Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\bullet$ $P(-3)

When Ava purchased six packages of tulip bulbs and twelve bags of daffodil bulbs, the price per tulip bulb was $7 and the price each daffodil bulb was $13.

The algebraic equation y=mx+b is known as a linear equation. M serves as the y-intercept, and B serves as the slope. The previous clause has two variables, y and x, and is sometimes referred to as a "linear equation with two variables". Bivariate linear equations are those with two independent variables. The following are a few examples of system of equations: 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. When an equation takes the form y=mx+b, with m denoting the slope and b denoting the y-intercept, it is referred to as being linear. The term "linear" refers to an equation having the form y=mx+b, where m stands for the slope and b for the y-intercept.

given

Let x be the price of a single tulip bag.

Y should equal the price of one bag of daffodil bulbs.

Grace = 14x + 12y = 254

ava = 6x + 12y = 198

- 8x = - 56

x = - 56/-8

x = 7.

Equation 1 becomes

6* 7 + 12y = 198

42 + 12y = 198 when x = 7 is substituted.

12y = 198 - 42

12y = 156

y = 156/12

y = 13

When Ava purchased six packages of tulip bulbs and twelve bags of daffodil bulbs, the price per tulip bulb was $7 and the price each daffodil bulb was $13.

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2a+b=15.7 is the formula used to get the base's length and b has a value of 3.

Therefore, an isosceles triangle has two equal sides as well as two equal angles. The Greek words iso (same) and Skelos are the source of the name (leg). An equilateral triangle is one in which all of its sides are equal, whereas a scalene triangle is one in which none of its sides are equal.

An isosceles triangle has 2 equal sides that are longer than the length of the base

perimiter=15.7

equation is 2a+b=15.7

so if the longer side is 6.3

we know that identical sides are bigger so 6.3 is one of the identical sides

2a means the 2 identical sides

2(6.3) + b = 15.7

12.6 + b = 15.7

subtract 12.6 from both sides

b = 3.1

therefore, The equation used to find the length of the base is 2a+b=15.7

and the value of b is 3.1

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Answer:

12.6 + b = 15.7

The brand-name television's measurements are 32 inches by 64 inches, so answer (C) is accurate.

Given: The generic version was created based on the brand name and was three eighths the size of the brand name.

12 inches by 24 inches is the size of the standard television set.

Allowing for x by y as the brand name's measurements

12 inches divided by three eighths

8/3 x = 12

x = 12 * 8 / 3 = 32 inch

and y=3/8 inches equals 24 inches

8/3 y = 24

y = 24 * 8 / 3 = 64 inch

As a result, the brand-name television has the following measurements: 32 by 64 inches.

Therefore, choice (C) is the appropriate response.

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The complete question is: Jason considered two similar televisions at a local electronics store. The generic version was based on the brand name and was  the size of the brand name. If the generic television set is 12 inches by 24 inches, what are the dimensions of the brand name television?

a) 7.5 inches by 15 inches

b) 28 inches by 56 inches

c) 32 inches by 64 inches

d) 4.5 inches by 9 inches

The score of Larry is 32 points.

Two algebraic expressions having same value and symbol '=' in between are called as an equation.

Given:

Ervin scores half as many points in a game as Larry.

If Larry scored x points,

then the points of Ervin are x/2 points.

Here, x = 16,

So,

Ervin's points = Larry's points

The equation is,

16 = x/2

x = 16(2)

x = 32 points

Therefore, 32 points are the score of Larry.

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The volume of air present in the room is 27410.7075 lt .

The space occupied inside an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.

Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied inside an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.

The capacity occupied by a three-dimensional solid shape is known as volume. It is difficult to imagine in any shape, yet it may be compared amongst shapes. For instance, a compass box has a larger volume than an eraser placed inside of it. We split the area into equal square units to get the area of any two-dimensional form. Similar to this, we shall split the volume of solid objects into equal cubical units while calculating it. In the part after this one, let's examine how to determine the volume of various solid forms.

