suppose a vector y is orthogonal to vectors u and v. prove or give a counter example that y is orthogonal to the vector u v.

Answers

Answer 1

The vector y is orthogonal to the vector u v.

Is it true that the vector y is orthogonal to the vector u v?

Since y is orthogonal to both u and v, it implies that the dot product of y with each of u and v is zero. Let's denote the dot product as y · u and y · v, respectively.

Now, we need to determine if y is orthogonal to the vector u v, which is the sum of u and v. To prove this, we need to show that the dot product of y with u v is also zero, that is, y · (u v) = 0.

To verify this, we can expand the dot product y · (u v) using the distributive property: y · (u v) = y · u + y · v.

Since y is orthogonal to both u and v, we know that y · u = 0 and y · v = 0. Therefore, y · (u v) = 0 + 0 = 0.

The result y · (u v) = 0 confirms that the vector y is orthogonal to the vector u v, which is the sum of u and v.

Therefore, the statement holds true, and the vector y is indeed orthogonal to the vector u v.

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Related Questions

Instructions: Find the missing segment in the image below.

Answers

Answer: 7

Step-by-step explanation:

By the triangle proportionality theorem,

[tex]\frac{?}{21}=\frac{3}{9}\\\\?=7[/tex]


2. Rotate the following points 180°.

a.) B(-2,-5) →B'( )
b.) B(-4,1) B'( )

c.) In the graphs above connect the pre-image point B to the origin. Then connect
the origin to the image point B. What angle has been formed?

Answers

Answer:

hi helo bol ke gatu jama gol ke

The ratio of two numbers is 2/3, and their sum is 535. One of the numbers is:

(Select one)

A. 242

B. 321

C. 667

D. 408

Answers

The answer is D

Step-by-step:

X is one of these two numbers and the other is 2/3X
Sum=X+2/3x=5/3x=535
So X=535*3/5=321

One of the numbers would be 321. Hence option B is true.

Used the concept of the Number system that states,

A writing system used to express numbers is known as a number system. It is the mathematical notation used to consistently express the numbers in a particular set using digits or other symbols.

Given that,

The ratio of the two numbers is 2/3, and their sum is 535.

Let us assume that,

The two numbers are x and y.

Hence we have;

[tex]\dfrac{x}{y} = \dfrac{2}{3}[/tex]  .. (i)

And, [tex]x + y = 535[/tex]   .. (ii)

From equation (i);

[tex]\dfrac{x}{y} = \dfrac{2}{3}[/tex]

[tex]x = \dfrac{2y}{3}[/tex]

Substitute the above value of x in (ii);

[tex]x + y = 535[/tex]

[tex]\dfrac{2y}{3} + y = 535[/tex]

[tex]2y + 3y = 535 \times 3[/tex]

[tex]5y = 1605[/tex]

[tex]y = 321[/tex]

From equation (i);

[tex]x = \dfrac{2y}{3}[/tex]

[tex]x = \dfrac{2\times 321}{3}[/tex]

[tex]x = 214[/tex]

Therefore, the number is 321. So option B is true.

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the graph of the derivative of a function f crosses the x-axis 3 times. what does this tell you about the graph of f

Answers

Answer:

  the graph of f has 3 turning points

Step-by-step explanation:

The graph of a function has a turning point (local extreme) where the derivative is zero and changes sign.

Derivative

The derivative of a function tells you the slope of that function's graph. When the derivative is positive, the function is increasing. When the derivative is negative, the function is decreasing.

Turning Point

Where the derivative changes sign from positive to negative, the graph of the function changes direction from increasing to decreasing. At the point where the derivative is zero (between positive and negative), the graph is neither increasing nor decreasing. A tangent to the function at that point is a horizontal line, and the function itself is at a local maximum, a turning point.

The reverse is also true. When the derivative changes sign from negative to positive, the function changes from decreasing to increasing. The turning point where that occurs is a local minimum.

