Submit the worksheet with your constructions to your teacher to be graded

Answers

Answer 1

However, to give you an idea of what you should include in the worksheet, I can tell you that it depends on the instructions that your teacher gave you. Here are some possible steps that you can follow:

Step 1: Follow the instructions provided by your teacher.If your teacher provided you with specific instructions on how to construct the worksheet, then follow them carefully.

This may include the format of the worksheet, the length of the responses, and the type of information that you need to include. Make sure to read the instructions carefully before you start constructing the worksheet.

Step 2: Include all necessary informationIn general, a worksheet should include all the relevant information that is needed to complete a task or to answer a question.

If you are constructing a worksheet for a math problem, for example, make sure to include all the necessary data and formulas that are needed to solve the problem.

If you are constructing a worksheet for a reading assignment, make sure to include all the necessary information about the text that you read.

Step 3: Check for accuracy and completeness Once you have finished constructing the worksheet, make sure to check it for accuracy and completeness.

This means checking that all the necessary information is included, and that there are no errors or omissions. Double-check your calculations and your spelling and grammar.

Step 4: Submit the worksheet to your teacherOnce you are satisfied with the accuracy and completeness of your worksheet, submit it to your teacher for grading.

Make sure to follow any specific submission instructions that your teacher has provided, such as the file format or the deadline for submission.

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Related Questions

Determine the (x, y) coordinates of the vertex of the parabola that represents each of the following functions:​

Answers

The vertices of the parabolae are:

(h, k) = (- 3, - 1)(h, k) = (1, - 9)(h, k) = (4, 1)(h, k) = (3/4, 9/4)(h, k) = (- 3, 2)(h, k) = (0, 36)(h, k) = (7/2, 9/4)(h, k) = (5, - 1)(h, k) = (1, - 3)(h, k) = (- 1/2, 1)

How to find the coordinates of the vertex of a parabola

Parabolae are represented by quadratic equations. In this problem we have parabolae in standard form and we need to determine its vertex form to find the needed information. Now we summarize the forms of quadratic equations:

Standard form

y = a · x² + b · x + c     (1)

Vertex form

y - k = C · (x - h)²     (2)

Please notice that (x, y) = (h, k) represents the vertex of the parabola.

To change quadratic equations from standard form into vertex form we need to apply algebraic handling:

y = x² + 6 · x + 8

y + 1 = x² + 6 · x + 9

y + 1 = (x + 3)²

(h, k) = (- 3, - 1)

y = x² - 2 · x - 8

y + 9 = x² - 2 · x + 1

y + 9 = (x - 1)²

(h, k) = (1, - 9)

y = - x² + 8 · x - 15

y = - 1 · (x² - 8 · x + 15)

y - 1 = - 1 · (x² - 8 · x + 16)

y - 1 = - 1 · (x - 4)²

(h, k) = (4, 1)

y = - 4 · x² + 6 · x

y = - 4 · [x² - (3/2) · x]

y + (- 4) · (9/16) = - 4 · [x² - (3/2) · x + 9/16]

y - 9/4 = - 4 · (x - 3/4)²

(h, k) = (3/4, 9/4)

y = x² + 6 · x + 11

y - 2 = x² + 6 · x + 9

y - 2 = (x + 3)²

(h, k) = (- 3, 2)

y = - x² + 36

y - 36 = - x²

(h, k) = (0, 36)

y = - x² + 7 · x - 10

y = - (x² - 7 · x + 10)

y + (- 1) · (9/4) = - (x² - 7 · x + 49/4)

y - 9/4 = - (x - 7/2)²

(h, k) = (7/2, 9/4)

y = x² - 10 · x + 24

y + 1 = x² - 10 · x + 25

y + 1 = (x - 5)²

(h, k) = (5, - 1)

y = 2 · x² - 4 · x - 1

y = 2 · (x² - 2 · x - 1/2)

y + 2 · (3/2) = 2 · (x² - 2 · x + 1)

y + 3 = 2 · (x - 1)²

(h, k) = (1, - 3)

y = - 4 · x² - 2 · x

y = - 4 · [x² + (1/2) · x]

y + (- 4) · (1/4) = - 4 · [x² + (1/2) · x + 1/4]

y - 1 = - 4 · (x + 1/2)²

(h, k) = (- 1/2, 1)

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CAN SOMEONE SHOW ME HOW TO DO THIS PLEASE!

