The Sun's mass is 1.778 x 10 m/s2. v=2rT, where T is the amount of time it takes for the Earth to turn around the Sun.
What is our sun's mass?Mass and volume: 1.989 x 1030 kilograms The sun has a mass of 1.989 x 1030 kilograms, which is about 333,000 times the mass of the Earth. Leading astronomers Jack J. and Imke de Pater found that the sun contains 99.8 percent of the mass of the entire solar system.
Earth's mass, Me, is 6 x 10 kg.
Earth's R Radius and Time of Rotation are 1.5x10m. 3.15 x 107 Sec.
Ac = earth's centripetal acceleration We know that W = 345X107 1.99 X 10 Rad/s Gravitational Force F 6x1024 x 1.99x107x mass of the Sun Me 2
F equals 35 + 82 x 10° N Ani.
F = 6 R2 28 2522 x 10" 6.67 x 10" x 6 x 1024 x Ms (1.5 X 10") 2 Ms 35.82 x 1028 x 1.5X1-5 x 1822 6.67 X 10" x 6 x 10' 24 Ms 50 80.59 x 10° 40.02 X 10/3 37 Ms = 2.01 x 10 kg is known to exist.
The fact that centripetal acceleration F-ma f 22 equates both equations is known by mass of now. ma Scanner a equals 52.
ат 24 6.67 x 10" x 6X 10° 1-5 x 10" 17:78 x 16-9 = 1.778 x 10 m/s2 Ans
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find the value of e, the margin of error, for c = 0.99, n = 16 and s = 2.6.
The margin of error is 3.96.
The value of e, or the margin of error, can be calculated using the formula:
e = z*(s/√n)
where:
z = the critical value from a standard normal distribution table (for c = 0.99, z = 2.576)
s = the sample standard deviation (in this case, s = 2.6)
n = the sample size (in this case, n = 16)
So, to find the margin of error for this scenario, we plug the given values into the formula:
e = 2.576*(2.6/√16) = 2.576*(2.6/4) = 2.576*0.65 = 3.96
Therefore, the margin of error is 3.96.
It's worth noting that this value represents the range within which we expect the true population value to fall with a certain level of confidence
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The upper and lower fixed points of a mercury thermometer corresponds to 9.00mV and 16.50mV on the thermocouple thermometer. The temperature of a warm iron giving a reading of 11.21mV to the nearest whole number is.
To find the temperature of the warm iron, we first need to convert the reading on the thermocouple thermometer to a temperature value. To do this, we will use the formula:
Temperature = (Reading - Lower Fixed Point) / (Upper Fixed Point - Lower Fixed Point) * (Upper Temperature - Lower Temperature) + Lower Temperature
In this case, the lower fixed point is 9.00mV and the upper fixed point is 16.50mV. We also know that the lower temperature is 0°C (the freezing point of water) and the upper temperature is 100°C (the boiling point of water). So, we can plug in these values:
Temperature = (11.21mV - 9.00mV) / (16.50mV - 9.00mV) * (100°C - 0°C) + 0°C
Simplifying, we get:
Temperature = (2.21mV / 7.50mV) * 100°C
And further simplifying, we get:
Temperature = 0.2907 x 100°C
So, the temperature of the warm iron is approximately 29.07°C to the nearest whole number.
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A student wants to investigate the motion of a ball by conducting two different experiments, as shown in Figure 1 and Figure 2 above. In Experiment 1, the student releases a ball from rest and uses a slow-motion camera to film the ball as it falls to the ground. Using video analysis, the student is able to plot the ball’s horizontal position x and vertical position y as a function of time t. In Experiment 2, the student horizontally rolls the same ball off a table, and uses video analysis to plot the ball’s horizontal position x and vertical position y as a function of time t starting from the instant the ball leaves the table. The graphs from each experiment are shown above along with each graph’s best-fit curve line.