3 Crossings

If the derivative crosses the x-axis (changes sign) 3 times, then there are three local extremes in the graph of f. The graph of f has 3 turning points.

__

Additional comment

In the attached graph, we have constructed a derivative function (red) that crosses the x-axis 3 times. It is the derivative of f(x), which is shown in blue. The purpose is to show the local extremes of f(x) match the zero crossings of the derivative.

An account pays 8% per year simple interest. in year 1, the amount in the account is $850. how much is in the account in year 6?

Answers

Answer:

Step-by-step explanation:

$1,248.92

(14x2 + 13x + 12) + (7x2 + 20x + 4)

Answers

Answer:

21x^2 + 33x + 16

Step-by-step explanation:

(14x^2 + 13x + 12) + (7x^2 + 20x + 4)

Combine like terms:

14x^2 + 7x^2 = 21x^2

13x + 20x = 33x

12 + 4 = 16

Thus:

21x^2 + 33x + 16

Answer:

21x^2 + 33x + 16.

Step-by-step explanation:

(14x2 + 13x + 12) + (7x2 + 20x + 4)   Remove the parentheses:

= 14x2 + 13x + 12 + 7x2 + 20x + 4    Bring like terms togethher:

= 14x^2 + 7x^2 + 13x + 20x + 12 + 4

= 21x^2 + 33x + 16.

F(x)= x(x+3)(x+1)(x-4) has zeros at x=-3

Answers

Answer:  C) Sometimes positive; sometimes negative

============================================================

Explanation:

Pick a value between x = -1 and x = 0. Let's say we go for x = -0.5

Plug this into f(x)

f(x) = x(x+3)(x+1)(x-4)

f(-0.5) = -0.5(-0.5+3)(-0.5+1)(-0.5-4)

f(-0.5) = -0.5(2.5)(0.5)(-4.5)

f(-0.5) = 2.8125

We get a positive value.

This shows that f(x) is positive on the region of -1 < x < 0

----------------

Now pick a value between x = 0 and x = 4. I'll use x = 1

f(x) = x(x+3)(x+1)(x-4)

f(1) = 1(1+3)(1+1)(1-4)

f(1) = 1(4)(2)(-3)

f(1) = -24

Therefore, f(x) is negative on the interval 0 < x < 4

----------------

In short, f(x) is both positive and negative on the interval -1 < x < 4

It's positive when -1 < x < 0

And it's negative when 0 < x < 4

Answer:

sometimes positive sometimes negative

Step-by-step explanation:

I did it on Khan Academy

find the exact value of sin (x-y) if sinx=4/9 and siny=1/4

Answers

Answer:

sin(x - y) = 0.21

Step-by-step explanation:

we have the sin values which we need to get cos values

sin (A-B) = sin A cos B - sin B cos A

sin² A + cos² A = 1

sin x = 4/9

cos² x = 1 - sin² x = 1 - 16/81 = 65/81

cos² x = 65/81

cos x = √65/9

sin y = 1/4

cos² y = 1 - sin² y = 1 - 1/16 = 15/16

cos² y = 15/16

cos y = √15/4

sin(x − y) = sin x cos y - sin y cos x

sin(x - y) = 4/9 √15/4 - 1/4 √65/9

sin(x - y) = (4√15-√65)/36

sin(x - y) = 0.21

socratic Narad T

Answer: C

Step-by-step explanation:

on edg

an equation for loudness, in decibles, is L=10log10 R where R is the relative intensity of the sound. Sounds that reach levels of 120 decibles or more are painful to humans what is the relative intensity of 120 decibles

Answers

Considering the logarithmic loudness equation, the relative intensity of 120 decibels is of [tex]R = 10^{12}[/tex].

What is the logarithmic loudness equation?

The equation is:

[tex]L = 10\log{R}[/tex]

In which:

L is the loudness, in decibels.R is the relative intensity.