The dimension of the room is 11*11*8 in feet.

so, 11 ft = 11 *2.54*12 = 335.28 cm

And, 8 ft = 8 *2.54*12 = 243.84 cm

Volume of the room is = 335.28 * 335.28 * 243.84 = 27410707.5 [tex]cm\x^{3}[/tex]

In litre,

27410707.5 [tex]cm\x^{3}[/tex] = 27410707.5/1000 = 27410.7075 lt.

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The equation of the linear function after a translation down 9 units is given as follows:

f(x) = x - 11.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which:

The graph of the function crosses the y-axis at y = -2, hence the intercept b is given as follows:

b = -2.

When x increases by 2 units, from x = 0 to x = 2, y increases by 2 units, from y = -2 to y = 0, hence the slope is calculated as follows:

m = 2/2.

Then the function is of:

y = x - 2.

After the translation down 9 units, 9 is subtracted from the function, hence:

f(x) = x - 2 - 9

f(x) = x - 11.

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Point P lies on the diagonal AC of square ABCD with AP > CP. Let [tex]$O_1$[/tex] and [tex]$O_2$[/tex] be the circumcenters of [tex]$\triangle \mathrm{ABP}$[/tex] and [tex]$\triangle \mathrm{CDP}$[/tex] respectively. Given that AB = 12 and [tex]$\angle \mathrm{O}_1 \mathrm{PO}_2=120^{\circ}$[/tex], then [tex]$\mathrm{AP}=\sqrt{\mathrm{a}}+\sqrt{\mathrm{b}}$[/tex],

where a and b are positive integers.

The value of a + b is 96.

Let mid-point of DC be E and mid-point of AB be F.

Since [tex]$\mathrm{O}_1$[/tex] and [tex]$\mathrm{O}_2$[/tex] are circumcenters, therefore both lie on the perpendicular bisectors of DC and AB passing through E and F.

Now, [tex]$\mathrm{O}_1 \mathrm{P}=\mathrm{O}_1 \mathrm{~B}$[/tex] and [tex]$\mathrm{O}_2 \mathrm{P}=\mathrm{O}_2 \mathrm{D}$[/tex]

Also [tex]$\angle \mathrm{CAB}=\angle \mathrm{ACD}=45^{\circ}$[/tex]

Therefore [tex]\angle \mathrm{BO}_1 \mathrm{P}=2 \times 45^{\circ}=90^{\circ}=\angle \mathrm{DO}_2 \mathrm{P}$[/tex]

Angle subtended by an arc of a circle at its center = 2 × the angle subtended at its circumference

Therefore [tex]\angle \mathrm{O}_1 \mathrm{~PB}$[/tex] and [tex]$\angle \mathrm{O}_2 \mathrm{PD}$[/tex] are isosceles right triangles.

Using the above information and symmetry,

[tex]$\angle \mathrm{DPB}=120^{\circ}$[/tex]

Also, [tex]$\triangle[/tex]ABP is congruent to [tex]$\triangle[/tex]ADP (SAS)

and [tex]$\triangle[/tex]CPB is congruent to [tex]$\triangle[/tex]CPD (SAS)

Therefore [tex]\angle \mathrm{APB}=\angle \mathrm{APD}=60^{\circ}[/tex]

And [tex]\angle \mathrm{CPB}=\angle \mathrm{CPD}=120^{\circ}[/tex]

Now, [tex]$\angle \mathrm{ABP}=(180-60-45)^{\circ}=75^{\circ}$[/tex]

[tex]\Rightarrow \angle \mathrm{O}_1 \mathrm{BF}=30^{\circ}[/tex]

And [tex]$\angle \mathrm{PDC}=(180-120-45)^{\circ}=15^{\circ}$[/tex]

[tex]\Rightarrow \angle \mathrm{O}_2 \mathrm{DE}=30^{\circ}[/tex]

Therefore [tex]\triangle \mathrm{O}_1 \mathrm{BF}$[/tex] and [tex]$\triangle \mathrm{O}_2 \mathrm{DE}$[/tex] are right angled triangles.

