For tank 2, the height is given as 120 feet.

V2 = (1/2)π(15²)(120) = 31,416 cubic feet.

The maximum density is 0.000021142 killer whales per cubic foot

we can calculate the maximum number of killer whales as follows:

Number of killer whales = (Volume of main show tank) / (Density of killer whales)

Number of killer whales = 1,387,244 / 0.000021142 ≈ 65,606,197.

Therefore, the maximum number of killer whales allowed in the main show tank at any given time is 65,606,197

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The accounting equation is:

Assets (Rs. 1,75,000 - Rs. 35,000) = Liabilities (Rs. 45,000 + Rs. 5,000) + Capital (Rs. 20,000)

We have,

Based on the given transactions, we can prepare the accounting equation as follows:

a. Started business with Cash Rs. 250,000.

Assets: Cash = Rs. 250,000

b. Purchased goods amounting to Rs. 45,000 on credit from Harish.

Assets: Cash = Rs. 250,000, Inventory = Rs. 45,000

Liabilities: Accounts Payable = Rs. 45,000

c. Goods costing to Rs. 80,000 was sold for Rs. 1,25,000 on credit.

Assets: Cash = Rs. 250,000, Accounts Receivable = Rs. 1,25,000

Inventory: Rs. 45,000 - Rs. 80,000 = Rs. -35,000 (Assuming no additional purchases or returns)

Liabilities: Accounts Payable = Rs. 45,000

Capital: Retained Earnings = Rs. 1,25,000 - Rs. 80,000 = Rs. 45,000

d. Salaries outstanding Rs. 5,000.

Liabilities: Salaries Payable = Rs. 5,000

e. Rent paid Rs. 50,000.

Assets: Cash = Rs. 250,000 - Rs. 50,000 = Rs. 2,00,000

f. Withdrawn by owner for personal use Rs. 25,000.

Assets: Cash = Rs. 2,00,000 - Rs. 25,000 = Rs. 1,75,000

Capital: Retained Earnings = Rs. 45,000 - Rs. 25,000 = Rs. 20,000

Now, let's summarize the accounting equation:

Assets:

Cash = Rs. 1,75,000

Inventory = Rs. -35,000 (negative value indicates loss or returns)

Liabilities:

Accounts Payable = Rs. 45,000

Salaries Payable = Rs. 5,000

Capital:

Retained Earnings = Rs. 20,000

Therefore,

The accounting equation is:

Assets (Rs. 1,75,000 - Rs. 35,000) = Liabilities (Rs. 45,000 + Rs. 5,000) + Capital (Rs. 20,000)

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You will be able to withdraw $3,548.50 per month for 20 years if you have $400,000 saved for retirement and earn 10% interest.

To calculate the monthly withdrawals for a given time period, we can use the present value annuity formula. This formula allows us to calculate the fixed monthly withdrawal amount needed to deplete a given initial amount (in this case, $400,000) over a specified time period (20 years) at a given interest rate (10%).

The formula for present value annuity is:

PMT = PV * r / (1 - (1 + r)⁻ⁿ)

Where:

PMT = the fixed monthly withdrawal amount

PV = the present value of the initial investment ($400,000)

r = the interest rate per month (10%/12 = 0.00833)

n = the total number of monthly withdrawals (20 years * 12 months per year = 240)

Plugging in the values, we get:

PMT = 400,000 * 0.00833 / (1 - (1 + 0.00833)⁻²⁴⁰) = $3,548.50 (rounded to the nearest cent)

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The equation of the line in point-slope form, using the point (-2, -1), is: y + 1 = -2(x + 2)

The equation of a line in point-slope form is given by y - y₁ = m(x - x₁), where (x₁, y₁) represents a point on the line and m represents the slope.

Given:

Slope (m) = rise/run = -2

Point (-2, -1)

Substituting the given slope and point into the equation, we have:

y - (-1) = -2(x - (-2))

y + 1 = -2(x + 2)

Therefore, the equation of the line is: y + 1 = -2(x + 2).