For this problem, we have that L = 120, hence the relative intensity is found as follows:

[tex]120 = 10\log{R}[/tex]

[tex]\log{R} = 12[/tex]

[tex]R = 10^{12}[/tex]

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Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline)

Answers

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

How to determine the notation

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

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Answer:

A

Step-by-step explanation:

Find the difference. Express the answer in scientific notation.

(5.29 times 10 Superscript 11 Baseline) minus (3.86 times 10 Superscript 11 Baseline)

1.43 times 10 Superscript 11

9.15 times 10 Superscript 11

1.43 times 10 Superscript 22

9.15 times 10 Superscript 22

Speedy Swift is a package delivery service that serves the greater Atlanta, Georgia, metropolitan area. To maintain customer loyalty, one of Speedy Swift's performance objectives is on-time delivery. To monitor its performance, each delivery is measured on the following scale: early (package delivered before the promised time), on-time (package delivered within 15 minutes of the promised time), late (package delivered more than 15 minutes past the promised time), or lost (package never delivered). Speedy Swift's objective is to deliver 99% of all packages either early or on-time.
Speedy collected the following data for last month's performance:
On-time On-time Early Late On-time On-time On-time On-time Late On-time
Early On-time On-time Early On-time On-time On-time On-time On-time On-time
Early On-time Early On-time On-time On-time Early On-time On-time On-time
Early On-time On-time Early Early Early On-time Loss On-time Early
Late Late Late On-time On-time On-time On-time On-time On-time On-time
On-time Late Early On-time Early On-time Lost On-time On-time On-time
Early Early On-time On-time Late Early Early On-time On-time On-time
On-time On-time Early On-time Early On-time Early On-time Late On-time
On-time Early On-time On-time On-time Late On-time Lost On-time On-time
On-time On-time On-time On-time On-time Early Early On-time On-time On-time
(a) What scale is used to measure delivery performance? What kind of variable is delivery performance?
(b) Construct a frequency table for delivery performance for last month.
(c) Construct a relative frequency table for delivery performance last month.

Answers

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table is a table showing frequency of each variable for the number of times they appear in the data.

The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency for a variable is the ratio of its frequency to the total frequency.

The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

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Answer:

C.

Step-by-step explanation:

there are three red marbles 5 green marbles 2 blue marbles in a bag which of the follwing are true

Answers

Answer:

4 and 1

Step-by-step explanation:

Find the area of the region defined by the region defined by the inequality 2|x| + 3|y-1| ≤ 6

Answers

If [tex]x[/tex] and [tex]y-1[/tex] have the same sign, then either

[tex]x>0,y>1 \implies 2|x| + 3|y-1| = 2x + 3(y-1)=6 \implies 2x + 3y = 9[/tex]

or

[tex]x<0,y<1 \implies 2|x| + 3|y-1| = -2x - 3(y-1) = 6 \implies 2x + 3y = -3[/tex]

If [tex]x[/tex] and [tex]y-1[/tex] have opposite sign, then

[tex]x>0,y<1 \implies 2|x| + 3|y-1| = 2x - 3(y-1) = 6 \implies 2x -3y = 3[/tex]

or

[tex]x<0,y>1 \implies 2|x| + 3|y-1| = -2x + 3(y-1) = 6 \implies 2x-3y = -9[/tex]

This is to say that the region has boundaries given by these two sets of parallel lines, so we can equivalently describe the region with the set

[tex]R = \left\{(x,y) \mid -3\le2x+3y\le9 \text{ and } -9\le2x-3y\le3\right\}[/tex]

The area of [tex]R[/tex] is given by the double integral

[tex]\displaystyle \iint_R dx\,dy[/tex]

To compute the area, change the variables to

[tex]\begin{cases}u = 2x + 3y \\ v = 2x - 3y\end{cases} \implies \begin{cases}x = \frac14(u+v) \\ y = \frac16(u-v)\end{cases}[/tex]

The Jacobian for this transformation is

[tex]J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix}1/4 & 1/4 \\ 1/6 & -1/6\end{bmatrix}[/tex]

with determinant [tex]\det(J) = -\frac1{12}[/tex]. Then the integral transforms to

[tex]\displaystyle \iint_R dx\,dy = \iint_R |J| \, du \, dv = \frac1{12} \int_{-3}^9 \int_{-9}^3 dv\, du[/tex]

which is 1/12 the area of a square with side length 12. Hence the integral evaluates to

[tex]\displaystyle \iint_R dx\,dy = \frac1{12}\times12^2 = \boxed{12}[/tex].