3.5 ft If the ADA guidelines state that a wheelchair ramps angle of elevation must equal 4.8°, would a ramp with the following dimensions be up to code? Show your work and explain. (Picture is
not drawn to scale.)
40 ft
Ꮎ°

Answers

Answer:

∠α = 5.001°

a easy calculator for this is:

https://www.calculator.net/right-triangle-calculator.html?av=3.5&alphav=&alphaunit=d&bv=40&betav=&betaunit=d&cv=&hv=&areav=&perimeterv=&x=57&y=16

In a survey of 300 college graduates, 46% reported that they entered a profession closely related to their college major. If 9 of those survey subjects are randomly selected without replacement for a follow-up survey, what is the probability that 3 of them entered a profession closely related to their college major

Answers

Probability is 17.5% that 3 of them entered a profession closely related to their college

According to the statement

we have given that survey of 300 college graduates, 46% reported that they entered a profession closely and

We know that  For each college graduate, there are only two possible outcomes. Either they have entered a profession closely related to their college major, or they have not. The probability of a college graduate having entered a profession closely related to their college major is independent of other college graduates, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

This is P(X = 3) when n = 8. and the value of p is 0.46 put the value in the binomial formula then the outcome of answer will 17.5%

So, Probability is 17.5% that 3 of them entered a profession closely related to their college

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Select the correct answer. Which function has a domain of all real numbers?
y = -x + 5 y = -2(3x) ³ O A. B. OC. y = CD. y = (x + 2)² (2x) ³ (2x) - 7​

Answers

The function that has a domain of all real numbers is:

A. [tex]y = 2x^{\frac{1}{3}} - 7[/tex].

What is the domain of a function?

The domain of a function is the set that contains all possible input values for the function.

If a function has an even root, equivalent to an exponent of [tex]\frac{1}{n}[/tex] with n even, the domain is only positive values, while if the exponent is odd, the domain is all real values.

Researching the problem on the internet, the function with odd exponent is:

A. [tex]y = 2x^{\frac{1}{3}} - 7[/tex].

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F(x)= x(x+3)(x+1)(x-4) has zeros at x=-3

Answers

Answer:  C) Sometimes positive; sometimes negative

============================================================

Explanation:

Pick a value between x = -1 and x = 0. Let's say we go for x = -0.5

Plug this into f(x)

f(x) = x(x+3)(x+1)(x-4)

f(-0.5) = -0.5(-0.5+3)(-0.5+1)(-0.5-4)

f(-0.5) = -0.5(2.5)(0.5)(-4.5)

f(-0.5) = 2.8125

We get a positive value.

This shows that f(x) is positive on the region of -1 < x < 0

----------------

Now pick a value between x = 0 and x = 4. I'll use x = 1

f(x) = x(x+3)(x+1)(x-4)

f(1) = 1(1+3)(1+1)(1-4)

f(1) = 1(4)(2)(-3)

f(1) = -24

Therefore, f(x) is negative on the interval 0 < x < 4

----------------

In short, f(x) is both positive and negative on the interval -1 < x < 4

It's positive when -1 < x < 0

And it's negative when 0 < x < 4

Answer:

sometimes positive sometimes negative

Step-by-step explanation:

I did it on Khan Academy

Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline)

Answers

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

How to determine the notation

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

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Answer:

A

Step-by-step explanation:

Find the difference. Express the answer in scientific notation.