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Answer:

GCF of 30 and 50 is 10 :}

The expression which gives the number of months passed in terms of p is √300 -0.5p

We make t the subject of the formula in the expression

p = 600 - 2t²

subtract 600 from both sides in other to isolate 2t²

p - 600 = 600 - 2t² - 600

p - 600 = -2t²

Rearrange the equation

2t² = 600 - p

Divide both sides by 2 in other to isolate t²

2t²/2 = 600/2 - p/2

t² = 300 - 0.5p

Take the Square root of both sides in other to isolate t

√t² = √300 - 0.5p

t = √300 - 0.5p

Hence, the correct expression which gives the number of months t in terms of price p is t = √300 - 0.5p

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Answer: b and c

Step-by-step explanation:

Answer:

The first question is 3 and the third question is the one with = 20

I have no answer for the second

The other answer left by farrelljacob646 is incorrect

The value of period of function is,

Period = 2

Since, A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

We have to given that;

The graph of function is shown in figure.

Since, The distance between the repetition of any function is called the period of the function.

And, For a trigonometric function, the length of one complete cycle is called a period.

Hence, By definition of period, we get;

The value of period of function is,

Period = 3 - 1

Period = 2

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(a) The given system of equation as an augmented matrix is [tex]\left[\begin{array}{cccc}1&3&0&150\\0&1&0&250\\-1&-1&1&400\end{array}\right][/tex];

(b) For the given augmented matrix, the system of equations is

-5x-6y-4z=400;

    y+z=100;

-3x-3y-2z=150;

A "system-of-equations" is a set of two or more equations which contain multiple variables. The solution to the system of equations is the set of values for the variables that satisfy all the equations in the system.

An "Augmented-Matrix" is a way to represent a system of linear equations in a concise and organized manner. It is obtained by writing the coefficients of the variables and the constants in each equation in a rectangular array, with each row representing an equation.

Part(a) : The system-of-equations is given as :

x  + 3r +0m = 150

0x + r + 0m = 250

-x - r + m = 400,

We see that the first column of the matrix will have 1, 0, -1,

the second-column will have 3, 1, -1 ;

the third-column will have 0, 0, 1.

So, the Augmented Matrix is represented as : [tex]\left[\begin{array}{cccc}1&3&0&150\\0&1&0&250\\-1&-1&1&400\end{array}\right][/tex].

Part(b) :

The augmented-matrix is given as : [tex]\left[\begin{array}{cccc}-5&-6&-4&400\\0&1&1&100\\-3&-3&-2&150\end{array}\right][/tex],

In this matrix, the terms in the "first-column" will be multiplied by variable"x";

the terms in the "second-column" will be multiplied by variable"y"; and

the terms in the "third-column" will be multiplied by variable"z";

The term sin the "fourth-column" represents the output value.

So, "system-of-equation" will be represented as : -5x - 6y - 4z = 400;

 0x + y + z = 100;

-3x - 3y - 2z = 150.

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There are no apparent solutions that satisfy both equations.

We have,

The system of equations is:

x² + 3x - 2 = 0

-x² + 2x + 4 = 0

To find the solutions, we can solve each equation separately:

x² + 3x - 2 = 0

This equation can be factored as:

(x + 2)(x - 1) = 0

Setting each factor equal to zero gives:

x + 2 = 0

x = -2

And,

x - 1 = 0

x = 1

-x² + 2x + 4 = 0

This equation does not factor easily, so we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

For this equation, a = -1, b = 2, and c = 4.

Plugging in the values into the quadratic formula:

x = (-2 ± √(2² - 4(-1)(4))) / (2(-1))

x = (-2 ± √(4 + 16)) / (-2)

x = (-2 ± √20) / (-2)

Simplifying further:

x = (-2 ± 2√5) / (-2)

x = 1 ± √5

Now,

let's check which of these solutions satisfies both equations:

For x = -2:

(-2)² + 3(-2) - 2 = 4 - 6 - 2 = -4 ≠ 0

-(-2)² + 2(-2) + 4 = -4 - 4 + 4 = -4 ≠ 0

x = -2 does not satisfy both equations.