BF = DE = [tex]\frac{12}{2}[/tex] = 6

[tex]\Rightarrow O_1 B=O_2 D=4 \sqrt{3}[/tex]

And  PB = PD = [tex]\frac{4 \sqrt{3}}{\cos 45^{\circ}}=4 \sqrt{6}[/tex]

Now, Let x = AP

Using law of cosine on [tex]$\triangle[/tex]ABP, we have

[tex]& 96=x^2+144-24 x \times \frac{1}{\sqrt{2}} \\[/tex]

[tex]& \Rightarrow x^2-12 \sqrt{2} x+48=0 \\[/tex]

[tex]& \Rightarrow x=\sqrt{72} \pm \sqrt{24}[/tex]

Taking the positive root, AP = [tex]\sqrt{72}+\sqrt{24}$[/tex]

Therefore a + b = 72 + 24 = 96

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Point P lies on the diagonal AC of square ABCD with AP > CP. Let [tex]$O_1$[/tex] and [tex]$O_2$[/tex] be the circumcenters of [tex]$\triangle \mathrm{ABP}$[/tex] and [tex]$\triangle \mathrm{CDP}$[/tex] respectively. Given that AB = 12 and [tex]$\angle \mathrm{O}_1 \mathrm{PO}_2=120^{\circ}$[/tex], then [tex]$\mathrm{AP}=\sqrt{\mathrm{a}}+\sqrt{\mathrm{b}}$[/tex], where a and b are positive integers. Find a + b. (correct answer +5, wrong answer 0 )

Answer: The graph is NOT [tex]\text{y} > 3\text{x}-4[/tex]

Explanation:

The inequality of [tex]\text{y} > 3\text{x}-4[/tex]  has the boundary equation [tex]\text{y} = 3\text{x}-4[/tex]

That equation is in the format [tex]\text{y} = m\text{x}+b[/tex] which is slope-intercept form.

m = 3 = slope

b = -4 = y intercept

The positive slope indicates the boundary line goes uphill when moving to the right. However, the graph shows the complete opposite with the line going downhill. This means that the graph cannot possibly be [tex]\text{y} > 3\text{x}-4[/tex]

F:4+4=8

A:23+8+4=35

H:53+3+28=84

I:11+17+93=121

I:24+8+3=35

I think that is all correct

2) y+ 3÷y is the equation that is not a polynomial. Using addition, subtraction, multiplication, and division of numbers .

Using just the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables, a polynomial is an expression in mathematics made up of variables (also known as indeterminates) and coefficients. Using addition, subtraction, multiplication, and division of numbers, a polynomial is an equation that combines variables, constants, and exponents (No division operation by a variable).

given

An algebraic mathematical equation known as a polynomial might have two components. coefficients and parameters

You can combine the solutions to these algebraic equations to achieve the result.

It follows the general formula as follows:

a + a1 + a+ …

2)y+ 3y is the equation that deviates from the formula above.

So, 2)y+ 3y is the equation that is not a polynomial.

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Question 1

The area of the fairway between two streams on a golf course cannot be determined without additional details such as the dimensions or measurements of the fairway and the streams.

Question 2

A. Triangle

To find the area of the fairway, you could separate it into figures whose areas you can find using formulas.

Step 1: Draw a diagram of the fairway, including the two streams and any other relevant features such as bunkers or trees.

Step 2: Divide the fairway into two sections, one on either side of the streams.

Step 3: Measure the width and length of each section of the fairway.

Step 4: Use the formula for the area of a rectangle to find the area of each section. (Area = width x length)

Step 5: Add the areas of the two sections together to find the total area of the fairway between the two streams.

The base of the trapezoid would be the width of the fairway and the width of the stream, and the height would be the distance between the fairway and the stream. The area of a trapezoid is (a+b)h÷2, where a and b are the lengths of the bases and h is the height. The triangle would be formed by the side of the trapezoid that is the distance between the fairway and the stream, and the width of the stream. The area of a triangle is base×height÷2.

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Answer:

∠8 = 139°

Step-by-step explanation:

Before we start solving, let's identify the figure to understand the problem.

We are given two parallel lines that are cut by a transversal.

