(1) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero is 0.4 m.
(2) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward is 0.25 m.
(3) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward is 0.25 m.
Maximum height
v² = u² - 2gh
where;
v is final velocityu is initial velocitywhen the lander's velocity = 0
0 = u² - 2gh
u² = 2gh
h = u²/2g
h = (2.8²)/(2 x 9.8)
h = 0.4 m
when the velocity of the lander is 1.7 m/s downwardh = (u² - v²)/2g
h = (2.8² - 1.7²)/(2 x 9.8)
h = 0.25 m
when the velocity of the lander is 1.7 m/s upwardh = (u² - v²)/2g
h = (2.8² - 1.7²)/(2 x 9.8)
h = 0.25 m
Thus, the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero is 0.4 m.
The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward is 0.25 m.
The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward is 0.25 m.
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a downward force of 400 N is applied to the small piston with a diameter of 6 cm in the hudraulic lift system. What is the
a) upward force exerted by the large piston with diameter of 30 cm
b) if the input force pushes the small piston down by 25 cm how high will the large piston rise
Pressure will be constant at both ends, with the use of formula, the upward force is 10,000 N and the height is 625 cm
What is Pressure ?Pressure can simply be defined as a ratio of force to area. Hydraulic lift system makes use of pressure principles.
Given that a downward force of 400 N is applied to the small piston with a diameter of 6 cm in the hydraulic lift system.
What is the
a) upward force exerted by the large piston with diameter of 30 cm
Pressure will be the same at both end.
Since pressure P = F/A
The area of the piston = πr²
F1 = 400r1 = 6cm = 0.06 mF2 = ?r2 = 30 cm = 0.3mF1/A1 = F2/A2
Since π will cancel out, substitute the Force and radius r directly
400/0.06² = F/0.3²
F = 111111.1 × 0.09
F = 9999.99 N
F = 10,000 N
b) if the input force pushes the small piston down by 25 cm, we can know how height will the large piston rise by using the same formula
400/0.25 = 10000/L
1600 = 10000/L
L = 10000/1600
L = 6.25 m
L = 625 cm
Therefore, the upward force exerted by the large piston is 10,000 N approximately and the height is 625 cm
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A house painter is standing on a uniform, horizontal platform that is held in equilibrium by two cables attached to support on the roof. The painter has a mass of 75 kg, and the mass of the platform is 20.0 kg. The distance from the left end of the platform to where the painter is standing is d=2.0 m, and the total length of the platform is 5.0 m. (a) How large is the force exerted by the left-band cable on the platform? (b) How large is the force exerted by the right-hand cable?
Aluminum has an atomic number of 13. This implies that the Al3+ ion contains the same number of electrons as (13-3 = 10) electrons.
A cation is a positively charged ion, to be more precise. An atom must lose an electron in order to become positively charged. The electronic configurations of an element with atomic number 13 are 2, 8, and 3. Thus, the atom of this element has three electrons in its valence shell. This atom has the valence M. The second element in the periodic table's thirteenth column is aluminum. It is categorized as a "poor metal" and a post-transition metal. 13 protons and 13 electrons make up an aluminum atom. The outer shell has three valence electrons.
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estimate the magnitude of the force per unit area on sheet i, in n/m2?
The magnitude of the force per unit area on sheet i, in n/m2, is equal to the product of the pressure applied to the sheet and its surface area. Therefore, it is necessary to know the applied pressure and the surface area of the sheet to calculate the force per unit area.
1. Determine the applied pressure: The applied pressure is the force applied to the sheet divided by the surface area of the sheet.
2. Calculate the surface area of the sheet: The surface area of the sheet can be calculated by multiplying its length, width, and height.
3. Calculate the force per unit area: Multiply the applied pressure by the surface area of the sheet to calculate the force per unit area, in n/m2.
