Solve and graph the inequality.

−x4−6≥−8

Answer:

comparing both equations

-2x-1=3x+4

or, -1-4 =3x+2x

or, -5=5x

or, X= -1

Y= -2x-1

or, Y= -2(-1)-1

or, Y=1

hence, ( -1,1)

Answer:

2.28% of players are under 86kg

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weights of the players were distributed normally with a mean of 98kg and a standard deviation of 6kg.

This means that [tex]\mu = 98, \sigma = 6[/tex]

What percentage of players are under 86kg?

The proportion is the pvalue of Z when X = 86. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{86 - 98}{6}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.0228*100% = 2.28%

2.28% of players are under 86kg

Answer:

C.

Step-by-step explanation:

Given

[tex]A =(x_1,y_1)[/tex]

[tex]B =(x_2,y_2)[/tex]

[tex]C =(x_3,y_3)[/tex]

[tex]D =(x_4,y_4)[/tex]

Required:

Which condition proves that AB is perpendicular to CD

First, calculate the slopes of both.

For AB

[tex]m_1 = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

For CD

[tex]m_2 = \frac{y_4 -y_3}{x_4 - x_2}[/tex]

The condition of perpendicularity is:

[tex]m_1 * m_2 = -1[/tex]

Substitute values for m1 and m2

[tex]\frac{y_2 -y_1}{x_2 - x_1} * \frac{y_4 -y_3}{x_4 - x_2} = -1[/tex]

Option (c) is correct

Answer:

h = -25

Step-by-step explanation:

h - 5 = - 30

   +5     +5

h = -25

Answer:

∠QRT = 42°

Step-by-step explanation:

arc QT + 2(∠QPT = 2(42°) = 84°

arc QT = arc TQ

arc TQ = 2(∠QRT)

84° = 2(∠QRT)

∠QRT = 42°

Answer:

hey there

The answer is 7/10

this is true because we have two green marbles and five blue

2+5=7

Step-by-step explanation:

Answer:

20% or 2/10

Step-by-step explanation:

10 marbles in total. We want to find the probability of not picking a green marble. 10marbles-3red-5blue=2marbles left.

So the probability of picking a green marble is 2/10 or 20%

Answer:25

Step-by-step explanation:

Answer:

618

Step-by-step explanation:

They are added

Answer:

240 + 378 = 618

Step-by-step explanation:

an easy way to add big numbers s to break it up into smaller pieces.

Example:   240+378 = (200 + 300 = 500) + (40 + 70 = 110) + (0 + 8 = 8) = 618

Answer:

Step-by-step explanation:

∠1 = 180° - ∠2 - ∠3 = 38°

∠5 = ∠1 = 38°

Answer:

Step-by-step explanation:

Midpoint formula:

(x1 + x2)/2, (y1 + y2)/2

Substitute needed values.

4 + -8 = -4

-4/2 = -2

Now for the y's

-1 + 3 = 2

2/2 = 1

MIDPOINT: (-2,1)

Answer: -1/3

Step-by-step explanation: slope is the difference in the y values over the difference in the x values

Answer:

0.5

Step-by-step explanation:

Answer:

The minimum velocity of the particle  = [tex]-e^{-2 }[/tex] units

Step-by-step explanation:

Given - A particle moves along a horizontal line so that its position at time t,

t ≥ 0, is given by  s(t) = 40 + te^−t/20.

To find - Find the minimum velocity of the particle for 0 ≤ t ≤ 100.

Proof -

Velocity, v(t)  = [tex]\frac{d}{dt}(40 + te^{-\frac{t}{20} } )[/tex]

Now,

[tex]\frac{d}{dt}(40 + te^{-\frac{t}{20} } )[/tex] =  [tex]\frac{d}{dt}(40 ) + \frac{d}{dt}(te^{-\frac{t}{20} } )[/tex]

                       = 0 + [tex]t\frac{d}{dt}(e^{-\frac{t}{20} } ) + e^{-\frac{t}{20} }\frac{d}{dt}(t )[/tex]

                       = [tex]t(-\frac{1}{20} )e^{-\frac{t}{20} } + e^{-\frac{t}{20} }[/tex]

⇒v(t) = [tex]-\frac{t}{20}e^{-\frac{t}{20} } + e^{-\frac{t}{20} }[/tex]

Now,

For minimum velocity, Put [tex]\frac{d}{dt}(v(t)) = 0[/tex]

Now,

[tex]\frac{d}{dt}[v(t)] = \frac{d}{dt} [ -\frac{t}{20}e^{-\frac{t}{20} } + e^{-\frac{t}{20} } ][/tex]

           = [tex]-\frac{2}{20} e^{-\frac{t}{20} } + \frac{t}{400} e^{-\frac{t}{20} }[/tex]

Now,

Put [tex]\frac{d}{dt}(v(t)) = 0[/tex], we get

[tex]-\frac{2}{20} = - \frac{t}{400}[/tex]

⇒t = 40

Now,

Check that the point is minimum or maximum

Calculate  [tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex]

Now,

[tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex] = [tex]\frac{d}{dt} [ -\frac{2}{20} e^{-\frac{t}{20} } + \frac{t}{400} e^{-\frac{t}{20} }][/tex]