Two lines are parallel if they have the same arrow head marking.

If two parallel lines are cut by a transversal, the following angles are created:

I have attached an image of the different types of angles to this response.

Thus, we can use the types of angles to solve for ∠8.

∠3 and ∠5 are corresponding angles. Therefore, they have the same measure.

Set up the equation to solve for x:

∠3 = ∠5

9x + 14 = 14x - 1 . . . . . . substitute the values

14 = 5x - 1 . . . . . . . . subtract 9x from the LHS and RHS

15 = 5x . . . . . . . . . . add 1  to the LHS and RHS

∴ 3 = x . . . . . . . . . . . . divide the LHS and RHS by 5 to isolate x

Now that we know what x is, we can substitute it into the value of ∠3.

∠3 = 9x + 14

∠3 = 9(3) + 14 . . . . substitute the values

∠3 = 27 + 14 . . . . . compute

∴ ∠3 = 41

∠3 and ∠8 are adjacent angles. Therefore, they add up to 180°.

Set up the equation to solve for ∠8:

∠8 + ∠3 = 180

∠8 + 41 = 180 . . . . substitute the known values

∴ ∠8 = 139° . . . . . subtract 41 from the LHS and RHS to isolate ∠8

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Answer:

Step-by-step explanation:

180-54=139 so 8 equals 139

By dividing we can get proper fraction is 9/10.We can find answer by dividing two fractions.

A proper fraction is a fraction which has its numerator value less than the denominator. For example, ⅔, 6/7, 8/9, etc. are proper fractions.. We simplify fractions because it is always to work or calculate when the fractions are in the simplest form.

To divide a fraction with a whole number  we multiply the given whole number with the denominator of the fraction. Here, 8/5 ÷ 5 = 8/5 × 1/5 = 8/25. Therefore, 8/5 ÷ 5 = 8/25. Because multiplication is easier than division and because division by itself does not always produce whole numbers.

Now we get

1/2 divide 5/9

1/2 * 9/5

9/5

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The horizontal distance required for the ramp is 143.5 inches

Consider the following figure.

In right triangle ACB, CB is the horizontal distance,

hypotenuse AB = 144 in.

and the vertical distance AC = 12 in.

We need to find the measure of side CB

Let m be the measure of the horizontal distance CB

Using Pythagoras theorem for right triangle ACB,

(AB)² = (AC)² + (CB)²

Substitute given values in above equation.

(144)² = (12)² + (m)²

20736 = 144 + m^2

20736 - 144 = 144 + m^2 - 144

20592 = m^2

m^2 = 20592

m = 143.5 in.

Therefore,  the horizontal distance is 143.5 in.

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Answer:2/5

Step-by-step explanation:

2/5+1/5 equals 3/5, so if the rest of the mixture is chili powder, it would be 2/5

The Geometric Mean (GM) is the average value or mean that, in mathematics, represents the centre tendency of a group of numbers by calculating the product of their values.

The Geometric Mean (GM) in mathematics is the average value or mean that represents the centre tendency of the group of numbers by calculating the product of their values. Basically, n is the entire amount of data values, and we multiply the numbers collectively before taking their nth root.

The geometric mean can be calculated in two steps: To obtain their product, multiply all values collectively. Calculate the product's nth root (n is the number of values).

The geometric mean of 14 and 20 must be determined. Let's see the numbers:

a = 14 and b = 20

For two numbers, the geometric mean is calculated as follows:

[tex]$M=\sqrt{a b}$[/tex]

Filling in the values as shown in the formula above:

[tex]$M=\sqrt{14 \times 20}$$M=\sqrt{7 \times 2 \times 5 \times 4}$$M=16.73$[/tex]

Therefore, the answer is 16.73.

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The required geometric mean of 14 and 20 is 16.73.

The Geometric Mean (GM) in mathematics is the average value or mean that represents the centre tendency of the group of numbers by calculating the product of their values. Basically, n is the entire amount of data values, and we multiply the numbers collectively before taking their nth root.

The geometric mean can be calculated in two steps: To obtain their product, multiply all values collectively. Calculate the product's nth root (n is the number of values).