The magnitude of the force per unit area on sheet i, in n/m2, is equal to the product of the pressure applied to the sheet and its surface area. Therefore, it is necessary to know the applied pressure and the surface area of the sheet to calculate the force per unit area.
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Diffraction Limit:
a) How far away can a human eye distinguish two car headlights 2.0m apart? Consider only diffraction effects and assume an eye pupil diameter of 6 mm and a wavelength of 560 nm.
b) What is the minimum angular separation an eye could resolve when viewing two stars, considering only diffraction effects?
c) In reality, the minimum angular separation is about 1′ of arc. Why is it not equal to your answer in part b)?
The human eye can distinguish two car headlights 2.0m apart when the angular separation is about 0.03°.
What is diffraction?Diffraction is the bending of waves around an obstacle or through an opening. When light or sound waves encounter an obstacle, the waves are scattered and spread out in a pattern known as a diffraction pattern. The size and shape of the obstacle affects the amount of diffraction that occurs. The same is true for an opening, such as a slit or a hole, which causes the waves to spread out in multiple directions. Diffraction is an important concept in many areas of physics, such as optics, acoustics, and quantum mechanics.
This is calculated by using the formula θ = 1.22λ/D, where θ is the angular resolution, λ is the wavelength of the light, and D is the diameter of the eye pupil. Assuming a light wavelength of 560nm and an eye pupil diameter of 6mm, the angular resolution is 0.03°.
The minimum angular separation an eye could resolve when viewing two stars, considering only diffraction effects, is 0.0003°. This is calculated using the same formula as before, only with the wavelength set to 550nm.
In reality, the minimum angular separation is about 1′ of arc, which is significantly larger than the answer calculated in part b). This is because diffraction effects are the only factor taken into account in part b), while in reality, other factors such as the eye's optical aberrations, the eye's accommodation, and atmospheric turbulence all play a role in limiting the resolution of the eye. Additionally, the eye's acuity is not constant and can be affected by fatigue and other factors. Thus, the true angular resolution of the eye is much lower than the theoretical limit calculated in part b).
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Consider the circuit shown in (Figure 1). Assume E = 19 V.
A. What is the equivalent capacitance?
B. What is the charge on 3.0 μF capacitor?
C. What is the charge on 4.0 μF capacitor?
D. What is the charge on 6.0 μF capacitor?
The equivalent capacitance is 5.4μF, the charge on 3.0μF capacitor is 57μC, the charge on 4.0μF capacitor is 76μC, the charge on 6.0μF capacitor is 114μC.
Given from the diagram below the emf E = 19V
The capacitance of first capacitor (C1) = 3.0μF
The capacitance of second capacitor (C2) = 4.0μF
The capacitance of third capacitor (C3) = 6.0μF
We can see that the capacitors C2 and C3 are connected in series and C1 is connected in parallel to C2 and C3.
So, the capacitance in series is 1/C' = 1/4 + 1/6
C' = 2.4μF and Ceq = C' + C1 = 2.4 + 3 = 5.4μF
(a) The equivalent capacitance = 5.4μF
We know that E = Q/C where Q is the charge and E is the voltage.
(b) the charge on 3.0μF capacitor (Q1) = 19 x 3 = 57μC
(c) the charge on 4.0 μF capacitor (Q2) = 19 x 4 = 76μC
(d) the charge on 6.0 μF capacitor (Q3) = 19 x 6 = 114μC
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Thursday Homework 1-12-23 SHOW ALL YOUR WORK! 5. A swimming pool is 8 meters long, 6 meters wide, and 2 meters deep. The water- resistant paint needed for the pool costs $6 per square meter. How much will it cost to paint the pool? a. How many faces of the pool do you have to paint? b. How much paint (in square meters) do you need to paint the pool? c. How much will it cost to paint the pool? Who can help me ?
Since you aren't painting on top of the pool, you are painting the pool's four sides, its bottom, and its five faces. 104 square meters is the surface area. The total cost of the paint was $624.