What three-dimensional object would be generated by the rotation of the semi circle about the x axis ?

Answers

If a semicircle is rotated about the x axis of the graph then the resulting three dimensional shape will be a sphere.

Given a semicircle on a graph.

A semicircle is a half circle .A sphere is a geometrical object that is a three dimensional  shape , It is the set of points that are all at the same distance r from given point in three dimensional shape.

Rotation is basically an action of rotating around an object or an axis.

If a semicircle is rotated about x axis then the resulting figure will be a sphere. This is because of the fact that when the semi circle is rotated about the x axis then all the points will be at equal distance in all directions from the center.

Hence if a semicircle is rotated about x axis then the resulting figure will be a sphere.

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how do you graph y=12/x

Answers

Answer: [tex]\frac{12}{x}[/tex] is an asymptote

Step-by-step explanation:

Apply a table, and plug in values of x into the equation.  For example f(2)=[tex]\frac{12}{2} =6[/tex]. That's one of the points on the graph that we just found (2,6)

the number 40 cannot be decomposed into prime factors

True
either
False​

Answers

[tex]\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\large{\textsf{\textbf{\underline{\underline{Answer : \:}}}}}}[/tex]

False, because the number 40 is a composite number, those that cannot be broken down are called Prime Numbers.

Prime numbers are numbers that are used to decompose any number, but prime numbers cannot be decomposed, since they only have two Divisors, which are 1 and itself.

[tex]~\sf{Atte: Murdock:)}[/tex]

Answer: False

Step-by-step explanation:

All whole numbers can be decomposed into prime factors. For the number 40, the prime factorization would be [tex]2 * 2 * 2*5[/tex]. Since all 4 of those numbers are prime numbers, the answer is false.

Solve the system of equations.
2x+y = 7
x - 2y = 6
Put your answer as a coordinate point, or use "no solution" or "infinitely many solutions"(aka "the set of all real numbers").​

Answers

Answer:

Ans: (4,-1)

Step-by-step explanation:

Lets keep:

2x+y=7 --- equation 1

x - 2y=6 ----- equation 2

equation 2 x 2: 2x - 4y=12 -------equation 3

now subtract equation 1 from equation 3

  2x - 4y = 12

(-) 2x + y = 7

----> -5y = 5 [ Divide both sides by -5 ]

------> y= -1

Substitute y= -1 into eqaution 1

----> 2x + -1 = 7 [ add 1 to both side]

----> 2x = 8 [Divide by 2 on both sids]

----> x=4

Ans: (4,-1)

(4x⁴-4x²-x-3) ÷ (2x²-3)


so far i have 2x²+1+?/2x²-3
what is the question mark? ​

Answers

Answer:

[tex]2x^2+1-\dfrac{x}{2x^2-3}[/tex]

Step-by-step explanation:

Use the long division method to divide polynomials:

[tex]\large \begin{array}{r}2x^2\phantom{)))))}+1\phantom{)}\\2x^2-3{\overline{\smash{\big)}\,4x^4-4x^2-x-3\phantom{)}}}\\\underline{-~\phantom{(}(4x^4-6x^2)\phantom{-b))))))}}\\0+2x^2-x-3\phantom{)}\\\underline{-~\phantom{()}(2x^2\phantom{))))}-3)}\\-x\phantom{))))))}\end{array}[/tex]

Therefore:

[tex]\dfrac{4x^4-4x^2-x-3}{2x^2-3}=2x^2+1-\dfrac{x}{2x^2-3}[/tex]

The area of a sector of a circle of radius 8cm is 45cm². Find the size of the angle subtended at the centre of the circle, correct to one decimal place. (Take π = 22/7)

Answers

Try redo this question on your own incase I may have mistake.. tq

The size of the angle subtended at the center of the circle is θ = 80.5397°

What is the Area of the Sector?