            = [tex]\frac{1}{400}e^{- \frac{t}{20} } [ 3 - \frac{t}{20}][/tex]

⇒[tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex]  = [tex]\frac{1}{400}e^{- \frac{t}{20} } [ 3 - \frac{t}{20}][/tex]  > 0

∴ we get

t = 40 is point of minimum

So,

The minimum velocity be

v(40) = [tex]-\frac{40}{20}e^{-\frac{40}{20} } + e^{-\frac{40}{20} }[/tex]

      = [tex]-2e^{-2 } + e^{-2 }[/tex]

      = [tex]-e^{-2 }[/tex]

⇒v(40) = [tex]-e^{-2 }[/tex] units

∴ we get

The minimum velocity of the particle  = [tex]-e^{-2 }[/tex] units

Answer:

7881.75

Step-by-step explanation:

10,170x0.775

Answer:

7881.75

Step-by-step explanation:

Answer:

a) 10

b) 3

c) 16

Step-by-step explanation:

Count the squares and the half ones match them with each other to get a full square... so so sorry if im wrong i did this a while ago! Currently Yr 9 x

Answer:

Its A

Step-by-step explanation:

ez

Answer:

A

Step-by-step explanation:

y= -3x + 7

Answer:

It's 15.

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Plug in m = 3 & n = 2 into the equation.

7(3) - 3(2)

21 - 6

15

Hope this helps & have a great rest of your day!

Answer:

[tex]1-8x-2x^2[/tex]

Step-by-step explanation:

(-4x^3-14x^2+10x-1)÷(2x-1)

Factor the expressions that are not already factored.

[tex]\frac{(2x-1)(2x^2-8x+1)}{2x-1}[/tex]

Cancel out 2x−1 in both numerator and denominator.

[tex]2x^2-8x+1[/tex]

Swap terms to the left side.

[tex]1-8x-2x^2[/tex]

Graph if needed:

Answer:

Option A, Left by 4 units

Step-by-step explanation:

Step 1:  Convert g(x) to a function square

We currently have g(x) in this order:  [tex]ax^2 + bx + c[/tex]

However, we want g(x) to be in this order:  [tex](ax + c)^{2}[/tex]

The first thing we have to do is to factor it out:

[tex]g(x)=x^{2}+8x+16[/tex]

[tex]g(x) = (x + 4)(x + 4)[/tex]

[tex]g(x) = (x+4)^{2}[/tex]

Step 2:  Now we can see which way we need to move it

The original form is:  [tex]f(x) = (ax - b)^{2}[/tex]

Since the - has changed to a +, that means that we moved -4 spaces down the x-axis.  This means that we move left by 4 units.

Answer:  Option A, Left by 4 units

Look at the graphs below to make sure:

Answer:

A.) Left By 4 Units

Step-by-step explanation:

Functions f(x) and g(x) are shown below: f(x) = x2 g(x) = x2 + 8x + 16

The direction in which and by how many units the f(x) should be shifted to obtain the g(x) is given by as follows.

Given,

f(x) = x²

g(x) = x² + 8x + 16

we have to consider, the dependent term while selecting the direction.

Therefore, except x², only x term is dependent term.

In g(x), the x term is given by 8.

Therefore, we need to shift the f(x) left by 4 units.

Therefore, option A is correct.

Answer:

D. Triangles A and C

Step-by-step explanation:

We can see whether the figures are congruent or not by checking out the similarity ratio

For triangle A and C the side lengths and angle measures are proportional so we can say that these two angles are congruent.

Answer:

0.1034 = 10.34% probability that the first student selected is an accounting major and the second student is a history major

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

14 account majors from a set of 29 students.

Then, 6 history majors from a set of 29 - 1 = 28 students.

So

[tex]p = \frac{14}{29}*\frac{6}{28} = \frac{14*6}{29*28} = 0.1034[/tex]

0.1034 = 10.34% probability that the first student selected is an accounting major and the second student is a history major

Answer:

73373773737477374747373738

9514 1404 393

Answer:

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

Answer:

You are correct

Step-by-step explanation:

Answer: yes, you are correct :)

Step-by-step explanation:

☁️ Answer ☁️

Inequality Form:

b < −2

❤️

Interval Notation:

(− ∞, −2)

Hope it helps.

Explanation: Have a nice day!~ ￣▽￣

Answer:

b < -2

Step-by-step explanation:

-3 (4b + 7) > 3

-12b -21 > 3

-12b > 3 + 21

-12b > 24

b < 24/-12

b < -2

Answer:

y=-16

Step-by-step explanation:

Answer:

y = -16

Step-by-step explanation:

−10y+4(3y−8)=−64

Step 1: Simplify both sides of the equation.

−10y+4(3y−8)=−64

−10y+(4)(3y)+(4)(−8)=−64(Distribute)

−10y+12y+−32=−64

(−10y+12y)+(−32)=−64(Combine Like Terms)

2y+−32=−64

2y−32=−64

Step 2: Add 32 to both sides.

2y−32+32=−64+32

2y=−32

Step 3: Divide both sides by 2.

2y

2

=

−32

2

y=−16

Answer:

y=−16

Answer:

D

D. license, permits, and stamp requirements

The type of information that determine the hunting regulations publication is option D.

The following information should be considered:

Learn more: brainly.com/question/16911495