What does surface area mean?A three-dimensional shape's surface area is the sum of all of its faces. Finding the area for every face and adding them together gives us the land area of a shape.
The water-resistant paint required for the pool, which is 8 meters long, 6 meters wide, and 2 meters deep, costs $6 per sq meter.
A) Because you aren't painting on top of the pool, you are painting the pool's four sides, its bottom, and its five faces.
B) The pool requires 104 square meters of paint.
Just use surface area equation assuming the pools is a rectangular prism:
SA = wl + 2(hl) + 2(hw)
Since we're only including pool's bottom, don't add times 2 for wl.
l = 8 m
w = 6 m
h = 2 m
SA = (6)(8) + 2((2)(8)) + 2((2)(6))
SA = 104 sq m
C) The total cost of the paint was $624. $624 is equivalent to $104 × 6 square meters.
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Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
Which of the graphs illustrate how the current through an inductor might possibly change over time?(Figure 1) Type the numbers corresponding to the right answers in alphabetical order. Do not use commas. For instance, if you think that only graphs C and D are correct, type CD. Graph A Current (MA) 3.5 3 2.5 2 1.5 1 0.5 0
Time (ms) 0 0.5 1 1.5 2 Graph B Current (MA) 3.5 3 2.5 2 1.5 0.5 0 Time (ms) 0 0.5 1 1.5 2 Graph C Current (MA) 3.5 3 2.5 2 1.5 1 0.5 0
Time (ms) 0 0.5 1 1.5 2
Graph D Current (MA) 3.5 3 2.5 2 1.5 1 0.5 0
Time (ms) 0 0.5 1 1.5 2
Induction describes the fundamental action of creating currents with magnetic fields.
To distinguish it from charging by induction, which makes use of the electrostatic Coulomb force, this method is sometimes known as magnetic induction. Faraday reasoned that there must be an electromotive force moving the charges through the coil if a current is created in the coil. This interpretation was found to be wrong; instead, the energy added to the charges in the coil comes from an outside source that moves the magnet. The electromotive force is actually a potential since the energy added per unit charge is measured in volts. Regrettably, the term electromotive force stuck, along with the possibility for people to mistake it for a genuine force.
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The maximum height of a cylindrical column is limited by the compressive strength of the material; if the compressive stress at the bottom were to exceed the compressive strength of the material, the column would be crushed under its own weight. Part 1 out of 3
(a) For a cylindrical column of height h and radius r, made of material of density rho, calculate the compressive stress at the bottom of the column. compressive stress =
A cylindrical column has height h and radius r, made of material of density ρ. The compressive stress at the bottom of this column is ρgh.
A cylinder's volume refers to the amount of interior space it has to hold a given quantity of material. And, this is given by [tex]V = \pi r^2h[/tex] where h is the cylinder's height and r is the cylinder's radius.
Given the cylinder's radius is r, height is h, and density is ρ. Then, the mass of the cylinder is calculated by multiplying the cylinder's volume and density. This is written as [tex]M = \pi r^2h\times \rho[/tex].
And the cylinder's weight is calculated by multiplying mass and gravity g. This is written as [tex]W = \rho \pi hr^2\times g[/tex].
We have to calculate the compressive stress at the bottom of the column. So the area of the bottom circle [tex]A = \pi r^2[/tex]. The compressive stress be then calculated as follows,
[tex]\begin{aligned}\text{Compressive stress}&=\frac{\text{ Weight}}{\text{Area}}\\&= \frac{(\rho \pi hr^2g)}{(\pi r^2)}\\&= \rho gh \end{aligned}[/tex]
The required answer is ρgh.
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write the formula for isothermal compressibility (see example 5) in terms of p
Isothermal compressibility is given by K=−1V(∂V∂P)T.
What is meant by isothermal compressibility?
Isothermal compressibility is defined by the fractional differential change in volume due to a change in pressure.
What is the isothermal process?