In circles, a sector is said to be a part of a circle made of the arc of the circle together with its two radii. This means that it is a portion of the circle formed by a portion of the circumference (arc) and radii of the circle at both endpoints of the arc.

The formula for Area of a sector is given as;

A = θ/360 x πr²

where;

θ is the central angle of the sector

r is radius

Given data ,

The area of a sector of a circle of radius 8cm is 45cm²

On simplifying , we get

A = θ/360 x πr²

45 = θ/360 ( 22/7 ) ( 8 )²

45 = ( θ/360 ) ( 201.1428 )

Divide by 201.1428 on both sides , we get

( θ/360 ) = 0.22372159

Multiply by 360 on both sides , we get

θ = 80.5397

Hence , the angle is θ = 80.5397°

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The number 321.8 is 34% of x. What is the value of x rounded to the nearest whole number?

Answers

Answer:

946

Step-by-step explanation:

Let's make an equation :

34% of x = 321.8

Covert 34% into decimal by dividing by 100 :

34 ÷ 100 = 0.34

Rewrite equation with decimal form :

0.34x = 321.8

Divide both sides by x to make x the subject :

x = 321.8 ÷0.34

x = 946.470588235

To the nearest whole number will be 946 as 4 rounds it down

So our final answer will be 946

Hope this helped and have a good day

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{34}{100} \sdot x = 321.8[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{(321.8) \sdot(100)}{34} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 946.47[/tex]

Round off to nearest whole number :

[tex]\qquad \sf  \dashrightarrow \: x = 946[/tex]

In a survey of 300 college graduates, 46% reported that they entered a profession closely related to their college major. If 9 of those survey subjects are randomly selected without replacement for a follow-up survey, what is the probability that 3 of them entered a profession closely related to their college major

Answers

Probability is 17.5% that 3 of them entered a profession closely related to their college

According to the statement

we have given that survey of 300 college graduates, 46% reported that they entered a profession closely and

We know that  For each college graduate, there are only two possible outcomes. Either they have entered a profession closely related to their college major, or they have not. The probability of a college graduate having entered a profession closely related to their college major is independent of other college graduates, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

This is P(X = 3) when n = 8. and the value of p is 0.46 put the value in the binomial formula then the outcome of answer will 17.5%

So, Probability is 17.5% that 3 of them entered a profession closely related to their college

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Calculate the first difference between 7, and where 7,-688. 2​

Answers

The difference between the numbers given is 6.882.

How to illustrate the information?

Based on the information given, it should be noted that difference means subtraction.

The difference between the numbers given will be:

= 7 - (7 - 6.882)

= 7 - 0.118

= 6.882

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Someone help me please

Answers

Answer:

2√10

Step-by-step explanation:

We can use the Pythagorean theorem to solve this because it is a right triangle. a^2+b^2 = c^2

7^2-3^2 = x^2

49-9 = x^2

40 = x^2

√4*√10 = 2√10

Quadrilateral A'B'C'D' is the result of rotating quadrilateral ABCD by 60 about
the origin
y
0
Select all of the correct statements about the unchanged properties of quadrilateral
ABCD and quadrilateral A'B'C'D.
Choose all answers that apply.
O
B
3 4/5 6
BC and BC are both parallel to the y-axis
2B and B' have the same measures.
D and D' have the same coordinates.
None of the above
Activate

Answers

Answer: B

Step-by-step explanation:

A) False. Rotations do not preserve parallelism.

B) True. Rotations are rigid motions and thus preserve angle measure.