The geometric mean of 14 and 20 must be determined. Let's see the numbers:

a = 14 and b = 20

For two numbers, the geometric mean is calculated as follows:

G.M = [tex]\sqrt{ab}[/tex]

Filling in the values as shown in the formula above:

G.M = [tex]\sqrt{14(20)}[/tex]

G.M = [tex]\sqrt{280}[/tex]

Therefore, the answer is 16.73.

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The coordinates of the image of the square KLMN are:

K = (0, -1)

L = (2, -1)

M = (2, 1)

N = (0, 1)

The graph of the image is given below.

The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.

The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.

We have,

The coordinates of the square KLMN are:

K = (6, -5)

L = (8, -5)

M = (8, -3)

N = (6, -3)

Now,

Translation of 6 units left and 4 units up.

This means,

K = (6 - 6, -5 + 4) = (0, -1)

L = (8 - 6, -5 + 4) = (2, -1)

M = (8 - 6, -3 + 4) = (2, 1)

N = (6 - 6, -3 + 4) = (0, 1)

Thus,

The image of the square KLMN will be on the following coordinates.

K = (0, -1)

L = (2, -1)

M = (2, 1)

N = (0, 1)

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Answer:

  more than 110

Step-by-step explanation:

You want to know the number of $6 tickets that must be sold to pay for the $660 cost of a school play and make a profit.

The profit is the difference between revenue and cost. The revenue from the sale of n tickets will be 6n. We want the profit to be positive, so we want ...

  6n -660 > 0 . . . . . . positive profit

  n -110 > 0 . . . . . . divide by 6

  n > 110 . . . . . . add 110

More than 110 tickets must be sold to make a profit.

__

Additional comment

Sale of exactly 110 tickets will cover the cost, but there will be no profit.

As a result, the response to the query that the area provided With interiors of 32 and 44 square feet, respectively, the future complex will consist of a 60.1-foot circular.

Finding out how big a rectangle or rectangle is is the simplest (and most used) method. Divide the width by the altitude to find the area of a rectangle. Since all sides of a square are equal in length, determining the area of unit only requires knowledge of the size of one of its sides.

Here,

Here is the formula for area:

The area formula is length times width.

=> 8 × 4

= >32ft²

Following space will be on the trapezoid:

=>(14 + 18)/2 × 4

=> 44ft²

By multiplying the measurement by two, the perimeter will indeed be determined. Knowing this,

= 2(8 + 4) + (14 + 8 + 4 + 5.6 + 4.5)

= 24 + 36.1

= 60.1 ft

In light of this, the answer to the area-related question is

For the specified polygon, 60.1 square feet.

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The required expression that has the coefficient 4 is 4x⁵. Option B is correct.

The expression is the relationship between variables and represented as y = ax + b is an example of a polynomial expression.

here,
Since the question seems to be incomplete,
A standard question can be given as,
Among the following option find the expression that has a coefficient of 4.
(a) 2x + 1
(b) 4x⁵
(c) ax⁶
(d) 7x²

Since the coefficient is the value present at the prefix of the variable term,
So the variable term that holds the coefficient 4 is 4x⁵.

Thus, the required expression is 4x⁵. Option B is correct.

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Answer:

Step-by-step explanation:

Perimeter is the addition of all the sides.

So in this question, if you add up all the sides :

14x + 8x +7x +12

Simplify by adding all terms with x :

29x + 12  

(As you can not add a number constant to a variable )

The exponential function formula for the parent function is found to be

[tex]f(x) = 2^x[/tex]

What is an exponential function?

The formula for an exponential function is [tex]f(x) = a^x[/tex], where x is a variable and a is a constant that serves as the function's base and must be bigger than 0.

The general formula to find an exponential function is [tex]f(x) = ab^x[/tex]

From the given graph, we take two points on the graph : (1,2) and (2,4)

Substituting in the above equation, taking f(x) as y

[tex]ab^1 = 2\\\\ab^2 = 4[/tex]

Solving the above equations, we get

a= 1, b=2

So the parent function  [tex]f(x) = 2^x[/tex].