An isothermal process is a thermodynamic process in which the temperature of a system remains constant. The transfer of heat into or out of the system happens so slowly that thermal equilibrium is maintained.
How is isothermal compressibility calculated?
To measure isothermal compressibility a known increment of pressure must be applied and the consequent isothermal volume change measured. During compression, however, heat is generated in the test liquid and must be dissipated before the volume change can be measured.
Is isothermal positive or negative?
The isothermal compression of the gas was performed in two ways, one irreversible and one reversible. The work done on the gas is positive because the gas is compressed; the surroundings do positive work on the gas.
Thus, the formula is K=−1V(∂V∂P)T.
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Suppose a transparent vessel 30.0 cm long is placed in one arm of a Michelson interferometer, as in Example 25.2. The vessel initially contains air at 0 ° C and 1.00 atm. With light of vacuum wavelength 633 nm, the mirrors are arranged so that a bright spot appears at the center of the screen. As air is slowly pumped out of the vessel, one of the mirrors is gradually moved to keep the center region of the screen bright. The distance the mirror moves is measured to determine the value of the index of refraction of air, n. Assume that, outside of the vessel, the light travels through vacuum. Calculate the distance that the mirror would be moved as the container is emptied of air.
The distance that the mirror in pressure would be moved as the container is emptied of air is 0.0084 cm.
What is pressure?
Pressure is the amount of force applied to an area over a given surface. It is measured in units of force per area, such as pascals (Pa) or pounds per square inch (psi). Pressure is a fundamental physical property and is the result of the interaction of forces between particles of matter.
The index of refraction of air can be calculated using the equation:
n = c/v,
where n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium.
The speed of light in a vacuum is 3.00 x 10^8 m/s, and the speed of light in air is given by the equation:
v = c/n = (3.00 x 10^8 m/s)/(1.00028) = 2.99972 x 10^8 m/s.
Therefore, the index of refraction of air at 0 °C and 1.00 atm is 1.00028.
The difference between the index of refraction of air and the index of refraction of vacuum is 1.00028 – 1 = 0.00028.
Distance = (0.00028)*(30.0 cm) = 0.0084 cm
Therefore, the distance the mirror must be moved as the container is emptied of air is 0.0084 cm.
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1. a. Find the angle between a diagonal of a cube and one of its edges. Show all working. b. Is the line through (4,6,3) and (2,0, -1) parallel to the line through (6,22,12) and (1,7,2)? Your explanation must include full details. c. Two forces F1 and F2 with magnitudes 100 Newtons and 120 Newtons, respectively, act on an object at point P as shown in the figure (not to scale).
a. The angle between a diagonal of a cube and one of its edges is approximately 54.7356°.
b. No, the line through (4,6,3) and (2,0, -1) is not parallel to the line through (6,22,12) and (1,7,2).
C. question is incomplete.
a. To show the working, consider the diagonal of a cube with edge length "a":
Diagonal = √(a^2 + a^2 + a^2) = √(3a^2) = a√3
The length of the edge is "a".
To find the angle between the two, use the dot product formula:
cos(θ) = (a * a) / (a * √(3a^2)) = a / √(3a^2) = a / (a√3) = 1 / √3
Therefore, θ = cos^-1 (1 / √3) = 54.7356°
b. The line through (4,6,3) and (2,0, -1) is not parallel to the line through (6,22,12) and (1,7,2).
Parallel lines have the same direction and therefore the same slope. To check for parallelism, we can find the direction ratios of the lines.
The direction ratio of the line through (4,6,3) and (2,0, -1) is: (2-4,0-6,-1-3) = (-2,-6,-4)
The direction ratio of the line through (6,22,12) and (1,7,2) is: (1-6,7-22,2-12) = (-5,-15,-10)
Since the direction ratios are different, the two lines are not parallel.
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Why are there convection currents in the mantle?
A camera lens has a focal length of 180.0 mm and an aperture diameter of 16.36 mm. What is the f-number of the lens? a. f/5.6 b. f/16 c. f/11 d. f/45
Option C is the correct answer .