(5.29 times 10 Superscript 11 Baseline) minus (3.86 times 10 Superscript 11 Baseline)

1.43 times 10 Superscript 11

9.15 times 10 Superscript 11

1.43 times 10 Superscript 22

9.15 times 10 Superscript 22

Ellen has a bag with 3 red marbles and 2 blue marbles in it. she is going to randomly draw a marble from the bag 300 times, putting the marble back in the bag after each draw. how many times do you predict that the marble picked will be blue using the theoretical probability?

Answers

The blue marble is predicted to be picked 120 times, in the experiment of picking a marble from a bag containing 3 red and 2 blue marbles and performing this experiment 300 times, using the theoretical probability.

The theoretical probability of any event is the ratio of the number of favorable outcomes to the event, to the total number of possible outcomes in the experiment.

If we have an event A, the number of favorable outcomes to event A as n, and the total number of possible outcomes in the experiment as S, then the theoretical probability of event A is given as:

P(A) = n/S.

In the question, we are given that Ellen has a bag with 3 red marbles and 2 blue marbles in it. She is going to randomly draw a marble from the bag 300 times, putting the marble back in the bag after each draw.

We are asked the predict the number of times that the marble picked will be blue using the theoretical probability.

Let the event of picking a blue marble be A.

The number of favorable outcomes to event A (n) = 2 {The total number of blue marbles in the bag}.

The total number of possible outcomes in the experiment of picking a ball (S) = 5 {The total number of marbles in the bag}.

Thus, the theoretical probability of event A is,

P(A) = n/S = 2/5 = 0.4.

To predict the number of times marble picked was blue, we multiply the time's the experiment was performed by the theoretical probability of picking a blue ball.

Thus, the predicted number of times = 300 * 0.4 = 120.

Thus, the blue marble is predicted to be picked 120 times, in the experiment of picking a marble from a bag containing 3 red and 2 blue marbles and performing this experiment 300 times, using the theoretical probability.

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an equation for loudness, in decibles, is L=10log10 R where R is the relative intensity of the sound. Sounds that reach levels of 120 decibles or more are painful to humans what is the relative intensity of 120 decibles

Answers

Considering the logarithmic loudness equation, the relative intensity of 120 decibels is of [tex]R = 10^{12}[/tex].

What is the logarithmic loudness equation?

The equation is:

[tex]L = 10\log{R}[/tex]

In which:

L is the loudness, in decibels.R is the relative intensity.

For this problem, we have that L = 120, hence the relative intensity is found as follows:

[tex]120 = 10\log{R}[/tex]

[tex]\log{R} = 12[/tex]

[tex]R = 10^{12}[/tex]

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At the DVD rental store, Jamie found 6 DVDs that she wanted, but can only rent 4. How many possible choices can she make

Answers

At the DVD rental store, Jamie found 6 DVDs that she wanted, but can only rent 4. Jamie can make 15 possible choices, as per combinations of DVDs.

Number of Possible Combinations:

Given Information is as follows,

Total number of DVDs that Jamie wanted, n = 6

Number of DVDs Jamie can rent at a  time, x =4

The Combinations formula is given as,

ⁿCₓ = n! / (n-x)! x!

Here, n = 6 and x = 4

Substituting these values of n and x in the Combinations formula, we get,

⁶C₄ = 6! / (6-4)! 4!

⁶C₄ = 6! / 2! 4!

⁶C₄ = 6×5×4! / 2! 4!

⁶C₄ = 6×5 / 2

⁶C₄ = 3×5

⁶C₄ = 15

Thus, Jamie can make 15 possible combinations of DVDs.

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find the equation of the straight line with ng gradient and points. b) - 1/2, (2,3)​

Answers

Answer:

[tex]y = -\frac{1}{2} x+4[/tex]

Step-by-step explanation:

Standard form for equation of line: y = mx + c

where m = gradient or slope

c = y-intercept

From the question we know that,

x = 2

y = 3

m = - 0.5

We will substitute these values into the equation to find c.

