Solve for x.


5.3 > x + 2/5


Responses


x < 5 7/10



x > 5 7/10



x < 4 9/10



x > 4 9/10

Answer:

The answer is below

Step-by-step explanation:

Select the correct answer from each drop-down menu. Simplify the given polynomial and use it to complete the statement.

(-5x² - 2x + 4) + (8x² - x - 1) + (x + 2)(x - 5)

.The polynomial simplifies to an expression that is a____

A.quadratic

B.liner

C.constany

A.trinomial

B.binomial

C.monomial

with a degree of____

A.1

B.2

C.0

Solution:

A polynomial is an expression involving operations of addition, subtraction, multiplication, exponents which consists of variables and their coefficient. A trinomial is a polynomial consisting of three terms, while a binomial consist of two terms and a monomial consist of one term.

The degree of a polynomial is the highest degree of any of the terms of the polynomial. If it has a degree of 0 it is a constant, a degree of 1 it is linear while for a degree of 2 it is quadratic.

(-5x² - 2x + 4) + (8x² - x - 1) + (x + 2)(x - 5)

= (-5x² - 2x + 4) + (8x² - x - 1) + (x² -5x + 2x - 10)

= (-5x² - 2x + 4) + (8x² - x - 1) + (x² - 3x - 10)

= (-5x² + 8x² + x² - 2x - x - 3x + 4 - 1 - 10)

= 4x² - 6x - 7

Therefore:

.The polynomial simplifies to an expression that is a quadratic trinomial of degree 2.

Answer:

sorry but don't know this answer

Answer:

-3x² -2y² -8xy +5y

34x² + 51xy - 8y + 6y²

7x² - 11xy +12y - 8y²

Step-by-step explanation:

Given:

A: 5x²+3xy +2y

B: 2y²-xy +4x²

С: 12xy+4x²-3y

Find:

1) А-В-С

2) 2A+3B+4C

3) 3A-4B--2C

Computation:

1) А-В-С

5x²+3xy +2y - [2y²-xy +4x²] - [12xy+4x²-3y]

5x²+3xy +2y -2y² +xy -4x² -12xy -4x²+3y

-3x² -2y² -8xy +5y

2) 2A+3B+4C

2[5x²+3xy +2y]+3[2y²-xy +4x²]+4[12xy+4x²-3y]

10x² + 6xy + 4y + 6y² - 3xy + 8x² + 48xy + 16x² - 12y

34x² + 51xy - 8y + 6y²

3) 3A-4B-2C

3[5x²+3xy +2y]-4[2y²-xy +4x²]-2[12xy+4x²-3y]

15x² + 9xy + 6y -8y² + 4xy - 16x² - 24xy - 8x² +6y

7x² - 11xy +12y - 8y²

probably it's 8 or 4. and as $8 is the initial fee, that sounds like the starting value. :-)

the line equation you need is the slope intercept form y = mx + b where m = gradient and b = y intercept.

in this case, y = 4x + 8 where x = number of movies seen, and y = total cost in $

for this line m = 4 and b = 8. hence, indeed, the y intercept is 8

Mark as brainlist

Answer:

Step-by-step explanation:

C is a piecewise function because it represents more than one type of deal.

Answer:

Step-by-step explanation:

(2-4x)+(2-4x)+(-2x+8)=12-10x

Answer:

Explicit

Step-by-step explanation:

Given

[tex]Term: a_{50[/tex]

Required

Explicit or Recursive; which is easier

The explicit form is easier.

Take for instance, the explicit form of the sequence is:

[tex]a_n = 2n + 1[/tex]

And the recursive form is:

[tex]a_n = a_{n-1} + 2[/tex]

To find [tex]a_{50}[/tex] in [tex]a_n = 2n + 1[/tex]

You simply substitute 50 for n and then solve for [tex]a_n[/tex]

Which gives:

[tex]a_{50} = 2*50 + 1 = 101[/tex]

The case is different in: [tex]a_n = a_{n-1} + 2[/tex]

First, you substitute 50 for n

[tex]a_{50} = a_{50-1} + 2[/tex]

[tex]a_{50} = a_{49} + 2[/tex]

Next, you need to calculate a49.

This action continues until you get to a1

Then you evaluate the corresponding expressions from a1 to a49 before you get a50.

Hence, the explicit form is easier.

Answer:

99.7%

Step-by-step explanation:

Given that:

sample size (n) = 655

sample mean ([tex]\overline x[/tex]) = 43.29

Standard deviation [tex]\sigma[/tex] = 2.75

Let's assume we are to estimate the percentage between $33.72 and $51.54

Then;

The test statistics at 33.72 is :

[tex]Z = \dfrac{X - \mu}{\sigma}[/tex]

[tex]Z = \dfrac{33.72 -43.29}{2.75}[/tex]

[tex]Z = -3.48[/tex]

Z at 51.54

[tex]Z = \dfrac{X - \mu}{\sigma}[/tex]

[tex]Z = \dfrac{51.54 -43.29}{2.75}[/tex]

[tex]Z = 3.00[/tex]

Using the empirical standard rule, the percentage will be 99.7%

Answer:

Step-by-step explanation:

the x is 30

60=2x

x=30

Answer:

d

Step-by-step explanation:

its d i think

Answer:

Question 1) 72

Question 2) 40

Question 3) Both C and D.

Question 4) Both A and C.