What is lens ?
A lens is a transparent material, usually circular, with two polished surfaces, one or both of which are curved, either convex (curved) or concave (deep). Curves are almost always spherical. That is, the radius of curvature is constant. Lenses have the valuable property of producing images of objects in front of us. Singlet lenses are used in eyeglasses, contact lenses, pocket magnifiers, projection condensers, signal lights, viewfinders, and simple box cameras
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fig. 1 shows a motion di- agram of a car traveling down a street. the camera took one frame every 10 s. a distance scale is provided.
The graph obtain from the plot is consistent and the velocity is changing at different instance from the distance scale provided.
(a) In first frame to third frame car velocity is decreasing and in fourth frame car moves with constant velocity up to sixth frame. From seventh frame to ninth frame velocity is increasing
(b) Measure the x-value of the car at each dot and place your data in a table, showing each position and the instant of time at which it occurred.
The table below shows a position and time of a car traveling down a street.
t v
0 1200
1 1000
2 850
3 750
4 700
5 650
6 600
7 500
8 300
9 0
(c) Yes, The slope of position vs time graph gives velocity. We can explain from graph how the velocity is changing at different instance.
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The complete question is :
a) Describe what the car is doing in various regions.
(b) Note the position and time of the car at each dot and record in the table below.
Time t (s) Position x (m)
(c) Plot a graph of position vs. time below, labeling axes. Draw a curve of best fit through the points that passes through or close to as many of the data points as possible.
(d) Is your graph consistent with your description in part (a)? Explain.
Six Thermodynamic States Of The Same Monatomic Ideal Gas Sample Are Represented In The Figure.
Six thermodynamic states of the same monatomic ideal gas sample are represented in the figure.
a. Rank these states on the basis of the temperature of the gas sample in each state.
b. Rank from largest to smallest. To rank items as equivalent, overlap them.
1. Ranking Of The Same Monatomic Ideal Gas Sample on the basis of the temperature of the gas sample in each state is F=E>D>C=B>A.
Monatomic, which is a combination of the terms "mono" and "atomic" and refers to a single atom, is a term used in physics and chemistry. A monatomic gas is a gas in which atoms are not bonded to one another, and it is typically used to describe gases.
All of the noble gases (helium, neon, argon, krypton, xenon, and radon) are examples at conventional temperatures and pressures, yet at sufficiently high temperatures, all chemical elements become monatomic in the gas phase (or very low pressure). Because a monatomic gas has no rotational or vibrational energy, its thermodynamic behavior is significantly simpler than that of polyatomic gases.
We take into account an ideal monatomic gas with particles of mass m that don't interact and whose center of mass stays at rets.
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Complete Question -
Two objects of equal mass are placed 0.8meters apart. There is an attractive force between them of 6.253 x 10-10Newtons. What is the value of each mass?
Answer: The value of each mass is approximately 9.8 x 10^-5 kg. ✅
Explanation:
PLEASEEEE GIVE BRANLIEST
To solve for the mass of each object, we can use the formula F = G(m1m2)/r^2, where F is the force between the two objects, G is the gravitational constant (6.67 x 10^-11 N*(m^2)/(kg^2)), m1 and m2 are the masses of the two objects, and r is the distance between them.