3 = (-0.5)(2) + c

3 = - 1 + c

c = 3 + 1 = 4

Therefore the equation of this line is [tex]y = -\frac{1}{2} x+4[/tex]

A sculpture is formed from a square-based pyramid resting on a cuboid. The base of the cuboid and the base of the pyramid are both squares of side 3 cm. The height of the cuboid is 8 cm and the total height of the sculpture is 15 cm. The total mass of the sculpture is 738 g. The cuboid-part of the sculpture is made of iron with density 7.8 g/cm³. The pyramid is made from copper. Calculate the density, in g/cm³, of the copper.​

Answers

Answer:

7.8g/cm

Step-by-step explanation:

help i’ll give brainliest!

Answers

F would be 1. G would be 4. E would be negative 3

Solve kx-2=7 for x. A. x=5/k B. x=9k C. x=9-k D. x=9/k ​

Answers

Answer:

the answer is D- 9/k

Answer:

D- 9/k

Step-by-step explanation:

Look at the pic and show your work

Answers

We kindly invite to check the image attached below to see the representation of the exponential function. This function shows exponential growth.

How to graph exponential functions

In this occasion we must plot the graph of exponential functions of the form:

y = a · bˣ     (1)

Where:

a - Initial valueb - Base of the functionx - Independent valuey - Dependent value

First, we need to follow this procedure to create the graph of the curve on Cartesian plane:

Evaluate the function at every x-value.Fill the blanks on table.Mark the rectangular points (x, y) on the Cartesian plane.Match the points.

Therefore, we build the exponential curve with the help of a graphing tool (i.e. Desmos), whose result is shown in the image attached below.

From (1) we must understand that exponential functions report growth for b > 1 and decay for 0 < b < 1. Thus, the exponential function y = 3ˣ shows exponential growth according to graphical and analytical findings.

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the graph of the derivative of a function f crosses the x-axis 3 times. what does this tell you about the graph of f

Answers

Answer:

  the graph of f has 3 turning points

Step-by-step explanation:

The graph of a function has a turning point (local extreme) where the derivative is zero and changes sign.

Derivative

The derivative of a function tells you the slope of that function's graph. When the derivative is positive, the function is increasing. When the derivative is negative, the function is decreasing.

Turning Point

Where the derivative changes sign from positive to negative, the graph of the function changes direction from increasing to decreasing. At the point where the derivative is zero (between positive and negative), the graph is neither increasing nor decreasing. A tangent to the function at that point is a horizontal line, and the function itself is at a local maximum, a turning point.

The reverse is also true. When the derivative changes sign from negative to positive, the function changes from decreasing to increasing. The turning point where that occurs is a local minimum.

3 Crossings

If the derivative crosses the x-axis (changes sign) 3 times, then there are three local extremes in the graph of f. The graph of f has 3 turning points.

__

Additional comment

In the attached graph, we have constructed a derivative function (red) that crosses the x-axis 3 times. It is the derivative of f(x), which is shown in blue. The purpose is to show the local extremes of f(x) match the zero crossings of the derivative.

Simplify b^10/b^2

A. b^5

B. b^-5

C. b^8

D. b^-8

Answers

Answer:

C.  b^8.

Step-by-step explanation:

b^10/b^2     We subtract the exponents:-

= b^(10-2)

= b^8.

b^8

Step-by-step explanation:

b^10/b^2 ,. b^10-2 ;. b^8

Simplify: 2n (n^2 + 3n + 4)

Answers

Answer:

2n^3 + 6n^2 + 8n

Answer: It's 2n^3 + 6n^2 + 8n

Step-by-step explanation:

Quadrilateral A'B'C'D' is the result of rotating quadrilateral ABCD by 60 about
the origin
y
0
Select all of the correct statements about the unchanged properties of quadrilateral
ABCD and quadrilateral A'B'C'D.
Choose all answers that apply.
O
B
3 4/5 6
BC and BC are both parallel to the y-axis
2B and B' have the same measures.
D and D' have the same coordinates.
None of the above
Activate

Answers

Answer: B

Step-by-step explanation:

A) False. Rotations do not preserve parallelism.

B) True. Rotations are rigid motions and thus preserve angle measure.

C) False. A rotation that changes the location of every point except for the center of rotation.