Question:
Suppose that Experiment 1 and Experiment 2 are conducted at the same time; one student drops the ball from rest at the same instant that a second student horizontally rolls an identical off the table. After both balls have traveled half their vertical distance to the floor, what is the acceleration of the center of mass of the two-ball system relative to Earth?
A) Equal to g
B) Less than g, but not zero
C) Less than g , but not zero
D) Zero
The acceleration of the center of mass of the two-ball system relative to Earth is equal to g after the balls have travelled for half their vertical distance to the ground, option A.
What is the center of mass of any object?The total force acting on the system is equal to the acceleration of the center of mass multiplied by the total mass of the system. When applied to an extended object, Newton's second law, F = ma, predicts the motion of a specific reference point for this object. The center of mass is the name given to this reference point.
When we throw an object upward, gravity acts on it, and the acceleration it experiences is the inverse of the acceleration caused by gravity, i.e. deceleration. As a result, the acceleration of each ball will be g. As a result, the acceleration of the center of mass of the two balls thrown upward is g.
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Mess Me and You will have nonsense Explain how this riddle relates to mutation in DNA
Nonsense mutations are those point mutations in the DNA where stop codons will appear before the time they should appear.
What are nonsense mutations?At the time of transcribing from DNA to RNA, the template needs to have both start and stop codons for the transcription to occur correctly, but sometimes mutations can occur that do not allow the protein to be produced correctly. This mutation can be permanent which causes damage to the formation of proteins.Sometimes mutations can be beneficial, allowing evolution and helping organisms to be better formed for a new environment.
It is the type of mutation in which a termination codon occurs before the time it should be, instead of giving a codon with a certain amino acid. Which gives a much shorter protein than it should be, giving a non-functional protein.
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What did Galileo discover when he dropped two cannon balls into f different weights from the leaning tower of pisa
Answer: The time it took for them to fall ere the same.
Explanation:
The only difference was because of resistance, weight doesn't affect the speed of gravity, the speed of gravity stays the same (9.801 meters per second)
If an object was traveling horizontally off a cliff at 6 m/s for 3 seconds, how long did it take to
hit the ground?
The time taken by the object to hit the ground is 1.8 seconds.
What do you mean by gravitational force?The attraction that draws two objects together is known as gravitational force, sometimes referred to as gravity. Every mass-containing object pulls on nearby things gravitationally in a sizable way.
The time it takes for an object to hit the ground after being dropped off a cliff can be calculated using the formula:
t = √(2*d/g)
where t is the time, d is the distance fallen, and g is the acceleration due to gravity.
In this case, we don't know the distance fell, but we can use the horizontal velocity and time of travel to find it:
d = v * t
where v is the velocity (6 m/s), and t is time (3 seconds)
d = 6 * 3 = 18 m
Now we can use the distance fallen to calculate the time it takes to hit the ground:
t = √(2*d/g)
g is approximately 9.8 m/s^2
t = √(2*18/9.8) = √ (3.6) = 1.8 seconds
So, it takes 1.8 seconds for the object to hit the ground after traveling horizontally off a cliff at 6 m/s for 3 seconds.
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How do you calculate lever arm in torque?
We can find the torque of lever arm by the formula Torque(T)=Force * perpendicular distance.
A torque is an action that causes objects to rotate. A torque is required to rotate an object, just as a force is required to move an object in a line. Torque is created by force, but it also depends on where the force is applied and the point about which the object rotates.
Force and lever arm are not always perpendicular. When the force and lever arm are not perpendicular, trigonometry is required to calculate the length of the lever arm. The force applied is perpendicular to the surface of the object rotating. When this force is at an angle θ with the plane of the object, the perpendicular force requires the use of the sine function.
When an object is in rotational equilibrium, the net torque applied to it is zero. For example, if an object such as a see-saw is not rotating, you know the torque on each side is balanced Rotational equilibrium is often used to determine unknown forces. Any object that is not moving is in rotational equilibrium and in translational equilibrium.