Given that F = 6.253 x 10-10 N and r = 0.8 meters, we can plug these values into the formula and solve for m1 and m2 (which are equal in this case)
6.253 x 10-10 N = (6.67 x 10^-11 N*(m^2)/(kg^2)) * (m1 * m2) / (0.8 m)^2
m1 = m2 = sqrt((6.253 x 10-10 N) * (0.8 m)^2 / (6.67 x 10^-11 N*(m^2)/(kg^2)))
m1 = m2 = sqrt((6.253 x 10-10 N) * (0.8^2 m^2) / (6.67 x 10^-11 N*(m^2)/(kg^2)))
m1 = m2 = sqrt((6.253 x 10-10 N) * (0.64 m^2) / (6.67 x 10^-11 N*(m^2)/(kg^2)))
m1 = m2 = sqrt((6.253 x 10-10 N) * (0.64 ) / (6.67 x 10^-11 N))
m1 = m2 = sqrt((6.253 x 10-10 N * (0.64 )) / (6.67 x 10^-11 N))
Answer:
Explanation:
According to gravitation law of universe,
Force=(G*M1*M2)/R^2
R=8/2=4m ,F=6.253*10^-10
M^2/R^2=6.253*10^-10/6.6743*10^-11
M=12.243KG
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For each of the cases in which you predicted that there will be an induced current, draw a diagram that illustrates: O the direction of the current through the wire of the loop, O the direction of the magnetic moment of the loop, and O the direction of the magnetic force exerted on the loop. Is the force on the wire loop in a direction that would tend to increase or decrease the change in net flux through the wire loop?
The direction of the current through the wire loop, the direction of the magnetic moment of the loop, and the direction of the magnetic force exerted on the loop are all related to the direction of the changing magnetic field and the direction of the wire loop.
If the magnetic field is increasing and the wire loop is perpendicular to the field, the current will flow in a direction that creates a magnetic moment in the loop that opposes the increasing field. The force on the loop will be in a direction that tends to decrease the change in net flux.
If the magnetic field is decreasing and the wire loop is perpendicular to the field, the current will flow in a direction that creates a magnetic moment in the loop that aligns with the decreasing field. The force on the loop will be in a direction that tends to increase the change in net flux. If the magnetic field is constant and the wire loop is moving perpendicular to the field, the current will flow in a direction that creates a magnetic moment in the loop that is perpendicular to the field and the direction of the loop's motion. The force on the loop will be in a direction that tends to increase the change in net flux. It is worth noting that the direction of the current and magnetic force can be determined by using the "right-hand rule".
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find the electric field strength 58 cm from the sphere's center. express your answer in meganewtons per coulomb.
The electric field strength is 58 cm from the sphere's center. express your answer in meganewtons per coulomb is [tex]{E_{19cm}} = 1.0517 \times {10^6}N/C\end{array}$$[/tex]
The formula for the electric field inside a solid sphere is:
[tex]$$\begin{array}{l}{E_{19cm}} = \frac{{kQr}}{{{R^3}}}\\{E_{19cm}} = \frac{{\left( {9 \times {{10}^9}N{m^2}/{C^2}} \right)\left( {15\mu C \times \frac{{{{10}^{ - 6}}C}}{{1\mu C}}} \right)\left( {19cm \times \frac{{{{10}^{ - 2}}m}}{{1cm}}} \right)}}{{{{\left( {29cm \times \frac{{{{10}^{ - 2}}m}}{{1cm}}} \right)}^3}}}\\{E_{19cm}} = 1.0517 \times {10^6}N/C\end{array}$$[/tex]
An electric-powered subject (occasionally E-discipline) is the bodily discipline that surrounds electrically charged particles and exerts a force on all differently charged particles in the field, either attracting or repelling them. It additionally refers to the bodily discipline of a device of charged debris. electric powered fields originate from electric charges and time-varying electric-powered currents. electric powered fields and magnetic fields are each manifestation of the electromagnetic subject, one of the 4 fundamental interactions (additionally referred to as forces) of nature.
Electric fields are vital in lots of areas of physics and are exploited in electrical generation. In atomic physics and chemistry, for example, the electrical field is the appealing force maintaining the atomic nucleus and electrons collectively in atoms. it's also the force answerable for chemical bonding among atoms that bring about molecules.
The electrical field is described as a vector discipline that pals to each factor in the area the electrostatic (Coulomb) force per unit of fee exerted on an infinitesimal advantageous test fee at relaxation at that factor. The derived SI unit for the electrical discipline is the volt in line with the meter (V/m), which is equal to the newton per coulomb (N/C).