Find the area of the region defined by the region defined by the inequality 2|x| + 3|y-1| ≤ 6

Answers

If [tex]x[/tex] and [tex]y-1[/tex] have the same sign, then either

[tex]x>0,y>1 \implies 2|x| + 3|y-1| = 2x + 3(y-1)=6 \implies 2x + 3y = 9[/tex]

or

[tex]x<0,y<1 \implies 2|x| + 3|y-1| = -2x - 3(y-1) = 6 \implies 2x + 3y = -3[/tex]

If [tex]x[/tex] and [tex]y-1[/tex] have opposite sign, then

[tex]x>0,y<1 \implies 2|x| + 3|y-1| = 2x - 3(y-1) = 6 \implies 2x -3y = 3[/tex]

or

[tex]x<0,y>1 \implies 2|x| + 3|y-1| = -2x + 3(y-1) = 6 \implies 2x-3y = -9[/tex]

This is to say that the region has boundaries given by these two sets of parallel lines, so we can equivalently describe the region with the set

[tex]R = \left\{(x,y) \mid -3\le2x+3y\le9 \text{ and } -9\le2x-3y\le3\right\}[/tex]

The area of [tex]R[/tex] is given by the double integral

[tex]\displaystyle \iint_R dx\,dy[/tex]

To compute the area, change the variables to

[tex]\begin{cases}u = 2x + 3y \\ v = 2x - 3y\end{cases} \implies \begin{cases}x = \frac14(u+v) \\ y = \frac16(u-v)\end{cases}[/tex]

The Jacobian for this transformation is

[tex]J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix}1/4 & 1/4 \\ 1/6 & -1/6\end{bmatrix}[/tex]

with determinant [tex]\det(J) = -\frac1{12}[/tex]. Then the integral transforms to

[tex]\displaystyle \iint_R dx\,dy = \iint_R |J| \, du \, dv = \frac1{12} \int_{-3}^9 \int_{-9}^3 dv\, du[/tex]

which is 1/12 the area of a square with side length 12. Hence the integral evaluates to

[tex]\displaystyle \iint_R dx\,dy = \frac1{12}\times12^2 = \boxed{12}[/tex].

Determine the number of terms in the sequence: –45, –32, –19, –6, ..., 124.

Answers

Step-by-step explanation:

[tex] - 32 + 45 = 13 \\ t_{n} = ( a_{1} + (n - 1)d) \\ \\ d = 13 \: \: a_{1} = - 45[/tex]

[tex] t_{n} = - 45 + (n - 1)13 = = = > \\ - 45 + 13n - 13 = = = > \\ t_{n} = 13n - 58[/tex]

and now

[tex]124 = 13n - 58 = = = > \\ 182 = 13n = = = > n = 14[/tex]

The number of terms in the sequence: –45, –32, –19, –6, ..., 124 = 9.

The common difference is -45 - (-32)= 13

                                                  d = 13.

What is arithmetic progress?

AP is a sequence of numbers in order, in which the difference among any two consecutive numbers is a constant cost. it's also referred to as mathematics series.

using arithmetic progress:-

last term = (n-1)d

first term(a) = –45

    term = a + (n-1)d

there is a difference of 13, so the sequence will be

–45, –32, –19, –6,7, 20, 33, 46, 59, 72, 85, 98, 111, 124.

∴ number of terms = 9

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a pot contains 5 black beads and 7 white beads.another pot contain 6 white beads. if one beads is drawn from each pot without looking, what will be the probability of getting atleast one white beads?​

Answers

Step-by-step explanation:

is there something missing in the question ?

or is this meant to be a trick question ?

let me repeat :

pot1 contains 5 black and 7 white beads

pot2 contains 6 white beads (and nothing else, right ?)

then one bead is drawn from each pot.

so, 1 bead from pot1, and 1 bead from pot2.

the bead from pot1 is either white or black.

the bead from pot2 is white for sure.

so, the probability to get at least 1 white bead is 100% or 1, as there will be always the white bead taken from pot2.