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A proton moves at 3.80 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.20 103 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 4.50 cm horizontally. 118.42 Correct: Your answer is correct. ns (b) Find its vertical displacement during the time interval in which it travels 4.50 cm horizontally. (Indicate direction with the sign of your answer.) mm (c) Find the horizontal and vertical components of its velocity after it has traveled 4.50 cm horizontally.
Answer:
(a) The time interval required for the proton to travel 4.50 cm horizontally is
t = (4.50 cm) / (3.80 x 105 m/s) = 118.42 ns
(b) The vertical displacement of the proton during the time interval is
dY = (F × t2) / 2m = (9.20 x 103 N/C × (118.42 ns)2) / (2 × 1.67 x 10-27 kg) = 0.0033 mm
(c) The horizontal and vertical components of the velocity after the proton has traveled 4.50 cm horizontally are
Vx = 3.80 x 105 m/s
Vy = (F × t) / m = (9.20 x 103 N/C × 118.42 ns) / (1.67 x 10-27 kg) = 1.90 x 105 m/s
An object that is moving in a circle at a constant speed has a velocity vector that is directed ________and an acceleration vector that is directed ________.
A directed velocity vector and a directed velocity acceleration vector characterise an item travelling in a circle at a constant speed.
When an item is travelling in a circle at a constant speed, what is its acceleration?Consequently, an object travelling in a circle at constant speed is speeding up its approach to the circle's centre. Centripetal acceleration is the term used to describe the speed toward the centre of the circle.
What happens to an object's velocity when it rotates in a circle at a constant speed?There is a fluctuating velocity for an object in a circular orbit travelling at a constant speed. Considering that velocity is a vector quantity that depends on both speed and direction, this makes sense. Accelerating is the object in orbit.
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What is the speed of a truck that travels 10 km in 20 minutes?
Answer:
8.3 m/s
Explanation:
Here's the answer in m/s:
(10 km)(1000 m/km) = 10000 m
(20 min)(60 s/min) = 1200 s
speed = d/t = 10000m / 1200s = 8.3 m/s
An airplane starts from rest and accelerates at a constant 3.00 m/s2 for 30.0 s before leaving the ground. a. How far did it move
The airplane that starts from rest and accelerates at 1 constant 3 m/s2 for 30 s before leaving the ground moved by the distance of 1350m.
Acceleration is given as 3.00 m/s2
Time is 30 sec.
The formula we can use in this case is:
s = ut + 0.5 at^2
v = at + u
where,
s is distance travelled
u is initial velocity = 0 since at rest
t is time travelled
a is acceleration
v is the final velocity when it took off
a. s = 0 + 0.5 * 3 * 30^2
s = 1350 m
The distance moved by the airplane is 1350 m.
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Please explain what the above equation shows and justify your answer. Does this equation prove that gamma radiation cannot be produced by this type of nuclear decay? Please explain your answer.
This is not a gamma radiation because there is a change in the atomic number of the daughter nucleus. It is rather a beta decay.
What is a nuclear decay?We have to note that when we talk about a decay we are talking about the manner that we can be able to break up the atom of a radioactive substance so that we can be able to produce a new substance.
We can see now that what we have here is the loss of a beta ray or an electron from the specie that is shown. This is evidenced by the change in the atomic number of the daughters nucleus.
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What is the formula to calculate torque?
Torque = force x distance from point of rotation
Torque is a measure of the turning effect of an applied force about a specific point or axis. It is calculated by multiplying the force applied to an object by the distance from the point of rotation to the point where the force is applied. The greater the force or the longer the distance from the point of rotation, the greater the torque. The unit of torque is typically Newton-meters (N·m) in the International System of Units (SI) or pound-feet (lb·ft) in the imperial system. Torque is essential in various fields such as physics, mechanics, engineering and robotics.
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If A and B are non-zero vectors, is it possible for A×B and A·B both to be zero?
It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore A×B and A·B cannot both be zero.
What are non-zero vectors?In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.
The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.
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how long after closing the switch s will the potential across each capacitor be reduced to 15.0 v ?