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The symbol used for a magnetic pole is:
m
M
P
p
The symbol used for a magnetic pole is option Ana d B: "m" and "M" , which are used to indicate North and South magnetic poles.
What is the magnetic pole about?In physics, a magnetic pole is a point on a magnet where the magnetic field is most concentrated. The north pole of a magnet is the pole that points towards the Earth's geographic north pole, while the south pole of a magnet is the pole that points towards the Earth's geographic south pole.
Therefore, These poles are labeled "N" (for north) and "S" (for south) respectively, but it's also common to use the symbols "m" and "M" to indicate magnetic poles.
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why does hot water have more kinetic energy ?
Answer:
The average kinetic energy of the atoms and/or molecules increases, roughly, in proportion to the absolute temperature: [eq] As the temperature increases, the diffusivity increases. Therefore, the water molecules of the hot water have more kinetic energy than the cold ones, and they oscillate more rapidly.
A ball of mass 0.10 kg is dropped from a height of 18 m. Its momentum when it strikes the ground is? (2.4 kg m/s, 1.9 kg m/s, 1.5 kg m/s, 3.8 kg m/s).
A ball of mass 0.10 kg is dropped from a height of 18 m.1.5 Kgm/sec is strikes the ground. option (c) is correct.
What is mass ?
Mass, pronounced "măs," is a unit of measurement for the quantity of substance that comprises a physical body. In classical mechanics, an object's mass is important because it affects the amount of inertia it possesses and the force required to accelerate it according to Newton's equations of motion.
What is momentum ?
The mathematical relationship between mass and velocity is that of momentum. The amount of motion that is made up of the mass moved and the speed at which it is moving is known as momentum.
Momentum = sqrt (2mK) [K = Kinetic energy of block]
Applying energy conservation
K when it hits ground = mgh
So P = sqrt ( 2m2 gh) = m sqrt (2gh) = 0.10 * sqrt(2*9.8*12) = 1.534 Kgm/sec
So correct option is C) 1.5 Kgm/sec
Therefore, A ball of mass 0.10 kg is dropped from a height of 18 m.1.5 Kgm/sec is strikes the ground. option (c) is correct.
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if the current at t=0 is 12.0a, what is the current at t=2.00s?
When the current is I, the energy is stored as U B.= 2 1 LI 2, where L denotes the self-inductance.
The pace of development of this is dt dU \sB
="Li dt di"
where I is determined by the equation i= R E (1e t/ L.) (increase of current), and the derivative of that equation (or the use of Eq. C =RC) yields di/dt. As a result, at time t=1.61 using the symbols V to represent the battery voltage (12.0 volts) and R to represent the resistance (20.0), we have L.
dt dU \sB\s = \sR \sV \s2 \s (1−e \s−t/τ \sL)e \s−t/τ \sL
= \s20.0Ω \s(12.0V) (12.0V) 2 \s (1−e \s−1.61 \s )e \s−1.61 \s
=1.15W
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A particle with mass 2.30 g and charge +10.0μC enters through a small hole in a metal plate with a speed of 8.50 m/s8.50 m/s at an angle of 55.0∘. The uniform E→ field in the region above the plate has magnitude 6.50×10^3 N/C and is directed downward. The region above the metal plate is essentially a vacuum, so there is no air resistance. (a) Can you neglect the force of gravity when solving for the horizontal distance traveled by the particle? Why or why not? (b) How far will the particle travel, Δx, before it hits the metal plate?
No, the force of gravity cannot be neglected when solving for the horizontal distance traveled by the particle.
The gravitational force would be described as a force of attraction (attractive force) that attracts all physical forms having mass. It is by far the weakest recognized natural force. Mathematical representation. Mathematically, gravitational force can be represented as F = G m 1 m 2 r.
Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the mass in your body. That's what gives you weight.
And if you were on a planet with less mass than Earth, you would weigh less than you do here.