For x = 1:

1² + 3(1) - 2 = 1 + 3 - 2 = 2 ≠ 0

-(1)² + 2(1) + 4 = -1 + 2 + 4 = 5 ≠ 0

x = 1 does not satisfy both equations.

For x = 1 ± √5:

We can substitute these values into the equations, but it can be seen that they will not satisfy both equations either.

Therefore,

There are no apparent solutions that satisfy both equations.

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Approximately 7 employees took a break longer than 49 minutes.

We have,

In a box-and-whisker plot, the box represents the interquartile range (IQR), which includes the middle 50% of the data.

The line within the box represents the median.

The "whiskers" extend to the minimum and maximum values, excluding any outliers.

Given the information provided:

Median = 41

Q1 = 37

Q3 = 49

Largest = 55

Smallest = 35

Since Q3 represents the upper quartile and corresponds to the boundary for the upper 25% of the data, we can conclude that 25% of the employees took a break longer than 49 minutes.

Now,

The number of employees who took a break longer than 49 minutes can be estimated by calculating 25% of the total number of employees:

25% of 27 employees

= (25/100) x 27

= 6.75

Since we cannot have a fractional number of employees, we round up to the nearest whole number.

Therefore,

Approximately 7 employees took a break longer than 49 minutes.

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Answer: 7,640

Step-by-step explanation: Because we know that she flew 2,299 the first year and 3,831 the second, we can add them together to get: 6,130. It says that she flew 1,510 more miles the third year than the first and second combined. Therefore: 6,130 + 1,510 = 7,640

Answer:

Step-by-step explanation:

1 = 20cm

2 = 0.56cm^2

3 = 77.5m2

Each number should be dragged to a box to complete the table as follows;

Kilometers     Meters

1                        1,000

2                       2,000

3                       3,000

5                       5,000

8                       8,000

In Science and Mathematics, a conversion factor is a number that is used to convert a number in one set of units to another, either by dividing or multiplying.

Generally speaking, there are one (1) kilometer in one thousand (1,000) meters. This ultimately implies that, a proportion or ratio for the conversion of kilometer to meters would be written as follows;

Conversion:

1 kilometer = 1,000 meters

2 kilometer = 2,000 meters

3 kilometer = 3,000 meters

4 kilometer = 4,000 meters

5 kilometer = 5,000 meters

6 kilometer = 6,000 meters

7 kilometer = 7,000 meters

8 kilometer = 8,000 meters

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Based on these data, the correct statement is B. The mean best describes the data.

The mean is one of the measures of central tendency.

The mean is also described as the average.

The average or mean is the quotient of the total data value divided by the number of data items.

Furniture Store Sofa Sales

January              255

February            234

March                 263

April                   229

May                    248

Total sales =   1,229

The number of months of sales = 5

Mean = 245.8 (1,229 ÷ 5)

Thus, using the mean, we can conclude that the average sales from Januar to May were 245.8.

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The following table displays the number of sofas sold in a furniture store during certain months of the year.

Furniture Store Sofa Sales

January 255

February 234

March 263

April 229

May 248

Based on these data, which statement is correct?

A. There are outliers.

B. The mean best describes the data.

C. The median best describes the data.

D. The measure of variability that best describes the data is the IQR, 27.5.

To completely solve the problem, Karim should convert the product back into standard decimal notation.

We cannot directly apply the product of powers property because the binomial is not raised to a power itself.

(1) To convert a number from scientific notation to standard decimal notation, we multiply the coefficient (0.0258) by 10 raised to the power of the exponent (-8).

0.0258 × [tex]10^{-8[/tex]  = 0.0258 × 0.00000001

                         = 0.000000000000258

(2) The product of powers property states that when you raise a term with an exponent to another exponent, you can simplify it by multiplying the exponents.

In the expression [tex](3z + y)^3[/tex], we have a binomial term (3z + y) raised to the power of 3. This is not a situation where we can directly apply the product of powers property because the binomial is not raised to a power itself.

To simplify the expression, we need to expand it using the binomial theorem or by applying the concept of binomial expansion.

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The image triangle △A'B'C' is formed by reflecting triangle ABC across the origin, resulting in each point's coordinates being negated.