The time taken can be calculated by the equation: t = -RC ln(15/50)
To determine how long after closing the switch s the potential across each capacitor will be reduced to 15.0 V, we need to know the initial potential across the capacitors, the capacitance value and the resistance in the circuit.
When a switch is closed, the potential across a capacitor decreases exponentially with time according to the equation:
V(t) = V0e^(-t/RC)
Where V0 is the initial potential across the capacitor, t is time, R is the resistance in the circuit, and C is the capacitance.
In this case, the initial potential across each capacitor is 50.0 V, and the resistance in the circuit is 80 ohms.
To find the capacitance value we need to know that the capacitors are parallely connected, which means that the total capacitance is the sum of the individual capacitances:
Ctotal = C1 + C2
Once we have the capacitance value, we can find the time constant RC:
RC = R / Ctotal
Now we can use the equation above to find the time it takes for the potential to decay to a certain percentage of the initial value.
For example, if we want to find the time it takes for the potential to decay to 15.0 V (30% of the initial value), we can use the following equation:
15.0 V = 50.0 Ve^(-t/RC)
and we can solve for t:
t = -RC ln(15/50)
It's worth noting that this is an estimation and that in real world situations the resistance and capacitance values are also affected by other factors such as leakage current or parasitic capacitances.
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draw the standing wave if the tension is quadrupled while the frequency is held constant
The diagram for the standing wave after the tension is quadrupled while the frequency is held constant has been attached and explained below.
We already know that the frequency of a standing wave is given by,
= f = nv/2l
and
= v = [tex]\sqrt{\frac{T}{m} }[/tex]
In the given problem, the frequency of the wave after the tension is quadrupled will be -
= f2 = 2v/2l
= f2 = v/l
= f2 = 1/l [tex]\sqrt{\frac{T}{m} }[/tex]
Now, since we have quadrupled the tension, we have -
= f = 1/l [tex]\sqrt{\frac{4T}{m} }[/tex]
= f = 2(f2)
So, now we know that the final frequency will be of this form(the image has been attached here) and it would look like this if the tension is quadrupled while the frequency is held constant.
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If a container is stressed beyond its limits of recovery and opens up, then it is in this event of the General Hazardous Materials Behavior Model.
A container is said to have breached when it has been overstressed beyond its point of recovery.
The GEBMO model enables a systematic evaluation of the outcomes that are most likely to occur when a hazardous material container is strained. Hazardous material containers typically have the capacity to hold that material under typical shipping, storage, and use circumstances. Thus, API gravity is a measure of the density of a petroleum liquid in relation to water (also known as specific gravity). It is used to compare petroleum liquid densities. For instance, if one petroleum liquid has a higher API gravity than another because it is less dense.Specific gravity (Sp.Gr. or SG) is the weight or density of a liquid or solid relative to water. Floaters and sinkers have specific gravities below that of water and are very immiscible with itTo know more about Hazard here
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CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!
1.) Compare reflection and refraction. How are they similar and how are they different?
2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.
3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.
4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.
Answer:
1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.
2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.
3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.
Laws of reflection:
(i) The angle of reflection is always equal to the angle of incidence.
(ii) The incident rays, reflected rays and the normal, all lie in the same plane.
4.)Snell’s law formula is expressed as: μ= sin i/sin r
, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.
Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)
-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch
The astronaut being pushed back into his seat as the rocket accelerates - this was the example of Newton's first law of motion.
What is Newton's first law of motion?According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.
When the astronaut worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .
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25. What force must be exerted on the pedal cylinder of a hydraulic lift to support the weight of a 2000-kg car (a large car) resting on the wheel cylinder
A hydraulic lift's master cylinder must be subjected to a force of 136N.
What is the tenet of the Archimedes Principle?According to Archimedes' principle, an object that is totally or partially submerged in a fluid will feel upward buoyant force that is equivalent in strength toward the point of gravity here on displaced fluid.
Where is the principle of Archimedes used?The design principle for vessels and submarines uses Archimedes' principle. The Archimedes principle is the foundation of hydrometers.