Now using this function we can graph [tex]f(2x), -3f(x), 2f(2x)\\[/tex].

[tex]f(2x) = 2^{2x} = 4^x\\\\-3f(x) = -3 * 2^x\\2f(2x) = 2 * 4^x[/tex]

Therefore using the Desmos, the above exponential functions are graphed.

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x->∞,y->∞ and as x-> - ∞ , y-> - ∞ this statement  best describes the end behavior.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

First, we need to analyze the plotting of the graph. When it is on the negative axis of x, as the values of x increase (x values increasing in the negative axis means it's decreasing in value), the y values also increase. So as x decreases, y increases.

On the positive axis of x, as the x values increase, the corresponding values of y also increase with x. So as x increases, y values also increase with it.

Hence, x->∞,y->∞ and as x-> - ∞ , y-> - ∞ this  statement  best describes the end behavior.

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Answer:

F.

Step-by-step explanation:

y = k/x where k is a constant

given that x = 4 when y = 3, we have:

3 = k/4

So, k =12.

The equation of variation is:

y = 12/x

When x = 15

y = 12/15 = 4/5.

So not 12 so this is False,

The solution of the given system of equations is x = -7/3 and y = 7.

The given system of equations is given as,

3x + 2y = 7

y = 3x + 11

To solve this system of equations, we need to eliminate one of the variables. We can eliminate y by subtracting the second equation from the first.

3x + 2y = 7

y = 3x + 11

⇒ 3x + 2y - y = 7 - 11

⇒ 3x + 2y - 3x - 11 = -4

⇒ 2y - 11 = -4

⇒ 2y = -4 + 11

⇒ 2y = 7

Now, substitute the value of y in the first equation to find the value of x.

3x + 2(7) = 7

⇒ 3x + 14 = 7

⇒ 3x = 7 - 14

⇒ 3x = -7

⇒ x = -7/3

Therefore, the solution of the given system of equations is x = -7/3 and y = 7.

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Answer:

It will either invert the graph or stretch/compress the horizontal

Step-by-step explanation:

When a is negative It will invert the graph, and reflect it over the x-axis

By plugging in a=1 you get a normal absolute value function of x ( a V on the graph)

If a>1 then your graph will compress

If a<1 then your graph will stretch

A 69 sided shape called"Hexacontakaienneagon".

Naming a polygon by its number of sides requires that we know the appropriate:

3=tri, 4=tetra, 5=penta, 6=Hexa, 7=hepta, 8=octa, 9=Nona or ennea, 10=deca,11=hendeca,12=dodeca,13=triskaideca,14=tetradeca,15=pentadeca,16=hexadeca,17=heptadeca,18=octadeca,19=enneadeca,20=icosa

For polygons with 3 through 20 sides, simply add "gon" to the prefixes at the left.

For more than 20 sides, we "construct" the name by using so-called combining prefixes:

For Tens Digit:

20=icosi,30=triaconta,40=tetraconta,50=pentaconta,60=hexaconta,70=heptaconta,80=octaconta,90=enneaconta

for One's Digit:

1=hena,2=di,3=tri,4=tetra,5=penta,6=hexa,7=hepta,8=octa,9=ennea

60                and      9    

hexaconta    kai     ennea

As per the given information, 69 is defined as "Hexacontakaienneagon".

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The x-intercept of the line 4x-y =- 4  is (1,0).

At x-intercepts, y=0  and at

y-intercepts, x=0.

So, to find the,

x-intercept, set y=0

4x−0=4

4x=4

x=1.

The points at which the graph of a function or an equation crosses or "touches" the x-axis of the Cartesian Plane are referred to as the x-intercepts. This could be thought of as a point with a y-value of zero. Let y equal 0 and then solve for x to determine the equation's x-intercepts.

Because the line crosses the x-axis when y=0, the equation for x must be solved in order to determine the x-intercept. We can solve for the intercepts when an equation is not in the form y = mx + b by solving for the remaining variable and plugging in 0 as necessary. To locate the y-intercept: solve for y and set x to zero.

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