The preimage triangle ABC undergoes a reflection across the x-axis followed by a reflection across the y-axis.

To determine the image triangle △A'B'C', we need to understand the effects of these transformations.

Reflection across the x-axis flips the points of the preimage vertically, while reflection across the y-axis flips the points horizontally.

When both reflections are applied successively, the resulting image will be a reflection across the origin (0,0).

Given that, the image triangle △A'B'C' will be the reflection of triangle ABC across the origin.

In this case, the x-coordinate and y-coordinate of each point in triangle ABC will be negated to obtain the corresponding point in △A'B'C'.

Let's consider the points of triangle ABC:

A(x₁, y₁), B(x₂, y₂), C(x₃, y₃)

To obtain the corresponding points in △A'B'C', we negate the x and y coordinates:

A'(-x₁, -y₁), B'(-x₂, -y₂), C'(-x₃, -y₃)

Therefore, the image triangle △A'B'C' is formed by reflecting triangle ABC across the origin, resulting in each point's coordinates being negated.

Note: It's important to note that without the actual coordinates of triangle ABC, it's not possible to determine the specific shape or size of the image triangle △A'B'C'.

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The equations and their graphs are:

Graph 4: I(x)=P(x)−4

Graph 2: I(x)=P(x+4)

Graph 1: I(x)=P(x)+4

Graph 3: I(x)=P(x−4)

Here we have,

to match the equations and their graphs:

The parent function is given as:

P(x) = x^2

As a general rule of function transformation, we have:

Vertical translation up: I(x) = P(x) + k

Vertical translation down: I(x) = P(x) - k

Horizontal translation left: I(x) = P(x + k)

Horizontal translation right : I(x) = P(x - k)

Using the above rules and the assumption that k is 4;

We have:

Vertical translation up: I(x) = P(x) + 4

Vertical translation down: I(x) = P(x) - 4

Horizontal translation left: I(x) = P(x + 4)

Horizontal translation right : I(x) = P(x - 4)

Hence, the graphs of the equations are:

Graph 4: I(x)=P(x)−4

Graph 2: I(x)=P(x+4)

Graph 1: I(x)=P(x)+4

Graph 3: I(x)=P(x−4)

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complete question;

Consider the function P(x)=x2, which is a parabola that opens upward, with a vertex at (0,0).

It undergoes four separate transformations as indicated by the graphs that follow.

P(x) represents the preimage and is placed correctly on all images. I(x) represents the image after the transformation.

Match each transformation indicated by I(x) to the correct graph.

Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.

I(x)=P(x)−4

I(x)=P(x+4)

I(x)=P(x)+4

I(x)=P(x−4)

For the transformations of the triangle, we have that:

1. The translation of triangle ABC preserves side lengths and angles.

2. The dilation of triangle ABC preserves angles but not side lengths.

Hence the correct options are, respectively, C and B.

A translation involves shift left, shift right, shift down, or shift up, meaning that just the coordinates of the figure change, not the angles or the side lengths,

1. The translation of triangle ABC preserves side lengths and angles.

For a dilation, the coordinates of the vertices are multiplied by a constant, hence the side lengths change while the angles remain constant, thus:

2. The dilation of triangle ABC preserves angles but not side lengths.

Hence the correct options are, respectively, C and B.

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John will have to pay $12.24 in interest at the end of the loan.

To calculate the amount of interest John will have to pay at the end of the loan, we can use the formula for simple interest:

Interest = Principal * Rate * Time

Given:

Principal (P) = $4,300.00

Rate (R) = 13.75% per annum

Time (T) = 8 days

First, we need to convert the rate from an annual percentage to a daily rate. Since there are 365 days in a year:

Daily Rate = (Rate / 100) / 365 = (13.75 / 100) / 365 = 0.0003767

Now we can calculate the interest:

Interest = Principal * Rate * Time

= $4,300.00 * 0.0003767 * 8

= $12.24

Therefore, John will have to pay $12.24 in interest at the end of the loan.