Step-by-step explanation:

Question 1)

We are given that:

[tex]\displaystyle \int_1^5f(x)\, dx=8\text{ and we want to find} \int_1^5xf'(x)\, dx[/tex]

We will use integration by parts, given by:

[tex]\displaystyle \int_a^b u\, dv=uv-\int_a^b v\, du[/tex]

We will let:

[tex]u=x\Rightarrow du=dx\text{ and } dv=f'(x)\, dx \Rightarrow v=f(x)[/tex]

Therefore:

[tex]\displaystyle \int_1^5xf'(x)\, dx=xf(x)\Big|_1^5-\int_1^5f(x)\, dx[/tex]

Substitute:

[tex]\displaystyle \int_1^5xf'(x)\, dx=(5(f(5))-(1(f(1))-(8)[/tex]

Evaluate:

[tex]\displaystyle \int_1^5xf'(x)\, dx=75-(-5)-8=72[/tex]

Question 2)

Similarly, we will let:

[tex]\displaystyle u=x\Rightarrow du=dx\text{ and } dv=f'(x)\, dx \text{ so } v=f(x)[/tex]

Hence:

[tex]\displaystyle \int_0^3 xf'(x)\, dx=xf(x)\Big|_0^3-\int_0^3f(x)\, dx[/tex]

Evaluate:

[tex]\displaystyle \int_0^3 xf'(x)\, dx=(3f(3))-(0(f(0))-(2)[/tex]

Thus:

[tex]\displaystyle \int_0^3 xf'(x)\, dx=3(14)-2=40[/tex]

Question 3)

We are given:

[tex]\displaystyle g(x)=\int_4^xf(x)\, dx[/tex]

By the Fundamental Theorem of Calculus:

[tex]g'(x)=f(x)>0[/tex]

The derivative of g is always positive. So, the values of g are always increasing.

The tables that reflect this are C and D.

And there are, as I understand it, no way to determine their exact values. Both C and D are correct.

Question 4)

Similarly, we are given:

[tex]\displaystyle g(x)=\int_{-2}^xf(x)\, dx[/tex]

By the FTC:

[tex]g'(x)=f(x)<0[/tex]

So, g should be decreasing for all x.

The tables that reflect this are A and C.

So, both A and C are correct.

Answer:

It b

Step-by-step explanation:

We know this because 1/2 is 0.5 while 2/3 is 0.67. With this we can say that 1/2 is least than 2/3

Hope this Helped

Answer:

8.1

Step-by-step explanation:

We denote the number as x.

6 * x = 48.6

We can divide both sides by 6 to get,

x = 8.1

Answer:

8.1

Step-by-step explanation:

Let the unknown number be n.  Translating this statement into symbols, we get:

6n = 48.6

Solving for n by dividing both sides by 6, we get  n = 8.1

The number is 8.1

Answer:

Area = 5542.488 unit^2

Circumference= 263.9 units

Step-by-step explanation:=

Given data

Radius= 42 units

Circumference= 2πr

C= 2*3.142*42

C=263.9 units

Area= πr^2

A= 3.142* 42^2

A= 3.142* 1764

A= 5542.488 unit^2

Answer:

1/12

Step-by-step explanation:

Answer:

Step-by-step explanation:

1301/100 is the correct answer

Answer:

35

Step-by-step explanation:

Answer: 2.71 packs

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

4 squared, which is the same thing as 4 times 4, is 16.

[tex]4^2=16[/tex]  or [tex]4 * 4 = 16[/tex]

you can check your answer by finding the square root of 16.

[tex]\sqrt{16}=4[/tex]

i hope this helps! have a nice day <3

Answer:

12/6-1/6=11/6 simplified to 1 5/6

Step-by-step explanation:

to make this easier make sure all fractions have the same denominator 6/3x2/2=12/6 since they now have the same denominator add 12/6+-1/6=11/6

adding a negative(6/3+-1/6) is the same as subtracting a positive(6/3-1/6)

Answer:

1 5/6

hope this helps :)........

Answer:

1) 5 2)7 3)18 4) 14

Step-by-step explanation:

Answer:

The answer is 1 and 4

Step-by-step explanation:

.25 x 4y = Y

36 divided by 4 = 9

Answer:

B 4456448444424346464646464664646464

Answer:

1.02

Step-by-step explanation:

Answer:

3.764

Step-by-step explanation:

Answer:

4 3/4 yards

Step-by-step explanation:

5 1/4 + 2 1/2 = 7 3/4

(1/2 is equal to 2/4)

12 1/2 - 7 3/4 = 4 3/4

Hope this helps, mark me brainliest if it does! :)

Answer:

[tex]4\frac{3}{4} [/tex]

Jotted Solution:

Answer:

Use mathcway its 2 ez with that page trust me bro

Step-by-step explanation:

No cap

5 10 okey espero te sirva

Answer:

130

Step-by-step explanation:

Answer:

what grade is this ?

Step-by-step explanation:

Answer:

[tex] \bold{ \red{{y}^{2} + 7y - 8 = 0}}[/tex]

Step-by-step explanation:

[tex] {(3x + 2)}^{2} + 7 {(3x + 2)} - 8 = 0 \\ \\ plug \: (3x + 2 )= y \\ \\ so \: above \: quadratic \: equation \: \\transforms \: to \\ \\ \bold{ \red{{y}^{2} + 7y - 8 = 0}}[/tex]