According to Archimedes' principle:
F1 / A1 = F2 / A2
F2 = (A2 / A1) * F1
Also, the formula for the force is F = mg.
The formula for the area of the cylinder is A = , therefore we get
F2 = ( π [tex](r2)^{2}[/tex] / π [tex](r1)^{2}[/tex] ) * mg
Since the cylinders' diameter is 2 cm and 24 cm, r1 = 12 and r2 = 1.
Substituting the values to the derived equation, we get
F2 = ( π [tex](1)^{2}[/tex] / π [tex](12)^{2}[/tex] ) * 2000 * 9.8
2 = 136 N
Thus, the force exerted must be 136N.
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How do you find thermal energy from kinetic and potential energy?
Thermal energy can be found from kinetic and potential energy by calculating the amount of work done on an object. Work is equal to the amount of force multiplied by the distance moved by the object.
The Kinetic energy is equal to the mass of the object multiplied by the square of its velocity. Potential energy is equal to the mass of the object multiplied by the acceleration of gravity multiplied by the height of the object. Thermal energy is equal to the sum of the kinetic and potential energies.
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In an electrical circuit, two resistors of 2Ω & 4Ω have been connected in series to a 6V battery. The heat dissipated by the 4Ω resistor in 5s will be
R= 2+4=6Ω
in series connection, same current and different voltage
total voltage= total current × total resistance
6=I×6
I=6/6= 1A
voltage across 4Ω resistor= 1×4=4v
Therefore, heat dissipated by the 4Ω resistor in 5s= (v²/R)×t= (4²/4)× 5 = 16/4 × 5 = 20J
1. Calculate the size of the gravitational pull of a sphere of mass 10 kg on a mass 2.0 kg. When their
centres are 200 mm apart. What is the force of the 2.0 kg mass on the 10 kg mass?
Please answer with an explanation if you can!!!
Explanation:
Let a be the sphere of mass 10 kg and b be the sphere of mass 20 kg. According to Newton's universal law of gravitation, the gravitational force of a on b is expressed as:
F
a
b
=
G
m
M
d
2
, where:
G
=
6.67
×
10
−
11
N
m
2
/
k
g
2
is the gravitational constant
m = 2 kg is the mass of a
M = 10 kg is the mass of b
d = 0.2 m is the separation between the two spheres
So:
Fab=GmMd26.67
×
10
−
11
×
2
×
10
0.2
2
What does an increases in concentration do to a material?
Answer:
it will increase the frequency of collisions between the two reactants
Explanation:
mark brainliest?
At t = 0, a wheel rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2 has an angular velocity of 1.5 rad/s and an angular position of 2.3 rad. what is the angular position of the wheel at t = 2.0 s?
At t = 0, the wheel has an angular position of 2.3 rad and an angular velocity of 1.5 rad/s.
Since the wheel is rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2, we can use the equation for angular position to calculate the wheel's angular position at t = 2.0 s.
Angular position = initial angular position + (initial angular velocity × time) + (1/2 ×angular acceleration ×time²)
Angular position at t = 2.0 s = 2.3 rad + (1.5 rad/s × 2.0 s) + (1/2 ×-0.40 rad/s2 × (2.0 s)²)
Angular position at t = 2.0 s = 2.3 rad + 3.0 rad + -1.6 rad
Angular position at t = 2.0 s = 3.7 rad
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It took the bike messenger 36 minutes to ride from the school to the blue house. If they are 2160 meters apart, what was the messenger's velocity
The bike messenger's velocity will be 1 m/s.
Given as per the question is,
Distance between school and the blue house is 2160 meters
Time taken by the bike messenger is 36 minutes
Velocity is to be calculated.
Converting minutes into seconds,
36 minutes = 36 X 60 = 2160 seconds.
Velocity of an object can be calculated by the formula as,
Velocity = Distance/ Time
Substituting the values as per the formula above,
Velocity = 2160/2160 = 1 m/s
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8. Jax bounced a dodgeball off a wall. The dodgeball has a momentum of 32. 6 kg · m/s after the
collision. What is the total momentum of the system before the collision?