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10. Johnny completes the bicycle ride across the country with the final velocity of 10 m/s and
acceleration 2 ms² within 3s. Calculate the initial velocity.
bicycle goes in a circle to go forward
A school bus traveling at 40 km/hr. (11.1m/s) has a momentum of 152625 kg.m/s.
What is the mass of the bus?
Answer:
13,750 kg
Explanation:
p = mv
m = p/v = (152625 kg·m/s) / (11.1 m/s) = 13,750 kg
how can you maximize the torque applied to a given lever arm without applying more force?
Answer:
Apply the force in the same direction, but at a distance further away from the pivot.
Explanation:
Consider a force of magnitude [tex]F[/tex] applied on to this lever.
Let [tex]r[/tex] denote the distance between the pivot and the point where this force is applied. Let [tex]\theta[/tex] denote the angle between the force and the lever.
The torque [tex]\tau[/tex] applied on this lever would be:
[tex]\tau = r\, F\, \sin(\theta)[/tex].
Assume that the magnitude and direction of the force stay the same, such that [tex]F[/tex] and [tex]\theta[/tex] would be constant. Note that torque [tex]\tau = r\, F\, \sin(\theta)[/tex] would be proportional to the distance [tex]r[/tex]. This distance can be increased by moving the force further away from the pivot.
Therefore, when the magnitude and direction of the external force on the lever are the same, applying the force at a point further away from the pivot would increase the torque.
At what point during the cycle is the mass moving at it' $ maximum speed? A. At the equilibrium points and at the maximum amplitudes B. When displacement approaches the maximum amplitude C. It will change from cycle to cycle D. At the equilibrium points in the middle of the cycle E. There is not enough information to answer
B. When displacement approaches the maximum amplitude.
When an object is moving in a periodic motion, such as a harmonic oscillation, the speed of the object is at its maximum when the displacement is closest to the maximum amplitude. At this point, the velocity vector is pointing in the direction of motion and the object is moving at its highest speed. The maximum amplitude is the highest point on the graph of displacement versus time, and it is the point where the object is moving at its fastest.
At the equilibrium point, the object is at rest and the velocity is zero. It's important to note that the maximum speed is not always constant, it will depend on the specific conditions of the oscillation, such as the amplitude and frequency of the motion.
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from an evolutionary perspective, the most basic division among all organisms on earth is among:
From an evolutionary standpoint, the division between bacteria, archaea, and eukarya is the most fundamental one among all living things on earth.
Since both Bacteria and Archaea are made up of unicellular organisms, scientists once believed that these two domains of life were the most closely linked to one another. The most closely linked domains, according to new genome sequencing data, are actually Archaea and Eukarya. Prokaryotic cells lack membrane-bound cell organelles such mitochondria, the Golgi apparatus, and chloroplasts, among other traits. There isn't a tightly confined, clearly defined nucleus. Circular DNA makes up genetic material, which is found bare in the cytoplasm of cells.
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a composite wall is made of a layer of material a sandwiched between two layers of material b. the inner and outer surface temperatures are 25 and 10oc, respectively. calculate heat flow in w/m2 through the wall. take k values for a and b as 0.04 and 0.10 w/m k, respectively. the thickness of a is 5 cm and that of b is 2 cm, respectively.
We get 12∘C amount of heat flow in w/m2 through the wall.
What are heat?According to thermodynamics, heat is a type of energy that crosses a thermodynamic system's boundary due to a temperature differential across the barrier. [1] In a thermodynamic system, heat is not present. But the phrase is also frequently used to refer to the thermal energy that makes up a system's internal energy and is reflected in the system's temperature. Heat is a type of energy in both senses of the word. Heat is energy that is transferred into or out of a thermodynamic system via a mechanism involving either the corresponding macroscopic characteristics or microscopic atomic modes of motion. [3] The transmission of energy through thermodynamic work or mass transfer is not included in this descriptive description.
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