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Answer:

Step-by-step explanation:

1+3=4

4x4=16

10/2=5

16-5=11

answer is 11

The value of c in the polynomial is - 7.

The polynomial is given as follows:

p(x) = 2x³ - x² +  cx + 2 . The value of c if x - 2 is a factor of p(x) can be computed as follows:

Therefore,

p(x) = 2x³ - x² +  cx + 2

when x - 2 is a factor, p(x) = 0

Therefore,

0 = 2x³ - x² +  cx + 2

Hence,

2(2)³ - (2)² +  2c + 2 = 0

16 - 4 + 2c + 2 = 0

12 + 2 + 2c  = 0

2c = - 14

divide both sides by 2

c = - 14 / 2

c = - 7

Therefore,

c = -7

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The square root of y is not simplified and can be represented as:

y = √([tex]2^4 \times[/tex] 5) or y = 4√5.

To solve the proportion y/8 = 10/y for y, we can cross-multiply:

y [tex]\times[/tex] y = 8 [tex]\times[/tex]10

This simplifies to:

[tex]y^2[/tex] = 80

To solve for y, we can take the square root of both sides of the equation:

[tex]\sqrt{y^2[/tex] = √80

Since the square root of [tex]y^2[/tex] is simply y, we have:

y = √80

The square root of 80 can be further simplified by breaking it down into its prime factors. Since 80 can be expressed as 2 [tex]\times[/tex]2 [tex]\times[/tex]2 [tex]\times[/tex]2 [tex]\times[/tex]5, we can simplify the square root:

y = [tex]\sqrt(2 \times 2 \times 2 \times 2 \times 5)[/tex]

Therefore, the square root of y is not simplified and can be represented as:

y = [tex]\sqrt{(2^4 \times 5)[/tex] or y = 4√5.

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Answer:

[tex]y = \sqrt{80\\} =4\sqrt{5}[/tex]

Step-by-step explanation:

Answer:

ans d

Step-by-step explanation:

5 percent of 30 is 1.5 so d

The value of the y-intercept represent,

⇒  the amount of the account increases by each year.

We have to given that;

The graph shows an exponential function relating the balance in an investment account to the time in years.

Now, From graph we have;

The value of the y-intercept represent,

⇒  the amount of the account increases by each year.

Thus, value of the y-intercept represent,

⇒  the amount of the account increases by each year.

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a. Raina will have to pay a total of $2100 in interest.

b. The total repayment amount, including interest, will be $9100.

To calculate the total interest and total repayment amount, we can use the formula for simple interest:

Simple Interest = Principal * Rate * Time

(a) Total interest:

Principal = $7000

Rate = 6% per year

Time = 5 years

Total Interest = Principal * Rate * Time

= $7000 * 0.06 * 5

= $2100

(b) Total Repayment Amount = Principal + Total Interest

= $7000 + $2100

= $9100

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This is a basic arithmetic problem and the solution to 9.7/0.0268 is equal to  361.94

Basic Arithmetic Operations are fundamental to solving mathematical problems and they are addition (+), subtraction (-), multiplication (×) and division (÷).

1. Addition:

Addition is the process of combining two or more numbers to find their total or sum. The symbol used for addition is "+". For example, to add the numbers 3 and 5, you write it as:

3 + 5 = 8

Here, 3 and 5 are added together to get the sum, which is 8.

2. Subtraction:

Subtraction is the process of finding the difference between two numbers. The symbol used for subtraction is "-". For example, to subtract 5 from 8, you write it as:

8 - 5 = 3

Here, 5 is subtracted from 8 to get the difference, which is 3.

3. Multiplication:

Multiplication is the process of repeated addition or combining equal groups. The symbol used for multiplication is "×" or "*". For example, to multiply 4 and 6, you write it as:

4 × 6 = 24

Here, 4 is multiplied by 6 to get the product, which is 24.

4. Division:

Division is the process of dividing a number into equal parts or finding how many times one number is contained within another. The symbol used for division is "÷" or "/". For example, to divide 20 by 5, you write it as:

20 ÷ 5 = 4

Here, 20 is divided by 5 to get the quotient, which is 4.

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