32. 6 kg m/s will be the total momentum of the system before the collision.
What does "collision" mean?In physics, a collision is any circumstance in which two or more bodies rapidly apply forces to one another.
Despite the fact that the most common usage of the word "collision" relates to instances in which two or more objects smash violently, the scientific usage of the word makes no such assumptions.
If most or all of the total kinetic energy from the collision is lost (dissipated as heat, sound, etc., or absorbed by the objects themselves), the collision is said to be inelastic; such collisions result in the objects coming to a complete stop. A collision involving a car serves as an example of this type of collision since cars fold inward rather than colliding with one another.
Briefing:pf = Final momentum of the system = 32.6 kg m/s
According to the principle of conservation of angular momentum we have
pi = pf => pi = 32.6 kg m/s
The wall is not moving so the initial and final momentum of the system are equal.
Therefore, the total momentum of the system before the collision is 32.6 kg m/s
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Impulse is ________. View Available Hint(s)for Part A the time interval that a force lasts. the area under the force curve in a force-versus-time graph. a force that is applied very suddenly. a force that is applied at a random time.
The area below the force curve on a force versus time graph is known as the impulse.
The concept of "impulse" refers to how much of an impact a force has over time. The cricket batsman striking the ball is one of the most well-known and frequently used illustrations. The bat significantly changes the ball's trajectory despite making contact with it for a relatively brief period and launching a bicycle. Everyone occasionally makes rash decisions, particularly when we're young. In general, as we get older, we learn to control our urges. It might or might not be a sign of a problem. A mental health concern may be indicated by persistently impulsive behavior.
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Matt i a 85kg lifeguard, he lide down a water lide that i inclined at 35 degree to the horizontal into a wimming pool. If the coefficient of kinetic friction of the lide i 0. 9. What i Matt’ rate of acceleration a he goe down the lide
The rate of acceleration at which Matt goes down the slide is equal to 5.32 m/s².
The normal force or [tex]F_{N}[/tex] acts perpendicular to the object.
The angle of inclination = 35°
cosθ = [tex]F_{N}[/tex]/mg
[tex]F_{N}[/tex] = mgcosθ = 85 × 10 × cos 35
= 850 × 0.819 = 696.15 N
To find the force of friction,
μ = 0.050
[tex]F_{f}[/tex] = μ × [tex]F_{N}[/tex]
= 0.050 × 696.15 = 34.80 N
To find the downward component of weight that pulls him down the slide.
sinθ = [tex]F_{d}[/tex]/mg
[tex]F_{d}[/tex] = mgsinθ
= 85 × 10 × sin35
= 850 × 0.5736 = 487.56 N
To find the acceleration,
[tex]F_{net} = F_{d} - F_{f}[/tex]
= 487.56 - 34.80 = 452.76 N
To solve for acceleration,
F = force = 452.76 N
m = mass = 85 kg
Force = mass × acceleration
a = F/m = 452.76/85 = 5.32 m/s²
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If you rub an air filled balloon on your hair it is possible to stick on the wall and have it statically remain there. Explain how this is possible and be sure to answer the following questions in your explanation: (A) is the balloon a conductor or an insulator? (B) is the wall a conductor or an insulator?
The balloon will be drawn to the wall once it has been rubbed sufficiently to build up a sufficient negative charge. Even though the wall should generally be neutrally charged, its charges can change, causing a positively charged region to pull the negatively charged balloon toward it.
The balloon gains electrons when it is rubbed against your hair or a piece of wool cloth, making it negatively charged. Once charged, the two balloons will move away from one another because like charges repel and like charges attract (the paper will be attracted to the charged balloons.)The pull of an electrostatic force is what keeps the ball clinging to the wall.The balloon becomes charged when we rub it with a synthetic cloth, and when it is brought close to a wall, the electrostatic force causes it to be drawn to the neutral wall.To know more about conductor here
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