C) False. A rotation that changes the location of every point except for the center of rotation.

Please help with this

Answers

Answer:

the answer is 8

Step-by-step explanation:

thats what i got

CAN SOMEONE SHOW ME HOW TO DO THIS PLEASE!

3.5 ft If the ADA guidelines state that a wheelchair ramps angle of elevation must equal 4.8°, would a ramp with the following dimensions be up to code? Show your work and explain. (Picture is
not drawn to scale.)
40 ft
Ꮎ°

Answers

Answer:

∠α = 5.001°

a easy calculator for this is:

https://www.calculator.net/right-triangle-calculator.html?av=3.5&alphav=&alphaunit=d&bv=40&betav=&betaunit=d&cv=&hv=&areav=&perimeterv=&x=57&y=16

determine the fall (drop) on 20' of drainage piping with a 1/4" per ft. grade

Answers

The Fall (drop)  of drainage piping is: A. 5".

Fall (drop) of drainage piping

In order to determine the fall (drop) of drainage piping we would need to multiply the drainage piping by the inch per feet.

Hence:

Using this formula

Fall (drop) of drainage piping = Drainage piping× inch per feet

Where:

Drainage piping=20

Inch per feet=1/4"

Let plug in the formula

Fall (drop) of drainage piping =20×1/4"

Fall (drop) of drainage piping =5"

Therefore the correct option is A. 5".

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In a math class of $30$ students, $12$ out of $15$ girls are freshmen and $11$ out of $15$ boys are freshmen. What is the probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys

Answers

The probability of selecting five students from the class, where there will be two freshmen girls and three freshmen boys is 0.23 approximately.

What is Probability ?

Probability is the game of chance. Probability of an event is the ratio of the required outcome to the total possible outcome.

Given that In a math class of 30 students, 12 out of 15 girls are freshmen and 11 out of 15 boys are freshmen. In Probability, the word "and" means multiplication

The probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys can be expressed as follow

12/15 x 11/14 x 11/15 x 10/14 x 9/13

132/210 x 990/2730

130680/573300

0.2279

Therefore, the probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys is 0.23 approximately.

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ا سکول کے پرنسپل کے نام سکول میں ہم نصابی سرگرمیوں کا اہتمام کرنے کی درخواست ھیے ۔

Answers

Answer:

Step-by-step explanation:

a pot contains 5 black beads and 7 white beads.another pot contain 6 white beads. if one beads is drawn from each pot without looking, what will be the probability of getting atleast one white beads?​

Answers

Step-by-step explanation:

is there something missing in the question ?

or is this meant to be a trick question ?

let me repeat :

pot1 contains 5 black and 7 white beads

pot2 contains 6 white beads (and nothing else, right ?)

then one bead is drawn from each pot.

so, 1 bead from pot1, and 1 bead from pot2.

the bead from pot1 is either white or black.

the bead from pot2 is white for sure.

so, the probability to get at least 1 white bead is 100% or 1, as there will be always the white bead taken from pot2.

Other Questions
(x-2)(x+3)=(x-2)(4-x) Calculate the minute ventilation for the 5mm tube and then for the 3 mm tube. What effect does decreasing tube radius have on resistance and minute ventilation? Read Article A.In 1925, there was an outbreak of disease in the small Alaskan town of Nome. The people needed medicine, but there were no roads, and the harsh weather made it impossible for a plane to reach them. The only way to get medicine to Nome was by dogsled. Twenty teams of dogs, each with a handler, or musher, braved dangerous conditions to bring the medicine from Nenana, Alaska, along the Iditarod Trail to Nome.The first team to set out was led by a dog named Togo. Togo was a small, black and white husky who had spent most of his life pulling sleds. When he was a puppy, his owner, Leonhard Seppala, never thought he would be a good sled dog. Togo was smaller than most dogs on the team. He was ill when he was very young, and at six months old, he was given away to be a house pet. 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