The ratio of two numbers is 2/3, and their sum is 535. One of the numbers is:

(Select one)

A. 242

B. 321

C. 667

D. 408

Answers

The answer is D

Step-by-step:

X is one of these two numbers and the other is 2/3X
Sum=X+2/3x=5/3x=535
So X=535*3/5=321

One of the numbers would be 321. Hence option B is true.

Used the concept of the Number system that states,

A writing system used to express numbers is known as a number system. It is the mathematical notation used to consistently express the numbers in a particular set using digits or other symbols.

Given that,

The ratio of the two numbers is 2/3, and their sum is 535.

Let us assume that,

The two numbers are x and y.

Hence we have;

[tex]\dfrac{x}{y} = \dfrac{2}{3}[/tex]  .. (i)

And, [tex]x + y = 535[/tex]   .. (ii)

From equation (i);

[tex]\dfrac{x}{y} = \dfrac{2}{3}[/tex]

[tex]x = \dfrac{2y}{3}[/tex]

Substitute the above value of x in (ii);

[tex]x + y = 535[/tex]

[tex]\dfrac{2y}{3} + y = 535[/tex]

[tex]2y + 3y = 535 \times 3[/tex]

[tex]5y = 1605[/tex]

[tex]y = 321[/tex]

From equation (i);

[tex]x = \dfrac{2y}{3}[/tex]

[tex]x = \dfrac{2\times 321}{3}[/tex]

[tex]x = 214[/tex]

Therefore, the number is 321. So option B is true.

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If x =2 y=3 z=4 solve the following

x² + y²

Answers

Answer:

13

Step-by-step explanation:

Given x = 2, y = 3 and z = 4. We'll evaluate the value of x² + y² with given condition.

First, remind that we are only given the expression of x-term and y-term only and therefore, z-term is not included - it's not to be considered.

Substitute x = 2 and y = 3 in the expression:

[tex]\displaystyle{2^2+3^2 = 4+9}\\\\\displaystyle{4+9 = 13}[/tex]

Hence, the value of x² + y² when x = 2 and y = 3 is 13.

Please let me know if you have any questions!

Solve the system of equations.
2x+y = 7
x - 2y = 6
Put your answer as a coordinate point, or use "no solution" or "infinitely many solutions"(aka "the set of all real numbers").​

Answers

Answer:

Ans: (4,-1)

Step-by-step explanation:

Lets keep:

2x+y=7 --- equation 1

x - 2y=6 ----- equation 2

equation 2 x 2: 2x - 4y=12 -------equation 3

now subtract equation 1 from equation 3

  2x - 4y = 12

(-) 2x + y = 7

----> -5y = 5 [ Divide both sides by -5 ]

------> y= -1

Substitute y= -1 into eqaution 1

----> 2x + -1 = 7 [ add 1 to both side]

----> 2x = 8 [Divide by 2 on both sids]

----> x=4

Ans: (4,-1)

Show your steps in evaluating each of the following expressions. The steps count 4 points each, the answer is 1

Answers

The steps in evaluating each of the following expressions is shown below.

What is an expression?

An expression is a mathematical equation which shows the relationship that exist between two or more numerical quantities or variables.

How to evaluate the given expressions?

15 - 35/7 - 2 + 3 - 4

15 - (35/7) - 2 + 3 - 4 (bracket and division)

15 - 5 - 2 + 3 - 4 (regroup)

15 + 3 - 5 - 2 - 4 (subtract and add)

18 - 11 = 7.

Expression 2.

10 + 2(9 - 5) - 16/18

10 + (2 × 4) - 8/9 (bracket and division)

10 + 8 - 8/9 (add)

18 - 8/9 (subtract)

162/9 - 8/9 = 17 1/9 or 154/9.

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Complete Question:

Show your steps in evaluating each of the following expressions. The steps count 4 points each, the answer is 1 point.

A. 15 - 35/7 -2 + 3 -4

B. 10 + 2(9 - 5) - 16/18

In Circle P, chord AB measures 4x - 6 centimeters and chord CD measures 6x - 12
centimeters. If Segment AB and Segment CD are each 4 centimeters from P, find AP.

Answers

Answer:

5 cm

Step-by-step explanation:

When two chords are equidistant from the center of the circle, the two chords have equal length. Therefore, the length of chord AB, 4x - 6, is equal to the length of chord CD, 6x - 12.

4x - 6 = 6x - 12

6 = 2x

x = 3

Now that we know x = 3, we can substitute the value back into the original expression, 4x - 6, to find the length of chord AB.

AB = 4x - 6 = 4*3 - 6 = 12 - 6 = 6 cm

When measuring the distance between a line and a point, we create a segment through the point perpendicular to the line. In Geometry, we also learn that the perpendicular bisector of a chord in a circle contains the center of the circle.

In this case, the gray line perpendicularly bisects segment AB. PX is 4 cm long and AX is 3 cm long (because AX is half the length of AB). Notice that triangle AXP is a right triangle, so we can use Pythagorean Theorem to find AP.

[tex]AP^{2} = AX^{2} +PX^{2}[/tex]

[tex]AP = \sqrt{3^{2} +4^{2} }[/tex]

[tex]AP =\sqrt{9+16}[/tex]

[tex]AP = \sqrt{25}[/tex]

[tex]AP = 5[/tex]

Instructions: Find the missing segment in the image below.

Answers

Answer: 7

Step-by-step explanation:

By the triangle proportionality theorem,

[tex]\frac{?}{21}=\frac{3}{9}\\\\?=7[/tex]

find the exact value of sin (x-y) if sinx=4/9 and siny=1/4

Answers

Answer:

sin(x - y) = 0.21

Step-by-step explanation:

we have the sin values which we need to get cos values

sin (A-B) = sin A cos B - sin B cos A

sin² A + cos² A = 1

sin x = 4/9

cos² x = 1 - sin² x = 1 - 16/81 = 65/81

cos² x = 65/81

cos x = √65/9

sin y = 1/4

cos² y = 1 - sin² y = 1 - 1/16 = 15/16

cos² y = 15/16

cos y = √15/4

sin(x − y) = sin x cos y - sin y cos x

sin(x - y) = 4/9 √15/4 - 1/4 √65/9

sin(x - y) = (4√15-√65)/36

sin(x - y) = 0.21

socratic Narad T

Answer: C

Step-by-step explanation:

on edg

Which quadratic function is in standard
form?

Answers

Answer:

  h(x) = 2x² -8x -10

Step-by-step explanation:

In the US, a quadratic is in standard form when the terms are listed in order of decreasing degree.

In the UK, a quadratic is in standard form when it is written in vertex form.

__

US

The only function with terms in order of decreasing degree is ...

  h(x) = 2x² -8x -10

UK

All of the functions except the last are written in vertex form:

f(x) = (x +1)² +0 . . . . . . . . would usually be written f(x) = (x +1)²y(x) = -(x -6)² +16g(x) = -3(x -3)² +4

__

Additional comment

Since the question asks about one function, we assume it is from the perspective of the US understanding of standard form. The point here is that "standard form" may vary from one tradition to another. (The "standard form" for numerical values varies by tradition, as well.)

The number 321.8 is 34% of x. What is the value of x rounded to the nearest whole number?

Answers

Answer:

946

Step-by-step explanation:

Let's make an equation :

34% of x = 321.8

Covert 34% into decimal by dividing by 100 :

34 ÷ 100 = 0.34

Rewrite equation with decimal form :

0.34x = 321.8

Divide both sides by x to make x the subject :

x = 321.8 ÷0.34

x = 946.470588235

To the nearest whole number will be 946 as 4 rounds it down

So our final answer will be 946

Hope this helped and have a good day

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{34}{100} \sdot x = 321.8[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{(321.8) \sdot(100)}{34} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 946.47[/tex]

Round off to nearest whole number :

[tex]\qquad \sf  \dashrightarrow \: x = 946[/tex]

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